The law that relates the absolute pressure to atmospheric pressure and gauge pressure is Pascal law.
What is Pascal law?
Pascal's law states that when an object is immersed in a fluid, it experiences equal pressure on all surfaces.
P = Patm + pgh
where;
P is absolute pressurepgh is gauge pressurePatm is atmospheric pressureThus, the law that relates the absolute pressure to atmospheric pressure and gauge pressure is Pascal law.
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describe one similarity and one difference between the velocity on the reference circle and the velocity on the pendulum
SHM can be acquired by perpendicular projection of uniform circular motion of a particle on its diameter such a particle is called reference particle and its circular path is called reference circle.
A pendulum reaches its maximum velocity when the block is at its lowest point (the pendulum is vertical and pointing straight down). We can then use the term for conservation of energy to determine the maximum height of the block.
What is the velocity at the bottom of a pendulum?
As the pendulum swings downward, gravity converts this potential energy into kinetic energy, so that at the bottom of the swing, the pendulum bob has zero potential energy, and its kinetic power, (1/2)mv2, equals the initial potential energy (mgh). (So the velocity, v, equals √(2gh).)
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The small spherical planet called "Glob" has a mass of 7.88×10^18 kg and a radius of 6.32×10^4 m. An astronaut on the surface of Glob throws a rock straight up. The rock reaches a maximum height of 1.44×10^3 m, above the surface of the planet, before it falls back down.
1. What was the initial speed of the rock as it left the astronaut's hand? (Glob has no atmosphere, so no energy is lost to air friction. G = 6.67×10^-11 Nm2/kg2.)
2. A 36.0 kg satellite is in a circular orbit with a radius of 1.45×10^5 m around the planet Glob. Calculate the speed of the satellite.
(a) The initial speed of the rock as it left the astronaut's hand is 19.35 m/s.
(b) The speed of the satellite is 50.24 m/s.
Acceleration due to gravity of the planet
g = GM/R²
where;
M is mass of the planetR is radius of the planetg = (6.67 x 10⁻¹¹ x 7.88 x 10¹⁸)/(63200)²
g = 0.13 m/s²
Initial speed of the rockv² = u² - 2gh
where;
v is final velocityu is initial velocityat maximum height, v = 0
u² = 2gh
u = √2gh
u = √(2 x 0.13 x 1,440)
u = 19.35 m/s
Speed of the satellitev = √GM/r
M is mass of the planet Globr is the total distance from the center of the planet Globr = radius of planet Glob + radius of the satellite
r = 63200 m + 145,000 m = 208,200 m
v = √[(6.67 x 10⁻¹¹ x 7.88 x 10¹⁸)/(208,200)]
v = 50.24 m/s
Thus, the initial speed of the rock as it left the astronaut's hand is 19.35 m/s.
The speed of the satellite is 50.24 m/s.
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An astronaut on a spacewalk 200km above Earth drops a hammer (mass 2kg), which goes into orbit about the Earth (radius 6,400km) How long does it take the hammer to orbit the Earth?
Answer:
See below
Explanation:
T = period of orbit = sqrt ( 4 pi^2 r^3 / (G Me) )
G = gravitational constant 6.6743 x 10^-11 m^3 / (kg-s^2)
Me = mass of earth = 6 x 10^24 kg
r = radius = 6600 km = 6,600,000 m
plug in the values to find T = 5323.75 seconds
(check my math)
*Look at attachment for photo of object**
An object, whose mass is 0.520 kg, is attached to a spring with a force constant of 106 N/m. The object rests upon a frictionless, horizontal surface (shown in the figure below).
The object is pulled to the right a distance A = 0.150 m from its equilibrium position (the vertical dashed line) and held motionless. The object is then released from rest.
(a) At the instant of release, what is the magnitude of the spring force (in N) acting upon the object?
__________ N
(b) At that very instant, what is the magnitude of the object's acceleration (in m/s2)?
________ m/s2
(c)
In what direction does the acceleration vector point at the instant of release?
- The direction is not defined (i.e., the acceleration is zero).
- Toward the equilibrium position (i.e., to the left in the figure).
- Away from the equilibrium position (i.e., to the right in the figure).
- You cannot tell without more information.
A. The magnitude of the spring force (in N) acting upon the object is 15.9 N
B. The magnitude of the object's acceleration (in m/s²) is 30.58 m/s²
C. The direction of the acceleration vector points toward the equilibrium position (i.e., to the left in the figure).
A. How to determine the force Extension (e) = 0.150 mSpring constant (K) = 106 N/mForce (F) = ?F = Ke
F = 106 × 0.15
F = 15.9 N
B. How to determine the accelerationMass (m) = 0.52 KgForce (F) = 15. 9 NAcceleration (a) =?F = ma
Divide both sides by m
a = F / m
a = 15.9 / 0.52
a = 30.58 m/s²
C. How to determine the direction of the acceleration vectorConsidering the diagram, we can see that the spring was pulled away from the equilibrium point.
Thus, when the spring is released, it will move toward the equilibrium point. This is also true about the acceleration.
Therefore, we can conclude that the direction of the acceleration vector is towards the equilibrium point.
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Select the correct answer. Which graphs show the correct relationship between kinetic energy and mass? A. Graph representing a relationship between mass on the x-axis and kinetic energy on the y-axis. the line starts at the origin and increases upwards B. Graph representing the relationship between mass on the x-axis and kinetic energy on the y-axis. the curve starts at the origin and keeps on increasing C. Graph representing a linear relationship between mass on the x-axis and kinetic energy on the y-axis D. Graph representing a relationship between mass on the x-axis and kinetic energy on the y-axis. the line starts at the origin and increases as it goes with a small bend Reset Next
C. Graph representing a linear relationship between mass on the x-axis and kinetic energy on the y-axis.
What is kinetic energy?
Kinetic energy is the energy possessed by a body due to its motion.
K.E = ¹/₂mv²
where;
m is mass of the objectThe kinetic energy of a body is directly proportional to the mass of the object.
Thus, the correct relationship between kinetic energy and mass is Graph representing a linear relationship between mass on the x-axis and kinetic energy on the y-axis.
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A 45-kg pole vaulter running at 10 m/s vaults over the bar. Her speed when she is above the bar is 1.1 m/s. Neglect air resistance, as well as any energy absorbed by the pole, and determine her altitude as she crosses the bar.
_______m
The altitude or height of the pole vaulter as she crosses the bar is 4.04 m.
What is the height of the pole vaulter?The height of the pole vaulter is determined from the change in kinetic energy which is equal to the potential energy at that height.
Potential energy = Change in kinetic energymgh = m(v - u)²/2h = (v - u)²/2g
h = (10 - 1.1)²/2 * 9.8
h = 4.04 m.
In conclusion, the height is determined from the potential energy at that height.
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A fisherman and his young son are in a boat on a small pond. Both are wearing life jackets. The son is holding a large helium filled balloon by a string. Consider each action below independently and indicate whether the level of the water in the pond, Rises, Falls, is Unchanged or Cannot tell.
The son pops the helium balloon.
The fisherman knocks the tackle box overboard and it sinks to the bottom.
The son finds a cup and bails some water out of the bottom of the boat
The fisherman lowers himself in the water and floats on his back.
The fisherman lowers the anchor and it hangs one foot above the bottom of the pond.
The son gets in the water, looses his grip on the string, letting the balloon escape upwards.
Based on the weight of the objects in the water, the water level in the given scenario is as follows;
unchangedrisesfallsunchangedrisesrisesWhat changes will be observed in each of the given scenario?The rise or fall of a fluid when an object is placed in it is determined by the density, mass, and volume of the object.
According to Archimedes' principle, the upthrust or upward force acting on a body fully or partially immersed in a fluid, is equal to the weight of the fluid displaced.
Considering the given situations:
The son pops the helium balloon - water level is unchanged because the weight of the balloon is negligible.Fisherman knocks the tackle box overboard and it sinks to the bottom - water level will rise since the tackle box has significant weightSon finds a cup and bails some water out of the bottom of the boat - water level will fall since some volume of water is being removed and added to the boat.Fisherman lowers himself in the water and floats on his back - water level is unchanged because no additional weight is added to the waterFisherman lowers the anchor and it hangs one foot above the bottom of the pond - water level will rise since the anchor will displace some volume of water equal to its weight in the pondSon gets in the water, looses his grip on the string, letting the balloon escape upwards- water level will rise since the weight of the balloon and string are significant.In conclusion, the rise in water level depends on the weight of the objects.
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A car is being tested on a track. The driver approaches the test section at a speed of 28 m s−1. He then accelerates at a uniform rate between two markers separated by 100 m. The car reaches a speed of 41 m s−1.
The uniform acceleration of the car is 4.485 m/s².
Acceleration of the car
The uniform acceleration of the car is calculated as follows;
v² = u² + 2as
a = (v² - u²)/2s
where;
v is final velocity = 41 m/su is initial velocity = 28 m/ss is distance = 100 ma is acceleration = ?a = (41² - 28²)/(2 x 100)
a = 4.485 m/s²
Thus, the uniform acceleration of the car is 4.485 m/s².
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All moving objects have ____________.
A. Force
B. Distance
C. Momentum
D. Time
Answer:
I think it's force
Explanation:
Mark as brainliest if it is right
Answer: A
Explanation:
Force can cause a stationary object to start moving or a moving object to change its speed or direction or both
Currents in dc transmission lines can be 100 A or higher. Some people are concerned that the electromagnetic fields from such lines near their homes could pose health dangers.
a) For a line that has current 150 A and a height of 8.0 m above the ground, what magnetic field does the line produce at ground level? Express your answer in teslas.
b) What magnetic field does the line produce at ground level as a percent of the earth's magnetic field, which is 0.50 G .
c) Is this value of magnetic field cause for worry?
Yes. Since this field does not differ a lot from the earth's magnetic field, it would be expected to have almost the same effect as the earth's field.
No. Since this field does not differ a lot from the earth's magnetic field, it would be expected to have almost the same effect as the earth's field.
Yes. Since this field is much greater than the earth's magnetic field, it would be expected to have more effect than the earth's field.
No. Since this field is much smaller than the earth's magnetic field, it would be expected to have less effect than the earth's field.
(a) The magnetic field the line produced at ground level is 3.75 x 10⁻⁶ T.
(b) The lines magnetic field as a percent of the earth's magnetic field is 7.5%.
(c) No, since this field is much smaller than the earth's magnetic field, it would be expected to have less effect than the earth's field.
Magnetic field the line produced at ground levelB = (μ x I) / (2πr)
B = (4π x 10⁻⁷ x 150) / (2π x 8)
B = 3.75 x 10⁻⁶ T
Percent of the earth's magnetic fieldx = 3.75 x 10⁻⁶ /0.5G
x = (3.75 x 10⁻⁶ ) / (0.5 x 10⁻⁴)
x = 0.075
x = 0.075 x 100% = 7.5%
Thus, we can conclude that, since this field is much smaller than the earth's magnetic field, it would be expected to have less effect than the earth's field.
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please help me with this physics question ASAP
Answer:
See below
Explanation:
With switches open, the circuit is a simple series circuit ....the ammeters will have the same readings
V = IR
I = V/R = 5 / (10+5+5) = .25 A
b) With S1 closed 5 ohm and 10 ohm in parallel become = 5 *10 / (5+10) = 3.33 ohm
then the series circuit current becomes
5 v / ( 10 + 3.33 + 5 ) = ammeter 1 = .273 amps
ammeter 2 will get a portion of this ...the smaller resistor will get 2/3 ...the 10 ohm resistor will get 1/3 .273 * 10 / 15 =.182 amps
Which best describes the results of Becquerel’s experiments?
Both forming images when placed in their respective places best describes Becquerel’s experiments.
What is Becquerel’s experiment?This was conducted by Henri Becquerel in which he sought to know how uranium salts are affected by light.
He discovered that the salts emits a penetrating radiation and formed an image in the presence of light but didn't form any in darkness.
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Two spheres with uniform surface charge density, one with a radius of 7.4 cm and the
other with a radius of 5.0 cm, are separated by a center-to-center distance of 38 cm. The
spheres have a combined charge of +55μC and repel one another with a force of 0.62 N.
Assume that the charge of the first sphere is greater than the charge of the second sphere.
Question 1.
What is the surface charge density in the sphere of radius 7.4?
Question 2
What is the surface density on the 2nd sphere?
EXPRESS ANSWER USING TWO SIGNIFICANT FIGURES.
(a) The surface charge density in the sphere of radius 7.4 is 0.0322 C/m³.
(b) The surface density on the 2nd sphere is 3.48 x 10⁻⁴ C/m³.
Total charge of the spheresF = kq₁q₂/r²
Fr² = kq₁q₂
q₁q₂ = Fr²/k
where;
r is distance between the chargesk is Coulomb's constantq₁q₂ = (0.62 x 0.38²) / (9 x 10⁹)
q₁q₂ = 9.95 x 10⁻¹² C
q₂ = 9.95 x 10⁻¹² C/q₁
From the question;
q₁ + q₂ = 55 x 10⁻⁶
q₁ + 9.95 x 10⁻¹² /q₁ = 55 x 10⁻⁶
q₁² + 9.95 x 10⁻¹² = 55 x 10⁻⁶q₁
q₁² - 55 x 10⁻⁶q₁ + 9.95 x 10⁻¹² = 0
solve the quadratic equation using formula method;
q₁ = 5.48 x 10⁻⁵ C
q₂ = 55 x 10⁻⁶ C - 5.48 x 10⁻⁵ = 1.82 x 10⁻⁷ C
Volume of the first sphereV1 = ⁴/₃πr³
V1 = (⁴/₃ π)(0.074)³ = 1.7 x 10⁻³ m³
Surface charge density = (5.48 x 10⁻⁵ C) / (1.7 x 10⁻³ m³) = 0.0322 C/m³
Volume of the second sphereV2 = (⁴/₃ π)(0.05)³ = 5.236 x 10⁻⁴ m³
Surface charge density = ( 1.82 x 10⁻⁷ C) / (5.236 x 10⁻⁴ m³) = 3.48 x 10⁻⁴ C/m³
Thus, the surface charge density in the sphere of radius 7.4 is 0.0322 C/m³.
The surface density on the 2nd sphere is 3.48 x 10⁻⁴ C/m³.
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A jet of water squirts out horizontally from a hole near the bottom of the tank, as seen in the figure.
If the hole has a diameter of 3.13 mm, what is the height, h, of the water level in the tank? Assume that x = 1.33 m and y = 1.72 m.
The height, h, of the water level in the tank is mathematically given as
h=1.3675
What is the height, h, of the water level in the tank?Generally, the equation for kinematics is mathematically given as
S=v_o t+(1/2)at^2
Therefore
y=0+(1/2)gt^2
Where
t=(2y/g)^{1/2}
t=(2*1.72/9.8)^{1/2}
t=0.5925s
The horizontal exit velocity will be given as
[tex]Vx=x/t[/tex]
Therefore
[tex]Vx=\frac{0.3.13}{0.5925}[/tex]
Vx=0.5283
In conclusion, applying Bernoulli's Law the tank bottom and tank surface
P+(1/2)pv0^2+pgh=P+(1/2)pvx^2+pgh
(1/2)(p)(0m/s)^2+pgh=(1/2)pvx^2+pg(0m)
gh=(1/2)vx^2
h=(0.5283m/s)^2/(2)(9.8)
h=1.3675
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A proton moving along the positive x-axis enters a uniform magnetic field which is directed along the
positive y-axis. If the magnitude of the field is 0.7 T, and the charge and speed of the proton are 1.5 x10-19 C
and 3.0 x 106 m/s respectively. Calculate the force acting on the proton
Answer: The force acting on the proton of charge 1.5 x10-19 C moving with velocity 1.5 x10-19 C under the influence of a magnetic field of 0.7 T will be 3.15×10^-13 N.
Explanation: To find the answer we need to know more about the Lorentz magnetic force.
What is the Lorentz magnetic force acting on the proton?Consider a proton of charge q moving with a velocity v in a magnetic field, then the Lorentz magnetic force exerted on the proton can be expressed as,F= q (v× B)
[tex]F= qvBsin\alpha[/tex] where, [tex]\alpha[/tex] is the angle between v and B.
In the question, it is given that,[tex]B=0.7 T\\q=1.5*10^{-19}C\\v= 3*10^{6}m/s.\\\alpha =90 degree.\\[/tex] because, from the question it is clear that the proton is moving along x axis and the magnetic field is along the y axis.
Thus, we can find the force acting on the proton as,[tex]F=qvBsin\alpha =1.5*10^{-19}C*3*10^6 m/s*0.7T*sin (90)\\F=3.15*10^{-13}N[/tex]
Thus, we can conclude that the Lorentz force acting on the proton will be 3.15×10^-13 N.
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In response to a magnetic field of 0.7 T, a proton with a charge of 1.5 x 10-19 C travelling at a speed of 1.5 x 10-19 C will experience a force of 3.15 x 10^-13 N.
We need to learn more about the Lorentz magnetic force in order to locate the solution.
What does the proton experience as the Lorentz magnetic force?If you imagine a proton with charge q travelling at speed v in a magnetic field, you can write down the Lorentz magnetic force acting on the proton as,F= Q (v× B)
[tex]F=QvBsin\alpha[/tex]
[tex]\alpha[/tex] the angle between v and B is, where.
It is stated in the query that, the magnetic field is along the y axis and the proton is travelling along the x axis. Thus, the angle will be 90 degrees.As a result, we can identify the proton's driving force as,[tex]F=3.15*10^{-13}N[/tex]
Thus, we can infer that the proton will be subject to a 3.15 10^-13 N Lorentz force.
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1. Is the image projected on a movie screen real or virtual? What about the image of yourself seen in a bathroom mirror?
2. Hold a shiny spoon in front of you. What differences do you notice about the image of your face seen in the convex and concave sides?
3. Where are the images formed by each side of the spoon? In front or behind the spoon? (Try the parallax method. Look at the image of an overhead light. Hold the tip of a pencil where you think the image is. Move your head from side to side. If the image and pencil tip appear to move relative to each other, adjust the position of the pencil back and forth until they appear as one)
Answer: 1. The movie one is virtual and the bathroom mirror is real
2. The image is distorted in a way
3. Behind the spoon
Explanation:
The movie one is virtual and the bathroom mirror is real and The image is distorted in a way and Behind the spoon.
What is virtual screen?In virtual desktops, the desktop environment is segregated from the physical device being used to access it. They are preloaded images of operating systems and apps. Over a network, users can remotely view their virtual desktops.
A virtual desktop can be accessed from any endpoint device, including a laptop, smartphone, or tablet. The user interacts with the client software that was installed on the endpoint device by the virtual desktop provider.
A virtual desktop mimics the appearance and feel of a real workstation. Because robust resources, like storage and back-end databases, are easily accessible, the user experience is frequently even better than that of a physical workstation.
Therefore, The movie one is virtual and the bathroom mirror is real and The image is distorted in a way and Behind the spoon.
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Find the speed of a satellite in a circular orbit around the Earth with a radius 3.57 times the mean radius of the Earth. (Radius of Earth = 6.37×103 km, mass of Earth = 5.98×1024 kg, G = 6.67×10-11 Nm2/kg2.)
The speed of a satellite in a circular orbit around the Earth is 4,188 m/s.
Speed of the satelliteThe speed of the satellite is calculated as follows;
v = √GM/r
where;
M is mass of Earthr is radius of satellitev = √[(6.67 x 10⁻¹¹ x 5.98 x 10²⁴) / (3.57 x 6.37 x 10⁶)]
v = 4,188 m/s
Thus, the speed of a satellite in a circular orbit around the Earth is 4,188 m/s.
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The figure below shows a motorcycle leaving the end of a ramp with a speed of 39.0 m/s and following the curved path shown. At the peak of the path, a maximum height h above the top of the ramp, the motorcycle's speed is 37.1 m/s. What is the maximum height h? Ignore friction and air resistance. (Enter your answer in m.)
_____m
The maximum height h of the curved path is 7.38 m.
Maximum height of the curved path
Apply the following kinematic equation;
v² = u² - 2gh
where;
v is the final velocity of the motorcycleu is initial velocity of the motorcycleh is the maximum height(u² - v²)/2g = h
(39² - 37.1²)/(2 x 9.8) = h
7.38 m = h
Thus, the maximum height h of the curved path is 7.38 m.
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Which of the following is an example of an offensive action?
An example of an offensive action is B. kicking a ball into the goal
Something that is offensive upsets or embarrasses people because it is rude or insulting.
What is a example of an offensive action?Offensive is an arranged campaign or plan of action, normally created by the military or planned to achieve some specific political aim or goal. A military plan to strike is an example of a military offensive. A plan to fight the war on medications is an instance of an offensive.
What are the types of offensive operations?The four types of offensive operations are move to contact, attack, exploitation, and pursuit.
Leaders direct these offensive operations sequentially and in combination to generate highest combat power and destroy the enemy.
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A golf ball is driven from a point A with a speed of 40 m/s at an angle of elevation of 30°. On its downward flight, the ball hits an advertising hoarding at a height 15.1 m above the level of A, as shown in the diagram below. Find A. The time taken by the ball to reach its greatest height above A, B. The time taken by the ball to travel from A to B, C. The speed with which the ball hits the hoarding. 20
(a) The time taken by the ball to reach its greatest height is 2 seconds.
(b) The time taken by the ball to travel from A to B, C is 4.08 m/s.
(c) The speed with which the ball hits the hoarding is 69.3 m/s.
Maximum height of the projectile
H = u²sin²θ/2g
H = (40² x (sin 30)²) / (2 x 9.8)
H = 20.4 m
Time for the ball to travel 20.4 mh = ut - ¹/₂gt²
20.4 = (40 x sin 30)t - (0.5)(9.8)t²
20.4 = 20t - 4.9t²
4.9t² - 20t + 20.4 = 0
solve the quadratic equation using formula method;
t = 2 seconds
Time taken for the ball to travel A, B , CThis is the time of motion of the ball;
T = 2usinθ/g
T = (2 x 40 sin 30)/9.8
T = 4.08 s
Speed of the ball when it hits the hoardingv = u + gt
vy = 40 sin30 + (9.8 x 4.08)
vy = 59.98 ms
vx = 40 x cos30
vx = 34.64 m/s
vf = √(vy² + vx²)
vf = √(59.98² + 34.64²)
vf = 69.3 m/s
Thus, the time taken by the ball to reach its greatest height is 2 seconds.
The time taken by the ball to travel from A to B, C is 4.08 m/s.
The speed with which the ball hits the hoarding is 69.3 m/s.
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This technique allowed multiple peoples DNA to be compared to look for
similarities and differences in order to solve crime
DNA Examination
DNA Elimination
ODNA Sequencing
ODNA Fingerprinting
*2
DNA sequencing is the technique which allows multiple peoples DNA to be compared to look for similarities and differences in order to solve crime and is denoted as option C.
What is DNA?This is referred to as the deoxyribonucleic acid and contains the genetic components of organisms and is also located in the nucleus. On the other hand, DNA sequencing refers to the process of determining the nucleic acid sequence.
Each organisms has a unique DNA sequence which is why it is used to identify individuals through the use of bodily fluids such as saliva, blood etc.
It is used to compare the similarities and differences in order to solve crime thereby making it the most appropriate choice.
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Part B
A roller coaster ride starts with the roller coaster car being pulled to the top of the first hill with pulley system. The car is
released from the top with an initial velocity close to zero, then accelerates downward. From that first hill, the roller coaster just
coasts; there is no driving force, other than gravity, to keep It going. Assuming no friction, what can you say about the height of
the other hills in the roller coaster ride?
The highest point of a roller coaster is almost always the first hill. In the majority of roller coasters, the hills get smaller as the train travels down the track.
To find the answer, we have to know more about the mechanical energy of a system.
How to find the answer?Since it influences the mechanical energy of the system, the first hill must be the highest.One of the fundamental tenets of physics is that, in the absence of friction, mechanical energy must be conserved. Mechanical energy is the product of kinetic energy and potential energy.When the vehicles ascend the first hill on the roller coaster, mechanical energy is provided to the system because the speed is zero at this point.Mechanical energy = U = mgh
Where m represents the car mass, g represents gravity, and h represents height
If the system is to continue moving, the other hills on the mountain must be lower than the first hill. When the vehicles are released, this energy is converted into kinetic and potential energy when it lowers and ascends, but the sum of these two cannot be larger than the starting energy.Finally, by applying the principle of energy conservation, we may determine that, the initial hill must be the highest.
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A rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. Calculate the normal force (in N) acting on an astronaut of mass 87.4 kg, including his space suit. (Assume the rocket's initial motion parallel to the +y-direction. Indicate the direction with the sign of your answer.)
According to Newton's 3rd law, there will be equal and opposite force on the astronaut which is -6048 N
What does Newton's third law say ?The law state that in every action, there will be equal and opposite reaction.
Given that a rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. We are to calculate the normal force (in N) acting on an astronaut of mass 87.4 kg, including his space suit.
Let us first calculate the force involved in the acceleration of the rocket by using the formula
F = ma
Where mass m = 87.4 kg, acceleration a = 69.2 m/s2
Substitute the two parameters into the formula
F = 87.4 x 69.2
F = 6048.08 N
According to the Newton's 3rd law, there will be equal and opposite force on the astronaut.
Therefore, the normal force acting on the astronaut is -6048 N approximately
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10. When the force applied on an object is doubled, how does the pressure exert on the object change?
Answer:
It doubles as well.
Explanation:
Assuming that the area on which the force acts remains constant, and knowing that by definition:
P = F/A
We see that if we have a double force:
p = 2 F/A
Then the pressure is doubled.
Answer:
pressure doubles if area is constant
Explanation:
we know,
p=F/A
when force is double by keeping area constant
F=2F
Then,
Change in pressure (p') will be
P'=2F/A
or,p'=2×F/A
or,p'=2p(since, P=F/A)
therefore, when force is double by keeping area constant the pressure will increase by 2 times
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emily is standing 150 feet from a circular target with radius 3 inches. will she hit the target if her aim is off by 0.2 degrees?
Answer:
no
Explanation:
The angle subtended by the radius of the target at Emily's distance can be found using the tangent relation.
tan(α) = opposite/adjacent = (1/4 ft)/(150 ft) = 1/600
The angle is found using the inverse relation -
α = arctan(1/600) ≈ 0.095°
If Emily's aim is off by 0.2°, she will miss the target by several inches.
Emily's projectile will miss her aiming point by ... (150 ft)tan(0.2°) ≈ 0.524 ft ≈ 6.28 in
do you think an Electromagnet can be used for separating plastic bags from a garbage heap? explain
Answer:
No
Explanation:
Plastic bags are not magnetic materials, only magnetic materials (such as iron) can be attracted by the magnet.
Hope this helps.
Planet-X has a mass of 4.74×1024 kg and a radius of 5870 km.
1. What is the Second Cosmic Speed i.e. the minimum speed required for a satellite in order to break free permanently from the planet?
2. If the period of rotation of the planet is 16.6 hours, then what is the radius of the synchronous orbit of a satellite?
The minimum speed required for a satellite in order to break free permanently from the planet and the radius of the synchronous orbit of a satellite are 7.3 Km/s and 3.1 × 10⁴ km respectively.
To find the answer, we need to know about the escape velocity and time period of revolving satellite.
What's the expression of escape velocity of a satellite?Mathematically, escape velocity= √(2GM/R)G = gravitational constant, M = mass of planet, R= radius of the planetHere, M = 4.74×10²⁴kg, R = 5870 kmEscape velocity= √(6.67×10^(-11)×4.74×10²⁴/5.870×10⁶)= 7.3 Km/s
What's the expression of time period of a circularly orbiting satellite?T= {2π×r^(3/2)}/√(GM)r= (T/2π)⅔× (GM)^(1/3)r is the radius of the orbitWhat's the radius of the circular orbit, if the time period of the satellite is 16.6 hours?T = 16.6 hours = 16.6×3600 second = 59760sr = (59760/2π)^⅔× (6.67×10^(-11)×4.74×10²⁴)^(1/3)= 3.1 × 10⁴ km
Thus, we can conclude that the escape velocity and the radius of the synchronous orbit of a satellite are 7.3 Km/s and 3.1 × 10⁴ km respectively.
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Why is air resistance friction not useful for an airplane?
A. Causes turbulence
B. Speeds it up
C. Slows it down
D. Creates heat
The correct option is C. Air resistance friction is not useful for an airplane because it slows it down.
What is air resistance?Air resistance is the opposition to motion of an object caused by air flow.
High air resistance may cause turbulence during the motion of an air plane. This can lead to engine failure or some mishap during flight.
Air resistance is also a type of friction between air and another material such as airplane.
Effect of air resistance on airplaneFriction between the air and the plane slows the airplane down. This is known as air resistance, or drag.
The faster an object travels through the air, the more it has to fight against drag.
Thus, air resistance friction is not useful for an airplane because it slows it down.
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A person has a reasonable chance of surviving a car crash if the deceleration is no more than 30 'g's (g=9.8m/s2). Calculate the force on a 70 kg person undergoing this acceleration. What distance is travelled if the person is brought to rest at this rate from 100 km/h?
Thus, the distance traveled by automobile is [tex]=1.31m[/tex]
How do you find the distance traveled by automobile?Newton's second law can be used to compute the force being applied to the subject. The force is calculated as the product of the vehicle's acceleration and the person's mass. Newton's third law can be used to calculate the distance driven by a car.The mass of the person is [tex]m=65kg[/tex]
The deceleration of the automobile is [tex]a=30g[/tex]
The acceleration due to gravity is [tex]g=9.81m/s.[/tex]
The initial velocity of the automobile is [tex]v_{i}=100 km/h*\frac{1m/s}{3.6km/h} =27.78m/s[/tex]
Determination of the force exerted on the person:
The force applied to the person can be calculated using Newton's second law as follows:
[tex]F=ma[/tex]
[tex]30g[/tex]Here, m denotes the person's mass, while a denotes the car's acceleration. Because the driver is moving at 30g, the car's acceleration is assumed to be positive.
Substitute the values as 70 kg for [tex]m,(30g)[/tex] for a, and[tex]9.81m/s^{2}[/tex]
for g in the above equation.
[tex]F=70kg*30g[/tex]
[tex]=70kg*30g*9.81m/s^{2} (\frac{1N}{1kg*m/s^{2} })[/tex]
[tex]=20,601N[/tex]
Thus, the force acting on the person is [tex]=20,601N[/tex]
Determination of the distance traveled by automobile:
The final velocity of the car can be calculated using Newton's third law and represented as follows:
[tex]v_{f} ^{2}=v_{i} ^{2}+2ad[/tex]
[tex]d=\frac{v_{f} ^{2}=v_{i} ^{2}}{2a}[/tex]
Here [tex]v_{f}[/tex] is the final velocity of the automobile. The final velocity of the automobile becomes 0 m/s as the automobile comes to rest. The acceleration is taken to be negative because the automobile is decelerating at [tex]30g[/tex]
Substitute the values as [tex]0 m/s[/tex] for[tex]v_{f} =27.78m/s[/tex], for[tex]v_{i} ,(-30g)[/tex], for a, and [tex]9.81m/s^{2}[/tex]for g in the above equation.
[tex]d=\frac{(0 m/s)^{2} - (27.78m/s)^{2} }{2*(-30)*9.81m/s^{2} }[/tex]
[tex]=1.31m[/tex]
Thus, the distance traveled by automobile is[tex]=1.31m[/tex]
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By how many newtons does the weight of a 100-kg person decrease when he goes from sea level to mountain top at an altitude of 5000 m? The mean radius of the earth is 6.38 × 106 m.
The weight of a 100-kg person decreases by 4 N when he goes from sea level to mountain top at an altitude of 5000 m.
What determines the weight of a person?The weight of a person is determined by the mass of the body and the acceleration due to gravity.
The acceleration due to gravity, g is dependent on the mass of the earth, M the radius of the earth and the gravitational force constant , G.
Mathematically, the acceleration due to gravity at the mountain top is determined using the formula:
g = GM/r²where:
G = 6.67 × 10⁻¹¹ Nm²/kg²
M = 5.9736 x 10²⁴ kg
r = 638000 + 5000 = 6385000
g = (6.67 × 10⁻¹¹ * 5.9736 x 10²⁴ )(6385000)²
g = 9.77 m/s²
His weight at the mountain top will be:
weight = 100 * 9.77
weight = 977 N
Weight at sea level = 100 * 9.81 = 981 N
Decrease in weight = 981 - 977
Decrease in weight = 4 N
In conclusion, the weight of the man varies according to his distance from the earth.
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