Proving Theorems about Parallelograms: Tutorial
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Given: Quadrilateral ABCD is a parallelogram. Prove: ZBAD ZDCB, and ZABO ZODA. Match each
statement to its corresponding reason. Scroll down to see all the choices. Click the links in the statements to view
related diagrams. Drag the items on the left to the correct location on the right.
AB CD
BO ADview diagram)
Let A, B, C, and D form a parallelogram.
Draw ACand BD. (view diagram)
AB=CD
BC=AD
AABCE ACDA
AABD ACDB
ZBAD ZDCB(view diagram)
LABC ZCDA(view diagram)
ACAC, and BD BD
given
9 of 2
Opposite sides of a
parallelogram are .
line segments have
equal measures.
drawing line segments
Reflexive Property of
Equality
SSS criterion for
Corresponding angles
of triangles are

Answer:

sin(x - y) = 0.21

Step-by-step explanation:

we have the sin values which we need to get cos values

sin (A-B) = sin A cos B - sin B cos A

sin² A + cos² A = 1

sin x = 4/9

cos² x = 1 - sin² x = 1 - 16/81 = 65/81

cos² x = 65/81

cos x = √65/9

sin y = 1/4

cos² y = 1 - sin² y = 1 - 1/16 = 15/16

cos² y = 15/16

cos y = √15/4

sin(x − y) = sin x cos y - sin y cos x

sin(x - y) = 4/9 √15/4 - 1/4 √65/9

sin(x - y) = (4√15-√65)/36

sin(x - y) = 0.21

socratic Narad T

Answer: C

Step-by-step explanation:

on edg

Answer: 120 hr

Step-by-step explanation: 15$ every hr so for 120 hrs it would be 1,800$ plus the signing bonus of 200$ would total 2,000$ but with out the bonus she would have to work 134 hrs for 2,010$

Answer:

Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle

Answer:

In mathematics, the trigonometric functions are real functions which relate an angle of a right-angled triangle to ratios of two side lengths. They are widely used in all sciences that are related to geometry, such as navigation, solid mechanics, celestial mechanics, geodesy, and many others.

Hi

How are you?

Kya kar rahi hoo?

The transformations that are applied to pentagon ABCDE to create A"B"C"D"E" are:

1) Translation (x, y) → (x + 8, y + 2)

2) Reflection across the x-axis (x, y) → (x, -y)

So, the overall transformation given in the graph is (x, y) → {(x + 8), -(y + 2)}.

The transformation rules are:

The pentagons in the graph have vertices as

For the pentagon ABCDE: A(-4, 5), B(-6, 4), C(-5, 1), D(-2, 2), and (-2, 4)

For the pentagon A"B"C"D"E": A"(4, -7), B"(2, -6), C"(3, -3), D"(6, -4), and E"(6, -6)

Consider the vertices A(-4, 5) from the pentagon ABCDE and A"(4, -7) from the pentagon A"B"C"D"E".

Applying the Translation rule for the pentagon ABCDE:

The rule is (x, y) → (x + a, y + b)

So, the variation is

-4 + a = 4

⇒ a = 4 + 4 = 8

5 + b = 7

⇒ b = 7 - 5 = 2

So, the pentagon ABCDE is translated by (x + 8, y + 2).

Applying the Reflection rule for the translated pentagon:

The translated pentagon has vertices (x + 8, y + 2).

When applying the reflection across the x-axis,

(x + 8, y + 2) → {(x + 8), -(y + 2)}

Therefore, the complete transformation of the pentagon ABCDE to the pentagon A"B"C"D"E" is (x, y) → {(x + 8), -(y + 2)}

Verification:

A(-4, 5) → ((-4 + 8), -(5 + 2)) = (4, -7)A"

B(-6, 4) → ((-6 + 8), -(4 + 2)) = (2, -6)B"

C(-5, 1) → ((-5 + 8), -(1 + 2)) = (3, -3)C"

D(-2, 2) → ((-2 + 8), -(2 + 2)) = (6, -4)D"

E(-2, 4) → ((-2 + 8), -(4 + 2)) = (6, -6)E"

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The arc length of [tex]y=2\cos(3x)[/tex] on the interval [tex][a,b][/tex] is

[tex]\displaystyle \int_a^b \sqrt{1 + (y')^2} \, dx = \int_a^b \sqrt{1 + (-6\sin(3x))^2} \,dx = \boxed{\int_a^b \sqrt{1+36\sin^2(3x)} \, dx}[/tex]

Answer:1.166 reams of paper.

Step-by-step explanation:

Just use simple division and divide 7/6.

Each classroom will get  [tex]\dfrac{7}{6}[/tex]  paper when there are 6 fifth grade classrooms that share 7 packs of paper.

A fraction is defined as a part of a whole. The upper part of the fraction is called the numerator, and the lower part is called the denominator.

Given that:

Number of fifth grade classrooms = 6

Number of packs of paper = 7

The number of paper each classroom get in fractions can be obtained by dividing the number of packs of paper by the number of fifth grade classrooms.

Each classroom get = [tex]\dfrac{Number \ of \ packs \ of \ paper}{ \ Number \ of \ fifth \ grade \ classrooms}[/tex]

Each classroom get = [tex]\dfrac{7}{6}[/tex]

Each classroom will get  [tex]\dfrac{7}{6}[/tex]  paper.

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p→r

The law of syllogism, also known as transitivity reasoning, is a legitimate kind of deductive reasoning that adheres to a predetermined pattern. The transitive property of equality states that if a = b and b = c, then a = c. so we can conclude that The law of syllogism is almost  similar to the transitive property.

now if we want to define general case then we can say tha

a→b

and

b→c  => a→c

now according to statements given in the problem

p→q and q→r ⇒ p→r

which completes the syllogism.

hence ,  p→r is the required answer.

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The terms that explains the value of Sin(pi/3) on the unit circle would be Sin(pi/3) = Opposite side of angle.

According to the statement

we have to give the terms which explain the sin (pi/3) perfectly.

And we have choose these terms from the these below written conditions like From Right Triangle, Hypotenuse, and unit circle.

And Now we explain all terms below

So,

"Right Triangle is a triangle whose one of the angle measures 90° "

And "The hypotenuse is a longest side of the right triangle.

And"Unit Circle is a circle with radius 1."

For given question,

We have been  given a unit circle.

So, We need to find the sin (pi/3)

We know, in a right triangle for any angle , θ

Sinθ = Opposite side of angle / Hypotenuse

So, for , Sin(pi/3) = Opposite side of angle / 1

Sin(pi/3) = Opposite side of angle

Therefore, The terms that explains the value of Sin(pi/3) on the unit circle would be Sin(pi/3) = Opposite side of angle.

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The  appropriate display to show the spread of 150 test scores for Mrs. Hansen's last science test is: b.  box and whisker plot.

Box and whisker plot which is also called box plot can be defined as the plot that show a graphical presentation of data set by helping to display the data set or data score .

Hence a graphical presentation display to show the spread of 150 test scores for Mrs. Hansen's last science test is option B which is Box and whisker plot .

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Answer: b

///////////

Evaluating the given expressions and inequalities, we have;

[tex]11) \: \frac{x}{4} \cdot \left(2 + y - x \right) = 4[/tex]

12) (8•a - 5•b) - 2•(a + b) = 4

[tex] 13) \: \frac{p \cdot (p + {a}^{2} )}{6} = 55 [/tex]

[tex] 14) \: 3\cdot m - \frac{2\cdot m}{2} +\frac{n}{3} = 12 [/tex]

[tex] 16) \: x \geq 11\frac{2}{3} [/tex]

17) k > 9

18) v > 9

20) m ≤ 16

The given expressions are;

[tex]11) \: \frac{x}{4} \cdot \left(2 + y - x \right)[/tex]

Where x = 4, and y = 6, we have;

[tex]\frac{x}{4} \cdot \left(2 + y - x \right) = \frac{4}{4} \cdot \left(2 + 6 - 4 \right) = 4[/tex]

Therefore;

[tex]\frac{x}{4} \cdot \left(2 + y - x \right) = 4[/tex]

12) (8•a - 5•b) - 2•(a + b)

Where a = 3 and b = 2, we have;

(8•a - 5•b) - 2•(a + b) = (8×3 - 5×2) - 2•(3 + 2) = 4

Therefore;

[tex]13) \: \mathbf{\frac{p \cdot (p + {a}^{2} )}{6}} [/tex]

Where a = 7, and p = 6, we have;

[tex] \frac{p \cdot (p + {a}^{2} )}{6} = \mathbf{ \frac{6 \times (6 + {7}^{2} )}{6}} = 55 [/tex]

Therefore;

[tex] \frac{p \cdot (p + {a}^{2} )}{6} = 55 [/tex]

[tex]14) \: \mathbf{3\cdot m - \frac{2\cdot m}{2} +\frac{n}{3} } [/tex]

Where m = 5, and n = 6, we have;

[tex] 3\cdot m - \frac{2\cdot m}{2} +\frac{n}{3} = \mathbf{3\times 5 - \frac{2\times 5}{2} +\frac{6}{3} }= 12 [/tex]

Therefore;

[tex] 3\cdot m - \frac{2\cdot m}{2} +\frac{n}{3} = 12 [/tex]

[tex]16) \: \mathbf{1 \frac{1}{6} }\leq \frac{x}{10} [/tex]

Which gives;

[tex] \frac{7}{6} \times 10 \leq x [/tex]

[tex] \mathbf{ \frac{35}{3} }\leq x [/tex]

[tex] x \geq 11\frac{2}{3} [/tex]

17) 20 < k + 11

Therefore;

k > 20 - 11 = 9

18) 6•v > 54

v > 54 ÷ 6 = 9

Therefore;

[tex]20) \: 8 \geq \mathbf{ \frac{m}{2}} [/tex]

Therefore;

2 × 8 = 16 ≥ m

Which gives;

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The triangle is illustrated below.

The first thing you should find are the new vertices:

(x, y) ---> (2x, 2y) ---> (x', y')

(0, 0) ---> (2 (0), 2 (0)) ---> (0, 0)

(-4, 4) ---> (2 (-4), 2 (4)) ---> (-8, 8)

(-4, -2) ---> (2 (-4), 2 (-2)) ---> (-8, -4)

Then, you must join the ordered pairs and graph the new triangle.

See the attached graph.

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Answer: 433.33 cm^3

Step-by-step explanation: Since the base is a square, volume = base area × height / 3

10*10 = 100,  100 * 13 = 1300, divided by 3 = 433.33 cm^3

Answer:

there should have been names of every line and joining parts

While solving the pictogram, we get that the number of hamsters owned  are 4.

Solution:

total number of pets = 33

total number of cats = 12

total number of dogs = 11

total number of rabbits = 6

then total number of hamsters = total pets - total cats, dogs, and rabbits

total number of hamsters = 33 - ( 12 + 11 + 6)

total number of hamsters = 4

also, on the pictogram one block represents 4 animal. then, total number of hamsters will be represented by one block.

view the second attachment for answer.

What is pictogram?

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I hope you are trying to ask the question below in the image

The equation that is represented by the graph below is y = e^x - 4.

From the graph, it can be seen that the only exponential function n to hat intercept the function at equal to 3 is y = e^x - 4.

Let's equate y to 0.

y = e^x - 4.

e^x - 4 = 0

e^x = 4

In(e^x) = In(4)

x = 1.386

The x intercept is located at (1.386, 0).

In conclusion, the correct option is D.

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i. The number of people who like banana only is 20.

ii. The number of people who like none of the fruits is zero.

iii. The number of people who like at most one fruit is 30.

The question has to do with sets.

A set a collection of well ordered items

Since we have 55 people, 3x + 5 people like banana and x + 5 people like apple. If all the people who like apple also like banana and if 2x + 15 people like at least one of fruit then, we have that

3x + 5 + x + 5 + 2x + 15 = 55

3x + 2x + x + 5 + 5 + 15 = 55

6x + 30 = 55

6x = 55 - 25

6x = 30

x = 30/6

x = 5

Since the number of people who like banana only is 3x + 5.

So, number of people who like banana only is n = 3x + 5

= 3(5) + 5

= 15 + 5

= 20

So, the number of people who like banana only is 20.

Since from the question, a person likes at least one fruit, either banana, apple or both. No one likes none of the fruits.

So, the number of people who like none of the fruits is zero.

To like at most one fruit, the person either likes apple or banana.

So, their sum is n = 3x + 5 + x + 5

= 4x + 10.

Since x = 5, we have n = 4x + 10.

= 4(5) + 10

= 20 + 10

= 30

So, the number of people who like at most one fruit is 30.

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The expression that is not equivalent to (1 - sin²(x)) tan(-x) is D. (cos²x - 1)(cot -x).

It should be noted that (cos²x - 1)(cot -x). is not equivalent to the given expression.

This is illustrated as:

(cos²x - 1)(cot -x)

= (-sin²x) × (-cot x)

= sin²x × cosx/sin x = sinxcosx

In conclusion, the correct option is D.

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The expression _______ is not equivalent to (1 − sin2(x)) tan(-x).

a. (1 - cos^2(x)) cot(-x)

b. (cos^2(x) - 1) cot(x)

c. (sin^(x) - 1) tan(x)

d. (cos^2(x) - 1) cot(-x)

Hello,

John : n

Brad : n + 12

n + n + 12 = 84

2n + 12 = 84

2n = 84 - 12

2n = 72

n = 72/2

n = 36

John $36 and Brad $36 + $12 = $48

Answer:

jhon =36 brad=48

Step-by-step explanation:

B=J+12

J+B=84

12+J+J=84

2J=72

J=36

B=J+12=36+12=48

Answer:

[tex]\frac{\sqrt{3} }{6}[/tex]

Step-by-step explanation:

using the 30- 60- 90 triangle for exact values , then

tan60° = [tex]\sqrt{3}[/tex] , and

cot60° = [tex]\frac{1}{tan60}[/tex] = [tex]\frac{1}{\sqrt{3} }[/tex]

cos60° = [tex]\frac{1}{2}[/tex]

cot60° cos60°

= [tex]\frac{1}{\sqrt{3} }[/tex] × [tex]\frac{1}{2}[/tex]

= [tex]\frac{1}{2\sqrt{3} }[/tex] ← rationalise the denominator by multiplying by [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex]

= [tex]\frac{1}{2\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex]

= [tex]\frac{\sqrt{3} }{6}[/tex]

The answer is [tex]\boxed {\frac{1}{2\sqrt{3}}}[/tex]

The needed trigonometric values :

Hence, the value of the expression is :

Answer:

2 face cards

Step-by-step explanation:

By definition, there are 12 face cards (Kings, queens, and jacks) and 36 numbered cards (2's through 10's) in a standard deck of 52 cards.  Aces are not considered face cards (no face on the card).

The ratio of face cards in a full deck is (12/52) or slightly over 23%.

The likelihood of a face card in a hand of 8 cards is:

(8 cards)*(12 face cards/52 cards) = 1.85 cards.  We need to round to the nearest whole card, so the expected number of face cards in a hand of 8 is 2 cards.  

Step-by-step explanation:

The least and greatest amounts that the two friends could spend on food are 100 and 140 respectively

Functions and values

Functions are expressions written in terms of letters known as variables. Given the equation that represents the food budget of two friends as shown;

1/2(x-120)=10

where x is the amount spent on food.

In order to determine the least and greatest amounts that the two friends could spend on food,

For the least amount

-(x-120) = 20

-x+120 = 20

x = 100

For the greatest amount

(x-120) = 20

x = 140

Hence the least and greatest amounts that the two friends could spend on food are 100 and 140 respectively

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Answer:

12 units^2

Step-by-step explanation:

Area of a triangle = 1/2 * base * height

  base goes from -4 to +4  = 8 units

  Height goes from 1 to 4  = 3 units

    area = 1/2 * 8 * 3 = 12 units^2

The simplification of the polynomial expression will give 3x² - 20x + 8.

The polynomial expression is given as:

(5x² + 13x4) (17x² + 7x - 19) + (5x-7)(3x + 1)

= 5x² + 13x - 4 - 17x² - 7x + 19 + 15x² + 5x - 21x - 7

Then collect like terms

= 5x² + 15x² - 17x² + (13x - 7x + 5x - 21x) - 4 - 7 + 19

= 3x² - 20x + 8.

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Answer: (8,10)

Step-by-step explanation:

To go from A to C, we go right 2 units and up 6 units.

So, if we let the fourth vertex be D, then to go from B to D, we must also go right 2 units and up 6 units from B.

Therefore, the answer is (8, 10).

The ship captain should be turned 129.49 so it's heading straight for Island B.

Given Island A is 160 miles from Island B and the captain of a ship travels 170 miles from Island A and then discovers that he is off course and 200 miles from island B.

So we gave it

a = 200 feet

b = 170 feet

c = 160 feet

We need to find angle C which goes directly to island B.

We apply the "cosine law":

[tex]\begin{aligned}\cos C&=\frac{a^2+b^2-c^2}{2ab}\\ &=\frac{(200)^2+(170)^2-(160)^2}{2\times 200\times 170}\\ &=\frac{40000+28900-25600}{68000}\\ &=\frac{43300}{68000}\\ &=0.636\end[/tex]

Now we multiply both sides by cos⁻¹, we get

cos⁻¹(cos C)= cos⁻¹(0.636)

C = 50.51

The interior angle is 50.51°

We need to find the outer angle to find the bearing the captain needs to turn

Applying the additional angle ruler:

The outside angle = 180 - 50.51 = 129.49°

Therefore, he must turn so as to head directly for Island B, where Island A is 160 miles from Island B and the captain is sailing 170 miles.

from Island A and then discovers that it is off-road and 200 miles away

Island B is 129.49.

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