PLEASE HELP MEEEEEEEEEEEEEEE

Answer: Option B, 16/81

Step-by-step explanation:

So we have 4 prisoners, they will roll a fair six side die and the product of the four rolls must NOT be a multiple of 3.

We know that every integer number can be "decomposed" into a product of prime numbers.

Then a number N,  that is divisible by 3, can be written as:

N = 3*k

Where k is another integer.

Here we will have a product of 4 numbers, each of them are in between 1 and 6.

Now, if only one of the prisoners rolls a 3, then the product of the rolls will always be a multiple of 3. And if one of the rolls is 6 the same will happen, because 6 = 3.2

Then the probability of surviving is when in none of the four rolls we have a 3 or a 6.

Then we must have a 1, 2, 4 or 5.

The probability of 4 outcomes out of 6, is:

P = 4/6.

But we have 4 rolls, so we have that probability four times, and the joint probability will be equal to the product of the probabiliities for each roll, then the probability of surviving is:

P = (4/6)^4 = (2/3)^4 = 16/81

Answer:

16

Step-by-step explanation:

Answer:

x( x-4)(x+2)

Step-by-step explanation:

x^3-2x^2-8x

First factor out the greatest common factor x

x( x^2 -2x -8)

What 2 numbers multiply to -8 and add to -2

-4*2 = -8

-4+2 = -2

x( x-4)(x+2)

Answer:

239=5

478=10

956=20

Step-by-step explanation:

Gianna's car can travel 478 mi with 10 gallons of gas

so, 47.8 mi with 1 gallon

by dividing 239 by 47.8 miles/gallon we get the answer 5 miles.

if we multiply 20 gallons by 47.8 mi/gallon #e get the answer 956 miles.

easy weasy

HELLO THERE

3 and 4 is the answer

I hope I helped

Answer:

Reserve rate = 9%

Step-by-step explanation:

Reserve ratio/rate is the percentage of deposits which commercial banks are required to keep as cash, as directed by the central banks.

first, let us calculate the reserve amount as follows:

Reserve = Deposit - (free amount to lend out)

Reserve = 28,000 - 25,480 = $2,520

[tex]Reserve\ rate = \frac{Reserves}{Deposits} \times100\\Reserve\ rate = \frac{2520}{28000} \times100\\=\frac{252000}{28000} =9\%[/tex]

Therefore the reserve rate = 9%

Answer:

(-4,-9)

Step-by-step explanation:

multiply (a,b)

Answer:

18.711

Step-by-step explanation:

Volume = L * W * H

V = 1.08 * 5.25 * 3.3

1.08 * 5.25 = 5.67

5.67 * 3.3 =

V = 18.711

Answer:

70

Step-by-step explanation:

1+9+40-40+40+10*2

----------------------- 20

10+40-40+40+20

50 (-40+40 cancels out to 0) +20

50+20= 70

(Following PEMDAS)

Multiply, add, subtract.

if you were to instead go through it left to right, you would get 120, which is incorrect.

The percentage of your savings that I use is 60%

This shows that the amount of money the organization will raise in total is $25,000.

1) Given

Total amount saved = $4500

Amount used = $2,700

Percentage of money used = Amount used/Total amount saved × 100%

[tex]Percentage \ of \ money \ used = \frac{2700}{4500} \times 100\\Percentage \ of \ money = \frac{27}{45} \times 100\\Percentage \ of \ money \ used = \frac{2700}{45} \\Percentage \ of \ money \ used = 60 \%[/tex]

Hence the percentage of your savings that I use is 60%

2) Let the amount of money the organization will raise in total be x

Since the 45% of the money they raise represents $11,250, hence:

[tex]45\% \ of \ x = \$11,250\\0.45x = 11,250\\x = \frac{11250}{0.45}\\ x = 25,000[/tex]

This shows that the amount of money the organization will raise in total is $25,000

Learn more on percentages here: https://brainly.com/question/18811795

Answer:

Below

Step-by-step explanation:

First let's find the equation of the doted line.

Notice that the line is crossing these points:

● (0,1)

● (1,2)

The equation of the line has the following form:

● y = ax+c

C is the y-intercept wich is given by the output of 0.

Notice that the output of 0 is 1.

● y = ax+1

● a = rise / run = (2-1)/(1-0) = 1

So y = x + 1

■■■■■■■■■■■■■■■■■■■■■■■■■■

Notice that the line divide the plan into 2 areas.

● y > x+1 => x+1-y < 0

● y < x+1 => x+1 -y > 0

To khwo wich one that represent the shaded area take a point and replace x and y by its coordinates

● (-1,2)

● -1+1-2 = 0-2 = -2

It is a negative value so the inequality is

● y > x+1

Answer:

bonds: $65,000

cd's: $30,000

stocks: $20,000

Step-by-step explanation:

b + c + s = 115000

0.045b + 0.0325c + 0.082s = 5540

b = c + 35000

b = 65,000

c = 30,000

s = 20,000

Answer:

73%

Step-by-step explanation:

Answer:

x  ≤ 9

Step-by-step explanation:

x − 6 ≤ 3

Add 6 to each side

x − 6+6 ≤ 3+6

x  ≤ 9

Answer:

x ≤ 9

I hope this helps!

Answer:

[tex]\text{Critical Region} = z<-1.96\ \text{or}\ z>1.96[/tex]

Step-by-step explanation:

A test for the difference between two population means is to be performed.

As the population variances are known, the z-test will be used.

The hypothesis can be defined as follows:

H₀: μ₁ = μ₂ vs. Hₐ: μ₁ ≠ μ₂

Assume that the significance level of the test is, α = 0.05.

The critical region can be defined as follows:

The critical value of z for α = 0.05 is:

[tex]z_{\alpha/2}=z_{0.05/2}=z_{0.025} =-1.96\\\\z_{1-\alpha/2}=z_{1-0.05/2}=z_{0.975} =1.96[/tex]

Use a z-table.

[tex]\text{Critical Region} = z<-1.96\ \text{or}\ z>1.96[/tex]

Answer:

y=-6x

Step-by-step explanation:

ccccccccccccccccccccccc

Answer:

Option B

-13°c-2°c= 15°c

hope it helps

Answer:

44°

Step-by-step explanation:

Given:

m<DOC = 44°

m<COB = 80°

Required:

Angle measure of arc DC

SOLUTION:

A central angle is said to be equal to the angle measure of the arc it intercepts or corresponds with. Therefore, angle measure of arc DC = m<DOC.

measure of arc DC = 44°

Answer:

- At any time t, the population is:

P = 375t² + 3000t + 1000

- At time t = 3 days, the population is:

P = 13,375

Step-by-step explanation:

Given the rate of change of the population of bacteria as:

dP/dt = 3000/(1 + 0.25t)

we need to rewrite the given differential equation, and solve.

Rewriting, we have:

dP/3000 = (1 + 0.25t)dt

Integrating both sides, we have

P/3000 = t + (0.25/2)t² + C

P/3000 = t + 0.125t² + C

When t = 0, P = 1000

So,

1000/3000 = C

C = 1/3

Therefore, at any time t, the population is:

P/3000 = 0.125t² + t + 1/3

P = 375t² + 3000t + 1000

At time t = 3 days, the population is :

P = 375(3²) + 3000(3) + 1000

= 3375 + 9000 + 1000

P = 13,375

Step-by-step explanation:

Pls Mark me

Answer:

2

Step-by-step explanation:

The term 3x² has 2 as an exponent, the correct option is C.

Exponents are the base raised by power, it is written in the superscript of a number.

The expression is  3x² +y-5

The term 3x² has 2 as an exponent.

Therefore, the correct option is C.

The missing options are

A.3x2

B. y

A 2

C. -5

D. None of these choices are correct.

To know more about Exponents

https://brainly.com/question/5497425

#SPJ2

Answer:

d

Step-by-step explanation:

[tex]\\ \sf\longmapsto -4-(-9)[/tex]

[tex]\\ \sf\longmapsto -4+9[/tex]

Option C is correct .

Note:-

Answer:

C) 2

Step-by-step explanation:

From the point (2,0), the next point on the graph is up 2, right 1, meaning that the slope is a positive 2.

Answer:

.87

Step-by-step explanation:

She gets 13 off so 100-13 =87

She will pay 87%

Multiply by .87

Kylie must multiply the price by 0.87 to get the discounted price.

Given that,
Kylie has a loyalty card good for a 13% discount at her local hardware store. What number should she multiply the prices on the tags by to find the price she would have to pay, is to be determined.

The percentage is the ratio of the composition of matter to the overall composition of matter multiplied by 100.

Here,
let the price be x,
Now,
According to the question,
discounted price = x - 13% of x
Discounted price = x - 0.13x
Discounted price = 0.87 x
The coefficient of the x represents the multiplication factor for Kylie.

Thus, Kylie must multiply the price by 0.87 to get the discounted price.

Learn more about percentages here:

brainly.com/question/13450942

#SPJ2

Answer:

[tex]\approx \bold{6544\ in^3/sec}[/tex]

Step-by-step explanation:

Given:

Rate of change of radius of cylinder:

[tex]\dfrac{dr}{dt} = +7\ in/sec[/tex]

(This is increasing rate so positive)

Rate of change of height of cylinder:

[tex]\dfrac{dh}{dt} = -6\ in/sec[/tex]

(This is decreasing rate so negative)

To find:

Rate of change of volume when r = 20 inches and h = 16 inches.

Solution:

First of all, let us have a look at the formula for Volume:

[tex]V = \pi r^2h[/tex]

Differentiating it w.r.to 't':

[tex]\dfrac{dV}{dt} = \dfrac{d}{dt}(\pi r^2h)[/tex]

Let us have a look at the formula:

[tex]1.\ \dfrac{d}{dx} (C.f(x)) = C\dfrac{d(f(x))}{dx} \ \ \ (\text{C is a constant})\\2.\ \dfrac{d}{dx} (f(x).g(x)) = f(x)\dfrac{d}{dx} (g(x))+g(x)\dfrac{d}{dx} (f(x))[/tex]

[tex]3.\ \dfrac{dx^n}{dx} = nx^{n-1}[/tex]

Applying the two formula for the above differentiation:

[tex]\Rightarrow \dfrac{dV}{dt} = \pi\dfrac{d}{dt}( r^2h)\\\Rightarrow \dfrac{dV}{dt} = \pi h\dfrac{d }{dt}( r^2)+\pi r^2\dfrac{dh }{dt}\\\Rightarrow \dfrac{dV}{dt} = \pi h\times 2r \dfrac{dr }{dt}+\pi r^2\dfrac{dh }{dt}[/tex]

Now, putting the values:

[tex]\Rightarrow \dfrac{dV}{dt} = \pi \times 16\times 2\times 20 \times 7+\pi\times 20^2\times (-6)\\\Rightarrow \dfrac{dV}{dt} = 22 \times 16\times 2\times 20 +3.14\times 400\times (-6)\\\Rightarrow \dfrac{dV}{dt} = 14080 -7536\\\Rightarrow \dfrac{dV}{dt} \approx \bold{6544\ in^3/sec}[/tex]

So, the answer is: [tex]\approx \bold{6544\ in^3/sec}[/tex]

Answer:

B

Step-by-step explanation:

Use the quadractic equation, x=-b+or-sqrtb^2-4ac/2a, then simplify.

I'm really sorry that it looks messy, I don't know how to make my text look better :(

9514 1404 393

Explanation:

1. End behavior is the behavior of the function when the value of the independent variable gets large (or otherwise approaches the end of the domain). There are generally four kinds of end behavior:

Of these, behavior 2 will ultimately look like one of the others.

For polynomials, the function will always approach ±∞ as the independent variable approaches ±∞. Whether the signs of the infinities agree or not depends on the even/odd degree of the polynomial, and the sign of its leading coefficient.

For exponential functions, the end behavior is a horizontal asymptote in one direction and a tending toward ±∞ in the other direction.

For trig functions sine and cosine, the end behavior is the same as the "middle" behavior: the function oscillates between two extreme values.

For rational functions (ratios of polynomials), the end behavior will depend on the difference in degree between numerator and denominator. If the degree of the denominator is greater than or equal to that of the numerator, the function will have a horizontal asymptote. If the degree of the numerator is greater, then the end behavior will asymptotically approach the quotient of the two functions—often a "slant asymptote".

__

2. A polynomial inequality written in the form f(x) ≥ 0, or f(x) > 0, will be solved by first identifying the real zeros of the function f(x), including the multiplicity of each. For positive values of x greater than the largest zero, the sign of the function will match the sign of the leading coefficient. The sign will change at each zero that has odd multiplicity, so one can work right to left to identify the sign of the function in each interval between odd-multiplicity zeros.

The value of the function will be zero at each even-multiplicity zero, but will not change sign there. Obviously, the zero at that point will not be included in the solution interval if the inequality is f(x) > 0, but will be if it is f(x) ≥ 0. Once the sign of the function is identified in each interval, the solution to the inequality becomes evident.

As a check on your work, you will notice that the sign of the function for x > max(zeros) will be the same as the sign of the function for x < min(zeros) if the function is of even degree; otherwise, the signs will be different.

The solution to a polynomial inequality is a set of intervals on the real number line. The solution to a polynomial equation is a set of points, which may be in the complex plane.

__

3. A composite function is a function of a function, or a function of a composite function. For example f(g(x)) is a composite function. The composition can be written using either of the equivalent forms ...

  [tex](f\circ g)(x)\ \Leftrightarrow\ f(g(x))[/tex]

It can be easy to confuse an improperly written composition operator with a multiplication symbol, so the form f(g(x)) is preferred when the appropriate typography is not available.

When simplifying the form of a composition, the Order of Operations applies. That is, inner parenthetical expressions are evaluated (or simplified) first. As with any function, the argument of the function is substituted wherever the independent variable appears.

For example, in computing the value f(g(2)), first the value of g(2) is determined, then that value is used as the argument of the function f. The same is true of other arguments, whether a single variable, or some complicated expression, or even another composition.

Note that the expression f(g(x)) is written as the composition shown above. The expression g(f(x)) would be written using the composition operator with g on the left of it, and f on the right of it:

  [tex](g\circ f)(x)\ \Leftrightarrow\ g(f(x))[/tex]

That is, with respect to the argument of the composition, the functions in a composition expression are right-associative. For example, ...

  for h(x)=2x+3, g(x)=x^2, f(x)=x-2 we can evaluate f(g(h(x)) as follows:

  f(g(h(x)) = f(g(2x+3) = f((2x+3)^2) = (2x+3)^2 -2

It should be obvious that g(h(f(x)) will have a different result.

  g(h(f(x)) = g(h(x-2)) = g(2(x-2)+3) = (2(x-2)+3)^2

Answer:

[tex] \boxed{\sf Instantaneous \ velocity \ (v) = -3} [/tex]

Given:

Relation between position of an object at time t is given by:

s(t) = -9 - 3t

To Find:

Instantaneous velocity (v) at t = 8

Step-by-step explanation:

To find instantaneous velocity we will differentiate relation between position of an object at time t by t:

[tex] \sf \implies v = \frac{d}{dt} (s(t))[/tex]

[tex] \sf \implies v = \frac{d}{dt} ( - 9 - 3t)[/tex]

Differentiate the sum term by term and factor out constants:

[tex] \sf \implies v = \frac{d}{dt} ( - 9) - 3 (\frac{d}{dt} (t))[/tex]

The derivative of -9 is zero:

[tex] \sf \implies v = - 3( \frac{d}{dt} (t)) + 0[/tex]

Simplify the expression:

[tex] \sf \implies v = - 3( \frac{d}{dt} (t))[/tex]

The derivative of t is 1:

[tex] \sf \implies v = - 3 \times 1[/tex]

Simplify the expression:

[tex] \sf \implies v = - 3 [/tex]

(As, there is no variable after differentiating the relation between position of an object at time t by t so at time t = 8 is of no use.)

So,

Instantaneous velocity (v) at t = 8 is -3

Answer:

c is the answer

Step-by-step explanation:

-3h = 31

-9h-12h = -3h

54-23= 31

Answer:

[tex]\boxed{C. -3h = 31}[/tex]

Step-by-step explanation:

Hey there!

9h - 12h = 54 - 23

Simplify

-3h = 31

C. -3h = 31

Hope this helps :)

Answer:

Only one solution.

Step-by-step explanation:

y = 3x +2

y -2x =4

y - 2x = 4

=> y = 2x +4

y = 3x + 2

y = 2x + 4

Since both equations are not the same, so the answer cannot be "infinitely many solutions".

They both intersect each other 1 point, so it cannot be "no solutions".

So the answer is "Only 1 solution".