Plz help asap!
Martha works in a toy shop and earns $44 per day. She earns an extra $2 for each toy she sells. If Martha wants to earn at least $80 per day, which inequality shows the minimum number of toys, n, that she should sell?

1) 44 + 2n ≥ 80, so n ≥ 18

2) 44 + 2n ≤ 80, so n ≤ 18

3) 44 + 2n ≥ 80, so n ≥ 34

4) 44 + 2n ≤ 80, so n ≤ 34

Answers

Answer 1

Answer:

The answer is 1) :)

Step-by-step explanation:

Answer 2

Answer:

N.2

Step-by-step explanation:

Because if it's the minimum it can't be 34.

So it's either 1 or 2.

N.1: 44+2(19) ≥ 80, 44+38 ≥ 80, 82 ≥ 80

N.2: 44+2(18) ≤ 80, 44+36 ≤ 80, 80 ≤ 80


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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answer:

584 is the total number of students in the school.

5/8 are in seventh grade and 3/8 are in eighth grade.

4/5 of the seventh graders participated in the track meet, so there were (4/5 · 5/8) · 584 students in the seventh grade participating in the track meet.

7/8 of the eighth graders participated, so there were (7/8 · 3/8) · 584 students in the eighth grade participating in the track meet.

So, all together, there were

(4/5 · 5/8) · 584 + (7/8 · 3/8) · 584 students from the school in the track meet.

Let's simplify as you asked:

(4/5 · 5/8) · 584 + (7/8 · 3/8) · 584 = [(4/5 · 5/8) + (7/8 · 3/8)] · 584 (distributive property - factoring)

= [20/40 + 21/64] · 584 (multiply fractions)

= (1/2 + 21/64) 584 (reduce the first fraction to lowest terms)

= (32/64 + 21/64) 584 (getting a common denominator)

= (53/64) 584 (combine/add the two fractions)

= 483.625 (multiply together)

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Step-by-step explanation:

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