Robin currently has 50 subscribers on her You.Tube channel, and Dimitri currently has 17 subscribers. Robin gains 4 subscribers every week, while Dimitri gains 7 subscribers each week.
Part A: Set up a system of equations to shows each person's subscribers.
Part B: After how many weeks will Robin and Dimitri have the same number of subscribers?
Part C: How many subscribers will Robin and Dimitri have when their subscriber count is equal?
Answers
Answer:
Part A :
Robin : 50 divided by 4 = 12.5, Robin took 12.5 Weeks to get to 50 subscribers.
Dimitri : 17 divded by 7 = 2.4, Dimitri took 2.4 weeks to get to 7 subscribers.
Part B : In 7 weeks, Dimitri will have 66 subscribers, And in 4 weeks, Robin will have 66 subscribers. So after 7 weeks for Robin and 4 for Dimitri
Part C , They will have 66 subscribers. After 7 weeks Dimitri will have 66 subcribers, and after 4 weeks Robin will have 66 subscribers.
Explanation :
I have calculated out Robins and Dimitris subscribers counts with math.
Part A: The attached image is for Robin but I didn't have time for Dimitri.
Dimitri: Currently has 17 subscribers, 7x11=77. 17+77 = 94 and the same goes for Robin.
Robin: Currently he has 50 subscribers, 4x11=44. 50+44 = 94.
Part B: After 11 weeks Robin and Dimitri will have the same number of subscribers.
Part C: Robin and Dimitri will have 94 Subscribers when their subscriber count is equal.
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Short
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Answers
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Step-by-step explanation:
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[tex]\\ \sf\Rrightarrow \dfrac{6}{7}x-\dfrac{2}{5}y+\dfrac{5}{7}(y+x)[/tex]
[tex]\\ \sf\Rrightarrow \dfrac{6}{7}x-\dfrac{2}{5}y+\dfrac{5}{7}x+\dfrac{5}{7}y[/tex]
[tex]\\ \sf\Rrightarrow \dfrac{6}{7}x+\dfrac{5}{7}x-\dfrac{2}{5}y+\dfrac{5}{7}y[/tex]
[tex]\\ \sf\Rrightarrow \dfrac{11}{7}x+\dfrac{-14+25}{35}y[/tex]
[tex]\\ \sf\Rrightarrow \dfrac{11}{7}x+\dfrac{11}{35}y[/tex]
Done!
[tex] \boxed{\huge \bf \: Question:—}[/tex]
[tex] \sf \longmapsto \: \dfrac{6}{7} x - \dfrac{2}{5} y + \dfrac{5}{7} (y + x)[/tex]
[tex]\boxed{\huge\bf \: Solution:—}[/tex]
[tex] \boxed{\bf \: Distribute:—}[/tex]
[tex]\sf \longmapsto \: \dfrac{6}{7} x - \dfrac{2}{5} y + \dfrac{5}{7} y + \dfrac{5}{7} \: x[/tex]
[tex]\sf \longmapsto \dfrac{6}{7} x + \dfrac{ - 2}{5} y + \dfrac{5}{7} y \: + \dfrac{5}{7} x[/tex]
[tex] \boxed{\bf \: Combining \: Like \: Terms:—}[/tex]
[tex]\sf \longmapsto\dfrac{6}{7} x + \dfrac{ - 2}{5} y + \dfrac{5}{7} y \: + \dfrac{5}{7} x[/tex]
[tex]\sf \longmapsto \bigg(\dfrac{6}{7} x + \dfrac{5}{7} x \bigg) \: + \bigg( \dfrac{ - 2}{5} y + \dfrac{5}{7} \: y \bigg)[/tex]
[tex]\sf \longmapsto \: \dfrac{11}{7} x \: + \dfrac{11}{35} y[/tex]
[tex]\boxed{\bf \: Answer:—}[/tex]
[tex] \boxed{\bf \: \dfrac{11}{7} x \: + \dfrac{11}{35} y}[/tex]
Enrique bought a football and a puzzle at a store.
He paid $15.35 for the football.
He paid a total of $24.02 for the football and the puzzle.
How much did Enrique pay for the puzzle, in dollars and cents?
Answers
Answer:
8 dollars and 67 cents...8.67
Step-by-step explanation:
5 dollar bill
3 one dollar bills
2 quarters
1 dime
1 nickel
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At the movie theatre, child admission is $5.50 and adult admission is $8.90. On Friday four times as many adults tickets as child tickets were sold, for a total sales of $986.40. How many child tickets were sold that day?
Answers
Answer:
You can use grouping, quantity and value to solve this question.
Child admission = $5.50
Adult admission = $8.90
Friday sales (Quantity):
Child = x
Adult = 4x
Total sales = 5x
Friday sales (Value):
Child = $5.50
Adult = 4 × $8.90
= $35.60
Total sales = $986.40
1 group = $5.50 + $35.60
= $41.10
Number of groups = $986.40 ÷ $41.10
= 24
The number of child tickets sold is 24.