Predict the mass (in grams) of precipitate that will form if a solution containing 2. 34 g of cesium hydroxide is added to a solution containing a large excess of tiso4?

Answers

Answer 1

The mass (in grams) of precipitate is 0.6386 gram.

Calculation,

To find the mass of precipitate, first we have to find the precipitate. So, the chemical  reaction when cesium hydroxide react to large excess of [tex]TiSO_{4}[/tex].

Mole of cesium hydroxide = given mass/molar mass = 2.34 gm/ 149.912 g/mol= 0.0156 moles

[tex]2CsOH+TiSO_{4}[/tex]→[tex]Ti(OH)_{2} +Cs_{2} SO_{4}[/tex]

So, mole ratio 2: 1

It means two moles of cesium hydroxide required to form one mole of titanium hydroxide.

To produce 0.0156 moles of cesium hydroxide = 0.0156 moles×1 mole/2

Mole of titanium hydroxide = 0.0078 mole

Mole of titanium hydroxide = given mass/molar mass of titanium hydroxide

Mole of titanium hydroxide = given mass/81.82 g/mol = 0.0078 mole

Mass of titanium hydroxide = 0.0078 mole ×81.88 g/mol  = 0.6387 gm

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Related Questions

The mass percentage of pencils in a collection of keys that weigh
132.456 g and a pencil that weighs 9.540 g is
%?

Answers

Answer:

Mass Percent of Pencils  =  7.20%

Explanation:

The mass percent can be calculated using the following equation. In this case, the "solute" is the pencil and the "solution" is the collection of pencils.

                               mass solute
Mass Percent  =  ------------------------  x 100%
                              mass solution

                                         9.540 g (pencil)
Mass Percent  =  --------------------------------------------  x 100%
                              132.456 g (pencil collection)

Mass Percent  =  7.20%

The table shows the amount of radioactive element remaining in a sample over a period of time. radioactive decay rate amount of radioactive sample (grams) time (years) 56.0 0 47.1 400 39.6 800 33.3 1,200 28 1,600 part 1: what is the half-life of the element? explain how you determined this. part 2: how long would it take 312 g of the sample to decay to 9.75 grams? show your work or explain your answer.

Answers

1. The half life of the element, given the data from the question is 1600 years

2. The time taken for 312 g of the sample to decay to 9.75 grams is 8000 years

1. How to determine the half life of the element

Half-life is the time taken for half a material to decay.

To determine the half life of the given element, do the following:

Original amount = 56 gHalf the original amount = 56 / 2 = 28 gTime for 28 g = 1600 yearHalf life of element = 1600 years

How to determine the time

We'll begin by determining the number of half-lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 312 gAmount remaining (N) = 9.75 gNumber of half-lives (n) =?

2ⁿ = N₀ / N

2ⁿ = 312 / 9.75

2ⁿ = 32

2ⁿ = 2⁵

n = 5

Finally, we shall determine the time. This can be obtained as follow:

Half-life (t½) = 1600 yearsNumber of half-lives (n) = 5Time (t) =?

t = n × t½

t = 5 × 1600

t = 8000 years

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Sulfur has an oxidation number of +6 in which two formulas?

A. SO₂ and SO4²-

B. H₂SO4 and SO₂

C. SO3 and SO4²-

D. HSO4- and S₂03²-

Answers

Answer:

[tex] \sf \blue{B. H_{2}SO4 \: and \: SO_{2}}[/tex]

Explanation:

As we know in oxidation, oxygen is added and hydrogen is reduced. And in option B, we can observe that is oxygen added +6. So, we conclude that option B is valid.

Hope it help you

Menthol, the substance we can smell in mentholated cough drops, is composed of C, H, and O. A 0.1005g sample of menthol is combusted, producing 0.2829g of CO2 and 0.1159g of H2O.

What is the empirical formula of menthol?

If the compound has a molar mass of 156 g/mol, what is its molecular formula?

Answers

The Empirical formula of compound is C₁₀H₂₀O₁. The Molecular Formula of compound is C₁₀H₂₀O₁.

What is Empirical Formula ?

Empirical formula is the simplest whole number ratio of atoms present in given compound.

[tex]\text{Mass of C} = 0.2829\ g\ CO_2 \times \frac{12\ g\ C}{44\ g\ CO_2}[/tex]

                = 0.07720 g C

[tex]\text{Mass of H} = 0.1159\ g\ H_2O \times \frac{2\ g\ H}{18\ g\ H_2O}[/tex]

                = 0.01297 g H

Mass of O = Mass of methanol - mass of C - mass of O

                 = 0.1005 g - 0.07720 g - 0.01297 g

                 = 0.01033 g

Element    Mass/g         Moles              Ratio      Integers

C                0.07720       0.006428        9.956      10

H                0.01297        0.01287            19.93      20

O                0.01033        0.0006456       1              1              

The Empirical formula of compound is C₁₀H₂₀O₁.

How to find the Molecular formula of compound ?

Molecular formula = Empirical formula × n

[tex]n = \frac{\text{Molar Mass}}{\text{Empirical formula weight}}[/tex]

  [tex]= \frac{156}{156}[/tex]

  = 1

Molecular formula = n × Empirical formula

                               = 1 (C₁₀H₂₀O₁)

                               = C₁₀H₂₀O₁

Thus from the above conclusion we can say that The Empirical formula of compound is C₁₀H₂₀O₁. The Molecular Formula of compound is C₁₀H₂₀O₁.

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what discovery was found by Nels Bohr model of atom ?​

Answers

Answer:

What was Niels Bohr's most important discovery? Niels Bohr proposed a model of the atom in which the electron was able to occupy only certain orbits around the nucleus. This atomic model was the first to use quantum theory, in that the electrons were limited to specific orbits around the nucleus.

Explanation:

Subjects Of Study: atomic model

Phosphorus reacts with oxygen gas to produce solid diphosphorus pentoxide. What type of reaction is represented

Answers

It is a combination reaction.

            P + O₂ → P₂O₅

What is a combination reaction?

Combination reactions are those in which two or more reactants combine to create a single product.

A synthesis reaction is another name for a combination reaction. The overall form of the reaction is as follows:

                                        X + Y → XY

There can be a combination reaction between two elements, two compounds, or a compound and an element.

Examples:

H₂ + Cl₂ → 2HCl

P + O₂ → P₂O₅

C + O₂ → CO₂

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If a reaction occurs, what will be the products of the unbalanced reaction below?Zn(s) + HCl(aq) -->

A. No reaction will occur
B. ZnH(s) + Cl2(g)
C. ZnCl2(s) + H2(g)
D. HZnCl(s)

Answers

The products will be [tex]ZnCl_2(s) + H_2(g)[/tex]

Chemical reactions

Zn is higher than hydrogen in the reactivity series. Thus, it will be able to displace hydrogen from the acid.

The equation of the reaction becomes: [tex]Zn(s) + HCl(aq) -- > ZnCl_2 (s) + H_2 (g)[/tex]

Hydrogen gas is released as a result. In fact, it is one of the ways of preparing hydrogen gas in the laboratory.

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The book value of a machine, as shown on the balance sheet, is not relevant in a decision concerning the replacement of that machine by another machine. (Ignore taxes.) Group starts

Answers

The book value of a machine, as shown on the balance sheet, is not relevant in a decision concerning the replacement of that machine by another machine: TRUE

What is the book value?Book value is the worth of an asset based on its balance sheet account balance in accounting. The value of an asset is determined by subtracting the asset's original cost from any depreciation, amortization, or impairment expenses. Traditionally, a company's book value is equal to its total assets minus intangible assets and liabilities. In practice, however, depending on the source of the computation, book value may include either goodwill or intangible assets, or both. The value inherent in its employees, which is part of a company's intellectual capital, is always overlooked. When intangible assets and goodwill are specifically omitted, the indicator is frequently defined as "tangible book value."

Therefore, the statement "the book value of a machine, as shown on the balance sheet, is not relevant in a decision concerning the replacement of that machine by another machine" is TRUE.

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Complete question:

The book value of a machine, as shown on the balance sheet, is not relevant in a decision concerning the replacement of that machine by another machine. (Ignore taxes.) TRUE or FALSE

predict the theoretical mass of baco3 that should form

Answers

A precipitation reaction occurs when 50. 0 mL of 0. 50 M BaCl₂ is mixed with 75. 0 mL of 0. 75 M Na₂CO₃ (aq). The only precipitate is the BaCO₃ (s) formed. (a) The balanced chemical equation is BaCl₂ + Na₂CO₃ → BaCO₃ + 2NaCl. (b) The limiting reagent is Na₂CO₃.

What is Balanced Chemical Equation ?

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

BaCl₂ + Na₂CO₃ → BaCO₃ + 2NaCl

How to find the number of moles ?

To calculate number of moles when molarity and volume are given as:

Number of moles = Molarity × Volume

Now,

Number of moles of BaCl₂ = Molarity  × Volume

                                             = 0.50 M  × 0.05 L         [1 ml = 0.001 L]

                                             = 0.025 moles

Number of moles of Na₂CO₃ = Molarity  × Volume

                                                = 0.75 M × 0.075 L     [1 ml = 0.001 L]

                                                = 0.05625 moles

The limiting reagent is Na₂CO₃ here.

Thus from the above conclusion we can say that A precipitation reaction occurs when 50. 0 mL of 0. 50 M BaCl₂ is mixed with 75. 0 mL of 0. 75 M Na₂CO₃ (aq). The only precipitate is the BaCO₃ (s) formed. (a) The balanced chemical equation is BaCl₂ + Na₂CO₃ → BaCO₃ + 2NaCl. (b) The limiting reagent is Na₂CO₃.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: A precipitation reaction occurs when 50. 0 mL of 0. 50 M BaCl₂ is mixed with 75. 0 mL of 0. 75 M Na₂CO₃ (aq). The only precipitate is the BaCO₃ (s) formed.

a) Write the balanced equation that describes this reaction.

b) Which chemical is the limiting reactant

In a mining community, groups of dead fish appear in a local river every few weeks. These fish kills coincide with incidents of mining waste dumped into the river. Which of the following components is an abiotic factor causing these fish kills?

Human activities
Biodiversity in the river
Water pollution
Overfishing

Answers

In a mining community, water pollution kills the fish in local river.

How does mining affect the rivers?

Large amounts of water are frequently used in mining, which has the potential to contaminate local groundwater, rivers, streams, and other water sources. A community's ability to grow its own food may be hampered by mining since it consumes grazing or agricultural land and pollutes the soil and the environment.

Metals that leach from the rock also contaminate nearby water sources when they do so. chemical processing pollution: When minerals are extracted from their ores using cyanide or sulfuric acid and water, the runoff pollutes the rivers in the area.

Through erosion and sedimentation, dewatering of wetlands, diverting and channelizing streams, and poisoning surface water and aquifers with harmful chemicals, surface mining can have an impact on fish and aquatic resources.

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Answer:

a

Explanation:

Please help me i really need it!

Answers

The average atomic mass of sulfur = 32.33 u

What is the average atomic mass of sulfur?

The average atomic mass of sulfur is determined as follows:

Average atomic mass = (31.977 × 0.818) + (32.97 × 0.008) + (33.97 × 0.174)

Average atomic mass = 32.33

In conclusion, the average atomic mass of sulfur is determined from the sum of the isotopic masses and their relative abundance.

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How many molecules of H₂O are
equivalent to 97.2 g H₂O?
(H = 1.008 g/mol, O = 16.00 g/mol)
[?]
[?]x10 molecules
Enter your answer with the correct number of
significant figures and be sure the prefix is a number
between 1 and 10!
dro's Number = 6.02 x 1023 molecules/mole

Answers

Answer:

3.25 x 10²⁴ molecules H₂O

Explanation:

To find the number of H₂O molecules, you need to (1) convert grams to moles (via molar mass) and then (2) convert moles to molecules (via Avogadro's Number). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the amount of sig figs in the given value.

Atomic Mass (H): 1.008 g/mol

Atomic Mass (O): 16.00 g/mol

Molar Mass (H₂O): 2(1.008 g/mol) + 16.00 g/mol

Molar Mass (H₂O): 18.016 g/mol

Avogadro's Number:

6.02 x 10²³ molecules = 1 mole

97.2 g H₂O            1 mole              6.02 x 10²³ molecules
------------------  x  -------------------  x  ------------------------------------  =
                              18.016 g                      1 mole

=  3.25 x 10²⁴ molecules H₂O

He nitrogen cycle is one of the most important (and complex!) of the biogeochemical cycles. Why is nitrogen important?

Answers

Nitrogen is an essential part of proteins and nucleic acids (DNA).

Why is nitrogen important?

All living things require nitrogen. It is a part of proteins, ATP, chlorophyll, DNA, and RNA. Given that it makes up a significant portion of the structures of biomolecules in living organisms, its synthesis and consumption in the biogeochemical cycle are of highest importance. Proteins are made up of amino acids (NH2 group).

The structural development of living species' genetic material (DNA, RNA) also involves nitrogen. It is a part of the nitrogenous bases, which together with other nucleotides create RNA and DNA.

Therefore, a nitrogen deficit can cause major structural issues for such an organism.

What happens if nitrogen cycle is disrupted?

A number of undesirable consequences can result from the nitrogen cycle being disrupted. For instance, an abundance of nitrogen in aquatic systems leads to eutrophication. Acid rain can be caused by a rise in atmospheric nitrogen.

The majority of ecosystems can tolerate low nitrogen levels since the majority of nitrogen is not biologically accessible in nature. Ecosystems become out of balance when humans significantly increase the quantity of nitrogen that is accessible through fertilizers, fertilizer use, and other means.

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What is the purpose of a signal phrase?

6.01 formation of the solar system

Answers

Answer: The purpose is to analyze the speed of planets around a central star.

Explanation: using variables

Use the following, balanced equation for the question below:
2Al(s) + 3CuCl₂(aq) → 3Cu(s) + 2AlCl3(aq)
How many moles of aluminum are needed to produce 50.0 grams of aluminum chloride?

Answers

Answer:

0.375 moles Al

Explanation:

To find the moles Al, you need to (1) convert grams AlCl₃ to moles AlCl₃ (via molar mass) and then (2) convert moles AlCl₃ to moles Al (via mole-to-mole ratio from equation coefficients). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (50.0 g).

Molar Mass (AlCl₃): 26.982 g/mol + 3(35.453 g/mol)

Molar Mass (AlCl): 133.341 g/mol

2 Al(s) + 3 CuCl₂(aq) -----> 3 Cu(s) + 2 AlCl₃(aq)

50.0 g AlCl₃           1 mole                 2 moles Al
--------------------  x  ------------------  x  -----------------------  =  0.375 moles Al
                               133.341 g           2 moles AlCl₃

A 4.40g piece of solid CO2 (dry ice) is allowed to sublime in a balloon. The final volume of the balloon is 1.00 L at 300 K. What is the pressure of the gas

Answers

Answer:

2.46 atm

Explanation:

We are going to use ideal gas law   PV = n RT

find n    mole weight of CO2 = 12.011 + 2 * 15.999 = ~ 44 gm/mole

SO    4.4 gm / 44 gm/mole = .1 mole     (this is 'n' )

R = gas constant = .082057366  L-atm/k-mol

T  must be in Kelvin = 300

PV = nRT

P * 1  = .1 * .082057366 * 300

P = 2.46 atm

A sample of air at room temperature in a 4.00 L container holds approximately 0.562 moles of O2and 2.11 moles of N2 along with other trace elements to total 2.67 moles. What is the mole fraction of N2 in the mixture

Answers

Taking into account the definition of mole or molar fraction, the mole fraction of N₂ in the mixture is 0.79.

Molar fraction

The molar fraction is used to express the concentration of a solute in a solution and expresses the proportion in which a substance is found with respect to the total moles of the solution, which are calculated by adding the moles of solute(s) and solvent.

The mole fraction "x" of the elements in a compound is defined as a ratio between the number of moles of each of the different elements present in the compound and the total number of moles of them:

x=number of moles of the solute÷ total number of moles

Mole fraction of N₂ in the mixture

In this case, you know that:

number of moles of N₂: 2.11 molestotal number of moles: 2.67 moles

Replacing in the definition of mole fraction:

x=2.11 moles÷ 2.67 moles

Solving:

x= 0.79

Finally, the mole fraction of N₂ in the mixture is 0.79.

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What is the osmotic pressure of a solution made from 12.5 g of CaCl2 in enough water to make 500 mL, if CaCl2 is 78.5% dissociated at 30oC

Answers

The osmotic pressure of a solution made from 12.5 g of CaCl2 in enough water to make 500 mL, if CaCl2 is 78.5% dissociated at 30oC is 167.087 atm

Define osmotic pressure:-

Osmotic pressure and osmosis are connected. Osmosis is the passage of a solvent through a semipermeable membrane into a solution. The pressure that halts the osmosis process is known as osmotic pressure. Osmotic pressure is a collective attribute of material because its value is determined by the solute's concentration rather than its chemical composition.

The formula used to calculate Osmotic Pressure is:-

π = M x R x T x i

Where;

π =osmotic pressure (in atm)

M=molar concentration (in mol/L)

  =(given mass/molar mass)/volume=(12.5g /111.0)/(500/1000)

  =0.224 mol/L

R=Universal gas constant (0.08206 L.atm/mol.K)

T=absolute temperature (in K) = 30.C + 273 = 303 K

i= van't Hoff factor of solute =3

using the formula and  substituting values;

π=0.224 x 0.08206 x 303 x 3

   = 167.087 atm

The osmotic pressure is 167.087 atm

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Which equation agrees with the ideal gas law?
StartFraction V subscript 1 over T subscript 1 EndFraction equals StartFraction V subscript 2 over T subscript 2 EndFraction.
V subscript 1 n subscript 1 equals V subscript 2 n subscript 2.
P subscript 1 n subscript 1 equals P subscript 2 n subscript 2.
StartFraction P subscript 1 over P subscript 2 EndFraction equals StartFraction T subscript 2 over T subscript 1.

Answers

The equation for ideal gas law is written as PV = nRT.

What is Ideal gas law?

Ideal gas law states that, the volume of a given amount of gas is directly proportional to the number on moles of gas, directly proportional to the temperature and inversely proportional to the pressure.

PV = nRT

where;

P is pressure of the gasV is volume of the gasn is number of molesR is ideal gas constantT is temperature

Thus, the equation for ideal gas law is written as PV = nRT.

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Answer:

A edg

Explanation:

There are exactly 1000 m in 1 km. how many significant figures does this number have?

Answers

Answer:

There is 1 significant figure

Explanation:

In the number 1000, 1 is the only number that counts as a significant figure since the zeros are not in between two non-zero numbers, and there isn't a decimal place either.

What part of the autonomic
nervous system calms you down
after an exciting event?
A. Somatic
B. Temporal lobe
C. Parasympathetic

Answers

Answer:

C. Parasympathetic

Explanation:

HELPPP!!! how do i solve this

8. What mass of sodium hypochlorite (NaClO) is required to prepare 1.5 L of chlorine bleach, if the bleach is a 0.70 mol/L solution of sodium hypochlorite? Show your work and explain each step. The molar mass of sodium hypochlorite is 74.44 g/mol.

9. What is the final concentration when 420 mL of a 12.0 mol/L sodium hydroxide solution is diluted to 2.0 L? Show your work and explain each step.

Answers

Taking into account the definition of molarity, molar mass and dilution:

the mass of sodium hypochlorite (NaClO) required is 78.162 grams.the final concentration of a sodium hydroxide solution is 2.52 mol/L.Definition of molarity

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]molarity=\frac{number of moles}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{L}[/tex].

Definition of molar mass

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

Mass of sodium hypochlorite (NaClO)

If the bleach is a 0.70 mol/L solution of sodium hypochlorite and is required to prepare 1.5 L of chlorine bleach, replacing in the definition of molarity you get:

0.70 [tex]\frac{moles}{L}[/tex]=[tex]\frac{number of moles}{1.5 L}[/tex]

Solving:

0.70 [tex]\frac{moles}{L}[/tex]× 1.5 L= number of moles

1.05 moles= number of moles

The molar mass of sodium hypochlorite is 74.44 g/mol. So you can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 74.44 grams, 1.05 moles of the compound contains how much mass?

[tex]mass=\frac{1..05 molesx74.44 grams}{1 mole}[/tex]

mass= 78.162 grams

Finally, the mass of sodium hypochlorite (NaClO) required is 78.162 grams.

Dilution

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

Ci: initial concentrationVi: initial volumeCf: final concentrationVf: final volume

Final concentration of sodium hydroxide solution

In this case, you know:

Ci= 12 mol/LVi= 420 mLCf= ?Vf= 2 L= 2000 mL (being 1 L= 1000 mL)

Replacing in the definition of dilution:

12 mol/L× 420mL= Cf× 2000 mL

Solving:

(12 mol/L× 420mL)÷ 2000 mL= Cf

2.52 mol/L= Cf

In summary, the final concentration of a sodium hydroxide solution is 2.52 mol/L.

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When the total pressure inside a tennis ball reaches 1013 kPa, the tennis ball will burst. If the ball
originally has a pressure of 405 kPa at room temperature (20°C), at what temperature will the ball burst?
(submit your work)

Answers

Answer:

50.0 °C

Explanation:

If all other variables are being held constant, you can find the temperature using Guy-Lussac's Law. The equation looks like this:

P₁ / T₁ = P₂ / T₂

In this equation, "P₁" and "T₁" represent the initial pressure and temperature. "P₂" and "T₂" represent the final pressure and temperature. You can find the missing temperature (T₂) by plugging the given values into the equation and simplifying.

P₁ = 405 pKa                    P₂ = 1013 pKa

T₁ = 20 °C                         T₂ = ? °C

P₁ / T₁ = P₂ / T₂                                              <----- Guy-Lussac's Law

405 pKa / 20 °C = 1013 pKa / T₂                  <----- Insert values

20.25 = 1013 pKa / T₂                                   <----- Divide 20 from 405

20.25 x T₂ = 1013 pKa                                  <----- Multiply both sides by T₂

T₂ = 50.0 °C                                                  <----- Divide both sides by 20.25

Calculate the molecular weight of Na2sio3

Answers

Answer:

Answer:122 g/ mol

Answer:122 g/ molExplanation:

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compound

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/mol

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/mol

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/molO= 16× 3 = 48 g/ mol

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/molO= 16× 3 = 48 g/ molhence , summation of the molar masses

Answer:122 g/ molExplanation:first must find the molar mass of each element in the compoundNa= 23×2 =46 g/molSi= 28 g/molO= 16× 3 = 48 g/ molhence , summation of the molar masses46+28+48 = 122g/mol

The molecular weight of [tex]\rm Na_2SiO_3[/tex] (sodium silicate) is approximately 122.07 g/mol.

To calculate the molecular weight of [tex]\rm Na_2SiO_3[/tex] (sodium silicate), we need to add the atomic weights of each individual element in the compound.

The atomic weights are as follows:

- Sodium (Na) = 22.99 g/mol

- Silicon (Si) = 28.09 g/mol

- Oxygen (O) = 16.00 g/mol

Now, multiply the atomic weights by the number of atoms in the compound:

- Sodium (Na) = 2 atoms * 22.99 g/mol = 45.98 g/mol

- Silicon (Si) = 1 atom * 28.09 g/mol = 28.09 g/mol

- Oxygen (O) = 3 atoms * 16.00 g/mol = 48.00 g/mol

Finally, add up all the atomic weights:

[tex]\rm \[Molecular \, weight \, of \, Na2SiO3 = 45.98 g/mol + 28.09 g/mol + 48.00 g/mol \\= 122.07 g/mol\][/tex]

So, the molecular weight of [tex]\rm Na_2SiO_3[/tex] (sodium silicate) is approximately 122.07 g/mol.

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The equilibrium concentration of sulfide ion in a saturated lead sulfide solution is M. (Assume that .)

Answers

[S^2-] =8x10^-15 M ( I hope this is right )

Which best describes the reducing agent in the reaction below? cl2(aq) 2br–(aq) right arrow. 2cl–(aq) br2(aq)

Answers

The [tex]Br^{-}[/tex] describes the reducing agent in the reaction below.

[tex]Cl_{2} (aq) + 2Br^{-} (aq)[/tex] → [tex]2Cl^{-}(aq) + Br_{2}( aq)[/tex]

Reducing agent is the species in which oxidation is takes place. Reducing agent is the species in which loss of electrons is takes place. In the above reaction bromine ion in left hand side of the reaction loss electron to become bromine atom. So, bromine ion is reducing agent.

Oxidizing agent is the species in which reduction is takes place. Oxidizing agent is the species in which gain of electrons is takes place. In the above reaction chlorine atom in right hand side of the reaction gain electron to become chlorine ion. So, chlorine atom is reducing agent.

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How many chlorine molecules are in 6.5 moles of chlorine? ​

Answers

Answer:

the number of chlorine  molecules  in  6.5  moles  of  chlorine  is  calculated  as  follows

by  use  of Avogadro  constant  that  is  1mole =  6.02  x10^23    molecules

what  about  6.5  moles

6.5  x  (  6.02x 10^23)=  3.913  x10^24

A compound has an empirical formula of CH₂O. What is its molecular formula, if its molecular mass is 90 g/mol?

(C=12.01 amu, H=1.008 amu, O=16.00 amu)

A: C3H6O3
B: C9H1809

i need help asap, will give brainliest and 50 points, as this is on my final :)

Answers

Empirical formula mass

[tex]\\ \tt{:}\dashrightarrow 12+2+16[/tex]

[tex]\\ \tt{:}\dashrightarrow 30g/mol[/tex]

n:-

[tex]\\ \tt{:}\dashrightarrow \dfrac{Molecular\:mass}{Empirical\:mass}[/tex]

[tex]\\ \tt{:}\dashrightarrow \dfrac{90}{30}[/tex]

[tex]\\ \tt{:}\dashrightarrow 3[/tex]

Molecular formula

[tex]\\ \tt{:}\dashrightarrow n\times Empirical\: formula [/tex]

[tex]\\ \tt{:}\dashrightarrow 3(CH_2O)[/tex]

[tex]\\ \tt{:}\dashrightarrow C_3H_6O_3[/tex]

How does the appearance of
the protist differ from that of the onion sample?

Answers

The appearance of the protist differ from that of the onion sample due to the presence of motile structures.

What is a Protist?

This is an eukaryote which could be unicellular or multicellular and examples include protozoa etc.

The major difference between a protist and onion sample is that protists have motile structures such as flagella, cilia etc while plant cells such as onions don't have.

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A 684.6 mL sample of carbon dioxide was heated to 387 K. If the volume of the carbon dioxide sample at 387 K is 933.9 mL, what was its temperature at 684.6 mL

Answers

According to Charle's law equation, the volume of a sample of carbon dioxide will be 684.6 mL and the temperature will be 283.60 K.

Charle's law equation

According to Charles' Law, the volume of a gas container with a certain amount of gas within is precisely proportional to the temperature when the pressure is constant.

Calculation:

[tex]V_{1}[/tex] = 684.6 mL

[tex]V_{2}[/tex] = 933.9 mL

[tex]T_{1}[/tex] = ?

[tex]T_{2}[/tex] = 387 K

Using Charle's law equation

[tex]\frac{684.6}{T_{1} } = \frac{933.9}{387}[/tex]

[tex]T_{1} = \frac{2,64,862.8}{933.9}[/tex]

[tex]T_{1} = 283.60 K[/tex]

According to Charle's law equation, the temperature at 684.6 mL volume was 283.60 K.

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