Make Q the subject of the formula A = Q2 - 2a.

Answer:

20000 kg

Step-by-step explanation:

Recall that 1 kg = 2.2 lb approximately.  Then:

22 tons        1 kg        2000 lb

------------ * ------------ * --------------  =  20000 kg

      1           2.2 lb          1 ton

Answer:

D) 9 cm

Step-by-step explanation:

EDGE 2020

(D) 9 cm.

Therefore, the correct answer is (D) 9 cm.

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Answer:

Graph 2

Step-by-step explanation:

The equation x = t² - 3 is represented by exponential growth, ( t² ) so it's graph will be similar to the first graph, graph 1, in our options. Then again we have to consider the equation y = √t - 2, which will be similar to graph 4, but with a greater slope. This leaves us with a solution of graph b.

Answer:

Step-by-step explanation:

Let us first generate the frequency table from the information given:

Hurricane number(X)       Frequency(f)                f(X)

6                                            9                                   54

8                                            13                                  104

12                                           16                                  192

14                                            12                                168

Total                                     ∑(f) = 50                          ∑f(x) =518

In order to determine the last frequency (the remaining years), we will add the other frequencies and subtract the answer from 50, which is the total frequency (50 years). This is done as follows:

Let the last frequency be f

9 + 3 + 16 + f = 50

38 + f = 50

f = 50 - 38 = 12

Now, calculating mean:

[tex]\bar {X} = \frac{\sum f(x)}{\sum(f)} \\\\\bar {X} = \frac{518}{50} \\\\\bar {X} = 10.36[/tex]

Therefore mean number of hurricanes = 10.4 (to one decimal place)

Answer:

Step-by-step explanation:

The diagrammatic expression to understand this question very well is attached in the image below.

By applying the law of cosine rule; we have:

From the diagram attached below, we need to determine the side "b" by using equation (2) from above:

b² = a² + c² - 2ac Cos B

From the information given:

a = 12 miles;  c = 18 miles;   ∠B = 38°

∴

replacing the values into the above equation:

b² = 12² + 18² - 2(12)(18) Cos (38°)

b² = 144 + 324 - 432 × (0.7880)

b² = 468 - 340.416

b² = 127.584

[tex]b = \sqrt{127.584}[/tex]

b = 11.30 miles

However, we are also being told that the speed from A → C = 6.8 mph

Thus, the time required to go from A → C  can be determined by using the relation:

[tex]\mathbf{speed = \dfrac{distance}{time}}[/tex]

making time the subject of the formula, we have:

[tex]\mathbf{time= \dfrac{distance}{speed }}[/tex]

[tex]\mathbf{time= \dfrac{11.30}{6.8}}[/tex]

time = 1.66 hours

By using the paved roads, the speed is given as = 22 mph

thus, the total distance covered = |AB| + |BC|

= (18+12) miles

= 30 miles

∴

[tex]\mathbf{time= \dfrac{distance}{speed }}[/tex]

[tex]\mathbf{time= \dfrac{30}{22}}[/tex]

time = 1.36 hours

Therefore, the time used off-road = 1.661 hours while the time used on the paved road is 1.36 hours.

Since we are considering the shortest time possible;

We can conclude that it would be faster for the bicyclist to ride from A to C on the paved roads since it takes a shorter time to reach its destination compared to the time used off-road.

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It would be faster for the bicyclist to ride from A to C on the paved roads since the time to go from A to C on the paved roads is 1.4 h and the time to go from A to C off-road is 1.7 h.        

To calculate which way would be faster we need to find the distance from point A to C with the law of cosines:

[tex] \overline{AC}^{2} = \overline{AB}^{2} + \overline{BC}^{2} - 2\overline{AB}\overline{BC}cos(38) [/tex]

Where:

[tex]\overline{AB}[/tex]: is the distance between the point A and B = 18 mi

[tex]\overline{BC}[/tex]: is the distance between the point B and C = 12 mi        

[tex] \overline{AC} = \sqrt{(18 mi)^{2} + (12 mi)^{2} - 2*18 mi*12 mi*cos(38)} = 11.3 mi [/tex]

Now, let's find the time for the two following cases.

1. From point A to C on the paved roads (t₁)

[tex] t_{1} = t_{AB} + t_{BC} [/tex]

The time can be calculated with the following equation:

[tex] t = \frac{d}{v} [/tex]    (1)

Where:

d: is the distance

v: is the velocity

Then, the total time that it takes the bicyclist to go from point A to C on the paved roads is:

[tex] t_{1} = t_{AB} + t_{BC} = \frac{18 mi}{22 mph} + \frac{12 mi}{22 mph} = 1.4 h = 84 min [/tex]

2. From point A to C off-road (t₂)

With equation (1) we can calculate the time to go from point A to C off-road:

[tex] t_{2} = \frac{\overline{AC}}{v_{2}} = \frac{11.3 mi}{6.8 mph} = 1.7 h = 102 min [/tex]

Therefore, it would be faster for the bicyclist to ride from A to C on the paved roads.  

To find more about the law of cosines, go here: https://brainly.com/question/15740431?referrer=searchResults  

I hope it helps you!                                  

Answer:

147

Step-by-step explanation:

The number is three times the other number

so 7 and 21

cause 7 x 3 = 21

finally check 21 x 7 = 147

Let

ATQ

[tex]\\ \sf \longmapsto Area=Length\times Width[/tex]

[tex]\\ \sf \longmapsto x(x+3)=28[/tex]

[tex]\\ \sf \longmapsto x^2+3x=28[/tex]

[tex]\\ \sf \longmapsto x^2+3x-28=0[/tex]

[tex]\\ \sf \longmapsto x^2+7x-4x-28=0[/tex]

[tex]\\ \sf \longmapsto x(x+7)-4(x+7)=0[/tex]

[tex]\\ \sf \longmapsto (x-4)(x+7)=0[/tex]

[tex]\\ \sf \longmapsto x=4\:or\:x=-7[/tex]

[tex]\\ \sf \longmapsto Width=4units[/tex]

[tex]\\ \sf \longmapsto Length=4+3=7units[/tex]

Answer:

yes, the volume = 16 ft^3

Hey there! I'm happy to help!

Here is our equation.

[tex]2y-3x=10[/tex]

Let's add 3x to both sides.

[tex]2y=3x+10[/tex]

Divide both sides by 2.

[tex]y=\frac{3}{2}x+5[/tex]

Here is slope intercept form.

[tex]y=mx+b\\m=slope\\b=y-intercept[/tex]

So, we can just find those two things in the equation, and here are our answers.

[tex]y=\frac{3}{2}x+5\\m=\frac{3}{2}\\b=5[/tex]

The graph is down below. If our y-intercept is 5, then one of our points is (0,5). You can then plug a random x-value into the formula to find another point and then draw the line going through the two points.

[tex]y=\frac{3}{2}(2)+5\\y=3+5\\y=8\\(2,8)[/tex]

Have a wonderful day and keep on learning! :D

hope it helps you

Answer:

116 miles

Step-by-step explanation:

We can solve this by first writing an equation for the cost of the car rental. To begin, the base cost is $17.95, so any further costs must be added to that. Next, the car costs 19 cents (0.19 dollars) for each mile driven, so for each mile, we add 19 cents. This can be written as 0.19 *x if x represents the amount of miles driven. Therefore, we can add the two input costs of the car (the base cost and cost per mile) to get

17.95 + 0.19 * x = total cost.

After that, we want to maximize x/the number of miles with only 40 dollars. We can do this by setting this equal to the total cost, as going over the total cost is impossible and going under would be limiting the amount of miles (this because we are adding money for each mile, so more money means more miles). Therefore, we have

17.95 + 0.19 * x = 40

subtract 17.95 from both sides to isolate the x and its coefficient

22.05 = 0.19 * x

divide both sides by 0.19 to isolate x

22.05/0.19 = x = 116.05

The question asked us to round down, and 116.05 rounded down is 116 for our answer

Answer: 3/8

Step-by-step explanation:

A=3

B=5

3/3+5=3/8

Answer:

Step-by-step explanation:

From the given information;

Let consider p to be the number of large buses and q to be the number of small buses.

The company has 18 large buses which can carry up to 30 students and 19 small buses which can carry up to 15 students.

The linear inequality represent the students with respect to the total students s:

30p + 15q   ≥  450   -----(1)

They are only 20 drivers available on the day of the field trip, therefore only 20 buses can be used. So,

p  +   q    ≤  20      ----- (2)

Also , There  are only 19 small buses and 18 large buses:

∴

0 ≤  p ≤ 18

0 ≤  q ≤ 19

The total cost of operating one large bus is $225 a day, and the total cost of operating one small bus is $100 per day

In order to minimize the cost of transporting all 450 students, let z be the minimal cost. i.e

z = 225p + 100q

From equation 1 and 2 ; if we plot them graphically on the graph, the following points of intersection were obtained as shown in the sketch below, in which the shaded region lies the answer.

The point of intersection between equation (1) and (2) is (p,q) = (10,10)

From the critical point in the sketch of our graph attached below, the following values of z can be determined.

Point(s)              Value for Z

(15,0)                 15 ×  225 = 3375

(18,0)                 18 ×  225 =  4050

(18,2)                 (18 × 225 )+ (2 × 100 ) = 4250

(10,10)                (10 × 225) + (10 × 100) = 3250

Thus ; the minimum cost of transporting all 450 students = $3250

Answer:

Step-by-step explanation:

Since m and k are the parallel lines and a transverse 'l' is intersecting these lines at two different points.

- Opposite angles at the point of intersection of parallel lines and the transverse will be the vertical angles.

∠1 ≅ ∠3, ∠2 ≅ ∠4, ∠5 ≅ ∠8 and ∠6 ≅ ∠7 [Vertical angles]

- Pair of angles between parallel lines 'k' and 'm' but on the opposite side of the transversal are the alternate interior angles.

∠4 ≅ ∠6 and ∠3 ≅ ∠5 [Alternate interior angles]

- Angles having the same relative positions at the point of intersection are the corresponding angles.

∠2 ≅ ∠6, ∠3 ≅ ∠8, ∠4 ≅ ∠7 and ∠1 ≅ ∠5 [Corresponding angles]

- Co interior angles are the angles between the parallel lines located on the same side of the transversal.

∠4 and ∠5, ∠3 and ∠6 [Co interior angles]

- Co exterior angles are the angles on the same side of the transverse but outside the parallel lines.

∠2 and ∠8, ∠1 and ∠7 [Co exterior angles]

Answer:

24 units²

Step-by-step explanation:

A rhombus is divided into 4 right triangles when it's two diagonals intersect at right angles. All the sides are of equal lengths.

Therefore, a simple method to use to find the area of the given rhombus is to calculate the area of one of the right triangles, and multiply by 4.

Area of right triangle = ½*base*height

Height = 3

Base = [tex]\sqrt{5^2 - 3^2} = \sqrt{16} = 4[/tex] (Pythagorean theorem)

Area of right triangle = ½*4*3 = 2*3 = 6 units²

Area of rhombus = 4(6 units²) = 24 units²

Answer:

Answer is below

Step-by-step explanation:

The width of the CI is directly proportional to critical value. When t* is greater than z value, the t value would then cause the margin of error to be larger and this will in turn cause the width of the confidence interval to be larger.

Greater t*df than z* gives us a bigger margin of error. This would in turn give bigger width of confidence interval. t distribution has greater width confidence interval compared to z distribution.

The width of confidence interval is a function of the margin of error. If the critical value of t(t*) is slightly larger than the critical value of z(z*), then the width of the confidence interval will be larger.

The margin of error is the product of the critical value and the standard error. Therefore, given the same standard error value, the value of the margin of error will increases based on the value of the critical value.

Since, t* is slightly larger than z*, then the confidence interval, t will be wider.

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Answer:

6.5

Step-by-step explanation:

The sum of all angles in a triangle are 180 degrees.

=> 10x -10 + 8x + 10x + 8 = 180

=> 28x -2 = 180

=> 28x = 182

=> x = 6.5

So, Angle A = 10 x 6.5 -10 = 65 - 10 = 55 degrees

     Angle B = 8 x 6.5 = 52 degrees

     Angle C = 10 x 6.5 + 8 = 65 + 8 = 73 degrees.

55 + 52 + 73 = 55 + 125 = 180 degrees

Answer: = a = 0.0206

b = 0.0205.

Step-by-step explanation:

From the question, given that;

Order Accurate         =  328     273    242     142

Order Not Accurate  =  32       54       37       20

Let us make the Total orders given be

T.O = 328+273+242+142+32+54+37+20 = 1128.

a) Let the Prob. that the first order is from restaurant D be

= Number of order from restaurant D / Total number of orders

= 162 / 1128 = 0.1436

Probability of the second order is 0.1436.

This is because, from the question we can tell that the selections are made with replacement, that means the order is the same.

So, the probability of getting 2 orders =

= 0.1436 * 0.1436 = 0.0206

NB: The probability of getting two orders from restaurant B is 0.0206.

This is because choosing the first order does not affect the second order

(independent events).

b) Assuming that the selections are made without replacement , the probability of getting both the orders from restaurant D =

This gives the Total Probability of getting both the orders from restaurant D, without replacement to be =  0.1436*0.1428

= 0.0205.

That is to say choosing the first order affects the second order because of the events are not independent as compared to the first question.

cheers i hope tis helps

Answer:

Shift the graph of y = x2 right 6 units.

hypotenuse goes to the line across from the right angle. adjacent is the bottom one. lastly opposite is the left one.

Step-by-step explanation:

Hi, there!!

According to the question, we should find the hypotenuse, adjacent, and opposite to the refrence angle A ,right.

so, let's simply work with it,

hypotenuse (h)= AC {side opposite to the 90° is always a hypotenuse}.

opposite (p)= BC { as the side opposite to the refrence angle is always perpendicular or opposite}

adjacent (b)= AB { as remaining side is always base or adjacent}

Hope it helps....

Answer:

The numbers:

-43    and     58

Step-by-step explanation:

a + b = 15

a = b - 101

then:

(b-101) + b = 15

2b = 15+101

2b = 116

b = 116/2

b = 58

a = b - 101

a = 58 - 101

a = -43

Check:

a + b = 15

-43 + 58 = 15

Answer:

See below

Step-by-step explanation:

we want to prove that A.M, G.M. and H.M between any two unequal positive numbers satisfy the following relations.

well, to do so let the two unequal positive numbers be [tex]\text{$x_1$ and $x_2$}[/tex] where:

the AM,GM and HM of [tex]x_1[/tex] and[tex] x_2[/tex] is given by the following table:

[tex]\begin{array}{ |c |c|c | } \hline AM& GM& HM\\ \hline \dfrac{x_{1} + x_{2}}{2} & \sqrt{x_{1} x_{2}} & \dfrac{2}{ \frac{1}{x_{1} } + \frac{1}{x_{2}} } \\ \hline\end{array}[/tex]

[tex] \displaystyle \rm AM \times HM = \frac{x_{1} + x_{2}}{2} \times \frac{2}{ \frac{1}{x_{1} } + \frac{1}{x_{2}} } [/tex]

simplify addition:

[tex] \displaystyle \frac{x_{1} + x_{2}}{2} \times \frac{2}{ \dfrac{x_{1} + x_{2}}{x_{1} x_{2}} } [/tex]

reduce fraction:

[tex] \displaystyle x_{1} + x_{2} \times \frac{1}{ \dfrac{x_{1} + x_{2}}{x_{1} x_{2}} } [/tex]

simplify complex fraction:

[tex] \displaystyle x_{1} + x_{2} \times \frac{x_{1} x_{2}}{x_{1} + x_{2}} [/tex]

reduce fraction:

[tex] \displaystyle x_{1} x_{2}[/tex]

rewrite:

[tex] \displaystyle (\sqrt{x_{1} x_{2}} {)}^{2} [/tex]

[tex] \displaystyle AM \times HM = (GM{)}^{2} [/tex]

hence, PROVEN

[tex] \displaystyle x_{1} > x_{2}[/tex]

square root both sides:

[tex] \displaystyle \sqrt{x_{1} }> \sqrt{ x_{2}}[/tex]

isolate right hand side expression to left hand side and change its sign:

[tex]\displaystyle\sqrt{x_{1} } - \sqrt{ x_{2}} > 0[/tex]

square both sides:

[tex]\displaystyle(\sqrt{x_{1} } - \sqrt{ x_{2}} {)}^{2} > 0[/tex]

expand using (a-b)²=a²-2ab+b²:

[tex]\displaystyle x_{1} -2\sqrt{x_{1} }\sqrt{ x_{2}} + x_{2} > 0[/tex]

move -2√x_1√x_2 to right hand side and change its sign:

[tex]\displaystyle x_{1} + x_{2} > 2 \sqrt{x_{1} } \sqrt{ x_{2}}[/tex]

divide both sides by 2:

[tex]\displaystyle \frac{x_{1} + x_{2}}{2} > \sqrt{x_{1} x_{2}}[/tex]

[tex]\displaystyle \boxed{ AM>GM}[/tex]

again,

[tex]\displaystyle \bigg( \frac{1}{\sqrt{x_{1} }} - \frac{1}{\sqrt{ x_{2}}} { \bigg)}^{2} > 0[/tex]

expand:

[tex]\displaystyle \frac{1}{x_{1}} - \frac{2}{\sqrt{x_{1} x_{2}} } + \frac{1}{x_{2} }> 0[/tex]

move the middle expression to right hand side and change its sign:

[tex]\displaystyle \frac{1}{x_{1}} + \frac{1}{x_{2} }> \frac{2}{\sqrt{x_{1} x_{2}} }[/tex]

[tex]\displaystyle \frac{\frac{1}{x_{1}} + \frac{1}{x_{2} }}{2}> \frac{1}{\sqrt{x_{1} x_{2}} }[/tex]

[tex]\displaystyle \rm \frac{1}{ HM} > \frac{1}{GM} [/tex]

cross multiplication:

[tex]\displaystyle \rm \boxed{ GM >HM}[/tex]

hence,

[tex]\displaystyle \rm A.M>G.M>H.M[/tex]

PROVEN

Answer:

There are 2000 pounds in a short ton. To convert short tons to pounds, multiply the ton value by 2000.

Answer:

5/100000 tons

Step-by-step explanation:

Answer:

1. a. tobt = -4.73

2. b. 9

3. a. +- 2.162

4. d. Reject H0; stress affects the menstrual cycle.

Step-by-step explanation:

The degrees of freedom is number of independent variable factors that affect the range of parameters. The degrees of freedom is the calculation of number values that are free to vary. The degrees of freedom is calculated by N-1. Standard error is the estimated deviation of standard deviation from its sample mean distribution. The null hypothesis is rejected or accepted on the basis of level of significance. When the p-value is greater than level of significance we fail to reject the null hypothesis and null hypothesis is then accepted.

Answer:

19 purses

Step-by-step explanation:

Set up an inequality where x represents the number of purses:

127 [tex]\geq[/tex] 7x

Solve for x by dividing each side by 7:

18.14 [tex]\geq[/tex] x

Round up to 19 because purses have to be whole

So, 19 purses have to be sold.

Answer:

the correct answer is 3 m............

Answer:

A consistent of equations has at least one solution,and an inconsistent system has no solution, watch an example of analyzing a system to see if its consistent or inconsistent.

Answer:  see below

Step-by-step explanation:

Consider the standard form of a linear equation in Slope-Intercept form:

        y = mx + b    where

A CONSISTENT system of equations is where the equations have different slopes OR the same slope and y-intercept.

This results in the lines crossing so they have at least one solution.

An INCONSISTENT system of equations is where the equations have the same slope but different y-intercepts.

This results in parallel lines so they have no solutions.

Answer:

too complex:<

Step-by-step explanation:

120cm+120cm=240cm (2 squirrels + 2 air spaces)

90cm+90cm=180cm (2 rats + 2 air spaces)

240cm-180cm=(2 squirrels + 2 air spaces) - (2 rats + 2 air spaces)

                       =2 squirrels + 2 air spaces - 2 rats - 2 air spaces

                       =2 squirrels - 2 rats

                       =60cm

1 squirrel - 1 rat = 60cm divided by 2

                         = 30cm

120cm + 90cm = squirrel + air space + rat + air space

                        = 210cm

I've no idea!! This qn is too challenging!!

But i hope the above workings might help you in a way or another:>

The table is 105cm tall.

Two or more expressions with an Equal sign is called as Equation.

Let the table is x

Squirrel is y

Rat is z

From 1st diagram

x+y-z=120...(1)

From 2nd diagram

x+z-y=90...(2)

Add 1 and 2

x+y-z+x+z-y=120+90

2x=210

Divide both sides by 2

x=105

Hence, the table is 105cm tall.

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Answer:

6(x-3)

Step-by-step explanation:

the common number for 6 and 18 is 6 so if you extract that from the expression then it turns to 6(x-3) which cannot be factored further

Answer:

Option B:  6(x - 3)

Step-by-step explanation: