Let [tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex] be the nonzero rows of [tex]$R$[/tex] starting from the 1st row to the [tex]k[/tex]th row.
Step 1: We want to show that
R(R)= span [tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex]
For any vector [tex]v $$\in \mathcal{R}(R)$$[/tex], We may write
v= [tex]$$c_{1} \boldsymbol{r}_{1}+c_{2} \boldsymbol{r}_{2}+\cdots+c_{k} \boldsymbol{r}_{k}+c_{k+1} \mathbf{0}+\cdots+c_{m} \mathbf{0}$$[/tex]
Then v= [tex]$$c_{1} r_{1}+c_{2} r_{2}+\cdots+c_{k} r_{k}$$[/tex]
So [tex]v[/tex] belongs to span{ [tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex]}
Thus R(R)[tex]\leq[/tex] Span [tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex]
But trivially,
span [tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex]≤ span{[tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex], 0, . . . , 0} = R(R),
span [tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex]=R(R)
Step 2: We want to show that [tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex]are linearly independent. Suppose otherwise,
then we can write
[tex]$$c_{1} \boldsymbol{r}_{i_{1}}+\cdots+c_{\ell} \boldsymbol{r}_{i_{\ell}}=\mathbf{0}$$[/tex]
From Steps 1 and 2, we have proven that the nonzero rows of R form a basis for the row space.
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Find a linear inequality with the following solution set. Each grid line represents one unit. [asy] size(200); fill((-2,-5)--(5,-5)--(5,5)--(3,5)--cycle,yellow); real ticklen=3; real tickspace=2; real ticklength=0.1cm; real axisarrowsize=0.14cm; pen axispen=black+1.3bp; real vectorarrowsize=0.2cm; real tickdown=-0.5; real tickdownlength=-0.15inch; real tickdownbase=0.3; real wholetickdown=tickdown; void rr_cartesian_axes(real xleft, real xright, real ybottom, real ytop, real xstep=1, real ystep=1, bool useticks=false, bool complexplane=false, bool usegrid=true) { import graph; real i; if(complexplane) { label("$\textnormal{Re}$",(xright,0),SE); label("$\textnormal{Im}$",(0,ytop),NW); } else { label("$x$",(xright+0.4,-0.5)); label("$y$",(-0.5,ytop+0.2)); } ylimits(ybottom,ytop); xlimits( xleft, xright); real[] TicksArrx,TicksArry; for(i=xleft+xstep; i 0.1) { TicksArrx.push(i); } } for(i=ybottom+ystep; i 0.1) { TicksArry.push(i); } } if(usegrid) { xaxis(BottomTop(extend=false), Ticks("%", TicksArrx ,pTick=gray(0.1),extend=true),p=invisible);//,above=true); yaxis(LeftRight(extend=false),Ticks("%", TicksArry ,pTick=gray(0.1),extend=true), p=invisible);//,Arrows); } if(useticks) { xequals(0, ymin=ybottom, ymax=ytop, p=black, Ticks("%",TicksArry , pTick=black+0.8bp,Size=ticklength), above=true, Arrows(size=axisarrowsize)); yequals(0, xmin=xleft, xmax=xright, p=black, Ticks("%",TicksArrx , pTick=black+0.8bp,Size=ticklength), above=true, Arrows(size=axisarrowsize)); } else { xequals(0, ymin=ybottom, ymax=ytop, p=axispen, above=true, Arrows(size=axisarrowsize)); yequals(0, xmin=xleft, xmax=xright, p=axispen, above=true, Arrows(size=axisarrowsize)); } }; draw((-2,-5)--(3,5),dashed+red, Arrows(size=axisarrowsize)); rr_cartesian_axes(-5,5,-5,5); f
The linear inequality of the graph is: -x + 2y + 1 > 0
How to determine the linear inequality?First, we calculate the slope of the dashed line using:
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Two points on the graph are:
(1, 0) and (3, 1)
The slope (m) is:
[tex]m = \frac{1 - 0}{3 - 1}[/tex]
This gives
m = 0.5
The equation of the line is calculated as:
[tex]y = m(x -x_1) + y_1[/tex]
So, we have;
[tex]y = 0.5(x -1) + 0[/tex]
This gives
[tex]y = 0.5x -0.5[/tex]
Multiply through by 2
[tex]2y = x - 1[/tex]
Now, we convert the equation to an inequality.
The line on the graph is a dashed line. This means that the inequality is either > or <.
Also, the upper region of the graph that is shaded means that the inequality is >.
So, the equation becomes
2y > x - 1
Rewrite as:
-x + 2y + 1 > 0
So, the linear inequality is: -x + 2y + 1 > 0
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Complete question
Find a linear inequality with the following solution set. Each grid line represents one unit. (Give your answer in the form ax+by+c>0 or ax+by+c [tex]\geq[/tex] 0 where a, b, and c are integers with no common factor greater than 1.)
Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options. The radius of the circle is 3 units. The center of the circle lies on the x-axis. The center of the circle lies on the y-axis. The standard form of the equation is (x – 1)² + y² = 3. The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.
Answer:
A, B, F
- The radius of the circle is 3 units
- The center of the circle lies on the x-axis
- The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9
Step-by-step explanation:
The first option is correct because the standard equation of the circle is:
[tex](x - 1)^{2} + {y}^{2} = 9[/tex]
making the radius equal to 3.
The center is at (-1,0), therefore it lies on the x-axis.
And lastly, the last option is correct because both options have the radius of 3.
1)Convert the following binary numbwers into decimal number(only a,b,c,f,i)
#1
(11)_2(1×2⁰+1×2¹)_10(1(1)+1(2))_10(1+2)_10(3)_10#b
(110)_2(0+1×2¹+1×2²)_10(2+4)_10(6)_10#c
(111)_2(1×2⁰+1×2¹+1×2²)_10(1+2+4)_10(7)_10#f
(10011)_2(1×2⁰+1×2¹+0+0+1×2⁴)_10(1+2+16)_10(19)_10#i
(10110101)_2(1×2⁰+0+1×2²+0+1×2⁴+1×2⁵+0+1×2⁷)_10(1+4+16+32+128)_10(181)_10Answer:
a) 3₁₀
b) 6₁₀
c) 7₁₀
f) 19₁₀
i) 181₁₀
Step-by-step explanation:
Binary to Decimal Conversion (Positional Notation Method)
Multiply each digit by the base (2) raised to the power dependent upon the position of that digit in the binary number. Sum all the values obtained for each digit.Express the number as a decimal number by placing subscript 10 after it.For a binary number with 'n' digits:
The right-most digit is multiplied by 2⁰The left-most digit is multiplied by [tex]\sf 2^{n-1}[/tex]For example, to convert the binary number 111001₂ into a decimal:
[tex]\begin{array}{ c c c c c c}1 & 1 & 1 & 0 & 0 & 1\\\downarrow & \downarrow & \downarrow & \downarrow & \downarrow & \downarrow \\2^5 & 2^4 & 2^3 & 2^2 & 2^1 & 2^0\\\end{array}[/tex]
Multiply each digit by the base (2) raised to the power as indicated above and sum them:
[tex]=(1 \times 2^5)+(1 \times 2^4)+(1 \times 2^3)+(0 \times 2^2)+(0 \times 2^1)+(1 \times 2^0)[/tex]
[tex]= 32+16+8+0+0+1[/tex]
[tex]= 57[/tex]
Finally, express as a decimal number ⇒ 111001₂ = 57₁₀
Question (a)
[tex]\begin{aligned}\implies 11_2 & = (1 \times 2^1)+(1 \times 2^0)\\& = 2+1\\& = 3\end{aligned}[/tex]
Therefore, 11₂ = 3₁₀
Question (b)
[tex]\begin{aligned}\implies 110_2 & = (1 \times 2^2)+(1 \times 2^1)+(0 \times 2^0)\\& = 4+2+0\\& = 6\end{aligned}[/tex]
Therefore, 110₂ = 6₁₀
Question (c)
[tex]\begin{aligned}\implies 111_2 & = (1 \times 2^2) +(1 \times 2^1)+(1 \times 2^0)\\& =4+2+1\\& = 7\end{aligned}[/tex]
Therefore, 111₂ = 7₁₀
Question (f)
[tex]\begin{aligned}\implies 10011_2 & =(1 \times 2^4)+(0 \times 2^3)+ (0 \times 2^2) +(1 \times 2^1)+(1 \times 2^0)\\& =16+0+0+2+1\\& = 19\end{aligned}[/tex]
Therefore, 10011₂ = 19₁₀
Question (i)
[tex]\phantom{)))}10110101_2 \\\\=(1 \times 2^7)+(0 \times 2^6)+(1 \times 2^5)+(1 \times 2^4)+(0 \times 2^3)+ (1 \times 2^2) +(0 \times 2^1)+(1 \times 2^0)\\\\=128+0+32+16+0+4+0+1\\\\= 181[/tex]
Therefore, 10110101₂ = 181₁₀
the height of a can of coke is in 11 cm and the radius is 6 cm calculate the total surface area of the can in cm^3 assuming that the
can is a closed cylinde
Answer:
The total surface area of the the cylinder is 640.56cm², surface are is always give in cm² not in cm³ b/c cm³ indicates the volume of the cylinder not the surface area.
Step-by-step explanation:
Hello!
. SA=2πr(r+h) ,or 2πr²+h(2πr)
SA=2(3.14)(6cm)(6cm+11cm)SA=6.28(6cm)(17cm)SA=37.68cm(17cm)SA=640.56cm²Answer:
204π cm^2
which is 640.88 cm^2 to the nearest hundredth.
Step-by-step explanation:
Surface area = 2 * area of the base + area of the curved side.
= 2*π *r^2 + 2*π*r*h
= 2π(6)^2 + 2π(6)(11)
= 72π + 132π
= 204π cm^2.
Last week salazar played 13 more tennis games than perry. if they played a combined total of 53 games. How many games did salazar play?
If last week Salazar played 13 more tennis games than Perry and they played a combined total of 53 games, then Salazar played a total of 33 games.
Let the total number of games played by Perry be x.
It is given that, Salazar played 13 more tennis games than Perry.
⇒ Total games played by Salazar = x + 13
Also, Salazar and Perry played a combined of 53 games.
Hence, total number of tennis games played by Salazar and Perry = 53
⇒ Games played by Salazar + Games played by Perry = 53
⇒ x + (x + 13) = 53
2x + 13 = 53
2x = 53 - 13
2x = 40
x = 40 / 2
x = 20
Therefore, total number of games played by Salazar = x+13
= 20 + 13
= 33
Thus, Salazar played total 33 games.
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Find the smallest number by which the following numbers should be multiplied to obtain a perfect cube. (a) 3087 (b) 2560
Check each number's prime factorization, then add any factors necessary to make each one a cube.
(a) 3
[tex]3087 = 3^2 \times 7^3 \implies \boxed{3}\times3087 = (3\times7)^3 \implies 9261=21^3[/tex]
(b) 25
[tex]2560 = 2^9\times5^1 \implies \boxed{5^2}\times2560 = \left(2^3\times5\right)^3 \implies 64000 = 40^3[/tex]
Please help and explain!!!
As x increases, y value decreases.
The rate of change for y as a function of x is decreasing, therefore the function is a decreasing function.
For all values of x, the function value y, decreases to 0.
The y intercept of the graph is the function value y=8
When x=1, the function value y=5.
From the given graph, it is clear that the curve is decreasing for all values of x. Hence, the rate of change of the give curve is decreasing.
Therefore, the giving function is called as decreasing function.
Since, the function is decreasing for all values of x, the value of y decreases to 0.
Form the graph, it is clear that the y-intercepts is at y=8.
Also, the value of y at x=1 is 5 from the graph.
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Two numbers are independently selected from the set of positive integers less than or equal to 5. What is the probability that the sum of the two numbers is greater than their product
There is a 9/25 chance that two numbers will be added together such that their total exceeds their product.
How to find out the probabilityThe set of positive numbers are:
{1,2,3,4,5}
We have to independently select two numbers from these sets.
We are trying to determine the likelihood that the sum is larger than the product of the integers.
When one of the chosen numbers is 1, the total will always be greater than the product because:
1*1=1 & 1+1=2
1*2=2 & 1+2=3
1*3=3 & 1+3=4
1*4=4 & 1+4=5
1*5=5 & 1+5=6
and so on.
If we select 2 as both numbers then,
2*2=4 & 2+2=4
Here sum and the product are equal.
If not, the product will be bigger than the sum.
Now, the first stage is to evaluate the total number of two combinations that are feasible:
We have 5 alternatives for the first number and 5 alternatives for the second number.
The product of the number of possibilities in each scenario yields the total number of combinations:
C= 5*5=25
The following combinations have a sum that is greater than the product :
1 and 1
1 and 2
1 and 3
1 and 4
1 and 5
2 and 1
3 and 1
4 and 1
5 and 1
So, we get 9 combinations.
So, Probability,p=9/25
Therefore it is concluded that the probability is 9/25.
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Michael collects 45 trays of eggs every week . how many trays does he collect in two months?
If x =2 y=3 z=4 solve the following
x² + y²
Answer:
13
Step-by-step explanation:
Given x = 2, y = 3 and z = 4. We'll evaluate the value of x² + y² with given condition.
First, remind that we are only given the expression of x-term and y-term only and therefore, z-term is not included - it's not to be considered.
Substitute x = 2 and y = 3 in the expression:
[tex]\displaystyle{2^2+3^2 = 4+9}\\\\\displaystyle{4+9 = 13}[/tex]
Hence, the value of x² + y² when x = 2 and y = 3 is 13.
Please let me know if you have any questions!
HELPPPP‼️‼️
19. In a school election, 250 votes are tallied for 3
candidates: Eric, Kai, and Sarah. If Eric got 50
votes, and Kai gets 60% of the remaining votes,
how many votes did Sarah get?
Answer:
The answer is 75 and here's why.
Let's figure out the amount of remaining votes to prove this.
250 total votes - 150 votes for candidate a = 100 votes.
minus ↑ sign
Candidate B received 25% of the votes, so let's find 25% of 100
100 * 0.25 = 25 votes
Candidate B only got 25 votes (that's kinda sad, poor guy)
100 - 25 votes = the # of votes candidate C got
Candidate C got 75 votes!
A line passes through the points ( p , a ) and ( p , − a ) where p and a are real numbers. If p = 0 , what is the y-intercept? Explain your reasoning.
The y-intercept of the linear function is y = 0.
What is a linear function?A linear function is modeled by:
y = mx + b
In which:
m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.The y-intercept is given by (0,a) = (0,-a). From this, we have that for it to be a function, a = -a, and the only value that respects this condition is a = 0, hence the y-intercept of the linear function is y = 0.
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Which answer best describes the complex zeros of the polynomial function? f(x)=x3+x2+10x+10
"The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location."
Polynomial functions are equations such as quadratic and cubic equations that take only the non-negative integer power of a variable or a positive integer exponent. For example, 2x + 5 is a polynomial with an exponent equal to 1.
A polynomial function is an expression that is a combination of variables of different degrees, non-zero coefficients, positive exponents (of variables), and constants. For example, f (b) = 4b2 – 6 is a polynomial of'b'and has a degree of 2.
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Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.
x < 5
–6x – 5 < 10 – x
–6x + 15 < 10 – 5x
A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.
The steps to derive the quadratic formula are shown below:
Step 1 ax2 + bx + c = 0
Step 2 ax2 + bx = − c
Step 3 x2 + b over a times x equals negative c over a
Step 4
Provide the next step to derive the quadratic formula.
x squared plus b over a times x minus quantity b over 2 times a all squared equals negative c over a minus quantity b over 2 times a all squared
x squared plus b over a times x plus quantity b over 2 times a all squared equals negative c over a plus quantity b over 2 times a all squared
x squared plus b over a times x minus quantity 2 times a over b all squared equals negative c over a minus quantity 2 times a over b all squared
x squared plus b over a times x plus quantity 2 times a over b all squared equals negative c over a plus quantity 2 times a over b all squared
Answer:
[tex]\huge\boxed{\sf Option \ B}[/tex]
Step-by-step explanation:
Step 3:[tex]\displaystyle x^2+\frac{bx}{a} =\frac{-c}{a}[/tex] --------------------(1)
The next step will be:to find the b² for the expression on the left.How to find b²:Take the expression
[tex]\displaystyle x^2 + \frac{bx}{a}[/tex]
We can also write it as:
[tex]\displaystyle (x)^2 + 2(x)(\frac{b}{2a} )[/tex]
According to the formula [tex]a^2+2ab+b^2[/tex], the b of this expression is [tex]\displaystyle \frac{b}{2a}[/tex]. So,
b² will be:
[tex]\displaystyle =(\frac{b}{2a} )^2\\\\=\frac{b^2}{4a^2}[/tex]
So, we will add [tex]\displaystyle \frac{b^2}{4a^2}[/tex] to both sides in Eq. (1)
For STEP 4, the equation will become:
[tex]\displaystyle x^2+\frac{bx}{a} + \frac{b^2}{4a^2} = \frac{-c}{a} + \frac{b^2}{4a^2}[/tex]
[tex]\rule[225]{225}{2}[/tex]
Answer:
Below in bold.
Step-by-step explanation:
The next step is to divide b/a by 2 then square it and add to both sides.
This creates a perfect square quadratic on left side.
So the answer is :
x squared plus b over a times x plus quantity b over 2 times a all squared equals negative c over a plus quantity b over 2 times a all squared
A square piece of paper measures 20
centimeters on each side. Four equally-
sized circles are going to be cut out from
the paper. What is the largest possible
area of ONE of the circles?
The largest possible area of one of the circles would be 314. 2 cm²
Area of a circleIt is important to note that the formula for finding the area of a circle is given as;
Area = [tex]\pi r^2[/tex]
From the information given, we have the sides of the square to have a value of 20cm
Also note that the measure of the sides of the square is the size of the diameter of the circle
But we need to find the radius
radius = diameter/2
radius = 20/ 2 = 10cm
Substitute value of radius into the formula for area
Area = 3. 142 × 10^2
Area = 3. 142 × 10 × 10
Area = 314. 2 cm²
The area of the circle is 314. 2cm^2
Thus, the largest possible area of one of the circles would be 314. 2 cm²
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Which equation has an a-value of 1 a b-value of -3 and a c-value of -5
The equation which has the values as given in the task content is; y= x² -3x -5.
What is the quadratic equation with the given values?By convention, the general form representation of a quadratic equations is;
y = ax² + bx +c.
Hence, it follows that when the equation has an a-value of 1 a b-value of -3 and a c-value of -5, the equation is; y= x² -3x -5.
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Circle C is shown. 2 secants intersect at a point outside of the circle to form angle 1. The first arc formed is 36 degrees, and the second arc formed is 106 degrees.
In the diagram of circle C, what is the measure of ∠1?
17°
35°
70°
71°
The measure of the ∠1 is 35 degrees.
How to determine the angleit is important to know that the measure of an angle with its vertex outside the circle is half the difference of the intercepted arcs.
Also, the angle subtended by the arc at the center of the circle is the angle of the arc
From the diagram, we have
m ∠ of external angle = half of the difference of arc angles
The arc angles are
106°36°m ∠ of external angle = ∠ 1
Let's substitute the angles
∠1 = [tex]\frac{106 - 36}{2}[/tex]
∠ 1 = [tex]\frac{70}{2}[/tex]
∠ 1 = 35°
We can see that the external angle 1 measures 35 degrees.
Note that the complete image is added.
Thus, the measure of the ∠1 is 35 degrees.
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One of the legs of a right triangle measures 10 cm and the other leg measures 7 cm.
Find the measure of the hypotenuse. If necessary, round to the nearest tenth.
Answer:
12.2 cm
Step-by-step explanation:
we are going to use the formula (below).
Our a and b are going to be our two legs: 10cm and 7cm
[tex]C^{2} =10^{2} +7^{2} \\C^{2}=100+49\\C^{2}=149\\C=\sqrt{149} \\C=12.2cm[/tex]
Instructions: Find the missing length indicated.
400
144
X
The missing side of a right triangle x is 24 units.
How to find side of a right angle triangle?A right triangle has one of its angles as 90 degrees. The side of a right angle triangle can be found using trigonometric ratios.
The side x can be found using similar triangle ratios,
Hence,
x / 400 = 144 / x
cross multiply
x × x = 400 × 144
x² = 57600
square root both sides
√x² = √57600
x = 240
Therefore, the value of x in the right triangle is 240 units.
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Which expression would be easier to simplify if you used the commutative property to change the order of the numbers?
A. 1/7 + (-1)+ 2/7
B. - 15+(-25) +43
C. 120+80+(-65)
D. 40+10+(-12)
The order of the numbers which satisfies commutative property exists 1/7 + (-1)+ 2/7.
What is meant by commutative property?
The commutative property exists a math rule that states that the order in which we multiply numbers does not change the product. The commutative property uses for addition and multiplication. The property states that phrases can “commute,” or transfer locations, and the outcome will not be affected. This exists described as a + b = b + a for addition, and a × b = b × a for multiplication.
Arranging the order of the numbers the fractions
[tex]$& \frac{1}{7}+(-1)+\frac{2}{7} \\[/tex]
[tex]$=& \frac{1}{7}+\frac{2}{7}+(-1) \\[/tex]
Simplifying the equation, we get
[tex]$= \frac{1}{7}+(-1) \\[/tex]
[tex]$&=\frac{4}{7}[/tex]
Therefore, the correct answer is option A. 1/7 + (-1)+ 2/7
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Answer the question please!!!!!!
[tex]Simplify \: \: \\ ( \: a \: ) \: 287 \: \times \: 90 \\ ( \: b \: ) \: 105 \: \times 95[/tex]
Answer:
a) 25830
b)9975
Step-by-step explanation:
a) 287
x 90
25830
b) 105
x 95
9975
heloo need help with this integration
Use the given function to find the [tex]y[/tex]-coordinate of [tex]A[/tex].
[tex]x=2 \implies y = 10+8\cdot2+2^2-2^3 = 22[/tex]
Find the equation of the line through the origin and [tex]A[/tex]. This line has slope
[tex]\mathrm{slope} = \dfrac{22-0}{2-0} = 11[/tex]
and passes through (0, 0), so its equation is
[tex]y - 0 = 11 (x-0) \implies y = 11x[/tex]
Then the area of the shaded region is given by the definite integral
[tex]\displaystyle \int_0^2 (y - 11x) \, dx = \int_0^2 (10 + 7x + x^2 - x^3) \, dx \\\\ ~~~~~~~~ = \left(10x + \frac72 x^2 + \frac13 x^3 - \frac14 x^4\right)\bigg|_0^2 \\\\ ~~~~~~~~ = 10\cdot2+\frac72\cdot2^2+\frac13\cdot2^3-\frac14\cdot2^4 = \boxed{\frac{98}3}[/tex]
Find the value of X. Round to the nearest tenth HELP ASAP!!!!
Answer: 22.5
Step-by-step explanation:
[tex]\sin 64^{\circ}=\frac{x}{25}\\\\x=25 \sin 64^{\circ}\\\\x \approx 22.5[/tex]
Use cylindrical coordinates to find the volume of the region in the first octant bounded by the cylinder r and the plane z.
The volume of the region in first octant is 9.
Given that the region in the first octant bounded by the cylinder r=3 and the plane z=y.
The graph is shown below.
we are given that first octant is bound by r=3 and z=y
We will use the conversion formula, i.e.
x²+y²=r² where x=rcos∅ and y=rsin∅
Firstly, we will find bound octant
0≤∅≤π/2
0≤r≤3
0≤z≤r sin∅
Now, we can set up integral
[tex]V=\int_{0}^{\frac{\pi}{2}}\int_{0}^{3}\int_{0}^{rsin(\theta)}rdzdrd\theta[/tex]
Further, we can solve it.
Firstly, we solve integral for z then we solve for r and after that we will solve for ∅, we get
[tex]\begin{aligned}V&=\int_{0}^{\frac{\pi}{2}}\int_{0}^{3}r^2 \sin (\theta)dr d\theta\\&=\int_{0}^{\frac{\pi}{2}}\frac{1}{3}r^3\sin \theta d\theta\left|_{0}^{3}\\ &=\int_{0}^{\frac{\pi}{2}}\left(\frac{1}{3}\sin\theta d\theta(27-0)\right)\\ &=\int_{0}^{\frac{\pi}{2}}9\sin \theta d\theta\\ &=0-(-9)\\ &=9\end[/tex]
Hence, the volume of the region in the first octant is bounded by the cylinder r=3 and the plane z=y is 9.
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How many employers ask that employees be skilled in communication and handling money
Based on the Venn diagram, the number of employers who ask employees to be skilled in both communication (C) and handling money (M) is equal to 47 employers.
What is a Venn diagram?A Venn diagram is a circular graphical tool that is used to graphically show, logically compare and contrast two (2) or more finite data set or samples in a given population.
From the Venn diagram, we can deduce that the number of employers who ask employees to be skilled in both communication (C) and handling money (M) is given by:
C∩M = 22 + 25
C∩M = 47 employers.
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Prove that 41 is congruent to 21 (mod 3). Explain using words, symbols, as you wish
From the proof of modular congruence below, it has been shown that;
41 ≡ 21 (mod 3).
How to Solve Modular Arithmetic?We want to use the definition of modular congruence to prove that;
41 is congruent to 21 (mod 3) i.e if a ≡ b (mod m) then b ≡ a (mod m).
We are trying to prove that modular congruence mod 3 is a symmetric relation on the integers.
First, if we recall the definition of modular congruence:
For integers a, b and positive integer m,
a ≡ b (mod m) if and only if m|a–b
Suppose 41 ≡ 21 (mod 3).
Then, by definition, 3|41–21, so there is an integer k such that 41 – 21 = 3k.
Thus;
–(41 – 21) = –3k
So
21 – 41 = 3(–k)
This shows that 3|21 – 41.
Thus;
21 ≡ 41 (mod 3) and the proof is complete
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Total area=
Help me please
Thanks so much
Drag the values to the correct locations to write this series using sigma notation and find the sum of the terms. Not all values will be used.
45 + [45 − 2.5] + ⋯ + [45 − 4(2.5)]
Answer:
[tex]\displaystyle \\\sum_{k=0}^4 45-2.5k=200[/tex]
Step-by-step explanation:
We start off with the term 45 and decrease by 2.5 each term, ending with four 2.5's subtracted from 45.
Therefore, our index starts at k=0 and ends at 4. The general term can be defined then as [tex]\displaystyle \\\sum_{k=0}^4 45-2.5k[/tex] and evaluating yields 200.
what scale factor can be applied to Cone 1 to make Cone 2?
The scale factor that can be applied to Cone 1 to make Cone 2 is 0.8
What are scale factors?This are constants that is used to enlarge of diminish a given figure of sides of a figure
We can determine the scale factor by finding the ratio of the similar sides of two figures, From the given cones, the ratio of their radius can determine the scale factor that is applied to Cone 1 to make Cone 2
From the given figure;
scale factor = radius of cone 2/radius of cone 1
Given the following parameters
radius of cone 2 = 2 ft
radius of cone 1 = 2.5ft
Substitute
scale factor = 2/2.5
scale factor = 0.8
Hence the scale factor that can be applied to Cone 1 to make Cone 2 is 0.8
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