On a straight road (taken to be in the x direction) you drive for an hour at 60 km per hour, then quickly speed up to 120 km per hour and drive for an additional two hours. What is your average x component of velocity

Answer:

A) 10.243 s

B) 514.64 m

C) 153.645 m

Explanation:

From projectile motion;

y(t) = h - ½gt²

Where;

h is the height of cliff

t is the time taken to fall from top of cliff down to half the height of the cliff

y(t) is height of the rock as function of time

We are told the rock falls half way of the cliff height.

Thus;

y = h/2

So;

h/2 = h - ½gt²

This gives;

h - h/2 = ½gt²

h/2 = ½gt²

h = gt² - - - - (1)

Also,the total free fall time from top of the cliff to ground would be;

T = t + 3

Thus, distance at this point is zero.

So;

0 = h - ½gT²

h = ½gT²

Putting t + 3 for T, we have;

h = (1/2)g(t + 3)² - - - 2

Inspecting eq 1 and eq 2,we have;

gt² = (1/2)g(t + 3)²

g will cancel out to give;

2t² = t² + 6t + 9

t² - 6t - 9 = 0

The roots are -1.243 or 7.243.

We will pick the positive value as time can't be negative.

Thus, T = 7.243 + 3 = 10.243 s

h = gt² = 9.81 × 7.243²

h = 514.64 m

Formula for horizontal distance is given by;

x = uT

Where u is initial speed given as;

u = 15 m/s

Thus;

x = 15 × 10.243

x = 153.645 m

Your question has been heard loud and clear.

Averge velocity formula=  Total distance travelled / total time taken.

Total distance=7meters

Total time taken=9 seconds.

Average velocity = 7/9= 0.77 metres/second

Average velocity= 0.77m/s

Thank you.

Answer:

provide new testble ideas

Answer:

[tex] \boxed{\sf Tension \ in \ the \ string \ (T) = 3 \ kN} [/tex]

Given:

Mass (m) = 3.0 kg

Uniform speed (v) = 20 m/s

Length of string (r) = 40 cm = 0.4 m

To Find:

Tension in the string (T)

Explanation:

Tension (T) is the string will be equal to centripetal force ([tex] \sf F_c [/tex]).

[tex] \boxed{ \bold{ T = F_c = \frac{m {v}^{2} }{r} }}[/tex]

Substituting value of m, v & r in the equation:

[tex] \sf \implies T = \frac{3 \times {20}^{2} }{0.4} \\ \\ \sf \implies T = \frac{3 \times 400}{0.4} \\ \\ \sf \implies T =3 \times 1000 \\ \\ \sf \implies T =3000 \: N \\ \\ \sf \implies T =3 \: kN[/tex]

[tex] \therefore[/tex]

Tension in the string (T) = 3 kN

Answer:

Hey !.

I think the answer will be water vapour,ice ,water.

Answer:

water vapor, water, ice

Hope this answer correct ✌️

Answer:

Following are the answer to this question:

Explanation:

Galileo claims that perhaps the air resistance is due to an object falling slower. The object gradually falls under its control of free-fall gravity.  

A free-falling object is also an object, which is affected by gravity only. The object operated only by the gravitational force is considered to get into a condition of free fall and the Items, that fall free may not feel air resistance.

please find the attachment.

Answer:

Using sold paper is better than to burn it because burning paper may cause pollution.

Explanation:

Hope it will help ^_^

Answer:

A.

Explanation:

The answer is A because the weight of the crate is sitting on something rough. The roughness is going to resist anything that tries to move against it because the force being exerted by the 2 workers is not strong enough to get the crate to move out of its place on the mud since it's static.

The answer can't be B because ice is smooth and doesn't have any friction, the little girl can't move it because it's to heavy for her to move, not because there's friction acting against it.

The resistance one encounters when attempting to move a stationary object over a surface without also moving their bodies in relation to the surface is known as static friction. Thus, option A is correct.

An object cannot move down the path due to a force known as static friction. Two materials sliding over one another causes this friction. Conflict can be found everywhere around us. Consider how the ground is in contact with our feet when we walk.

When there is no relative motion between the object and the surface, a body is subjected to the effects of static friction. As a result, it can still act when the body is moving, but there shouldn't be any relative motion.

Therefore, Static friction slows the car down if the tire is moving so smoothly that the ground-contact surface is never slipping. Kinetic friction will cause the wheels to slow down if they are locked and sliding.

Learn more about Static friction here:

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Answer:

Let the resultant be

A= ( C2 + B2 )1/2

So

sin = B / ( C2 + B2 )1/2

And

cos = C / ( C2 + B2 )1/2

So the total force is

F = FA + FC + FY

= - k y2 i / c2 + k y2 j / B2 + k y Q ( -cos i + sin j ) / ( C2 + B2 )

F = 0

- k y2 i / C2 + k y2 j / B2 + k y Q ( -sin i + sin j ) / ( L2 + H2 ) = 0

- k y2 i / C2 + k y2 j / B2 + k y Q ( - C / ( C2 + B2 )1/2 i + B/ ( C2+ B )1/2 j ) / ( C2 + B2 )1/2 = 0

Q = - y ( C2 + B )3/2 / C3

k y2 / B2 + k y Q B/ ( C2 + B2 )3/2 = 0

Q = -y ( C2 + b2 )3/2 / B

So equating both " Q " values

- y ( C2 + B2 )3/2 / L3 = - y( C2 + B2 )3/2 / B

so the possible length and the relationship is C= B

Answer:

velocity = 62.89 m/s  in 58 degree measured from the x-axis

Explanation:

Relevant information:

Before the collision, asteroid A of mass 1,000 kg moved at 100 m/s, and asteroid B of mass 2,000 kg moved at 80 m/s.

Two asteroids moving with velocities collide at right angles and stick together. Asteroid A initially moving to right direction and asteroid B initially move in the upward direction.

Before collision Momentum of A = 1000 x 100 = [tex]$ 10^5$[/tex] kg - m/s in the right direction.

Before collision Momentum of B = 2000 x 80 = 1.6 x [tex]$ 10^5$[/tex]  kg - m/s in upward direction.

Mass of System of after collision = 1000 + 2000 = 3000 kg

Now applying the Momentum Conservation, we get

Initial momentum in right direction = final momentum in right direction = [tex]$ 10^5$[/tex]

And, Initial momentum in upward direction = Final momentum in upward direction = 1.6 x [tex]$ 10^5$[/tex]

So, [tex]$ V_x = \frac{10^5}{3000} $[/tex]  = [tex]$ \frac{100}{3} $[/tex]  m/s

and [tex]$ V_y=\frac{160}{3}$[/tex]  m/s

Therefore, velocity is = [tex]$ \sqrt{V_x^2 + V_y^2} $[/tex]

                                   = [tex]$ \sqrt{(\frac{100}{3})^2 + (\frac{160}{3})^2} $[/tex]

                                   = 62.89 m/s

And direction is

tan θ = [tex]$ \frac{V_y}{V_x}$[/tex]     = 1.6

therefore, [tex]$ \theta = \tan^{-1}1.6 $[/tex]

                   = [tex]$ 58 ^{\circ}$[/tex]  from x-axis

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

A

   [tex]v_w = 2.256 *10^{8} \ m/s[/tex]

B

  [tex]v_e = 2.21 *10^{8} \ m/s[/tex]

C

The  correct option is  B  

Explanation:

From the question we are told that

      The refractive  index of water is  [tex]n_w = 1.33[/tex]

      The  refractive  index of ethanol is  [tex]n_e = 1.36[/tex]

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

       [tex]v_w = \frac{c}{n_w }[/tex]

Where  c is the speed of light with value  [tex]c = 3.0 *10^{8} \ m/s[/tex]

       [tex]v_w = \frac{3.0 *10^{8}}{1.33 }[/tex]

       [tex]v_w = 2.256 *10^{8} \ m/s[/tex]

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

            [tex]v_e = \frac{ c}{n_e }[/tex]

  =>       [tex]v_e = \frac{3.0 *10^{8}}{1.36 }[/tex]

=>          [tex]v_e = 2.21 *10^{8} \ m/s[/tex]

Complete Question

A grating has 767 lines per centimetre.Find the angles of the first three principal maxima above the central fringe when this grating is illuminated with 672 nm light.

Answer:

The  first is  

      [tex]\theta_1 = 2.92^o[/tex]

 The second is  

       [tex]\theta _2 = 5.93^o[/tex]

 The third is  

        [tex]\theta _3 = 8.92^o[/tex]

Explanation:

From the question we are told that

        The  number of lines per cm is  [tex]I = 767 \ lines/cm = 76700 \ lines / m[/tex]

        The  wavelength is  [tex]\lambda = 672nm = 672 *10^{-9} \ m[/tex]

Generally the condition for constructive  interference is  

            [tex]dsin (\theta ) = n\lambda[/tex]    

Here d is the distance of separation of the slit which is mathematically represented as

             [tex]d = \frac{1}{l}[/tex]

             [tex]d = \frac{1}{76700}[/tex]

             [tex]d = 1.30*10^{-5} \ m[/tex]

So          

           [tex]\theta_1 = sin^{-1} [\frac{ n \lambda }{ d} ][/tex]

For the  first angle  n =  1  

  So  

        [tex]\theta_1 = sin^{-1} [\frac{ 1 * 672 *10^{-9} }{ 1.30 *10^{-5}} ][/tex]

          [tex]\theta_1 = 2.92^o[/tex]

For  the second angle  n  =  2

      So  

            [tex]\theta_2 = sin^{-1} [\frac{ 2 * 672 *10^{-9} }{ 1.30 *10^{-5}} ][/tex]

            [tex]\theta _2 = 5.93^o[/tex]

For  the second angle  n  =  3

      So  

           [tex]\theta_3 = sin^{-1} [\frac{ 3 * 672 *10^{-9} }{ 1.30 *10^{-5}} ][/tex]

          [tex]\theta _3 = 8.92^o[/tex]

Answer:

The first graph is showing the constant acceleration (1 m/s)

Explanation:

The second graph showing the flexible velocity therefore a in the graph is different at t1, t2, t3, t4

The last graph is showing constant velocity therefore there is no acceleration (a = 0)

Answer:

A

Explanation:

on edge

Answer:

t = 125 C

Explanation:

The force on a charge due to other charge is given by Coulomb's Law, as follows:

F = kq₁q₂/r²

where,

F = Electric Force = 5 N

k = Coulomb Constant = 9 x 10⁹ N.m²/C²

q₁ = magnitude of first charge = 15 nC = 1.5 x 10⁻⁸ C

q₂ = Magnitude of 2nd Charge = t = ?

r = distance between charges = 15 m

Therefore,

5 N = (9 x 10⁹ N.m²/C²)(1.5 x 10⁻⁸ C)t/(15 m)²

t = (5 N)/(0.04 N/C)

t = 125 C

Answer:

The wavelength of the emitted photon is 413.6 nm

Explanation:

Given;

energy of the emitted photon, E = 3 eV = 3 x 1.602 x 10⁻¹⁹ J

speed of light, c  = 3 x 10⁸ m/s

The energy of the emitted photon is given by;

E = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

f is the frequency of the light = c / λ

λ is the wavelength

[tex]E = \frac{hc}{\lambda}\\\\\lambda = \frac{hc}{E}\\\\\lambda = \frac{(6.626*10^{-34})(3*10^8)}{3*1.602*10^{-19}}\\\\\lambda = 4.136 *10^{-7} \ m\\\\\lambda = 413.6 *10^{-9} \ m\\\\\lambda = 413.6 \ nm[/tex]

Therefore, the wavelength of the emitted photon is 413.6 nm

Answer:

Radio waves have frequencies as high as 300 gigahertz(GHz)to as low as 30 hertz(Hz).At 300 GHz the corresponding wavelength is 1mm and at 30Hz is 10,000 km

The average wavelength of radio waves ​ranges from roughly two millimeters to more than 150 kilometers. The wavelengths of radio waves are the longest in the electromagnetic spectrum

It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.

It is the total length of the wave for which it completes one cycle.

The wavelength is inversely proportional to the frequency of the wave as from the following relation.

C = νλ

They also have the lowest frequencies, ranging from around 4,000 cycles per second, or 3 kilohertz, to roughly 280 billion hertz, or 280 gigahertz.

The wavelengths of radio waves are the longest in the electromagnetic spectrum, ranging from roughly two millimeters to more than 150 kilometers.

To learn more about wavelength from here, refer to the link given below;

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Answer:

Here are some of the main cons of nuclear energy.

•Expensive to Build. Despite being relatively inexpensive to operate, nuclear power plants are incredibly expensive to build—and the cost keeps rising. ...

•Accidents. ...

•Produces Radioactive Waste. ...

•Impact on the Environment. ...

•Security Threat. ...

•Limited Fuel Supply.

[tex]\huge\underline\mathcal\pink{Answer:-}[/tex]

The nuclei of atoms contain a large amount of energy. Releasing this energy would free the world from having to use fossil fuels. There are two methods of doing this: fission and fusion.

1. Nuclear is a bad match for renewables.

2. Building nuclear power stations is very expensive.

3.There are huge costs beyond simply constructing the power stations.

4 Nuclear power stations take at least a decade to build.

[tex]\huge\red{kya \: aap \: samajhe?}[/tex]

Answer:

Explanation:

a ) Temperature at ground level is a field and it is scalar field .At any point in space near ground level  , the temperature is specific so it is a field .  It is scalar  because temperature has no direction .

b )

 Wind velocity at 100 feet above the ground is also a field but it is a vector field . At any point in space , the wind velocity is specific so it is a field .  It is vector   because velocity  has a particular  direction at any point .

c )

Gravitational force on Roessler Hall is a vector field because gravitational force also depends on location in space and it has direction.

d )

Height of a person in your group is not a space because it does not depend upon  location is space . It is same for all location .

e )

Height (above sea level) of the ground is a field  because it also depends upon location in space . It is scalar field .

f )

Slope of the surface of the earth is a scalar field .

Answer:

Marked image of the top of the object

Answer:

t = log9/10 x RC

Explanation:

Let's say initial energy is

E= 1/2Q²/C

But if 90% is discharged what will be remaining will be

E= E"/100= 1/2Q²/C

So if we divide the first by the second equation we have

Q'= Q/10

Then using

q=q0(1-e^-t /RC)

So that

Q= Q/10(1-e^-t /RC)

t/RC= log9/10

So t = log9/10 x RC

Here ,

• Height of sign post = 30 m

• Distance between signpost and truck = 24 m

Let the

• Top of signpost = A

• Bottom of signpost = B

• The end of truck facing sign post be = C

Now as we can clearly imagine that the ladder will act as an hypotenuse to the Triangle ABC .

Where

• AB = Height of signpost = 30 m

• BC = distance between both = 24 m

• AC = Minimum length of ladder

→ AC² = AB² + BC² ( As we can see AB is perpendicular to BC )

→ AC² = (30)² + (24)²

→ AC² = 900 + 576

→ AC² = 1476

→ AC = 38.41875

or AC apx = 38.42

So minimum height of ladder = 38.42

This question can be solved by using the formula of "Pythagora's Theorem".

The ladder must be "38.42 m" long.

If we imagine the whole situation in terms of a right-angled triangle, we can safely assume the height of the billboard (which is the pole supporting the billboard) as the perpendicular of the right-angled triangle. The distance between the signpost and the truck can be assumed as the base of the triangle. The length of the ladder will then be acting as the Hypotenuse of the right-angled triangle.

The attached picture clearly depicts the condition explained in the above paragraph.

Now applying Pythagora's Theorem to this situation, we get:

[tex]Hypotenuse^2 = Perpendicular^2+Base^2\\Length\ of\ Ladder^2 = (30\ m)^2+(24\ m)^2\\L^2 = 1476\ m^2\\[/tex]

L = 38.42 m

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Answer:

27 Joules.

Explanation:

use the formula for kinetic energy:

KE = 1/2mv^2

A 54 kg pig runs at a speed of 1.0 m/s.

What is the pig’s kinetic energy?

Answer: 27 J

Answer:

1) Only the perpendicular component of wind is responsible for the rotation, because gravity points downward.

2) static friction is greater than kinetic friction and the applied force acts oppositely

3)   Inertia decreases with decreasing radius of the orbit.

4) constant is the mass of the car

Explanation:

1) In order to know which statement is correct, let's analyze the movement of the mill.

The rotation of the blades due to a force perpendicular to each one, which creates a torque that results in its rotation.

The true force does not affect the movement because it is applied at the center of mass of the mill that coincides with its axis of rotation.

Of the statements, the correct one is:

The perpendicular to the wind is responsible for the movement

2) static friction is the result of microscopic bonds between two surfaces when there is no relative motion between them

kinetic friction is the result of the unions between the two surfaces when there is a relative movement between them.

From these statements it follows that friction is contrary to motion, static friction must be greater than kinetic friction.

Of the statements the correct one is:

static friction is greater than kinetic friction and the applied force acts oppositely

3) The inertia of a particle is

         I = m R²

where m is the mass of the satellite and R is the distance from the center of the Earth, decreasing with each orbit

The correct answer is:

  Inertia decreases with decreasing radius of the orbit.

4) From the figure it can be seen that the motorist subjected to a constant force, for which we can apply Newton's second law

          F = m a

The force equals the applied weight.

The quantity that is held constant is the mass of the car

since the applied force and therefore the acceleration can be changed by changing the applied weight.

Answer:

1. The perpendicular components of gravity and the force of wind are responsible for the rotation.  

2. Static friction is greater than kinetic friction, but they both act opposite the applied force.

3. Rotational inertia decreases proportional to the decrease in the radius of rotation.

4. mass

Answer:

we have to find out the work done in order to find the power since power is the amount of joules spent every second

work done by the bull = Force * Displacement

work done = 200 N * 10 m

work done = 2000 Nm or  2000 j

since we know that the bull spent the 2000 j in 10 seconds,

we will find the amount of energy spent in a second:

power = work done / time

power = 2000 / 10

power = 200 W

a brainly will be appreciated

Answer:

200W

Explanation:

as power = work/time

               = force * distance /time

               = 200 * 10/ 10

               ==200W

Complete Question

A thin, horizontal, 12-cm-diameter copper plate is charged to 4.4 nC . Assume that the electrons are uniformly distributed on the surface. What is the strength of the electric field 0.1 mm above the center of the top surface of the plate?

Answer:

The  values is  [tex]E =248.2 \ N/C[/tex]

Explanation:

From the question we are told that

   The  diameter is  [tex]d = 12 \ cm = 0.12 \ m[/tex]

    The charge  is  [tex]Q = 4.4 nC = 4.4 *10^{-9} \ C[/tex]

    The  distance from the center  is  [tex]k = 0.1 \ mm = 1*10^{-4} \ m[/tex]

Generally the radius is mathematically represented as

        [tex]r = \frac{d}{2}[/tex]

=>     [tex]r = \frac{0.12}{2}[/tex]

=>       [tex]r = 0.06 \ m[/tex]

Generally electric field is mathematically represented as  

       [tex]E = \frac{Q}{ 2\epsilon_o } [1 - \frac{k}{\sqrt{r^2 + k^2 } } ][/tex]

substituting values  

      [tex]E = \frac{4.4 *10^{-9}}{ 2* (8.85*10^{-12}) } [1 - \frac{(1.00 *10^{-4})}{\sqrt{(0.06)^2 + (1.0*10^{-4})^2 } } ][/tex]

     [tex]E =248.2 \ N/C[/tex]

Answer:

Magnitude of the momentum (P) = 5.96 Kg.m /s (Approx)

Explanation:

Given:

Mass of baseball (m) = 155 gram = 0.155 kg

Velocity (v) = 86 miles/ hour

Find:

Magnitude of the momentum (P)

Computation:

1 mile = 1,609.344 meters

So,

Velocity (v) = 86 × (1,609.344 / 3600)

Velocity (v) = 38.45 m/s

Magnitude of the momentum (P) = mv

Magnitude of the momentum (P) = (0.155)(38.45)

Magnitude of the momentum (P) = 5.96 Kg.m /s (Approx)

Answer:

Explanation:

 |F-->1| =  E-->1 x charge on proton

= 300 x 1.6 x 10⁻¹⁹

Magnitude of electric force on proton

|F-->1| = 480 x 10⁻¹⁹ N .

Inside lithium nucleus , there are three protons so charge on it

= 3 x 1.6 x 10⁻¹⁹ = 4.8 x 10⁻¹⁹ C .

Magnitude of electric force on lithium nucleus

|F-->Li|  =   E-->1 x charge on lithium nucleus

= 300 x  4.8 x 10⁻¹⁹

= 1440 x 10⁻¹⁹ N .

Electron has same charge as that possessed by proton so charge on electron = 1.6 x 10⁻¹⁹ C

Magnitude of force on electron

|F-->1| =  E-->1 x charge on electron

= 300 x 1.6 x 10⁻¹⁹

=  480 x 10⁻¹⁹ N .

Complete Question

A parallel-plate capacitor has square plates 20 cm on a side and 0.50 cm apart. If the voltage across the plates is increasing at the rate of 220 V/s, what is the displacement current in the capacitor?

Answer:

The value is  [tex]I = 1.416*10^{-8} \ A[/tex]

Explanation:

From the question we are told that

       The  length and breath of the square plate is  [tex]l = b = 20 \ cm = 0.2 \ m[/tex]

        The  distance of separation between each plate is [tex]k = 0.50 \ cm = 0.005 \ m[/tex]

       The rate of voltage  increase is  [tex]\frac{dV}{dt} = 200 \ V/s[/tex]

Generally the charge on the plate is mathematically represented as

  [tex]Q = CV[/tex]

Now C is the capacitance of the capacitor which is mathematically represented as

   [tex]C = \frac{\epsilon_o * A}{k}[/tex]

Here A is the cross-sectional area which is mathematically represented as

    [tex]A = l^2[/tex]

=>   [tex]A = 0.2^2[/tex]

=>   [tex]A = 0.04 \ m^2[/tex]

So  

     [tex]C = \frac{8.85 *10^{-12} * 0.04}{0.005}[/tex]

          [tex]C = 7.08*10^{-11} \ F[/tex]

Now the change of the charge flowing through the plates with time is mathematically represented as

        [tex]\frac{d Q}{dt} = C \frac{dV}{dt}[/tex]

So  

       [tex]\frac{d Q}{dt} = 7.08 *10^{-11} * 200[/tex]

       [tex]\frac{d Q}{dt} = 1.416*10^{-8}[/tex]

Generally   [tex]\frac{d Q}{dt} = \ current \ i.e \ I[/tex]

So

     [tex]I = 1.416*10^{-8} \ A[/tex]

Answer:

W = 5000 J

Explanation:

Weight hold by a weightlifter is 1700 N, 1 meter above the ground.

One end of a 2-meter-long chain hangs from the center of the barbell. The chain has a total weight of 800 N.

We need to find the work is required to lift the barbell to a height of 2 m.

Total force is : 1700 N + 800 N = 2500 N

Work done in Physics is given by :

W = F×d

So,

W = 2500 N × 2 m

W = 5000 J

Hence, 5000 J of work is required to lift the barbell to a height of 2 m.