please solve quick ​

Answer:

Step-by-step explanation:

I think the answer should be that there is an if -- then way the statement is worded. Quite often if then statements are used in this kind of experiment. Beyond that I can't make any comment. I don't know that it truly is testable, but it sounds like it should be.

Answer:

The hypothesis includes an explanation and makes a prediction.

Step-by-step explanation: I took the quiz on primavera and got that answer

Answer:

8

Step-by-step explanation:

if you have 6 pounds and you use 0.75 pounds per then you can make 6/0.75 dinners = 8

Answer:

C

Step-by-step explanation:

180 degrees + 30 =210 degrees

210 degrees equals 7π/6

Answer:

0.8343

Step-by-step explanation:

From the question, we have the following values:

Probability of vehicles that pass within the check point that are from within the state = 75% = 0.75

Probability of vehicles that pass within the check point that are from outsode the state = 100 - 75 = 25% = 0.25

P = 0.25

n = number of random variables = 9

The probability that fewer than 4 of the next 9 vehicles are from out of state is calculated as:

P < 4 = P ≤ 3

n = 9

P(x) = n!/(n - x)! x! × p^x × q^(n - x)

x = 3

p = 0.25

q = 0.75

P(x) = 9! /(9 - 3)! × 3! × 0.25^3 × 0.75^(9 - 3)

P(x) =0.8343

The probability that fewer than 4 (x<4) of the next 9 vehicles are from out of state is 0.83427.

Given information:

75% of the vehicles passing through a checkpoint are from within the state.

So, the probability that the vehicle is from within the state is 0.75.

The probability that the vehicle is from outside the state will be 1-0.75=0.25.

Now, let x be the random variable. So, the value of n=9. and x<4

It is required to calculate the probability that fewer than 4 of the next 9 vehicles are from out of state.

So, [tex]x< 4[/tex], p=0.25 and q=0.75.

So, the required probability can be calculated as,

[tex]P(x\le3) =\sum ^nC_x\times p^x \times q^{(n - x)}\\P(x\le3)=\sum\dfrac{n!}{(n - x)! x!} \times p^x \times q^{(n - x)}\\P(x\le3)= \dfrac{9!}{(9 - 3)! 3!} \times 0.25^3 \times 0.75^{(9 - 3)}+\dfrac{9!}{(9 - 2)! 2!} \times 0.25^2 \times 0.75^{(9 - 2)}+\dfrac{9!}{(9 - 1)! 1!} \times 0.25^1 \times 0.75^{(9 - 1)}+\dfrac{9!}{(9 - 0)! 0!} \times 0.25^0 \times 0.75^{(9 - 0)}\\P(x\le3)=0.83427[/tex]

Therefore, the probability that fewer than 4 of the next 9 vehicles are from out of state is 0.83427.

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Answer:

27.756

Step-by-step explanation:

1) Move all the decimal points to the right and do the multiplication

  18 * 1524 = 27756

1.8 to 19 = one move

15.42 to 1542 = two moves

total three decimal point shifts

2) count the number (total) that you moved the decimal points

3) starting from the right move the decimal point that many times to the LEFT in for the answer

27.756

9514 1404 393

Answer:

  38.1% decrease

Step-by-step explanation:

A percentage change is found from ...

  % change = (change)/(original amount) × 100%

  = (new value - original amount)/(original amount) × 100%

  = (13 -21)/21 × 100% = -8/21 × 100% ≈ -38.1%

Frazer's speed decreased by 38.1% during the second part.

_____

Additional comment

A negative % change represents a decrease; a positive % change represents an increase.

Answer:

The two missing sides are : 79.54m and 58.62m

Step-by-step explanation:

first we look for the missing angle in the triangle

so now we use sine rules:

Let us make:

so :

so the side facing 35° = 79.54m

To find the area of this triangle

Answer:

Left angle = 60°

Top angle = 120°

Right angle = 60°

Step-by-step explanation:

Use what you know about angle relationships to set up equations you can solve for each variable.

The top top angle, for example, added to one of the other angles must equal 180° because they are supplementary.

You have two variables, so you need at least two equations (I made three but only used two).

The work is in my attachment, comment of you have questions.

Answer:

p(n) = -1/100 n  40

Step-by-step explanation:

Use the two points (n, p): (1000, 30) and (3000, 10).

Now we find the equation of the line that passes through these two points.

m = (10 - 30)/(3000 - 1000)

m = -20/2000

m = -1/100

p(n) = mn + b

30 = -1/100 * 1000 + b

30 = -10 + b

b = 40

The equation is:

p(n) = -1/100 n  40

Answer:

Below

Step-by-step explanation:

You can use this formula to calculate the volume of an object

     Volume = Mass / Density

Plugging everything in...

     Volume = 800g / 8 g/cm^3

                   = 100 cm^3

Hope this helps!

The volume of the boulder will be equal to 100 cubic centimeters.

A substance's density is defined as its mass per unit volume. The density in other words can be defined as the ratio of mass and volume. Its unit will be kg per cubic meter.

The volume is defined as the space occupied by an object in three-dimensional geometry.

It is given that an 800g boulder has a density of 8g/cm^3. The volume will be calculated by using the formula below:-

Volume = Mass / Density

Volume = 800g / 8 g/cm^3

             = 100 cm^3

Therefore, the volume of the boulder will be equal to 100 cubic centimeters.

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Answer:

plane

Step-by-step explanation:

The two-dimensional set of points that has no beginning or end is described by the undefined geometric term is plane.

Answer:

Step-by-step explanation:

Your answer would be 80% or a B

Answer:

5 and 3/32 of an inch.

Answer:

1080

Step-by-step explanation:

PEMDAS says multiply and divide from left to right

9*5*6*3÷3*4*6÷6

45*6*3÷3*4*6÷6

270*3÷3*4*6÷6

810÷3*4*6÷6

270*4*6÷6

1080*6÷6

6480÷6

1080

Answer:

Cos C = a/h

= 21/35

Step-by-step explanation:

since cos is equal to adjacent angle over hypotenuse angle, so from the question we conclude Cos C = 21/35

9 L of 40% silver iodine solution contains 0.40 (9 L) = 3.6 L of silver iodine.

x L of a 10% solution contains 0.10 (x L) = 0.1x L of silver iodine.

Mixing these two solutions results in another solution of volume (x + 9) L and containing (0.1x + 3.6) L of silver iodine, which gives it a concentration of 6%.

But this is impossible! Let a < b. You cannot mix two solutions at concentrations of a and b and magically end up with a mixture whose concentration is smaller than a or larger than b, it has to fall somewhere in the middle.

We can still try solving for x to demonstrate this:

(0.1x + 3.6)/(x + 9) = 0.06

0.1x + 3.6 = 0.06 (x + 9)

0.1x + 3.6 = 0.06x + 0.54

0.04x = -3.06

x = -76.5

Nonsense.

Perhaps you meant the target concentration to be 16%? In that case, there is a valid solution:

(0.1x + 3.6)/(x + 9) = 0.16

0.1x + 3.6 = 0.16 (x + 9)

0.1x + 3.6 = 0.16x + 1.44

0.06x = 2.16

x = 36

Answer:

box plot titled ACT Score with a minimum of 24, quartile 1 of 27, median of 28, quartile 3 of 30, and maximum of 35

Step-by-step explanation:

The scores of the students represented on the dot plot are:

1 dot => 24

3 dots => 26, 26, 26

3 dots => 27, 27, 27

5 dots => 28, 28, 28, 28, 28

3 dots => 30, 30, 30

3 dots => 32, 32, 32

1 dot => 35

Quickly, we can ascertain 3 values from these data points of which we can use to find out which box plot represents the dot plot data.

The minimum score = 24

The maximum score = 35

The median score is the 10th value, which is the middle value of the data point = 28

Therefore, we can conclude that: "box plot titled ACT Score with a minimum of 24, quartile 1 of 27, median of 28, quartile 3 of 30, and maximum of 35".

Answer:  [tex]-\frac{\sqrt{2a}}{8a}[/tex]

=======================================================

Explanation:

The (x-a) in the denominator causes a problem if we tried to simply directly substitute in x = a. This is because we get a division by zero error.

The trick often used for problems like this is to rationalize the numerator as shown in the steps below.

[tex]\displaystyle \lim_{x\to a} \frac{\sqrt{3a-x}-\sqrt{x+a}}{4(x-a)}\\\\\\\lim_{x\to a} \frac{(\sqrt{3a-x}-\sqrt{x+a})(\sqrt{3a-x}+\sqrt{x+a})}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{(\sqrt{3a-x})^2-(\sqrt{x+a})^2}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{3a-x-(x+a)}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{3a-x-x-a}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\[/tex]

[tex]\displaystyle \lim_{x\to a} \frac{2a-2x}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{-2(-a+x)}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{-2(x-a)}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{-2}{4(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\[/tex]

At this point, the (x-a) in the denominator has been canceled out. We can now plug in x = a to see what happens

[tex]\displaystyle L = \lim_{x\to a} \frac{-2}{4(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\L = \frac{-2}{4(\sqrt{3a-a}+\sqrt{a+a})}\\\\\\L = \frac{-2}{4(\sqrt{2a}+\sqrt{2a})}\\\\\\L = \frac{-2}{4(2\sqrt{2a})}\\\\\\L = \frac{-2}{8\sqrt{2a}}\\\\\\L = \frac{-1}{4\sqrt{2a}}\\\\\\L = \frac{-1*\sqrt{2a}}{4\sqrt{2a}*\sqrt{2a}}\\\\\\L = \frac{-\sqrt{2a}}{4\sqrt{2a*2a}}\\\\\\L = \frac{-\sqrt{2a}}{4\sqrt{(2a)^2}}\\\\\\L = \frac{-\sqrt{2a}}{4*2a}\\\\\\L = -\frac{\sqrt{2a}}{8a}\\\\\\[/tex]

There's not much else to say from here since we don't know the value of 'a'. So we can stop here.

Therefore,

[tex]\displaystyle \lim_{x\to a} \frac{\sqrt{3a-x}-\sqrt{x+a}}{4(x-a)} = -\frac{\sqrt{2a}}{8a}\\\\\\[/tex]

Answer:

[tex]\large \boxed{\sf \bf \ \ 12 \ \ }[/tex]

Step-by-step explanation:

Hello, we can see that this shape is ...

...at the left, a right triangle of side = 2

   area = (2*2)/2 =2

... at the middle, a square of side = 2

   area = 2*2 = 4

... at the right, a right triangle of sides 2 and 6

   area= (2*6)/2 = 6

So the total is 2 + 4 + 6 = 12

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

[tex]\mathbf{P(x>6) = 0.0265}[/tex]

Step-by-step explanation:

Given that:

A baseball player has a batting average (probability of getting on base per time at bat) of 0.215

i.e

let x to be the random variable,

consider [tex]x_1 = \left \{ {{1} \atop {0}} \right.[/tex]  to be if the baseball player has a batting average or otherwise.

Then

p(x₁ = 1) = 0.125

What is the probability that they will get on base more than 6 of the next 15 at bats

So

[tex]\mathtt{x_i \sim Binomial (n,p)}[/tex]

where; n =  15 and p = 0.125

P(x>6) = P(x ≥ 7)

[tex]P(x>6) = \sum \limits ^{15}_{x=7} ( ^{15 }_x ) \ (0.215)^x \ (1 - 0.215)^{15-x}[/tex]

[tex]P(x>6) = 1 - \sum \limits ^{6}_{x=7} ( ^{15 }_x ) \ (0.215)^x \ (1 - 0.215)^{15-x}[/tex]

[tex]P(x>6) = 1 - \sum \limits ^{6}_{x=0} ( ^{15 }_x ) \ (0.215)^x \ (1 - 0.215)^{15-x}[/tex]

[tex]P(x>6) = 1 -0.9735[/tex]

[tex]\mathbf{P(x>6) = 0.0265}[/tex]

Answer:

3x^2

Step-by-step explanation:

3 x times the fraction 1 over x to the power of negative 4 => 3x * 1/x^-4

= 3x *x^4 = 3x^5

times x to the power of negative 3 => x^-3

3x^5 * x^-3 = 3x^2

Answer:

3x^2

Step-by-step explanation:

i got it right on the test on god!

Answer:

Entrada

{-x = -1, x = +61, x = 3}

Resultado

{-x = -1, x = 61, x = 3}

Alternate form

{x = 1, x = 61, x = 3}

The answer will be  [tex]x=-1,\:x=3,\:x=\sqrt{6}i,\:x=-\sqrt{6}i[/tex]

Equations are mathematical statements containing two algebraic expressions on both sides of an 'equal to (=)' sign. It shows the relationship of equality between the expression written on the left side with the expression written on the right side. In every equation in math, we have, L.H.S = R.H.S (left hand side = right hand side). Equations can be solved to find the value of an unknown variable representing an unknown quantity. If there is no 'equal to' symbol in the statement, it means it is not an equation.

Given equation:

x^7 - 11x^6 +48X^5 - 120x^4 + 225x^3 - 243x^2 - 162X + 486 = 0.

x^7 +48X^5+ 225x^3+ 486 = 11x^6+ - 120x^4 + 243x^2 + 162x

On solving

[tex]\left(x+1\right)\left(x-3\right)^4\left(x^2+6\right)=0[/tex]

[tex]\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0[/tex]

[tex]x+1=0\quad \mathrm{or}\quad \:x-3=0\quad \mathrm{or}\quad \:x^2+6=0[/tex]

Hence, the solution is [tex]x=-1,\:x=3,\:x=\sqrt{6}i,\:x=-\sqrt{6}i[/tex]

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Answer:

B. 36 square units

Step-by-step explanation:

This is a triangle and to calculate the area of a triangle we multiply height with base and that divided by two

The height of this triangle is 8 units and the base is 9 units

9 × 8 ÷ 2 = 36 square units

Answer:

B: -x^2 + 4

Step-by-step explanation:

If the equation was [tex]f(x)=x^2[/tex], then the vertex would be at 0, and the "U" would be facing straight up. Here, the "U" is upside down, so that means the "x^2" would have to be a negative number ([tex]-x^2[/tex]) to get the upside-down "U". Then, we could see that the vertex is at positive 4, so that means that the parabola moved up 4 units, so the equation should end in +4.

Our answer is:

B: -x^2 + 4

Answer:

The sample correlation coefficient r = 0.9113

Step-by-step explanation:

In this question, we are interested in calculating the sample correlation coefficient.

From the question, we are given;

We are given that,

The sample standard deviation of stock X = 4.665

The sample standard deviation of stock Y = 8.427

The sample covariance = 35.826

Mathematically, the Pearson correlation coefficient "r", it is given as;

r = (co-variance of X and Y)/(standard deviation of X * Standard deviation of Y)

Inputing these values, we have;

r = (35.826)/(4.665 * 8.427) = 0.9113

Answer:

the events of using Brand Z computers and quitting your job are independent.

Step-by-step explanation:

Let A be the event that the population used Brand Z computers and let B be the event that the population quit their jobs.

We are told that 50% of the population used Brand Z computers last year. Thus, the probability of event A is;

P(A) = 50% = 0.5

Also, we are told that 4% of the population quit their jobs last year. Thus the probability of event B is;

P(B) = 4% = 0.04

Since 2% of the population used Brand Z computers and then quit their jobs. Then the probability of the population used Brand Z computers and then quit their jobs is;

P(A ∩ B) = 2% = 0.02

From the law of independent events, if A and B are to be independent events, then;

P(A ∩ B) = P(A) × P(B)

Thus;

P(A ∩ B) = 0.5 × 0.04 = 0.02

This is same value as what was given in the question, thus the events of using Brand Z computers and quitting your job are independent.

Answer:

272 yd²

Step-by-step explanation:

Surface area = base area + lateral area

= (10×10)+(8.6×10×2)

= 100+172

= 272 yd²

Answer:

Question 1: 40 shirts and 40 magizines

Question 2: $4.4

Question 3: 6 gallons

Answer:

hello

Step-by-step explanation:

Answer:

The acceleration on the unit is 0.667 m/s^2

The tension on the draw-bar is 13.34 kN

Step-by-step explanation:

The mass of the truck = 10 Mg = 10 x 10^3 kg

The mass of the trailer = 20 Mg = 20 x 10^3 kg

Tractive force from the truck = 20 kN = 20 x 10^3 N

The total mass of the unit = 10 Mg + 20 Mg = 30 Mg = 30 x 10^3 kg

The tractive force on the unit will produce an acceleration that is given as

F = ma

where

F is the tractive = 20 x 10^3 N

m is the mass of the unit = 30 x 10^3 kg

a is the acceleration of the unit = ?

substituting into the equation

20 x 10^3 = 30 x 10^3 x a

a = (20 x 10^3)/(30 x 10^3) = 0.667 m/s^2

the tension on the draw-bar T is gotten from considering only the mass that is pulled by the draw-bar which is 20 Mg

The acceleration on the unit = 0.667 m/s^2

The drawn mass = 20 Mg = 20 x 10^3 kg

The tension on the draw bar = ma = 20 x 10^3 x 0.667 = 13340 N

= 13.34 kN

The acceleration is 0.00067m/s^2, while the tension on the horizontal bar is 13.4 N

The given parameters are:

[tex]\mathbf{m = 10Mg}[/tex] -- mass of the truck

[tex]\mathbf{M = 20Mg}[/tex] -- mass of the trailer

[tex]\mathbf{F_T = 20kN}[/tex] --- tractive force

Start by calculating the total mass

[tex]\mathbf{M_T = m + M}[/tex]

So, we have:

[tex]\mathbf{M_T = 10Mg + 20Mg}[/tex]

[tex]\mathbf{M_T = 30Mg}[/tex]

Convert to kilograms

[tex]\mathbf{M_T = 30 \times 10^3kg}[/tex]

[tex]\mathbf{M_T = 30000 kg}[/tex]

Force is calculated as:

[tex]\mathbf{F =ma}[/tex]

So, we have:

[tex]\mathbf{20kN =30000kg \times a}[/tex]

Divide both sides by 30000

[tex]\mathbf{a = 0.00067ms^{-2}}[/tex]

The tension on the horizontal bar (i.e. the 20 Mg trailer) is:

[tex]\mathbf{T=ma}[/tex]

So, we have:

[tex]\mathbf{T=20Mg \times 0.00067ms^{-2}}[/tex]

Rewrite as:

[tex]\mathbf{T=20 \times 10^3 kg \times 0.00067m/s}[/tex]

[tex]\mathbf{T=13.4N}[/tex]

Hence, the acceleration is 0.00067m/s^2, while the tension on the horizontal bar is 13.4 N

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