Question 1 (5 points)
The line segment AB with endpoints A(-3, 6) and B(9, 12) is dilated with a scale
factor 2/3 about the origin. Find the endpoints of the dilated line segment.
OA) (-2, 4), (6,8)
B) (2, 4). (6,8)
OC) (4, -2), (6,8)
OD) (-2,4), (8,6)​

Answers

Answer 1

Answer: A) (-2, 4), (6,8)

Step-by-step explanation:

When a point (x,y) is dilated by a scale factor of k , then the new points is given by (kx,ky).

Given: The line segment AB with endpoints A(-3, 6) and B(9, 12) is dilated with a scale factor [tex]\dfrac23[/tex] about the origin.

Let A' and B' b the endpoints of the dilated line segment.

Then, [tex]A'(\dfrac{2}{3}(-3), \dfrac23(6))=A'(-2,4)[/tex]

[tex]B'(\dfrac{2}{3}(9), \dfrac23(12))=B'(6,8)[/tex]

Hence, the correct option is A) (-2, 4), (6,8)


Related Questions

which table shows a proportional relationship between x and y?

Answers

the answer is c because b doesn’t make sense

Answer:

Table C

Step-by-step explanation:

For x and y to be proportional , then the values of

[tex]\frac{y}{x}[/tex] = constant k

Table B

[tex]\frac{y}{x}[/tex] = [tex]\frac{6}{3}[/tex] = 2

[tex]\frac{y}{x}[/tex] = [tex]\frac{24}{6}[/tex] = 4

[tex]\frac{y}{x}[/tex] = [tex]\frac{36}{9}[/tex] = 4

The values are not constant

Table C

[tex]\frac{y}{x}[/tex] = [tex]\frac{2}{3}[/tex]

[tex]\frac{y}{x}[/tex] = [tex]\frac{4}{6}[/tex] = [tex]\frac{2}{3}[/tex]

[tex]\frac{y}{x}[/tex] = [tex]\frac{6}{9}[/tex] = [tex]\frac{2}{3}[/tex]

These values are constant

Then Table C shows a proportional relationship between x and y

Carl recorded the number of customers who visited his new store during the week:


Day Customers

Monday 17

Tuesday 13

Wednesday 14

Thursday 16


He expected to have 15 customers each day. To answer whether the number of customers follows a uniform distribution, a chi-square test for goodness of fit should be performed. (alpha = 0.10)


What is the chi-squared test statistic? Answers are rounded to the nearest hundredth.

Answers

Answer:

The chi - square test can be [tex]\approx[/tex] 0.667

Step-by-step explanation:

From the given data :

The null hypothesis and the alternative hypothesis can be computed as:

Null hypothesis: The number of customers does  follow  a uniform distribution

Alternative hypothesis: The number of customers does not  follow  a uniform distribution

We learnt that: Carl recorded the number of customers who visited his new store during the week:

Day              Customers

Monday               17

Tuesday              13

Wednesday         14

Thursday              16

The above given data was the observed value.

However, the question progress by stating that : He expected to have 15 customers each day.

Now; we can have an expected value for each customer  as:

                      Observed Value                   Expected Value

Day                 Customers                        

Monday                17                                          15

Tuesday               13                                          15

Wednesday          14                                          15

Thursday               16                                         15

The Chi square corresponding to each data can be determined by using the formula:

[tex]Chi -square = \dfrac{(observed \ value - expected \ value )^2}{expected \ value}[/tex]

For Monday:

[tex]Chi -square = \dfrac{(17 - 15 )^2}{15}[/tex]

[tex]Chi -square = \dfrac{(2)^2}{15}[/tex]

[tex]Chi - square = \dfrac{4}{15}[/tex]

chi - square = 0.2666666667

For Tuesday :

[tex]Chi -square = \dfrac{(13- 15 )^2}{15}[/tex]

[tex]Chi -square = \dfrac{(-2)^2}{15}[/tex]

[tex]Chi - square = \dfrac{4}{15}[/tex]

chi - square = 0.2666666667

For Wednesday :

[tex]Chi -square = \dfrac{(14- 15 )^2}{15}[/tex]

[tex]Chi -square = \dfrac{(-1 )^2}{15}[/tex]

[tex]Chi -square = \dfrac{(1 )}{15}[/tex]

chi - square = 0.06666666667

For Thursday:

[tex]Chi -square = \dfrac{(16- 15 )^2}{15}[/tex]

[tex]Chi -square = \dfrac{(1 )^2}{15}[/tex]

[tex]Chi -square = \dfrac{(1 )}{15}[/tex]

chi - square = 0.06666666667

                   Observed Value   Expected Value    chi - square

Day                 Customers                        

Monday                17                     15                       0.2666666667

Tuesday               13                     15                       0.2666666667

Wednesday          14                     15                       0.06666666667

Thursday               16                    15                       0.06666666667

Total :                                                                        0.6666666668

The chi - square test can be [tex]\approx[/tex] 0.667

At level of significance ∝ = 0.10

degree of freedom = n - 1

degree of freedom = 4 - 1

degree of freedom = 3

At ∝ = 0.10 and df = 3

The p - value for the chi - square test statistics is 0.880937

Decision rule: If the p - value is greater than the level of significance , we fail to reject the null hypothesis

Conclusion: Since the p - value is greater than the level of significance , we fail to reject the null hypothesis and conclude that there is insufficient evidence to show that the number of customers does not follows a uniform distribution.

Answer:.67

Step-by-step explanation:

Complete the equation describing how x
and y are related
Х у
-2-8
-1 -5
y = [? ]x +
0 -2
1 1
2 4 Enter the answer that
3 7
belongs in [?]

Answers

Answer:

3

Step-by-step explanation:

-2=0+x

x¹=-2 (purple one)

4=2x-2

2x=6

x²=3 (green one)

Simplify (x + 4)(x2 − 6x + 3). x3 − 14x2 + 3x + 12 x3 − 6x2 − 17x + 12 x3 − 10x2 − 27x + 12 x3 − 2x2 − 21x + 12

Answers

Answer:

36 x^3 - 32 x^2 + (x + 4) (x^2 - 6 x + 3).x^3 - 62 x + 12

Step-by-step explanation:

Answer:

x^6-2x^5-21x^4+48x^3-32x^2-62x+12

Step-by-step explanation:

Mark me as brainliest!!!!

show working to this question ​

Answers

Answer:

Step-by-step explanation:

A = {p, q, r}

Subsets: {p,q,r}, {p,q}, {p,r}. {q,r}, {p}, {q}, {r}, ∅

::::

Slope of RT = (-7/2 - 0)/(-3/2 - 0) = 7/3

Point-slope equation for line of slope 7/3 that passes through (0,0):

y = (7/3)x

You plan to conduct a marketing experiment in which students are to taste one of two different brands of soft drink. Their task is to correctly identify the brand tasted. You select a random sample of 200 students and assume that the students have no ability to distinguish between the two brands. The probability is 90% that the sample percentage is contained within what symmetrical limits of the population percentage

Answers

Answer:

the probability is 90% that the sample percentage is contained within 45.5% and 54.5% symmetric limits of the population percentage.

Step-by-step explanation:

From the given information:

Sample size n = 200

The standard deviation for a sampling distribution for two brands are equally likely because the individual has no ability to discriminate between the two soft drinks.

The population proportion [tex]p_o[/tex] = 1/2 = 0.5

NOW;

[tex]\sigma _p = \sqrt{\dfrac{p_o(1-p_o)}{n}}[/tex]

[tex]\sigma _p = \sqrt{\dfrac{0.5(1-0.5)}{200}}[/tex]

[tex]\sigma _p = \sqrt{\dfrac{0.5(0.5)}{200}}[/tex]

[tex]\sigma _p = \sqrt{\dfrac{0.25}{200}}[/tex]

[tex]\sigma _p = \sqrt{0.00125}[/tex]

[tex]\sigma _p = 0.035355[/tex]

However, in order to determine the symmetrical limits of the population percentage given that the z probability is 90%.

we use the Excel function as computed as follows in order to determine the z probability  = NORMSINV (0.9)

z value = 1.281552

Now the symmetrical limits of the population percentage can be determined as: ( 1.28, -1.28)

[tex]1.28 = \dfrac{X - 0.5}{0.035355}[/tex]

1.28 × 0.035355 = X - 0.5

0.0452544= X - 0.5

0.0452544 + 0.5 = X

0.5452544 = X

X [tex]\approx[/tex] 0.545

X = 54.5%

[tex]-1.28 = \dfrac{X - 0.5}{0.035355}[/tex]

- 1.28 × 0.035355 = X - 0.5

- 0.0452544= X - 0.5

- 0.0452544 + 0.5 = X

0.4547456 = X

X [tex]\approx[/tex] 0.455

X = 45.5%

Therefore , we can conclude that the probability is 90% that the sample percentage is contained within 45.5% and 54.5% symmetric limits of the population percentage.

4/17 + 3/10 + 9/20 + 3/11 + 7/15

Answers

Answer:

[tex]\frac{19351}{11220}[/tex]

Step-by-step explanation:

[tex]\frac{2640+3366+5049+3060+5236}{11220} = \frac{19251}{11220}[/tex]

Salina currently has an account balance of $1,047.69. Her initial deposit on the account was $630 and it earned 3.9% simple interest. How long has Salina held the account?

A - 17 years

B - 26 years

C - 10 years

D - 43 years

Answers

Answer:

A. 17 years

Step-by-step explanation:

Use the simple interest equation, I = prt, where I is the interest money gained, p is the starting amount of money, r is the interest rate in decimal form, and t is the time in years.

Plug in the values to solve for t:

417.69 = (630)(0.039)(t)

417.69 = 24.57t

17 = t

= 17 years

So, the correct answer is A, 17 years

Chris wanted to know how likely he is to win at his favorite carnival game. He conducted 50 tests and won 15 times. What is the probability that he will win next time he plays? All answers are rounded to the nearest hundredth. a.) 0.15 b.) 0.30 c.) 0.50 d.) 0.35 SUBMIT MY ANSWER g

Answers

Answer:

b.) 0.30

Step-by-step explanation:

15/50 = 0.3

If f(x)=logx, show that f(x+h)-f(x)/h=log[1+h/x]^1/h, h=/=0 (Picture attached, thank you!)

Answers

Answer:

Step by step proof shown below.

Step-by-step explanation:

To prove the equation, you need to apply the Logarithm quotient rule and the Logarithm power rule. Here's how the quotient rule looks like.

[tex]log_b(x/y) = log_b(x) - log_b(y)[/tex]

And here's how the power rule looks like

[tex]log_a(x)^n = nlog_a(x)[/tex]

First let's apply the quotient rule.

[tex]\frac{f(x+h)-f(x)}{h} = \frac{log_a(x+h)-log_a(x) }{h} = \frac{log_a(\frac{x+h}{x} )}{h}[/tex]

Now we can do some quick simplification, and apply the power rule.

[tex]\frac{1}{h} log_a(1 + \frac{h}{x} ) = log_a(1+\frac{h}{x} )^\frac{1}{h}[/tex]

Find the value of the variable(s) in each figure. Explain your reasoning. Thank you in advance

Answers

Answer:

1. x 55

2. y 117

x 51

3.x39

y116

4.x 18

5.x 48

y 14

for the last one I'm not sure. please give 5 start

Find x in each triangle. PLZ ANSWER FAST!!!!!!!!!!!

Answers

a) a^2 + b^2 = c^2
c^2 - a^2 = b^2
13^2 - 5^2 = b^2
b = 12dm

b) a^2 + b^2 = c^2
10^2 + 24^2 = c^2
c = 26 in

c) a^2 + b^2 = c^2
c^2 - a^2 = b^2
17^2 - 8^2 = b^2
b = 15 ft

The following sample contains the scores of 6 students selected at random in Mathematics and English. Use the scores in English as the dependent variable Y.

Mathematics score (X) 70 92 80 74 65 83
English score 74 84 63 87 78 90

Σx =464 Σy=476 Σx^2= 36354 Σy^2=38254 Σxy= 36926

Find the sample coefficient of determination and interpret.

a. 0.0575 and prediction accuracy is 5.75%
b. 0.2397 and prediction accuracy is 23.97%
c. 0.0575 and prediction accuracy is 94.25%
d. 0.2397 and prediction accuracy is 76.03%

Answers

Answer:

d the answer is d

Step-by-step explanation:

HCF of x minus 2 and X square + X - 6 ​

Answers

Answer:

[tex] \boxed{ \sf{ \bold{ \huge{ \boxed{x - 2}}}}}[/tex]

Step-by-step explanation:

[tex] \sf{x - 2} \: and \: { {x}^{2} + x - 6}[/tex]

To find the H.C.F of the algebraic expressions, they are to be factorised and a common factor or the product of common factors is obtained as their H.C.F

Let's solve

First expression = x - 2

Second expression = x + x - 6

Here, we have to find the two numbers which subtracts to 1 and multiplies to 6

= x + ( 3 - 2 ) x + 6

Distribute x through the parentheses

= x + 3x - 2x + 6

Factor out x from the expression

= x ( x + 3 ) - 2x + 6

Factor out -2 from the expression

= x ( x + 3 ) - 2 ( x + 3 )

Factor out x+3 from the expression

= ( x + 3 ) ( x - 2 )

Here, x - 2 is common in both expression.

Thus, H.C.F = x - 2

Hope I helped!

Best regards!!!

Answer:

x - 2

Step-by-step explanation:

by factorization method

1) x - 2

2) x^2 + x - 6

by splitting method

x^2 + 3x - 2x - 6

taking separate common from the first two terms and last two terms

x(x + 3) - 2(x + 3)

now writing x+3 once and the other term to get the right answer

(x + 3)(x - 2)

in both parts just see the similar term and write it as HCF

HCF= x - 2

and the second method by which you can get this answer is division method

The amount of money spent on textbooks per year for students is approximately normal.
a. To estimate the population mean, 19 students are randomly selected the sample mean was $390 and the standard deviation was $120. Find a 95% confidence for the population meam.
b. If the confidence level in part a changed from 95% 1to1999%, would the margin of error for the confidence interval (mark one answer): decrease stay the same increase not enough information to answer
c. If the sample size in part a changed from 19 10 22. would the margin of errot for the confidence interval (mark one answer): decrease in stay the same increase in not enough information to answer
d. To estimate the proportion of students who purchase their textbookslused, 500 students were sampled. 210 of these students purchased used textbooks. Find a 99% confidence interval for the proportion of students who purchase used text books.

Answers

Answer:a

a

   [tex]336.04 < \mu < 443.96[/tex]

b

  The  margin of error will increase

c

The  margin of error will decreases

d

The 99% confidence interval is  [tex]0.4107 < p < 0.4293[/tex]

Step-by-step explanation:

From the question we are  told that

   The sample size  [tex]n = 19[/tex]

    The sample mean is  [tex]\= x = \$\ 390[/tex]

    The  standard deviation is  [tex]\sigma = \$ \ 120[/tex]

 

Given that the confidence level is  95% then the level of significance is mathematically represented as

           [tex]\alpha = 100 - 95[/tex]

          [tex]\alpha = 5 \%[/tex]

          [tex]\alpha = 0.05[/tex]

Next we obtain the critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table

    So  

         [tex]Z_{\frac{\alpha }{2} } = 1.96[/tex]

The  margin of error is mathematically represented as

      [tex]E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }[/tex]

=>    [tex]E = 1.96 * \frac{120}{\sqrt{19} }[/tex]

=>   [tex]E = 53.96[/tex]

The 95% confidence interval is  

     [tex]\= x - E < \mu < \= x + E[/tex]

=>   [tex]390 - 53.96 < \mu < 390 - 53.96[/tex]

=>  [tex]336.04 < \mu < 443.96[/tex]

When the confidence level increases the [tex]Z_{\frac{\alpha }{2} }[/tex] also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

         [tex]n \ \ \alpha \ \ \frac{1}{E^2 }[/tex]

So if the sample size increases the margin of error decrease

The  sample proportion is mathematically represented as

       [tex]\r p = \frac{210}{500}[/tex]

       [tex]\r p = 0.42[/tex]

Given that the confidence level is 0.99 the level of significance is  [tex]\alpha = 0.01[/tex]

The critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table is  

      [tex]Z_{\frac{\alpha }{2} } = 2.58[/tex]

  Generally the margin of error is mathematically represented as

       [tex]E = Z_{\frac{\alpha }{2} }* \sqrt{ \frac{\r p (1- \r p )}{n} }[/tex]

=>   [tex]E = 0.42 * \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }[/tex]

=>     [tex]E = 0.0093[/tex]

The 99% confidence interval  is

     [tex]\r p - E < p < \r p + E[/tex]

     [tex]0.42 - 0.0093 < p < 0.42 + 0.0093[/tex]

     [tex]0.4107 < p < 0.4293[/tex]

 

Write x2 − 2x − 3 = 0 in the form (x − a)2 = b, where a and b are integers. (1 point) (x − 4)2 = 3 (x − 3)2 = 2 (x − 2)2 = 1 (x − 1)2 = 4

Answers

Answer:

Answer is (x - 1)² = 4

Step-by-step explanation:

[tex]{ \tt{ {x}^{2} - 2x - 3 = 0}} \\ [/tex]

By completing squares:

[tex]{ \tt{ {x}^{2} - 2x + { (\frac{2}{2} )}^{2} - 3 - {( \frac{2}{2}) }^{2} = 0 }} \\ { \tt{( {x}^{2} - 2x + 1) = 4}} \\ { \tt{(x - 1) {}^{2} = 4 }}[/tex]

[tex]{ \underline{ \sf{ \blue{christ \:† \: alone }}}}[/tex]

HELP ASAP

What is the area of the circle shown below?

Answers

Answer:

C

Step-by-step explanation:

The area (A) of a circle is calculated as

A = πr² ( r is the radius )

Here r = 18 cm , thus

A = π × 18² = 324π ≈ 1017.9 cm² → C

Answer:

C.) 1017.9 cm²

Step-by-step explanation:

For a given circle

radius (r) = 18 cm

Now,

Area of Circle

= πr²

= 3.14 × (18)² cm

= 3.14 × 324 cm

= 1017.9 cm²

Plz answer quick will give good rate and thanksss
h(x) = (x - 3)^2 determine which x-value whether it is in the domain of h or not

In domain not in domain
0
3
4

Answers

Answer:

Hey there!

All of the values: 0, 3, and 4 are in the domain.

This is because h(x) = (x - 3)^2 is a parabola, or a quadratic. By definition, the domain, or the possible x values of a parabola are infinite.

Hope this helps :)

Use De Moivre's theorem to find the indicated power of the complex number. Write the answer in rectangular form.[2(cos10∘ + i sin10∘)]^3.

Answers

Answer:

[tex]\bold{4\sqrt3 + i4}[/tex]

Step-by-step explanation:

Given complex number is:

[tex][2(cos10^\circ + i sin10^\circ)]^3[/tex]

To find:

Answer in rectangular form after using De Moivre's theorem = ?

i.e. the form [tex]a+ib[/tex] (not in forms of angles)

Solution:

De Moivre's theorem provides us a way of solving the powers of complex numbers written in polar form.

As per De Moivre's theorem:

[tex](cos\theta+isin\theta)^n = cos(n\theta)+i(sin(n\theta))[/tex]

So, the given complex number can be written as:

[tex][2(cos10^\circ + i sin10^\circ)]^3\\\Rightarrow 2^3 \times (cos10^\circ + i sin10^\circ)^3[/tex]

Now, using De Moivre's theorem:

[tex]\Rightarrow 2^3 \times (cos10^\circ + i sin10^\circ)^3\\\Rightarrow 8 \times [cos(3 \times10)^\circ + i sin(3 \times10^\circ)]\\\Rightarrow 8 \times (cos30^\circ + i sin30^\circ)\\\Rightarrow 8 \times (\dfrac{\sqrt3}2 + i \dfrac{1}{2})\\\Rightarrow \dfrac{\sqrt3}2\times 8 + i \dfrac{1}{2}\times 8\\\Rightarrow \bold{4\sqrt3 + i4}[/tex]

So, the answer in rectangular form is:

[tex]\bold{4\sqrt3 + i4}[/tex]

Suppose there is a 11.3% probability that a randomly selected person aged 30 years or older is a smoker. In​ addition, there is a 23.3% probability that a randomly selected person aged 30 years or older is male given that he or she smokes. What is the probability that a randomly selected person aged 30 years or older is male and smokes? Would it be unusual to randomly select a person aged 30 years or older who is
male and smokes?

Answers

Answer:

2.63%

Step-by-step explanation:

11.3/100*23.3/100*100%

if the numbers x+3,2x+1and x-7are in AP then find x​

Answers

Answer:

  -3

Step-by-step explanation:

If these numbers are part of an arithmetic progression, their differences are the same:

  (x -7) -(2x +1) = (2x +1) -(x +3)

  -x -8 = x -2

  -6 = 2x

  -3 = x

___

The numbers in the sequence are 0, -5, -10.

Answer:

x = -3.

Step-by-step explanation:

As it is an Arithmetic Progression the differences between successive terms are common, so:

2x + 1 - (x + 3) = x - 7 - (2x + 1)

2x - x + 1 - 3 = x - 2x - 7 - 1

x - 2 = -x - 8

2x = -8 + 2 = -6

x = -3.

find the greatest number that divides 56 and 84 exactly​

Answers

Answer:

28

Step-by-step explanation:

Find the gcf

A department store offers two promotions. Promotion A says, "Buy one pair of shoes, get the second pair for half the price." Promotion B says, "Buy one pair of shoes, get $10 off the second pair." Jane wants to buy two pairs of shoes that cost $30 each. She can only use one of the promotions, A or B. Jane decides to use the promotion that will save her the most money. How many dollars does Jane save by picking one promotion over the other? (For example, if Jane spends $150 on her purchase by using one promotion and $100 on her purchase by using the other promotion, she saves $150-100=50$ dollars by using the second promotion over the first.)

Answers

Answer:

$5

Step-by-step explanation:

Using Promotion A, Jane would buy the first pair for $30 and the second for 1/2 * 30 = $15 for a total of 30 + 15 = $45. Using Promotion B, she would buy the first pair for $30 and the second for 30 - 10 = $20 for a total of 30 + 20 = $50. Since 45 < 50, Promotion A is the better deal, so Jane would save 50 - 45 = $5.

find the product
(4\m+m)(4/m-m)

Answers

[tex]\\ \sf\longmapsto \dfrac{4}{m+m}\times \dfrac{4}{m-m}[/tex]

[tex]\\ \sf\longmapsto \dfrac{4\times 4}{(m+m)(m-m)}[/tex]

[tex]\boxed{\sf (a-b)(a+b)=a^2-b^2}[/tex]

[tex]\\ \sf\longmapsto \dfrac{16}{m^2-m^2}[/tex]

[tex]\\ \sf\longmapsto \dfrac{16}{0}[/tex]

[tex]\\ \sf\longmapsto \infty[/tex]

Answer:

(16-m^4)/m^2

Step-by-step explanation:

=([tex]\frac{4}{m}[/tex]+m)([tex]\frac{4}{m}[/tex]-m)

=[tex]\frac{4+m^2}{m}[/tex]*[tex]\frac{4-m^2}{m}[/tex]  (LCM)

[tex]\frac{16-m^4}{m^2}[/tex] (a-b)(a+b)

Beer shelf life is a problem for brewers and distributors because when beer is stored at room temperature, its flavor deteriorates. When the average furfuryl ether content reaches 6 μg per liter, a typical consumer begins to taste an unpleasant chemical flavor. At α = .05, would the following sample of 12 randomly chosen bottles stored for a month convince you that the mean furfuryl ether content exceeds the taste threshhold? 8.92 6.99 5.54 5.73 6.38 5.51 6.45 7.50 8.48 5.56 6.90 6.46

Answers

Answer:

As the calculated value of t =2.1698 is greater than t (0.05,11) = 1.796 reject H0 . It means  chosen bottles stored for a month convince you that the mean furfuryl ether content exceeds the taste threshhold.

Step-by-step explanation:

We formulate our null and alternative hypotheses as

H0 u≤ 6 ug     Ha : u > 6 ug

The significance level ∝ = 0.05

The test statistic used is

t = X` - u / s/ √n

which if H0 is true, has the students' t test with n-1 = 11 degrees of freedom.

The critical region t > t (0.05,11) = 1.796

We compute the t value from the data

Xi               Xi²

8.92         79.5664

6.99          48.8601

5.54          30.6916

5.73           32.8329

6.38           40.7044

5.51            30.3601

6.45           41.6025

7.50           56.25

8.48           71.9104

5.56          30.9136

6.90          47.61

6.46          41.7316          

80.42         553.0336      

Now x` = ∑x/ n = 80.42/12 = 6.70

S²= 1/n-1 ( ∑(xi- x`)²= 1/11 ( 553.034 - (80.42)²/12)

= 1/11 (553.034-538.948) = 1.2805

s= 1.1316

Putting the values in the test statistics

t = X` - u / s/ √n = 6.70- 6 / 1.1316 / √12

= 2.1698

The critical region t > t (0.05,11) = 1.796

As the calculated value of t =2.1698 is greater than t (0.05,11) = 1.796 reject H0 . It means  chosen bottles stored for a month convince you that the mean furfuryl ether content exceeds the taste threshhold.

Write
801
1000
as a decimal number.

Answers

Answer:

0.801

Step-by-step explanation:

Answer:

0.801

Step-by-step explanation:

801/1000 = 0.801

A person collected ​$700 on a loan of ​$600 they made 5 years ago. If the person charged simple​ interest, what was the rate of​ interest? The interest rate is ​%. ​(Type an integer or decimal rounded to the nearest hundredth as​ needed.)

Answers

Answer:

Rate= 3 1/3%

Or Rate= 3.33%

Step-by-step explanation:

Final amount collected= $700

Initial amount given out= $600

Interest made= Final amount - initial amount

Interest made= $700-$600

Interest made= $100

Type of interest rate = simple

Number of years = 5

PRT/100= interest

R=(100*interest)/(PT)

R= (100*100)/(600*5)

R= 10000/3000

R= 10/3

R= 3 1/3%

Or R= 3.33%

how do you change a hot air baloon descends 200 feet per minute from a altitude of 1000 feet into a algebraic expression.

Answers

y = 1000-200x where x is the number of minutes and y is the altitude of the balloon

In the figure below. MN is the arc of a circle with center L. If the length of arc MN is 6π, what is the area of sector LMN?

Answers

On a number​ line, the coordinates of​ X, Y,​ Z, and W are −7​, −2​, 2​, and 7​, respectively. Find the lengths of the two segments below. Then tell whether they are congruent. XY and

A loaf of bread costs $1.40 and the markup is 30% of the selling price. Find the selling price.

Answers

Answer:

The selling price after the markup is $1.82

Step-by-step explanation:

$1.40 * .30 =

Multiply $1.40 times .30 (which is same as 30%)

$1.40 * .30 = $0.42

Add $1.40 and $0.42

= $1.82

Hope this helps.

Other Questions
Ruben goes to a shop to buy 24.5m of cloth and 13.5m ribbon. The cloth costs Rs.85.40 per metre and the ribbon costs Rs.8.5 per metre. If he pays Rs. 2300 to the shopkeeper, how much money will he get back? The beta of company Myerss stock is 2. The annual risk-free rate is 2% and the annual market premium is 8%. What is the expected return for Myers stock? A. 14% B. 25% C. 20% D. 18 How do people use their bodies and voices to communicate different emotions? What do individual behaviors indicate about their feelings toward one another or their social rank? write a letter to invite your friend to your birthday party in french What is the probability of the complement of rolling a number less than 5 by using a six sided dye Discuss Machiavelli's beliefs about the state. help it's due in 20 minutes Write the names of any four newly established universities of Nepal and mention the role they can play for transforming society. help for abunch of points. How does 4D Shape look like? and, do (4 < n)D are possible? Based on this map, which of the following countries would you expect to have the least opportunity for citizen political participation?A. CanadaB. MexicoC. EgyptD. Italy Kindly help me here Find the least number which added to 3597 will make it a perfect square? Based on these documents, what socioeconomic and sociopolitical conditions in late medieval Europe do you think combined to infantilize women and severely limit their legal rights? Factor the following expression completely:32z4+8z34z2 If you know the answer please help me When did the CIAwrite this brief? What was going on in the U.S. atthis time? Find th slope of the line passing through the points (5,8) and (6,12) 1) At AJ Welding Company they employ 253 people, 108 employees receive 2 weeks of paid 1) _______ vacation each year. Find the ratio of those who receive 2 weeks of paid vacation to those whose paid vacation is not 2 weeks. PLEASE HELP !! (4/5) -50 POINTS-