PLEASE HELP AND ANSWER FAST!!! :( Della has $575.38 in her checking account. What is the balance after she makes a deposit of $50.00 and a withdrawal of $85.45?


A. $539.93

B.558.45

C. 561.63

D.603.73

[tex] {1000}^{ \frac{2}{3} } = {10}^{ {3}^{ \frac{2}{3} } } = {10}^{3 \times \frac{2}{3} } = {10}^{2} = 100 \\ [/tex]

Step-by-step explanation:

Hey there!

Given;

[tex] {2}^{4x - 1} =32 [/tex]

[tex] {2}^{4x} . {2}^{ - 1} = {2}^{5} [/tex]

[tex] {2}^{4x} . \frac{1}{2} = {2}^{5} [/tex]

[tex] {2}^{4x} = {2}^{5} . {2}^{1} [/tex]

[tex] {2}^{4x} = {2}^{6} [/tex]

[tex]4x = 6[/tex]

[tex]x = \frac{6}{4} [/tex]

[tex]x = \frac{3}{2} [/tex]

7.)

[tex] \sqrt{x} - 3 = 7[/tex]

[tex] \sqrt{x} = 7 + 3[/tex]

[tex]( { \sqrt{x}) }^{2} = {(10)}^{2} [/tex]

X= 100

8.)

[tex]( {x + 1)}^{2} = 81[/tex]

[tex](x + 1) = \sqrt{81} [/tex]

[tex]x + 1 = \sqrt{ {9}^{2} } [/tex]

[tex]x + 1 = 9[/tex]

[tex]x = 9 - 1[/tex]

X=8

Hope it helps...

Answer:

Gabriela Mistral works as a humanitarian for [tex]8[/tex] days.

Step-by-step explanation:

Gabriela Mistral was a poet, diplomat, teacher and humanitarian such that each week she worked a certain amount of days as a poet diplomat teacher and humanitarian.

Ratio is [tex]1:1:3:2[/tex]

Let [tex]x[/tex] denotes total number of days Gabriela Mistral work.

As she works 12 days as a teacher,

[tex]\frac{3}{7}x=12\\ x=\frac{7}{3}(12)\\ x=28[/tex]

Total number of days [tex]=x=28[/tex]

So,

she works as a humanitarian for [tex]\frac{2}{7}x=\frac{2}{7}(28)=8[/tex] days.

Answer:

Ordered Pair An ordered pair is a composition of the x coordinate (abscissa) and the y coordinate (ordinate), having two values written in a fixed order within parentheses. It helps to locate a point on the Cartesian plane for better visual comprehension. The numeric values in an ordered pair can be integers or fractions.

Step-by-step explanation:

i hope this helped! :)

Answer:

An ordered pair contains the coordinates of one point in the coordinate system. A point is named by its ordered pair of the form of (x, y). The first number corresponds to the x-coordinate and the second to the y-coordinate. To graph a point, you draw a dot at the coordinates that corresponds to the ordered pair.

Step-by-step explanation:

Answer:

B 7

Step-by-step explanation:

5 stars plz mark a brainleast

Answer:

just fill in -4 for x so it would be g(-4)

Step-by-step explanation:

Happy Halloween

Answer:

m = 2 and n = 3

Step-by-step explanation:

We want to find the value of the integers m and n that will make the given expression true

(2x^ny^2)^m = 4x^6y^4

We can rewrite the left hand side of the equation as follows;

(2x^3y^2)^2

we can proceed to use inspection to ind the value of m and n

Through inspection since the left hand side of the equation now looks like the right hand side;

Then;

m= 2 and n = 3

Answer:

n= -32

Step-by-step explanation:

Answer:

If 16 quarters is equal to 2 toonies, then 1 quarter is;

16 : 2

1 : x

16x = 2

x = 2/16

x = 1/8 toonies

20 quarters would therefore be;

= 1/8 * 20

= 2.5 toonies

24 quarters would be;

= 1/8 * 24

= 3 toonies

Answer: (100,000, 10,000,000]

Step-by-step explanation:

The interval is given by ( 100,000 , 10,000,000], the correct option is C.

The threshold value is the minimum value above which the desired results can be expected.

The decibel reading was consistently above 50, but never above 70.

d = 10log(x)

50 = 10log(x)

5 = log x

10⁵ = x

x > 10⁵

d = 10log(x)

70 = 10log(x)

x = 10⁷

From the given data

x ≤ 10⁷

Therefore, the interval is given by ( 100,000 , 10,000,000], the correct option is C.

To know more about Threshold value

https://brainly.com/question/13031415

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Answer:

[tex]2x^5-9x^4+0x^3-2x^2+0x+10[/tex]

Step-by-step explanation:

A polynomial is in standard form when its terms are ordered from highest to lowest degree.

If the polynomial is missing terms, it must be completed by setting their coefficients to 0.

The given polynomial is:

[tex]2x^5-9x^4-2x^2+10[/tex]

The terms are ordered, but it's incomplete. The terms with exponent 3 and 1 must be included with zero coefficient.

Thus the polynomial in standard form is:

[tex]\boxed{2x^5-9x^4+0x^3-2x^2+0x+10}[/tex]

Answer:

y =-x-3

Step-by-step explanation:

slope intercept/ y-intercept form is y=mx+b

you have to isolate y here

x+y=-3      subtract x from both sides

y=-x-3

Answer/Step-by-step explanation:

Given:

m<9 = 80°,

m<5 = 68°

Lines w and v are parallel to each other.

m<1 = m<9 (corresponding angles theorem)

m<1 = 80°

m<2 + m<1 = 180° (linear pair)

m<2 + 80° = 180° (substitution)

m<2 = 180° - 80°

m<2 = 100°

m<3 = m<1 (vertical angles are congruent)

m<3 = 80°

m<4 = m<2 (vertical angles are congruent)

m<4 = 100°

m<6 + m<5 = 180° (linear pair)

m<6 + 68° = 180° (substitution)

m<6 = 180° - 68°

m<6 = 112°

m<7 = m<5 (vertical angles)

m<7 = 68°

m<8 = m<6 (vertical angles)

m<8 = 112°

m<10 = m<2 (corresponding angles)

m<10 = 100°

m<11 = m<9 (vertical angles)

m<7 = 80°

m<12 = m<10 (vertical angles)

m<12 = 100°

m<13 = m<5 (corresponding angles)

m<13 = 68°

m<14 = m<6 (corresponding angles)

m<14 = 112°

m<15 = m<13 (vertical angles)

m<15 = 68°

m<16 = m<14 (vertical angles)

m<16 = 112°

Answer:

the answer is B!! hopefully this helps

Answer:

C. JK and LM are congruent

Step-by-step explanation:

Given the coordinates J(-2,8), K(0,8), L(1,0), and M(1,-2), in other to determine whether JK is congruent to LM, we need to determine if the length of side JK and LM are equal i.e JK = LM

To get JK:

We will find the distance between the coordinates J(-2,8), K(0,8) to get the length JK using the formula:

JK =√(x2-x1)²+(y2-y1)²

JK = √(0-(-2))²+(8-8)²

JK = √2²+0²

JK = √4

JK = 2

For the length of LM with coordinate L(1,0), and M(1,-2)

LM = √(1-1)²+(-2-0)²

LM = √0²+(-2)²

LM = √0²+2²

LM = √0+4

LM =√4

LM = 2

Since JK = LM = 2 units, this means that JK and LM are congruent.

Answer:4

Step-by-step explanation: 1x2x1x2

Answer: it would be 2

Step-by-step explanation:

Answer:

y= 3/4z + 25/4

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Δ CED and Δ CAB are similar thus the ratios of corresponding sides are equal, that is

[tex]\frac{CE}{CA}[/tex] = [tex]\frac{ED}{AB}[/tex] , substitute values

[tex]\frac{x}{156-x}[/tex] = [tex]\frac{7}{84}[/tex] = [tex]\frac{1}{12}[/tex] ( cross- multiply )

12x = 156 - x ( add x to both sides )

13x = 156 ( divide both sides by 13 )

x = 12

Thus

AC = 156 - x = 156 - 12 = 144 → D

Answer:

D.  144

Step-by-step explanation:

Triangle BAC is similar to triangle DEC, so you can set up a ratio:

[tex]\frac{84}{156-x} = \frac{7}{x}[/tex]

Then cross multiply

84x = 7 (156 - x)

84x = 1092 - 7x

Add 7x to both sides.

91x = 1092

Divide both sides by 91.

x = 12

AC = 156 - x

AC = 156 - 12

AC = 144

Answer:

Line A and Line C are parallel.

Step-by-step explanation:

Answer:

f(- 3) = - 14

Step-by-step explanation:

To evaluate f(- 3) substitute x = - 3 into f(x), that is

f(- 3) = (- 3)³ + 2(- 3)² - 5 = - 27 + 2(9) - 5 = 27 + 18 - 5 = - 14

Answer:

B) p<5

Step-by-step explanation:

Answer:

its a anwser

Step-by-step explanation:

22+2 = 187

Answer:

u + 15

Step-by-step explanation:

Since we don't know the value of u, we have to put the equation like this.

Hope I helped :)

Please consider Brainliest :)

Answer:

I got 1.19446588127

Answer:

B)[tex]\frac{-3}{4}[/tex]

Step-by-step explanation:

We are supposed to find the difference of the fractions

a) [tex]-2\frac{1}{2}-(-1\frac{3}{4})[/tex]

[tex]=\frac{-5}{2}+\frac{7}{4}[/tex]

Using equivalent fraction

[tex]-\frac{5}{2} \times \frac{2}{2} = \frac{-10}{4}\\\Rightarrow \frac{-10}{4}+\frac{7}{4}[/tex]

Plot both fractions on number lines

So Using number line

[tex]\frac{-10}{4}+\frac{7}{4}=\frac{-5}{2}+\frac{7}{4}=\frac{-3}{4}[/tex]

So, Option B is true

Answer:

The point (1 | 6) is on the graph.

Step-by-step explanation:

Answer:

it is 1/6

Step-by-step explanation:

Answer:

the answer is 486

Step-by-step explanation:

Answer:

[tex]m=8[/tex]

Step-by-step explanation:

[tex]9m-3(m+6)=2(m+7)[/tex]

[tex]9m-3m-18=2m+14[/tex]

[tex]6m-18=2m+14[/tex]

[tex]4m= 32[/tex]

[tex]m=8[/tex]