Answer:
a. There is_sufficient evidence that the leg
C. 0.010 < P-value < 0.025
b. Power of test = 1- β=0.2066
c. So the sample size is 88
Step-by-step explanation:
We formulate the null and alternative hypotheses as
H0 : u1= u2 against Ha : u1 > u2 This is a right tailed test
Here n= 7 and significance level ∝= 0.005
Critical value for a right tailed test with 6 df is 1.9432
Sample Standard deviation = s= 32
Sample size= n= 7
Sample Mean =x`= 630
Degrees of freedom = df = n-1= 7-1= 6
The test statistic used here is
Z = x- x`/ s/√n
Z= 630-600 / 32 / √7
Z= 2.4797= 2.48
P- value = 0.0023890 > ∝ reject the null hypothesis.
so it lies between 0.010 < P-value < 0.025
b) Power of test if true strength is 610 watts.
For a right tailed test value of z is = ± 1.645
P (type II error) β= P (Z< Z∝-x- x`/ s/√n)
Z = x- x`/ s/√n
Z= 610-630 / 32 / √7
Z=0.826
P (type II error) β= P (Z< 1.645-0.826)
= P (Z> 0.818)
= 0.7933
Power of test = 1- β=0.2066
(c)
true mean = 610
hypothesis mean = 600
standard deviation= 32
power = β=0.9
Z∝= 1.645
Zβ= 1.282
Sample size needed
n=( (Z∝ +Zβ )*s/ SE)²
n= ((1.645+1.282) 32/ 10)²
Putting the values and solving we get 87.69
So the sample size is 88
"Julien is trying to determine his variable type in order to select the proper statistical tests. He is measuring the height of a part. What type of variable is this"
Answer:
Quantitative
Step-by-step explanation: Quantitative or numerical variable are statistical or measured variables which involves numbers. Numerical variables allows for mathematical operations such as addition, subtraction and so on to be performed in them. Quantitative variables include height, age, weight, population and other measured variable with have numerical attributes. They can be measured on either ordinal, ratio or interval scales. Hence, since Julien is trying to determine height, the variable is a quantitative or numeric variable.
Hi I need help with 800×200= 8 × ______ hundreds=_____ Hundreds = _______ plz help me
Answer:
800×200= 8 × 200 hundreds= 1600 Hundreds = 160000
Factor the polynomial: 11x− xy +11y−x2
[tex]11x- xy +11y-x^2=\\-x^2-xy+11x+11y=\\-x(x+y)+11(x+y)=\\-(x-11)(x+y)[/tex]
Answer:
(x - 11)(-x - y)
Step-by-step explanation:
To factor the polynomial 11x - xy + 11y - x² completely, let's group the terms and factor them separately.
Rearranging the terms, we have:
11x - xy + 11y - x²
Let's rearrange the terms again to group similar terms together:
x² + 11x - xy + 11y
Now, we can factor out the common factor from each pair of terms:
x(-x + 11) - y(x - 11)
Simplifying further, we can factor out -1 from the first pair of terms:
-x(x - 11) - y(x - 11)
Now, notice that we have a common factor of (x - 11) in both terms. Factoring out this common factor, we obtain:
(x - 11)(-x - y)
Therefore, the polynomial 11x - xy + 11y - x² can be factored completely as (x - 11)(-x - y).
Rewrite the following expressions using the distributive property.
1. 5(3x - 2)
2. 2x(6x + 5)
3.
2x
(9x + 6)
3
2
What is the correct answer and how can this be solved?
Answer:
[tex]$\mathbf{\frac{1}{19} }[/tex]
Step-by-step explanation:
[tex]$$\bullet \Nth \ Term;\\$$$\frac{n+2}{2n^{2} +3n-2}[/tex]
[tex]$$\bullet U_{10} \ Term;\\\\$$\boxed{\frac{(10+2) }{2*10^{2} +3*10-2}= \frac{1}{19} }[/tex]
Answer:
[tex]\boxed{\displaystyle \frac{1}{19}}[/tex]
Step-by-step explanation:
[tex]\displaystyle \frac{n+2}{2n^2 +3n-2}[/tex]
Replace n with 10 to find the 10th term.
[tex]\displaystyle \frac{10+2}{2(10)^2 +3(10)-2}[/tex]
Evaluate.
[tex]\displaystyle \frac{12}{2(100) +30-2}[/tex]
[tex]\displaystyle \frac{12}{200 +30-2}[/tex]
[tex]\displaystyle \frac{12}{228}[/tex]
Simplify.
[tex]\displaystyle \frac{1}{19}[/tex]
Frank and Gregory leave Centreville traveling in opposite directions on a straight road. Gregory drives 22 miles per hour faster than Frank. After 2.25 hours, they are 216 miles apart. Find Frank's speed and Gregory's speed.
Answer:
Frank speed = 37mi/hGregory speed = 59mi/hrStep-by-step explanation:
Let the speed of Frank be x and speed of Gregory be y. If Gregory drives 22 miles per hour faster than Frank, then y = 22+x. SInce they they are 216miles apart after 2.25 hours,
Speed = Distance/Time
Total time travelled by them = 2.25hours
Total distance = 216 hours
Total speed = x+y = x+22+x
Substituting this parameters into the formula given to get x we will have;
x+22+x = 216/2.25
2x+22 = 96
2x = 96-22
2x = 74
x = 74/2
x = 37
Hence the speed of Frank is 37miles per hour while that of gregory is 37+22 = 59miles/hour
What is the solution to X+9 = 24?
A. x = 33
B. x= 15
C. x= 18
D. x= 9
Answer:
X+9=24
Or,x=24-9
:.x=15
Step-by-step explanation:
Answer:
B. x=15
Step-by-step explanation:
To find the solution to the equation, we must get x by itself on one side of the equation.
[tex]x+9=24[/tex]
9 is being added to x. The inverse of addition is subtraction. Subtract 9 from both sides of the equation.
[tex]x+9-9=24-9[/tex]
[tex]x=24-9[/tex]
[tex]x=15[/tex]
Let's check our solution. Plug 15 in for x.
[tex]x+9=24 (x=15)[/tex]
[tex]15+9=24[/tex]
[tex]24=24[/tex]
This checks out, so we know our solution is correct. The answer is B. x=15
Which is the simplified form of (StartFraction 2 a b Over a Superscript negative 5 Baseline b squared EndFraction) Superscript negative 3? Assume a not-equals 0, b not-equals 0. StartFraction b cubed Over 8 a Superscript 18 Baseline EndFraction StartFraction b squared Over 8 a Superscript 45 Baseline EndFraction StartFraction a Superscript 6 Baseline Over 4 b EndFraction StartFraction 2 a Superscript 6 Baseline Over b Superscript 5 Baseline EndFraction
Answer:
[tex]\dfrac{b^3}{8a^{18}}[/tex] matches the first choice
Step-by-step explanation:
[tex]\left(\dfrac{2 a b}{a^{-5}b^2}\right)^{-3}=(2a^{1-(-5)}b^{1-2})^{-3}=(2a^6b^{-1})^{-3}\\\\=2^{-3}a^{6(-3)}b^{-1(-3)}=8^{-1}a^{-18}b^3=\boxed{\dfrac{b^3}{8a^{18}}}[/tex]
__
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
a^-b = 1/a^b
Answer:
A
Step-by-step explanation:
just took the pretest! good luck!
Guess the rule and write down the missing number:
Answer:
17
Step-by-step explanation:
We are adding the previous two terms
1+5 = 6
5+6 = 11
6+11 = 17
11+17 = 28
The missing term is 17
Help please! it’s due soon
Answer:
33. That means (A) can be any number and b times any number wilo get 0 so any numbr will do
34.It is wrong because if x equals 40 anything multiply that will be more than that and so isnt a good reasoning
Factorize p2-15q-5p+2pq
Hope it's help you!!!!!!
If y varies directly with x and y = 5 when x = 4, find the value of y when x = -8
Answer:
-10
Step-by-step explanation:
y : x
= 5 : 4
4z = -8
= -8 / 4 = -2 = z
y : x
= 5 * -2 : 4 * -2
= -10 : -8
The sequence below represents Marisa’s fine at the library for each day that she has an overdue book: $0.50, $0.65, $0.80, $0.95, $1.10, ... Which equation represents Marisa’s library fine as a function of a book that is n days overdue? f(n) = 0.15n f(n) = 0.50n f(n) = 0.15n + 0.35 f(n) = 0.50n + 0.15
Answer:
f(n) = 0.15n + 0.35Step-by-step explanation:
The sequence of the problem above is an arithmetic sequence
For an nth term in an arithmetic sequence
F(n) = a + ( n - 1)d
where a is the first term
n is the number of terms
d is the common difference
To find the equation first find the common difference
0.65 - 0.5 = 0.15 or 0.80 - 0.65 = 0.15
The first term is 0.5
Substitute the values into the above formula
That's
f(n) = 0.5 + (n - 1)0.15
f(n) = 0.5 + 0.15n - 0.15
The final answer is
f(n) = 0.15n + 0.35Hope this helps you
Answer:
The correct option is: f(n) = 0.15n + 0.35Step-by-step explanation:
Took the math test on edge
I need help ASAP THANK YOU
Answer:
174 cm²
Step-by-step explanation:
The figure given is a prism with isosceles trapezoid as base.
Its surface area can be calculating the area of each face that makes up the prism, and summing all together.
There are 6 faces. Their dimensions and areas can be calculated as follows:
2 isosceles trapezium:
It has 2 parallel bases, (a and b), of 4cm and 6cm,
Height (h) = 2.8cm
Area = ½(a+b)*h
Area = ½(4+6)*2.8
Area = ½(10)*2.8 = 5*2.8 = 14 cm²
4 rectangles of different dimensions:
Rectangle 1 (down face): l = 10cm, b = 4cm
Area = 10*4 = 40 cm²
Rectangle 2 and 3 (side faces): l = 10cm, b = 3cm
Area = 2(l*b) = 2(10*3) = 60cm²
Rectangle 4 (top face) = l = 10cm, b = 6cm
Area = 10*6 = 60cm²
Surface area of the figure = 14 + 40 + 60 + 60 = 174 cm²
Determine what type of decimal each is.
8.54
●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●
Hi my lil bunny!
❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙
[tex]8.54 \div 100 = 0.0854[/tex]
(what do you mean by Determine what type of decimal each is: 8.54 because there is only one decimal there )
❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙
●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●
Have a great day/night!
❀*May*❀
simplify 4x+3y please
Answer:
[tex]\boxed{4x + 3y}[/tex]
Step-by-step explanation:
Hey there!
Well 4x + 3y cannot be added together because they are 2 different variables.
4x + 3y = 4x + 3y
So 4x + 3y simplified is,
4x + 3yHope this helps :)
I buy 6 CDs costing £6.99.
How much change do I get from
£50?
Answer:
subtract the 6.99 from 50 and you get your answer
Step-by-step explanation:
Answer:
8.06
Step-by-step explanation:
Take the cost of a cd and multiply by 6
6.99 *6
41.94
Subtract this from 50.00
50.00 - 41.94
8.06
You will get 8.06 back
Which of the following equations have infinitely many solutions?
Choose all answers that apply:
A10x- 10 = -10x + 10
B- 10x - 10 = -10x + 10
C-10x – 10 = -10x - 10
D10x - 10 = -10x – 10
Hey there! I'm happy to help!
An equation with infinite solutions has a solution of x=x. You can plug in any x-value and it will equal x, so there are infinitely many solutions.
ANSWER A
10x-10=-10x+10
We add 10 to both sides.
10x=-10x+20
We add 10x to both sides.
20x=20
We divide both sides by 20.
x=1
We have a solution of 1, so this is not an equation with infinitely many solutions.
Answer B
-10x-10=-10x+10
We add 10 to both sides.
-10x=-10x+20
We add 10 x to both sides.
0=20
This has no solutions because the x is gone, so there cannot be a solution.
Answer C
-10x-10=-10x-10
We add 10 to both sides.
-10x=-10x
We divide both sides by -10.
x=x
This has infinitely many solutions.
Answer D
10x-10= -10x-10
We add 10x to both sides.
20x-10=-10
We add 20 to both sides.
20x=0
We divide both sides by 20.
x=0
There is a single solution here, not infinitely many.
Therefore, the answer is C. -10x-10=-10x-10.
Have a wonderful day! :D
A senior accounting major at Midsouth State University has job offers from four CPA firms. To explore the offers further, she asked a sample of recent trainees how many months each worked for the firm before receiving a raise in salary. The sample information is submitted to Minitab with the following results:
Analysis of Variance
Source df SS MS F P
Factor 3 28.17 9.39 5.37 0.010
Error 15 26.26 1.75
Total 18 54.43
A) Reject H0 if F >
B) For the 0.05 level of significance, is there a difference in the mean difference in the mean number of months before a raise was anted among the four CPA firms?
Answer:
A) Reject H0 if F > 5.417
B) we fail to reject the null hypothesis and conclude that we do not have sufficient evidence at 0.05 level of significance to support the claim that there is a difference in the mean number of months before a raise was granted among the four CPA firms
Step-by-step explanation:
A) From the table, we can see that we have df1 = 3 and df2 = 15. And we are given a significance level of α = 0.01
We are also given f-value of 1.75
Thus,from the f-distribution table attached at significance level of α = 0.01 and df1 = 3 and df2 = 15, we have;
F-critical = 5.417
Normally, we reject H0 if F > 5.417
But in this case, F is 1.75 < 5.417 and so we conclude that we do not reject H0 at the 0.01 level of significance
B) for 0.05 level of significance, df1 = 3 and df2 = 15, from the 2nd table attached, we have;
F-critical = 3.2874
Again the f-value is less than this critical one.
Thus, we fail to reject the null hypothesis and conclude that we do not have sufficient evidence at 0.05 level of significance to support the claim that there is a difference in the mean number of months before a raise was granted among the four CPA firms
Solve for x.
5(2x - 1) = 6
A) x = 11/10(Fraction)
B) x = 1/2 (Fraction)
C) x = 1/10 (Fraction)
Answer:
x = 11/10
Step-by-step explanation:
5(2x - 1) = 6
Distribute
10x -5 = 6
Add 5 to each side
10x-5+5 = 6+5
10x = 11
Divide each side by 10
10x/10 = 11/10
x = 11/10
PRECAL QUESTION - please help thanks
Answer:
203/169 -183i/169
"A"
Step-by-step explanation:
[tex]\frac{9-19i}{12-5i}[/tex]
[tex]\frac{9-19i}{12-5i}[/tex] * [tex]\frac{12+5i}{12+5i}[/tex]
12^2 - (5i)^2 = 144 + 25 = 169
FOIL: 108 +45i - 228i + 95
203 -183
An item is regularly priced at $70. Keiko bought it on sale for 80% off the regular price. How much did Keiko pay? $
Answer:
$14
Step-by-step explanation:
80% of $70 is $14, saving him $56
The other person has a great answer. Here's another approach.
If the discount is 80%, then you have to pay the remaining 20% (the two percentages add to 100%)
20% of 70 = 0.20*70 = 14
The sale price is $14 which is the amount Keiko pays
We see that Keiko saves 70-14 = 56 dollars.
the production of a printer consists of the cost of raw material at 100 dollars the cost of overheads at 80$ and wages at 120$ if the cost of raw materials and overheads are increased by 11% and 20% respectively while wages are decreased by 15% find the percentage increase or decrease in the production cost of the printer
Answer:
The percentage increase in the production cost of the printer is 3%.
Step-by-step explanation:
We are given that the production of a printer consists of the cost of raw material at 100 dollars the cost of overheads at 80$ and wages at 120$.
Also, the cost of raw materials and overheads are increased by 11% and 20% respectively while wages are decreased by 15%.
Cost of raw material = $100
Cost of overheads = $80
Cost of wages = $120
So, the total cost of the printer = $100 + $80 + $120
= $300
Now, the increase in the cost of raw material = $100 + 11% of $100
= [tex]\$100 + (\frac{11}{100} \times \$100)[/tex]
= $100 + $11 = $111
The increase in the cost of overheads = $80 + 20% of $80
= [tex]\$80 + (\frac{20}{100} \times \$80)[/tex]
= $80 + $16 = $96
The decrease in the cost of wages = $120 - 15% of $120
= [tex]\$120 - (\frac{15}{100} \times \$120)[/tex]
= $120 - $18 = $102
So, the new cost of a printer = $111 + $96 + $102 = $309
Now, the percentage increase in the production cost of the printer is given by;
% increase = [tex]\frac{\text{Net increase in the cost of printer}}{\text{Original cost of printer}} \times 100[/tex]
= [tex]\frac{\$309- \$300}{\$300} \times 100[/tex]
= 3%
Hence, the percentage increase in the production cost of the printer is 3%.
Salaries of 42 college graduates who took a statistics course in college have a mean, , of . Assuming a standard deviation, , of $, construct a % confidence interval for estimating the population mean .
Answer:
The 99% confidence interval for estimating the population mean μ is ($60,112.60, $68087.40).
Step-by-step explanation:
The complete question is:
Salaries of 42 college graduates who took a statistics course in college have a mean, [tex]\bar x[/tex] of, $64, 100. Assuming a standard deviation, σ of $10,016 construct a 99% confidence interval for estimating the population mean μ.
Solution:
The (1 - α)% confidence interval for estimating the population mean μ is:
[tex]CI=\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex]
The critical value of z for 99% confidence interval is:
[tex]z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.57[/tex]
Compute the 99% confidence interval for estimating the population mean μ as follows:
[tex]CI=\bar x\pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex]
[tex]=64100\pm 2.58\times\frac{10016}{\sqrt{42}}\\\\=64100+3987.3961\\\\=(60112.6039, 68087.3961)\\\\\approx (60112.60, 68087.40)[/tex]
Thus, the 99% confidence interval for estimating the population mean μ is ($60,112.60, $68087.40).
Choose all properties that were used to simplify the following problem: [38 + 677] + (-38) [677 + 38] + (-38) 677 + [38 + (-38)] 677 + 0 677 Choices: additive identity additive inverse commutative property of addition associative property of addition distributive property
Answer:
Distributive property, addition property
Answer:
additive identity
associative property of addition
distributive property
Step-by-step explanation:
Look at attachment down below. If can’t see let me know
Answer:
C and E
Step-by-step explanation:
C and E are the correct answer
Policeman A and Policeman B hand out 70 speeding tickets in a month.
Policeman A hands out 4 times as many speeding tickets as Policeman B.
Policeman A handed out ? Speeding tickets.
Answer:
Policeman A = 56 tickets
Step-by-step explanation:
Policemen A + B = 70
If Policeman B hands out x no of tickets...
Then Policeman A hands out 4x no of tickets
meaning...
x + 4x = 70
5x = 70
x = 70/5
x = 14
Therefore Policeman A hands out..
4x = 4 × 14 = 56 tickets
The data set {3, 7, 5, 4, 1} consists of the lengths, in minutes, of a sample of speeches at an awards banquet. Use a formula to find the standard deviation of the sample, and label it with the correct variable.
Answer:
Standard deviation = 2.2360679774998
Step-by-step explanation:
We are asked to find the Standard deviation of a samples of speeches as an awards.
The formula for sample standard deviation is given as:
√[(x - μ)²/N - 1 ]
Step 1
We find the mean (μ)
The mean of the sample =>
= Sum of term/ Number of terms
= (3 + 7 + 5 + 4 + 1)/5
= 20/5
= 4
Step 2
Find the Standard deviation of the sample
√[(x - μ)²/N - 1 ]
N = number of samples or terms = 5
= √[(3 - 4) ² + (7 - 4)² + (5 - 4)² +(4 - 4)² +(1 - 4)²/ 4]
= √ (1 ² + 3² + -1² + 0² + -3²/4)
= √( 1 + 9 + 1 + 0 + 9/4)
= √20/5 - 1
= √5
= 2.2360679774998
The standard deviation of the sample = 2.2360679774998
If possible, find AB. & State the dimension of the result.
Answer:
The answer is "[tex]AB= \left[\begin{array}{cc} -2 &51 \\-8&33\\0&27&\end{array}\right][/tex]"
Step-by-step explanation:
If the value of A and B is:
[tex]A= \left[\begin{array}{cc}-1&6\\-4&5\\0&3\end{array}\right][/tex]
[tex]B=\left[\begin{array}{cc}2&3\\0&9\end{array}\right][/tex]
Find the value of A[tex]\times[/tex]B:
[tex]AB =\left[\begin{array}{cc}-1 \times 2+6 \times 0 &-1 \times 3+6 \times 9\\ -4 \times 2+5 \times 0& -4 \times 3+5 \times 9\\ 0 \times 2+3 \times 0&-1 \times 2+3\times 9\end{array}\right] \\ \\\\AB =\left[\begin{array}{cc}-2+0 &- 3+54\\ -8+0& -12+45\\ 0+ 0&-2 +27\end{array}\right] \\ \\[/tex]
[tex]AB= \left[\begin{array}{cc} -2 &51 \\-8&33\\0&27&\end{array}\right][/tex]
find the equation of the line which is parallel to the line 5 x + 4y = 18 and makes an intercept of 2 units on the x-axis
Answer:
[tex]{ \underline{ \sf{equation \: is : \: y = - \frac{5}{4} x + 2 }}}[/tex]
Step-by-step explanation:
[tex]y = mx + c \\ 4y = - 5x + 18 \\ y = - \frac{5}{4} x + \frac{9}{2} [/tex]
since it is parallel, the gradients are the same; m = -5/4
[tex]y = - \frac{5}{4} x + 2[/tex]
Answer:
y=-5x+2
Step-by-step explanation:
x intercept=2
points will be (2,0)
slope of given line:
4y=-5x+18
y=mx+c
comparing equation:
m=-5
lines are parallel so given slope is equal to required slope.
using point slope form:
y-0=-5(x-2)
y=-5x+2