Answers
Excuse me, is this I ready because you know you can get reported right... just try your best, it's not a real grade! :)
& possibly delete this question because a bot can track and report this to your school. People at my school did that and got in 3 days detention...
Related Questions
please halp with this step by step to further understand thank you!
. . . . . . plssssss
Answers
the number of real solutions to the quadratic equ
5a² + 30a + 45 = 0
Answers
The answer is 1.
There is one unique real solution, which is x = -3.
Hello, please consider the following.
[tex]5a^2+30a+45 = 0\\\\<=> 5(a^2+6a+9)=0\\\\<=> a^2+6a+9=0\\\\<=> a^2+2*3*a+3^2=(a+3)^2=0\\\\<=>\boxed{a=-3}[/tex]
Thank you
Answer:
two equal, real solutions
Step-by-step explanation:
The quickest way to determine this is to find the discriminant b^2 - 4ac. If this determinant (D) is > 0, the quadratic has two different real roots; if + 0, the quadratic has two equal real roots, and if < 0, the quadratic has two imaginary or complex roots.
Here a = 5, b = 30 and c = 45. The discriminant is
30^2 - 4(5)(45) = 900 - 900 = 0
and so this quadratic has two equal, real solutions.
Chester, the dog, loves to eat treats. He has eaten twice as many today as yesterday. He has eaten a total of 15 dog treats in both days.
-write the equation-
Answers
Answer:
The equations are:
[tex]T = 2Y[/tex] and [tex]T + 2Y = 15[/tex]
Step-by-step explanation:
Given
Represent bones eaten Today with T and yesterday with Y
Required
Write the equation
In the first statement, we have that:
[tex]T = 2Y[/tex]
Reading further; In the second statement
[tex]T + 2Y = 15[/tex]
Hence, the equations are:
[tex]T = 2Y[/tex] and [tex]T + 2Y = 15[/tex]
Solving further:
Substitute 2Y for T in the second equation
[tex]2Y + 2Y = 15[/tex]
[tex]4Y = 15[/tex]
Divide both sides by 4
[tex]Y = \frac{15}{4}[/tex]
[tex]Y = 3.75[/tex]
Recall that
[tex]T = 2Y[/tex]
[tex]T= 2 * 3.75[/tex]
[tex]T= 7.5[/tex]
3 - (4m + 1) > 5m - 25
Answers
Step-by-step explanation:
3 - (4m + 1) > 5m - 25
3 - 4m - 1> 5m - 25
3 - 1 +25 > 4m + 5m
27 > 9m
m> 27/9
m> 3
what is the probability of spinning a multiple of 3 The Spinner is 1-8 numbered
Answers
Answer:
1/4
Step-by-step explanation:
There are 8 possible outcomes
Multiples of 3 are
3,6 = 2 outcomes
P ( multiple of 3) = number of multiples of 3/ total
= 2/8
= 1/4
The probability of spinning a multiple of 3 The Spinner is 1-8 numbered will be [tex]P= \dfrac{1}{4}[/tex]
What is probability?Probability is the extent to which an event is likely to occur, measured by the ratio of the favourable cases to the whole number of cases possible.
There are 8 possible outcomes
Multiples of 3 are
3,6 = 2 outcomes
[tex]\rm P ( multiple \ of\ 3) =\dfrac{ number\ of\ \ multiples\ of\ 3 }{ total }[/tex] [tex]= \dfrac{2}{8}[/tex] [tex]= \dfrac{1}{4}[/tex]
Hence the probability of spinning a multiple of 3 The Spinner is 1-8 numbered will be [tex]P= \dfrac{1}{4}[/tex]
To know more about probability follow
https://brainly.com/question/24756209
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Round the following number to the nearest hundred
123,456
Answers
Answer:
Hey!
Your answer is 123,500!
Step-by-step explanation:
TO ROUND TO THE NEAREST HUNDRED we need to look at the TENS column...
IN THIS CASE WE LOOK AT '5'...
If its bigger than 4 INCREASE THE DIGIT IN THE HUNDREDS PLACE BY ONE
If its smaller than 5 DECREASE THE DIGIT IN THE HUNDREDS PLACE BY ONE!
So as 5 is a digit that makes us ROUND UP...we change 4 to a 5 to have 123,500 as our answer!
HOPE THIS HELPS!
Suppose that X and Y are independent random variables from binomial experiments where n = 4 in both cases but the probability of success is p = 0.25 for X and p = 0.5 for Y . Calculate the probability of the events (a) {X = 1, Y = 2}, (b) {X + Y = 1}.
Answers
Answer:
(a) The value of P (X = 1, Y = 2) is 0.1583.
(b) The value of P (X + Y = 1) is 0.1055.
Step-by-step explanation:
It is provided that:
[tex]X\sim Bin(n=4,p=0.25)\\\\Y\sim Bin(n=4,p=0.50)[/tex]
The variables X and Y are independent random variables.
The probability mass function of a Binomial distribution is:
[tex]P(U=u)={n\choose u}(p)^{u}(1-p)^{n-u};\ u=0,1,2,3...[/tex]
(a)
Compute the value of P (X = 1, Y = 2) as follows:
[tex]P(X=1,Y=2)=[{n\choose x}(p_{x})^{x}(1-p_{x})^{n-x}]\times [{n\choose y}(p_{y})^{y}(1-p_{y})^{n-y}][/tex]; Independent
[tex]=[{4\choose 1}(0.25)^{1}(1-0.25)^{4-1}]\times [{4\choose 2}(0.50)^{2}(1-0.50)^{4-2}]\\\\=0.422\times 0.375\\\\=0.15825\\\\\approx 0.1583[/tex]
Thus, the value of P (X = 1, Y = 2) is 0.1583.
(b)
Compute the value of P (X + Y = 1) as follows:
[tex]P(X+Y=1)=P(X=0,Y=1)+P(X=1,Y=0)[/tex]
[tex]=\{[{4\choose 0}(0.25)^{0}(1-0.25)^{4-0}]\times [{4\choose 1}(0.50)^{1}(1-0.50)^{4-1}]\}\\+\{[{4\choose 1}(0.25)^{1}(1-0.25)^{4-1}]\times [{4\choose 0}(0.50)^{0}(1-0.50)^{4-0}]\}\\\\=(0.3164\times 0.25)+(0.422\times0.0625)\\\\=0.0791+0.0264\\\\=0.1055[/tex]
Thus, the value of P (X + Y = 1) is 0.1055.
Estimate the mean of the age of the people in group A
Answers
Answer:
48
Step-by-step explanation:
The ages are 18,28,38,48,58,68,78 I don't use 88 bacause the graph don't show any data so there is 88 years old
now lets find the mean
18+28+38+48+58+68+78= 336= 48
7 7
so the mean of the age is 48
i hope u like it
The water level as a river recedes after a flood is measured at regular intervals, and its height relative to normal, in inches, follows the sequence below. If the sequence continues, what do you expect the 7th measurement to be? 16, 9, 2, –5, ...,
Answers
Answer:
7th measurement = -26
Step-by-step explanation:
The sequence is 16, 9, 2, –5, ...,
First term( a)= 16
Second term=9
Common difference (d) = 9-16
Common difference= -7
The sequence is a arithmetic progression
For AP's ,the terms formula is
Term(n) = a + (n-1)d
Where n represent the term to be found
In this case,we Are looking for the 7th term , so n= 7
Term(7) = 16+ (7-1)-7
Term(7)= 16 +6(-7).
Term (7) = 16-42
Term(7) = -26
7th term =-26
Could anyone help me with this?
Answers
Answer:
x = 17
KNM = 131
Step-by-step explanation:
(8x - 5) + (4x - 19) = 180
12x - 24 = 180
12x = 204
x = 17
Answer:
x = 17
Step-by-step explanation:
Opposite Angles must be the Same Value so In other words, 2(8x - 5) + 2(4x - 19) = 360.
2(8x - 5) + 2(4x - 19) = 360
24x - 48 = 360
24x = 408
x = 17
3. Represent each addend with number disks in the place value chart. Show the composition of larger units
from 10 smaller units. Write the sum in standard form.
a.
4 thousands + 11 hundreds =
:51 100
tens
ones
hundred
thousands
thousands
hundreds
ten
thousands
millions
O
b. 24 ten thousands + 11 thousands=_ 25 11000
hundreds
tens
ones
millions
hundred
thousands
thousands
ten
thousands
25
o
O
Answers
Answer:
4(1000) +11(100) + 24(10,000) +11(1000) = 256,100
Step-by-step explanation:
Maybe you want to add 4000 +1100 to 24(10,000) +11,000.
1 thousand = 10 hundreds, so 4000 = 40 hundreds
4000 +1100 = (40 +11) hundreds = 51 hundreds
__
1 ten-thousand = 10 thousands, so 24(10,000) = 240 thousands
24(10,000) +11,000 = (240 +11) thousands = 251 thousands
__
So, we want to add 251,000 and 51 hundreds. The latter can be considered to be 5000 +100, so we have ...
251,000 +5100 = 251,000 +5,100 = (251 +5) thousands + 1 hundred
= 256,100
A number close to an exact form is called?
Answers
Answer:
estimate or approximate number
Step-by-step explanation:
trust
If P is between L and A, PL = x+4, PA = 2x - 1, and LA = 5x - 3, then x = ____ and LA = ____. PLEASE HURRY
Answers
Answer:12
Step-by-step explanation:
La= LP + PA
5x-3=x+4+2x-1 Combine like terms.
5x-3=3x+3 Combine like terms
2x-3=3 Combine 3 and 3 ( Add)
2x=6 Divide by 2
X=3
LA=5x-3
5(3)-3 Multiply 5 and 3
15-3
LA=12
write a sentence as a equation
h plus 240 is 18
Answers
Hey there! The sentence is h + 240 = 18
The angled lines used to indicate the surfaces which are cut by the imaginary cutting-plane are called:
Answers
Answer:
Section lines
Step-by-step explanation:
Sectioning is the process of cutting a surface by an imaginary plane, the view of the surface that is cut is shown in the section view.
Section lines are used to indicate where an imaginary cutting plane cuts a material. The imaginary cut is then represented using section lines which are usually thin, crosshatched.
Section lines shows the surface that have been cut by the cutting plane. There are different ways of sectioning such as full section, half section, off set section and so on
Need this urgently!! Please help me
Answers
circumference= 2 x pi x r= 2x pi x10/2
=10pi feet
Area= pi x r^2=25pi square feet
Flower bed B:
circumference=12 pi feet
Area=36 pi square feet
Logan wants to have $130,000 to pay for a surgery on his retractable forearm claws in 30 months. If he can invest money in an account right now that will give him 7.5% interest compounded monthly, how much would he have to
invest now to end up with the amount needed for the surgery later on?
Answers
Answer: $107,836.69 or about $107,837 (to the nearest dollar)
Step-by-step explanation:
Formula to the accumulated amount received after investing principal amount (P) at rate of interest (r) compounded monthly for t months :
[tex]A=P(1+\dfrac{r}{12})^{t}[/tex]
As per given , A = $130,000
r= 7.5% = 0.075
t= 30 months
Now,
[tex]130000=P(1+\dfrac{0.075}{12})^{30}\\\\\Rightarrow 130000=P(1+0.00625)^{30}\\\\\Rightarrow 130000=P(1.00625)^{30}\\\\\Rightarrow 130000=P \times1.20552661036\\\\\Rightarrow\ P=\dfrac{130000}{1.2055266}=107,836.69[/tex]
Hence he need to invest $107,836.69 .
Temperature transducers of a certain type are shipped in batches of 50. A sample of 60 batches was selected, and the number of transducers in each batch not conforming to design specifications was determined, resulting in the following data.
5 1 2 4 0 1 3 2 0 5 3 3 1 3 2 4 7 0 2 3
3 4 2 1 3 1 1 3 4 1 2 3 2 2 8 4 5 1 3 1
8 0 2 3 2 1 0 6 4 2 1 6 0 3 3 3 6 1 2 3
(a) Determine frequencies and relative frequencies for the observed values of x = number of nonconforming transducers in a batch. (Enter relative frequencies to three decimal places.)
x Frequency Relati veFrequency
0
1
2
4
5
6
7
8
(b) What proportion of batches in the sample have at most six nonconforming transducers? (Enter your answer to three decimal places.)
What proportion have fewer than six? (Enter your answer to three decimal places.)
What proportion have at least six nonconforming units? (Enter your answer to three decimal places.)
(c) Draw a histogram of the data using relative frequency on the vertical scale, and comment on its features.
a) The center of the histogram is around 2 or 3 and it shows that there is some negative skewness in the data.
b) The center of the histogram is around 2 or 3 and it shows that the distribution is fairly symmetric.
c) The center of the histogram is around 4 or 5 and it shows that there is some positive skewness in the data.
d) The center of the histogram is around 2 or 3 and it shows that there is some positive skewness in the data.
e) The center of the histogram is around 4 or 5 and it shows that the distribution is fairly symmetric.
f) The center of the histogram is around 4 or 5 and it shows that there is some negative skewness in the data.
Answers
Answer:
The number of six non conforming transducers at most =54/60=0.9
The number of fewer than six non conforming transducers =51/60=0.85
The number of at least six non conforming transducers at most =30/60=0.5
d) The center of the histogram is around 2 or 3 and it shows that there is some positive skewness in the data
Step-by-step explanation:
Relative Frequency Frequency x
6/60=0.1 6 0
0.2 12 1
0.2 12 2
0.25 15 3
0.1 6 4
0.05 3 5
0.05 3 6
0.0167 1 7
0.033 2 8
∑ 60
The number of six non conforming transducers at most
= 6+12+12+15+6+3= 54
The number of six non conforming transducers at most =54/60=0.9
The number of fewer than five non conforming transducers
= 6+12+12+15+6 = 51
The number of fewer than six non conforming transducers =51/60=0.85
The number of at least six non conforming transducers
2+1+3+3+6+15= 30
The number of at least six non conforming transducers at most =30/60=0.5
We plot the histogram by placing the percentages (or relative frequency *100) on the y –axis and the X on the x-axis.
The center of the histogram is given by the mean of the distribution which in this case is = ∑fx/∑f= 161/60= 2.683
So option d is the best answer
d) The center of the histogram is around 2 or 3 and it shows that there is some positive skewness in the data
Because at the center (between 2 and 3) the curve is increasing
8 – 3x = 20
A.
x = 4
B.
x = 9.33
C.
x = –4
D.
x = –9.33
Please select the best answer from the choices provided
A
B
C
D
Answers
Answer:
The answer is option C.
www.g Suppose that 59% of people own dogs. If you pick two people at random, what is the probability that they both own a dog
Answers
Answer:
The value is [tex]P(O) = 0.3481[/tex]
Step-by-step explanation:
From the question we are told that
The proportion of people that own a dog is [tex]p = 0.59[/tex]
Generally the probability of the two selected people owning a dog is mathematically evaluated as
[tex]P(O) = p^2[/tex]
[tex]P(O) = (0.59 )^2[/tex]
[tex]P(O) = 0.3481[/tex]
1 kilometre is how much miles
Answers
Answer:
1 kilometre is 0.621 mile
Answer:
1 Kilometer = 0.621 mile
Step-by-step explanation:
The distance d in miles (mi) is equal to the distance d in kilometers (km) divided by 1.609344
Which of the following graphs represent a function?
Graph A
Graph B
Graph
Graph
a. Graph A and Graph C
b. Graph A
C. Graph D
D. graph b and d
Answers
The graphs that represent functions are given as follows:
a. Graph A and Graph C.
When does a graph represents a function?A graph represents a function if it has no vertically aligned points, that is, each value of x is mapped to only one value of y.
For this problem, we have that:
Graph B has one vertically aligned point, hence it is not a function.Graph D has multiple vertically aligned points, hence it is also not a function.Hence the graphs that represent functions are given as follows:
a. Graph A and Graph C.
More can be learned about graphs and functions at https://brainly.com/question/12463448
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Answer: The only graphs that classify as function are Graph A and Graph C, so the answer is C. It's not possible for B and D to be functions.
1: During an electronics experiment in your laboratory, you measure the voltage at terminal A
on your newly designed circuit. You measure -12 volts. You check the same terminal after
making a small change to the circuit and this time you measure -18 volts. What was the voltage
difference between the two readings?
2: What is the change in temperature a customer in a grocery store experience when they walk from the chilled vegetable section at 4 c to the frozen fish section which is set to -18 c?
Answers
Answer:
1) - 6 volts (or 6 volts drop)
2) -22°C (or 22°C drop)
Step-by-step explanation:
1. ............................
Initial voltage = -12 volts
Later voltage = - 18 volts
The difference:
-18 - (-12) = -18 + 12 = - 6 volts2. ............................
Temperature in the chilled vegetable section = 4°C
Temperature in the frozen fish section = - 18°C
The difference:
-18°C - 4°C = -22°CLaura purchased two puppies from a
litter. One of the puppies weighs 4 5/6 pounds.
.
and the other puppy weighs 5 1/2 pounds.
How much more does the second puppy
weigh than the first?
Answers
The first significant digit in any number must be 1, 2, 3, 4,5, 6, 7, 8, or 9. It was discovered that first digits do not occur with equal frequency. Probabilities of occurrence to the first digit in a number are shown in the accompanying table. The probability distribution is now known as Benford's Law. Forexample, the following distribution represents the first digits in 187 allegedly fraudulent checks written to a bogus company by an employee attempting to embezzle funds from his employer.
a.) Using the level of significance alpha 0.10, test whether the first digits in the allegedly fraudulent checks obeyBenford's Law. What is the null hypothesis?
b.) What is the alternative hypothesis?
c.) What is the test statistic?
d.) What is the p-value?
e.) Using the P-value approach, compare the P-value with the given alpha = 0.10, level of significance. Based on theresults, do the first digits obey the Benford's Law?
f.) (b) Based on the results of part (a),could one think that the employee is guilty of embezzlement?
Digit Probability Frequency
1 0.301 36
2 0.176 25
3 0.125 28
4 0.097 26
5 0.079 23
6 0.067 17
7 0.058 9
8 0.051 16
9 0.046 7
Answers
Answer:
We fail to reject the null hypothesis
Step-by-step explanation:
See the attachment for detailed calculations
A formula to find the frequency, f, of a cyclic phenomena based on the period, T, is
f = . Solve the formula for T' in terms of f.
Answers
Step-by-step explanation:
The frequency and the time period is related by the formula as follows :
[tex]f=\dfrac{1}{T}[/tex]
Here, f is frequency and T is time period
Now, we need to solve T in terms of f.
Firstly, cross multiplying the above equation,
[tex]f\times T=1[/tex]
Now dividing both sides by T.
[tex]\dfrac{f\times T}{T}=\dfrac{1}{T}\\\\f=\dfrac{1}{T}[/tex]
Hence, this is the required solution.
Answer:
T= 1/f
Step-by-step explanation:
T= one OVER f
Solve each equation. Check your solutions.
15. 27 - 31 = 29
Answers
Answer:
y=16, -13
Step-by-step explanation:
The absolute value operator makes all negative numbers positive. So y has two values in this equation: one where (2y-3)=29 and one where it =-29.
Work is in the attachment.
What is the area of this figure? 15 yd 4 yd 7 yd 25 yd 21 yd 22 yd square yards Submit
Answers
-170=5(8n+6)
Help please !!
Answers
Answer:
Step-by-step explanation:
40n + 30 = -170
40n + 30 = -170
40n = -200
n = -5
PLEASE SOMEONE HELP
I WILL GIVE 25 POINTS JUST PLEASE HELP
Answers
Answer:
50) 8, 16, 24, 32, 40, 48 (count by 8’s)
12, 24, 36, 48, 60, 72 (Count by 12’s)
Common Multiples: 24, 48
Least Common Multiple: 24
51) 7: 7, 14, 21, 28, 35, 42
11: 11, 22, 33, 44, 55, 66
Common Multiples: none
Least Common Multiple: none
52) 25: 25, 50, 75, 100, 125, 150
10: 10, 20, 30, 40, 50, 60
Common Multiples: 50
Least Common Multiple: 50
53) 24: 24, 48, 72, 96, 120, 144
36: 36, 72, 108, 144, 180, 216
Common Multiples: 72, 144
Least Common Multiple: 72
Step-by-step explanation:
50) 8, 16, 24, 32, 40, 48 (count by 8’s)
12, 24, 36, 48, 60, 72 (Count by 12’s)
Common Multiples: 24, 48
Least Common Multiple: 24
51) 7: 7, 14, 21, 28, 35, 42
11: 11, 22, 33, 44, 55, 66
Common Multiples: none
Least Common Multiple: none
52) 25: 25, 50, 75, 100, 125, 150
10: 10, 20, 30, 40, 50, 60
Common Multiples: 50
Least Common Multiple: 50
53) 24: 24, 48, 72, 96, 120, 144
36: 36, 72, 108, 144, 180, 216
Common Multiples: 72, 144
Least Common Multiple: 72