The angle subtended at the centre of the circle by a 2.9 centimeter arc is equal to 15° 38.46'/15° 38' 27.6''.
What is the measure of the central angle of a circular section?
In this problem we have to determine the measure of a central angle of a circular section in DMS (Degrees - Minutes - Seconds) system, in which a degree is equal to 60 minutes and a minute to 60 seconds. First, we must calculate the radius of the circle by the area formula:
r = √ (A / π) (1)
r = √ (354 / π)
r ≈ 10.615 cm
Then, the measure of the central angle in radians is found by the equation of circular arc:
θ = s/r
θ = 2.9 cm / 10.615 cm
θ = 0.273 radians
Finally, we convert the angle into DMS system:
θ = 0.273 rad × 180°/π
θ = 15.641°
Degrees: 15°
Minutes and seconds: 0.641° (38.46')
Minutes: 38'
Seconds: (0.46' = 27.6'')
The angle subtended at the centre of the circle by a 2.9 centimeter arc is equal to 15° 38.46'/15° 38' 27.6''.
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1. Which of the statements is NOT true about the illustration?
Angle DME is another name for angle 3.
MDis congruent to AE.
Angle 3 is congruent to angle 5.
MEis parallel to AD.
Answer: Option (1)
Step-by-step explanation:
[tex]\angle DMA[/tex] is another name for angle 3, but not [tex]\angle DME[/tex].
A cruise line ship left Port A and traveled 90 miles due west and then 400 miles due north. At this point, the ship docked at Port B What is the shortest distance between Port A and Port B?
Answer:
410 Miles
Step-by-step explanation:
Please refer to the photo attached. (Apologies for the legitimately terrible drawing)
The Shortest Distance between any 2 points is the distance thats connects the 2 points directly.
In this case, we can use Pythgoras's Theorem to find AB which is the shortest distance between A and B.
By Pythagoras's Theorem,
[tex] {c}^{2} = {a}^{2} + {b}^{2} \\ {ab}^{2} = {ac}^{2} + {cb}^{2} \\ {ab}^{2} = {90}^{2} + {400}^{2} \\ab = \sqrt{ {90}^{2} + {400}^{2} } \\ = 410 \: miles[/tex]
Marissa is painting her rectangular patio, with the exception of a bench that does not need to be painted: rectangle with a length of x plus 20 and width of x plus 10 with a rectangle in the bottom right corner labeled bench that has a length of 6 and width of 2 write an equation to determine the area, a, of the patio that will be painted. a = (x 20)(x 10) 12 a = (x 20)(x 10) − 12 a = (x 26)(x 12) a = (x 14)(x 8)
The area of the rectangular patio to be painted is: B. A = (x + 20)(x + 10) - 12.
What is a Rectangle?A rectangle, by definition, is a quadrilateral with two pairs of opposite that have the equal lengths. All four angles of a rectangle are right angles (90 degrees).
What is the Area of a Rectangle?The area of a rectangle = (length of rectangle)(width of rectangle).
Given the following parameters for the patio and the bench:
Length of rectangular patio = x + 20Width of rectangular patio = x + 10Length of rectangular bench = 6Width of rectangular bench = 2Area to be painted = area of rectangular patio - area of rectangular bench
Area of rectangular patio = (x + 20)(x + 10)
Area of rectangular bench = (6)(2) = 12
Area to be painted = (x + 20)(x + 10) - 12
The answer is: B. A = (x + 20)(x + 10) - 12.
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suppose cos(A) = 4/5. use the trig identity sin^2(A)+cos^2(A)=1 to find sin(A) in quadrant IV. round to the ten-thousandth.
a. -0.3954
b. -0.6000
c. 0.6485
d. 0.4500
In quadrant IV, [tex]\sin(A)[/tex] is negative. So
[tex]\sin^2(A) + \cos^2(A) = 1 \implies \sin(A) = -\sqrt{1-\cos^2(A)} = -\dfrac35 = \boxed{-0.6000}[/tex]
Find the equation of the line that
is perpendicular to y = 6x-2 and
contains the point (6, -2).
y =
= [2²] x + [ ]
Answer:
y = - [tex]\frac{1}{6}[/tex] x - 1
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 6x - 2 ← is in slope- intercept form
with slope m = 6
given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{6}[/tex] , then
y = - [tex]\frac{1}{6}[/tex] x + c ← is the partial equation
to find c substitute (6, - 2 ) into the partial equation
- 2 = - 1 + c ⇒ c = - 2 + 1 = - 1
y = - [tex]\frac{1}{6}[/tex] x - 1 ← equation of perpendicular line
A school cafeteria uses 10
8 bowls of chocolate pudding.
How many cups of milk are in each bowl of chocolate pudding?
cups
Using proportions, it is found that there are 5 cups of milk in each bowl of chocolate pudding.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three.
The cafeteria used 10 quarts for 8 bowls, hence the number of quarts per bowl is:
10/8 = 1.25
Each quart has 4 cups, hence the number of cups is:
4 x 1.25 = 5 cups.
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PLEASE HELP IM SO STUCK
Answer:
-4
Step-by-step explanation:
Slope = y/x
1. y=12 x=-3
12/-3=-4
2. y=8, x=-2
8/-2 = -4
3. y=4, x=-1
4/-1 = -4
4. 0/0 = 0
5. y=-4, x=1
-4/1 = -4
Hope it helps I had this question last year on Acellus.
Which ordered pair is a solution to the system of linear equations? 2x 3y= 6 –3x 5y = 10
The given system of equations has the solution, x = 0, and y = 2, giving the ordered pair (0, 2). Hence, the first option is the right choice.
In the question, we are asked for the ordered pair, which is the solution to the system of equations:
2x + 3y= 6 ... (i)
–3x + 5y = 10 ... (ii).
To solve for the solution to the system of equations, we use the elimination method.
We multiply (i) by 3, and (ii) by 2, and then add the resultant equations to eliminate x as follows:
6x + 9y = 18 {(i) * 3}
-6x + 10y = 20 {(ii) * 2}
_____________
19y = 38,
or, y = 38/19 = 2.
Substituting, y = 2, in (i), we get:
2x + 3y = 6,
or, 2x + 3(2) = 6,
or, 2x + 6 = 6,
or, 2x = 6 - 6 = 0,
or, x = 0/2 = 0.
Thus, the given system of equations has the solution, x = 0, and y = 2, giving the ordered pair (0, 2). Hence, the first option is the right choice.
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The complete question is:
"Which ordered pair is a solution to the system of linear equations?
2x + 3y= 6
–3x + 5y = 10
(0,2)
(2,0)
(3,2)
(2,3)"
Which graph represents the function p(x) = |x-1|?
-3
O
-2-
-3.
O
64-3
3.
2
2
3
O
5
Graph is in the attached image.
The table represents a function.
X f(x)
-4 -2
-1 5
3 4
5 -8
What is f(5)?
-8
-1
1
8
Answer: -8
Step-by-step explanation:
When x = 5, f(x) = -8.
The value of the function f(5) = -8.
We have,
The concept used to find the value of f(5) is function evaluation.
In this case, we are given a function represented by a table with x and f(x) values.
To evaluate the function at a specific value, such as f(5), we look for the corresponding x-value in the table and determine the corresponding f(x) value.
In this example, we found that when x = 5, f(x) is -8 by looking at the table provided.
To find the value of f(5), we need to look at the table and find the corresponding value of the function when x = 5.
From the given table, when x = 5, f(x) is -8.
Therefore,
The value of the function f(5) = -8.
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rewrite the equation to represent the resistance of resistor 2, r2, in terms of rt and r1.
The rewritten equation to represent the resistance of resistor 2, R₂, in terms of [tex]R_T[/tex] and R₁ is [tex]R_2 = \frac{R_TR_1}{R_1-R_T}[/tex].
Hence, the 3rd option is the right choice.
To rewrite any equation, in terms of the other variable, we just need to change the isolation of the variable by rearranging it.
In the question, we are given the equation for the total resistance [tex]R_T[/tex] for a circuit with two resistance R₁ and R₂ connected in parallel as:
[tex]R_T = \frac{R_1R_2}{R_1+R_2}[/tex]
We are asked to rewrite the equation to represent the resistance of resistor 2, R₂, in terms of [tex]R_T[/tex] and R₁.
To rewrite the equation, we do as follows:
[tex]R_T = \frac{R_1R_2}{R_1+R_2}\\\Rightarrow R_T(R_1 + R_2) = R_1R_2\\\Rightarrow R_TR_1 + R_TR_2 = R_1R_2\\\Rightarrow R_1R_2 - R_TR_2 = R_TR_1\\\Rightarrow R_2(R_1-R_T) = R_TR_1\\\Rightarrow R_2 = \frac{R_TR_1}{R_1-R_T}[/tex]
Thus, the rewritten equation to represent the resistance of resistor 2, R₂, in terms of [tex]R_T[/tex] and R₁ is [tex]R_2 = \frac{R_TR_1}{R_1-R_T}[/tex].
Hence, the 3rd option is the right choice.
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For the complete question, refer to the attachment.
For what value of mc009-1 is the function one-to-one?
(1, 2), (2, 3), (3, 5), (4, 7), (5, 11), (6, c)
2
5
11
13
Using the concept of an one-to-one function, it will be one-to-one for c = 13.
What is an one-to-one function?A function is said to be one-to-one if each output is mapped to only one input.
In this problem, outputs 2, 5 and 11 have already been matched to inputs 1, 3 and 5, respectively, hence the output for input 6 has to be c = 13 for a one-to-one function.
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3, -3/2, -6, -21/2… what is the explicit function that defines the sequence
The explicit function that defines the sequence is 15/2 - 9n/2
How to determine the explicit rule?The sequence is given as:
3, -3/2, -6, -21/2
The above sequence is an arithmetic sequence, with the following parameters
First term, a = 3Common difference, d = -9/2 i.e. -3/2 - 3The explicit formula is then calculated as:
T(n) = a + (n -1) * d
This gives
T(n) = 3 +(n -1) * -9/2
Expand
T(n) = 3 + 9/2 - 9n/2
Evaluate
T(n) = 15/2 - 9n/2
Hence, the explicit function that defines the sequence is 15/2 - 9n/2
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Consider rolling a fair die thrice and tossing a fair coin sixteen times. Assume that all the tosses and rolls are independent. The chance that the total number of heads in all the coin tosses equals 12 is (
The probability that the total number of heads in all the coin tosses equals 12 is 0.0273.
Given a fair dice and tossing a fair coin sixteen times.
We have to find the probability that the total number of heads in all the coin tosses equals 12.
The probability lies between 0 and 1.
Probabiltiy of coming head when the coin is tossed 1 time is 0.5 and probability of coming tails is also 0.5.
Let X shows the sum of heads while tossing.
P(X=12)=?
We can find the probability using binomial theorem.
=[tex]16C_{12} (0.5)^{12} (0.5)^{2}[/tex]
We have to toss sixteen times and out of 16 times we need head 12 times.
=16!/12!4!*0.00024*0.0625
=1820*0.000015
=0.0273
Hence the probability that the total number of heads in all the coin tosses equals 12 is 0.0273.
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Which is the graph of the linear inequality 2x-3y < 12?
Answer:
First, transform the given equation into the slope-intercept form, y = mx + b.
2x - 3y < 12
3y > 2x - 12
y > [tex]\frac{2}{3}[/tex]x - 4
Since the equation is y > [tex]\frac{2}{3}[/tex]x - 4, first draw the graph of y = [tex]\frac{2}{3}[/tex]x - 4 with a dotted line (because it is >, not ≥) and shade the area above the dotted line.
there are three red marbles 5 green marbles 2 blue marbles in a bag which of the follwing are true
Answer:
4 and 1
Step-by-step explanation:
Determine if the solution set for the system of equations shown is the empty set, contains one point or is infinite.
2x - y = 7
2y = 4x - 14
Since there are same number of either side, hence the solution has infinite number of solution
System of equationsSystem of equations are equation that consist of two or more equations with unknown variables.
Given the equations
2x - y = 7
2y = 4x - 14
This can also be written as
2x - y = 7
y = 2x - 7
Substitute equation 2 into 1
2x - (2x - 7) = 7
2x-2x+7= 7
7 = 7
Since there are same number of either side, hence the solution has infinite number of solution
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What is the final step in solving the inequality –2(5 – 4x) < 6x – 4?
x < –3
x > –3
x < 3
x > 3
x<3
Step-by-step explanation:
–2(5 – 4x) < 6x – 4
(–10 + 8x) < 6x – 4
8x –6x < –4 + 10
2x < 6
x < 3
Peter sells ice cream for a living. On Monday, his revenue was 150 dollars. On Tuesday, his revenue was 100 dollars. Finally, on Wednesday, his revenue was 50 dollars. How much is Peter's revenue so far?
Answer:
300 dollars
Step-by-step explanation:
Note that:
{Peter's revenue on Monday: 150 dollars
Peter's revenue on Tuesday: 100 dollars
Peter's revenue on Wednesday: 50 dollars}
---------------------------------------------------------------
In this problem, we need to find how much is Peter's revenue so far (total).
We need to use addition to determine how much Peter's revenue is in total.
So, add 150, 100, and 50.
We get 150 + 100 + 50 = 300
Finally, Peter's revenue in total is 300 dollars.
Answer:
$300
Step-by-step explanation:
add 150+100+50
=300
Wey wey wonders how much water it would take to fill her cup. she drops her pencil in her cup and notices that it only fits diagonally. the pencil is 17 centimeters long and the cup is 15 centimeters tall. how much water can the cup hold? use paper to help you with your thinking.
Answer:
240π cm³ (exact)
754 cm³ (approximate)
Step-by-step explanation:
I assume the shape of the cup is a cylinder. The height of the cylinder is 15 cm.
Think of a vertical rectangle that contains the vertical axes of the cylinder.
Two sides of the rectangle are diameters of the bases of the cylinder. The other two side are heights of the cylinder. The pencil is 17 cm long and is a diagonal of this rectangle. We can find the diameter of the base of the cylinder using the Pythagorean theorem.
In a rectangle that is 15 cm long, the diagonal measures 17 cm.
a² + b² = c²
15² + b² = 17²
b = 8
The diameter of the cup is 8 cm.
radius = 8 cm/2 = 4 cm
V = πr²h
V = π(4 cm)²(15 cm) = 240π cm³ (exact)
V = 754 cm³ (approximate)
Someone please help meeeeeee
Answer:
a ≈ 16.5 cm , b ≈ 23.8 cm
Step-by-step explanation:
using the Law of Sines in Δ ABC
[tex]\frac{a}{sinA}[/tex] = [tex]\frac{b}{sinB}[/tex] = [tex]\frac{c}{sinC}[/tex]
we require to calculate ∠ C
∠ C = 180° - (42 + 75)° = 180° - 117° = 63°
Then to find a
[tex]\frac{a}{sinA}[/tex] = [tex]\frac{c}{sinC}[/tex] ( substitute values )
[tex]\frac{a}{sin42}[/tex] = [tex]\frac{22}{sin63}[/tex] ( cross- multiply )
a × sin63° = 22 × sin42° ( divide both sides by sin63° )
a = [tex]\frac{22sin42}{sin63}[/tex] ≈ 16.5 cm ( to the nearest tenth )
similarly to find b
[tex]\frac{b}{sinB}[/tex] = [tex]\frac{c}{sinC}[/tex] ( substitute values )
[tex]\frac{b}{sin75}[/tex] = [tex]\frac{22}{sin63}[/tex] ( cross- multiply )
b × sin63° = 22 × sin75° ( divide both sides by sin63° )
b = [tex]\frac{22sin75}{sin63}[/tex] ≈ 23.8 cm ( to the nearest tenth )
Answer:
Step-by-step explanation:
Sine rule of Law of sine:[tex]\sf \boxed{\bf\dfrac{a}{Sin \ A}=\dfrac{b}{Sin \ B}=\dfrac{c}{Sin \ C}}[/tex]
Side 'a' faces ∠A.
Side 'b' faces ∠B.
Side 'c' faces ∠C.
We have to find ∠C using angle sum property of triangle.
∠C + 75 + 42 = 180
∠C +117 = 180
∠C = 180 - 117
∠C = 63°
[tex]\sf \dfrac{a}{Sin \ 42}= \dfrac{22}{Sin \ 63}\\\\ \dfrac{a}{0.67}=\dfrac{22}{0.89}\\\\[/tex]
[tex]\sf a = \dfrac{22}{0.89}*0.67\\\\ \boxed{a = 16.56 \ cm }[/tex]
[tex]\sf \dfrac{b}{Sin \ B} = \dfrac{c}{Sin \ C}\\\\ \dfrac{b}{Sin \ 75}=\dfrac{22}{Sin 63}\\\\ \dfrac{b}{0.97} =\dfrac{22}{0.89}\\\\[/tex]
[tex]\sf b = \dfrac{22}{0.89}*0.97\\\\ \boxed{b =23.98 \ cm }[/tex]
Which expression is equivalent to (r^5/4
Answer:
2
Step-by-step explanation:
• Multiplying two numbers with same bases is the same as adding their powers:
∴ [tex](\frac{4^{\frac{5}{4} } \cdot 4^{\frac{1}{4} }}{4^{\frac{1}{2} }})^{\frac{1}{2} }[/tex]
⇒ [tex](\frac{4^{\frac{5}{4} } ^ + ^{\frac{1}{4} }}{4^{\frac{1}{2} }})^{\frac{1}{2} }[/tex]
⇒ [tex](\frac{4^{\frac{6}{4} }}{4^{\frac{1}{2} }})^{\frac{1}{2} }[/tex]
• Dividing two numbers with same bases is the same as subtracting their powers:
∴ [tex](\frac{4^{\frac{6}{4} }}{4^{\frac{1}{2} }})^{\frac{1}{2} }[/tex]
⇒ [tex](4^{{\frac{6}{4} - \frac{1}{2} }})^{\frac{1}{2} }[/tex]
⇒ [tex](4^{1})^{\frac{1}{2} }[/tex]
⇒ [tex]4^{\frac{1}{2}[/tex]
• Raising anything to the power of [tex]\frac{1}{2}[/tex] is the same as square-rooting it:
∴ [tex]4^{\frac{1}{2}[/tex]
⇒ [tex]\sqrt{4}[/tex]
⇒ 2
A badminton net is tethered to the ground with a strand of rope that forms a 50 angle with the ground. What is the length of the rope, x? Write an equation and show work below. Round to the nearest tenth.
Answer:
5.4 ft to nearest tenth.
Step-by-step explanation:
We know the adjacent side of the right triangle and we need the hypotenuse so we use the cosine:
cos 50 = 3.5/x
x = 3.5 / cos 50
= 5.445 ft.
Find the volume of this cone.
To start calculating the volume of the cone, we obtain the following data:
r = 4 cmh = 9 cmπ = 3To calculate the volume of a cone, we apply the following formula:
[tex]\boldsymbol{\sf{V=\dfrac{\pi r^{2}h }{3} }}[/tex], where
V = volumeh = heightr = radiusπ = piWe solve, substituting our data in the formula:
[tex]\boldsymbol{\sf{V=\dfrac{3*(4 \ cm)^{2}*9 \ cm }{3} }}[/tex]taking the square root
[tex]\boldsymbol{\sf{V=\dfrac{3 *16 \ cm^{2}*9 \ cm }{3} }}[/tex]Multiplying
[tex]\boldsymbol{\sf{V=\dfrac{432 \ cm^{3} }{3} }}[/tex]Dividing
[tex]\boxed{\boldsymbol{\sf{V=144 \ cm^{3} }}}[/tex]Therefore the volume of the cone is 144 cm³.
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\textbf{What is the formula for finding the}\\\\\huge\textbf{the volume of a cone?}[/tex]
[tex]\large\boxed{\mathsf{\dfrac{\pi \times r^2\times h}{3} = volume}}[/tex]
[tex]\bullet\large\textsf{ Whereas, \boxed{r} is your \underline{radius}, \boxed{h} is your \underline{height}, \& \boxed{\pi} is your pi.}[/tex]
[tex]\bullet\large\textsf{The pi }\boxed{(\pi)}\large\textsf{ is approximately equal to 3.14.}[/tex]
[tex]\huge\textbf{What are the labels in your equation?}[/tex]
[tex]\star\ \large\boxed{{Radius}}\rightarrow \textsf{\underline{4\ centimeters}}}}}[/tex]
[tex]\star\ \large\boxed{{Height}}\rightarrow \textsf{\underline{9\ centimeters}}}}}[/tex]
[tex]\star\ \large\boxed{{\pi}}\rightarrow \textsf{\underline{3}}}}}[/tex]
[tex]\huge\textbf{What does should the equation look}\\\\\huge\textbf{like?}[/tex]
[tex]\large\boxed{\mathsf{\dfrac{3 \times 4^2 \times9}{3}}}[/tex]
[tex]\huge\textbf{What are the steps to solve for the}\\\\\huge\textbf{question to get the result?}[/tex]
[tex]\large\boxed{\mathsf{\dfrac{3 \times 4^2 \times9}{3}}}[/tex]
[tex]\large\boxed{\mathsf{= \dfrac{3\times4\times4\times9}{3}}}[/tex]
[tex]\large\boxed{= \mathsf{\dfrac{3\times16\times9}{3}}}[/tex]
[tex]\large\boxed{\mathsf{= \dfrac{48\times9}{9}}}[/tex]
[tex]\large\boxed{\mathsf{= \dfrac{432}{3}}}[/tex]
[tex]\large\boxed{\mathsf{= \dfrac{432 \div 3}{3\div3}}}[/tex]
[tex]\large\boxed{= \mathsf{\dfrac{144}{1}}}[/tex]
[tex]\large\boxed{\mathsf{= 144\div1}}[/tex]
[tex]\large\boxed{= \textsf{144}}[/tex]
[tex]\huge\textbf{What is the result to this question?}[/tex]
[tex]\huge\boxed{\frak{144\ cm^3}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
15. Juan has a fair six-sided die, if Juan rolls the die
twice in a row, what is the probability that the die
will show a 3 both times?
Answer:
1/36
Step-by-step explanation:
The probability for showing a three the first time is 1/6, and then again is another 1/6, multiply and you get 1/36
SOMEONE PLEASE HELP!!!!!!
Consider the functions graphed below. A curve a intersects a parabola b at (negative 1, 0 point 5) and a parabola c at (negative 2 point 4, 0 point 3). A diagonal curve d intersects the parabola b at (0 point 5, 0) and (2, 3) and parabola c at (negative 1 point 2, negative 1 point 2). Determine which function has the greatest rate of change over the interval [0, 2]. A. d B. b C. c D. a
The function with the greatest rate of change over the interval [0, 2] is: D. a.
How to determine function with the greatest rate of change?In Mathematics, the rate of change of a function over a given interval can be determined by calculating the slope of the straight line which connect its end points.
Mathematically, the slope of any straight line can be calculated by using this formula;
[tex]Slope = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}[/tex]
For line a, we have:
Points (x, y) = (0, 1) and (2, 4)
Slope = (4 - 1)/(2 - 0)
Slope = 3/2 or 1.5.
For line b, we have:
Points (x, y) = (0, 0) and (2, 2)
Slope = (2 - 0)/(2 - 0)
Slope = 2/2 or 1.0.
For line c, we have:
Points (x, y) = (0, -1) and (2, 0)
Slope = (0 + 1)/(2 - 0)
Slope = 1/2 or 0.5.
For line d, we have:
Points (x, y) = (0, 0.5) and (2, 2.5)
Slope = (2.5 - 0.5)/(2 - 0)
Slope = 2/2 or 1.
In conclusion, we can logically deduce that "function a" has the greatest rate of change over the interval [0, 2].
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Calculate the mean and standard deviation for the average yards rushed by
each player. Then graph the data (use the mean for each player and SD for error bars).
Compare and contrast the mean rushing yards Dillon and Corey.
What does the SD indicate about the mean rushing yards for each player?
Question:
A sample of cans of peaches was taken from a warehouse, and the content of each can mearsed for weight. the sample means was 486g with stand deviation 6g. state the weight percentage of cans with weight:
Draw normal curve to help - split into 8 section ( i can't draw it here)
a) 34.13% of cans will be between 480g and 486g.
b) 13.59 + 2.15 + 0.13= 15.87% of cans greater than 492g.
Look at the Stand Dev Graph where the give you the number
Step-by-step explanation:
Let me give you a different question and i will answer it, which you help you answer your question.
The image is listed below. Any help would be appreciated!
Check the picture below.
part A
since the base of the triangular base is 16, and the altitude "h" splits the base in two equal halves, half that is just 8, so we're looking at a right triangle with a hypotenuse of 17 and a side of 8, thus
[tex]\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2 - a^2}=b \qquad \begin{cases} c=\stackrel{hypotenuse}{17}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{h}\\ \end{cases} \\\\\\ \sqrt{17^2-8^2}=h\implies \sqrt{225}=h\implies \boxed{15=h}[/tex]
part B
well, the prism is simply two triangles and 3 rectangles, le's simply add their areas.
[tex]\stackrel{two~triangles}{2\left[ \cfrac{1}{2}(\stackrel{base}{16})(\stackrel{height}{15}) \right]}~~ + ~~\stackrel{two~rectangles}{2(20)(17)}~~ + ~~\stackrel{one~rectangle}{(20)(16)} \\\\\\ 240~~ + ~~680~~ + ~~320\implies \text{\LARGE 1240}[/tex]
Determine the slope of the line
Answer:1+1
Step-by-step explanation:
What’s 2 + 2 + 5 + 69 + 89. This will definitely help me out.
Answer:
167
Hope this helps you out
Answer:
167
Step-by-step explanation:
Break it into steps.
2+2+5 = 9
69 + 9 = 78
78 + 89 = 167
Hope this helps.