PLEASE HELP ASAP! - 14 POINTS

Step-by-step explanation:

the common increment is 20

Answer:

8, 13, 18, 23

Step-by-step explanation:

Answer:

x = -11/5 or -2.2

y = 13/5 or 2.6

Step-by-step explanation:

well, start by doing the multiplication. then we will see better.

2x + 2yi + xi + yii = -7 + 3i

2x + 2yi + xi - y = -7 + 3i

this is because, remember, i = sqrt(-1), and ii = -1.

now we group the i-factors and the terms without i and compare it to the corresponding parts on the right side.

2x - y = -7

2yi + xi = 3i

=> 2y + x = 3

x = 3 - 2y

and that we use ihr the first equation again

2×(3-2y) - y = -7

6 - 4y - y = -7

-5y = -13

y = 13/5

x = 3 - 2×13/5 = 3 - 26/5 = 15/5 - 26/5 = -11/5

Answer:

Brainliest!

Step-by-step explanation:

36x^-4y^2/5x^2y^-3z^-2

36y^5z^2/5x^6

make everything positive

OPTIONS:

A. The interquartile range of the trail mix data is greater than the range of the cracker data.

B. The value 70 is an outlier in the trail mix data.

C. The upper quartile of the trail mix data is equal to the maximum value of the cracker data.

D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

Answer:

D.

Step-by-step explanation:

With the given information about how the box plot looks like, let's examine each option to see if they are true or not.

Option A: "The interquartile range of the trail mix data is greater than the range of the cracker data."

The interquartile range of trail mix data = 105 - 90 = 15

Range of cracker data = 100 - 70 = 30

Option A is NOT TRUE.

Option B: "The value 70 is an outlier in the trail mix data."

This is NOT TRUE. There are not outliers as 70 is the minimum value if the ranges of the data set for the trail mix.

Option C: "The upper quartile of the trail mix data is equal to the maximum value of the cracker data."

Upper quartile of the trail mix data = 105

Max value of cracker data = 100

This statement is NOT TRUE.

Option D: "The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers."

The greater the range value, the greater the variation. Thus,

Range value of the trail mix data = 115 - 70 = 45

Range value of the cracker data = 100 - 70 = 30

This is statement is correct because trail mix data have a greater range value, hence, it has a greater variation in the number of calories.

Answer: D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

Answer:

  g(x) = 4, 6, 9, 13.5 for the x-values given

Step-by-step explanation:

The table and graph are attached.

Answer:

x³ - 5x² - x + 5

Step-by-step explanation:

(x+1)(x-1)(x-5) = 0

fisrt step:

(x+1)(x-1) = x*x + x*-1 + 1*x + 1*-1 = x² - x + x - 1 = x² - 1

then:

(x+1)(x-1)(x-5) = (x²-1)(x-5)

(x²-1)(x-5) = x²*x + x²*-5 -1*x -1*-5 = x³ - 5x² - x + 5

9514 1404 393

Answer:

  KM = 8

Step-by-step explanation:

The ratio of long side to short side is the same for all of the triangles in this geometry:

  KM/ML = JM/KM

  KM² = ML·JM = 4(20-4) = 64

  KM = √64 = 8

The length of KM is 8 units.

Answer:

Total amount in dollars= $64614.00

Step-by-step explanation:

Initial starting salary is $40000.

Rate of increase is 3%

Number of years is 16 years

The salary is compounded yearly.

Amount A after 16 years is given as

A= p (1+r/n)^ (nt)

A=40000(1+0.03/16)^(16*16)

A= 40000(1.001875)^(256)

A=40000(1.61534824)

A= 64613.92959

Total amount in dollars= $64614.00

Answer: the answer is $806275

Step-by-step explanation:

A p e x

Answer:

The answer to your question will be the choice "D."

Cost of 17 inches of wire = 68 cents

Cost of 1 inch of wire

= 68 cents/17

= 4 cents

Cost of 39 inches of wire

= 4 cents × 39

= 156 cents

= $1.56

Answer:

17 inches of wire costs 68 cents,

Step-by-step explanation:

x=234

b=456

Answer:

A. The interquartile range (IQR) for brand A, $10, is less than the IQR for brand B, $25.

Step-by-step explanation:

The most appropriate measure that can be used to compare the SPREAD of the data of the 2 brands plotted on a box plot, is the Interquartile range (IQR).

Interquartile range is the difference between Q3 and Q1.

Q3 is the value which lies at the end of the rectangular box, while the Q1 lies at the beginning of the box.

From the box plot given,

IQR for brand A = 80 - 70 = $10

IQR for brand B = 50 - 25 = $25

Therefore, the correct option is "A. The interquartile range (IQR) for brand A, $10, is less than the IQR for brand B, $25."

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of a line given two points first find the slope of the line and use the formula

y - y1 = m( x - x1) to find the Equation of the line using any of the points given

Slope of the line using points

(3,2) and (4,6) is

[tex]m = \frac{6 - 2}{4 - 3} = \frac{4}{1} = 4[/tex]

So the equation of the line using point

( 3 , 2 ) and slope 4 is

Hope this helps you

Answer:

-28

Step-by-step explanation:

(–7) + (–7) + (–7) + (–7)

=> -7 -7 -7 -7

=> - 28

Answer:

question is not proper

Step-by-step explanation:

question is

Answer: x ≤ 120

Step-by-step explanation: To get x by itself in this inequality, since it's being divided by -6, we must multiply both sides by -6, just like we would if we were solving an equation, but here is the trick you have to watch out for with inequalities.

When you multiply or divide both sides of an inequality by a

negative, you must switch the direction of the inequality sign.

So our second step in this problem reads x ≤ 120.

Please give this idea your full attention.

Even the most advanced algebra students will sometimes forget to switch the direction of the inequality sign when multiplying or dividing both sides of an inequality by a negative.

Answer:

x ≤ 120

I hope this helps!

[tex]\\ \rm\longmapsto \sqrt{-18}[/tex]

[tex]\\ \rm\longmapsto \sqrt{18}i[/tex]

[tex]\\ \rm\longmapsto \sqrt{9\times 2}i[/tex]

[tex]\\ \rm\longmapsto \sqrt{3(3)(2)}i[/tex]

[tex]\\ \rm\longmapsto 3i\sqrt{2}[/tex]

Answer:

A. [tex]\displaystyle 3i\sqrt{2}[/tex]

Step-by-step explanation:

[tex]\displaystyle \sqrt{-18} → \sqrt{[2][-1][9]}\\ \\ 3i\sqrt{2}[/tex]

As you can see, you need a perfect square to wourk with, which in this case is 9. Now, [tex]\displaystyle \sqrt{-1}[/tex] comes out as an imaginary number [tex]\displaystyle [i],[/tex]so pull it out of the radical alongside 3, [tex]\displaystyle \sqrt{9}.[/tex]

I am joyous to assist you at any time.

Answer:

absolutely convergent

Step-by-step explanation:

given data

sin(n)/3^n

solution

we have given term [tex]\frac{sin(n)}{3^n}[/tex]

when n = 1

and we know that

value of sin(n) ≤ 1

so that we can say that

[tex]\frac{sin(n)}{3^n}[/tex]  ≤  [tex]\frac{1}{3^n}[/tex] or [tex](\frac{1}{3})^n[/tex]

here [tex]\frac{1}{3^n}[/tex]  is converges this is because common ratio in geometric series

here r is [tex]\frac{1}{3}[/tex]  and here it satisfy that -1 < r < 1

so it is converges

and

[tex]\frac{sin(n)}{3^n}[/tex]  is also similar

so it is  converges

and here no [tex](-1)^n[/tex]  term is

so we can say series is absolutely convergent

Answer:

x = 10

Step-by-step explanation:

2x/3 + 1 = 7x/15 + 3

(times everything in the equation by 3 to get rid of the first fraction)

2x + 3 = 21x/15 + 9

(times everything in the equation by 15 to get rid of the second fraction)

30x+ 45 = 21x + 135

(subtract 21x from 30x; subtract 45 from 135)

9x = 90

(divide 90 by 9)

x = 10

2x/3 + 1 = 7x/15 + 3

(find the LCM of 3 and 15 = 15)

(multiply everything in the equation by 15, then simplify)

10x + 15 = 7x + 45

(subtract 7x from 10x; subtract 15 from 45)

3x = 30

(divide 30 by 3)

x = 10

Answer:

y = 3 passes through (8, 3) and is therefore parallel to y = -2

Step-by-step explanation:

Any line parallel to y = -2 is a horizontal one, and it has the same slope (zero) as does y = -2.

We could invent the horizontal line y = 3 (which comes from the point (8, 3) and surmise that it is parallel to the given line y = -2.

Thus, y = 3 passes through (8, 3) and is therefore parallel to y = -2.

In the future, please share any answer choices that are give you.  Thank you.

The gallons of irrigation water is 326,700 gallons per square foot

Given:

area of the land, A = 43,560 ft²/acre

7.5 gallons = 1 ft³

To find:

number of gallons per square foot

Note:

The number of gallons per square foot is calculated as;

[tex]= \frac{43,560 \ acre}{ft^2} \times \ foot\times \frac{7.5 \ gallons}{ft^3} \\\\= \frac{43,560 \ acre-ft}{ft^2} \times \frac{7.5 \ gallons}{ft^3} \\\\= \frac{43,560 \ ft^3}{ft^2} \times \frac{7.5 \ gallons}{ft^3}\\\\= \frac{43,560 \ ft^3}{ft^3} \times \frac{7.5 \ gallons}{ft^2}\\\\=(43,560\times 7.5) \frac{gallons}{ft^2} \\\\= 326,700 \ \frac{gallons}{ft^2}[/tex]

Therefore, the gallons of irrigation water per square foot is 326,700 gallons per square foot.

Learn more here: https://brainly.com/question/21631650

Answer:

These are the first 100 digits of pi: 3.14159 26535 89793 23846 26433 83279 50288 41971 69399 37510 58209 74944 59230 78164 06286 20899 86280 34825 34211 7067

Step-by-step explanation:

Pi goes on continuously forever, so this is a reduced version, by including the first 100 digits.

Answer:

0.0009765625

Step-by-step explanation:

This is what i got its probally incorrect

Answer:

1.3859

Step-by-step explanation:

The formula for Margin of Error is given as:

Margin of Error = Critical value × Standard Error

Critical value = z score

In the question, we are given a confidence interval of 95%.

Z score for a 95% confidence level is given as: 1.96

Hence, critical value = 1.96

Standard Error = σ / √n

Where n = number of samples = 98 chicken eggs

σ = Standard deviation = 7 milligrams

Standard Error = 7/√98

Standard Error = 0.7071067812

Hence, Margin of Error = Critical value × Standard Error

Margin of Error = 1.96 × 0.7071067812

Margin of Error = 1.3859292911

Therefore, the margin of error corresponding to a 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is approximately 1.3859

Answer:

(a) 1.341

(b) -2.539

(c) -2.160 and 2.160

Step-by-step explanation:

(a) We have to find the critical​ value(s) for a​ right-tailed test of a population mean at the alpha = 0.10 level of significance with 15 degrees of freedom. ​

Since the degrees of freedom are included here, so we will use t table here for a population mean test.

In the table there are two values given, one is the degrees of freedom and another is the value of P.

P is the level of significance at which the critical values are calculated.

So, here the degrees of freedom (n - 1) = 15 and the level of significance for a right-tailed test is 0.10, i.e. P = 10%

Now, looking in the t table with P = 10% and [tex]\nu[/tex] = 15, we get the critical value of 1.341.

(b) We have to find the critical​ value(s) for a​ left-tailed test of a population mean at the alpha = 0.01 based on a sample size of n = 20. ​

Since the degrees of freedom are included here, so we will use t table here for a population mean test.

In the table there are two values given, one is the degrees of freedom and another is the value of P.

P is the level of significance at which the critical values are calculated.

So, here the degrees of freedom (n - 1) = 20 - 1 = 19 and the level of significance for a left-tailed test is 0.01, i.e. P = 1%

Now, looking in the t table with P = 1% and [tex]\nu[/tex] = 19, we get the critical value of 2.539. But since it is a left-tailed test, so the critical value will be -2.539.

(c) We have to find the critical​ value(s) for a​ two-tailed test of a population mean at the alpha = 0.05 level of significance based on a sample size of n = 14. ​

Since the degrees of freedom are included here, so we will use t table here for a population mean test.

In the table there are two values given, one is the degrees of freedom and another is the value of P.

P is the level of significance at which the critical values are calculated.

So, here the degrees of freedom (n - 1) = 14 - 1 = 13 and the level of significance for a two-tailed test is [tex]\frac{0.05}{2}[/tex] is 0.025, i.e. P = 2.5%.

Now, looking in the t table with P = 2.5% and [tex]\nu[/tex] = 13, we get the critical value of -2.160 and 2.160 for a two-tailed test.

Answer:

[tex]x=4[/tex]

Step-by-step explanation:

Solving for [tex]x[/tex], we get:

[tex]16=2(3x-6)+x[/tex]

[tex]16=2*3x+2(-6)+x[/tex] (Distributive Property of Multiplication)

[tex]16=6x-12+x[/tex] (Multiply distributed terms)

[tex]16=7x-12[/tex] (Combine like terms)

[tex]16+12=7x-12+12[/tex] (Add [tex]12[/tex] to both sides of the equation to isolate [tex]x[/tex])

[tex]28=7x[/tex] (Combine like terms / Simplify)

[tex]\frac{28}{7}=\frac{7x}{7}[/tex] (Divide both sides of the equation by [tex]7[/tex] to get rid of [tex]x[/tex]'s coefficient)

[tex]\bf x=4[/tex] (Simplify / Symmetric Property of Equality)

Hope this helps!

Step-by-step explanation:

[tex]16 = 2(3x - 6) + x \\ 16 = 6x - 12 + x \\ - 6x - x = - 12 - 16 \\ - 7x = - 12 - 16 \\ 7x = 12 + 16 \\ 7x = 28 \\ x = \frac{28}{7} \\ x = 4[/tex]

Answer:422977164210 or it could be [tex]4.2297716421(10) ^{11}[/tex]

Step-by-step explanation:

Answer:

NEGATIVE; DECREASED.

Step-by-step explanation:

A correlation coefficient of -0.76 indicates that there is a "fairly" strong negative relationship between the daily temperature and the number of people who visit the store.

This implies that, as the daily temperature increases, number of customers who come to the store decreases.

Therefore, the interpretation of the situation is:

"There is a NEGATIVE association between x and y. As the high temperature of the day increases across days, the number of customers who come to the store DECREASED.

Answer:

this is the return on an investment that does not include the taxes the investor must pay on this return

Answer:

The correct answer is:

Stratified (c.)

Step-by-step explanation:

Stratified sampling technique is one in which the groups of data are divided into smaller groups or strata, based on shared common characteristics in these groups, and the samples randomly selected from each group in a proportional way. In this example, the sub-groups used is "times of the day" ie. morning, afternoon or evening. Other strata that can be used are; age, gender, continents etc. Stratification is done when the researcher wants to understand the relationships between the two or more groups. Stratified random sampling is also known as proportional random sampling or quota random sampling.