Olcquations
Week 5 Assignment: Mixture Problems and Systems of Equations
Due Sunday by 11:59pm
Points 10
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Solve interest applications using a system of equations
Question
Matthew invested $3,000 into two accounts. One account paid 3% interest and the other paid 8% interest. He earned 4%
interest on the total investment. How much money did he put in each account?
Sorry, that's incorrect. Try again?
3% amount: S 600
8% amount: S 2400
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Answers

Answer 1

Answer:

$600 at 8%$2400 at 3%

Step-by-step explanation:

You have the right numbers, but the wrong accounts.

__

Let x represent the amount invested at 8% (the highest rate). Then the total interest is ...

  .08x +.03(3000 -x) = .04(3000)

  .05x = .01(3000) . . . . subtract .03(3000)

  x = 3000/5 = 600

Matthew invested $600 at 8%, $2400 at 3%.

_____

Comment on checking your answer

You may notice that the overall interest rate is 4%, closer to 3% than to 8%. That means more of the money must be invested at 3% than at 8%.


Related Questions

look at the image for the question

Answers

Answer:

117.8

Step-by-step explanation:

surface area = πr²+πrl, where r = radius and l = slant height

so,

πr²+πrl

= π×3²+π×3×9.5

= 75π/2

= 117.8 (rounded to the nearest tenth)

Ughhh this is hard for me!

Answers

Answer:

(x+4)/3. When x is 5 the answer is 3

Step-by-step explanation:

Hãy tìm hàm gốc f(t) có hàm ảnh Laplace như dưới đây:
F(p)=6/p(2p^2+4p +10)

Answers

It looks like we're given the Laplace transform of f(t),

[tex]F(p) = L_p\left\{f(t)\right\} = \dfrac6{p(2p^2+4p+10)} = \dfrac3{p(p^2+2p+5)}[/tex]

Start by splitting up F(p) into partial fractions:

[tex]\dfrac3{p(p^2+2p+5)} = \dfrac ap + \dfrac{bp+c}{p^2+2p+5} \\\\ 3 = a(p^2+2p+5) + (bp+c)p \\\\ 3 = (a+b)p^2 + (2a+c)p + 5a \\\\ \implies \begin{cases}a+b=0 \\ 2a+c=0 \\ 5a=3\end{cases} \implies a=\dfrac35,b=-\dfrac35, c=-\dfrac65[/tex]

[tex]F(p) = \dfrac3{5p} - \dfrac{3p+6}{5(p^2+2p+5)}[/tex]

Complete the square in the denominator,

[tex]p^2+2p+5 = p^2+2p+1+4 = (p+1)^2+4[/tex]

and rewrite the numerator in terms of p + 1,

[tex]3p+6 = 3(p+1) + 3[/tex]

Then splitting up the second term gives

[tex]F(p) = \dfrac3{5p} - \dfrac{3(p+1)}{5((p+1)^2+4)} - \dfrac3{5((p+1)^2+4)}[/tex]

Now take the inverse transform:

[tex]L^{-1}_t\left\{F(p)\right\} = \dfrac35 L^{-1}_t\left\{\dfrac1p\right\} - \dfrac35 L^{-1}_t\left\{\dfrac{p+1}{(p+1)^2+2^2}\right\} - \dfrac3{5\times2} L^{-1}_t\left\{\dfrac2{(p+1)^2+2^2}\right\} \\\\ L^{-1}_t\left\{F(p)\right\} = \dfrac35 - \dfrac35 e^{-t} L^{-1}_t\left\{\dfrac p{p^2+2^2}\right\} - \dfrac3{10} e^{-t} L^{-1}_t\left\{\dfrac2{p^2+2^2}\right\} \\\\ \implies \boxed{f(t) = \dfrac35 - \dfrac35 e^{-t} \cos(2t) - \dfrac3{10} e^{-t} \sin(2t)}[/tex]

multiply 725base 9× 367base 9​

Answers

Answer:

Hello,

Answer 303028

Step-by-step explanation:

Multiplication in base 9

[tex]\begin{array}{cccccc}9^5&9^4&9^3&9^2&9^1&9^0\\--&--&--&--&--&--\\&&&7&2&5\\&&&3&6&7\\--&--&--&--&--&--\\&&5&5&8&8\\&4&7&6&3&\\2&3&7&6&&\\--&--&--&--&--&--\\3&0&3&0&2&8\end{array}[/tex]

What is the equation of the line that passes through the point (2, -1) and has a
slope of
3/2

Answers

Answer:

The answer is

[tex]y = \frac{3}{2} x - 4[/tex]

Step-by-step explanation:

To find the equation of the line using a point and slope we use the formula

y - y1 = m(x - x1)

where m is the slope

(x1 ,y1) is the given point

From the question

slope = 3/2

point = ( 2 , - 1)

Substitute these values into the above formula

That's

[tex]y + 1 = \frac{3}{2} (x - 2)[/tex]

[tex]y + 1 = \frac{3}{2} x - 3[/tex]

[tex]y = \frac{3}{2} x - 3 - 1[/tex]

We have the final answer as

[tex]y = \frac{3}{2} x - 4[/tex]

Hope this helps you

Answer:

y= 3/2x -4

Step-by-step explanation:

Since we are given a point and a slope, we can use the point-slope formula.

[tex]y-y_{1} = m(x-x_{1})[/tex]

where m is the slope and (x1, y1) is a point the line passes through.

We know the slope is 3/2 and the point we are given is (2, -1).

[tex]m=\frac{3}{2} \\\\x_{1} = 2\\\\y_{1} = -1[/tex]

Substitute the values into the formula.

[tex]y- -1 = \frac{3}{2} (x-2)[/tex]

[tex]y+1=\frac{3}{2} (x-2)[/tex]

We want to find the equation of line , which is y=mx+b ( m is the slope and b is the y-intercept). Therefore, we must get y by itself on the left side of the equation.

First, distribute the 3/2. Multiply each term inside the parentheses by 3/2.

[tex]y+1= (\frac{3}{2} * x) + (\frac{3}{2} *-2)[/tex]

[tex]y+1= \frac{3}{2}x + (\frac{3}{2} *-2)[/tex]

[tex]y+1=\frac{3}{2} x + -3[/tex]

[tex]y+1=\frac{3}{2} x -3[/tex]

Next, subtract 1 from both sides.

[tex]y+1-1=\frac{3}{2} x + -3 -1[/tex]

[tex]y=\frac{3}{2} x + -3 -1[/tex]

[tex]y=\frac{3}{2} x -4[/tex]

Now the line is in slope intercept form, therefore the equation of the line is y=3/2x -4. The slope of the line is 3/2 and the y-intercept is -4.

What is the scale factor of the dilation?
A. 2/5
B. 2/3
C. 3/2
D. 8/5

Answers

the answer is A. 2/5

Which of the following equations is of a parabola with a vertex at (1, 2)?
O y = (x - 1) 2 - 2
Oy= (x - 1)2 + 2
O y = (x + 1)2 - 2
O y = (x + 1)2 + 2

Answers

Answer:

the second option: (x-1)squared +2

Explanation:

The x value of the vertex can be found in the parenthesis after the x. However, you have to do the opposite value of it. So, since the paranthesis has (x-1) then that means that the vertex's x-value has to be 1.

For the y-value of the vertex, that can be found after the paranthesis. This value will not be used as the opposite like with the x-value. So, we know that in (x-1)^2 +2 the "+2" indicates the y-value to be 2.

Which polynomial can be factored using the binomial theorem?
64x2 + 200x + 625
64x2 + 400x + 625
14,641x4 - 11,979x3 + 9,801x2 – 8,019x + 6,561
14,641x4 - 23,958x3 + 19,602x2 – 16,038x + 6,561

Answers

Answer:

B

Step-by-step explanation:

64x2 + 400x + 625=(8x+25)^2

A data set lists earthquake depths. The summary statistics are
nequals=400400​,
x overbarxequals=6.866.86
​km,
sequals=4.374.37
km. Use a
0.010.01
significance level to test the claim of a seismologist that these earthquakes are from a population with a mean equal to
6.006.00.
Assume that a simple random sample has been selected. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim.
What are the null and alternative​ hypotheses?


A.
Upper H 0H0​:
muμequals=5.005.00
km
Upper H 1H1​:
muμnot equals≠5.005.00
km

B.
Upper H 0H0​:
muμnot equals≠5.005.00
km
Upper H 1H1​:
muμequals=5.005.00
km

C.
Upper H 0H0​:
muμequals=5.005.00
km
Upper H 1H1​:
muμgreater than>5.005.00
km

D.
Upper H 0H0​:
muμequals=5.005.00
km
Upper H 1H1​:
muμless than<5.005.00
km
Determine the test statistic.


​(Round to two decimal places as​ needed.)
Determine the​ P-value.


​(Round to three decimal places as​ needed.)
State the final conclusion that addresses the original claim.

Fail to reject

Upper H 0H0.
There is


evidence to conclude that the original claim that the mean of the population of earthquake depths is
5.005.00
km

Answers

Answer:

Step-by-step explanation:

The summary of the given statistics data include:

sample size n = 400

sample mean [tex]\overline x[/tex] = 6.86

standard deviation = 4.37

Level of significance ∝ = 0.01

Population Mean [tex]\mu[/tex] = 6.00

Assume that a simple random sample has been selected. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim.

To start with the hypothesis;

The null and the alternative hypothesis can be computed as :

[tex]H_o: \mu = 6.00 \\ \\ H_1 : \mu \neq 6.00[/tex]

The test statistics for this two tailed test can be computed as:

[tex]z= \dfrac{\overline x - \mu}{\dfrac{\sigma}{\sqrt {n}}}[/tex]

[tex]z= \dfrac{6.86 - 6.00}{\dfrac{4.37}{\sqrt {400}}}[/tex]

[tex]z= \dfrac{0.86}{\dfrac{4.37}{20}}[/tex]

z = 3.936

degree of freedom = n - 1

degree of freedom = 400 - 1

degree of freedom = 399

At the level of significance ∝ = 0.01

P -value = 2 × (z < 3.936)  since it is a two tailed test

P -value = 2 × ( 1  - P(z ≤ 3.936)

P -value = 2 × ( 1  -0.9999)

P -value = 2 × ( 0.0001)

P -value =  0.0002

Since the P-value is less than level of significance , we reject [tex]H_o[/tex] at level of significance 0.01

Conclusion: There is sufficient evidence to conclude that the original claim that the mean of the population of earthquake depths is  5.00 km.

Find the sum of the first 10 terms of the following geometric sequences: 3,6,12,24,48

Answers

Answer:

3,069

Step-by-step explanation:

The sequence is doubling, so terms 1 through 10 are:

3, 6, 12, 24, 48, 96, 192, 384, 768, 1,536

3 + 6 + 12 + 24 + 48 + 96 + 192 + 384 + 768 + 1,536 = 3,069

(-t^3+5t^2-6t)+(8t^2-8t)

Answers

Answer:

-t^3+13t^2-14t

Step-by-step explanation:

(-t^3+5t^2-6t)+(8t^2-8t)

Combine like terms

-t^3+5t^2+8t^2-6t-8t

-t^3+13t^2-14t

what is the area and perimeter of the figure below?

Answers

Answer:

the perimeter is : 40

the area is: 10,000

Use the set of ordered pairs to determine whether the relation is a one-to-one function. {(−6,21),(−23,21),(−12,9),(−24,−10),(−2,22),(−22,−22)}

Answers

Answer:

the relation is not one-to-one.

Step-by-step explanation:

it can't because every number is in the 4th quadrant.  

Identify the vertex of the function f(x) = |x-^1/2|-2

Answers

the negative will shift the graph right, so x = 1/2

the negative 2 will shift the graph down, so y = -2

Thus, the vertex is (1/2, -2)

01:15:51 Differential equation of the family of circles touching the y-axis at origin is

Answers

Step-by-step explanation:

Correct option is

B

x

2

−y

2

+2xy

dx

dy

=0

The system of circles touching Y axis at origin will have centres on X axis. Let (a,0) be the centre of a circle. Then the radius of the circle should be a units, since the circle should touch Y axis at origin.

Equation of a circle with centre at (a,0) and radius a

(x─a)²+(y─0)²=a²

That is,

x²+y²─2ax=0 ─────► (1)

The above equation represents the family of circles touching Y axis at origin. Here 'a' is an arbitrary constant.

In order to find the differential equation of system of circles touching Y axis at origin, eliminate the the arbitrary constant from equation(1)

Differentiating equation(1) with respect to x,

2x+2ydy/dx─2a=0

or

2a=2(x+ydy/dx)

Replacing '2a' of equation(1) with the above expression, you get

x²+y²─2(x+ydy/dx)(x)=0

That is,

─x²+y²─2xydy/dx=0

or

x²─y²+2xydy/dx=0

If two events are mutually exclusive, can they occur concurrently? Explain. Yes. By definition, mutually exclusive events can occur together. No. By definition, mutually exclusive events cannot occur together. No. Two events will never occur concurrently. Yes. Any two events can occur concurrently.

Answers

Answer:

No. By definition, mutually exclusive events cannot occur together.

Step-by-step explanation:

If two events are mutually exclusive, can they not occur concurrently because by definition, mutually exclusive events cannot occur together or at the same time. This ultimately implies that the events or outcome of the sampling is disjointed.

Mathematically, if two events A and B are mutually exclusive;

[tex]P(AnB) = 0[/tex]

From the above expression, we can deduce that the probability of the two (2) events occurring or having an intersection is zero (0).

[tex]P(A or B) = P(A) + P(B)[/tex]

From the above expression, we can deduce that the probability of either of the two (2) events occuring is the sum of the probability of each occurrence.

For example, when a fair die is tossed once, the outcomes are mutually exclusive.

P(d) = 1, 2, 3, 4, 5 and 6.

Other examples include;

1. Tossing a coin once, you'll either get a head or a tail but not a head and a tail at the same time.

2. In cards, both a king and an ace or a king and a queen are mutually exclusive because you can't have both occurring at the same time.

hello help Plis……..

Answers

Answer:

1.)149800

2.)75.9820

3.)49990

4.)29.900

A study of the effect of television commercials on 12-year-old children measured their attention span, in seconds.
Clothes Food Toys
27 44 61
22 49 64
46 37 57
35 56 48
28 47 63
31 42 53
17 34 48
31 43 58
20 57 47
47 51
44 51
54
1. Find the values of mean and standard deviation.
2. Is there a difference in mean attention span of the children for various commercials?
3. Are there significance differences between pair of means?

Answers

Answer: Find answers in the attachment files

Step-by-step explanation:

(4 points) Determine whether each of these functions is O(x 2 ). Proof is not required but it may be good to try to justify it (a) 100x + 1000 (b) 100x 2 + 1000 (c) x 3 100 − 1000x 2 (d) x log x (2) (2 points) U

Answers

Answer:

(a) O(x²)

(b) O(x²)

(c) O(x²)

(d) Not O(x²)

Step-by-step explanation:

If a function is O(x²), then the highest power of x in the function ia greater or equal to 2.

(a) 100x + 1000

This is O(x), not O(x²)

(b) 100x² + 1000

This is O(x²)

(c) x³.100 − 1000x²

This is O(x²)

(d) x log x²

This is not O(x²)

AC is included between __________

Answers

Answer:

AC is included between <A and <C.

Step-by-step explanation:

i think, not sure tho

Find the value of x.
A. 22
B. 7.3
C. 3.6
D. 5.5

Answers

Answer:

x= 5.5

Step-by-step explanation:

(segment piece) x (segment piece) =    (segment piece) x (segment piece)

x*4 = 11*2

4x = 22

Divide each side by 4

4x/4 = 22/4

x =5.5

(4.8 × 10⁷) + 6,500,000

Answers

Answer:

5.45 * 10^7

Step-by-step explanation:

[tex](4.8 * 10^7) +6,500,000[/tex]

= [tex](4.8 * 10^7) + 6.5 * 10^6[/tex]

= [tex](4.8 * 10^7) + (0.65 * 10^7)[/tex]

= [tex]5.45 * 10 ^7[/tex]

Write the ratio 4 L : 5.6 L as a fraction in the simplest form with whole numbers in the numerator and denominator

Answers

Answer:

Step-by-step explanation:

It's 5/7

You get that by having a calculator that does that. If you don't then the way to do it is multiply the numerator and denominator by 1.25

4 * 1.25 = 5

5.6 * 1.25 = 7

What is the solution to the following system of equations? 3x-2y=12 6x - 4y = 24

Answers

Answer:

D question,somewhat confusing, itsit's like simultaneous equation,but values are different

Answer:

x = 4 + 2y/3

Step-by-step explanation:

How many g of amino acids are in a 2,000mL total parenteral nutrition of 4.25% travesol (amino acids and 20%dextrose?

Answers

Answer:

The  mass of  amino acid present is  85 g

Step-by-step explanation:

From the question we are told that

   The  volume of the total  parenteral nutrition is  [tex]V = 2000 mL[/tex]

   

Generally the volume of the amino acid present is  

                [tex]V_a = 0.0425 * 2000[/tex]

                [tex]V_a = 85 mL[/tex]

Generally  

               [tex]mass \ \ \alpha \ \ volume[/tex]

So the mass of amino acid present is 85g

How many skirt-blouse outfits can a woman choose from if she has 5 skirts and 6 blouses?

Answers


She can have 30 different outfits/combinations

How many two-digit numbers are there which are multiples of both 2 and 7?


Answers

2 digits number = 10-99

Lets find the multiples of 2 and 7 both

Which are = 14, 28,42,56,70,84,98

Therefore there are 7 two digit multiples of both 2 and 7

Must click thanks and mark brainliest

9514 1404 393

Answer:

  7

Step-by-step explanation:

Those numbers are 14, 28, 42, 56, 70, 84, 98. There are 7 numbers that are multiples of 2 and 7 (multiples of 14).

Find the distance between the pair of points.
(-6/11, -3)
and (-6/11, 2/3)
The distance between the pair of points is
Type an integer or a simplified fraction.)

Answers

Answer:

3 2/3

Step-by-step explanation:

The x value is the same for both points. So we're only trying to figure out the difference in the y values. One y value is three steps down from zero and one y value is 2/3 of a step up from zero. So the total vertical distance between the two points is 3 and 2/3.

Find the 84th term of an arithmetic sequence if the first term and common
difference are given as:
ai = 3; d = -4
ag4 =
I
Next
Previous

Answers

Answer:

-329

Step-by-step explanation:

1st term a1 = 3, common difference d = -4

84th term,

3+(84-1)(-4)

= -329

Gail paid a total of $12,000 for stock that was $6 per share. If she sold all her shares for $18,000, how much profit on each share did she make?
A
$9
B
$3
С.
S2000
D
$6.000

Answers

Answer:

$3

Step-by-step explanation:

Given

Total Cost Price: $12,000

Unit Cost Price= $6

Total Selling Price = $18,000

Required

Determine the profit on each share

First, we need to determine the units of share bought;

Units = Total cost price / Unit Cost Price

[tex]Units = \frac{\$12000}{\$6}[/tex]

[tex]Units = 2000[/tex]

Next is to determine the selling price of each share; This is calculated as follows;

Unit Selling Price = Total Selling Price / Units Sold

[tex]Unit\ Selling\ Price = \frac{\$18000}{\$2000}[/tex]

[tex]Unit\ Selling\ Price = \$9[/tex]

The profit is the difference between the unit cost price and unit selling price

[tex]Profit = Unit\ Selling\ Price - Unit\ Cost\ Price[/tex]

[tex]Profit = \$9 - \$6[/tex]

[tex]Profit = \$3[/tex]

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