Please help ASAP!! Conner and Jana are multiplying (3⁵6⁸)(3⁹6¹⁰).

Conner's Work: (3⁵6⁸)(3⁹6¹⁰) = 3⁵ + ⁹ 6⁸ + ¹⁰ = 3¹⁴6¹⁸
Jana's Work: (3⁵6⁸)(3⁹6¹⁰) = 3⁵⋅⁹ 6⁸⋅¹⁰ = 3⁴⁵6⁸⁰

Is either of them correct? Explain your reasoning. (i do think jana is incorrect but im not sure how to answer for conner)

Answer:

The answer is X=3/4 or -1/2

The equation p=4+3y is maximised at (4,5) and the maximised value is 31.

Given equation p=4x+3y and constraints x>0,x<4, y<5.

We have to maximise the equation p=4x+3y with constraints x>0,x<4,y<5.

To find out the points we have to make graphs of the constraints first.

From the graph we have found that points are (0,0),(0,5),(4,0),(4,5).

The above points are common points of graphs of all constraints.

The value of equations are as under:

At (0,0) , p=4*0+3*0=0

At (0,5), p=4*0+3*5=15

At (4,0),p=4*4+3*0=16

At (4,5),p=4*4+3*5=16+15=31

Maximum value of p is 31 and that is for (4,5).

Hence the equation is maximised at (4,5) and the maximum value is 31.

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Answer:

first option

Step-by-step explanation:

two solutions means 2 cutting points

The correct answer is (40, 35) because by plugging in,  40 +35 = 75 and

(40 x 5) + (35 x 3) > 300

Word problem can be solved by interpreting the problem into its best fit equation. The equation may be linear, quadratic or simultaneous equations.

Given that

5x + 3y > 300

x + y = 75

Let us first assume that 5x + 3y = 300. That is,

5x + 3y = 300

x + y = 75

Eliminate y by multiplying equation 2 by 3

5x + 3y = 300

3x + 3y = 225

2x = 75

x = 75/2

x = 37.5

Substitute x in equation 2

37.5 + y = 75

y = 75 - 37.5

y = 37.5

The correct answer is (40, 35) because 40 +35 = 75 and

(40 x 5) + (35 x 3) > 300

Therefore,  the solution to the system is (40, 35)

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The minimum value of z is -12.

Given that the system of linear programming

z=-3x+5y

x+y≥-22

x-y≥-4

x-y≤2

Firstly, we will convert the given constraints into equality as

x+y=-22

x-y=-4

x-y=2

Now, we will take the equation x+y=-22 and taking x as 0 as find y and taking y as 0 to find x, we get

If x=0 then y is

0+y=-22

y=-22

If y=0 then x=-22

So, the points lie on the line x+y=-22 is (0,-22) and (-22,0).

Further, we will take the equation x-y=-4 and taking x as 0 as find y and taking y as 0 to find x, we get

If x=0 then y=4

If y=0 then x=-4

So, the points lie on the line x-y=-4 is (0,4) and (-4,0).

Furthermore, we will take the equation x-y=2 and taking x as 0 as find y and taking y as 0 to find x, we get

If x=0 then y=-2

If y=0 then x=2

So, the points lie on the line x-y=2 is (0,-2) and (2,0).

now, we will find the feasible region of the given constraints as shown in figure.

We will find that each constraint will contain origin or not by substituting (0,0), we get

0+0≥-22 containing origin

0-0≥-4 containing origin

0-0≤2 containing origin

From the graph we can see that the minimum value of x is -13 and minimum value of y is -12.

z=-3x+5y

z=-3x+3y+2y

z=-3(x-y)+2y

minmum value of x-y from the given constraints is

-4≤x-y≤2

From here minimum value of x-y is -4

So, z=-3(-4)+2y

z=12+2y

For the minimum value of z the value of y should be minimum.

From the graph we can see the minimum value of y=-12

So, z=12+2(-12)

z=12-24

z=-12

Hence, the minimum value of z for the system of Linear Programming:

z=-3x + 5y, x+y≥-22, x-y≥-4, x - y ≤ 2 is -12.

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Answer:

Step-by-step explanation:

i think it is c

Answer:

A

Step-by-step explanation:

So let's look at each and determine whether they're true or not.

A. It's vertex is at the origin:

   This is true! The reason for this is because you can express a quadratic in vertex form as such: [tex]f(x)=a(x-h)+k[/tex] where (h, k) is the vertex. If you remember the parent function is simply: [tex]f(x)=x^2[/tex] which we can express as: [tex]f(x) = (x-0)+0[/tex] meaning the vertex is at (0, 0). This also intuitively makes sense, the x^2 will only output positive values for real numbers, so when x<0, f(x) is still going to be positive because it's squaring the negative, so that means when you go from -5 to -4, even though you increased x by 1, the f(x) decreases by 1, since it's squaring the value to get a positive value. The lowest value this can output is 0 because 0^2 = 0. This means you vertex is at the origin.

B. It is not a function:

   So the quadratic parent function only outputs 1 value for each input, although it isn't a one-to-one function, meaning that each output isn't unique, but each input still only outputs 1 output, which makes this a function

C. It is not a parabola:

   parabolas are expressed as quadratic equations, so this is false.

D. It is in quadrants ||| and IV:

   This is not true since the parent function opens upwards and has a vertex at (0, 0) so it will only be in quadrant I and II. I'll provide a diagram showing this.

The sum of areas of circle C and circle D exists 98 square units.

Given: Radius of circle = 7 units

Area of circle [tex]=\pi r^2[/tex] ..............(1)

Where, r be the radius of circle

The radius of circle C, r = 7 units

(1) becomes

Area of circle, C [tex]= \pi 7^2[/tex] square units

[tex]= 49\pi[/tex] units²

Area of circle, D [tex]= \pi 7^2[/tex] square units

[tex]= 49\pi[/tex] units²

Sum of areas of circles C and D,

= Area of circle C + Area of circle D

= 49 + 49

= 98 units²

The sum of areas of circles C and D exist 98 units².

Therefore, the correct answer is option d) 98 units².

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The probability that a prize ticket with a vowel will be chosen, not replaced, and then another prize ticket with a vowel will be chosen is 0.031 or 3.1%. So, this represents a dependent event.

It is given that there are 26 prize tickets in a bowl, labeled A to Z.

There are 5 vowels- A, E, I, O, U

So, the probability of choosing a ticket with a vowel will be - (5/26)

Another ticket with a vowel will be chosen without replacing the first ticket. Then, its probability is (4/25)

So, the required probability is,

(5/26) × (4/25) = 2/65 = 0.031

The event of choosing the first ticket with a vowel effect the event of choosing the second ticket with a vowel and vice-versa. So, this represents dependent events.

Therefore, the probability is 3.1 %.

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Point-slope form

[tex]y-2=4(x+1)[/tex]

Slope-intercept form

[tex]y-2=4x+4 \\ \\ y=4x+6[/tex]

Standard form

[tex]4x-y+6=0[/tex]

Answer:

[tex]\textsf{Point-slope form}: \quad \sf y-2=4(x+1)[/tex]

[tex]\textsf{Slope-intercept form}: \quad \sf y=4x+6[/tex]

[tex]\textsf{Standard form}: \quad \sf 4x-y=-6[/tex]

Step-by-step explanation:

Given information:

Point-slope form of linear equation:  

[tex]\sf y-y_1=m(x-x_1)[/tex]

(where m is the slope and (x₁, y₁) is a point on the line)

Substitute the given slope and point into the formula:

[tex]\implies \sf y-2=4(x-(-1))[/tex]

[tex]\implies \sf y-2=4(x+1)[/tex]

Slope-intercept form of a linear equation:

[tex]\sf y=mx+b[/tex]

(where m is the slope and b is the y-intercept)

Substitute the given slope and point into the formula and solve for b:

[tex]\implies \sf 2=4(-1)+b[/tex]

[tex]\implies \sf b=6[/tex]

Therefore:

[tex]\sf y=4x+6[/tex]

Standard form of a linear equation:

[tex]\sf Ax+By=C[/tex]

(where A, B and C are constants and A must be positive)

Rearrange the found slope-intercept form of the equation into standard form:

[tex]\implies \sf y=4x+6[/tex]

[tex]\implies \sf 4x-y+6=0[/tex]

[tex]\implies \sf 4x-y=-6[/tex]

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The cost of kilograms of almonds is $8.5 if 4 kilograms of almonds cost $34.

According to the questions,

4 kilograms of almonds cost $34. In order to find one kilograms of almonds  only if we divide 34 by 4.

= [tex]\frac{34}{4}[/tex] = 8.5

Hence, the cost of kilograms of almonds is $8.5 if 4 kilograms of almonds cost $34.

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Rule 1:

1, 3, 7, 15, 31, 63, 127, 255, 511, 1023 etc

Rule 2:

40, 24, 16, 12, 10, 9, 8.5, 8.25, 8.125, 8.0625 etc

Hope this helps!

The first sequence is 1,3,7,15,31 and second sequence is 40,24,16,12,10.

Given that first rule is that multiply by 2 then add 1 starting from 1 and second rule is that divide by 2 then add 4 starting from 40.

We have to find the sequences for each rule.

We have to start from starting point and then apply the rule to find the sequence.

Sequence of rule 1:

Second term of sequence=2*1+1=3

Third term of the sequence=2*3+1=7

Fourth term of the sequence=2*7+1=15

Fifth term of the sequence=2*15+1=31.

Sequence will be 1,3,7,15,31.

Sequence of rule 2:

Second term of sequence=40/2+4=24

Third term of sequence=24/2+4=16

Fourth term of sequence=16/2+4=12

Fifth term of sequence=12/2+4=10

Sequence will be : 40,24,16,12,10.

Hence the first sequence is 1,3,7,15,31 and second sequence is 40,24,16,12,10.

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Answer:

no

Step-by-step explanation:

using the converse of Pythagoras' identity

if the square on the longest side is equal to the sum of the squares on the other 2 sides then the triangle is right.

longest side = 11 and 11² = 121

7² + 9² = 49 + 81 = 130

since 121 ≠ 130 then sides do not form a right triangle

The expression that must be true for a to be parallel to b are mAngle2 = 58Degrees and <1 = 4x - 10

A line is the shortest distance between two points and the point where two lines meet is known as an angle

From the figure shown

m<2 = 58 degrees (alternate exterior angle)

Since the sum of angles on a straight line is 180 degrees, hence;

3x-1+<2 + 4x - 10= 180

3x-1 + 58 + 4x - 10 =180

7x + 47 = 180

7x = 180- 47

7x = 133

x = 19

Hence the expression that must be true for a to be parallel to b are mAngle2 = 58Degrees and <1 = 4x - 10

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Answer:

angle 2=58 degrees

angle 1=4x-10 degrees

Step-by-step explanation:

a. The equivalent expression for cos(4x) in terms of just x is 8cos⁴x - 8cos²x + 1

b. The equivalent expression for sin(4x) in terms of just x is 4sinxcos³x - 2sinxcosx

To find the trigonometric expression for cos(4x)

cos(4x) = cos[2(2x)]

Now from trigonometric identities

cos2Ф = 2cos²Ф - 1

Let 2x = Ф.

So, cos(4x) = 2cos²2x - 1

Also, cos2x = 2cos²x - 1

So, substituting cos2x into cos4x, we have

cos(4x) = 2cos²2x - 1

cos(4x) = 2[2cos²x - 1]² - 1

cos(4x) = 2[4cos⁴x - 4cos²x + 1] - 1

cos(4x) = 8cos⁴x - 8cos²x + 2 - 1

cos(4x) = 8cos⁴x - 8cos²x + 1

So, the equivalent expression for cos(4x) in terms of just x is 8cos⁴x - 8cos²x + 1

To find the expression for sin(4x)

sin(4x) = sin2(2x)

From trigonometric identities sin2Ф = 2sinФcosФ

Let 2x = Ф

So, sin(4x) = sin2(2x)

= 2sin2xcos2x

Since

Substituting these into the equation, we have

sin(4x) =  2sin2xcos2x

sin(4x) = (2sinxcosx)(2cos²x - 1)

sin(4x) = 4sinxcos³x - 2sinxcosx

So, the equivalent expression for sin(4x) in terms of just x is 4sinxcos³x - 2sinxcosx

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(a) The scale used in the analysis is qualitative as the data is not assigned any numeric value.

The daily performance is an ordinal variable, as the values assigned are ranked according to an order of the delivery time.

(b) The frequency table of the given data is:

Variable Frequency

Early  23

On-time  65

Late            9

Lost            3

Total 100.

(c) The relative frequency table for the given data is:

Variable Frequency Relative frequency

Early  23           23/100 = 0.23 = 23%

On-time  65           65/100 = 0.65 = 65%

Late            9             9/100 = 0.09 = 9%

Lost            3             3/100 = 0.03 = 3%

(a) The scale used in the analysis is qualitative as the data is not assigned any numeric value.

The daily performance is an ordinal variable, as the values assigned are ranked according to an order of the delivery time.

(b) The frequency table is a table showing frequency of each variable for the number of times they appear in the data.

The frequency table of the given data is:

Variable Frequency

Early  23

On-time  65

Late            9

Lost            3

Total 100.

(c) The relative frequency for a variable is the ratio of its frequency to the total frequency.

The relative frequency table for the given data is:

Variable Frequency Relative frequency

Early  23           23/100 = 0.23 = 23%

On-time  65           65/100 = 0.65 = 65%

Late            9             9/100 = 0.09 = 9%

Lost            3             3/100 = 0.03 = 3%

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Answer:

C.

Step-by-step explanation:

No she is not correct 1/3 is great that 1/4

Answer:

No, she isn't correct because if the numerator are same but if denominators is different,then the fraction with smaller denominator is greater.

Answer:

23 there will be 100 paperclips leftover

Answer:

33.3

Step-by-step explanation:

The scale factor is 2/3.

The ratio of the surface areas is the square of the scale factor, so the surface area of the smaller cone is 75(2/3)², which is about 33.3 cm²

Answer:

correct answer is 110x + 29y = 333

Step-by-step explanation:

Answer:

Since April 1, 1986 was a Tuesday, March,

1986 had? Mondays.

og

the answer A

Using the binomial distribution, it is found that there is a 0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

With 5 shoots, the probability of making at least one is [tex]\frac{211}{243}[/tex], hence the probability of making none, P(X = 0), is [tex]\frac{232}{243}[/tex], hence:

[tex](1 - p)^5 = \frac{232}{243}[/tex]

[tex]\sqrt[5]{(1 - p)^5} = \sqrt[5]{\frac{232}{243}}[/tex]

1 - p = 0.9908

p = 0.0092

Then, with 6 shoots, the parameters are:

n = 6, p = 0.0092.

The probability that at least two of them make it inside the recycling bin is:

[tex]P(X \geq 2) = 1 - P(X < 2)[/tex]

In which:

[P(X < 2) = P(X = 0) + P(X = 1)

Then:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{6,0}.(0.0092)^{0}.(0.9908)^{6} = 0.9461[/tex]

[tex]P(X = 1) = C_{6,1}.(0.0092)^{1}.(0.9908)^{5} = 0.0527[/tex]

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.9461 + 0.0527 = 0.9988

[tex]P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9988 = 0.0012[/tex]

0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

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The slope of the line through the points is -3

The points are given as:

(-1, 8) and (3, -4)

The slope is calculated as:

m = (y2 - y1)/(x2 - x1)

So, we have:

m = (-4 - 8)/(3 + 1)

Evaluate the expression

m = -3

Hence, the slope of the line through the points is -3

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The slope of the line that passes through (-1, 8) and (3, -4) is: -3.

Slope of a line (m) = change in y / change in x.

Given the points, (-1, 8) and (3, -4):

Slope (m) = (-4 - 8)/(3 - (-1))

Slope (m) = (-12)/(4)

Slope (m) = -3

Thus, the slope that passes through the given points is: -3.

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hi

"does not change "  or "remain the same "

The number of tickets sold on Friday were 66 children tickets and 97 adult tickets.

An equation is an expression that shows the relationship between two or more numbers and variables.

The equation of the parabola passing through (0, 0), (-3, 9) and (3, 9) is y = x²

The equation of the parabola with vertex at (4, 22) passing through (0, 6), (8, 6) and (3, 9) is y < -x² + 8x + 6

The solution to the system of equation is the darker region and it contains the point (-1, 6)

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Answer:

(2,9)

Step-by-step explanation:

Got it on FlVS

Answer:

They are similar.  Triangle abc is similar to triangle edc.

Step-by-step explanation:

To prove that triangles are similar, you must show that the 3 angles in one triangle are equal to the 3 angles in the other triangle.  We know that they both have a 50 degree angle.  We can also see that they both have a right angle.  That means that the 3rd angle must also equal 40 (180-90-50).  So by AAA the two triangles are congruent.

Triangle ABC is similar to triangle EDC.

Answer:

triangle ABC is similar to triangle DCE

Step-by-step explanation:

Reason being that angles in triangle ABC Correspond to That of triangle DCE Eg triangle ABC=CDE

Step-by-step explanation:

we first divide fourteen by four

14/4= 3.5

then we change 0.5 to hours by multiplying by 60

0.5 * 60 = 30

so in conclusion it would take 3hrs 30mins to finish each activity

In a two-tailed hypothesis test the null hypothesis is rejected.

According to the statement

The test statistic is 3.06 and the critical values are /-2.086.

If we find the value of t by using the formula the then it comes with Negative sign and it lies under the critical region.

That's why In a two-tailed hypothesis test the null hypothesis is rejected.

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Question 4

[tex]\sin 30^{\circ}=\frac{y}{14\sqrt{3}}\\\\\frac{1}{2}=\frac{y}{14\sqrt{3}}\\\\\boxed{y=7\sqrt{3}}\\\\\\\\\cos 30^{\circ}=\frac{x}{14\sqrt{3}}\\\\\frac{\sqrt{3}}{2}=\frac{x}{14\sqrt{3}}\\\\\boxed{x=21}[/tex]

Question 5

[tex]\cos 45^{\circ}=\frac{x}{28}\\\\\frac{1}{\sqrt{2}}=\frac{x}{28}\\\\x=\frac{28}{\sqrt{2}}\\\\\boxed{x=14\sqrt{2}}\\\\\\\\\sin 45^{\circ}=\frac{y}{28}\\\\\frac{1}{\sqrt{2}}=\frac{y}{28}\\\\y=\frac{28}{\sqrt{2}}\\\\\boxed{y=14\sqrt{2}}[/tex]

None of the expressions is an identity

The expressions are given as:

I. y=x

II. 4 = 3x^2 + 2

III. x=x

In algebra, there are three identities; and they are

None of the given expression take the above forms

Hence, none of the expressions is an identity

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