question down below need rply fast

The Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x [tex]10^{24}[/tex] Kg

Linear speed is the product of angular speed and the maximum displacement of the particle. That is,

V = Wr

Where

Given that the earth orbits the sun at an average circular radius of about 149.60 million kilometers every 365.26 Earth days.

a) To determine the Earth’s average orbital speed, we will make use of the below formula to calculate angular speed

W = 2[tex]\pi[/tex]/T

W = (2 x 3.143) / (365.26 x 24)

W = 6.283 / 876624

W = 7.2 x [tex]10^{-4}[/tex] Rad/hr

The Earth’s average orbital speed V = Wr

V = 7.2 x  [tex]10^{-4}[/tex] x 149.6 x [tex]10^{6}[/tex]

V = 107225.5 kilometers per hours.

b) Based on the information given in this question, to calculate the approximate mass of the Sun, we will use Kepler's 3rd law

M = (4[tex]\pi ^{2}[/tex][tex]r^{3}[/tex]) / G[tex]T^{2}[/tex]

M = (4 x 9.8696 x 3.35 x [tex]10^{24}[/tex]) / (6.67 x [tex]10^{-11}[/tex] x 7.68 x [tex]10^{11}[/tex])

M = 1.32 x [tex]10^{26}[/tex] / 51.226

M = 2.58 x [tex]10^{24}[/tex] Kg

Therefore, the Earth’s average orbital speed expressed in kilometers per hours is 107225.5 Km/hr and the mass of the sun is 2.58 x [tex]10^{24}[/tex] Kg

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The weight required to stretch the spring 12.5 cm is 7.5 N (Option A)

The new weight required to stretch the spring can be obtained as follow:

W₁ / L₁ = W₂ / L₂

3 / 5 = W₂ / 12.5

Cross multiply

W₂ × 5 = 3 × 12.5

Divide both sides by 5

W₂ = (3 × 12.5) / 5

W₂ = 7.5 N

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The average acceleration in the first 10 seconds of the journey is 2 m/s²; option B.

Acceleration is the rate of change of velocity with time.

From the graph;

Acceleration in first  seconds = 20 - 0/5 = 4 m/s²

Acceleration in second 5 seconds = 0

Average acceleration = 4 + 0/2

Average acceleration = 2 m/s²

In conclusion, average acceleration is the average of the final and initial acceleration.

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The speed with which the puck must rotate in the circular path is 5.42 m/s.

The speed of the puck is calculated as follows;

centripetal force = weight of hanging mass

mv²/r = W

where;

v² = Wr/m

v² = (1.2 x 9.8 x 0.5) / (0.2)

v² = 29.4

v = √29.4

v = 5.42 m/s

Thus, the speed with which the puck must rotate in the circular path is 5.42 m/s.

The complete question is below:

With what speed must the puck rotate in a circle of radius 0.50 m if the block is to remain hanging at rest?

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400 J power will be delivered by lifting a stone of mass 2 kg at the height of 20m in two minutes.

The quantity of energy transferred or transformed per unit of time is known as power. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as an activity in ancient writings. A scalar quantity is a power.

Work completed and time is linked in the power equation. Since forces may move objects and we know that forces perform work, we might anticipate that by understanding the power, we can gain insight into how a body moves through time. This outcome may be especially beneficial.

Given that, a stone ‘X’ of mass 2 kg is lifted to the height of 20m in two minutes, and g=10 m/s-2

Power Delivered = Work done in lifting the stone

Work Done = Potential energy = mgh

Work done = 2 × 10 × 20

Work done = 400 J

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Vega, the brightest star in the constellation lyra, has a parallax angle of approximately 0.13 arcseconds,  approximately  Vega will be 25.076 Light year or 7.692 Parsec away from the sun

The parallax angle is the angle between the Earth at one time of year, and the Earth six months later, as measured from a nearby star.

Mathematically it can be understood as that the parallax angle is the angle which is taken from a point at one time on the earth and again after six months later from the same point on the earth. The parallax angle is the semi-angle of inclination between the two lines to sight.

Stellar parallax is the basis for the parsec, which is the distance from the Sun to an astronomical object that has a parallax angle of one arcsecond.

Distance (in parsec) = 1 / (parallax angle ( arcsec))

given

parallax angle = 0.13 arcseconds

Distance (in parsec) = 1/ 0.13 = 7.692 Parsec

if 1 Parsec = 3.26 Light year

So, 7.692 Parsec will be equal to =  3.26 * 7.692 = 25.076 Light year

                                                        ≈ 25.076 Light year

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The mechanical power expended when transporting the wheelchair is 25 Watts

Power is defined as  the amount of energy transferred or converted per unit time. The unit of power is measured in Watts. The higher units are kilowatts, megawatts etc.

The formula for calculating the power expended is expressed as:

Power = Workdone/Time

Since workdone = force * distance, the formula for power will be:

Power = Force*distance/Time

Given the following parameters

Force = 50N

distance = 0.5m

time = 1 second

Substitute to determine the power

Power = 50*0.5/1

Power = 25/1

Power = 25Watts

Hence the mechanical power expended when transporting the wheelchair is 25 Watts

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Two worlds in the outer solar system that seem remarkably similar to each other are: Triton and Pluto

The outer solar system comprises the next four planets and everything beyond the planet Neptune but within the gravitational pull of the Sun. The Kuiper Belt and the Oort Cloud are also parts of the outer region.

Triton is only slightly larger than Pluto. Both worlds have similar surface materials, such as nitrogen, methane and carbon monoxide. Their diameters, masses and densities are also similar. Both Triton and Pluto may also have originated within the Kuiper Belt. Triton is thought to be originally a Kuiper Belt Object that was captured by Neptune's gravity.

Because Triton and Charon-Pluto are both from the Kuiper belt they are both made of similar materials such as nitrogen, methane, carbon dioxide and water ice. Both  have large cores that are made primarily of rock with mantles of water ice and crusts made of frozen nitrogen. Neither of them have a magnetic field.

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While measuring , there are a lot of errors which can happen due to which ""true distances"" be different for different groups even though they are measuring the same distance.

While measuring , there are a lot of errors which can happen , to find the most correct value in order to make the result precise and accurate number of measurements needed to be done in order to reduce the error

As nothing can be measured with full precision and accuracy, different measurements for different groups even though they are measuring the same distance.

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From counting craters on each asteroids , astronomers have realized that the surface of ida is older than the surface of gaspra.

Ida, and Gaspra are three objects located in the asteroid belt between Mars and Jupiter.

Crater counting is a method for estimating the age of a planet's surface based upon the assumptions that when a piece of planetary surface is new, then it has no impact craters; impact craters accumulate after that at a rate that is assumed known.

Counting how many craters of various sizes there are in a given area allows determining how long they have accumulated and consequently, how long ago the surface has formed. Hence , from counting craters on each asteroids ,astronomers have realized that the surface of ida is older than the surface of gaspra.

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The path the bowling ball would most closely follow after leaving the airplane is horizontal direction.

Based on the law of inertia, which is the reluctance of an object to stop moving once in motion or start moving when it is at rest.

The bowling ball will maintain the path of the airline in the first few seconds of fall, after which it will change its path to vertical direction.

Thus, the path the bowling ball would most closely follow after leaving the airplane is horizontal direction.

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The velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.

The velocity of the boy when he hits the water at the bottom of the slide is calculated from the principle of conservation of energy.

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

v = √(2 x 9.8 x 10)

v = 14 m/s.

Thus, the velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.

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The acceleration Block A is derived as a= 11.983ft/s². See explanation below.

Recall that we are given the following:

Radium = 20 inches

Weight = 330lbs

Radius of gyration = 15in

Mass of Block = 110lb

The formula for Moment of Inertia is also given as:

I = mk²

= 330 [ 15/12]²

I = 515.625 lb/ft²

To derive the moment about O, we recourse to

∈M₀ = I∝

TR =  I∝

T [20/12] = 515.625 ∝

T = 309.375∝

Next, to derive the weight of the block A hanging freely,

Wa = MAg

= 110 x 32.2

= 3542 lbf

Acceleration is derived by

A = r∝

= [20/12] ∝

a = 1.667 ∝.........Lets call this equation 1

Value of the acceleration derived by Dalembert Principle

∈Fy = mAa

Wa-T = mAa

3542 - 309.375∝ = 110 x 1.667∝

3542 = 492.745∝

∝ = 7.8188 Rad/s²............Lets call this equation 2

Substituting the value of ∝ in equation 1, we have

a = 1.667∝

= 1.667 x 7.1883

a = 11.983 ft/s²

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The pressure in the hose as the speed of water changes from 2.05 m/s to 31.4 m/s as it goes through the nozzle is 5.92 × 10⁵ N/m².

Given:

The flow of water through the hose initially, v₁ = 2.05 m/s

The flow of water through the hose initially, v₂ = 31.4 m/s

Calculation:

From Bernoulli's equation we have:

P₁ + 1/2 ρv₁² + ρgh₁ = P₂ + 1/2 ρv₂² + ρgh₂

where P₁ is atmospheric pressure

           P₂ is the pressure in the hose

           ρ is the density of the fluid

           h₁ is the initial height

           h₂ is the final height

           v₁ is the initial velocity of the fluid

           v₂ is the final velocity of the fluid  and

           g is the acceleration due to gravity

Re-arranging the above equation we get:

P₂ = P₁ + 1/2 ρ(v₁²-v₂²) + ρg (h₁-h₂)

Applying values in the above equation we get:

P₂ = P₁ + 1/2 ρ(v₁²-v₂²) + ρg (0)

    = (1.01 × 10⁵ Pa)+ 1/2 (10³ g/m³) [(31.4m/s)²-(2.05 m/s)²]

    = (1.01 × 10⁵ Pa)+ 1/2 (10³ g/m³) [981.7575]

    = (1.01 × 10⁵ Pa)+ (4.91 × 10⁵ Pa)

    = 5.92 × 10⁵ Pa

    = 5.92 × 10⁵ N/m²

Therefore, the pressure in the hose is 5.92 × 10⁵ N/m².

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The ice melts because Thermal energy from Jan’s hand is transferred to the ice.

Thermal energy is the energy due to temperature difference.

Thermal energy flows from hotter to colder bodies.

The ice Jan is holding melts because heat is transferred from his hands t the ice.

In conclusion, thermal energy flow causes melting.

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Answer:

its b

Explanation:

because the heat from your hand makes the ice melt!

The forces listed are considered fundamental forces (2) gravitational (4) strong nuclear (6) electroweak.

Fundamental force, also called fundamental interaction, in physics, is any of the four primary forces—gravitational, electromagnetic, sturdy, and weak—that govern how gadgets or particles interact and how certain particles decay. All of the regarded forces of nature may be traced to those essential forces.

Now, physicists say they have discovered viable symptoms of a fifth essential force of nature. The findings come from studies performed at a laboratory near Chicago. The four fundamental forces govern how all of the objects and particles inside the Universe engage with each other.

The strong nuclear pressure pulled definitely and negatively charged quarks collectively to form undoubtedly charged protons and neutrally charged neutrons. The strong nuclear force also binds protons and neutrons within the nucleus of atoms. The weak nuclear force enabled complicated atoms to form through nuclear fusion.

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(b) when the magnetic field gets stronger.

correct option :

When a loop rest in the plane of the page and magnetic field is directed into the page then we will apply here right hand thumb rule in which thumb represent the direction of magnetic field and curling fingers represent direction of induced current. So, in this case the direction of magnetic field is into the page and curling fingers shows induced current in clockwise direction.

  Thus, option (b) is correct.

Incorrect options:

   option (A) is incorrect because when magnetic field will change  

     according to flux.

   option (C) is incorrect because field is stronger so it does not matter

     size of loop increases or decreases.

   option (D) is incorrect because it moves any other side the field will be

     stronger.

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[Your question is incomplete, but most probably your full question was-Check all that apply:

A. when the magnetic field is tilted so it is no longer perpendicular to the page

B. when the magnetic field gets stronger

C. when the size of the loop decreases

D. when the loop is moved sideways across the page]

Answer:

power p =24 watt

charge q=120 C

time t = 60s

let V be the potential difference

we know that

work done =qV = pt

qV = Pxt

120V = 24 * 60

V = (24 * 60) / 120

V = 12 volts

Answer:

As light from a star races through our atmosphere, it bounces and bumps through the different layers, bending the light before you see it. Since the hot and cold layers of air keep moving, the bending of the light changes too, which causes the star's appearance to wobble or twinkle.

As the number of protons in an atom’s nucleus increases, the number of electrons must increase to maintain the atom’s overall neutral charge; option B.

Atomic number is the number of protons present in the nucleus of an atom.

The atomic number of atoms of elements increase with increase in atomic number.

In conclusion, atomic number increases the size down a group and decreases atomic size across a period.

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Pelvic girdle

In human anatomy, the pelvis is a complex of bones that connects the trunk and the legs, supports and balances the trunk, and houses and supports the intestines, the urinary bladder, and the internal organ. It is sometimes referred to as the bony pelvis or the pelvic girdle.
One is located on the left side of the body and the other is located on the right. They come together to make the pelvic girdle, a portion of the pelvis. The hip bones are attached to the upper portion of the skeleton at the sacrum.
The pelvic girdle's main function is to support the upper body's weight while seated and transfer that weight to the lower limbs while standing. For the muscles in the trunk and lower limbs, it functions as attachment point.

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The hypothetical upper limit to the mass a star can be before it self-destructs due to the massive amount of fusion it would produce is apparently as a result of Eddington luminosity

Stars are a fixed luminous point in the sky which is a large and remote incandescent body

So therefore, the hypothetical upper limit to the mass a star can be before it self-destructs due to the massive amount of fusion it would produce is apparently as a result of Eddington luminosity

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The net force on particle particle q1 is 13.06 N towards the left.

F(12) = kq₁q₂/r₂

F(12) = (9 x 10⁹ x 13 x 10⁻⁶ x 7.7 x 10⁻⁶)/(0.25²)

F(12) = -14.41 N  (towards left)

F(13) = (9 x 10⁹ x 7.7 x 10⁻⁶ x 5.9 x 10⁻⁶)/(0.55²)

F(13) = 1.352 N (towards right)

F(net) = 1.352 N - 14.41 N

F(net) = -13.06 N

Thus, the net force on particle particle q1 is 13.06 N towards the left.

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Answer:

its +

Explanation:

According to motion in straight line  t1≠t2

A biker travels d1 meters in t1 seconds at v1 m/s for the first leg and d2 meters in t2 seconds at v2 m/s for the second leg. It's possible that t1t2 if his average speed is equal to the average of v1 and v2.
An object is said to be in motion if its position in relation to its surroundings changes over time. It is a shift in an object's position over time. The only type of motion that exists is motion in a straight line.

A reference system is constantly used to describe a particle's motion. An arbitrary origin point is used to create a reference system, and a coordinate system is imagined to be connected to it. The reference system for a specific problem is the coordinate system that has been selected for it. For the majority of the problems, we typically select an earth-based coordinate system as the reference system.

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Answer:

As light from a star races through our atmosphere, it bounces and bumps through the different layers, bending the light before you see it. Since the hot and cold layers of air keep moving, the bending of the light changes too, which causes the star's appearance to wobble or twinkle.

The diameter of the largest orbit just before the protons exit the cyclotron is 39 cm.

The number of orbits completed by the proton during this 1.0 ms is 14000 revolutions.

The kinetic energy for the protons can be computed by using the formula:

mv² = 2 K.E

v = sqrt( 2*KE / M)

the kinetic energy of the medical isotopes = 6.5 MeV

substituting the values,

v = sqrt( 2* 6.5* 1.6* 10^-13 / 1.67* 10^-27 )

v = 3.53 × 10⁷ m/s

The radius of the orbit can be estimated by using the formula:

mv² / R = qvB

r = q*v / mv²

r = ( 1.67* 10^-27 * 3.53 × 10⁷ ) / ( 1.9* 1.6* 10^-19 )

r = 0.19415 m

Since diameter (D) = 2r,

D= 2(0.19415  m)

D= 0.39 m

D≅ 39 cm

The time period to complete a revolution around the spiral trajectory is:

T = 2πr / v

T = 2*3.14* 0.1941 / 3.53*10^7

T = 0.7 × 10⁻⁷ s

Finally, the number of orbits that the proton does to complete the revolution in 1 ms is:

n = t / T

n = 10^-3 / (0.7*10^-7)

n = 14285.71

n ≅ 14000 revolutions

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Your question is incomplete, but most probably full question was:

A medical cyclotron used in the production of medical isotopes accelerates protons to 6.5 MeV. The magnetic field in the cyclotron is 1.9 T.

(a) What is the diameter of the largest orbit, just before the protons exit the cyclotron? Express your answer with the appropriate units. d = 57 cm Previous

(b) A proton exits the cyclotron 1.0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1.0 ms?

Answer:

200 m / min

Explanation:

Total distance = 2000 m

Total time = 2+4+1+3 = 10 minutes

Average speed = 2000 m / 10 min = 200 m/min

Work is being done when Jessica pushes a 25 kilogram cart a distance of 10 meters and Bane carries a 20 kilogram box a distance of 50 meters.

Work is the product of force and distance in the direction of the force. And the S.I unit of work is Joule

Looking at the given options one by one;

O Jessica pushes a 25 kilogram cart a distance of 10 meters. Work is done by Jessica. The work done = 25 x 10 x 10 = 2500 Joules

O A weightlifter holds a 100 kilogram barbell over his head. The weightlifter does no work.

O Bane carries a 20 kilogram box a distance of 50 meters. Bane does work. The work done = 20 x 10 x 10 = 2000 Joules

O Ali is trying to push a truck away from the parking lot. Since there is no movement, there is no work done.

Therefore, Work is being done when Jessica pushes a 25 kilogram cart a distance of 10 meters and Bane carries a 20 kilogram box a distance of 50 meters.

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[tex] \large{ \boxed{ \tt{447.3 \: m}}}[/tex]

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The tangential speed of a lug nut on a wheel of a car will be 4.68 m/s

Given:

Distance of lug nut = 0.114 m

wheel is rotating at speed = 6.53 rev/sec

To Find:

tangential speed of a lug nut

Solution: Tangential velocity is the linear speed of any object moving along a circular path. A point on the outside edge of a turntable moves a greater distance in one complete rotation than a point near to the center

Vr = r.ω

(0114 m)(41.03 rad/s) = Vr

Vr = 4.68 m/s

Hence, tangential speed of lug nut on wheel of car is 4.68 m/s

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