PLEASE HELP

Solve the equation for y. Identify the slope and y-intercept then graph the equation.

Y=-3x+1

Y=
M=
B=

Please Include a picture of the graph and show your work if you can

Answers

Answer 1

The equation is already solved for y

It's in y = mx+b form where

m = -3 = slope

b = 1 = y intercept

The graph is shown below. It's a straight line through the two points (0,1) and (1,-2).

Note that (0,1) is the y intercept. We use the slope = -3 = -3/1 to move 3 units down and 1 unit to the right to arrive at (1,-2).

PLEASE HELPSolve The Equation For Y. Identify The Slope And Y-intercept Then Graph The Equation. Y=-3x+1Y=M=B=Please

Related Questions

Julio is paid 1.1 times his normal hourly rate for each hour he works over 28 hours in a
week. Last week he worked 43 hours and earned $631.90.
Enter and solve an equation to find Julio's normal hourly rate, r. Complete the explanation
how you know that your answer is reasonable.
The earnings equation is $631.90 =
Julio's hourly l'ate is $
per hour.
This is reasonable because working 43 hours at a rate of $14 per hour is
43 · 14 = 43(10 + 4) = 430 + 172 =
and $
is close to $631.90.

Answers

Answer:

43-28= 15 extra hours

normal hourly rate = a

extra hourly rate = 1.1a

28a + 15(1.1a) = 631.90

28a + 16.5a = 631.90


The X- and y-coordinates of point P are each to be chosen at random from the set of integers 1 through 10.
What is the probability that P will be in quadrant II ?
О
1/10
1/4
1/2

Answers

Answer:

Ok, as i understand it:

for a point P = (x, y)

The values of x and y can be randomly chosen from the set {1, 2, ..., 10}

We want to find the probability that the point P lies on the second quadrant:

First, what type of points are located in the second quadrant?

We should have a value negative for x, and positive for y.

But in our set;  {1, 2, ..., 10}, we have only positive values.

So x can not be negative, this means that the point can never be on the second quadrant.

So the probability is 0.

An amusement park is open 7 days a week. The park has 8 ticket booths, and each booth has a ticket seller from 10am to 6pm. On average, ticket sellers work 30 hours per week. Write and equation that can be used to find "t", the minimum number of ticket sellers the park needs. show work if possible.

Answers

Answer:

t = (448 hrs/ week) / (30 hrs / week)

Step-by-step explanation:

Number of times park opens in a week = 7

Number of ticket booth = 8

Opening hours = 10am - 6pm = 8 hours per day

Max working hours per ticket seller per week = 30 hours

Therefore each booth works for 8 hours per day,

Then ( 8 * 7) = 56 hours per week.

All 8 booths work for (56 * 8) = 448 hours per week

If Max working hours per ticket seller per week = 30 hours,

Then muninim number of workers required (t) :

Total working hours of all booth / maximum number of working hours per worker per week

t = (448 hrs/ week) / (30 hrs / week)

solve 3/4x+5=-9 please

Answers

Answer:

exact form: x=-56/3

mixed number form: -18 2/3

Solve for x by simplifying both sides of the equation, then isolating the variable.

x=-56/3 or x= - 18.6

find the HCF of 54 and 81 by prime factorization method. pls send the photo​

Answers

3║54, 81

3║18, 27

3║9, 9

3║3, 3

3║1, 1

HCF = 27

Must click thanks and mark brainliest

Answer:

Hello,

Step-by-step explanation:

[tex]\begin{array}{c||c}\begin{array}{c|c}54&2\\27&3\\9&3\\3&3\\1\\\end{array}&\begin{array}{c|c}81&3\\27&3\\9&3\\3&3\\1\\\end{array}\end{array}\\\\54=2^1*3^3\\ 81=3^4\\\\\boxed{HCF(54,81)=3^3=27}\\[/tex]

the area of a rectangular park is 7/8 sqaure mile. the length of the park is 3/4 mile. what is the width of the park?

Answers

Answer:

7/6

Step-by-step explanation:

since the formula of area is length times width,you have to divide the area by the length to find the width

area=length×width

the width will be

width=area÷length

=7/8÷3/4

7/8×4/3

7/2×1/3

7/6

that's the width you can prove it by multiplying the length times the width to see if you will get 7/8..

I hope this helps

the formula s= I dont know how to type that but I really need helppppp​

Answers

Answer:

[tex] s = \sqrt{30} - 2\sqrt{5} m [/tex]

Step-by-step explanation:

Given:

Formula for side length of cube, [tex] s = \sqrt{\frac{SA}{6} [/tex]

Where, S.A = surface area of a cube, and s = side length.

Required:

Difference in side length between a cube with S.A of 180 m² and a cube with S.A of 120 m²

Solution:

Difference = (side length of cube with 180 m² S.A) - (side length of cube with 120 m² S.A)

[tex]s = (\sqrt{\frac{180}{6}}) - (\sqrt{\frac{120}{6}})[/tex]

[tex] s = (\sqrt{30}) - (\sqrt{20}) [/tex]

[tex] s = \sqrt{30} - \sqrt{4*5} [/tex]

[tex] s = \sqrt{30} - 2\sqrt{5} m [/tex]

Find the missing side length. Leave your answers radical in simplest form. PLEASE HURRY

Answers

Answer:

the answer for y is 9 and x is 9✔2( the check is square root symbol)

Lila is camping with her family. She wants to hike to the lake, go fishing, and hike back before 6:05 P.M. It will take 1 hour and 10 minutes to hike to the lake and 1 hour and 50 minutes to hike back. Lila wants to fish for 3 hours and 10 minutes. What is the latest time Lila can start the hike to the lake?

Answers

Lila will need to start the hike at 11: 55 a.m. to be back at exactly 6: 05 p.m. or at 11: 54 a.m. to be before 6: 05 p.m (6: 04 p.m.)

Explanation:

To solve this question, the first step is to calculate how much time does hiking to the lake, go fishing, and go back takes in total. This can be calculated by adding the time of the three activities. This means 1 hour 10 minutes + 3 hours 10 minutes + 1 hour 50 minutes which is equal to 6 hours 10 minutes. The detailed process is shown below.

Add the hours: 1 + 3 + 1 = 5

Add the minutes: 10+50 +10 = 70

Also, because the total of minutes is above 60 (each hour has 60 minutes) it is necessary to subtract 60 minutes and add 1 hour.

5 hours + 1 hour and 70 minutes - 60 minutes = 6 hours and 10 minutes

Now, to solve the question subtract the time of the activities to the time Lila needs to complete all the activities.

6: 05 p.m.  -  6 hours and 10 minutes = 11: 55 a.m

You can get this result by substracting first the hours and then the minutes

6: 05 p.m. - 6 hours = 12: 05 p.m.

12: 05 - 10 minutes = 11: 55 a.m.

According to this, Lila will need to start the hike at 11: 55 a.m. to be back at exactly 6: 05 p.m. or at 11: 54 a.m. to be before 6: 05 a.m because if she starts at 11: 54 a.m. she will be back at 6:04, which is a minute before 6:05 p.m.

The denominator of a fraction is 30 more than the numerator. The value of the fraction is 3/5. Find the fraction.

Answers

Answer:

45

------

75

Step-by-step explanation:

Let x be the value of the numerator and x+30 be the value of the denominator

This is equal to 3/5

x             3

-------- = -------

x+30      5

Using cross products

5x = 3(x+30)

Distribute

5x = 3x+90

Subtract 3x from each side

2x = 90

Divide by 2

x = 45

The fraction is

45

-----

30+45

45

------

75

[tex]\dfrac{x}{x+30}=\dfrac{3}{5}\\\\5x=3(x+30)\\5x=3x+90\\2x=90\\x=45\\\\\dfrac{x}{x+30}=\dfrac{45}{45+30}=\dfrac{45}{75}[/tex]

Angela took a general aptitude test and scored in the 90th percentile for aptitude in accounting. (a) What percentage of the scores were at or below her score? % (b) What percentage were above?

Answers

Answer:

Step-by-step explanation:

From the given information;

Angela took a general aptitude test and scored in the 90th percentile for aptitude in accounting.

What percentage of the scores were at or below her score?

The percentage of scores that were at or below her score is

Percentage P = 90%

This benchmark is more than average, so we can typically say more of the scores were at or below her score

What percentage were above?

Since The percentage of scores that were at or below her score is

Percentage P = 90%

Then the percentage of the scores that were above will be : (100 -90)%

= 10 %

We can see here that  less percentage of score were above Angela's Score.

Vu is three times as old as Wu. In 25 years Wu will be twice as old as Vu. How old is Vu now?

Answers

Answer: Vu is 15 years old now.

Step-by-step explanation:

Let present age of WU be x.

Then, the present age of Vu = 3x

Also, After 25 years

Age of Wu = x+25

According to the question:

[tex](x+25)=2(3x)\\\\\Rightarrow\ x+25=6x\\\\\Rightarrow\5x=25\\\\\Rightarrow\ x=5[/tex]

Present age of Vu = 3(5) = 15

Hence, Vu is 15 years old now.

Answer:

j

Step-by-step explanation:j

find the straight time pay $7.60 per hour x 40 hours

Answers

Answer:

The straight time pay for $ 7.60 per hour and 40 work hours per week is $ 304.

Step-by-step explanation:

Let suppose that worker is suppose to work 8 hours per day, so that he must work 5 days weekly. The straight time is the suppose work time in a week, the pay is obtained after multiplying the hourly rate by the amount of hours per week. That is:

[tex]C = \left(\$\,7,60/hour\right)\cdot (40\,hours)[/tex]

[tex]C = \$\,304[/tex]

The straight time pay for $ 7.60 per hour and 40 work hours per week is $ 304.

X-6 greater then equal to 15 + 8x

Answers

Answer:x ≤ 3

Step-by-step explanation:

Answer:

x ≥ -3

Step-by-step explanation:

x - 6 ≥ 15 + 8x

x - 8x ≥ 15 + 6

-7x ≥ 21

x ≥ 21/-7

x ≥ -3

x greater than equal to -3

check:

-3 - 6 ≥ 15 + 8*-3

-9 ≥ 15 - 24

A cola-dispensing machine is set to dispense 11 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer of the machine would like to set the control limit in such a way that, for samples of 35, 5% of the sample means will be greater than the upper control limit, and 5% of the sample means will be less than the lower control limit.Required:a. At what value should the control limit be set?b. If the population mean shifts to 10.7, what is the probability that the change will be detected?c. If the population mean shifts to 11.7, what is the probability that the change will be detected?

Answers

Answer:

a.  the control limits should be set at (10.72, 11.28)

b. [tex]\mathbf{P(10.72<x<11.28) = 0.4526}[/tex]

c. [tex]\mathbf{P(10.72<x<11.28) = 0.0065}[/tex]

Step-by-step explanation:

Given that:

population mean μ = 11

standard deviation [tex]\sigma[/tex] = 1.0

sample size n = 35

5% of the sample means will be greater than the upper control limit, and 5% of the sample means will be less than the lower control limit.

Therefore, level of significance ∝ = 0.05+0.05 = 0.10

Critical value for [tex]z_{1-\alpha/2} =z_{1-0.10 /2}[/tex]

[tex]\implies z_{1-0.05} = z_{0.95}[/tex]

Using the EXCEL FORMULA: = NORMSINV (0.95)

z = 1.64

The lower control limit and the upper control limit can be determined by using the respective formulas:

Lower control limit = [tex]\mathtt{\mu - z_{1-\alpha/2} \times \dfrac{\sigma}{\sqrt{n}}}[/tex]

Upper control limit = [tex]\mathtt{\mu + z_{1-\alpha/2} \times \dfrac{\sigma}{\sqrt{n}}}[/tex]

For the lower control limit = [tex]11-1.64 \times \dfrac{1.0}{\sqrt{35}}[/tex]

For the lower control limit = [tex]11-0.27721[/tex]

For the lower control limit = 10.72279

For the lower control limit [tex]\simeq[/tex] 10.72

For the upper control limit = [tex]11+1.64 \times \dfrac{1.0}{\sqrt{35}}[/tex]

For the upper control limit = 11 + 0.27721

For the upper control limit = 11.27721

For the upper control limit  [tex]\simeq[/tex]  11.28

Therefore , the control limits should be set at (10.72, 11.28)

b. If the population mean shifts to 10.7, what is the probability that the change will be detected?

i.e

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}<z < \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{10.72- 10.7}{\dfrac{1.0}{\sqrt{35}}}<z < \dfrac{11.28- 10.7}{\dfrac{1.0}{\sqrt{35}}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{0.02}{\dfrac{1.0}{5.916}}<z < \dfrac{0.58}{\dfrac{1.0}{5.916}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P(0.1183<z < 3.4313})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P(z< 3.4313) - P(z< 0.1183) }[/tex]

Using the EXCEL FORMULA: = NORMSDIST (3.4313) - NORMSDIST (0.118 ); we have:

[tex]\mathbf{P(10.72<x<11.28) = 0.4526}[/tex]

c If the population mean shifts to 11.7, what is the probability that the change will be detected?

i.e

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}<z < \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{10.72- 11.7}{\dfrac{1.0}{\sqrt{35}}}<z < \dfrac{11.28- 11.7}{\dfrac{1.0}{\sqrt{35}}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{-0.98}{\dfrac{1.0}{5.916}}<z < \dfrac{-0.42}{\dfrac{1.0}{5.916}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P(-5.7978<z < -2.48472})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P(z< -2.48472) - P(z< -5.7978) }[/tex]

Using the EXCEL FORMULA: = NORMSDIST (-2.48472) - NORMSDIST (-5.7978); we have:

[tex]\mathbf{P(10.72<x<11.28) = 0.0065}[/tex]

A plan for a dog park has a grassy section and a sitting section as shown in the figure. Which equation can be used to find the area of the grassy section?

Answers

Answer:

[tex]Area=\frac{1}{2} (B\,+\,b)\,h[/tex]

Step-by-step explanation:

The grassy area is that of a trapezoid, so recall the formula for the area of a trapezoid:

[tex]Area=\frac{1}{2} (Base\,+\,base)\,height[/tex]

where:

Base stands for the larger base (in our case the dimension "B" in the attached image)

base stands for the shorter base parallel to the largest Base (in our case the dimension "b" in the attached image)

and

height stands for the distance between bases (in our case the dimension "h" in the attached image.

Therefore the formula for the area of the grassy section becomes:

[tex]Area=\frac{1}{2} (Base\,+\,base)\,height\\Area=\frac{1}{2} (B\,+\,b)\,h[/tex]

Answer:

1/2 (b+b) h

here is the actual picture

a test has 10 multiple-choice questions with 6 choices each, followed by 35 true/false questions. if a student guesses on each equation, how many ways can he answer the questions on the test

Answers

Answer:

6¹⁰×2³⁵

Step-by-step explanation:

he has 6 choices for the first multiple choice question.

and for each of those he had again 6 more choices to answer the second question. 6×6 = 36

so, for all 10 multiple choice questions he answer in

6¹⁰ different ways = 60466176 ways

then there are 35 true/false questions, which are Bausch again multiple choice questions but with only 2 options instead of 6.

so we get 2³⁵ different possibilities. a huge number.

and they're possible for each of the 60466176 ways of the multiple choice part.

so, in total we have

6¹⁰×2³⁵ different answer possibilities.


What is an equation of the line that passes through the points (2, -7) and (8, -4)?

Answers

Answer:

The answer is

[tex]y = \frac{1}{2} x - 8[/tex]

Step-by-step explanation:

To find the equation of the line that passes through two points , first find the slope and then use the formula

y - y1 = m(x - x1)

where m is the slope

(x1 , y1) are any of the points

To find the slope of the line using two points we use the formula

[tex]m = \frac{y2 - y1}{x2 - x1} [/tex]

Slope of the line using points

(2, -7) and (8, -4) is

[tex] \frac{ - 4 + 7}{8 - 2} = \frac{3}{6} = \frac{1}{2} [/tex]

Now the equation of the line using point (2 , - 7) and slope 1/2 is

[tex] y + 7 = \frac{1}{2} (x - 2)[/tex][tex]y + 7 = \frac{1}{2} x - 1[/tex][tex]y = \frac{1}{2} x - 1 - 7[/tex]

We have the final answer as

[tex]y = \frac{1}{2} x - 8[/tex]

Hope this helps you

S varies inversely as G. If S is 8 when G is 1.5​, find S when G is 3. ​a) Write the variation. ​b) Find S when G is 3.

Answers

Step-by-step explanation:

a.

[tex]s \: = \frac{k}{g} [/tex]

[tex]8 = \frac{k}{1.5} [/tex]

[tex]k \: = 1.5 \times 8 = 12[/tex]

[tex]s = \frac{12}{g} [/tex]

b.

[tex]s = \frac{12}{3} [/tex]

s = 4

Write each expression in a simpler form that is equivalent to the given expression. Let F be a nonzero number. f-4

Answers

Answer:

f-4

Step-by-step explanation:

f-4  cannot be simplified

This is the simplest form

Answer:

[tex]\large \boxed{f-4}[/tex]

Step-by-step explanation:

[tex]f-4[/tex]

[tex]\sf f \ is \ a \ nonzero \ number.[/tex]

[tex]\sf The \ expression \ cannot \ be \ simplified \ further.[/tex]

A sample of 36 observations is selected from one population with a population standard deviation of 4.2. The sample mean is 101.5. A sample of 50 observations is selected from a second population with a population standard deviation of 5.0. The sample mean is 100.1. Conduct the following test of hypothesis using the 0.10 significance level.H0 : μ1 = μ2H1 : μ1 ≠ μ2a. This is a_________tailed test.b. State the decision rule. (Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.)The decision rule is to reject H0 if z is ___________the interval.c. Compute the value of the test statistic. (Round your answer to 2 decimal places.) Value of the test statistic d. What is your decision regarding H0?e. What is the p-value? (Round your answer to 4 decimal places.)

Answers

Answer:

Step-by-step explanation:

Given that :

the null and the alternative hypothesis are computed as :

[tex]H_o: \mu_1 = \mu_2[/tex]

[tex]H_a : \mu _1 \neq \mu_2[/tex]

This is a two tailed test

This is because of the ≠ sign in the alternative hypothesis which signifies that the rejection region in the alternative hypothesis are at the both sides of the hypothesized mean difference .

Decision Rule: at the level of significance ∝ = 0 . 10

The decision rule is to reject the null hypothesis if z < - 1 . 64 and z > 1 . 64

NOTE: DURING THE MOMENT OF TYPING THIS ANSWER THERE IS A TECHNICAL ISSUE WHICH MAKES ME TO BE UNABLE TO SUBMIT THE FULL ANSWER BUT I'VE MADE SCREENSHOTS OF THEM AND THEY CAN BE FOUND IN THE ATTACHED FILE BELOW

please solve asap thanks ​

Answers

Answer:

6x+36=180

6x=144

x=24

Step-by-step explanation:

this is the correct answer

X=24 That is the correct answer

Please help

Simple geometry / trig problem

Answers

Answer:

b, c, d

Step-by-step explanation:

a. tan 30/ sin 30 = (sin 30/cos 30) / sin 30 = 1 / cos 30, no

b. cos 30 = √3/2, yes

c. cos 60 tan 60 = cos 60 (sin 60/cos 60) = sin 60 = cos 30, yes

d. sin 60 = cos (90 - 60) = cos 30, yes

[tex]\bf{b.}\ \ \it cos30^o=\dfrac{\sqrt3}{2}\ \ (True)\\ \\ \bf{d.}\ \ \it sin60^o=cos(90^o-60^o)=cos30^o\ \ (True) \\ \\ \bf{c.}\ \it cos60^o\cdot tan60^o=cos60^o\cdot\dfrac{sin60^o}{cos60^o}=\dfrac{cos60^o}{cos60^o}\cdot sin60^o=1\cdot sin60^o=cos30^o\ (T)\\ \\ \\ \bf{a.}\ \ \it \dfrac{tan30^o}{sin30^o}=tan30^o\cdot\dfrac{1}{sin30^o}=\dfrac{sin30^o}{cos30^o}\cdot\dfrac{1}{sin30^o}=\dfrac{sin30^o}{sin30^o}\cdot\dfrac{1}{cos30^o}=\\ \\ \\ =1\cdot\dfrac{1}{cos30^o}=\dfrac{1}{cos30^o}\ \ne\ cos30^o[/tex]

Find the measure of A.
A. 50
B. 70
C. 100
D. 90

Answers

Answer:

D

Step-by-step explanation:

I don't know how to eliminate the wrong answers.

Two line segments which have one end at a diameter and the other end meeting at a common point, make a 90 degree angle.

A is made that way, so A is 90 degrees.

Answer:

Step-by-step explanation:

I believe it is 90

(PLEASE HELP ITS THE LAST QUESTION)

Find the measure of angle L.

A) 21.6°
B) 43.8°
C) 33.4°
D) 21.9°

Answers

Answer:

A

Step-by-step explanation:

lemme meh knw if it was helpful..

Please answer this correctly without making mistakes

Answers

Answer:

7/10 mi

Step-by-step explanation:

The total distance is 3 miles = 30/10 miles.

The other distances added gives 7/10+7/10+9/10 = 23/10

Therefore the last hop from Kingwood to Silvergrove is 30/10 - 23/10 = 7/10

Need Help
Please Show Work​

Answers

Answer:

1= 65 degrees

2=115 degrees

3=115 degrees

Step-by-step explanation: supplementary angles where 115 + x = 180 so go backwards by 180 - 115=65 to find corresponding angles. Angle 3 is also corresponding with the given angle of 115. Angle 2 is opposite the 115 so they have to be equal

Varia is studying abroad in Europe. She is required pay $3,500 (in US dollars) per year to the university; however, she must pay in euros. How many euros can Varia expect to pay per month to the university?

Answers

Answer: 247.92 euros

Step-by-step explanation:

Given, Varia is required pay $3,500 (in US dollars) per year to the university.

If she must pay in euros , then we convert $3,500 into euros.

Current rate : 1 US dollar = 0.85 euro

Then,  $3,500 = ( 0.85 x 3500) euros

= 2975 euros

She can expect 2975 euros to pay per year.

Also, [tex]2975\div 12\approx247.92[/tex]   [ 1 years = 12 months]

Hence, She can expect 247.92 euros to pay per month to the university.

A lottery ticket has a grand prize of $34.8 million. The probability of winning the grand prize is .000000047.

Answers

Answer:

000000047

Step-by-step explanation:

that is the answer

Fifty three million, eight hundred thousand and thirteen

Answers

Answer:

53,800,013

need brainliest!!!

Other Questions
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