m(t)=120e−0.018t
How much mass remains after 50 years? Round to 2 decimal places.

Answer:

The first 10 prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29.

Answer:

It is necesary to look for the least common denominator when one is trying to add or subtract rational expressions that do not have the same denominator

Step-by-step explanation:

The function g(x) is g(x)= (3x)^2

The complete question is in the image

From the graph in the image, we have:

f(x) = x^2

The function f(x) is stretched by a factor of 3 to form g(x).

This means that:

g(x) = f(3x)

So, we have:

g(x)= (3x)^2

Hence, the function g(x) is g(x)= (3x)^2

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Answer:

10 hours

Step-by-step explanation:

The rate x time of the first day + the rate x time of the second day equal the distance of 180 miles.

Let t = time

10t + 8t = 180

18t = 180

t = 10

Answer:

C. 0.12

Step-by-step explanation:

Let's use a sample number of 100

Out of 100 members, 50 are in the brass section

Out of those 50, 24% play the trombone. This means that 12 people total play the trombone.

12/100 is .12.. That is the final answer

Using the Fundamental Counting Theorem, it is found that:

The 2 people can arrange themselves in 40 ways.

It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

With one people in the aisle and one in the normal seats, the parameters are:

n1 = 4, n2 = 7

With both in the aisle, the parameters is:

n1 = 4, n2 = 3

Hence the number of ways is:

N = 4 x 7 + 4 x 3 = 28 + 12 = 40.

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Answer:

Step-by-step explanation:

Let the epicenter be E(x, y).

Use the distance formula for each given distance:

Use the first and third equations, considering both have same term for x, and solve for y:

Substitute y into one of equations and solve for x:

The epicenter is E( - 2, 3)

Answer:

(-2, 3)

Step-by-step explanation:

Given:

Model each given point as the center of a circle and the distance the epicenter is away from the point as the circle's radius.

The epicenter's location will be the point of intersection of the three circles.

Equation of a circle

[tex](x-a)^2+(y-b)^2=r^2[/tex]

where (a, b) is the center and r is the radius

Circle A

[tex]\implies (x+2)^2+(y-5)^2=4[/tex]

[tex]\implies x^2+4x+4+y^2-10y+25=4[/tex]

[tex]\implies x^2+4x+y^2-10y+25=0[/tex]

Circle B

[tex]\implies (x-2)^2+(y-3)^2=16[/tex]

[tex]\implies x^2-4x+4+y^2-6y+9=16[/tex]

[tex]\implies x^2-4x+y^2-6y-3=0[/tex]

Circle C

[tex]\implies (x+2)^2+(y+4)^2=49[/tex]

[tex]\implies x^2+4x+4+y^2+8y+16=49[/tex]

[tex]\implies x^2+4x+y^2+8y-29=0[/tex]

To find the point of intersection of the three circles, solve simultaneously.

Substitute equation B into equation A to eliminate x² and y²:

[tex]\implies x^2-4x+y^2-6y-3=x^2+4x+y^2-10y+25[/tex]

[tex]\implies -4x-6y-3=4x-10y+25[/tex]

Rearrange to isolate y:

[tex]\implies -6y-3=8x-10y+25[/tex]

[tex]\implies 4y-3=8x+25[/tex]

[tex]\implies 4y=8x+28[/tex]

[tex]\implies y=2x+7[/tex]

Substitute the expression for y into equation C and simplify:

[tex]\implies x^2+4x+(2x+7)^2+8(2x+7)-29=0[/tex]

[tex]\implies x^2+4x+4x^2+28x+49+16x+56-29=0[/tex]

[tex]\implies 5x^2+48x+76=0[/tex]

Substitute the expression for y into equation B and simplify:

[tex]\implies x^2-4x+(2x+7)^2-6(2x+7)-3=0[/tex]

[tex]\implies x^2-4x+4x^2+28x+49-12x-42-3=0[/tex]

[tex]\implies 5x^2+12x+4=0[/tex]

Equate the equations to eliminate 5x² and solve for x:

[tex]\implies 5x^2+48x+76=5x^2+12x+4[/tex]

[tex]\implies 48x+76=12x+4[/tex]

[tex]\implies 36x+76=4[/tex]

[tex]\implies 36x=-72[/tex]

[tex]\implies x=-2[/tex]

Substitute the found value of x into the found expression for y:

[tex]\implies y=2(-2)+7[/tex]

[tex]\implies y=-4+7[/tex]

[tex]\implies y=3[/tex]

Therefore, the point of intersection of the three circles if (-2, 3) and hence the location of the earthquake's epicenter is (-2, 3).

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The expression of v = (2,1,5) as a linear combination of (1,2,1), (1,0,2) and (1,1,0) is [tex](2,1,5)=1(1,2,1)+2(1,0,2)+-1(1,1,0)[/tex]

To express v= (2,1,5) as a linear combination of (1,2,1), (1,0,2) and (1,1,0), it will be written as:

[tex](2,1,5)=x(1,2,1)+y(1,0,2)+z(1,1,0)[/tex]

This will yield the following equations:

x + y + z = 2........(1)

2x + z = 1..........(2)

x + 2y = 5........(3)

The solution to the system of equations above is:

x = 1, y = 2, z = -1

Therefore, the linear combination is:

[tex](2,1,5)=1(1,2,1)+2(1,0,2)+-1(1,1,0)[/tex]

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answer: 200, 2 hundred, two hundred

The volume of the rectangular prism is of 28.6875 mm³.

The volume of rectangular prism of length l, width w and height h is given by:

V = lwh.

For this problem, the dimensions are:

Hence the volume is:

V = 2.125 x 6.75 x 2 = 28.6875 mm³.

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The solution to the problem when [tex]46.3[/tex] divided by [tex]1.5[/tex]  the result of the division is [tex]30.8666667[/tex] in decimal form.

When a large number is distributed into small numbers of equal parts is called division.

The number [tex]1.5[/tex] is not a factor of [tex]46.3[/tex] ,  on dividing them the remainder is not zero.

Therefore,  first convert [tex]1.5[/tex] it into a whole number by multiplying it  [tex]10[/tex] so it becomes [tex]15[/tex] .

Then convert [tex]46.3[/tex]  it into a whole number by multiplying it by [tex]10[/tex] so it becomes [tex]463[/tex]

Here,  [tex]\dfrac{463 \times 10}{15 \times 10}[/tex] which results in [tex]\dfrac{463}{15}[/tex].

Now, divide [tex]\dfrac{463}{15}[/tex] ,  the result will be [tex]30.8666667[/tex].

The solution to the problem when [tex]46.3[/tex] divided by  [tex]1.5[/tex] the result is [tex]30.8666667[/tex].

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Answer:

41.12 ft

Step-by-step explanation:

10 + 6 = 16

2 x pi x r = 25.12

16 + 25.12 = 41.12

Answer:

Step-by-step explanation:

find the outer perimeter of this figure

r = diameter : 2 = 8 : 2 = 4

2π4 =

8π=

8 × 3.14 = 25.12 ft

find figure perimeter

25.12 + 6 + 10 =

41.12 ft

Using derivatives, the equation of the tangent line is: y + 2= -(x + 2)

The equation is:

[tex]y - y_0 = m(x - x_0)[/tex]

In which m is the derivative at point [tex](x_0, y_0)[/tex].

The function is:

[tex]x^2 + y^2 = 8[/tex].

Applying implicit differentiation, the derivative is:

[tex]2x\frac{dx}{dx} + 2y\frac{dy}{dx} = 0[/tex]

[tex]2ym = -2x[/tex]

[tex]m = -\frac{x}{y}[/tex]

We have that x = y = -2, hence m = -1 and the equation is:

y + 2= -(x + 2)

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The test statistic based on the probability illustrated is -3.22.

Based on the information, the test statistic will be:

= (0.4 - 0.5)/[✓0.5(1 - 0.5)/260]

= -3.22

The p value using the distribution table is 0.0012.

The conclusion is to reject the null hypothesis as there's sufficient evidence to warrant rejection.

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Step-by-step explanation:

3 answer.....

......dkdkdk

The price the widgets should be sold for, to the nearest cent, for the company to make the maximum profit is 62.13

y = -14x² + 1035x - 10266

-14x² + 1035x - 10266 = 0

x = -b ± √b² - 4ac / 2a

= -1035 ± √1035² -4(-14)(-10266) / 2(-14)

= -1035 ± √1071225 - 574896 / -28

= -1035 ± √496329 / -28

x = 1035 / 28 ± √496329 / 28

x = 11.80 or 62.13

The maximum value of x is 62.13

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The maximum value of the objective function is 26 and the minimum is -10

The objective function is given as:

z=−3x+5y

The constraints are

x+y≥−2

3x−y≤2

x−y≥−4

Start by plotting the constraints on a graph (see attachment)

From the attached graph, the vertices of the feasible region are

(3, 7), (0, -2), (-3, 1)

Substitute these values in the objective function

So, we have

z= −3 * 3 + 5 * 7 = 26

z= −3 * 0 + 5 * -2 = -10

z= −3 * -3 + 5 * 1 =14

Using the above values, we have:

The maximum value of the objective function is 26 and the minimum is -10

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Answer:

A. True

Step-by-step explanation:

The ratio 1000 grams=1kilogram is correct.

Answer: 2.25 inches

Step-by-step explanation:

The radius of a circle is half the diameter.

Answer:

Multiply the top equation by -3 and the bottom equation by 2

Step-by-step explanation:

Given system of equations:

[tex]\begin{cases}4x-2y=7\\3x-3y=15 \end{cases}[/tex]

To solve the given system of equations by addition, make one of the variables in both equations sum to zero.  To do this, the chosen variable must have the same coefficient, but it should be negative in one equation and positive in the other, so that when the two equations are added together, the variable is eliminated.

To eliminate the variable y:

Multiply the top equation by -3 to make the coefficient of the y variable 6:

[tex]\implies -3(4x-2y=7) \implies -12x+6y=-21[/tex]

Multiply the bottom equation by 2 to make the coefficient of the y variable -6:

[tex]\implies 2(3x-3y=15) \implies 6x-6y=30[/tex]

Add the two equations together to eliminate y:

[tex]\begin{array}{l r r}& -12x+6y= &-21\\+ & 6x-6y= & 30\\\cline{1-3}& -6x\phantom{))))))} = & 9\end{array}[/tex]

Solve for x:

[tex]\implies -6x=9[/tex]

[tex]\implies x=-\dfrac{9}{6}=-\dfrac{3}{2}[/tex]

Substitute the found value of x into one of the equations and solve for y:

[tex]\implies 3\left(-\dfrac{3}{2}\right)-3y=15[/tex]

[tex]\implies -\dfrac{9}{2}-3y=15[/tex]

[tex]\implies -3y=\dfrac{39}{2}[/tex]

[tex]\implies y=-\dfrac{39}{2 \cdot 3}[/tex]

[tex]\implies y=-\dfrac{13}{2}[/tex]

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Answer:

they are the same line

Step-by-step explanation:

if you divide the first line by 2 you'll get:

2(3x)+2y=2(23)===> 3x+y=23

Answer: Choice B

[tex]2 = \log_{8}(64)[/tex]

======================================================

Explanation:

The original equation is [tex]8^2 = 64[/tex] with 8 as the base. That is also the base of the log when we get the final answer shown above. Logs are useful to isolate the exponent.

The general rule is that [tex]\text{y} = b^{\text{x}}[/tex] is equivalent to the log form of [tex]\text{x} = \log_{b}(\text{y})[/tex] where b is the base of each.

2 = log Subscript 64 Baseline 8 is the  logarithmic equation which is equivalent to 82 = 64.

Two or more expressions with an Equal sign is called as Equation.

A logarithmic equation is an equation that involves the logarithm of an expression containing a variable.

The logarithmic equation equivalent to 82 = 64 is:

2 = log Subscript 64 Baseline 8

This is because the logarithmic equation relates the base (64) to the result of the exponentiation (8), which in this case is 2.

Hence, 2 = log Subscript 64 Baseline 8 is the  logarithmic equation which is equivalent to 82 = 64.

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Answer: draw the line using a ruler on which you have identified points 2 7/16 inches apart

Step-by-step explanation:  On your ruler graduated in inches with marks at 1/16-inch intervals, locate the 0 mark and the mark 1/16 inch before the half-inch mark between 2 and 3 inches.Draw your line along the edge of the ruler between the two marks you have identified: 0 and 2 7/16. The line will be 2 7/16 inches

Step-by-step explanation:

b1) Any line parallel to the x-axis is horizontal. If we look at the graph of a horizontal line, we see that for any x-value you give, the y-value will be the same. In this case, the y-value is -1. Hence, the equation for the line is [tex]y=-1[/tex], as y will be -1 no matter the x.

The gradient for a horizontal line is 0, as the "rise" of the function is 0. If we use the formula [tex]\frac{rise}{run}[/tex], we would have 0 on the top, which makes the whole fraction 0.

b2) Any line parallel to the y-axis is vertical. If we look at the graph of a vertical line, we see that for any y-value, the x-value will be the same. In this case, the x-value is -1. Hence, the equation for the line is [tex]x=-1[/tex], as x will be -1 no matter the y.

The gradient for a vertical line is undefined, as the "run" of the function is 0. If we use the formula [tex]\frac{rise}{run}[/tex], we would be dividing by 0, which is undefined.

The solution of the equations y=[tex]x^{2}[/tex]-x-22 and y=x-7 is that x=-3,5 and y=-10,-2.

Given equations y=[tex]x^{2} -x-22[/tex], y=x-7.

We are required to solve these equations for the value of x and y.

Equation is relationship between two or more variables expressed in equal to form.Equations of two variables look like ax+by=c.It may be a linear equation, quadratic equation and cubic equations.

The given equations are:

y=[tex]x^{2}[/tex]-x-22-----------1

y=x-7----------------2

Put the value of y from second equation in first equation.

x-7=[tex]x^{2}[/tex]-x-22

Solving

[tex]x^{2}[/tex]-x-x-22+7=0

[tex]x^{2}[/tex]-2x-15=0

[tex]x^{2}[/tex]-5x+3x-15=0

x(x-5)+3(x-5)=0

(x+3)(x-5)=0

x=-3,5

Put the values of x=-3 and 5 one by one to get the two values of y in second equation.

y=x-7

x=-3

y=-3-7

=-10

x=5

y=5-7

=-2

Values of y are -10 and -2.

Hence the values of x are-3 and 5 and values of y are -10,-2.

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The data given illustrates that there's a constant ratio of 2 and y = 600(2)^x; 38400

The ratio based on the information given will be:

= 1200/600

= 2

Therefore, the constant ratio is 2.

In 6 years, the population will be:

= 600 × 2^6

= 600 × 64

= 38400

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Answer:

71.4% ( i think)

Step-by-step explanation:

If we translate 1 in 1.4 using what is described, it turns into (1/1.4)

Putting this into a calculator, we get 0.714286. Translated into a percent, that becomes 71.4286%

The probability that a member of the Senate (selected randomly) has a law degree is approximately 0.4167 or 41.67%.

When the odds are given as "1 in 1.4," it means that there is 1 chance of success (having a law degree) for every 1.4 chances of failure (not having a law degree).

To find the probability that a member of the Senate (selected randomly) has a law degree, you can use the formula:

Probability = 1 / (1 + Odds)

In this case, the odds are 1 in 1.4, so the probability is:

Probability = 1 / (1 + 1.4) ≈ 1 / 2.4 ≈ 0.4167

So, the probability that a member of the Senate (selected randomly) has a law degree is approximately 0.4167 or 41.67%.

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Answer:

x = 5

Step-by-step explanation:

Since the line is vertical,

the equation of the line then is x = (some value).

Since this particular line passes throught (5,-4), where the x coordinate is 5, we can deduce the equation of this line to be x = 5.