Please help ! I’ll mark you as brainliest if correct.

Answer:

1/5

Step-by-step explanation:

the two points are(7,5) and (2,4)

let,(x1,y1)=(7,5) and (x2,y2)=(2,4)

slope (m)=y2-y1/x2-x1

=4-5/2-7

=-1/-5

=1/5(minus ,minus are cut)

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Explanation:

When we reflect any point (x,y) over the line y = x, the x and y coordinates swap. So for instance, we have K = (5, -9) turn into K ' = (-9, 5).

Consider a point like (1,2). We can move it down 1 unit to have it land on the line y = x, then we can move it one unit to the right to move it to (2,1). These two translations effectively move the original point to its reflected location. The distance from (1,2) to y = x, is the same as the distance from (2,1) to y = x. Furthermore, the line connecting (1,2) to (2,1) is perpendicular to y = x.

Answer:

time taken for trip 2nd half >  time taken for trip 1st half

Step-by-step explanation:

Let the total distance of Joy's trip be = D

Then, the first half distance travelled = D/2

The rate (speed) at which Joy travels during first half = x

So, time taken to travel first half  = Distance / Speed

= (D/2) / x = D / 2x

Let the rate (speed) at which Joy travels during second half = x'

As given, x' (second half speed) < x (first half speed)

So, time taken to travel first half =  Distance / Speed  

(D/2) / x' =  D / 2x'

As  x' < x : D / 2x'  > D / 2x .

Trip 1st half Time taken trip < 2nd half ; or trip 2nd half time taken > 1st half

Answer:

The probability of randomly selecting a queen or club from a deck of cards = 17/52

Step-by-step explanation:

Here in this question, we are concerned with computing the probability of randomly selecting a queen or club form a deck of cards

Mathematically, the probability is;

Probability of selecting a queen + Probability of selecting a club

Probability of selecting a queen = number of queens/total card number

The number of queens = 4

Probability of selecting a queen = 4/52

Probability of selecting a club card = number of club cards/ total number of cards

Number of club cards = 13

Probability of selecting a club card = 13/52

The probability of selecting a queen or club from a deck of cards = 4/52 + 13/52 = 17/52

Answer:

sec^2(x)

Tell me if I'm correct or wrong. If I'm correct, plz mark me brainliest!

Step-by-step explanation:

Recall that

[tex]\sin (\frac{\pi}{2} - x) = \cos x[/tex]

[tex]\cos (\frac{\pi}{2} - x) = \sin x[/tex]

So we can rewrite the given expression as

[tex]\dfrac{\cos^2 x}{\sin^2 x} + (\sin^2 x + \cos^2 x)[/tex]

[tex]\Rightarrow \dfrac{\cos^2 x}{\sin^2 x} + 1[/tex]

or

[tex]\dfrac{\cos^2 x + \sin^2 x}{\sin^2 x} = \dfrac{1}{\sin^2 x} = \csc^2 x[/tex]

We need to find the amount of money Janet invested in 10 years to yield 7425 EUR

She invested EUR 21,214.29

Simple interest = P × R × T

Where,

P = principal = ?

R = interest rate = 3.5% = 0.035

T = Time = 10 years

Simple interest = 7425 EUR

Simple interest = P × R × T

7425 = p × 0.035 × 10

7425 = p × 0.35

7425 = 0.35p

Divide both sides by 0.35

P = 7425 / 0.35

= 21,214.285714285

Approximately,

P = EUR 21,214.29

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Responder:

2

Explicación paso a paso:

El valor absoluto de una expresión es el también conocido como valor positivo devuelto por la expresión. Una expresión en un signo de módulo se conoce como valor absoluto de la expresión y dicha expresión siempre toma dos valores (tanto el valor positivo como el negativo).

Por ejemplo, el valor absoluto de x se escribe como | x | y esto puede devolver tanto + x como -x debido al signo del módulo.

Pasando a la pregunta, debemos determinar el valor absoluto de | 13-11 |. Esto significa que debemos determinar el valor positivo de la expresión como se muestra;

= | 13-11 |

= | 2 |

Este módulo de 2 puede devolver tanto +2 como -2, pero el valor absoluto solo devolverá el valor positivo, es decir, 2.

Por tanto, el valor absoluto de la expresión es 2

Answer:

3003 ways

Step-by-step explanation:

(7+8)C5

= 15C5

= 15!/(5!10!)

= 3003

Answer:

17900

Step-by-step explanation:

First term a = -19

common difference d = -15-(-19) = 4

number of terms, n = 100

sum of first 100 terms,

n/2(2a+(n-1)d)

= 100/2(2×(-19)+(100-1)4)

= 50×(-38+99×4)

= 50×358

= 17900

Answer:

10/7 or 1 3/7. I hope this helps,

Step-by-step explanation:

Answer: The value of (f*g)(7) is 66.

Step-by-step explanation:

Given functions: [tex]f(x)= 4x-6\text{ and } g(x)=\sqrt{x+2}[/tex]

Since, product of two functions: [tex](u*v)(x)=u(x)\times v(x)[/tex]

[tex](f*g)(x)=f(x)\times g(x)\\\\=4x-6\times \sqrt{x+2}\\\\\Rightarrow\ (f*g)(x)=(4x-6) \sqrt{x+2}[/tex]

[tex](f*g)(7)=(4(7)-6)\sqrt{7+2}\\\\=(28-6)\sqrt{9}\\\\=22\times 3=66[/tex]

Hence, the value of (f*g)(7) is 66.

Answer:

6 years

Step-by-step explanation:

A parent increases a child’s monthly allowance by 20% each year. If the allowance is $8 per month now. This is an exponential function, An exponential function is given by:

[tex]y=ab^x[/tex]

Let x be the number of years and y be the allowance. The initial allowance is $8, this means at x = 0, y = 8

[tex]y=ab^x\\8=ab^0\\a=8[/tex]

Since it increases by 20% each year, i.e 100% + 20% = 1 + 0.2 = 1.2. This means that b = 1.2

Therefore:

[tex]y=ab^x\\y=8(1.2^x) \\[/tex]

To find the number of years will it take to reach $20 per month, we substitute y = 20 and find x

[tex]20=8(1.2)^x\\20/8=1.2^x\\1.2^x=2.5\\Taking \ natural\ log\ of \ both\ sides:\\ln(1.2^x)=ln2.5\\xln(1.2)=0.9163\\x=0.9163/ln(1.2)\\x=5.026[/tex]

x = 6 years to the nearest year

Answer:

5 years

Step-by-step explanation:444

9514 1404 393Answer:

  C) Rectangle

Step-by-step explanation:

In general, the vertical cross section of a "right" cylinder will be a rectangle. In some special cases, it may be a square.

Each intersection of the plane with the curved surface is a line, not a curve, so the shape cannot be a circle or ellipse.

Answer:

± 5

Step-by-step explanation:

2x/-5 = -10/x

2x^2 = 50

x^2 = 25

x = ± 5

Answer:

x=5

Step-by-step explanation:

Start with writing it like 2x/-5= -10/x

Then cross multiply: 2[tex]x^{2}[/tex]= 50

Divide by 2: [tex]x^{2}[/tex]=25

Square root of 25: 5

x=5

https://www.chegg.com/homework-help/questions-and-answers/contractor-susan-meyer-haul-gravel-three-building-sites-purchase-much-18-tons-gravel-pit-n-q8579741

9514 1404 393

Answer:

  B B C C A A

Step-by-step explanation:

If we number the equations 1 to 6 left to right, then we have ...

Answer:

-11.2 pounds

Step-by-step explanation:

It is given that,

Shawna finds a study of American men that has an equation to predict weight (in pounds) from  height (in inches):

y = -210 + 5.6x

Height of Shawna's dad is 72 inches

Weight is 182 pounds

We need to find the residual of weight and height for Shawna's dad.

Predicted weight of 72 inches men,

y' = -210 + 5.6(72)

y' = 193.2 pounds

So, residual is :

Y = 182 - 193.2

Y = -11.2 pounds

So, the residual of weight and height for Shawna's dad is -11.2 pounds.

Answer:

-11.2 pounds

Step-by-step explanation:

Got it right on the test.

Answer:

9  3  -7  -13

4  -4  11  8

0  9  2  -4

Step-by-step explanation:

9  3  -7  -13

4  -4  11  8

0  9  2  -4

Answer: 9  3  -7  -13

4  -4  11  8

0  9  2  -4

Step-by-step explanation:

Step-by-step explanation:

[tex]{ \bf{( \frac{ - 10 {a}^{3} {b}^{5} \times 6 {a}^{6} {b}^{2} }{ {12a}^{9} {b}^{5} } ) {}^{3} }} \\ \\ = { \sf{( \frac{ - 60 {a}^{9} {b}^{7} }{12 {a}^{9} {b}^{5} } ) {}^{3} }} \\ \\ = { \sf{(5 {b}^{2}) {}^{3} }} \\ = { \sf{125 {b}^{5} }}[/tex]

Answer:

[tex]\frac{98p^{6}}{q}[/tex]

Step-by-step explanation:

Distribute the exponents

[tex](\frac{(7^{-2}p^{-6}q^{-8})}{2q^{-9}} )^{-1}[/tex]

[tex](\frac{q}{98p^{6}} )^{-1}[/tex]

Distribute the -1

[tex]\frac{98p^{6}}{q}[/tex]

Answer:

Step-by-step explanation:

Second and Third which gives in total:

This is under 1/2 and greater than Crew.

Step-by-step explanation:

はい、両側を削除して、3を掛けて7にします

Step-by-step explanation:

Given:

3n = 21

if we multiply both sides by 1/3, we will get:

3n = 21

3n x (1/3)= 21 x (1/3)

3n/3 = 21/3

n = 21/3

n = 7

Hence we can indeed solve for n by multiplying both sides by (1/3)

Answer:

[tex]\displaystyle \left(\frac{-(m^{2}-1)\, x + 2\, m\, y - 2\, m \, c}{m^{2} + 1},\, \frac{(m^{2} - 1)\, y + 2\, m \, x + 2\, c}{m^{2} + 1}\right)[/tex].

Step-by-step explanation:

Consider the line that is perpendicular to [tex]y = m\, x + c[/tex] and goes through [tex](x,\, y)[/tex].

Both [tex](x,\, y)[/tex] and the reflection would be on this new line. Besides, the two points would be equidistant from the intersection of this new line and line [tex]y = m\, x + c[/tex].

Hence, if the vector between [tex](x,\, y)[/tex] and that intersection could be found, adding twice that vector to [tex](x,\, y)\![/tex] would yield the coordinates of the reflection.

Since this new line is perpendicular to line [tex]y = m\, x + c[/tex], the slope of this new line would be [tex](-1/m)[/tex].

Hence, [tex]\langle 1,\, -1/m\rangle[/tex] would be a direction vector of this new line.

[tex]\langle m,\, -1\rangle[/tex] (a constant multiple of [tex]\langle 1,\, -1/m\rangle[/tex] would also be a direction vector of this new line.)

Both [tex](x,\, y)[/tex] and the aforementioned intersection are on this new line. Hence, their position vectors would differ only by a constant multiple of a direction vector of this new line.

In other words, for some constant [tex]\lambda[/tex], [tex]\langle x,\, y \rangle + \lambda\, \langle m,\, -1 \rangle = \langle x + \lambda \, m,\, y - \lambda \rangle[/tex] would be the position vector of the reflection of [tex](x,\, y)[/tex] (the position vector of [tex](x,\, y)\![/tex] is [tex]\langle x,\, y \rangle[/tex].)

[tex]( x + \lambda \, m,\, y - \lambda )[/tex] would be the coordinates of the intersection between the new line and [tex]y = m\, x + c[/tex]. [tex]\lambda\, \langle m,\, -1 \rangle[/tex] would be the vector between [tex](x,\, y)[/tex] and that intersection.

Since that intersection is on the line [tex]y = m\, x + c[/tex], its coordinates should satisfy:

[tex]y - \lambda = m\, (x + \lambda \, m) + c[/tex].

Solve for [tex]\lambda[/tex]:

[tex]y - \lambda = m\, x + m^{2}\, \lambda + c[/tex].

[tex]\displaystyle \lambda = \frac{y - m\, x - c}{m^{2} + 1}[/tex].

Hence, the vector between the position of [tex](x,\, y)[/tex] and that of the intersection would be:

[tex]\begin{aligned} & \lambda\, \langle m,\, -1 \rangle \\= \; & \left\langle \frac{m\, (y - m\, x - c)}{m^{2} + 1},\, \frac{(-1)\, (y - m\, x - c)}{m^{2} + 1}\right\rangle \\ =\; &\left\langle \frac{-m^{2}\, x + m\, y - m\, c }{m^{2} + 1},\, \frac{-y + m\, x + c}{m^{2} + 1}\right\rangle \end{aligned}[/tex].

Add twice the amount of this vector to position of [tex](x,\, y)[/tex] to find the position of the reflection, [tex]\langle x,\, y \rangle + 2\, \lambda \,\langle m,\, -1 \rangle[/tex].

[tex]x[/tex]-coordinate of the reflection:

[tex]\begin{aligned} & x + 2\, \lambda\, m \\ = \; & x + \frac{-2\, m^{2}\, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1} \\ =\; & \frac{-(m^{2} - 1) \, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].

[tex]y[/tex]-coordinate of the reflection:

[tex]\begin{aligned} & y + (-2\, \lambda)\\ = \; & y + \frac{- 2\, y + 2\, m\, x + 2\, c}{m^{2} + 1} \\ =\; & \frac{(m^{2} - 1) \, y + 2\, m \, x + 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].

Answer:

-1/4

Step-by-step explanation:

f(x) = 1/(x+1)

f(a) = 1/(a+1)

f'(a) = {(a+1)×d/da (1) - d/da (a+1) × 1}/(a+1)²

f'(a) = {(a+1)×0 - 1×1}/(a+1)²

f'(a) = (0-1)/(a²+2a+1)

f'(a) = -1/(1+2a+a²)

putting a = 1

f'(a) = -1/(1+2+1)

f'(a) = -1/4

Answer:

20

Step-by-step explanation:

We can set up a percentage proportion to find the value of x.

[tex]\frac{12}{x} = \frac{60}{100}[/tex]

Now we cross multiply:

[tex]100\cdot12=1200\\\\1200\div60=20[/tex]

Hope this helped!

Answer:

B. 259

Step-by-step explanation:

6^(i - 1) for i = 1 to 4

sum = 6^(1 - 1) + 6^(2 - 1) + 6^(3 - 1) + 6^(4 - 1) =

= 6^0 + 6^1 + 6^2 + 6^3

= 1 + 6 + 36 + 216

= 259

Answer: B. 259

Answer:

Step-by-step explanation:

Given the sequence of interest earned by Marius on his savings account as

200, 208, 216.30, 225, …, the sequence of interest forms a geometric sequence since they have a common ratio.

[tex]r =\frac{T_2}{T_1}= \frac{T_3}{T_2}= \frac{T_4}{T_3}\\ r =\frac{208}{200}= \frac{216.30}{208}= \frac{225}{216.30} \approx 1.04[/tex]

To get how much total interest will Marius have earned by the 30th year the account is active, we will find the sum of the first 30 terms of the geometric sequence as shown.

[tex]S_n =\frac{ a(r^n-1)}{r-1} \ for \ r> 1\\ \\\\ n = 30, a = 200, r = 1.04\\S_{30} = \dfrac{ 200(1.04^{30}-1)}{1.04-1}\\\\S_{30} = \dfrac{ 200(3.243-1)}{0.04}\\\\S_{30} = \dfrac{ 200(2.243)}{0.04}\\\\S_{30} = \dfrac{ 448.6}{0.04}]\\\\S_{30} = 11,215[/tex]

Hence total interest that Marius will earn by the 30th year the account is active is 11,215.

the correct answer is

S30= 200(1-1.04^n)/1-1.04

i took the test

Answer: 50

Step-by-step explanation:

f(x) = 6x-4 and g(x) = x^2

f(g(3)) means what is the value of the function f when it is evaluated at the value of g(3).

So g(x) is x^2 so g(3) is 3^2 = 9

Therefore we put 9 in for f(g(3))= f(9) = 6(9) - 4 = 54 - 4 = 50