On Thursday, 40 trains left the station. Eight left late. On Saturday 50 trains left the station. Nine left late. What percentage of trains were not late on each day?

Answers

Answer 1

Answer:

Thursday=80%

Saturday=82 %

Step-by-step explanation:

Thursday trains not late=40-8=32

% trains not late=32/40×100=80

Saturday trains not late=50-9=41

% trains not late on Saturday=41/50×100=82


Related Questions

Consider the perfect square trinomial identity:
a2 + 2ab + b2 = (a + b)2.
For the polynomial x2 + 10x + 25,
and b =
a =

Answers

Answer:

a = x

b = 5

Step-by-step explanation:

for the polynomial x² + 10x + 25, b = 5 and a = x.

In the polynomial x² + 10x + 25, we can observe that the first term, x², is the square of x, and the last term, 25, is the square of 5. This suggests that the polynomial follows the perfect square trinomial identity.

The middle term, 10x, can be rewritten as 2ab, where a represents x and b represents a term that when squared equals the last term, 25.

In this case, b = 5, because 5² = 25.

To find a, we can take the square root of the first term, x². The square root of x² is x, so a = x.

Therefore, for the polynomial x² + 10x + 25, b = 5 and a = x.

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when the point ( k, 3 ) lies on each of these lines, find the value of k y= 3x+1 , y= 4x-2 , y=1/2x - 1 and 2x+3y=4

Answers

Answer:

see explanation

Step-by-step explanation:

Since (k, 3) lies on each of the lines, the point satisfies the equations.

Substitute x = k, y = 3 into each and solve for k

y = 3x + 1

3 = 3k + 1 ( subtract 1 from both sides )

2 = 3k ( divide both sides by 3 )

k = [tex]\frac{2}{3}[/tex]

-------------------------------------------------------

y = 4x - 2

3 = 4k - 2 ( add 2 to both sides )

5 = 4k ( divide both sides by 4 )

k = [tex]\frac{5}{4}[/tex]

--------------------------------------------------------

y = [tex]\frac{1}{2}[/tex] x

3 = [tex]\frac{1}{2}[/tex] k ( multiply both sides by 2 to clear the fraction )

k = 6

---------------------------------------------------------

2x + 3y = 4

2k + 3(3) = 4

2k + 9 = 4 ( subtract 9 from both sides )

2k = - 5 ( divide both sides by 2 )

k = - [tex]\frac{5}{2}[/tex]

Find the missing probability. P(A)=720,P(B)=35,P(A∩B)=21100 ,P(A∪B)=?

Answers

P (A U B) = 37/50

7/20+3/5+21/100

The missing probability P(A∪B) will be 37/50.

What is the probability?

Probability refers to a possibility that deals with the occurrence of random events.

The probability of all the events occurring need to be 1.

Given information;

P(A)= 7/20,

P(B)=3/5,

P(A∩B) =21/100 ,

We need to find the missing probability P(A∪B).

We know that

P(A∪B)= P(A) + P(B) + P(A∩B)

P(A∪B) = 7/20 + 3/5 + 21/100

P (A U B) = 37/50

Therefore, the missing probability P(A∪B) will be 37/50.

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The generic version was basedOn the brand name and was 2/3 the size of the brand name. If the generic television set is 12 inches by 24 inches what are the dimensions of the brand name television

Answers

Answer:

18 inches by 36 inches.

Step-by-step explanation:

Since we have given that

The generic version was basedOn the brand name and was 2/3

And given Dimensions of generic version is given by 12inches ×24inches

If we use the first dimensions of 12inches we have

12=2/3 × brand

12×3/2 = brand

=18inches= brand

we use the first dimensions of 24 inches we have

24=2/3 × brand

24×3/2 = brand

=36 inches= brand

brand= 36 inches

Therefore,the dimensions of brand name will be 18 inches by 36 inches.

Questions attached below (❁´◡`❁)

Answers

Problem 2

Josh forgot to apply the square root to 16 when he went from [tex](x-3)^2 = 16[/tex] to [tex]x-3 = 16[/tex]

Also, he forgot about the plus/minus.

This is what his steps should look like

[tex]x^2 - 6x - 7 = 0\\\\x^2 - 6x = 7\\\\x^2 - 6x +9= 7+9\\\\(x-3)^2= 16\\\\x-3= \pm\sqrt{16}\\\\x-3= 4 \text{ or } x-3= -4\\\\x= 7 \text{ or } x= -1\\\\[/tex]

There are two solutions and they are x = 7 or x = -1. To check each solution, you plug it back into the original equation

Let's try out x = 7

x^2 - 6x - 7 = 0

7^2 - 6(7) - 7 = 0

49 - 42 - 7 = 0

0 = 0 ... solution x = 7 is confirmed. I'll let you check x = -1

====================================================

Problem 3

We will have

a = 1, b = -4, c = 3

plugged into the quadratic formula below to get...

[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-4)\pm\sqrt{(-4)^2-4(1)(3)}}{2(1)}\\\\x = \frac{4\pm\sqrt{4}}{2}\\\\x = \frac{4\pm2}{2}\\\\x = \frac{4+2}{2} \ \text{ or } \ x = \frac{4-2}{2}\\\\x = \frac{6}{2} \ \text{ or } \ x = \frac{2}{2}\\\\x = 3 \ \text{ or } \ x = 1\\\\[/tex]

The two solutions are x = 3 or x = 1. You would check this by plugging x = 3 back into the original expression x^2 - 4x + 3. The result should be zero. The same applies to x = 1 as well.

can someone slove this −8 + x = 3

Answers

Answer:

11

Step-by-step explanation:

Subtract:

-8 + x = 3

+8        +8

--------------

    x = 11

Hope this helped.

Answer:

x = 11

Step-by-step explanation:

−8 + x = 3

Add 8 to both sides

x = 11 ✓

what is the lowest common denominator of 4 7 5 2 and 1

Answers

Answer:

140

Step-by-step explanation:

Lowest common denominator 4 , 7 ,5 , 2  and 1

= 4 * 7 * 5

= 140

Answer:

1

Step-by-step explanation:

Since usually common denominator is usually used with fractions (in this case), we can find out it's one because of how no numbers (except for 2 and 4) go into each other without a remainder except for one, so one would be the correct answer

David is the caption of the school soccer team. Last year, the team won four more games than it lost. If the team won 46 games, how many games did it lose?

Answers

Answer:

C

Step-by-step explanation:

Games lost=Games won - 4

Games lost=46-4=42

An equilateral triangle has a perimeter of 15x3 + 33x5 feet. What is the length of each side?
x3 feet
5 + 11x2 feet
5x2 + 11 feet
5x3 + 11x5 feet

Answers

Answer:

the answer is 5×3+11×5 feet

Answer:

4th option

Step-by-step explanation:

An equilateral triangle has 3 congruent sides

Divide the perimeter by 3 for length of side

[tex]\frac{15x^3+33x^5}{3}[/tex]

= [tex]\frac{15x^3}{3}[/tex] + [tex]\frac{33x^5}{3}[/tex]

= 5x³ + 11[tex]x^{5}[/tex] ← length of 1 side

For the rational equation,[tex]\frac{x^{2}+5x+6}{x+3}=1[/tex] , what is a valid value of x?

Answers

Answer:

-3 or -1 is a valid value for x

Step-by-step explanation:

We start by cross multiplying;

So the expression becomes;

x^2 + 5x + 6 = 1(x + 3)

x^2 + 5x + 6 = x + 3

x^2 + 5x -x + 6-3 = 0

x^2 + 4x + 3 = 0

x^2 + x + 3x + 3 = 0

x(x + 1) + 3(x + 1) = 0

(x + 3)(x + 1) = 0

x + 3 = 0 or x + 1 = 0

x = -3 or x = -1

12. Write 0.8 as a fraction,
Pls explain in full detail.

Answers

Answer:

8/10

Step-by-step explanation:

10x10 is 100 8x10 would be 80 so 80/100=8/10

Answer:

8/10 = 4/5

Step-by-step explanation:

0.8 is 8-10th which means 8 divided by 10

reducing 8/10 to its lowest term since 8 and 10 has 2 as common factor, then

(8=2*4)/(10=2*5)

if 2 cancels out, then you are left with 4/5

-4(2x-3) simplified

Answers

Answer:

-8x + 12

Step-by-step explanation:

Distribute -4 to the parentheses:

-4(2x - 3)

-4(2x) = -8x

-4(-3) = 12

-8x + 12

Answer:

-8x +12

Step-by-step explanation:

-4(2x-3)

Distribute

-4* 2x -4 *-3

-8x +12

Please help I’ll mark brainliest

Answers

Answer:

Step-by-step explanation:

The rule that makes a relation NOT a function is if there are shared x values. This function has 2 points with the same x value:

(7, 4) and (7, 6). The sharing of these x-values (or the repeating of them) within the same relation makes this NOT a function. The last choice is the one you want. Just remember that a relation is only a function if there are no shared x-values. The y-values don't matter to this at all. A relation would be a function if it were made up of the following coordinates:

(1, 2), (2, 2), (3, 2), (4, 2), (5, 2), etc. Again, as long as the x-values don't repeat, the relation is a function.

Please answer it now in two minutes

Answers

Answer:

x = 84

Step-by-step explanation:

∠ UWV is an angle in a semicircle and is right = 90°

VW = UW  thus Δ UVW is right isosceles, thus

∠ UVW = ∠ WUV = 45° ( sum of angles in triangle ) , thus

x - 39 = 45 ( add 39 to both sides )

x = 84

What are the lower quartile, upper quartile, and median for this box and
whisker plot?

A) LQ = 22 UQ = 10 Median = 18.5

B) LQ = 10 UQ = 22 Median = 18

C) LQ = 10 UQ = 22 Median = 18.5

D) LQ = 10 UQ = 22 Median = 19​

Answers

Answer:

C

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

The lower quartile range is shown by the bottom of the box which is at 10.

The median is shown in the middle line, which is closer to 18 than 18.5.

The upper quartile range in the end of the box, which is at 22!

(You can also look at the picture attached if that helps.)

4 of 204 of 20 Questions




Question 4
What is the equation of the line that is parallel to y−5=−13(x+2) and passes through the point (6,−1)?

Answers

Answer:

y= -13x+77

Step-by-step explanation:

Parallel lines do not share any points but have the same slope.

First, put the equation y-5=-13(x+2) into slope-intercept form.

y= -13x-21

Slope= -13x

Y-Intercept= (0,-21)

Now that we know the slope...

y-(-1)=-13(x-6)

becomes

y+1=-13x+78

y-1=-13x+78-1

y=-13x+77


Find the co-ordinates of the foot of the perpendicular drawn from the point (6, 3) to the line by
segment joining (4,1) and (8,3).​

Answers

The coordinates of the foot of the perpendicular drawn from the point (6, 3) to the line by segment joining (4,1) and (8,3). is (6.4, 2.2)

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

The equation of the line passing through (4,1) and (8,3) is:

y - 1 = [(3 - 1)/(8 - 4)](x - 4)

y = 0.5x - 1

The line perpendicular to y = 0.5x - 1 has a slope of -2. It passes the point (6, 3), hence:

y - 3 = -2(x - 6)

y = -2x + 15

The line y = 0.5x - 1 and y = -2x + 15 intersect at point (6.4, 2.2)

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reduce the following rational expression to the lowest form

[tex]\frac{64x^{5} - 64x}{( 8x^{2} +8) (2x +2) }[/tex]

please answer this. But no spam answers please
hurry

Answers

Answer:

4x(x - 1)

Step-by-step explanation:

Factor the numerator and denominator

64[tex]x^{5}[/tex] - 64x ← factor out 64x from both terms

= 64x([tex]x^{4}[/tex] - 1) ← difference of squares

= 64x(x² - 1)(x² + 1) ← x² - 1 is also a difference of squares

= 64x(x - 1)(x + 1)(x² + 1)

---------------------------------

(8x² + 8)(2x + 2) ← factor out 8 and 2 from each factor

= 8(x² + 1) × 2(x + 1)

= 16(x² + 1)(x + 1)

Then expression can be written as

[tex]\frac{64x(x-1)(x+1)(x^2+1)}{16(x^2+1)(x+1)}[/tex] ← cancel (x² + 1) and (x + 1) on numerator/ denominator

= [tex]\frac{64x(x-1)}{16}[/tex] ← cancel common factor 16 on numerator/ denominator

= 4x(x - 1)

Circles in the Coordinate Plane
Acellus
Complete the equation of this circle:
A
1

Answers

Answer:  [tex](x-3)^2 + (y-2)^2 = 16[/tex]

Explanation:

The center of this circle is point A(3,2). These coordinates are the (h,k) values.

The radius is r = 4

Plug those three items into the template [tex](x-h)^2 + (y-k)^2 = r^2[/tex] to arrive at the final answer shown above.

I'm doing a task which involves magic v's, a maths pattern which has the rule of having the same total on each side. For e.g.
6 5
3 4
2
Is a magic v because each side adds up to 11. I need to make magic V's with the number 2-6 and 3-7. There are 24 possibilities for each number set.

Answers

Answer:

--1-- (of set 23456)

2   4

5 3

 6

--2-- (of set 23456)

2   3

5 4

 6

--3-- (of set 23456)

2   5

6 3

 4

--4-- (of set 23456)

2   3

6 5

 4

--5-- (of set 23456)

3   5

4 2

 6

--6-- (of set 23456)

3   2

4 5

 6

--7-- (of set 23456)

3   6

5 2

 4

--8-- (of set 23456)

3   2

5 6

 4

--9-- (of set 23456)

3   5

6 4

 2

--10-- (of set 23456)

3   4

6 5

 2

--11-- (of set 23456)

4   5

3 2

 6

--12-- (of set 23456)

4   2

3 5

 6

--13-- (of set 23456)

4   6

5 3

 2

--14-- (of set 23456)

4   3

5 6

 2

--15-- (of set 23456)

5   4

2 3

 6

--16-- (of set 23456)

5   3

2 4

 6

--17-- (of set 23456)

5   6

3 2

 4

--18-- (of set 23456)

5   2

3 6

 4

--19-- (of set 23456)

5   6

4 3

 2

--20-- (of set 23456)

5   3

4 6

 2

--21-- (of set 23456)

6   5

2 3

 4

--22-- (of set 23456)

6   3

2 5

 4

--23-- (of set 23456)

6   5

3 4

 2

--24-- (of set 23456)

6   4

3 5

 2

--1-- (of set 34567)

3   5

6 4

 7

--2-- (of set 34567)

3   4

6 5

 7

--3-- (of set 34567)

3   6

7 4

 5

--4-- (of set 34567)

3   4

7 6

 5

--5-- (of set 34567)

4   6

5 3

 7

--6-- (of set 34567)

4   3

5 6

 7

--7-- (of set 34567)

4   7

6 3

 5

--8-- (of set 34567)

4   3

6 7

 5

--9-- (of set 34567)

4   6

7 5

 3

--10-- (of set 34567)

4   5

7 6

 3

--11-- (of set 34567)

5   6

4 3

 7

--12-- (of set 34567)

5   3

4 6

 7

--13-- (of set 34567)

5   7

6 4

 3

--14-- (of set 34567)

5   4

6 7

 3

--15-- (of set 34567)

6   5

3 4

 7

--16-- (of set 34567)

6   4

3 5

 7

--17-- (of set 34567)

6   7

4 3

 5

--18-- (of set 34567)

6   3

4 7

 5

--19-- (of set 34567)

6   7

5 4

 3

--20-- (of set 34567)

6   4

5 7

 3

--21-- (of set 34567)

7   6

3 4

 5

--22-- (of set 34567)

7   4

3 6

 5

--23-- (of set 34567)

7   6

4 5

 3

--24-- (of set 34567)

7   5

4 6

 3

Step-by-step explanation:

This javascript code is extremely brute-force, but it does the job:

function checkIfInSet(i, set) {

   return i.toString().split('').sort().join('') === set;

}

function checkIfMagic(s) {

   return (parseInt(s[0]) + parseInt(s[1]) == parseInt(s[3]) + parseInt(s[4]))

}

function printMagic(s) {

   console.log(`${s[0]}   ${s[4]}`);

   console.log(` ${s[1]} ${s[3]}`);

   console.log(`  ${s[2]}\n`);

}

function checkSet(set) {

   let counter = 1;

   for(let i=1; i<99999; i++) {

       if (checkIfInSet(i, set) && checkIfMagic(i.toString())) {

           console.log(`--${counter++}-- (of set ${set})`);

           printMagic(i.toString());

       }

   }

}

checkSet('23456');

checkSet('34567');

I promise i will mark as brainiest

Answers

Answer:

A

Step-by-step explanation:

[tex] \frac{2003}{n} = z + \frac{23}{n} [/tex]

where z is an integer

[tex]2003 = nz + 23[/tex]

[tex]nz = 1980[/tex]

[tex]nz = {2}^{2} \times {3}^{2} \times 5 \times 11[/tex]

possible values of n

n= {1980, 990, 660, 495, 396, 330, 198, 180, 165, 132, 99, 90, 60, 45, 36, 30, 20, 18, 15, 5, 3}

cardinality of n=21

Given 4,7,10,13. Calculate the 20th term.​

Answers

Answer:

61

Step-by-step explanation:

to calculate the 20th term you use the formula

Tn=a+(n-1)d where a stands for the first term,n the number of terms and d the common difference.in this case the first term is 4 the common difference is 3 cause they were adding 3 to go to the next term.. therefore the solution will be:

Tn=4+(20-1)3

=4+19×3

=4+57

=61

the 20th term is 61

I hope this helps

In the equation $\frac{1}{j} + \frac{1}{k} = \frac{1}{3}$, both $j$ and $k$ are positive integers. What is the sum of all possible values for $k$?

Answers

Answer:

Hello,

answer 22

Step-by-step explanation:

[tex]\dfrac{1}{j} +\dfrac{1}{k} =\dfrac{1}{3} \\\\\dfrac{k+j}{j*k} =\dfrac{1}{3} \\\\\\3k+3j=j*k\\\\k(3-j)=-3j\\\\k=\dfrac{3j}{j-3} \\\\k=\dfrac{3j-9+9}{j-3} \\\\k=3+\dfrac{9}{j-3} \\\\\\j-3\ must\ be \ a divisor\ of\ 9 ==> 1,3,9\\\\j-3=1 ==> j=4 , k=3+\dfrac{9}{1} =12\\\\j-3=3 ==> j=6 , k=3+\dfrac{9}{3} =6\\\\j-3=9 ==> j=12 , k=3+\dfrac{9}{9} =4\\\\\sum\ k=12+6+4=22\\[/tex]

The sum of all possible values for k is 22.

What is fraction?

The fractional bar is a horizontal bar that divides the numerator and denominator of every fraction into these two halves.

The number of parts into which the whole has been divided is shown by the denominator. It is positioned in the fraction's lower portion, below the fractional bar.How many sections of the fraction are displayed or chosen is shown in the numerator. It is positioned above the fractional bar in the upper portion of the fraction.

Given:

1/j + 1/k= 1/3

Simplifying the fraction

(k+ j)/ kj= 1/3

3k + 3j = kj

k(3- j) = -3j

k = -3j/ (3- j)

k= 3j/ (j-3)

k = 3j + 9 - 9 / (j-3)

k = 3 + 9/ (j-3)

Since (j-3) must be divisor of 9.

j- 3 = 1---> j=4, k= 3 +9 = 12

j- 3 = 3---> j=6, k= 3 +9/3 = 6

j- 3 = 9---> j=12, k= 3 +9/9 = 4

So, The sum is = 12+ 6 + 4 = 22

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Please answer this question now

Answers

Hello!

Answer:

[tex]\huge\boxed{V = 60 m^{3}}[/tex]

Formula for the volume of a triangular pyramid:

V = 1/3(bh)

The base is a triangle, so b = 1/2(b · h)

Solve for the base:

b = 1/2(8 · 5)

b = 1/2(40)

b = 20 m²

Solve for the volume:

V = 1/3(20 · 9)

V = 1/3(180)

V = 60 m³.

Hope this helped you!

Answer:

60 cubic meters

Step-by-step explanation:

I used the formula V = 1/3 AH to figure it out

if set a is 12345 and Set B is 23 find a union B and find a intersection b​

Answers

Answer:

a union b= {1,2,3,4,5}

a intersection b ={2,3}

Step-by-step explanation:

The union of two sets A and B is a set that contains all the elements of A and B and is denoted by A U B

the set composed of all elements that belong to both A and B is A intersection B (A ∩ B)

please tell me the right answer​

Answers

It’s either B = C or none of these.
I’m sorry I couldn’t choose one answer this was complicated

help me please !!! :)

Answers

Answer:

A

Step-by-step explanation:

f(x) = x+4 when x is equal to or less than - 2. f(-4)=0

points V W X Y and Z are collinear, VZ= 52, XZ =20, and WX=XY=YZ find the indicated length

21.) WX 22.) VW 23.) WY 24.) VX 25.) WZ 26.) VY

Answers

Answer:

WX=10; VW=22; WY=20; VX=32; WZ=30;VY=42

Step-by-step explanation:

1)WX=XY=XZ/2=20/2=10

2)VW=VZ-WX-XY-YZ=VZ-3*WX=52-3*10=52-30=22

3)WY=WX+XY=2*WX=2*10=20

4)VX=VW+WX=22+10=32

5)WZ=WX+XY+YZ=3*WX=3*10=30

6)VY=VZ-YZ=52-10=42

The points V, W, X, Y and Z are collinear. The indicated lengths are

[tex]WX=10\\VW=22\\WY=20\\VX=32\\WZ=30\\VY=42[/tex]

Given :

points V, W, X, Y and Z are collinear, VZ= 52, XZ =20, and WX=XY=YZ

Lets make diagram using the given information

The diagram is attached below

XY=YZ

XZ=20, so [tex]XY+YZ=20\\Both XY and YZ are same\\XY+XY=20\\2XY=20\\Divide \; by \; 2\\XY=10[/tex]

[tex]WX=XY=YZ \\XY=10\\WY=10\\YZ=10\\[/tex]

Now we find out VW

[tex]VW+WX+XY+YZ=52\\VW+10+10+10=52\\VW+30=52\\Subtract \; 30\\VW=52-30\\VW=22[/tex]

Now we find the indicated length

[tex]WX =10[/tex]

[tex]VW=22\\WY=WX+XY=10+10=20\\VX=VW+WX=22+10=32\\WZ=WX+XY+YZ=10+10+10=30\\VY=VW+WX+XY=22+10+10=42[/tex]

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The city plans a roadway to have trees every mile. If the path is miles long, how many trees will the city need?


30 trees

31 trees

32 trees

33 trees

Answers

Answer:

32

Step-by-step explanation:

the country would need 30 to 33 trees

Ruth is touring New York City with her family. They want to visit the Empire State Building, Central Park, and Times Square before their dinner reservations at 7:10 P.M. They want to spend 1 hour and 25 minutes at the Empire State Building, 2 hours and 5 minutes in Central Park, and 50 minutes in Times Square. What is the latest time Ruth's family can start their tour in order to make it to dinner on time?

Pls help :)

Answers

Answer:

The latest time Ruth's family can start their tour in order to make it to dinner on time is 2:50 P.M

Step-by-step

Change:

7h10= 430 mins

1 hour and 25 minutes= 85 mins

2 hours and 5 mintues= 125 mins

- Total time Ruth wants to do before his dinner reservations:

85+ 125+ 50= 260 (mins)

- The latest time Ruth's family can start their tour in order to make it to dinner on time:

430- 260= 170 (mins)

Change: 170 mins= 2 hours and 50 minutes

Good luck!

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