Pentagon ABCDE and pentagon A”B”C”D”E” are shown on the coordinate plane below. Which two transformations are applied to pentagon ABCDE to create A”B”C”D”E”?

Answer:

B

Step-by-step explanation:

x<15

There is an open circle at 15 and the line goes to the left

Answer:

There are 28 beads

Step-by-step explanation:

Total ratio:

[tex]{ \sf{ (4 + 7) = 11}}[/tex]

let total beads be x:

[tex]{ \sf{ \frac{4}{11} \times x = 16 }} \\ \\ { \sf{x = \frac{11 \times 16}{4} }} \\ x = 44 \: beads[/tex]

Blue beads:

[tex] = 44 - 16 \\ = 28 \: \: beads[/tex]

Answer:

the awnser is sqrt(-1) = i

Step-by-step explanation:

[tex]re(i(x + yi) = - im(x + yi) \\ re(xi - y) = - im(x + yi) \\ - y = - (y) \\ - y = - y \\ proved \: is \: correct[/tex]

Answer:

9%

Step-by-step explanation:

12x=6y eq 1

18x=9y eq 2

Answer:

2/3×3/5=2/3. 3/4×1/6=1/8

2/3-1/8=11/40

Answer:

Step-by-step explanation:

[tex]( \frac{2}{3} \times \frac{3}{5} ) - ( \frac{3}{4} \times \frac{1}{6} )[/tex]

Reduce the numbers with Greatest common factor 3

⇒[tex] \mathsf{(2 \times \frac{1}{5} ) - ( \frac{1}{4} \times \frac{1}{2} )}[/tex]

Calculate the product

⇒[tex] \mathsf{( \frac{2}{5} )- ( \frac{1}{4} \times \frac{1}{2}) }[/tex]

Subtract the fractions

⇒[tex] \mathsf{ \frac{2 \times 8 - 1 \times 5}{40} }[/tex]

⇒[tex] \mathsf{ \frac{16 - 5}{40} }[/tex]

⇒[tex] \mathsf{ \frac{11}{40} }[/tex]

Hope I helped!

Best regards!

Answer:

a) ∠X = 67.4°

ii) ∠Y = 22.6°

b) Hypotenuse = 13 miles

ii) Length of each congruent = 4.33 miles

c) Distance of mall from point A = 5.21 miles

d) Distance os mall from point B = 8.17 miles

e) Difference = 2.96 miles

ii) Amount it will cost = $1,628,000

Step-by-step explanation:

Because of the length of the solution, I sent it as an attachment to this answer.

Answer:

We accept H₀  data from the survey is not enough to claim that 50% of the proportion indicated in previous studies have change

Step-by-step explanation:

To get conclusions about the survey we need to develop a hypothesis test of proportion

According to previous studies, (p₀ ) 50 % of staff and customers use public transportation, and we got from a survey 0f 1002 people 483 responded they also use then  p = 483/1002 then

n sample size is   1002  and  p = 0,482    (48,2 % )

Test Hypothesis

Null hypothesis                                   H₀            p  =  p₀

Alternative hypothesis                       Hₐ            p  <  p₀

CI =  95 %    α  = 5 %     α = 0,05    and from z-table we find z score for that value    z(c)  =  - 1,64

z(s)  =  (  p  -  p₀ ) /  √ (p₀*q₀)/ n         p₀ = q₀  = 0,5

z(s)  =  - 0,018* 31,65 / 0,5

z(s)  =  - 1,1394

To compare

z(s)  and  z(c)          -1,1394 > 1,64

Then z(s) is inside the acceptance region. We accept H₀ , because we don´t have enough evidence to claim that the survey results indicate a change in

the original proportion

Answer:

False.

Step-by-step explanation:

Probability distribution is the function which describes the likelihood of possible values assuming a random variable. The variance distribution is the squared value of each the difference by the mean. values of probability are squared and then their sum is taken to calculate variance deviation. The number of motorcycles greater than 1 has probability of 0.35 so the probability of x = 1 must also be 0.35.

Answer:

total amount paid = 32.5 + 28.9 + 24.95 = 86.35

20% of the total amount paid = 0.2 * 86.35 = 17.27

you tip 17.25$

You can put [tex]n[/tex] different elements in order in [tex]n![/tex] different ways.

So, you can visit 12 different cities in [tex]12!=479001600[/tex] different ways.

Answer: 479,001,600

Step-by-step explanation:

There are 12 ways to go to the first place, 11 for the second, ten for the third, and so on. So 12! Means 12x11x10x9x8x7x6x5x4x3x2x1.

Answer:

8.8 pounds

Step-by-step explanation:

Given the following :

Combined weight loss which occurred within a week = 28 kg

Number of days in a week = 7 days

1 kilogram (kg) = 2.2 pounds

Combined weight loss in pounds that occurs within a week:

Weight loss in kg × 2.2

28kg * 2.2 = 61.6 pounds

Assume weight loss occurred at a constant rate :

Weight lost by the group per day :

(Total weight loss / number of days in a week)

(61.6 pounds / 7)

= 8.8 pounds daily

Answer:

88

Step-by-step explanation:

Found the answer and I am doing the quiz rn lel

The equation of the circle is  [tex](x - 2)^2 + (y - 3)^2 = 16[/tex] . The option C is the correct option.

Given that the centre of the circle is (2,3) and circle has radius 4.

To find the equation of the circle, use the general equation of the circle as:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Where (h, k) is the centre of the circle and r is the radius of the circle.

Since, h = 2, k = 3 and radius r = 4.

Therefore, the equation of the circle:

[tex](x-h)^2+(y-k)^2=r^2\\(x-2)^2+(y-3)^2=4^2\\(x-2)^2+(y-3)^2=16[/tex]

The equation of the circle cantered at (2,3) and has a radius of 4 is  [tex](x - 2)^2 + (y - 3)^2 = 16[/tex] .

Therefore, The equation of the circle cantered at (2,3) and has a radius of 4 is  [tex](x - 2)^2 + (y - 3)^2 = 16[/tex] .

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Answer:

median and quartile deviation

Answer:

(4,4)⋅(4,4)

Step-by-step explanation:

Step-by-step explanation:

Hello,

I hope you mean to cancel the common factor that exists in numerator and denominator,right.

so, Let's look for the common factor,

here, the expression is,

=4(x-2)/ (x+5)(x-2)

so, here we find the common factor is (x-2)

now, we have to cancel it. And after cancelling we get,

=4/(x+5)

Note:{ we cancel the common factor if the common factors are in multiply form.}

Hope it helps

Answer:

Step-by-step explanation:

x+y = 67

2x-y = 38

Add the equations together

3x = 108

x = 36

y = 67-x = 31

Answer:

The answer and explanation are below

Step-by-step explanation:

i followed the data that was given in the question.

∑x=15 ; ∑y=87.3;∑x2=55; ∑y2=1569.77; ∑xy=275

a.)  please refer to the attachment for the scatter diagram. Y was plotted against X.

b. The equation is given as:

Y = b₁ + b₀X

∑x=15 ; ∑y=87.3;∑x2=55; ∑y2=1569.77; ∑xy=275

b₁ = n∑xy - (∑x)(∑y)/n(∑x²) - (∑x)²

b₁ = 5 x 275 - 15 x 87.3/5 x 55 - (15²)

= 1375-1309.5/275-225

= 65.5/50

= 1.31

b₀ = 87.3/5 - 1.31(15/5)

= 87.3/5 - 1.31x3

= 13.53

the regression line is

Y = 13.53 + 1.31X

please refer to the attachment for the diagram for the regression line.

c. we are required to find r.

r = n∑XY - (∑X)(∑Y)/√n∑X²-(∑X)² × √n∑y²-(∑y)²

∑x=15 ; ∑y=87.3;∑x2=55; ∑y2=1569.77; ∑xy=275

inserting these values:

r = 5 x 275-(15)(87.3)/√275-225 x √7848.85 - 7621.29

= 65.5/106.69

= 0.6139

Coefficient of determination = r²

r = 0.6139

r² = 0.3769 = 37.69%

Therefore 37.69% variation in y is explained by variation in x and the least square model.

Answer:

(1,2)

Step-by-step explanation:

x+4y = 9

2x -4y= -6

Add the equations together

x+4y = 9

2x -4y= -6

-------------------

3x +0y = 3

3x=3

Divide by 3

3x/3 = 3/3

x=1

Now find y

x+4y = 9

1 +4y =9

Subtract 1 from each side

4y = 8

Divide by 4

4y/4 = 8/4

y =2

Answer:

-35

Step-by-step explanation:

7*5*(-1)

The solution to the expression 7 * -5 is -35

From the question, we have the following parameters that can be used in our computation:

7 * -5

Evaluate all the products in the expression

so, we have the following representation

7 * -5 = -35/1

Evaluate all the quotients in the expression

so, we have the following representation

7 * -5 = -35

Lastly, we have

7 * -5 = -35

Hence, the solution is -35

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Answer:

y = 4x -1.5

Step-by-step explanation:

The slope intercept form of a line is given by

y = mx+b  where m is the slope and b is the y intercept

y = 4x -1.5

Answer:

x≤−8

Step-by-step explanation:

2x+3≤x−5

Subtract x from each side

2x-x+3≤x-x−5

x+3≤−5

Subtract 3 from each side

x+3-3≤−5-3

x≤−8

Answer:

[tex]\huge \boxed{x \leq -8}[/tex]

Step-by-step explanation:

[tex]2x+3 \leq x-5[/tex]

[tex]\sf Subtract \ x \ from \ both \ parts.[/tex]

[tex]2x+3 -x\leq x-5-x[/tex]

[tex]\sf Simplify \ the \ inequality.[/tex]

[tex]x+3 \leq -5[/tex]

[tex]\sf Subtract \ 3 \ from \ both \ parts.[/tex]

[tex]x+3-3 \leq -5-3[/tex]

[tex]\sf Simplify \ the \ inequality.[/tex]

[tex]x \leq -8[/tex]

Answer:

It can be any two numbers that sum up to 36.

eg:18+18,30+6,15+21

Step-by-step explanation:

Given:

Let Benjamin's age be x and David's age y.

x+y=36

2x+2y=72

Solution:

As twice of 36=72, any two numbers that add up to 36 ,will give a sum of 72 after multiplying them with 2.Therefore ,Benjamin's and David's age can be any set of numbers that sum up to 36.

Answer:

3/6 = 1/2 = 0.5

Step-by-step explanation:

3 / 6 = 1/2 = 0.5

Answer:

1.84

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Answer:

21

Step-by-step explanation:

-5(-2)-(-2)²+15

10-(4)+15

10-4+15

21

Answer:

9

Step-by-step explanation:

f(x)=−5x+18

f(-2) = -5(-2)+18 = 10+18 = 28

​g(x)=x^2+15

g(-2) = (-2)^2 +15 = 4+15 = 19

f(02) - g(-2) = 28 - 19 = 9

Answer:

a.    [tex]\mathbf{36 \sqrt{5}}[/tex]

b.   [tex]\mathbf{ \dfrac{1}{108} [ 145 \sqrt{145} - 1]}}[/tex]

Step-by-step explanation:

Evaluate integral _C x ds  where C is

a. the straight line segment x = t, y = t/2, from (0, 0) to (12, 6)

i . e

[tex]\int \limits _c \ x \ ds[/tex]

where;

x = t   , y = t/2

the derivative of x with respect to t is:

[tex]\dfrac{dx}{dt}= 1[/tex]

the derivative of y with respect to t is:

[tex]\dfrac{dy}{dt}= \dfrac{1}{2}[/tex]

and t varies from 0 to 12.

we all know that:

[tex]ds=\sqrt{ (\dfrac{dx}{dt})^2 + ( \dfrac{dy}{dt} )^2}} \ \ dt[/tex]

∴

[tex]\int \limits _c \ x \ ds = \int \limits ^{12}_{t=0} \ t \ \sqrt{1+(\dfrac{1}{2})^2} \ dt[/tex]

[tex]= \int \limits ^{12}_{0} \ \dfrac{\sqrt{5}}{2}(\dfrac{t^2}{2}) \ dt[/tex]

[tex]= \dfrac{\sqrt{5}}{2} \ \ [\dfrac{t^2}{2}]^{12}_0[/tex]

[tex]= \dfrac{\sqrt{5}}{4}\times 144[/tex]

= [tex]\mathbf{36 \sqrt{5}}[/tex]

b. the parabolic curve x = t, y = 3t^2, from (0, 0) to (2, 12)

Given that:

x = t  ; y = 3t²

the derivative of  x with respect to t is:

[tex]\dfrac{dx}{dt}= 1[/tex]

the derivative of y with respect to t is:

[tex]\dfrac{dy}{dt} = 6t[/tex]

[tex]ds = \sqrt{1+36 \ t^2} \ dt[/tex]

Hence; the  integral _C x ds is:

[tex]\int \limits _c \ x \ ds = \int \limits _0 \ t \ \sqrt{1+36 \ t^2} \ dt[/tex]

Let consider u to be equal to  1 + 36t²

1 + 36t² = u

Then, the differential of t with respect to u is :

76 tdt = du

[tex]tdt = \dfrac{du}{76}[/tex]

The upper limit of the integral is = 1 + 36× 2² = 1 + 36×4= 145

Thus;

[tex]\int \limits _c \ x \ ds = \int \limits _0 \ t \ \sqrt{1+36 \ t^2} \ dt[/tex]

[tex]\mathtt{= \int \limits ^{145}_{0} \sqrt{u} \ \dfrac{1}{72} \ du}[/tex]

[tex]= \dfrac{1}{72} \times \dfrac{2}{3} \begin {pmatrix} u^{3/2} \end {pmatrix} ^{145}_{1}[/tex]

[tex]\mathtt{= \dfrac{2}{216} [ 145 \sqrt{145} - 1]}[/tex]

[tex]\mathbf{= \dfrac{1}{108} [ 145 \sqrt{145} - 1]}}[/tex]

Answer:

2.

Step-by-step explanation:

The first numbers in the ordered pairs are the x values;

Difference = 1 - 3 = -1

The absolute value is 2.

An absolute value of |x| {modulus of x} is the value of a real number x. The absolute value of the difference in the x-values between (1,7) and (3,11)​ is 2.

An absolute value of |x| {modulus of x} is the value of a real number x, the value we get is always a non-negative number, for example, |-5| will give 5, and also, |5| will give 5 as well.

Given the two coordinates (1, 7) and (3, 11)​ this can be written as,

(x₁ , y₁) = (1, 7)

(x₂ , y₂) = (3, 11)

Now, the absolute value of the difference in the x-values between (1,7) and (3,11)​ can be written as,

Absolute difference = |x₁ - x₂|

                                 = |1 - 3|

                                 = |-2|

                                 = 2

Hence, the absolute value of the difference in the x-values between (1,7) and (3,11)​ is 2.

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