Nan lives 13 miles from the airport. Felipe lives 6 miles from the airport.
How many more miles does Nan live from the airport than Felipe?
​

9514 1404 393

Answer:

  38.1% decrease

Step-by-step explanation:

A percentage change is found from ...

  % change = (change)/(original amount) × 100%

  = (new value - original amount)/(original amount) × 100%

  = (13 -21)/21 × 100% = -8/21 × 100% ≈ -38.1%

Frazer's speed decreased by 38.1% during the second part.

_____

Additional comment

A negative % change represents a decrease; a positive % change represents an increase.

Answer:

Step-by-step explanation:

36°

Answer:

Left angle = 60°

Top angle = 120°

Right angle = 60°

Step-by-step explanation:

Use what you know about angle relationships to set up equations you can solve for each variable.

The top top angle, for example, added to one of the other angles must equal 180° because they are supplementary.

You have two variables, so you need at least two equations (I made three but only used two).

The work is in my attachment, comment of you have questions.

Answer:

plane

Step-by-step explanation:

The two-dimensional set of points that has no beginning or end is described by the undefined geometric term is plane.

Answer:

The sample correlation coefficient r = 0.9113

Step-by-step explanation:

In this question, we are interested in calculating the sample correlation coefficient.

From the question, we are given;

We are given that,

The sample standard deviation of stock X = 4.665

The sample standard deviation of stock Y = 8.427

The sample covariance = 35.826

Mathematically, the Pearson correlation coefficient "r", it is given as;

r = (co-variance of X and Y)/(standard deviation of X * Standard deviation of Y)

Inputing these values, we have;

r = (35.826)/(4.665 * 8.427) = 0.9113

Answer:

Step-by-step explanation:

Your answer would be 80% or a B

Answer:

"C"

Step-by-step explanation:

-B means the B is in the opposite direction

Answer:

Shawn is correct because two events are independent if the probability of both occurring is equal to the product of the probabilities of the two events.

Step-by-step explanation:

We are given that A represent going to the movies on Friday and let B represent going bowling on Friday night. The P(A) = 0.58 and the P(B) = 0.36. The P(A and B) = 94%.

Now, it is stated that the two events are independent only if the product of the probability of the happening of each event is equal to the probability of occurring of both events.

This means that the two events A and B are independent if;

P(A) [tex]\times[/tex] P(B) = P(A and B)

Here, P(A) = 0.58, P(B) = 0.36, and P(A and B) = 0.94

So, P(A) [tex]\times[/tex] P(B) [tex]\neq[/tex] P(A and B)

      0.58 [tex]\times[/tex] 0.36 [tex]\neq[/tex] 0.94

This shows that event a and event B are not independent.

So, the Shawn statement that both events are not independent because P(A)P(B) ≠ P(A and B) is correct.

Answer:

Shawn is correct

Step-by-step explanation:

Answer:

A. y + 2= x

Step-by-step explanation:

Which equation is represented by the graph shown in the image?

A. y + 2= x

B. y + 1= x

C. y - 1= x

D. y - 2= x

Please show ALL work! <3

The graph shown has a slope of +1 and a y intercept of -2.

All given answer choices have a slope of +1, so that's not the problem.

We need one that has a y-intercept of -2, or the equation should be

y = x-2, or equivalently y+2 = x

which corresponds to answer choice A.

Answer:  [tex]-\frac{\sqrt{2a}}{8a}[/tex]

=======================================================

Explanation:

The (x-a) in the denominator causes a problem if we tried to simply directly substitute in x = a. This is because we get a division by zero error.

The trick often used for problems like this is to rationalize the numerator as shown in the steps below.

[tex]\displaystyle \lim_{x\to a} \frac{\sqrt{3a-x}-\sqrt{x+a}}{4(x-a)}\\\\\\\lim_{x\to a} \frac{(\sqrt{3a-x}-\sqrt{x+a})(\sqrt{3a-x}+\sqrt{x+a})}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{(\sqrt{3a-x})^2-(\sqrt{x+a})^2}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{3a-x-(x+a)}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{3a-x-x-a}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\[/tex]

[tex]\displaystyle \lim_{x\to a} \frac{2a-2x}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{-2(-a+x)}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{-2(x-a)}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{-2}{4(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\[/tex]

At this point, the (x-a) in the denominator has been canceled out. We can now plug in x = a to see what happens

[tex]\displaystyle L = \lim_{x\to a} \frac{-2}{4(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\L = \frac{-2}{4(\sqrt{3a-a}+\sqrt{a+a})}\\\\\\L = \frac{-2}{4(\sqrt{2a}+\sqrt{2a})}\\\\\\L = \frac{-2}{4(2\sqrt{2a})}\\\\\\L = \frac{-2}{8\sqrt{2a}}\\\\\\L = \frac{-1}{4\sqrt{2a}}\\\\\\L = \frac{-1*\sqrt{2a}}{4\sqrt{2a}*\sqrt{2a}}\\\\\\L = \frac{-\sqrt{2a}}{4\sqrt{2a*2a}}\\\\\\L = \frac{-\sqrt{2a}}{4\sqrt{(2a)^2}}\\\\\\L = \frac{-\sqrt{2a}}{4*2a}\\\\\\L = -\frac{\sqrt{2a}}{8a}\\\\\\[/tex]

There's not much else to say from here since we don't know the value of 'a'. So we can stop here.

Therefore,

[tex]\displaystyle \lim_{x\to a} \frac{\sqrt{3a-x}-\sqrt{x+a}}{4(x-a)} = -\frac{\sqrt{2a}}{8a}\\\\\\[/tex]

Answer:

[tex]\large \boxed{\sf C. \ (n+1)^{n+1}+1}[/tex]

Step-by-step explanation:

[tex]n^n+1[/tex]

Plug in the value for n as n+1 in the nth term to find the (n+1)st term.

[tex](n+1)^{n+1}+1[/tex]

Answer:

[tex]\boxed{Option \ 3}[/tex]

Step-by-step explanation:

=> [tex]n^n+1[/tex]

Given that n = n+1

So,

=> [tex](n+1)^{n+1}+1[/tex]

Explanation:

The origin is the center of the grid. This is where the x and y axis meet. The location of this point is (0,0).

Start at the origin and move 5 places to the right. Note how the x coordinate is 5 which tells us how to move left/right. Positive x values mean we go right.

Then we go down 2 spots to arrive at point D. We move down because the y coordinate is negative.

You could also start at (0,0) and go down 2 first, then to the right 5 to also arrive at point D. Convention usually has x going first as (x,y) has x listed first.

Answer:

Point D is located at (5, -2)

Step-by-step explanation:

The coordinates are in the form of (x,y) so that means the point has the x value of 5 and the y value of -2

Answer:

It’s b. $192,727

Step-by-step explanation

i hope this help

can I get brainly

Answer: 1023.75 (a)

Step-by-step explanation:

The sequence is a Geometric progression with the common ratio of ¹/₂ and first term of 512.

a = 512, r = ¹/₂. To determine the ratio, just divide the second term by the first term.

Now to calculate the sum, we consider two formula here and select the one that is most appropriate,

(1)  a( rⁿ - 1 )/r - 1, when r is greater than 1

(2) a( 1 - rⁿ )/1 - rⁿ, when r is less than 1.

In this question, formula 2 shall be appropriate because r is less than 1.

so,

S₁₂      =  512( 1 - 0.5¹² )/1 - 0.5

             512( 1 - 2.44 ₓ 10⁻⁴ )/0.5

          = 512( 0,9998 )/0.5

          = 511.875/0.5

          = 1023.75

The answer is a

Answer:

B: -x^2 + 4

Step-by-step explanation:

If the equation was [tex]f(x)=x^2[/tex], then the vertex would be at 0, and the "U" would be facing straight up. Here, the "U" is upside down, so that means the "x^2" would have to be a negative number ([tex]-x^2[/tex]) to get the upside-down "U". Then, we could see that the vertex is at positive 4, so that means that the parabola moved up 4 units, so the equation should end in +4.

Our answer is:

B: -x^2 + 4

Answer:

[tex]\mathbf{P(x>6) = 0.0265}[/tex]

Step-by-step explanation:

Given that:

A baseball player has a batting average (probability of getting on base per time at bat) of 0.215

i.e

let x to be the random variable,

consider [tex]x_1 = \left \{ {{1} \atop {0}} \right.[/tex]  to be if the baseball player has a batting average or otherwise.

Then

p(x₁ = 1) = 0.125

What is the probability that they will get on base more than 6 of the next 15 at bats

So

[tex]\mathtt{x_i \sim Binomial (n,p)}[/tex]

where; n =  15 and p = 0.125

P(x>6) = P(x ≥ 7)

[tex]P(x>6) = \sum \limits ^{15}_{x=7} ( ^{15 }_x ) \ (0.215)^x \ (1 - 0.215)^{15-x}[/tex]

[tex]P(x>6) = 1 - \sum \limits ^{6}_{x=7} ( ^{15 }_x ) \ (0.215)^x \ (1 - 0.215)^{15-x}[/tex]

[tex]P(x>6) = 1 - \sum \limits ^{6}_{x=0} ( ^{15 }_x ) \ (0.215)^x \ (1 - 0.215)^{15-x}[/tex]

[tex]P(x>6) = 1 -0.9735[/tex]

[tex]\mathbf{P(x>6) = 0.0265}[/tex]

Answer:

See Explanation

Step-by-step explanation:

The options are not given; however, you can take a clue from my explanation to answer your question

Let x be a real number;

Additive identity property implies that; adding x to 0 or 0 to x gives x;

In other words;

[tex]x + 0 = x[/tex]

[tex]0 + x = x[/tex]

Note that x can be replaced with any real number; Take for instance

[tex]1 + 0 = 1[/tex]

[tex]0 + 2.5 = 2.5[/tex]

[tex]3 + 0 = 3[/tex]

There are uncountable number of examples;

However, take note that adding 0 to a given digit results in the exact digit and that's the implication of addition identity property

Answer:

(7+4i)+0=7+4i

Step-by-step explanation:

Answer:

Step-by-step explanation:

149 11/16" ÷ 12 = 12.4739583333333333... ft

We subtract off the whole number part and call it 12'

0.4739583333333333 × 12 = 5 11/16 "

149 11/16" = 12'  5 11/46"

120 7/8" ÷ 12 = 10.07291666666

We subtract off the whole number part and call it 10'

0.07291666666 × 12 = 7/8"

120 7/8" = 10'  7/8"

The third one is moot as 0 1/8" equals 0' 1/8"

I suspect your photo framing has cut off some important numbers.

Answer:

G=21, F=9, M=6, L=7, E=20, D=15, B=10, R=12.5, T=16, N=13.5, W=18, H=36, Z=12

*I=5*

Step-by-step explanation:

I basically just found the scale factor/proportion from two given sides and then used that to find the remaining sides.

*I'm not sure about 'I' since the edge of the paper was cut off so I want sure if it was a 5 or a 15 on the left most problem in the third row. I assumed it was 15. If it's not, just shout it out in the comments and I'll fix it! :)*

You can fill the letters in at the bottom XD

I hope this helped! :D

Answer:

  (B) Step 2

Step-by-step explanation:

In step 2, Raul should have had one of these results:

  8 -7 . . . . according to the order of operations

or

  3 -2 . . . . properly adding 5 -7

Raul's step 2 is not either of these (or 5-4), so is incorrect.

Answer:

step 2 i did it on khan yall

Step-by-step explanation:

Answer:

272 yd²

Step-by-step explanation:

Surface area = base area + lateral area

= (10×10)+(8.6×10×2)

= 100+172

= 272 yd²

Answer:

Balance at the age of 20 will be $1455966.46

Step-by-step explanation:

Formula to calculate the final amount is,

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

Where A = Final amount

P = Principal amount or amount invested

A = Final amount

r = Rate of interest

n = Number of compounding in a year

If Jason invested $200 in an account for 4 years with rate of interest 223%.

P = $200

r = 223%

n = 365

t = 4 years

A = [tex]200(1+\frac{2.23}{365})^{(4\times 365)}[/tex]

A = [tex]200(1.0061096)^{1460}[/tex]

A = $1455966.46

Therefore, balance amount in Jason's account at the age of 20 will be $1455966.46.

Answer:

(1,4) (2,4)(3,4)

Step-by-step explanation:

Answer:

The two missing sides are : 79.54m and 58.62m

Step-by-step explanation:

first we look for the missing angle in the triangle

so now we use sine rules:

Let us make:

so :

so the side facing 35° = 79.54m

To find the area of this triangle

Answer:

x = 1/e^-5 - 1

Step-by-step explanation:

–2 ln (x + 1) − 3 = 7

–2 ln (x + 1) = 10

ln (x + 1) = –5

x + 1 = e^-5

x = e^-5 - 1

x = 1/e^-5 - 1

the approximate value of x in the equation -2 ln(x + 1) - 3 = 7 is x ≈ -0.9933.

To solve the equation -2 ln(x + 1) - 3 = 7 for the approximate value of x, we will follow these steps:

1. Begin with the given equation: -2 ln(x + 1) - 3 = 7.

2. Move the constant term to the other side of the equation: -2 ln(x + 1) = 7 + 3.

3. Simplify: -2 ln(x + 1) = 10.

4. Divide both sides of the equation by -2 to isolate the natural logarithm term: ln(x + 1) = -5.

5. Rewrite the equation using the exponential form of natural logarithm: e⁻⁵ = x + 1.

6. Calculate the value of e⁻⁵: e⁻⁵ ≈ 0.0067.

7. Subtract 1 from both sides of the equation: x = 0.0067 - 1.

8. Simplify: x ≈ -0.9933.

Therefore, the approximate value of x in the equation -2 ln(x + 1) - 3 = 7 is x ≈ -0.9933.

Learn more about equation here

https://brainly.com/question/32549431

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Answer:

84 beads

Step-by-step explanation:

She had 98 beads and lost all but fourteen. So it would be 98 - 14 which would get you 84 beads that the girl has lost

Answer:

B. 36 square units

Step-by-step explanation:

This is a triangle and to calculate the area of a triangle we multiply height with base and that divided by two

The height of this triangle is 8 units and the base is 9 units

9 × 8 ÷ 2 = 36 square units

Answer:

24

Step-by-step explanation:

13/3 / 2/11 = 13/3 * 11/2 = 143/6 = 23 and 5/6

23 and 5/6 is closest to 24.

Answer:

23 5/6

Step-by-step explanation:

Answer:

0.8343

Step-by-step explanation:

From the question, we have the following values:

Probability of vehicles that pass within the check point that are from within the state = 75% = 0.75

Probability of vehicles that pass within the check point that are from outsode the state = 100 - 75 = 25% = 0.25

P = 0.25

n = number of random variables = 9

The probability that fewer than 4 of the next 9 vehicles are from out of state is calculated as:

P < 4 = P ≤ 3

n = 9

P(x) = n!/(n - x)! x! × p^x × q^(n - x)

x = 3

p = 0.25

q = 0.75

P(x) = 9! /(9 - 3)! × 3! × 0.25^3 × 0.75^(9 - 3)

P(x) =0.8343

The probability that fewer than 4 (x<4) of the next 9 vehicles are from out of state is 0.83427.

Given information:

75% of the vehicles passing through a checkpoint are from within the state.

So, the probability that the vehicle is from within the state is 0.75.

The probability that the vehicle is from outside the state will be 1-0.75=0.25.

Now, let x be the random variable. So, the value of n=9. and x<4

It is required to calculate the probability that fewer than 4 of the next 9 vehicles are from out of state.

So, [tex]x< 4[/tex], p=0.25 and q=0.75.

So, the required probability can be calculated as,

[tex]P(x\le3) =\sum ^nC_x\times p^x \times q^{(n - x)}\\P(x\le3)=\sum\dfrac{n!}{(n - x)! x!} \times p^x \times q^{(n - x)}\\P(x\le3)= \dfrac{9!}{(9 - 3)! 3!} \times 0.25^3 \times 0.75^{(9 - 3)}+\dfrac{9!}{(9 - 2)! 2!} \times 0.25^2 \times 0.75^{(9 - 2)}+\dfrac{9!}{(9 - 1)! 1!} \times 0.25^1 \times 0.75^{(9 - 1)}+\dfrac{9!}{(9 - 0)! 0!} \times 0.25^0 \times 0.75^{(9 - 0)}\\P(x\le3)=0.83427[/tex]

Therefore, the probability that fewer than 4 of the next 9 vehicles are from out of state is 0.83427.

For more details, refer to the link:

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