Answer:
181.33Step-by-step explanation:
Since the base of the pyramid PABCD is a rectangle, the shape in question is a rectangular based pyramid. Volume of a rectangular based pyramid is expressed as V = 1/3 * Base Area * Height of the pyramid.
Given a rectangle ABCD with AB = 8 and BC = 4, the area of the rectangle will be equivalent to the base area of the pyramid.
Base Area = Length * Breadth
Base Area = AB * BC
Base Area = 8*4 = 32
If [tex]\overline{PA}\perp \overline{AD}\ and \ \overline{PA}\perp \overline{AB}[/tex], and PB = 17, then the height of the pyramid is PB = 17.
Volume of the pyramid = 1/3 * 32 * 17
Volume of the pyramid = 1/3 * 544
Volume of the rectangular based pyramid = 181.33
If a=2b=2c find the value of each.
Answer:
b=a/2
c=a/2
b=c
a=2b and a=2c
how to write this in number form The difference of 9 and the square of a number
Answer:
9-x^2
Step-by-step explanation:
The difference of means subtracting. the first number is 9 and the second is x^2, so you get 9-x^2
Area And Perimeter! Find the Area and the Perimeter of the Triangle!!! and explain.... ( help hurry!!)
perimeter of triangle: P = l+w+h
9+12+10= 31in.
area of triangle: A=b×h÷2
21 + 21 = 42in^2
Question 9
Explain using complete sentences how you would solve for the
variable a in this equation : p = (3a +4)/ b
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Answer:
To solve for a, you will need to get that variable alone on one side. First you will multiply each side by variable b. This will give you the equation pb = 3a + 4. Next you subtract 4 from each side. This puts it at pb - 4 = 3a. After that you’ll divide both sides by 3 and get a alone. This gives you (pb - 4)/3 = a or, if you switch it around, a = (pb - 4)/3. This is the simplest form when solving for a in this equation.
Answer:
Hello,
All my sentences will be written in mathematical language.
Step-by-step explanation:
[tex]p=\dfrac{3a+4}{b} \\\\p*b=3a+4 \ :\ \forall\ x,y,z\in\mathbb{R},z\neq 0:x=y\Longleftrightarrow\ x*z=y*z\\\\p*b-4=3a \ :\forall\ x,y,z\in\mathbb{R} :x=y\Longleftrightarrow\ x+z=y+z\\\\\dfrac{p*b-4}{3} =a \ :\forall\ x,y,z\in\mathbb{R},z\neq 0:x=y\Longleftrightarrow\ x*z=y*z\\\\a=\dfrac{p*b-4}{3} \ :\forall\ x,y\in\mathbb{R}:x=y\Longleftrightarrow\ y=x[/tex]
Find the most general antiderivative of the function. (Use C for the constant of the antiderivative).
f(x) = 6x5 − 7x4 − 9x2
F(x) = ?
Answer:
[tex]x^6 - \frac{7x^5}{5} - 3x^3 + C[/tex]
A person of height 2m observes the angle of elevations of the top of a Pole 62m height which is in front of him and finds it to be 45. find the distance between the person end the pole .
It need the answer to these please
hopefully this answer can help you to answer the next question
Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) f(x) = x , [0, 16]
Answer:
C = 4
Step-by-step explanation:
solution:
f(x) can be differentiated on (0,16)
By mean value theorem
= f(16) = 4
= f(0) = 0
= f(b) - f(a)/b - a
= f(4) - f(0)/ f(16) - f(0)
= f'(c) = 1/2√C
= 1/2√C = 4/16
= 1/2√C = 1/4
= 4 = 2√C
= √C = 4/2
we make c the subject of the formula and also eliminate the square root
= √C = 2
= C = 2²
= C = 4
A researcher is interested in finding a 95% confidence interval for the mean number of times per day that college students text. The study included 210 students who averaged 28 texts per day. The standard deviation was 21 texts.A. The sampling distribution follows a_______.1. "F"2. "normal"3. "T"4. "Chi-square" B. With 95% confidence the population mean number of texts per day of is between_______and______texts. A. 1. "24.92"2. "25.79"3. "27.37"4. "25.14"B. 1. "31.19"2. "31.20"3. "29.28"4. "30.86" C. If many groups of 210 randomly selected students are studied, then a different confidence interval would be produced from each group. About_______% of these confidence intervals will contain the true population mean number of texts per day and about______% will not contain the true population mean number of texts per day.A. 1. "5"2. "95"3. "1"4. "99"B. 1. "95"2. "99"3. "5"4. "1"
Answer: A. The sampling follows a normal distribution.
B. Between 25.14 and 30.86
C. About 95% will contain the true mean and about 5% won't
Step-by-step explanation: A. The sampling is normally distributed because:
it has a symmetric bell shape, mean and median are both the same and located at the center of graphic, approximately 68% of the data falls within one standard deviation;95% falls within two standard deviations;99.7% within 3 standard deviations;B. For a 95% confidence interval: α/2 = 0.025
Since n = 210, use z-score = 1.96
To calculate the interval:
mean ± [tex]z.\frac{s}{\sqrt{n} }[/tex]
Replacing for the values given:
28 ± [tex]1.96.\frac{21}{\sqrt{210} }[/tex]
28 ± [tex]1.96*1.45[/tex]
28 ± 2.84
lower limit: 28 - 2.84 = 25.14
upper limit: 28 + 2.84 = 30.86
Confidence Interval is between 25.14 and 30.86.
C. Confidence Interval at a certain percentage is an interval of values that contains the true mean with a percentage of confidence. In the case of number of times per day students text, 95% of the interval will contain the true mean, while 5% will not contain it.
I need help with this question please
Answer:
Step-by-step explanation:
30t - 5t² = 10
5t² - 30t + 10 = 0
t = [30 ± √(30² - 4 ⋅ 5 ⋅ 10)] / [2 ⋅ 5]
= [30 ± √700] / 10
= [30 ± 10√7] / 10
= 3 ± √7
≈ 0.35 seconds and 5.65 seconds
bon
Question 21
O pts
The recipe for a s'more is as follows:
1 graham cracker
chocolate bar
2 marshmallows
If you have 10 graham crackers, 7 marshmallows, and 5 chocolate bars, how many
complete s'mores can you make using this recipe?
Question 22
O pts
Answer:
3 s'mores
Step-by-step explanation:
If we center our attention on how many marshmallows you need per s'more which is 2 and you only have 7 you can only make 3 with one marshmallow remaining.
1.Write 32 1/2 in radical form
Answer:
√32
Step-by-step explanation:
Tính tích phân sau bằng cách dùng tọa độ cực I=∫∫ [tex]\frac{1}{\sqrt{x^{2} +y^{2} } }[/tex]dxdy R là miền nằm trọg góc phần tư thứ nhất thỏa mãn 4[tex]\leq x^{2} +y^{2} \leq 9[/tex]
It sounds like R is the region (in polar coordinates)
R = {(r, θ) : 2 ≤ r ≤ 3 and 0 ≤ θ ≤ π/2}
Then the integral is
[tex]\displaystyle \iint_R\frac{\mathrm dx\,\mathrm dy}{\sqrt{x^2+y^2}} = \int_0^{\pi/2}\int_2^3 \frac{r\,\mathrm dr\,\mathrm d\theta}{\sqrt{r^2}} \\\\ = \int_0^{\pi/2}\int_2^3 \mathrm dr\,\mathrm d\theta \\\\ = \frac\pi2\int_2^3 \mathrm dr \\\\ = \frac\pi2r\bigg|_2^3 = \frac\pi2 (3-2) = \boxed{\frac\pi2}[/tex]
An agriculture company is testing a new product that is designed to make plants grow taller. This can be thought of as a hypothesis test with the following hypotheses. H0: The product does not change the height of the plant. Ha: The product makes the plant grow taller. Is the following an example of a type I or type II error? The sample suggests that the product makes the plant grow taller, but it actually does not change the height of the plant.
Answer:
hi
Step-by-step explanation:
hji
A race car is traveling at a rate of 36 yards per second. What is the car's speed in miles per hour?
Answer: The car is traveling at 73.63638 Mph
Step-by-step explanation:
1 yard per second is the same as 3 feet per second.
there are 5280ft per mile
So, at 36 yards per second, the car is traveling at 108/5280th (0.02045455) of a mile per second
0.02045455 * 60 (seconds) * 60 (minutes) = 73.63638 Mph
Consider the function f(x) = x2. Which of the following functions shifts f(x)
downward 5 units and to the right 3 units?
A)f(x) = (x + 3)2 - 5
B) f(x) = (x - 3)2 - 5
C) f(x) = (x - 5)2 - 3
D) f(x) = (x - 5)2 + 3
Answer:
f(x) = (x - 3)² - 5
Step-by-step explanation:
equate equation to 0
(x - 3)² = 0
take the square root on both sides
x - 3 = 0
add 3
x = 3
If x = 3 then you are moving to 3 units to the right.
- 5 means you are going downward 5 units.
For the function F defined by F(x) = x^2 – 2x + 4, find F(| – 4|).
| - 4 | = 4
Thus :
f ( | - 4 | ) = f ( 4 )
f ( 4 ) = ( 4 )^2 - 2(4) + 4
f ( 4 ) = 16 - 8 + 4
f ( 4 ) = 16 + 4 - 8
f ( 4 ) = 20 - 8
f ( 4 ) = 12
Which of the following is a solution of y> Ix| - 5?
O (-4,1)
O (-1,-4)
O (4, -1)
Hurry plz
Answer:
O (-4,1)
I hope I helped you^_^
Which of the following expression is equal to X^2+9
Answer:
(x + 3i) * (x - 3i) = x^2 + 3xi - 3xi - 9(i^2) = x^2 + 9
Step-by-step explanation:
This person did something wrong and I do not know what it is :( Please help this is for points!
Answer:
It is, indeed, a reduction. But, the scale factor of the dilation should be a fraction instead of a whole number, since the shape has shrunk.
Instead of [tex]\frac{KN}{K'N'}[/tex], it should be [tex]\frac{K'N'}{KN}[/tex]. That would make it (4 - 2) / (8 - 4) = 2 / 4 = 1/2.
Hope this helps!
If the average(arithmetic mean) of g and 100 is 75,what is the value of g + 100?
The value of g + 100 is 150.
Given that,
The average of g and 100 is 75.
And we have to determine the value of g + 100.
So that means
The arithmetic mean of g and 100 is 75.
So, mathematically it should be
[tex]\frac{g + 100}{2} = 75\\\\[/tex]
So, g + 100 = 150
Therefore we can conclude that the value of g + 100 is 150
Learn more about the mean here: brainly.com/question/11230531
simplify 27- 9+(12-5)÷4 with solution
Answer:
It's 28 3/4
Step-by-step explanation:
Answer:
Answer is 19.5
Step-by-step explanation:
27-9+(12-5)÷4
27-9+6÷4 [BOD MAS Rule]
27-9+1.5
28.5-9
19.5
The data represent the membership of a group of politicians. If we randomly select one politician, what is the probability of getting given that a was selected?
Complete Question
The data represent the membership of a group of politicians. If we randomly select one politician, what is the probability of getting a Republican given that a male was selected?
Republican Democrat Independent
Male 11 6 0
Female 70 17 7
The probability is approximately_____?
Answer:
The probability is [tex]P(k) = 0.647[/tex]
Step-by-step explanation:
From the question we are told that
The sample size of male is [tex]n_m = 11 + 6 =17[/tex]
The number of male Republican is [tex]k = 11[/tex]
Generally the probability of getting a Republican given that a male was selected is
[tex]P(k) = \frac{k}{n_m}[/tex]
substituting values
[tex]P(k) = \frac{ 11}{17}[/tex]
[tex]P(k) = 0.647[/tex]
Given m -1/2 & the point ( 3, -6), which is the point slope form of the equation?
Answer:
[tex]y+6=-\frac{1}{2} (x-3)[/tex]
Step-by-step explanation:
Since point-slope form is [tex]y-y1=m(x-x1)[/tex], you have to plug in the values given to you to create the equation. The "y1" is the "y" coordinate given to us, while the x1 is the x coordinate given to us. So, you have to plug in the x and y coordinates, 3 and -6, into the equation. Since two negatives cancel out to be a positive, y--6= y+6. The "m" stands for the slope, so -1/2 is inserted into the equation, giving us [tex]y+6=-\frac{1}{2} (x-3)[/tex].
I will mark as brainliest:)
Answer:
Cube C
Step-by-step explanation:
[tex]{ \sf{because \: it \: is \: identical}}[/tex]
Try Again
Suppose that 16 inches of wire costs 48 cents.
At the same rate, how many inches of wire can be bought for 36 cents?
I inches
X Х
$
?
Find the value of f (x)=x²-4 and g(x)=3x+2 Find the value of f (-1)g(-1)
Answer:
3
Step-by-step explanation:
[tex]f(-1)g(-1) \text{ is the same thing as } f(-1)\cdot g(-1). \\\text{Therefore, find f(-1) and g(-1)}[/tex]
[tex]f(-1)=(-1)^2-4\\f(-1)=1-4\\f(-1)=-3[/tex]
[tex]g(-1)=3(-1)+2\\g(-1)=-3+2\\g(-1)=-1[/tex]
Therefore:
[tex]f(-1)\cdot g(-1)\\=(-3)(-1)=3[/tex]
one of these marbles is picked at random. what is the probability that a blue marble is picked?
A.1/3
B.2/5
C.1/2
D.1/4
Answer:
1/3
Step-by-step explanation:
there are twelve marbles total. there are 4 blue marbles.
4/12 = 1/3
help me by using formula how did came by reason
Answer:
angleABC=isosceles triangle
angleB=(180-50)÷2=65
angle B=angleX(alternative angle)
angleB=65degree
Suppose you do not know the population mean fee charged to H&R Block customers last year. Instead, suppose you take a sample of size n-8 and find a sample mean of 350. Assume that the distribution for fees is normally distributed with a sample standard deviation of $100.
i. Before conducting the survey, suppose you believed based on your previous observations, your best guess for population standard deviation of fee charged to H&R Block is $50. With this assumption in mind, What should your sample size n approximately be if you want:
Margin-of-Error of to be 2 % and confidence level to be 95 %?
Margin-of-Error of to be 4% and confidence level to be 95%?
Margin-of-Error of to be 4 % and confidence level to be 99%?
ii. 90% confidence interval for the population mean of fees H&R Block.
a. Calculate the margin of error (MOE) of x using a 10% significance level.
b. Calculate the 90 % confidence interval.
c. Suppose an analyst belief that the population mean fee is equal to $185. Using a 90% confidence level. can we conclude the analyst is right? Why or why not?
Answer:
i [tex]\to[/tex] a
[tex]n = 96040000[/tex]
i [tex]\to[/tex] b
[tex]n_1 =24010000[/tex]
i [tex]\to[/tex] c
[tex]n_2 =41602500[/tex]
ii[tex]\to[/tex]a
[tex]E = 58.16[/tex]
ii[tex]\to[/tex]b
[tex]291.84 < \mu < 408.16[/tex]\
ii[tex]\to[/tex]c
There is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval
Step-by-step explanation:
From the question we are told that
The sample size is [tex]n = 8[/tex]
The sample mean is [tex]\= x = \$ 350[/tex]
The sample standard deviation is [tex]\$ 100[/tex]
Considering question i
i [tex]\to[/tex] a
At [tex]E = 0.02[/tex]
given that the confidence level is 95% = 0.95
the level of significance would be [tex]\alpha =1-0.95 = 0.05[/tex]
The critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table is
[tex]Z_{\frac{ \alpha }{2} } = 1.96[/tex]
So the sample size is mathematically evaluated as
[tex]n = [ \frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ]^2[/tex]
=> [tex]n =[ \frac{ 1.96 * 100}{ 0.02} ]^2[/tex]
=> [tex]n = 96040000[/tex]
i [tex]\to[/tex] b
At [tex]E_1 = 0.04[/tex] and confidence level = 95% => [tex]\alpha_1 = 0.05[/tex] => [tex]Z_{\frac{\alpha_1 }{2} } = 1.96[/tex]
[tex]n_1 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_1} ]^2[/tex]
=> [tex]n_1 =[ \frac{ 1.96 * 100}{ 0.04} ]^2[/tex]
=> [tex]n_1 =24010000[/tex]
i [tex]\to[/tex] c
At [tex]E_2 = 0.04[/tex] confidence level = 99% => [tex]\alpha_2 = 0.01[/tex]
The critical value of [tex]\frac{\alpha_2 }{2}[/tex] from the normal distribution table is
[tex]Z_{\frac{ \alpha_2 }{2} } = 2.58[/tex]
=> [tex]n_2 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_2} ]^2[/tex]
=> [tex]n_2 =[ \frac{ 2.58 * 100}{ 0.04} ]^2[/tex]
=> [tex]n_2 =41602500[/tex]
Considering ii
Given that the level of significance is [tex]\alpha = 0.10[/tex]
Then the critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table is
[tex]Z_{\frac{\alpha }{2} } = 1.645[/tex]
Generally the margin of error is mathematically represented as
[tex]E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]
substituting values
[tex]E = 1.645 * \frac{100 }{\sqrt{8} }[/tex]
[tex]E = 58.16[/tex]
Generally the 90% confidence interval is mathematically evaluated as
[tex]\= x - E < \mu < \= x + E[/tex]
=> [tex]350 - 58.16 < \mu < 350 + 58.16[/tex]
=> [tex]291.84 < \mu < 408.16[/tex]
So the interpretation is that there is 90% confidence that the mean fee charged to H&R Block customers last year is in the interval .So there is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval.