Contact injury happens when a person is holding an object that is directly hit or splashed by lightning.
To find answer, we need to know more about the lightning and injuries.
What are the injuries caused by lightning?The phenomenon of natural electrical discharge happens in a short time with a bright flash is called lightning.It carries a huge amount of energy.The injuries caused by lightning can be classified as Direct strikes, Side splash and the Contact injury.Direct injuries happens when a person directly hit by lightning.Side splash occurs when a current splashes from a nearby object.Contact injury happens when a person touching an object that is hit by lightning.Thus, we can conclude that, contact injury occurs when a person is holding an object that is directly hit or splashed by lightning.
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When someone is holding something that has been struck or splashed by lightning, contact damage occurs.
We need additional information concerning lightning and injuries in order to identify the solution.
What types of injuries are brought on by lightning?Lightning is the name for a natural electrical discharge that occurs quickly and with a dazzling flash.It has a tremendous amount of energy.Lightning-related injuries can be divided into three categories: direct strikes, side splashes, and contact injuries.When someone is struck by lightning directly, they can get direct injury.When a current splashes from a neighboring object, it is called a side splash.When someone touches a lightning-hit object, contact harm results.In light of this, we can say that contact injuries happen when a person is holding an object that has been struck by lightning or splashed by it.
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What should a driver do when he/she gets to a speed hump? a maintain current speed. b accelerate. c brake. d reduce speed to suggested limit.
It is usually best to reduce speed to suggested limit when a driver gets to a speed hump and is denoted as option D.
What is Deceleration?This refers to a situation in which the speed or acceleration of a body is reduced while in the other hand, acceleration refers to the condition in which a body increases its speed or acceleration.
Speed humps are structures which are placed in the road in other to slow vehicles to between 10 to 15 mph. They ensure over speeding is checked due to it being dangerous to other users.
Applying brake or maintaining current speed may lead to the vehicle being tilted towards the front end which may result in collision and other forms of accident.
This therefore the reason why reducing speed to suggested limit is the most appropriate choice.
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A marching band is practicing. The band director sees the drum major hit a drum. How far away is the director if he hears the drumbeat in 0.40 seconds
The director is 132 meters away from the marching band when the sound travels to him at 330 m/s.
The speed of sound is 330 m/s.
Time taken by sound to travel = 0.40 seconds
Speed = Distance/Time
The temperature of the air that the sound travels through affects the speed of the sound. Assuming an air temperature of 59 degrees Fahrenheit (15 degrees Celsius), the speed of sound at sea level on Earth is 761.2 mph (1,225 km/h).
The speed of sound is slowed down because gas molecules move more slowly at lower temperatures; sound travels more quickly through warmer air. As a result, higher in the atmosphere, where it is colder, the speed needed to break the sound barrier drops.
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What mass will accelerate at 3 m/s² when a net force of 150 N acts on it?
Answer:
[tex]\huge\boxed{\sf m = 50\ kg}[/tex]
Explanation:
Given data:Acceleration = a = 3 m/s²
Force = F = 150 N
Required:Mass = m = ?
Formula:F = ma
Solution:Put the givens in the formula
150 = m (3)
Divide 3 to both sides
150/3 = m
50 kg = m
m = 50 kg
[tex]\rule[225]{225}{2}[/tex]
A car generator turns at 400 rpm (revolutions per minute) when the engine is idling. It has a rectangular coil with 300 turns of dimensions 5.00 cm by 5.22 cm that rotates in an adjustable magnetic field. What is the field strength needed to produce a 24.0 V peak emf
The field strength needed to produce a 24.0 V peak emf is 0.73T.
To find the answer, we need to know about the expression of emf.
What's the expression of peak emf produced in a rotating rectangular loops?
The peak emf produced in a rotating loops= N×B×A×wN= no. of turns of the loop, B= magnetic field, A= area of loop and w= angular frequencySo, B = emf/(N×A×w)What's the magnetic field applied to the loop, when rectangular coil with 300 turns of dimensions 5.00 cm by 5.22 cm rotates at 400 rpm produce a 24.0 V peak emf?N= 300, A= 5cm × 5.22cm = 0.05m × 0.0522m = 0.00261 m²Emf= 24V, w= 2π×400 rpm= 2π×(400rps/60) = 42 rad/sNow, B= 24/(300×0.00261×42)B= 24/(300×0.00261×42) = 0.73T
Thus, we can conclude that the magnetic field is 0.73T.
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This simulation has three parts: Intro, Compare, & Mystery.I. Explore the Intro section of this simulation.1. Based on your exploration how will you define the density D, of a substance? Writedown an algebraic expression relating D to the mass and volume of a substance.2. Does the density of a substance change with its mass? If yes, how? If no, why not?
a) Density is mass of a unit volume of a material substance
b) Algebraic expression relating Density = m / v
c) Density is an intensive property, which means the density does not change as the amount of the substance present changes
a) Density is mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is the measurement of how tightly a material is packed together.
The more closely packed particles are, the more dense the object. The amount of mass in a particular space or volume. The more particles (or mass) in a given space, the more dense it is.
b) Algebraic expression relating Density = mass / volume or m/v
where d is density, M is mass, and V is volume.
c) Density (ρ) is the amount of mass (m) per unit volume (V) of a substance. Density is an intensive property, which means the density does not change as the amount of the substance present changes.
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A rear window defroster consists of a long, flat wire bonded to the inside surface of the window. When current passes through the wire, it heats up and melts ice and snow on the window. For one window the wire has a total length of 11.0 mm, a width of 1.8 mmmm, and a thickness of 0.11 mmmm. The wire is connected to the car's 12.0 VV battery and draws 7.5 AA.
2.6×10[tex]^-8[/tex] Ωm,A long, flat wire is used as a rear window defroster and is bonded to the window's interior surface.
Resistivity of the wire ?Electrical resistivity is a measurement of a material's degree of resistance to current flow. The SI unit for electrical resistivity is the ohm meter (m). It is frequently represented by the Greek letter rho. Materials that easily transmit current and have a low resistance are called conductors.
Length of the wire, l = 12.2 m
width of the wire, w = 1.8 mm
Thickness of the wire, T = 0.11 mm
Potential difference of the battery, v = 12 V
Current in battery, I = 7.5 A
Ohms law says, V = IR.
So that, R = V/I
R = 12/7.5 = 1.6 Ω
The Greek letter rho is frequently used to represent resistance, which is numerically equivalent to the resistance R of a wire-like specimen, multiplied by its cross-sectional area A, and divided by its length.
Resistivity if a material is:
ρ = RA/l
ρ = [1.6 × 1.8 × 10[tex]^-3[/tex] × 0.11×10[tex]^-3[/tex]] / 12.2
ρ = (3.168×10[tex]^-7[/tex]) / 12.2
ρ = 2.596×10[tex]^-8[/tex]
Therefore, the resistivity of the wire is 2.60×10[tex]^-8[/tex] Ωm
Resistivity of the wire is 2.60*10^-8 Ωm
Given:
Length of the wire, I = 12.2 m
width of the wire, w = 1.8 mm
thickness of the wire, T = 0.11 mm
Potential difference of the battery, v = 12
Current in the battery, I = 7.5 A
To Find:
Resistivity
Solution: A characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents.
Remember, Ohms law says, V = IR
So that, RV/I
R = 12/7.5= 1.6 Q
Resistivity if a material is
p = RA/I
p = [1.6 * 1.8*10^-3* 0.11*10^-3] / 12.2
p = (3.168*10^-7)/12.2
p = 2.596*10^-8
Therefore, the resistivity of the wire is 2.60*10^-8 Ωm
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g The resistance of the wire in the windings of an electric starter motor for an automobile is 2.40 10-2 . The motor is connected to a 13-V battery. What current will flow through the motor when it is stalled (does not turn)
If the resistance of the wire in the windings of an electric starter motor for an automobile is [tex]2.40\times 10^{-2}\text{ } \Omega[/tex] and the motor is connected to a 13-V battery then the amount of current flow through the motor is [tex]5.42 \times10^2\text{ A}[/tex].
Calculation:
Step-1:
It is given that the resistance of the wire in the windings of an electric starter motor for an automobile is [tex]2.40\times 10^{-2}\text{ } \Omega[/tex] and the motor is connected to a 13-V battery. It is required to find the amount of current flow through the motor.
It is known from Ohm's law, it is known that voltage is the multiplication of the current and the resistance of a circuit.
V=IR
Where V is the voltage, I is current, and R is the resistance.
Step-2:
Substituting the given values into the equation to get the value of the current.
[tex]$$\\\begin{aligned}\\V&=IR\\\Rightarrow13 \text{ V}&=I \times 2.40\times10^{-2} \text{ }\Omega\\\Rightarrow I&=\frac{13}{2.40\times10^{-2}} \text{ A}\\ &=5.42 \times10^2\text{ A}\\\end{aligned}\\$$[/tex]
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Two students measure the time constant of an RC circuit. The first student charges the capacitor using a 12 V battery, then lets the capacitor discharge the resistor. The second student repeats the experiment using a 5 V battery. Which student measures the longer time constant
Answer: Two students measure the time constant of an RC circuit. The first student charges the capacitor using a 12 V battery, then lets the capacitor discharge the resistor. The second student repeats the experiment using a 5 V battery. The student who charged the capacitor using 5V will measures the longer time constant.
Explanation: To find the correct answer, we need to know about the time constant of RC circuit.
What is the time constant of the RC circuit?The time constant of a RC circuit can be defined as, the time taken by the charge in the capacitor to grow or decay.It can be expressed as,[tex]T=CR[/tex]
How to solve the problem?We have T=CR, and we know that,[tex]C=Q/V[/tex]
Thus, the lesser voltage will have more C.when C increases, CR will increase.Thus, we can conclude that, the lesser voltage source will take longer time constant.
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Even with the best and largest telescopes, we can’t see all the stars in the milky way galaxy, even though these same telescopes can show us other galaxies. Why is that?
Because starlight cannot pass through black space, we are unable to view all of the stars in the Milky Way galaxy, even with the best and largest telescopes.
In the Milky Way galaxy, the Earth is situated. Part of it can be seen as a broad, opaque ring of stars and dust on a clear night (from sufficiently dark areas). We can see thousands of these stars with our unaided eyes, and a telescope can reveal many more.
However, a large number of the Milky Way's stars are obscured. The supermassive black hole at the centre of the galaxy and the bulge, which is made up of stars, gas, and dust, are to blame for this. The substance in this is opaque to all but the most powerful telescopes.
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A 7.55 × 1014 hz electromagnetic wave travels in carbon tetrachloride with a speed of 2.05 ×108 m/s. what is the wavelength of the wave in this material?
Answer:
2.72×10^-7
Explanation:
velocity = frequency × wavelength
2.05×10^8=7.55×10^14 wavelength
wavelength = 2.05×10^8/7.55×10^14
wavelength = 2.72×10^-7
When a car driving up a hill with constant speed: I. its kinetic energy is decreasing. II. its potential energy is constant. III. its total mechanical energy is constant. Group of answer choices II I III none of the above
A car driving up a hill at a constant speed experiences no change in its kinetic energy while it's potential energy increases with increasing height, thus none of the options are correct.
Understanding the concept
Consider a car moving up the hill at a constant speed as shown in the figure below. The following forces act on the car:
N is the normal reaction force acting in an upward directionf_s is the static friction force exerted due to friction between the road and the tires of the carf_k is the rolling friction force in the direction opposing that of the tiremg is the force acting in a downward direction.θ is the angle of inclination.Here as the car is moving up the hill at a constant speed, the net force exerted on the car is zero. Also, the kinetic energy of the car will not change as its velocity is constant and the potential energy will change with increasing height. Thus, none of the given options are correct.
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What information do we know about the known exoplanets? a. estimates of orbits and masses b. complete composition c. precise masses d. all of the above e. none of the above
The correct option is A. The information we know about the known exoplanets is estimates of orbits and masses.
What is exoplanets?An exoplanet or extrasolar planet is a planet outside the Solar System.
In other words, exoplanet is any planet beyond our solar system.
Characteristics of exoplanetsexoplanets are known for the following characteristics;
they are usually hotthey can orbit their stars so tightly that a “year” lasts only a few daysthey can orbit two suns at onceThus, the information we know about the known exoplanets is estimates of orbits and masses.
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how do you use atomic models
1234567891011121314151617181920
Work is best described as?
Answer:
Explanation:
In physics, work can be described as force multiplied by the displacement of the object (distance caused by the force acted on the object).
Work is a form of energy, therefore, it is measured in joules.
If Alex pushed on an object with 10N of force, and the object moved 2 meters, the work of Alex will be equal to:
W = Ft
W = 10N * 2m
W = 20 Joules
But, if we have John, that pushed on an object with 2N of force, but, since the object was way smaller, therefore it had way less inertia, the object moved a distance equal to 10 meters. Let's also calculate his work.
W = Ft
W = 2N * 10m
W = 20 Joules
And we got the same result.
Work can also be used to calculate power.
Power is equal to P = Work / time
It can also be written as P = delta Work / delta time
Power is measured in joules per second.
With power you can make the difference between someone that got a 2 kg object up in 2 second, and someone that got a 2 kg object up in 5 second.
The more powerful one would be the one who managed to make the same work in less time.
Hope it Helped!
Work is described as: the measure of energy transfer resulting from the application of force over a displacement.
What is Work?In the field of physics, work is most accurately defined as the outcome of multiplying the force exerted on an object by the distance the object is displaced in the same direction as the force.
This calculation serves to quantify the energy transferred to or from the object. For instance, if an individual applies a 50 Newton force to push a box across a 5-meter distance in the force's direction, the work done on the box would equal 250 Joules (50 N × 5 m).
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irius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Another bright star, Regulus , has a parallax of 0.042 arcseconds. What is its distance in parsecs
The actual distance of Regulus from Earth is 23.81 parsecs.
Given:
Parallax of Regulus, p = 0.042 arc seconds
Calculation:
When an observer changes their position, an apparent change in the object's position takes place. This change can be calculated using the angle ( or semi-angle) made by the observer and object i.e. the angle made between the two lines of observation from the object to the observer.
Thus from the relation of parallax of a celestial body we get:
S = 1/ tan p ≈ 1 / p
where S is the actual distance between the object and the observer
p is the parallax angle observed
Here for Regulus, we get:
S = 1 / p
= 1 / (0.042) [ 1 parsecs = 1 arcseconds ]
= 23.81 parsecs
We know that,
1 parsecs = 3.26 light-years = 206,000 AU
Converting the actual distance into light years we get:
23.81 parsecs = 23.81 × (3.26 light yrs) = 77.658 light-years
Therefore, the actual distance of Regulus from Earth is 23.81 parsecs which is 77.658 in light years.
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A solenoid 6.00 cm in diameter and 10.0 cm long has 750 turns and carries a current of 15.0 A. Calculate the magnetic flux through the circular cross-sectional area of the solenoid.
The magnetic flux through the circular cross-sectional area of the solenoid is 0.00066 Weber or (Tm²).
What is a solenoid?A wire tightly twisted in a lengthy, thin coil is a solenoid. Due to its design, the solenoid will have an electromagnet inside of it and a weak magnetic field surrounding it if we pass a current through it.
Equation of solenoid's magnetic field:
The simplest solenoid to describe is one with unlimited length. An infinite solenoid's magnetic field has a constant within and a precise zero value outside. If we can accept that the magnetic field near the ends will be different from what is calculated for just an infinite solenoid, the unlimited solenoid is frequently a rough estimate of an actual, finite-length solenoid.By utilizing the convolution operation as well as right hand rule, the magnetic field within a large solenoid is appropriately computed, but all of that can be condensed into:
B = (µ₀ × N × I )/ L
where
B = magnetic field (Tesla)
µ₀ = [tex]\pi[/tex]× 10^-7 (Tm/A ) is the vacuum permeability,
N = number of turns on solenoid,
I = electric current (Ampere)
L = length of the solenoid (m)
According to the question;
A diameter of solenoid 6.00 cm.
A radius of solenoid is 3 cm = 0.03m
Number of turns = 750
The length of solenoid is 10cm = 0.1m
Substitute all the values in equation to fine mangetic filed.
B = ([tex]\pi[/tex]×[tex]10^{-7}[/tex] × 750× 15 )/ 0.1
B = 0.035 Tesla
The formula for magnetic flux is
Ф = B×A
= B×([tex]\pi[/tex][tex]r^{2}[/tex])
= 0.035×[tex]\pi[/tex]×[tex].03^{2}[/tex]
Ф = 0.000099
Ф = 99×[tex]10^{-6}[/tex] Weber
Therefore, the magnetic flux through the circular cross-sectional area of the solenoid. is 99×[tex]10^{-6}[/tex] Weber.
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You're holding an open house for Brenda. Walt and Mary walk in and ask you for a flyer that gives details about the property. At this point, what's your relationship with Walt and Mary
Walt and Mary are my Customers at this point.
To construct proper client relationships you need to: greet clients and approach them in a way that is herbal and suits the character scenario. show customers that you recognize what their desires are. be given that a few humans may not want your merchandise and concentrate on constructing relationships with people who do.
Use the time period clients, with an apostrophe before the “s” to expose a possessive form for a single consumer. Use the time period clients', with an apostrophe after the “s” to show the possessive plural shape of a couple of patrons. Do now not use an apostrophe if there's no possessive indication needed.
The definition of a consumer is a person who buys services or products from a store, restaurant, or different retail vendor. An example of a patron is someone who is going to an electronics save and buys a tv. (Casual) a person, mainly one engaging in a few types of interaction with others.
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The weight of a hydraulic barber's chair with a client is 2000 N. When the barber steps on the input piston with a force of 40 N, the output plunger of a hydraulic system begins to lift the chair. Determine the ratio of the radius of the output plunger to the radius of the input piston.
Answer: The weight of a hydraulic barber's chair with a client is 2000 N. When the barber steps on the input piston with a force of 40 N, the output plunger of a hydraulic system begins to lift the chair. Then the ratio of the radius of the output plunger to the radius of the input piston will be 7.07.
Explanation: To find the answer, we have to know more about the Pascal's law and the hydraulic lift.
What is pascal's law and how it is used in case of hydraulic lift?The law states that, the pressure exerted at any point on an enclosed liquid is transmitted equally in all directions.A hydraulic lift consists of two cylinders connected to each other by pipe.If the force F1 applied on the smaller piston of area A1, the pressure exerted will be,[tex]P_1=\frac{F_1}{A_1}[/tex]
By pascal's law, the pressure transmitted to the large piston of large area A2 will be,[tex]P_2=\frac{F_2}{A_2}[/tex]
Then,[tex]\frac{F_2}{A_2} =\frac{F_1}{A_1}[/tex]
How to solve the problem?We have to find the ratio of the radius of the output plunger to the radius of the input piston.We have the equation for this as,[tex]\frac{A_{Plunger}}{A_{piston}} =\frac{F_{Plunger}}{F_{piston}}[/tex]
[tex]\frac{R_{Plunger}}{R_{piston}}=\sqrt{ \frac{F_{Plunger}}{F_{piston}}}=\sqrt{\frac{2000}{40} } =7.07[/tex]
Thus, we can conclude that, the ratio of the radius of the output plunger to the radius of the input piston will be 7.07.
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He wavelengths of the sounds produced by two horns are 6.0 m and 7.0 m, respectively. what beat frequency is heard when the horns are sounded on a day when the speed of sound is 340 m/s?
The beat frequency will be 8.1 Hz when the horns are sounded on a day when the speed of sound is 340 m/s
frequency = speed / wavelength
f1 = 340 / 6 = 56.67 Hz
f2 = 340 / 7 = 48.57 Hz
Beat frequency = fb = | f2 - f1 |
= | 48.57 - 56.67 |
= 8.1 Hz
The beat frequency will be 8.1 Hz when the horns are sounded on a day when the speed of sound is 340 m/s
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A 36.5-g glass thermometer reads 23.6 ∘C before it is placed in 145 mL of water. When the water and thermometer come to equilibrium, the thermometer reads 40.8 ∘C. Ignore the mass of fluid inside the glass thermometer. The value of specific heat for water is 4186 J/kg⋅C∘, and for glass is 840 J/kg⋅C∘.
The initial temperature of the water was [tex]41.6688^{0} C[/tex].
Given,
Weight of glass 36.5g
specific heat for glass is 840 J/kg⋅C∘.
Initial temperature of glass was [tex]23.6^{0} C[/tex].
Weight of water is 145*1=145g (Density*Volume=145ml*1g/ml)
Temperature final was [tex]40.8^{0} C[/tex].
specific heat for water is 4186 J/kgâ‹…Câˆ
(m of glass)(Cp of glass)(Tf_glass-Ti_glass) = (m of water)(Cp of water)(Ti_water - Tf_water)
36.5*840*(40.8-23.6)=145*4186*(Ti_water - 40.8)
Ti_water=[tex]41.6688^{0} C[/tex]
Specific heatIn thermodynamics, a material's specific heat capacity, or massic heat capacity as it is sometimes known, is equal to the heat capacity of a sample of the substance divided by the mass of the sample (symbol cp). Informally, it is the quantity of heat needed to raise a substance's temperature by one degree for every unit of mass that is added to it. joule per kelvin per kilogram, or Jkg1K1, is the SI unit for specific heat capacity. For instance, the amount of energy needed to increase the temperature of 1 kilogram of water by 1 K is 4184 joules, making water's specific heat capacity 4184 J kg 1 K 1.
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= Sem 2 CR-SS159VGSZE
nating a my ponnesis. I art
Since the investigative question has two variables, you
need to focus on each one separately. Thinking only
about the first part of the question, mass, what might be
a hypothesis that would illustrate the relationship
between mass and kinetic energy? Use the format of
"if...then...because..." when writing your hypothesis.
The relationship between mass and kinetic energy is K.E ∝ m and K.E ∝ v².
What is the relationship between mass and kinetic energy?The kinetic energy of an object exists as the energy that it maintains due to its motion. It is defined as the work required to accelerate a body of a disseminated mass from rest to its stated velocity. Having acquired this energy during its acceleration, the body preserves this kinetic energy unless its speed changes.
The kinetic energy is directly proportional to the mass and also directly proportional to the square of the velocity.If we increase the mass, then kinetic energy will also increase.But if we increase the velocity by n times , then the kinetic energy will increase by [tex]n^{2}[/tex] times.To know more about kinetic energy, refer:
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According to the superstring theories, gravitation has its own energy-sharing particles called _____, analogous to photons and electromagnetism.
Graviton
Graviton, postulated quantum that is thought to be the carrier of the gravitational field. It is analogous to the well-established photon of the electromagnetic field.
What is Superstring theories ?String theory states that everything in our Universe is made up of tiny vibrating strings. These strings are one dimensional objects and are identical to one another.
Every fundamental particle that we know such as electrons, quarks, photons, gluons, etc are made up of these strings.String theory has contributed a number of advances to mathematical physics, which have been applied to a variety of problems in black hole physics, early universe cosmologyLearn more about Superstring theories here:
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What is the strength of the electric field between two parallel conducting plates separated by 1.00 cm and having a potential difference (voltage) between them of 1.50×10^4v ?
The question is in the picture
Answer:
See below
Explanation:
Power = amps * volts = .27 * 12 = 3.24 watts
V= IR
R = V/I = 12/.27 = 44.44 ohms
Car A is traveling with a constant speed of 80 km>h due north, while car B is traveling with a constant speed of 100 km>h due east. Determine the velocity of car B relative to car A
Answer:
80J
Explanation:
K.E = ½ mv²
k.e = ½ * 80*
100²
ke= 4*20
ke= 80 J
Two boys with masses of 40 kg and 60 kg stand on a horizontal frictionless surface holding the ends of a light 10-m long rod. The boys pull themselves together along the rod. When they meet the 40-kg boy will have moved what distance?.
When they meet the 40-kg boy will have moved a distance of 6 m.
Displacement of the 40 kg boy
The displacement of the 40 kg boy is calculated from the principle of center mass.
X(40 kg) = (60 x 10 m + 40 x 0)/(40 kg + 60 kg)
X(40 kg) = (600)/(100) = 6 m
X(60 kg) = (60 x 0 + 40 x 10 m)/(40 kg + 60 kg)
X(60 kg) = (400)/(100) = 4 m
Thus, when they meet the 40-kg boy will have moved a distance of 6 m.
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A piece of copper of mass 150g at temperature of mass 70g containing 60g of water at temperature of 20°C. Ignoring heat losses, what would be the final steady temperature of the mixture? [Specific of heat capacity of copper = 4.0× 10²J/kg-1/K ^-1. Please any Physics student can help or if you have any idea, you can help me out. Thanks.✨✨
Answer:
The final temperature is [tex]29.6^oC[/tex].
Explanation:
When the two masses come in contact, one releases heat and the other absorbs it. The former can be modelled with the equation [tex]HeatLost = (Mass1 (kg))(c1)(T1-T)[/tex], and the latter by [tex]HeatGained=(Mass2(kg))(c2)(T-T2)[/tex]
m1=0.15 kg
m2=0.06 kg
T1 = 70 degrees Celsius = 343 K
T2 = 20 degrees Celsius = 293 K
T= Final temperature
c1 = Specific heat capacity of copper
c2 = Specific heat capacity of water
Because there is no heat lost into the surroundings, the heat removed from one substance is the same as the heat gained in the other. Therefore:
[tex](Mass1)(c1)(T1-T)=(Mass2)(c2)(T-T2)[/tex]
[tex](0.150)(400)(343-T)=(0.06)(4184)(T-293)[/tex]
[tex](60)(343-T)=(251.04)(T-293)[/tex]
[tex]20580-60T=251.04T-73554.72[/tex]
[tex]-311.04T=-94134.72[/tex]
[tex]T=302.6 K[/tex]
[tex]T=29.6^oC[/tex]
Hope this helps! (My apologies if the answer is wrong, it has been a while since I've done this)
Your best friend weighs 81.5 kg and is a rugby player. In one of his games, he slides to a stop in a phenomenal manner. The coefficient of kinetic friction between the player and the ground is 0.70. His speed at the start of the slide is 8.23 m/s. I a) Calculate his acceleration during the slide. b) How long (in time) does he slide until he stops?
A. The acceleration during the slide is 6.86 m/s²
B. The time taken to slide until he stops is 1.2 s
How to determine the force of frictionMass (m) = 81.5 KgCoefficient of friction (μ) = 0.7Acceleration due to gravity (g) = 9.8 m/s²Normal reaction (N) = mg = 81.5 × 9.8 = 798.7 NFrictional force (F) =?F = μN
F = 0.7 × 798.7
F = 559.09 N
A. How to determine the accelerationMass (m) = 81.5 KgFrictional force (F) = 559.09 NAcceleration (a) =?a = F / m
a = 559.09 / 81.5
a = 6.86 m/s²
B. How to determine the time Initial velocity (u) = 8.23 m/sFinal velocity (v) = 0 m/sDecceleration (a) = -6.86 m/s²Time (t) =?a = (v – u) / t
t = (v – u) / a
t = (0 – 8.23) / -6.86
t = 1.2 s
Learn more about acceleration:
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When hydrogen is fused into helium, energy is released from Choose one: A. the increase in pressure. B. the decrease in the gravitational field. C. conversion of mass to energy. D. gravitational collapse.
The nuclear fusion of hydrogen atoms releases a huge amount of energy. So the correct choice is C. Conversion of mass to energy.
What is nuclear fusion?
When two small nuclei join to form a new nucleus, then this process is termed nuclear fusion. A huge amount of energy is released when there occurs nuclear fusion between the two nuclei. And a new element is formed.
It has been observed that the amount of energy released in nuclear fusion is equal to the mass difference between the mass of the formed nucleus and the total mass of old nuclei. Hence in the nuclear fusion of hydrogen nuclei to form a helium nucleus, the energy is released due to the conversion of mass into energy.
The pressure is increased to make the hydrogen atoms fuse but this change in pressure does not contribute to the energy released in the fusion of hydrogen.
The magnitude of the gravitational field is too low and it does not contribute to the energy released in the fusion of hydrogen.
The gravitational collapse does not occur between the two hydrogen atoms. This phenomenon occurs in celestial bodies so this also does not contribute to the energy released in the fusion of hydrogen.
Learn more about nuclear fusion here:
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A ball of mass 4 kg is initially traveling at 2 m/s and has a 5 N force applied to it for 3 s. What is the final velocity of the ball?
A. 4 m/s
B. 12 m/s
C. 5.75 m/s
D. 3.25 m/s
Answer:
the answer to your question will be D
Explanation:
5 N* 3S =3.25