PLEASE HELP NEED ANSWERS NOW! Time-Distance Graph
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Answer:

Explanation:

Can you please place the square roots in a proper manner so I may assist you?

Answer:

The displacement of the driver is 194400m in the east direction

Explanation:

In physics, the displacement of a body is the distance the body travels in a specified direction.

We are told that the trucker is driving east on a perfectly straight highway. From this, we know that his direction is East. The thing left will be to find the distance travelled within 2 hours.

We can convert the time (2 hours) to seconds by multiplying it by 3600

2 hours = 7200 seconds

The distance travelled will be obtained by a product of truck's speed and the time travelled.

distance = 27m/s X 7200 s = 194400m

Therefore the displacement of the driver is 194400m in the east direction

Answer:

hello your question is incomplete attached below is the remaining part and the solution

Explanation:

The accelerations at points 1,2,3 is zero and this is because the velocities at points 1,2,3 are constants.  attached below is the velocity vector diagram and the acceleration vectors

Wave speed = (wavelength) x (frequency)

Wave speed = (0.5 m) x (2 /sec)

Wave speed = 1 m/s

Answer:

George Washington

Explanation:

The image of the famous first President of the United States-George Washington (from  1789 to 1797) is found on every $1 bill. George Washington's image began to be found on the $1 bill in 1869.

Answer:

a. 3 s.

Explanation:

Given;

angular acceleration of the wheel, α = 4 rad/s²

time of wheel rotation, t = 4 s

angle of rotation, θ = 80 radians

Apply the kinematic equation below,

[tex]\theta = \omega_1 t \ + \ \frac{1}{2} \alpha t^2\\\\80 = 4\omega_1 + \frac{1}{2}*4*4^2\\\\80 = 4\omega_1 + 32\\\\ 4\omega_1 = 48\\\\ \omega_1 = \frac{48}{4}\\\\ \omega_1 = 12 \ rad/s[/tex]

Given initial angular velocity, ω₀ = 0

Apply the kinematic equation below;

[tex]\omega_1 = \omega_o + \alpha t_1\\\\12 = 0 + 4t\\\\4t = 12\\\\t = \frac{12}{4}\\\\t = 3 \ s[/tex]

Therefore, the wheel had been in motion for 3 seconds.

a. 3 s.

Answer:

0.995*c= 2.98*10^8m/s

Explanation:

Using

E= mc²

10.5 mc² = mc²/√1-v²/c²

So

1-v²/c²=( 1/10.5)²

V= √1-0.009c

V= 0.995 x 3E8m/s

= 2.98*10^8m/s

Answer:

Weak attraction will be observed

Explanation:

This is because the charge induction is less than the insulating rod, and a postive charge is induced when a a negative sphere is placed closed to the end of the rod

Answer:

Only the perpendicular component of gravity is responsible for the rotation because wind points toward the pivot.

Explanation:

Answer:

1.5 Ampere

Explanation:

The formula is V=IR

so now we can derive out the formula which is

I =V

R

I = 6

4

I = 1.5 Ampere

Answer:

B

Explanation:

The enzime's active site bindes to the substrate.... when an enzime binds to a substrate it forms a enzime-substrate complex

When an enzyme and a substrate interact at an active site, the products are bound irreversibly. Therefore, option B is correct.

Enzymes can be described as proteins that act as biological catalysts by accelerating reactions. The enzymes may act on the molecules called substrates, and the enzyme changes the substrates into different molecules known as products.

All metabolic processes require enzyme catalysis to occur at rates fast enough to sustain life. Metabolic pathways will depend upon enzymes to catalyze each step.

Enzymes catalyze more than 5,000 biochemical reaction types. Enzymes enhance reaction rates by lowering their activation energy. Some enzymes make their conversion of substrate to product occurs.

Enzymes are much larger than substrates, they can have 62 amino acid residues to over 2,500 residues in the animal fatty acid synthase. The catalytic site is located next to binding sites where residues are oriented to the substrates. The catalytic site and binding site compose the active site.

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Answer:

4 seconds

Explanation:

Given:

v₀ = 20 m/s

v = 0 m/s

a = -5 m/s²

Find: t

v = at + v₀

0 m/s = (-5 m/s²) t + 20 m/s

t = 4 s

Answer:

1500 m/s squared

Hope this helps :)

Explanation:

Answer:

The path difference will be zero.

Explanation:

Given that,

In a young's double-slit experiment the center of a bright fringe occurs wherever waves from the slits differ in the distance.

Suppose, we find the multiple of wavelength

In young's double slit experiment,

We need to calculate the multiple of wavelength

Using formula of path difference

[tex]\Delta x=d\sin\theta[/tex]....(I)

[tex]d\sin\theta=m\lambda[/tex]

Where, m = fringe number

[tex]\lambda[/tex] = wavelength

For center of a bright fringe ,

m = 0

Put the value into the formula

[tex]d\sin\theta=0\times\lambda[/tex]

[tex]d\sin\theta=0[/tex]

Put the value in equation (I)

[tex]\Delta x=0[/tex]

Hence, The path difference will be zero.

Answer:

F=5.7×10⁻⁶

Explanation:

Not knowing a formula outright, I decided to follow the units of some relationships I did know. Radiation pressure is defined as force per area and also intensity divided by velocity (the speed of light here of course). Breaking intensity down into power per area and isolating force gave me the relationship F=(Power/Velocity),where power is given and the velocity is a constant.

My work is in the attachment, where I double checked the units too, comment with any questions.

The force exerted by the beam on a completely absorbing target is of 0.0120 N.

Given data:

The power of laser beam is, P = 1700 W.

The wavelength of light emitted from the laser is, [tex]\lambda = 700 \;\rm nm[/tex].

The diameter of the beam is, [tex]d =3.00 \;\rm mm =3.00 \times 10^{-3} \;\rm m[/tex].

When the laser beam strikes the target, then the force exerted by the laser beam on the target is equal to the product of the laser power and the area of projection of beam.

Then the expression is,

[tex]P = \dfrac{F}{A}\\\\F = P \times \dfrac{\pi}{4} d^{2}[/tex]

Solving as,

[tex]F = 1700 \times \dfrac{\pi}{4} \times (3.00 \times 10^{-3})^{2}[/tex]

F = 0.0120 N

Thus, we can conclude that the force exerted by the beam on a completely absorbing target is of 0.0120 N.

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Answer:

We are given that

The

Mass of person = 135lbm

Weight of person on earth will be

= mass x gravity constant

= 135lbm x 32.174 ft/s2

=4343.49 lbm-ft/s2 x 1 poundal-s2/lbm-ft

= 4343.49 poundal

Again we are given that

Mass of person = 135 lbm

But here remember Mass remains the same

So

Weight of person on moon will be

mass x gravity constant on moon

= 135 lbm x 32.174 ft/s2 x 1/6

= 723.9 lbm-ft/s2 x 1 poundal-s2/lbm-ft

= 723.9poundal

But we know that

1 ft slug / lbf-s2 = 32.174 ft lbm/ lbf-s2

So

1 slug = 32.174 lbm

So then the Mass of person

= 135lbm x 1slug/32.174 lbm

=4.2slugs

So finally

Weight = 405 poundals is same as

405 lbm-ft/s2

So

Mass = 35 slug x 32.174 lbm/slug = 1126.09 lbm

Acceleration rate = weight /mass

= (405 lbm-ft/s2) / (1126.09 lbm)

= 0.3597ft/s2 x 0.305m/ft

= 1.179 m/s²

Answer:

Uninvolved (provide little guidance , nuturing and attention) that causes to grow up to be emotionally withdrawn, distant and lacking in curiosity.

Explanation:

Answer: heat loss by conduction

Explanation:

As the thermal energy from our body is flowing to the sponge, our body is losing heat.

Answer:

Explanation:

Temperature of air = 18°C = 273 + 18 = 291 K .

volume = 500 cc = 0 .5 litre .

pressure = one atmosphere ( atm) .

From gas equation , we can calculate this volume at NTP  as follows.

volume = .5 x ( 273 / 291  ) litre

= 0.469 litre .

In any gas at NTP , 22.4 litre contains 6.02 x 10²³ molecules

.469 litre will contain  6.02 x 10²³ x .469 / 22.4 molecules

= 126 x 10²⁰ molecules .

b )

one mole = 6.02 x 10²³ molecules

6.02 x 10²³ molecules  has weight of 28.96 grams

126 x 10²⁰ molecules has weight of 28.96 x 126 x 10²⁰ / 6.02 x 10²³ grams

= .606 gram .

c )

volume of all the air in the atmosphere = volume of sphere

=  4 / 3 x π  x R³

= ( 4 / 3) x 3.14 x (999.5 x 10³ )³ m³

= 4.18 x 10¹⁸ m³

density of air = 1.225 kg / m³

mass of air = 1.225 x 4.18 x 10¹⁸ kg

= 5.12 x 10¹⁸ kg

d )

volume of air inhaled by 7 billion people

= . 5 x 7 x 10⁹ litre

= 3.5 x 10⁶ m³ .

Total volume of air in atmosphere = 4.18 x 10¹⁸ m³

required percentage

= 3.5 x 10⁶ x 100 /  4.18 x 10¹⁸

= .8373 x 10⁻¹⁰ % .

Explanation:

HERACLITUS ALSO SPELLED HERADEITUS, [ BORN C.540 bce, EPHESUS, ANATOLIA [ NOW SELCUK, TURKEY] - DIED C.486 ] GREEK PHILOSOPHER REMEMBERED FOR HIS COSMOLOGY, IN WHICH FIRE FORMS THE BASIC MATERIAL PRINCIPLE OF AN ORDERLY UNIVERSE . LITTLE IS KNOWN ABOUT HIS LIFE, AND THE ONE BOOK HE APPARENTLY WROTE IS LOST.

Explanation:

Given:

v₀ = 10 m/s

v = 20 m/s

t = 60 s

Find: v_avg and Δx

v_avg = ½ (v + v₀)

v_avg = ½ (20 m/s + 10 m/s)

v_avg = 15 m/s

Δx = v_avg t

Δx = (15 m/s) (60 s)

Δx = 900 m

Answer:

770m/s

Explanation:

caculation using one of the newton law of motion

Answer:

Total distance covered (scalar quantity) = 23 km

Displacement (vector quantity) = 3 km north from the original starting point

Explanation:

Since he drove 13 km north and then 10 km south, the total distance he cover in his drive was: 13 km + 10 km = 23 km

On the other hand, his displacement was 3 km north from where he started.

Answer:

blindness

Explanation:

got it right

Blindness is not a symptom of strong emotions in this scenario and is denoted as option C.

These are mental states brought on by neurophysiological changes and examples include sad, happy etc.

Blindness is a physical condition which involves impairment of the eyes which is why it was chosen.

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Complete Question

(A) What is the maximum tension possible in a 1.00- millimeter-diameter nylon tennis racket string?

(B) If you want tighter strings, what do you do to prevent breakage: use thinner or thicker strings? Why? What causes strings to break when they are hit by the ball?

The  tensile  strength of the nylon string is  [tex]600*10^{6} \  N/m^2[/tex]

Answer:

A

   T = 471.3 \  N

B

 To prevent breakage the thickness of the string is increased

  String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension

Explanation:

From the question we are told that

     The  diameter is  [tex]d =  1.00 \ mm  =  0.001 \  m[/tex]  

       The  tensile strength of the nylon string is [tex]\sigma =  600 *10^{6} \  N/m^2[/tex]

  Generally the radius is mathematically evaluated as

     [tex]r=  \frac{d}{2}[/tex]

=>    [tex]r =  \frac{0.001}{2}[/tex]

=>     [tex]r =  0.0005 \  m[/tex]

The cross sectional area is mathematically represented as

     [tex]A = \pi  r^2[/tex]

=>   [tex]A =  3.142  *  (0.005)^2[/tex]

=>    [tex]A =  7.855*10^{-7}\  m^2[/tex]

Generally the tensile strength of nylon is mathematically represented as

      [tex]\sigma  = \frac{T}{ A }[/tex]

Where T is the tension on the maximum tension on the string

 So  

           [tex]T =  \sigma  *  A[/tex]

=>          [tex]T =  600*10^{6} *  7.855*10^{-7}[/tex]

=>         [tex]T = 471.3 \  N[/tex]

Form the equation above  we  see that

        [tex]T  \  \alpha \  A[/tex]

So if the tension is  increased to prevent breakage the thickness of the string is increased(i. e the cross-sectional  area )

String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension

Answer:

16:1

Explanation:

From the question,

Since the voltage of the transformer is increased, then the winding in the secondary coil is greater than the winding in the primary coil

Applying transformer's equation

Vs/Vp = Ns/Np............. Equation 1

Where Vs = Secondary voltage, Vp = primary Voltage, Ns/Np = Ratio of the winding between the secondary coil to the winding in the primary coil.

Given: Vs = 345000 V, Vp = 21600 V

Substitute these values into equation 1

Ns/Np = 345000/21600

Ns/Np = 16:1

Complete Question

Given that average speed is distance traveled divided by time, determine the values of m and n when the time it takes a beam of light to get from the Sun to the Earth (in s) is written in scientific notation. Note: the speed of light is approximately 3.0×108 m/s.

Answer:

The  values of  m and  n is    5 and  2  

Explanation:

From the question we are told that

   The  speed of light is [tex]v  =  3.0 *10^{8} \  m/s[/tex]

Generally the distance between the sun and the earth has a constant value

      [tex]d =  1.5*10^{11} \  m[/tex]

So the time  taken is mathematically evaluated as

        [tex]t =  \frac{1.5*10^{11}}{3.0*10^{8}}[/tex]

         [tex]t =  5.0 *10^{2}[/tex]

Generally scientific notation is represented as

        [tex]m* 10^n[/tex]

So comparing the standard representation of scientific notation and the value obtained we see that

     m =  5  and  n=  2  

Answer:

Z = 530.89 ohms

Explanation:

Given that,

Resistor, R = 40 ohms

Inductor, L = 3 mH

Capacitor, C = 5 μF

We need to find the impedance of the circuit at frequency of 60 Hz. For a series LCR circuit, its impedance is given by the formula as follows :

[tex]Z=\sqrt{R^2+(X_L-X_c)^2} \\\\Z=\sqrt{R^2+(2\pi fL-\dfrac{1}{2\pi fC})^2} \\\\Z=\sqrt{(40)^2+(2\pi \times 60\times 3\times 10^{-3}-\dfrac{1}{2\pi \times 60\times 5\times 10^{-6}})^2} \\Z=530.89\ \Omega[/tex]

So, the impedance of the circuit is 530.89 ohms.

Answer:

E=3V/m

Explanation:

The electric field here is simply the voltage running through the wire divided by its length. (Meaning E is independent of the diameter of the wire.)

Short work is in the attachment.

Answer:

The dimensionality of B is length per cubic time.

Explanation:

Units for displacement and time are length [tex][L][/tex] and time [tex][T][/tex], respectively. Then, formula can be tested for dimensional analysis as follows:

[tex][L] = B\cdot [T]^{3}[/tex]

Now, let is clear [tex]B[/tex] to determine its units:

[tex]B = \frac{[L]}{[T]^{3}}[/tex]

The dimensionality of B is length per cubic time.