Kindly solve this please!
Diagram for both the questions are given.​

The display that would best show the measures of variation of the given prices is; B: Box and Whisker Plot

We are given the prices of Phone chargers in a store as;

$19, $18, $15, $17, $19, $12, $19, and $15.

Now, since we want to determine the display that would best show the measures of variation, the best display would be a box and whisker plot. This is because Box and Whisker plots are a great chart to use when showing the distribution of data points across a selected measure. These  box and whisker plots display ranges within variables measured.

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Answer:

1/9, 3, 27

(A / the first option listed)

Step-by-step explanation:

Here, we are given an expression with an "x" in it, and we are to evaluate possible x values, which means we plug them in as the x in the expression

first,

x = -2

3ˣ → 3⁻²

when we raise something to a negative power, we simply find the positive version of that power, and put a 1 over it:

3²  =  3 · 3 =  9

so, 3⁻² =  [tex]\frac{1}{9}[/tex]  (1/9)

next,

x = 1

3ˣ → 3¹

now, here we have something raised to the power of 1, which is always itself, so  3¹ = 3

   (think of ^to the power of  as how many times we multiply that number, so 3² = 3 · 3, 3¹ = 3)

and finally,

x = 3

3ˣ → 3³

here, we can multiply 3 by itself 3 times:

3 · 3 · 3 = 27

so, 3³ = 27

[important note: when we raise something to a power, we are not multiplying the base number by that number, but this is a common mistake. but the exponent is how many times we are multiplying that number, which is confusing at first}

So, our answers in order are:

1/9, 3, 27 (the first option listed)

hope this helps! let me know if I should clarify anything :)

Answer:

3.528

Step-by-step explanation:

the scale factor from the large triangle to the smaller triangle is 1/2.  All of the side lengths of the small triangle is 1/2 the side lengths of the large triangle.

A = 1/2 (bh)  The area of a triangle.  I need to know the base and the height of the little triangle to figure out the area.  If I use AC as the base, the length is given to me.  It is 4.2.  I do not have the height of the base, but I know that it is half of the height of the large triangle and that number is given to me.  It is 3.36, if I divide that by 2, I get 1.68.  Now I know all that I need to find the area.

A = 1/2(4.2)(1.68)

3.528Units^2

Answer:

Step-by-step explanation:

Area Formula

A = (a + b) × h/2

A = (28 + 14) * 16/2

A = 42 * 8

A = 336 cm²

The tripling time of population is 6 days and the population will be doubled in 3.5 days.

Given that the population of a bacteria is tripling in 6 days.

We have to find the tripling time of population and the time when the population will be doubled.

Suppose the population of bacteria in beginning be x.

The population of bacteria seems like arithmetic progression in which a =x, nth term =3x and n=6.

Aritmetic progression is a sequence which is having common difference.

nth term=a+(n-1)d

3x=x+(6-1)*d

3x-x=5d

2x=5d

d=2x/5

d=0.4x

So now we have to find the value of n where population will be 2x.

nth term=a+(n-1)d

put nth term=2x,  a=x,d=0.4x

2x=x+(n-1)*0.4x

2x-x=(n-1)*0.4x

x/0.4x=n-1

2.5=n-1

n=2.5+1

n=3.5

Hence the population of bacteria willbe doubled after 3.5 days.

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Answer:

4

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

Refer to the attached image!!

Hope it helps!

Answer:

a) x = 1.5 or x = -0.3

b) x = 5 or x = -8

Explanation:

Quadratic formula:

[tex]\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \quad when \:\: ax^2 + bx + c = 0[/tex]

Here given equation: 5x² - 6x  - 2 = 0

Identify variable constants: a = 5, b = -6, c = -2

Putting these values into equation:

[tex]\sf x = \dfrac{ -(-6) \pm \sqrt{(-6)^2 - 4(5)(-2)}}{2(5)}[/tex]

[tex]\sf x = \dfrac{ 6 \pm \sqrt{36 + 40}}{10}[/tex]

[tex]\sf x = \dfrac{ 6 \pm \sqrt{76}}{10}[/tex]

[tex]\sf x = \dfrac{ 3\pm \sqrt{76}}{5}[/tex]

[tex]\sf x = \dfrac{ 3+ \sqrt{76}}{5} \quad or \quad \dfrac{ 3- \sqrt{76}}{5}[/tex]

In one decimal point:

[tex]\sf x = 1.5 \quad or \quad -0.3[/tex]

b) Here use "middle term split" method

⇒ x² + 3x = 40

relocate

⇒ x² + 3x - 40 = 0

The factors of 40 are 8 and 5

⇒ x² + 8x - 5x - 40 = 0

factor common terms

⇒ x(x + 8) - 5(x + 8) = 0

collect into groups

⇒ (x - 5)(x + 8) = 0

set to zero

⇒ x - 5 = 0 or x + 8 = 0

relocate

⇒ x = 5 or x = -8

Step-by-step explanation:

a) The quadratic formula can help find answers to a quadratic equation when it is equal to 0. The formula is [tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex] for a quadratic equation of the form [tex]ax^2+bx+c=0[/tex].

In this question, a is 5, b is -6, and c is -2. Let's put them in the equation and solve.

[tex]x=\frac{6\pm\sqrt{(-6)^2-4(5)(-2)}}{2(5)}\\x=\frac{6\pm\sqrt{36+40}}{10}\\x=\frac{6\pm\sqrt{76}}{10}\\x=\frac{6\pm2\sqrt{19}}{10}\\x=\frac{3\pm\sqrt{19}}{5}[/tex]

This means that the value of x is both [tex]\frac{3+\sqrt{19}}5[/tex] and [tex]\frac{3-\sqrt{19}}5[/tex], since both values make x equal to 0. Putting both into the calculator, we get that [tex]x=1.5[/tex] or [tex]x=-0.3[/tex].

b) We can easily solve this equation using factoring, which turns a quadratic into two factors, and finds the solutions by setting both to 0. This will only work if the quadratic is equal to 0.

[tex]x^2+3x-40=0[/tex]

Now, we have to find two numbers that add to 3 and multiply to -40. The numbers 8 and -5 work, as 8-5=3 and 8*-5 is -40.

we can now make our factors x+8 and x-5

[tex](x+8)(x-5)=0[/tex]

If two numbers, say A and B, are being multiplied and equal 0, then either A is 0, or b is 0, or both. Similarly, if x+8 and x-5 are being multiplied and equal 0, either x+8 = 0, or x-5=0.

[tex]x+8=0\\x=-8[/tex]    [tex]x-5=0\\x=5[/tex]

This makes our solutions x=-8 and x=5.

If you are not familiar with factoring or the process I have went through above, I highly recommend learning about it.

The width of the box is 3 ft that can be produced using the minimum amount of material.

Consider a box with length 'l', width 'w' and height 'h',

Volume V = l × w × h

Surface area S = 2(lw + wh + hl)

It is given that,

Volume of the box V = 36 cubic feet and l = 2w

Using the formulae,

V = 2w × w × h = 2w²h ...(1)

S = (2w² + 2wh + 4wh) = 2w² + 6wh ... (2) (here only single lw is considered since it is open top)

From equation (1),

36 = 2w²h

⇒ w²h = 18

⇒ h =18/w²

equation (2) becomes

S = 2w² + 6w(18/w²) = 2w² + 108/w ...(3)

So, for a minimum amount of material, the width of the box is,

On differentiating the surface area w.r.t 'w'

S' = 4w - 108/w²

For a minimum amount, substituting S' = 0 we get,

0 = 4w - 108/w²

⇒ 4w = 108/w²

⇒ 4w³ = 108

⇒ w³ =  27

∴ w = 3 feet

Therefore, the width of the given box is 3 feet.

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The system is:

y < x

y ≥  2

So we conclude that the correct option is D.

On the graph, we can see two lines. One with a positive slope that is dashed.

And a solid line that is constant of the form y = c.

We can see that the shaded region is above the constant line and below the line with a positive slope, so the system of inequalities is of the form:

The only option that has this form is option d:

y < x

y ≥  2

So we conclude that the correct option is D.

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[tex]\frac{119}{780}[/tex] fraction of the whole piece you play middle C.

To find  for what fraction of the whole piece do you play middle C:

Since 7 out of every 13 beats in the finale are played at middle C, [tex]\frac{7}{13}[/tex] the finale is played at middle C.

The finale is 17 measures out of a 60-measure piece or [tex]\frac{17}{60}[/tex] of the whole piece.

[tex]\frac{7}{13}[/tex] of [tex]\frac{17}{60}[/tex] is [tex]\frac{7}{13}[/tex] x [tex]\frac{17}{60} = \frac{119}{780}[/tex]

Therefore,  [tex]\frac{119}{780}[/tex] for a fraction of the whole piece you play middle C.

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Answer:

3x + 18

Step-by-step explanation:

3x + 10 = 3y - 2(y + 4)

3x + 10 = 3y - 2y - 8

3x + 18 = y

Answer:

D, 3x + 18.

Step-by-step explanation:

3x + 10 = 3y - 2(y + 4)

3x + 10 = 3y - 2y - 8

3x + 10 = y - 8

y = 3x + 10 + 8

y = 3x + 18.

Answer:39084620

Step-by-step explanation:

New questions in Mathematics

19 ft 4 ft l Find l. l = √ [?] ft

flying against the jet stream, a jet travels 3000 in 3 hours. Flying with the jet stream, the same jet travels 5360 miles in 4 hours. What is the rate…e of the jet in still air and what is the rate of the jet stream?

Please help! Express the area of the region bounded by the x-axis, y = 1/2x - 2, and y equals the cubed root of x, using definite integrals.

Solve the equation 7/4x-2=-5x+1

How to Convert 11010112 to base 10?

Answer the following. (a) A certain solution has a hydrogen ion concentration of 0.00000896 moles per liter. Write this number in scientific notation…. (b) A humpback whale can weigh up to ×1.1105 pounds. Write this number in standard notation.

Evaluate the expression if a=2,b=-3,C=-1, and D=4 -2(b^2-5c)

Evaluate the expression if a=2,b=-3,C=-1, and D=4 -2(b^2-5c)

The set of all triples of real numbers with the standard vector addition but with scalar multiplication defined by k(x, y, z) = (k2 x,k2 y,k2 z)

Evaluate each expression if a=2,b=-3,C=-1, and d=4 5+d(3b-2d)

Answer:

Slope: 2; Y-Intercept: (0,3)

Step-by-step explanation:

As you can see from the graph, it rises 4 and runs 2. So, the slope is 2. It intersects the y axis at (0,3)

Answer:

Slope: 3/2

Y-intercept: 3

Step-by-step explanation:

The line passes the y-axis at 3, and to find the slope you use rise over run. Our rise (which is going up) is 3, and our run (which is going across) is 2 (and since it moves from left to right, it is positive). The slope would be 3/2.

I hope it helps! Have a great day!  

bren~

By applying Pythagorean theorem, we have proven that the point (-1/2, -√3/2) lies on the unit circle.

In Trigonometry, an angle with a magnitude of -120° is found in the third quarter and as such, both x and y would be negative. Also, we would calculate the reference angle for θ in third quarter as follows:

Reference angle = 180 - θ

Reference angle = 180 - 120

Reference angle = 60°.

For the coordinates, we have:

sin(-120) = -sin(60) = -1/2.

cos(-120) = -cos(60) = -√3/2.

By applying Pythagorean theorem, we have:

z² = x² + y²

z = √((-1/2)² + (-√3/2)²)

z = √(1/4 + 3/4)

z = √1

z = 1.

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Step-by-step explanation:

I don't see any numbers, so I just give you an example :

11

every position in a number is worth 10 times the value of the position to its very right.

so, in e.g. 11

the left 1 is worth 10 times the value of the right 1.

The laterals surface area of the given hexagonal prism is: 250 cm².

Lateral surface area = 5ah, where:

Given the following:

a = 5 cm

h = 10 cm

Lateral surface area of the hexagonal prism = 5ah =  5(5)(10)

Lateral surface area of the hexagonal prism = 250 cm²

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The factorized expression using difference of squares is as follows,

9a²b⁵ (2+3a⁶b⁵)(2-3a⁶b⁵)

Difference of Squares

Difference of squares is a factorization method where an expression can be factored as (a + b) (a - b) when considered as the difference of two perfect squares,  a²-b². For instance, factoring x²-25 results in (x+5) (x-5). By enlarging the parentheses in (a + b) (a - b), the pattern (a + b) (a - b)=a²-b² is used as the foundation for this technique.

Factorization Using Difference of Squares

Given expression is,

36a⁴b¹⁰ - 81a¹⁶b²⁰

= (6a²b⁵)² - (9a⁸b¹⁰)²

Using square of differences, we have

a² - b² = (a + b) (a - b)

Here, a = 6a²b⁵ and b = 9a⁸b¹⁰

Thus, we get,

(6a²b⁵ + 9a⁸b¹⁰)(6a²b⁵ - 9a⁸b¹⁰)

Further Factorization

We can take out 3 common from both the bracket terms after applying difference of squares

3×3(2a²b⁵ + 3a⁸b¹⁰)(2a²b⁵ - 3a⁸b¹⁰)

= 9(2a²b⁵ + 3a⁸b¹⁰)(2a²b⁵ - 3a⁸b¹⁰)

Further, we can take out a²b⁵ as common from both the bracket terms

= 9a²b⁵ (2+3a⁶b⁵)(2-3a⁶b⁵)

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The volume of the cylinder having diameter 12 cm and height of 4 cm is 452 [tex]cm^{3}[/tex].

Given diameter of cylinder be 12 cm and height of cylinder be 4cm.

We are required to find the volume of cylinder.

Volume is the quantity of substance a container can hold in its capacity.

Diameter=12 cm

Radius=6 cm (Radius is always equal to half of diameter)

Volume of cylinder=π[tex]r^{2} h[/tex]

We have to just put the values of r, h and π in the formula to get the volume of the cylinder.

Volume=π[tex](6)^{2} 4[/tex]

=3.14*4*36

=452.57 [tex]cm^{3}[/tex]

After rounding off we will get 452 [tex]cm^{3}[/tex].

Hence the volume of cylinder is 452 [tex]cm^{3}[/tex].

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Question is incomplete as it should include height of cylinder be 4cm.

A. Up

Parabolas are graphs that make U-shapes and are formed from quadratic equations.

Vertical Parabolas

There are 2 different types of parabolas: vertical and horizontal.

If the x-value is squared, then the parabola is vertical. So, this graph must open up or down.

Positive A-Value

The a-value is the coefficient before the squared term. In a vertical parabola, the graph opens up if the a-value is positive. On the other hand, the graph opens down when the a-value is negative.

In this case, the graph is a vertical parabola that opens up. This means that the range will have a minimum value but no maximum.

a

jfjoydx9tdzrzfzixitxxytxixutx

Answer:

C)  x = 3

Step-by-step explanation:

Given equation:

[tex]5^x=125[/tex]

Rewrite 125 with base 5:  125 = 5³

[tex]\implies 5^x=5^3[/tex]

[tex]\textsf{Apply the one-to-one property of exponents}: \quad a^{f(x)}=a^{g(x)} \implies f(x)=g(x)[/tex]

[tex]\implies x=3[/tex]

Answer:

  (b)  I, III

Step-by-step explanation:

The correct answer can be chosen based on your knowledge of the shape of the graph of f(x).

The leading coefficient of this quadratic function being positive tells you the graph will be a parabola that opens upward. The left branch of the parabola will extend to positive infinity, as will the right branch.

If there are x-intercepts, the x-values between those will be where the graph has crossed the x-axis and function values are negative.

The answer choices suggest that x=2 and x=5 are x-intercepts of the function's graph. These can be checked, if you like, by evaluating f(2) and f(5).

  f(2) = 2² -7·2 +10 = 4 -14 +10 = 0

  f(5) = 5² -7·5 +10 = 25 -35 +10 = 0

This means the function will be positive for x < 2 and for x > 5. These intervals are described by I and III.

The volume of air inside the cube is 1887.376 cubic inches

The volume of a shape or an object is the amount of space in the object

The given parameters are:

The volume of the cube is calculated using

Volume = (Side length)^3

Substitute 12.6 for Side length

Volume = 12.6^3

Expand the exponent

Volume = 12.6 * 12.6 * 12.6

Evaluate the product

Volume = 2000.376

The volume of air inside the cube is calculated using

Volume of the air = Volume of the cube - Volume of the ball

So, we have

Air = 2000.376 - 113

Evaluate

Air = 1887.376

Hence, the volume of air inside the cube is 1887.376 cubic inches

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The polynomials are classified as follows:

Depends on the number of terms, as follows:

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Answer:

y is equal to 24

Step-by-step explanation:

If y is directly proportional to x when x is equal to 5 and y is 12, then when you multiply 5 by 2 which is 10, y will be proportional to that when you multiply 12 by 2 which is 24

Answer:

b: 25

Step-by-step explanation:

The previous answer wowwubbzy13 uploaded is absolutely correct!

I'll set up a proportion.

If y = 12, then x = 5

--> 12:5

We want to find the y when x is 10

--> y:10

12:5 = y:10

5y = 120

y = 25

So B: 25 is the correct answer!

Answer: A=187.5,2

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

a quintic polynomial is a polynomial of degree 5

A is a polynomial of degree 4 (- [tex]x^{4}[/tex] term )

B is a polynomial of degree 3 (x³ term )

C is a polynomial of degree 2 ( x² term )

D is a polynomial of degree 5 ( 3[tex]x^{5}[/tex] term )

The maximum number of integers is 27 that can be added together before the summation of the A.P. Series exceeds 401.

According to the statement

We have a given that the maximum sum of the positive integers is 400.

And we have to find the value of n which is a maximum number of integers by which the value of sum become 400.

So, to find the value of the n we use the

A.P. Series'Summation formula

According to this,

S = n (n+1)/2

Here the value of s is 401

Then

S = n (n+1)/2

401 = n (n+1)/2

401*2 = n (n+1)

802 =n (n+1)

n (n+1) = 802

n^2 + n -802 =0

By the use of the Discriminant formula the

value of n becomes n = -28 and n = 27.

The negative value of n is neglected.

Therefore the value of n is 27.

So, The maximum number of integers is 27 that can be added together before the summation of the A.P. Series exceeds 401.

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