Please answer this correctly without making mistakes

Please Answer This Correctly Without Making Mistakes

Answers

Answer 1

Step-by-step explanation:

Option A and B are the correct answer because it equal to 688.5 and 688.05

Answer 2

Answer:

it is 1377/2 and 688 1/17 thats the answer

Step-by-step explanation:


Related Questions

What is the surface area?
9 ft
6 ft
3 ft
square feet

Answers

Answer:

the answer to this question is equal to 162

After running 3/4 of a mile tess has only run 1/3 how long is the race in miles but I want to know how you did it

Answers

Take 3/4 and 1/3 multiply the bottom, thats your denominator. Then since you multiplied 4•3, multiply the top by three.

in figure , EF=1 and FC=2 What is the length of AC?

Answers

Step-by-step explanation:

ae=ec

ec=1+2=3

then ae=3

Answer:

6-most likely (AC=6)

Step-by-step explanation:

Because the 2 sides, AE and EC *look the same. Also you can look at the opposite sides.

*This is what I think

The age of some lecturers are 42,54,50,54,50,42,46,46,48 and 48 calculate the mean age and standard deviation

Answers

Answer:

Mean age: 48

Standard deviation: 4

Step-by-step explanation:

a) Mean

The formula for Mean = Sum of terms/ Number of terms

Number of terms

= 42 + 54 + 50 + 54 + 50 + 42 + 46 + 46 + 48+ 48/ 10

= 480/10

= 48

The mean age is 48

b) Standard deviation

The formula for Standard deviation =

√(x - Mean)²/n

Where n = number of terms

Standard deviation =

√[(42 - 48)² + (54 - 48)² + (50 - 48)² +(54 - 48)² + (50 - 48)² +(42 - 48)² + (46 - 48)² + (46 - 48)² + (48 - 48)² + (48 - 48)² / 10]

= √-6² + 6² + 2² + 6² + 2² + -6² + -2² + -2² + 0² + 0²/10

=√36 + 36 + 4 + 36 + 4 + 36 + 4 + 4 + 0 + 0/ 10

=√160/10

= √16

= 4

The standard deviation of the ages is 4

Help question 25 pleasee

Answers

Answer:

4b³ + 11b² - 6b + 13

Step-by-step explanation:

Subtract like terms.

6b³ - 2b³ = 4b³

3b² - (-8b²) = 3b² + 8b² = 11b²

0 - 6b = -6b

8 - (-5) = 13

All together, the difference is 4b³ + 11b² - 6b + 13.

How many variables terms are in the expression 3xcube y+5xsquare+y+9

Answers

Answer: Please Give Me Brainliest, Thank You!

2

Step-by-step explanation:

There are two variables here, X and Y

Please answer ASAP PLEASE!​

Answers

Answer/Step-by-step explanation:

The inequality, x ≤ 7, has solutions that includes values that is equal to 1 or less than 7.

This can be represented on a number line as shown in the number line graphed in the attachment below.

A full circle or shaded "o" indicates that the number 7 is included in the solution.

The arrow points from 7 to the left, telling us that the value of x are all numbers from 7 and below.

A house m by m is surrounded by a walkway m wide. 27 9 1.8 a) Find the area of the region covered by the house and the walkway. b) Find the area of the walkway.

Answers

Answer:

A. 385.56 square meters.

B. 142.56 square meters.

Step-by-step explanation:

A house 27m by 9m is surrounded by a walkway 1.8m wide.

a) Find the area of the region covered by the house and the walkway.

​b) Find the area of the walkway.

Let

Length of the house=l=27m

Width of the house=w=9m

Wideness of the walkway=x=1.8m

Area of the region covered by the house and the walkway

=( L + 2*x) * (w + 2*x)

= (27+2*1.8)*(9+2*1.8)

=(27+3.6)*(9+3.6)

=(30.6)*(12.6)

=385.56 square meters.

​b) Area of the walkway

= (L + 2*x)*(w + 2*x) - l*w

= (27+2*1.8)*(9+2*1.8) - 27*9

=(27+3.6)*(9+3.6) - 243

=(30.6)*(12.6) - 243

=385.56 - 243

=142.56 square meters.

A ball is thrown straight up into the air from an initial height of 5 feet at time t = 0. The height, in feet, of the ball above the ground is given by h(t), where t is measured in seconds for 0 ≤ t ≤ 15. Based on the values of t and h(t) given in the table, for which value of t would the speed of the ball most likely be the greatest?

t (seconds) 0 3 6 9 12 15
h(t) (feet) 5 12 15 11 6 0

Select one:
a. 2 seconds
b. 5 seconds
c. 9 seconds
d. 15 seconds

Answers

Answer:

5 seconds

Step-by-step explanation:

The speed of an object is the rate of distance over time. The value of time (t) at the greatest speed of the ball is at 2 seconds

First, we calculate the speed using:

[tex]Speed = \frac{h(t)}{t}[/tex] --- i.e. distance/time

At t = 0, h(t) = 5

So;

[tex]Speed = \frac{5}{0} = unde fine d[/tex]

At t = 3, h(t) = 12

[tex]Speed = \frac{12}{3} = 4[/tex]

At t = 6, h(t) = 15

[tex]Speed = \frac{15}{6} = 2.5[/tex]

At t = 9, h(t) = 11

[tex]Speed = \frac{11}{9} = 1.2[/tex]

At t = 12, h(t) = 6

[tex]Speed = \frac{6}{12} = 0.5[/tex]

At t = 15, h(t) = 0

[tex]Speed = \frac{0}{15} = 0[/tex]

By comparing the above values, we notice that as time and height increases, the value of speed reduces.

This means that the greatest value of speed will be at the least value of time (t).

From the given options, the least value of time is at:

[tex]t = 2[/tex]

Hence, the value of time (t) at the greatest speed of the ball is at 2 seconds

Read more about speed at:

https://brainly.com/question/7359669

Choose the best answer to the following question. Explain your reasoning with one or more complete sentences. At​ 11:00 you place a single bacterium in a​ bottle, and at​ 11:01 it divides into 2​ bacteria, which at​ 11:02 divide into 4​ bacteria, and so on. How many bacteria will be in the bottle at​ 11:30?

Answers

Answer:

we could work this out by geometric sequence

Step-by-step explanation:

G1=2, G2=4, we have a formula,Gn=G1r^n-1

G2=G1 (r)^1, 4=2r, r=2

G30=G1 (2)^29=1,073,741,824 bacterium

Last year, Leila had $30,000 to invest. She invested some of it in an account that paid 6% simple interest per year, and she invested the rest in an account that paid 5% simple interest per year. After one year, she received a total of $1580 in interest. How much did she invest in each account?

Answers

Answer:

6%: $8,0005%: $22,000

Step-by-step explanation:

Let x represent the amount invested at 6%. Then 30000-x is the amount invested at 5%. Leila's total earnings for the year are ...

  0.06x +0.05(30000-x) = 1580

  0.01x +1500 = 1580 . . . . . . . . . . . . simplify

  0.01x = 80 . . . . . . . . . . . subtract 1500

  x = 8000 . . . . . . . . . . . . multiply by 100

Leila invested $8000 at 6% and $22000 at 5%.

If f(x) = x2 + 9x – 14 and g(x) = x2 – x + 3, find (f – g)(x).

Answers

Answer:

10x-17

Step-by-step explanation:

f(x) = x^2 + 9x – 14

g(x) = x^2 – x + 3

(f – g)(x)=x^2 + 9x – 14  - (x^2 – x + 3)

Distribute the minus sign

(f – g)(x)=x^2 + 9x – 14  - x^2 + x - 3

Combine like terms

    =10x-17

The mass of a species of mouse commonly found in houses is normally distributed with a mean of 20.2 grams with a standard deviation of 0.18 grams. Enter your responses as a decimal with 4 decimal places. (a) What is the probability that a randomly chosen mouse has a mass of less than 19.99 grams?

Answers

Answer:

12.1%

Step-by-step explanation:

Given that:

Mean (μ) = 20.2 grams and standard deviation (σ) = 0.18 grams.

The z score is a score used to determine the number of standard deviations by which the raw score is above or below the mean. A positive z score means  that the raw score is above the mean and a negative z score means that the raw score is below the mean. It is given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

a) For x < 19.99 g:

[tex]z=\frac{x-\mu}{\sigma}\\\\z=\frac{19.99-20.2}{0.18} \\\\z=-1.17[/tex]

From the normal distribution table, P(x < 19.99) = P(z < -1.17) = 0.1210 = 12.1%

The probability that a randomly chosen mouse has a mass of less than 19.99 grams is 12.1%

Please help me to find out the answer

Answers

9514 1404 393

Answer:

  80.99 m

Step-by-step explanation:

The hypotenuse of the triangle is given, and the desired side length is the one adjacent to the angle marked. The relevant trig relation is ...

  Cos = Adjacent/Hypotenuse

Multiplying by the hypotenuse, we find ...

  RY = (82 m)cos(9°) ≈ 80.99 m

coordinates of England

Answers

Answer:

52.3555 north

1.1745 west

What fraction of a pound is an ounce?

Answers

Answer:

1/16

Step-by-step explanation:

there are 16 ounces in a pound

Answer:

1/16 pounds

Step-by-step explanation:

Simplify: y^-3

a) 3/y
b) - 1/y^3
c) -3y
d) 1/y^3

Answers

Answer:

1/y^3

Step-by-step explanation:

We know that a^-b = 1/a^b

y ^-3 = 1/y^3

Farah is x years old. Ibtisam is 3 years younger than Farah. Muna is twice as old as Ibtisam. Write and expression in terms of x, for
(a) Ibtisam's age,
(b) The sum of their three ages, giving your answer in its simplest form.​

Answers

Answer:

Farah: x

Ibtisam: x-3

Muna: 2(x-3) or 2x-6

Sum of all their ages: 4x-6

Step-by-step explanation:

Farah is x, so we don't need an expression for that.

Ibtisam is 3 years younger than Farah, which means that we need to subtract 3 from Farah, and that would be Ibtisam's age. x-3.

Muna is 2 TIMES Ibtisam's age, so we need to multiply whatever expression taht was used for Ibtisam by 2. Put brackets around the equation with 2 outside: 2(x-3). Solve and you get 4x-6

Now, you have all their ages in expression form, now you need to simplify by adding:

x+x+2x-6

We cannot simplify -6, so we put that aside. Add all the x's and you get 4x, insert the minus 6 at the end:

4x-6

Hope this helps!

--Applepi101

Answer:

a) X -3

b) 4x - 9

Step-by-step explanation:

a) Farah's age is X so Ibtisam will be X - 3 old since he is 3years younger than Farah

b) Farah is X years old

Ibtisam is X - 3 years old

Muna is 2(X -3) since she is 2 times older than Ibtisam.

the sum of Thier ages will be

X + X -3 + 2(x-3)

= 2x - 3 + 2x - 6

= 4x - 9

Find the first six partial sums S1, S2, S3, S4, S5, S6 of the sequence whose nth term is given. 1 2 , 1 22 , 1 23 , 1 24 , . .

Answers

Answer:

the first  partial sum  [tex]\mathbf{S_1= \dfrac{1}{2}}[/tex]

the second partial sum  [tex]\mathbf{S_2= \dfrac{3}{4} }[/tex]

the third partial sum [tex]\mathbf{S_3= \dfrac{7}{8}}[/tex]

the fourth  partial sum [tex]\mathbf{S_4= \dfrac{15}{16}}[/tex]

the fifth partial sum [tex]\mathbf{S_5= \dfrac{31}{32}}[/tex]

the sixth partial sum [tex]\mathbf{S_6= \dfrac{63}{64}}[/tex]

Step-by-step explanation:

The term of the sequence are given as : [tex]\dfrac{1}{2}[/tex], [tex]\dfrac{1}{2^2}[/tex], [tex]\dfrac{1}{2^3}[/tex], [tex]\dfrac{1}{2^4 }[/tex] ,  .  .  .  

The nth term for this sequence is , [tex]\mathtt{a_n =( \dfrac{1}{2})^n}[/tex]

The nth partial sum of the sequence for [tex]\mathtt{a_1,a_2,a_3.... a_n}[/tex] is [tex]\mathtt{S_n}[/tex]

where;

[tex]\mathtt{S_n = a_1 +a_2+a_3+ ...+a_n}[/tex]

The first partial sum  is:  [tex]\mathtt{S_1= a_1}[/tex]

[tex]\mathtt{S_1= (\dfrac{1}{2})^1}[/tex]

[tex]\mathbf{S_1= \dfrac{1}{2}}[/tex]

Therefore, the first  partial sum  [tex]\mathbf{S_1= \dfrac{1}{2}}[/tex]

The second partial sum is: [tex]\mathtt{S_2= a_1+a_2}[/tex]

[tex]\mathtt{S_2= (\dfrac{1}{2})^1 + (\dfrac{1}{2})^2}[/tex]

[tex]\mathtt{S_2= \dfrac{1}{2} + \dfrac{1}{4}}[/tex]

[tex]\mathtt{S_2= \dfrac{2+1}{4} }[/tex]

[tex]\mathbf{S_2= \dfrac{3}{4} }[/tex]

Therefore, the second partial sum  [tex]\mathbf{S_2= \dfrac{3}{4} }[/tex]

The third partial sum is : [tex]\mathtt{S_3= a_1+a_2+a_3}[/tex]

[tex]\mathtt{S_3= (\dfrac{1}{2})^1 + (\dfrac{1}{2})^2+(\dfrac{1}{2})^3 }[/tex]

[tex]\mathtt{S_3= \dfrac{1}{2} + \dfrac{1}{4}+\dfrac{1}{8}}[/tex]

[tex]\mathtt{S_3= \dfrac{4+2+1}{8}}[/tex]

[tex]\mathbf{S_3= \dfrac{7}{8}}[/tex]

Therefore, the third partial sum [tex]\mathbf{S_3= \dfrac{7}{8}}[/tex]

The fourth partial sum : [tex]\mathtt{S_4= a_1+a_2+a_3+a_4}[/tex]

[tex]\mathtt{S_4= (\dfrac{1}{2})^1 + (\dfrac{1}{2})^2+(\dfrac{1}{2})^3+(\dfrac{1}{2})^4 }[/tex]

[tex]\mathtt{S_4= \dfrac{1}{2} + \dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}}[/tex]

[tex]\mathtt{S_4= \dfrac{8+4+2+1}{16}}[/tex]

[tex]\mathbf{S_4= \dfrac{15}{16}}[/tex]

Therefore, the fourth  partial sum [tex]\mathbf{S_4= \dfrac{15}{16}}[/tex]

The fifth partial sum : [tex]\mathtt{S_5= a_1+a_2+a_3+a_4+a_5}[/tex]

[tex]\mathtt{S_5= (\dfrac{1}{2})^1 + (\dfrac{1}{2})^2+(\dfrac{1}{2})^3+(\dfrac{1}{2})^4 +(\dfrac{1}{2})^5 }[/tex]

[tex]\mathtt{S_5= \dfrac{1}{2} + \dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}}[/tex]

[tex]\mathtt{S_5= \dfrac{16+8+4+2+1}{32}}[/tex]

[tex]\mathbf{S_5= \dfrac{31}{32}}[/tex]

Therefore, the fifth partial sum [tex]\mathbf{S_5= \dfrac{31}{32}}[/tex]

The sixth partial sum: [tex]\mathtt{S_5= a_1+a_2+a_3+a_4+a_5+a_6}[/tex]

[tex]\mathtt{S_6= (\dfrac{1}{2})^1 + (\dfrac{1}{2})^2+(\dfrac{1}{2})^3+(\dfrac{1}{2})^4 +(\dfrac{1}{2})^5 +(\dfrac{1}{2})^6 }[/tex]

[tex]\mathtt{S_6= \dfrac{1}{2} + \dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+\dfrac{1}{64} }[/tex]

[tex]\mathtt{S_6= \dfrac{32+16+8+4+2+1}{64}}[/tex]

[tex]\mathbf{S_6= \dfrac{63}{64}}[/tex]

Therefore, the sixth partial sum [tex]\mathbf{S_6= \dfrac{63}{64}}[/tex]

13% of a sample of 200 students do not like ice cream. What is the 95% confidence interval to describe the total percentage of students who do not like ice cream?

Answers

The 95% confidence interval is (8.3%,17.7%), and the correct option is C.

------------------------------------------

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

------------------------------------------

13% of a sample of 200 students do not like ice cream.

This means that [tex]\pi = 0.13, n = 200[/tex]

------------------------------------------

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

------------------------------------------

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.13 - 1.96\sqrt{\frac{0.13*0.87}{200}} = 0.083[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.13 + 1.96\sqrt{\frac{0.13*0.87}{200}} = 0.177[/tex]

------------------------------------------

As a percentage:

0.083x100% = 8.3%0.177x100% = 17.7%

Thus, the 95% confidence interval is (8.3%,17.7%), and the correct option is C.

A similar problem is given at https://brainly.com/question/22223066

What are the Links of two sides of a special right triangle with a 306090° and a Hypotenuse of 10

Answers

Answer:

Step-by-step explanation:

60°=2×30°

one angle is double the angle of the same right angled triangle.

so hypotenuse is double the smallest side.

Hypotenuse=10

smallest side=10/2=5

third side =√(10²-5²)=5√(2²-1)=5√3

A train goes at a speed of 70km / h. If it remains constant at that speed, how many km will it travel in 60 minutes?

Answers

Answer:

Total distance travel by train =  70 km

Step-by-step explanation:

Given:

Speed of train = 70 km/h

Total time taken = 60 min = 60 / 60 = 1 hour

Find:

Total distance travel by train

Computation:

Distance = Speed × Time

Total distance travel by train = Speed of train × Total time taken

Total distance travel by train = 70 × 1

Total distance travel by train =  70 km

(20/2 + 4)/2

^^^ I NEED A EQUATION LIKE THAT BUT FOR IT TO EQUAL 16

Answers

Answer:

Here are a few examples.

(30/2 + 1)/2

(26/2 + 3)/2

(28/2 + 2)/2

A refrigeration system at your company uses temperature sensors fixed to read Celsius (0C) values, but the system operators in your control room understand only the Fahrenheit scale. You have been asked to make a Fahrenheit (°F) label for the high temperature alarm, which is set to ring whenever the system temperature rises above -10°C. What Fahrenheit value should you write on the label?

Answers

Answer:

14 °F

Step-by-step explanation:

To answer this problem, we will use the known celsius to fahrenheit conversion formula.

[Celsius * (9/5)] + 32 = Fahrenheit

Now we just plug in the value of celsius:

[-10 * (9/5)] + 32 = Fahrenheit

[ -2 * 9 ] + 32 = Fahrenheit

[ -18 ] + 32 = Fahrenheit

14 = Fahrenheit

So you should right 14(°F) on the label.

Cheers.

Estimate the product of 0.235 and 13.467 to the nearest hundredth. Round each value to the nearest hundredth before multiplying. Your final answer should also be rounded to the nearest hundredth.

Answers

Answer:

0.235 = 0.24

13.467 = 13.47

0.24+13.47=13.71

15. What is the next number in this series?
6, 11, 9, 14, 12,
a. 17
b. 10
C. 18
d. 16

Answers

Answer:

a. 17

Step-by-step explanation:

The pattern is add 5 then subtract 2

A random sample of 149 recent donations at a certain blood bank reveals that 76 were type A blood. Does this suggest that the actual percentage of type A donations differs from 40%, the percentage of the population having type A blood? Carry out a test of appropriate hypotheses using a significance level of 0.01. Would your conclusion have been different if a significance level of 0.05 has been used?

Answers

Answer:

Yes it suggest that the actual percentage of type A donations differs from 40%, the percentage of the population having type A blood.

Well if a significance level of 0.05 is used it will not affect the conclusion

Step-by-step explanation:

From the question we are told that

     The  sample size is   [tex]n = 149[/tex]

     The  number that where  type A blood is  k =  76

       The population proportion is   [tex]p = 0.40[/tex]

       The  significance level is  [tex]\alpha = 0.01[/tex]

Generally the sample proportion is mathematically represented as

      [tex]\r p = \frac{k}{n}[/tex]

=>    [tex]\r p = \frac{76}{149}[/tex]

=>    [tex]\r p = 0.51[/tex]

The  Null hypothesis is   [tex]H_o : p = 0.41[/tex]

The  Alternative hypothesis is  [tex]H_a : p \ne 0.40[/tex]

Next we obtain the critical value of [tex]\alpha[/tex] from the z-table.The value is  

       [tex]Z_{\alpha } = Z_{0.01} = 1.28[/tex]

Generally the test statistics is mathematically evaluated as

           [tex]t = \frac{\r p - p }{ \sqrt{ \frac{p(1-p)}{n} } }[/tex]    

substituting values

           [tex]t = \frac{0.51 - 0.40 }{ \sqrt{ \frac{0.40 (1-0.40 )}{149} } }[/tex]    

           [tex]t =2.74[/tex]

So looking at the values for t  and  [tex]Z_{0.01}[/tex] we see that  [tex]t > Z_{0.01}[/tex] so we reject the null hypothesis. Which means that there is no sufficient evidence to support the claim

Now if [tex]\alpha = 0.05[/tex] , the from the z-table the critical value for [tex]\alpha = 0.05[/tex] is  [tex]Z_{0.05} = 1.645[/tex]

So comparing the value of  t and  [tex]Z_{0.05} = 1.645[/tex]  we see that [tex]t > Z_{0.05}[/tex] hence the conclusion would not be different.

1.3 is 10% of what number

Answers

Answer:

33.33 percent

Step-by-step explanation:

Answer:

13

Step-by-step explanation:

Make a proportion

part/whole = part/whole

1.3/x=10/100

130=10x

x=13

The 1991 Tractor has a horse power of 195, which is five less than four times the horsepower of the Cinderella's carriage. What was the horsepower of the carriage?

Answers

Answer:

The horsepower of the carriage is 50

Step-by-step explanation:

Let the horsepower of the carriage=x

ATQ, 195+5=4x, x=50.

Convert 0.450 to a proper fraction

Answers

Answer:

9/20

Step-by-step explanation:

450/1000

this is not the answer, because it is not simplified

so here we have to find common factor and simplifying

________________________________________________

450/1000 is simplified to 9/20, and it can no longer be simplified.

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