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Answer:

12

Step-by-step explanation:

Answer:

64°

.

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[tex]\underline{\underline{\large\bf{Solution:-}}}\\[/tex]

[tex]\longrightarrow[/tex]Since angle X and Y have a sum of 159

[tex]\implies \bf Y + X= 159 \_\_\_\_(1) [/tex]

[tex]\longrightarrow[/tex]Since X is 43 degrees smaller than Y , so subtracting X from Y would give 43 , therefore equation will be written as -

[tex]\implies \bf Y - X = 43 \_\_\_\_(2) [/tex]

Adding Equation (1) and (2)

[tex]\begin{gathered}\\\implies\quad \sf Y+X+Y-X = 159+43 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf Y+Y + X-X = 202 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf 2Y = 202 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf Y = \frac{202}{2} \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \boxed{\sf {Y = 101 }} \\\end{gathered} [/tex]

Putting Y in eq (1)

[tex]\begin{gathered}\\\implies\quad \sf X + 101 = 153 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf X = 153-101 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \boxed{\sf{ X = 52 }}\\\end{gathered} [/tex]

Given :

To Find :

Solution :

Area of the outer circle :

[tex]\: \qquad \dashrightarrow \sf{{ \pi \: \times {(490)}^{2} {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:490 \times 490 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{490} \times 490 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ {22} \times 70 \times 490 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \bf{{ \ 754600 \: {m}^{2}}} [/tex]

⠀

Area of the inner circle :

[tex]\: \qquad \dashrightarrow \sf{{ \pi \: \times {(210)}^{2} {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{7} \times \:210 \times 210 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ \dfrac{22}{ \cancel{7}} \times \cancel{210} \times 210 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \sf{{ \ {22} \times 30 \times 210 \: {m}^{2}}} [/tex]

[tex]\: \qquad \dashrightarrow \bf{{ \ 138600 \: {m}^{2}}} [/tex]

⠀

Therefore,

Area of the region inside the circular paths :

[tex]\: \qquad \dashrightarrow \sf{{ \ (754600 - 138600 ) \: {m}^{2}}}[/tex]

[tex]\: \qquad \dashrightarrow \bf{{ \ 616000 \: {m}^{2}}}[/tex]

Answer: 360000m

Step-by-step explanation:

Okay, so since we know that this train’s speed is 200km/h, let’s find the time difference between 12 24 and 14 12.

14 12 - 2hrs = 12 12

12 12 + 12min = 12 24

2hrs -12min = 1hr 48 min

1hr 48 min also equals to 1.8hrs in decimals. So:

200km x 1.8 = 360km

Now we have to find the answer in meters. Since 1km is equal to 1000m,

That means 360km equals 360000m.

Therefore 360000m is the answer

Answer

B. 500 pi

Step-by-step explanation:

Step-by-step explanation:

[tex]V = \frac{ER}{R + a} [/tex]

[tex]V(R+a)=ER[/tex]

[tex]VR + Va=ER[/tex]

[tex]Va= ER-VR[/tex]

[tex]Va=R(E-V)[/tex]

[tex]R = \frac{Va}{E-V} [/tex]

Answer:

4

Step-by-step explanation:

50 times; 40% A

2/5(50) = A

A = 20

Answer:

50 times; 40% A

2/5(50) = A

A = 20

Step-by-step explanation:

Answer:

262,576.28

Step-by-step explanation:

35,000(1+.065)^32

Answer:

A, C, E

Step-by-step explanation:

You would want to graph the points an if the line goes through them then that would be the answer

Answer:

-x + 5y = 15

Step-by-step explanation:

Hello! This question simply asks us to rearrange the equation.

So we have this:

y - 2 = 5(x + 5)

Okay, so we need to get an answer with integers for x and y, but no brackets. This means we can start by expanding them:

5y - 10 = x + 5

now, let's put y and x on the same side of the equation, and numbers on the other side:

5y - x = 5 + 10

5y - x = 15

we can put x first, but it's not necessary:

-x + 5y = 15

A = -1

B = 5

C = 15

And that's it!

I hope this makes sense :))

Answer:

5x - y = - 27

Step-by-step explanation:

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

given

y - 2 = 5(x + 5) ← distribute parenthesis

y - 2 = 5x + 25 ( add 2 to both sides )

y = 5x + 27 ( subtract 5x from both sides )

- 5x + y = 25 ( multiply through by - 1 )

5x - y = - 27 ← in standard form

2x - 5y = 1

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term -5y to the other side of equation.

[tex]\rm{2x - 5y = 1 }\\ [/tex]

[tex] \rm{2x - 5y + 5y = 1 + 5y}\\[/tex]

Subtract -5y from both sides of the equation

Simplify 2x - 5y + 5y = 1 + 5y

Cancel -5y with 5y

Reorder 1 + 5y so highest order terms are first

[tex] \rm{x = \frac{5y + 1}{2} } \\ [/tex]

Move factors not having X from the left side of equation 2x = 5y + 1

[tex] \rm{ \frac{2x}{2} = \frac{5y + 1}{2} } \\ [/tex]

Divide both sides of equation 2x = 5y + 1 by 2

Cancel 2 with 2

[tex] \rm{ \frac{\cancel{2}x}{\cancel{2}} = \frac{5y + 1}{2} } \\ [/tex]

[tex] \rm{x = \frac{5y + 1}{2} } \\ [/tex]

Therefore, the x of 2x - 5y = 1 is [tex] \rm{ \frac{5y + 1}{2} } [/tex]

2x - 5y = 1

[tex]\rm{-5y + 2x = 1}\\ [/tex]

Reorder 2x -5y so highest order terms are first

-5y = -2x + 1

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2x to the other side of equation -5y + 2x = 1

[tex]\rm{-5y + 2x - 2x = 1 - 2x}\\[/tex]

Subtract 2x from both sides of the equation

Simply - 5y + 2x -2x = 1 - 2x

Cancel 2x with -2x

Reorder 1 - 2x so highest order terms are first

[tex] \rm{y = - \frac{2x + 1}{5} }\\[/tex]

Move factors not having y from the left side of equation -5y = -2x + 1

[tex]\rm{ \frac{ - 5y}{ - 5} = \frac{ - 2x + 1}{ - 5} }\\ [/tex]

Divide both sides of equation -5y = -2x +1 by -5

Simplify [tex]\rm{ \frac{ - 5y}{ - 5} = \frac{ - 2x + 1}{ - 5} } [/tex]

Cancel 5 with -5

Resolve sign on fraction [tex] \rm{\frac{ - 2x + 1}{ - 5} }[/tex]

Therefore, the y of 2x-5y = 1 is [tex]\rm{\frac{ - 2x + 1}{ - 5} } [/tex]

3x + 2y = 11

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2:y to the other side of equation 3 x + 2y - 2y = 11 - 2y

Subtract 2y from the both sides of the equation

Simplify 3x + 2y - 2y = 11 - 2y

Cancel 2y with 2y

Reorder 11 - 2y so highest order terms are first

[tex] \rm{x = \frac{2y + 11}{3} } \\ [/tex]

Move the factors not having x from the left side of equation 3x = -2y +11

[tex] \rm{ \frac{3x}{3} = \frac{-2y + 11}{3} } \\ [/tex]

Divide both sides of equation 3x = 2y + 11 by 3

Cancel 3 with 3

[tex] \rm{ \frac{\cancel{3}x}{\cancel{3}} = \frac{-2y + 11}{3} } \\ [/tex]

[tex] \rm{x = \frac{2y + 11}{3} } \\ [/tex]

Therefore, the x for 3x + 2y = 11 is [tex] \rm{ \frac{2y + 11}{3} } [/tex]

2y + 3x = 11

Reorder 3x + 2y so highest order terms are first

[tex]\rm{2y + 3x = 11}\\[/tex]

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2:y to the other side of equation 2y + 3x = 11

[tex]\rm{2y + 3x - 3x = 11 - 3x}[/tex]

Subtract 3y from the both sides of the equation

Simplify 2y + 3x - 3x = 11 - 3x

Cancel 3x with - 3x

Reorder 11 - 3x so highest order terms are first

[tex] \rm{y= - \frac{3x + 11}{3} } \\ [/tex]

Move factors not having y from the left side of equation 2y = -3x + 11

[tex] \rm{ \frac{2y}{2} = \frac{-3x + 11}{3} } \\ [/tex]

Divide both sides of equation 2y = -3x + 11 by 2

Cancel 2 with 2

[tex] \rm{ \frac{\cancel{2}y}{\cancel{2}} = \frac{-3x + 11}{3} } \\ [/tex]

[tex] \rm{y = \frac{-3x + 11}{3} } \\ [/tex]

Therefore, the y for 2y + 3x = 11 is [tex] \rm{ \frac{-3x + 11}{3} } [/tex]

Solution (1):

Note that:

This means that...

Finding the value of x.

Solution (2):

Note that:

This means that...

Finding the value of x.

Answer:

Well my answer is high data set I took the test and got 100%

Step-by-step explanation:

Answer:

High

Step-by-step explanation: I took the test.

Answer: 6x² - 20x + 6

Step-by-step explanation:

x(6x - 2) -3(6x - 2)

= 6x² - 2x - 18x + 6

= 6x² - 20x + 6

Answer:

£24

Step-by-step explanation:

= 3/(7+3) × £80

= 3/10 × £80

= £24

Answer:

30ft2. (C.)

I did this question once.

Sorry for my Lack of explanation.-

Answer:

C

Step-by-step explanation:

Draw a line to make 2 separate shapes and find the area of each them then add the 2 areas together

18+12=30

Answer:

the answer for d question is 10

Considering that we have two samples, and the standard deviation for each sample, the correct test is given by:

iii. A two-sample -interval for a difference between population means.

Here, there are two samples, and we will investigate their difference. The information taken from the sample is expanded to the population, and since we have the standard deviation for each sample, a t-test is used, hence the correct option is given by:

iii. A two-sample -interval for a difference between population means.

More can be learned about hypothesis tests at https://brainly.com/question/26454209

Answer:

ANSWER (A.

Step-by-step explanation:

HOPE IT HELP'S !

Answer:

39 seats are empty

Step-by-step explanation:

60% of 65 is 39

Answer:

Step-by-step explanation:

Answer:

There are 801 box seats and 9612 regular seats.

explanation:

Let the number of box seats be x,

Then the regular seats is 12x

The sum of seats equals to 10,413

Solve:

12x + x ➙ 10,413

13x ➙ 10413

x ➙ 801

There are 801 box seats.

Find for regular seats:

➙ 12(x)

➙ 12(801)

➙ 9612

There are 9612 regular seats.

Answer:

2

Step-by-step explanation:

subtract 15 from 30 till u have 0 and count how many times u subtracted 15 from 30

Answer:

2

Step-by-step explanation:

30÷15=2

so 15 goes into 30 2times

Answer:

1.

Step-by-step explanation:

the slope can be calculated as

[tex]slope=\frac{y_2-y_1}{x_2-x_1};[/tex]

according to the formula above:

slope=(9-1)/(10-2)=1.