Mary Ore and Tobi are to share 142naira such that Ore gets 11naira less than Mary and 7naira more than Tobi . How much is Tobi's share?

There are various charts which represents mathematical and statistical data with graphical representation.

The correct answer for the given question is ,

I - Chart

Since this chart is used to present data for continuous inspection.

The charts are used for representation of inspected data in to structure way which helps understand the changes easily.

I chart is usually used when there is continuous inspection for the data. This type of chart used to monitor the process when measuring data at regular intervals.

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Answer:

r = 11

Step-by-step explanation:

Hi there!

This scenario represents a linear relation, given the equation [tex]m=rp+k[/tex].

Linear equations are typically written in the form [tex]y=mx+b[/tex], where m is the slope and b is the y-intercept. As you can see, [tex]y=mx+b[/tex] and the given equation [tex]m=rp+k[/tex] share the same form.

This makes r the slope. This is also stated in the question, as r is the amount of money ($) paid per page.

The ordered pairs in the table represents points on a graph, if we were to graph this. For example, (9, 308) and (12, 341) both fall on the graph of this relation.

To solve for r, we must solve for the slope using the slope equation:

[tex]r=\displaystyle \frac{y_2-y_1}{x_2-x_1}[/tex] where two points are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex].

We can use any two points from the table in this equation. For example, (9, 308) and (12, 341):

[tex]r=\displaystyle \frac{341-308}{12-9}\\\\r=\displaystyle \frac{33}{3}\\\\r=11[/tex]

Therefore, the value of r is 11.

I hope this helps!

Answer:

The correct option is;

c. Number of science courses, discrete; time to complete homework, continuous

Step-by-step explanation:

There are two types of random variables, discrete random variables and continuous  random variables

Discrete random variables are variables that are always re-presentable by a finite countable number, such that discrete random variables can be taken as a count of items count

Therefore, as the number of science courses are fixed and such that a specific number can be ascribed to the courses at any time (except there are changes), is a discrete random variable

A continuous random variable is one whose possible values are infinite and are generally measurements of values of such as weight, height, time, and amount

Therefore, the time to complete the homework is a continuous random variable.

Answer:

Step-by-step explanation:

Given the expression (2 + i)(3 - i)(1 + 2i)(1 - i)(3 + i), we are to take the product of all the complex values. We must note that i² = -1.

Rearranging the expression [(3 - i)(3 + i)] [(2 + i)(1 - i)](1 + 2i)

On expansion

(3 - i)(3 + i)

=  9+3i-3i-i²

= 9-(-1)

= 9+1

(3 - i)(3 + i) = 10

For the expression (2 + i)(1 - i), we have;

(2 + i)(1 - i)

= 2-2i+i-i²

= 2-i+1

= 3-i

Multiplying 3-i with the last expression (1 + 2i)

(2 + i)(1 - i)(1 + 2i)

= (3-i)(1+2i)

= 3+6i-i-2i²

= 3+5i-2(-1)

= 3+5i+2

= 5+5i

Finally,  [(3 - i)(3 + i)] [(2 + i)(1 - i)(1 + 2i)]

= 10(5+5i)

= 50+50i

Hence,  (3 - i)(3 + i)(2 + i)(1 - i)(1 + 2i) is equivalent to 50+50i

Answer:

35⁰

Step-by-step explanation:

180-90-55=35⁰

there is a right angle

The angle sum property of a triangle:

The total measure of the three angles of a triangle is 180°

[tex]\rm\large\rightarrow \: \: x \: + \: 55 \degree \: + \: 90 \degree \: = \: 180 \degree[/tex]

[tex]\rm\large\rightarrow \: \: x \: + \: 145 \degree \: = \: 180 \degree[/tex]

[tex]\rm\large\rightarrow \: \: x \: = \: 180 \degree \: - \: \: 145 \degree [/tex]

[tex]\rm\large\rightarrow \: \: x \: = \: 35 \degree[/tex]

Answer:

Step-by-step explanation:

Answer:

A complex number bein scaled by a real number would NOT produce any "rotation" ... "C" should be the answer.

Step-by-step explanation:

Step-by-step explanation:

it's ur answers I hope it's helpful

Answer:

1

Step-by-step explanation:

[tex]cot^4x-cot^2x=1\\cot^4x=1+cot^2x\\cot^4x=cosec^2x\\ cos^4xsin^2x=sin^4x\\cos^4x=\frac{sin^4x}{sin^2x}\\cos^4x=sin^2x[/tex]------- (1)

Putting the value of [tex]cos^4x[/tex] in the equation:

[tex]cos^4x+cos^2x\\sin ^2x +cos^2x\\1[/tex]            (Using the identity [tex]cos^2x +sin^2x=1)[/tex]

Answer:

3×3×10^5×10^2

9×10^5-2

9×10³

Answer:

Y/X = 2/3 x^2 + 16/3

Y= 2/3 x^3 + 16/3 x

Just replace y with y/X and X with x^2

Answer:

Not a function fails the vertical line test

Step-by-step explanation:

This is not a function.  The value of x = -1  goes to two different values of y

This would fail the vertical line test

Answer:

the first one

Step-by-step explanation:

use the vertical line test. the horizontal line would intersect at two points.

Answer:

1/10 units ^3

Step-by-step explanation:

The formula for the volume is given by

V = Bh where B is the area of the base and h is the height

V = 3/20 units ^2 * 2/3 units

   = 3/20 * 2/3

  = 1/10 units ^3

Answer:

[tex]4x^2-21x-2[/tex]

Step-by-step explanation:

Given that:

Difference of two trinomials is [tex]x^2 - 10x + 2[/tex]

One of the two trinomials is  [tex]3x^2 - 11x - 4[/tex]

To find:

The other trinomial = ?

Four options are:

[tex]2x2 - x - 2 \\2x2 + x + 6 \\4x2 + 21x + 6\\ 4x2 - 21x - 2[/tex]

Solution:

Let the two trinomials be A and B.

Given A - B = [tex]x^2 - 10x + 2[/tex]

B = [tex]3x^2 - 11x - 4[/tex]

We have to find the other trinomial A.

A - B = [tex]x^2 - 10x + 2[/tex]

A - ([tex]3x^2 - 11x - 4[/tex]) = [tex]x^2 - 10x + 2[/tex]

[tex]\Rightarrow[/tex] A = [tex]x^2 - 10x + 2[/tex] + ([tex]3x^2 - 11x - 4[/tex])

[tex]\Rightarrow[/tex] A = [tex]4x^2-21x-2[/tex]

So, the correct answer is [tex]4x^2-21x-2[/tex].

Answer:

a) 148.52

Step-by-step explanation:

If sum of two angles is 180, then they are supplementary

Ratio = 10 : 47

Smaller angle = 10x

Larger angle = 47x

10x + 47x = 180

57x = 180

Divide  both sides by 57

x = 180/57

x = 3.16

Larger angle = 47x = 47 * 3.16 = 148.52

Answer:

Step-by-step explanation:

Since we are finding cos A we have

From the question

AC = √96

AB = 14

Substitute the values into the above formula

That's

We have the final answer as

Hope this helps you

Answer:

per second she was walking 14.54m roughly and driving is 32m per second therefore the average is 23.27m/s

Step-by-step explanation:

divide both sides by 55 to get one.

divide both sides by 25 to get one

THEN

to find the average you simply add them and divide by two which is 46.54 which divided by two is roughly 23.27.

And=2025 students gave 10125 rs

just divide it by 5hope it helps...pls mark me brainliest

Answer:

A. y = 3/7x

Step-by-step explanation:

Direct variation: y = kx

3 = 7k

k = 3/7

y = 3/7x

How long, to the nearest day, until it is safe to swim again will be 156 days

Let x represent number of day until it is safe to swim again

First step

=2000 *1/2^x

100=2000 *0.5^x

0.05=0.5^x

Second step

Log 0.05=xLog 0.5

Log 0.05/L0g 0.5=x

x=36 days* Log 0.05/L0g 0.5

x=36 days*43.22

x=156 days

Inconclusion How long, to the nearest day, until it is safe to swim again will be 156 days

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Answer:

a. 8.5 in.

b. 34 in

c. x = 1/39 x^2.

Step-by-step explanation:

Part a.

x = 1/34 y^2

y^2 = 34x

Comparing with y^2 = 4px where p is the focus:

4p = 34

p = 8.5 in.

Part b.

The diameter = 4p = 34 in.

Part c.

Diameter = 4p = 34 + 5 = 39 in

The new equation is x = 1/39 x^2.

Answer:

This is multiplicative identity in which 4✖️1=4

Step-by-step explanation:

Hope it will help you:)

Answer:

D. P(5+ 6's) = 0.4063

Step-by-step explanation:

Binomial distribution.

For the distribution to be applicable, the experiment must

1. Have a know and constant number of trials

2. Probability of success of each trial remains constant (and known if available)

3. Each trial is a Bernoulli trial, i.e. with only two outcomes, success or failure.

4. Independence between trials.

Let  

n = number of trials  = 25

p = probability of success of each trial  = 1 / 6

x = number of successes  (0 ≤ x ≤ n)  = 5

C(n,x) = number of combinations of picking x identical objects out of n

Applying binomial distribution

P(x,n) = probability of x successes in an experiment of n trials.

= C(n,x) * p^x * (1-p)^(n-x)

For n = 25 trials with probability of success (roll a 6) = 1/6

and x = 5,6,7,8,...25

It is easier to calculate the complement by

P(5+ 6's) = 1 - P(<5 6's)

= 1 - ( P(0,25) + P(1,25) + P(2,25) + P(3,25) + P(4,25) )

1- (

    P(0,25) = C(25,0) * (1/6)^0 * (5/6)^25 = 0.0104825960103961

    P(1,25) = C(25,1) * (1/6)^1 * (5/6)^24 = 0.05241298005198051

     P(2,25) = C(25,2) * (1/6)^2 * (5/6)^23 = 0.1257911521247532

    P(3,25) = C(25,3) * (1/6)^3 * (5/6)^22 = 0.1928797665912883

    P(4,25) = C(25,4) * (1/6)^4 * (5/6)^21 = 0.2121677432504171

)

= 1 - 0.59373

= 0.40626

= 0.4063 (to 4th decimal place)

Answer:

1) The region between the four lines x = 6, x = 1, y = 4 and y = 10 describing both equations is a rectangle

2) The joint equations of diagonals are;

5·y = 56 - 6·x and 5·y = 6·x + 14.

Step-by-step explanation:

The equations are;

x² - 7·x + 6 = 0......................(1)

y² - 14·y + 40 = 0.................(2)

Factorizing equation (1) and equation (2) , we get

x² - 7·x + 6 = (x - 6)·(x - 1) = 0

Which are vertical lines at points x = 6 and x = 1

For equation (2) , we get

y² - 14·y + 40 = (y - 10)·(y - 4) = 0

Which are horizontal lines at point y = 4 and y = 10

The region between the four lines x = 6, x = 1, y = 4 and y = 10 describing both equations is a rectangle

2) The points of intersection of the equations are;

(1, 4), (1, 10), (6, 4), and (6, 10)

The end point of the diagonals are;

(1, 10), (6, 4) and  (1, 4), (6, 10)

The slope of the diagonals are;

(10 - 4)/(1 - 6) = -6/5 and (4 - 10)/(1 - 6) = 6/5

The equation of one of the diagonals are then, y - 10 = -6/5×(x - 1)

y = -6/5·x + 6/5 + 10 = -6/5·x + 56/5

5·y = 56 - 6·x

The other diagonal is therefore;

y - 4 = 6/5×(x - 1)

y = 6/5·x - 6/5 + 4 = 6/5·x + 14/5

5·y = 6·x + 14.

The joint equations of diagonals are therefore;

5·y = 56 - 6·x and 5·y = 6·x + 14.

Answer:

Step-by-step explanation:

1) Diagonal bisect the angles of Rhombus

∠CAB = ∠CAD

∠CAB = 71

2) ∠DAB = ∠CAB + ∠CAD

 ∠DAB = 71 + 71 = 142

In Rhombus, adjacent angles are supplementary

∠DAB + ∠ABC = 180

142 + ∠ABC = 180

           ∠ABC = 180 - 142

         ∠ABC = 38

3)  In rhombus, opposite angles are congruent

∠ADC = ∠ABC

∠ABC = 38

In rhombus, diagonal bisect angles

∠BDC = (1/2)*∠ADC

∠BDC= 38/2

∠BDC = 19

4) Diagonals bisect each other at 90

∠DEC = 90

5) Diagonals bisect each other

BE = DE

BE + DE = DB

7x -2 +7x -2 =24   {add like terms}

        14x - 4 =24

              14x = 24+4

              14x = 28

                 x = 28/14

                 x = 2 m

6) AB = 13m

BE = 7x - 2 = 7*2 -2 = 14 -2 = 12 m

In right angle ΔAEB,  {use Pythagorean theorem}

AE² + BE² = AB²

AE² + 12² = 13²

AE² + 144 = 169

         AE² = 169 - 144

         AE² = 25

         AE = √25

        AE = 5 m

Diagonals bisect each other

AE = EC

AC = 2*5

AC = 10 m

7)Side = 13 m

Perimeter = 4*side

                  = 4*13

 Perimeter = 52 m

8) d1 = AC = 10 m

   d2 = DB = 24 m

Area = [tex]\frac{d_{1}*d_{2}}{2}[/tex]

         [tex]=\frac{10*24}{2}\\[/tex]

          = 10 *12

          = 120 m²

Answer:

[tex]35[/tex]

Step-by-step explanation:

One is given the following function ([tex]y=3x+5[/tex]). The given problem asks one to find the output of the function when the input is (10). Keep in mind, a general rule for dealing with functions is that, when present, the variable (x) represents the input. Whereas the variable (y) represents the output. Thus, if one were to substitute (10) in place of (x), and simplify: the result one would get is the output. Apply this idea to the given scenario:

[tex]y=3x+5[/tex]

[tex]y=3(10)+5[/tex]

[tex]y=30+5[/tex]

[tex]y=35[/tex]

Answer:

194.25meters

Step-by-step explanation:

The distance around the running track is calculated as:

Perimeter of the first semi circle + Perimeter of the second circle +50m + 50m

Semi circle has a length or diameter of = 30m

r = 30/2 = 15m

Perimeter of a circle = 2πr

Hence for a semi circle = 2πr/2 = πr

Perimeter of the first semi circle = π × 15

= 47.123889804m

Perimeter of the second semi circle is the same hence,

π × 15 = 47.123889804m

The distance around the running track

= 47.123889804m + 47.123889804m + 50m + 50m

= 194.24777961m

Approximately= 194.25meters.

Answer:

Points A, F, and G are three collinear points on line l.

Step-by-step explanation:

Answer:

Points A, F and G

Step-by-step explanation:

Answer:

[tex]-\frac{5}{2}[/tex]

Step-by-step explanation:

Step 1: Put this into an equation

[tex]-\frac{5}{3} - x = \frac{5}{6}[/tex]

Step 2: Solve for x

[tex]-x = \frac{5}{6} + \frac{5}{3}[/tex]

[tex]-x = \frac{5}{2}[/tex]

[tex]x =- \frac{5}{2}[/tex]

Therefore you need to subtract [tex]-\frac{5}{2}[/tex] from [tex]-\frac{5}{3}[/tex] to get [tex]\frac{5}{6}[/tex]

Answer:i don’t know

Step-by-step explanation:I’m sorry dude I have no idea I tried doing it in the browser and I could not find an answer sorry

Answer:

Does the answer help you?

[tex]\\ \sf\longmapsto Sin\Theta=\dfrac{P}{H}[/tex]

[tex]\\ \sf\longmapsto sin\Theta=\dfrac{49}{52}[/tex]

[tex]\\ \sf\longmapsto sin\Theta=0.94[/tex]

[tex]\\ \sf\longmapsto sin\Theta=sin71°[/tex]

[tex]\\ \sf\longmapsto \Theta=71°[/tex]

[tex]\\ \sf\longmapsto cos19°[/tex]

[tex]\\ \sf\longmapsto sin\Theta=0.9[/tex]

[tex]\\ \sf\longmapsto sin\Theta=sin70[/tex]

[tex]\\ \sf\longmapsto \Theta=70°[/tex]

[tex]\\ \sf\longmapsto cos20°[/tex]