Otto builds and sells model cars. He made a graph to compare the number of days to the number of model cars. Three of the points form a proportional relationship, but one does not. Which point does not fit in the proportional relationship? Coordinate plane with Number of Days on the x-axis and Number of Model Cars on the y axis. 4 points are plotted in the plane: 2, 1; 4, 2; 6, 2; and 8, 4. A (2, 1) B (4, 2) C (6, 2) D (8, 4)
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Need HELP ASAP

Answer:

Same side interior angles

x=10

Step-by-step explanation:

The angles are same side  interior angles

The add to 180 degrees

6x+10 + 110 = 180

Combine like terms

6x+120 =180

Subtract 120 from each side

6x = 180-120

6x= 60

Divide by 6

6x/6 = 60/6

x = 10

Answer:

Same-Side Interior Angles

Equation: 6x + 10 + 110 = 180

x = 10

Step-by-step explanation:

Hello!

The sum of the two given angles is 180°, as they are same-side interior angles.

Equation: 6x + 10 + 110 = 180

The value of x is 10°.

we can see that when they join with Carla, Carter and Isabella will get $200 less (individually).

When Carter and Isabella work together, they have a revenue of $6000, which is split in 50/50, so each one gets:

$6000/2 = $3000

Carter wins $3000 and Isabella wins $3000.

If they join with Carla, the revenue increases by $2400, so now the total revenue is:

$6000 + $2400 = $8400

And now they split it between 3, so each one gets:

$8400/3 = $2800

The difference of Carter's (Or Isabella's) part is:

$3000 - $2800 = $200

Then we can see that when they join with Carla, Carter and Isabella will get $200 less (individually).

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The depreciation expense per unit of production for the Textile Company is D. $0.20.

The unit-of-production depreciation method uses the useful life of an asset based on the units of production and the depreciable amount to estimate the depreciation expense per unit.

For each period, the depreciation expense per unit is multiplied by the units of production to determine the period's total depreciation expense.

Cost of equipment = $40,000

Residual value = $6,000

Depreciable amount = $34,000 ($40,000 - $6,000)

Estimated useful life = 170,000 units

Depreciation expense per unit of production = $0.20 ($34,000/170,000)

Thus, the depreciation expense per unit of production for A Textile Company is D. $0.20.

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The ordered pairs that is a solution to the linear inequality y > 3x + 2 is

(2, 9)

The inequality is as follows;

y > 3x + 2

Therefore, let's try option 1

(-1, -5)

-5 > 3(-1) + 2

-5 > -3 + 2

-5 > - 1 (This is false)

(–2, –7)

-7 > 3(-2) + 2

-7 > -6 + 2

-7 > -4 (This is false)

(2, 8)

8 > 3(2) + 2

8 > 6 + 2

8 > 8 (false)

(2, 9)

9 > 3(2) + 2

9 > 8 (This true)

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The total amount of the deposit is  $592.92.

The total amount of the deposit can be determined by adding all the money deposited together.

(47 x 1) + (22 x 5) + (9 x 10) + (17 x 20) + (67 x 0.01) + (0.05 x 12) + (9 x 0.1) + (15 x 0.25)

47 + 110 + 90 + 340 + 0.67 + 0.60 + 0.9 + 3.75 = $592.92

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The number of dogs in the animal shelter which comprise of cats, dogs, and rabbits is 84 dogs.

Total animals = 5 × 47

= 235

235 = d + (d + 20) + 1/2(d + 20) - 5

235 = d + d + 20 + 1/2d + 10 - 5

235 = 2 1/2d + 25

235 - 25 = 2 1/2d

210 = 2 1/2d

d = 210 ÷ 2 1/2

d = 210 ÷ 5/2

= 210 × 2/5

= 420/5

d = 84 dogs

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Using the Poisson distribution, we have that:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

The parameters are:

For this problem, the mean is given as follows:

[tex]\mu = 13[/tex]

The probability of having exactly 10 days of precipitation in the month of April is P(X = 10), hence:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 10) = \frac{e^{-13}13^{10}}{(10)!} = 0.0859[/tex]

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

The probability of having less than three days of precipitation in the month of April is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-13}13^{0}}{(0)!} \ approx 0[/tex]

[tex]P(X = 1) = \frac{e^{-13}13^{1}}{(1)!} = 0.00003[/tex]

[tex]P(X = 2) = \frac{e^{-13}13^{2}}{(2)!} = 0.00019[/tex]

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.00003 + 0.00019 = 0.00022

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

For more than 15 days, the probability is:

P(X > 15) = P(X = 16) + P(X = 17) + ... + P(X = 20)

Applying the formula for each of these values and adding them, we have that P(X > 15) = 0.2364, hence:

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

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Answer: (-1, 4)

Step-by-step explanation:

[tex]\left(\frac{-2+0}{2}, \frac{-1+9}{2} \right)=\boxed{(-1, 4)}[/tex]

(-1, 4) is the midpoint of the segment with endpoints at (-2,-1) and (0, 9). This can be obtained by using the formula for finding the midpoint of a line segment.

When the end points of a line segment are known, the mid point of the line segment is calculated using the midpoint formula,

Midpoint formula,

                   [tex](\frac{x_{1}+x_{2} }{2},\frac{y_{1}+y_{2} }{2})[/tex]

(x₁, y₁) and (x₂, y₂) are the endpoints of the line segment.

⇒ This means that, the midpoint of a line segment with endpoints (x₁, y₁) and (x₂, y₂) is [tex](\frac{x_{1}+x_{2} }{2},\frac{y_{1}+y_{2} }{2})[/tex].

From the question it is given that,

are the endpoints of the line segment.

By using the Midpoint formula we get,

[tex](\frac{x_{1}+x_{2} }{2},\frac{y_{1}+y_{2} }{2})[/tex] = [tex](\frac{-2+0 }{2},\frac{-1+9}{2})[/tex]

[tex](\frac{x_{1}+x_{2} }{2},\frac{y_{1}+y_{2} }{2})[/tex] = [tex](-1, 4)[/tex]

Hence (-1, 4) is the midpoint of the segment with endpoints at (-2,-1) and  (0, 9).

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The adjoint of the matrix [tex]\left[\begin{array}{cc}1&0\\2&-1\end{array}\right][/tex] is [tex]\left[\begin{array}{cc}-1&0\\-2&1\end{array}\right][/tex]

The matrix is given as:

[tex]\left[\begin{array}{cc}1&0\\2&-1\end{array}\right][/tex]

For a matrix A be represented as:

[tex]A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right][/tex]

The adjoint is:

[tex]Adj = \left[\begin{array}{cc}d&-b\\-c&a\end{array}\right][/tex]

Using the above format, we have:

[tex]Adj = \left[\begin{array}{cc}-1&0\\-2&1\end{array}\right][/tex]

Hence, the adjoint of the matrix [tex]\left[\begin{array}{cc}1&0\\2&-1\end{array}\right][/tex] is [tex]\left[\begin{array}{cc}-1&0\\-2&1\end{array}\right][/tex]

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The pieces of information that is provided by the box plots are the median and first quartile.

The piece of information that is not provided by the box plots is the mean.

The interquartile range is 22.50.

An outlier would distort the values of the median and the quartiles.

A box plot is used to study the distribution and level of a set of scores. The end of the first line represents the minimum number and the end of the second line represents the maximum number.

On the box, the first line to the left represents the lower (first) quartile. The next line on the box represents the median.  The third line on the box represents the upper (third) quartile. The difference between the quartiles is the interquartile range.

Interquartile range = 60 - 37.50 = 22.50

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The piece-wise linear functions can be written as follows:

A linear function is modeled by:

y = mx + b

In which:

For x less than 5, the y-intercept is of b = 3 and the function also gos through (2,2), hence the slope is:

m = (2 - 3)/(2 - 0) = -0.5.

Hence the rule is:

[tex]f(x) = -0.5x + 3, x < 5[/tex].

When x = 5, the function is constant at -5, hence:

[tex]f(x) = -5, x = 5[/tex]

For x less than 5, the function goes through points (6,3) and (7,2), hence the slope is:

m = (2 - 3)/(7 - 6) = -1.

Then:

y = -x + b

When x = 6, y = 3, hence the y-intercept is given as follows:

3 = -6 + b

b = 9.

Hence the rule is:

[tex]f(x) = -x  + 9, x > 5[/tex].

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The pressure of the submarine at a depth of 23000 meters is 2.3575 * 10⁸ N/m²

An equation is an expression that shows the relationship between two or more variables and numbers.

Pressure = density * acceleration due to gravity (g) * depth

g = 10 m/s², hence:

Pressure = 1025 * 10 * 23000 = 2.3575 * 10⁸ N/m²

The pressure of the submarine at a depth of 23000 meters is 2.3575 * 10⁸ N/m²

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Using the law of cosines, it is found that the approximate length of side a is 3.99 units.

The law of cosines states that we can find the side c of a triangle as follows:

[tex]c^2 = a^2 + b^2 - 2ab\cos{C}[/tex]

in which:

In the context of this problem, we have that side a is opposite to the angle of 53º, hence:

[tex]a^2 = b^2 + c^2 - 2bc\cos{53^\circ}[/tex]

We are given that:

Then:

[tex]a^2 = 34 - 30\cos{53^\circ}[/tex]

a² = 15.95

[tex]a = \sqrt{15.95}[/tex]

a = 3.99.

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Answer:

22222222222222222222222222+22222222

Answer:

when the question is rearranged so that y is by itself, any of the options that say - 2.5x will be parallel.

Step-by-step explanation:

5x + 2y = 1

to get y by itself, simple algebra rules must be applied.

1. subtract 5x from both sides.

5x - 5x + 2y = 1 - 5x

2y = 1 - 5x

divide both sides by 2

2y / 2 = 1 / 2 - 5x / 2

therefore the new equation is:

y = 0.5 - 2.5x

this is very close to standard form for a line which is y = mx + b

rearrange the right side of the equals sign:

y = -2.5x + 0.5

in a standard linear equation, the x value determines the gradient of the line. therefore, anything with the same gradient (in this case -2.5x) will be parallel to the given equation.

Hope this makes sense :)

The average price paid by him for the shares after 3 months is ksh. 163.33

Average price paid for the shares after 3 months

= (120 + 160 + 210) / 3

= 490 / 3

= 163.333333333333

Approximately,

ksh. 163.33

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Answer:

#3 5(2a+4)

#4 5(a+2+4)

#5 5a+5(2+4)

Step-by-step explanation:

I think so, I am probably wrong

Answer: Use this calculator to easily calculate the area of a trapezoid given its base s and height. The formula for the area of a trapezoid is (base 1 + base 2) / 2 x height,

Step-by-step explanation:

The cubic foot is a unit of volume used in the imperial and U.S. customary measurement systems.

The cubic foot can be used to describe a volume of a given material, or the capacity of a container to hold such a material.

hi,

a point is given  ( x; y)

standar line equation is  :  y = ax+b

So  with  (3;5)  and  (8;15)  we have  :  

   3a+b = 5

   8a+b = 15

so :  

8a+b - ( 3a +b) =  15 -5

8a +b -3a -b = 10

8a-3a = 10

5a = 10

   a = 10/5

    a = 2

if a = 2  so  3*2 +b = 5

                     6+b = 5

                       b = 5-6

                       b = -1

so let check :  

8*2 + (-1) = 16 -1 = 15

and  3*2 -1 = 6-1 = 5

coordonnate works for both point, so line  is   y = 2x -1

Answer:

62 inches

Step-by-step explanation:

Since we need to leave 2 cm of room on both sides, the maximum width of TV is 136 - 2 - 2 = 132 cm. Next, use the Pythagorean Theorem, a^2 + b^2 = c^2, to find the diagonal.

132^2 + 86^2 = c^2

c^2 = 17424 + 7396

c^2 = 24820

c = 157.543644746 cm

Finally, convert the value to inches using the given conversion factor.

157.543644746/2.54 = 62.0250569868 inches

Answer:

1.  x = -1  y= -2
2. infinitely many solutions

3. x = 6 y= -7

4.no solution

5. x = -3 y = -17

6. x= 3 y = 7

Step-by-step explanation:

1) y=x-1

7x+6y= -19

6y= -19 -7x

y= (-7x-19)/6

since x-1 and (-7x-19)/6 are both equal to y they are equal to each other

this is how to get x

x-1 = (-7x-19)/6

6x-6 = -7x-19

13x = -13

x = -1

now put back -1 in the equation to get y

y=x-1

y = -1 -1

y= -2

2)-10x+2y=-12

y=5x-6

2y= -12 + 10x

y= -6 + 5x

y = 5x - 6

5x-6 = 5x - 6

0 = 0

when something is

equal to itself its

infinitely many solutions

(when something is not equal to something its no solution)

((when something is equal to just one answer its one solution)

3) y= -4x+17

y=x-13

-4x+17 = x-13

30 = 5x

x = 6

y=x-13

y=6-13

y= -7

4) -3x-15y=8

x+5y=5

-3x-15y=8 -> y = -1/15(3x-8)

5y=5-x -> y= 1/5 (5-x)

-1/15(3x-8) = 1/5 (5-x)

-x-8/3 = 5-x

0 = 23/3

(when something is not equal to something its no solution)

5) -3x+6y=-3

3x-y=8

-3x+6y= -3 -> y = 1/6(3x-3)

3x-y=8 -> y = 3x-8

1/6(3x-3) = 3x-8

3x-3 = 18x-48

x-1 = 6x - 16

5x = -15

x = -3

3x-y=8

3(-3)-y=8

-9-8 = y

y = -17

6) -6x+6y=24

-3x-8y=1

-6x+6y=24 -> y = 1/6(6x+24) -> y = x+4

-3x-8y=1 -> -3x-1 = 8y -> y = 1/8 (-3x-1)

1/8 (-3x-1) = x+4

-3x-1 = 8x+32

11x = 33

x= 3

-6x+6y=24

-6(3)+6y=24

-18 + 6y = 24

6y = 24 + 18

6y = 42

y = 7

There are no real solutions to solve Z. If there may be a typo or something, there are no solutions.

The algebraic description that maps the image ΔABC onto ΔA′B′C′ is (x, y) ⇒ (x + 7, y - 4)

Transformation is the movement of a point from its initial location to a new location. Types of transformations are reflection, rotation, translation and dilation.

Translation is the movement of a point either up, left, right or down in the coordinate plane.

The algebraic description that maps the image ΔABC onto ΔA′B′C′ is (x, y) ⇒ (x + 7, y - 4)

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The area of the region that lies inside both curves r² = 2sin(2θ),  r = 1 is -0.1287 square units.

Since the curves are

We find their point of intersection.

So, r² = r²

2sin(2θ) = 1²

2sin(2θ) = 1

sin(2θ) = 1/2

2θ = sin⁻¹(1/2)

2θ = π/6

θ = π/12

So, we integrate the area from θ = 0 to θ = π/12

Now the area A of the region between two curves between θ = α to θ = β is

[tex]A = \int\limits^{\beta }_\alpha ({r^{2} - r^{'2} }) \, d\theta[/tex]

So, the area betwwen the curves r² = 2sin(2θ),  r = 1 between θ = 0 to θ = π/12 is

[tex]A = \int\limits^{\frac{\pi}{12} }_0 ({r^{2} - r^{'2} }) \, d\theta \\= \int\limits^{\frac{\pi}{12} }_0 ({2sin2\theta - 1^{2} }) \, d\theta\\= \int\limits^{\frac{\pi}{12} }_0 ({2sin2\theta - 1}) \, d\theta\\= \int\limits^{\frac{\pi}{12} }_0 {2sin2\theta}\, d\theta - \int\limits^{\frac{\pi}{12} }_0 {1} \, d\theta\\= [2(-cos2\theta)/2 - \theta]_{0}^{\frac{\pi}{12} } \\= [-cos2\theta - \theta]_{0}^{\frac{\pi}{12} } \\= -cos2\frac{\pi}{12} - \frac{\pi}{12} - ( -cos2(0) - 0)\\[/tex]

[tex]= -cos2(\frac{\pi}{12}) - \frac{\pi}{12} - ( -cos2(0) - 0)\\= -cos\frac{\pi}{6}- \frac{\pi}{12} - ( -cos0 - 0)\\= -cos\frac{\pi}{6}- \frac{\pi}{12} - ( -1)\\= -(\frac{\sqrt{3} }{2} ) - \frac{\pi}{12} + 1\\= -0.8660 - 0.2618 + 1\\= -1.1278 + 1\\= -0.1278[/tex]

So, the area of the region that lies inside both curves r² = 2sin(2θ),  r = 1 is -0.1287 square units.

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Answer:

(-∞, -1) U (0, ∞)

Step-by-step explanation:

To figure out which parts of the function are decreasing, we need to read the graph left to right.

Given this information, we can figure out that the first part of the graph is decreasing, starts to go up a little bit, and then starts to decrease again.

How do we write this in mathematical terms, however? We simply take the x-values for which parts it decreases.

The graph started on negative infinity, and kept decreasing until -1 on the x-axis. We can write this as (-∞, -1). The graph starts to increase, which is not relevant to the question. As it starts to decrease again, it starts on 0, and slowly decreases to the right, meaning that it is going towards positive infinity. We can write this as (0,∞).

Now that we have both parts of the decreasing function, we can combine them using the union symbol (∪).

Therefore, our final answer is (-∞, -1) U (0, ∞).  

The scale factor Of the larger prism to the smaller prism is 0.9

The given parameters are

Large area = 441

Small area = 361

Divide the small area by the large area

Small/Large = 361/441

Take the square root to determine the scale factor k

[tex]k = \sqrt{\frac{361}{441}[/tex]

Evaluate

k = 0.9

Hence, the scale factor Of the larger prism to the smaller prism is 0.9

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Answer:

A) 69

Step-by-step explanation:

• First , we put the numbers of the distribution in order:

60 , 66 , 72 , 78 , 80 , 82 , 88 , 90

• Notice that the set has 8 numbers which is an even number.

Then

→ the lower quartile is the mean of the set :

60 , 66 , 72 , 78

Which is the average of the two middle numbers 66 and 72.

Then

[tex]\text{the lower quartile}=\frac{66+72}{2} = 69[/tex]

Cultural identity component of an individual which makes him identifiable with a given group. For example, British Asian is a cultural identity.

Cultural identity can be described as a component of an individual which makes him identifiable with a given group that share the same characteristics.

Examples of cultural identities may include the following:

I can state that I am a British Asian. British Asian is my cultural identity.

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