SCIENTIFIC NOTATION 8TH GRADE MATH KA- CORRECT ANSWERS ONLY PLS :)))) have a great day folks

Answer:

4, Third option

Step-by-step explanation:

When you get 9^8 the answer is 43046721. So when raising a power to a power, the products should equal 8. Using simple math, we can determine that 4x2=8. To check our work you can calculate (9^2)^4, which equals 43046721. Now we can now for sure that this answer is correct. Hope this helps!

Answer:

lineHO parallel lineEN - Given

lineHW = lineNW - Given

angle HWO congruent angle EWN Vertical Angles

angle OHW congruent angle ENW Alternate interior angles

Thus triangle HOW congruent triangle NEW

[wouldn't let me use symbols sorry]

Answer:

Triangles are congruent due to SAS

Angles are congruent due to CPCTC

Step-by-step explanation:

In order to prove the congruency of the angles, we have to prove the congruency of the triangles.

ME=MR is given so that is a side

They share angle M so that is an angle

And, MA=MN which is given so that is a side.

The two triangles are congruent due to SAS postulate

So the angles are equal due to CPCTC

Angles E and R are congruent as they are the corresponding parts of two congruent triangle.

Given is a figure which shows two connected triangles ΔEMA and ΔRMN,

We need to prove ∠E ≅ ∠R.

Considering the triangles,

ME = MR [given]

MA = MN [given]

∠M is common angle in both triangles,

So, ΔEMA ≅ ΔRMN by SAS postulate.

So, ∠E ≅ ∠R by CPCTC.

Hence proved.

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Answer:

5/6

Step-by-step explanation:

Three-fourths x + StartFraction 1 Over 7 EndFraction y = 6

StartFraction 1 Over 8 EndFraction x minus three-fifths y = 16

is 5/6

Each girl washes 3 shirts. The 18 shirts are divided equally among the 6 girls

After putting 14 shirts in the washing machine, there are 32 - 14 = 18 shirts left to wash. These 18 shirts are shared equally among 6 girls. To find out how many shirts each girl washes, we divide the total number of shirts (18) by the number of girls (6):

Number of shirts washed by each girl = Total shirts / Number of girls

Number of shirts washed by each girl = 18 / 6

Number of shirts washed by each girl = 3

Each girl washes 3 shirts. The 18 shirts are divided equally among the 6 girls, so each girl washes the same number of shirts.

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Answer:

How do you figure out if a shape is similar or not using rectangle diagnols?

Assuming that diagnols = diagonal, it is not possible to define a similarity relationship without measuring at least one side.

Answer:

[tex]\textsf{b.} \quad 3x+5y=2[/tex]

Step-by-step explanation:

Define the given points:

[tex]\textsf{let}\:(x_1,y_1)=(4,-2)[/tex]

[tex]\textsf{let}\:(x_2,y_2)=(-1,1)[/tex]

Use the slope formula to determine the slope of the line:

[tex]\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{1-(-2)}{-1-4}=\dfrac{1+2}{-1-4}=-\dfrac{3}{5}[/tex]

Use the point-slope formula to determine the equation of the line.

[tex]\implies y-y_1=m(x-x_1)[/tex]

Substitute the found slope and point (4, -2):

[tex]\implies y-(-2)=-\dfrac{3}{5}(x-4)[/tex]

[tex]\implies y+2=-\dfrac{3}{5}(x-4)[/tex]

Multiply both sides by 5:

[tex]\implies 5(y+2)=-3(x-4)[/tex]

Expand the brackets:

[tex]\implies 5y+10=-3x+12[/tex]

Add 3x to both sides:

[tex]\implies 5y+10+3x=-3x+12+3x[/tex]

[tex]\implies 3x+5y+10=12[/tex]

Subtract 10 from both sides:

[tex]\implies 3x+5y+10-10=12-10[/tex]

[tex]\implies 3x+5y=2[/tex]

The value of a and b from the coordinates are 3 and 5 respectively

The formula for finding the midpoint of two coordinates is expressed as;

M(x, y) = {x1+x2/2, y1+y1/2}

Given the following coordinates

M(a, 4)

A(1,3)

B(5,b)

Using the formula

a = 1+5/2

a = 6/2

a = 3

Similarly

4 = 3+b/2

8 = 3+b

b = 8-3

b = 5

Hence the value of a and b from the coordinates are 3 and 5 respectively

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Answer:

34 (looking at the image im kinda unsure of my answer cuz 4*34=136 and that doesn't look like 136)

Step-by-step explanation:

angle TSU = angle PSR = 4x

from that we know that PSQ=x

so then we know PQS=180-2x

180-2x+68=180

2x=68

x=34

Answer:

Step-by-step explanation:

(A)length of a stamp=1/5foot

wide of a stamp=1/4foot

area of the stamp=?

area of the stamp=length of a stamp *wide of a stamp

                              =1/5*1/4

                              =1/20square foot

(B)an area of the room=1/4  square meter

width of the room=1/5meter

length of the room=?

an area of the room=width of the room*length of the room

1/4                              =1/5                          *  length of the room

1/4                              = length of the room/5                

5/4                             =length of the room

(C)the area of the canvas=1/5square yard

width of the canvas=1/4 yard

length of the canvas=?

an area of the  canvas=width of the  canvas*length of the  canvas

1/5                                = width of the  canvas*1/4

1/5                                 = width of the  canvas/4

4/5                                =width of the  canvas

width of the  canvas=   4/5

(D)length of the  rectangular course=1/5mile

area of the  rectangular course=1/4square mile

width of the  rectangular course=?

an area of the  rectangular course

                          =

width of the  rectangular course*length of the  rectangular course

1/4                      =width of the  rectangular course*1/5

1/4                      =width of the  rectangular course/5

5/4                     =width of the  rectangular course

width of the  rectangular course=5/4

Answer: 62.8in

Step-by-step explanation:

The formula for circumference is C=2πr. Put the values of 10 in for r and 3.14 in for pi, and you get an equation that looks like C=2(3.14)(10). Solving this equation gets you 62.8.

Answer:

62.8

Step-by-step explanation:

Circumference=2rpi

c=2*10*pi

c=20*pi

c=20*3.14

c=62.8

[tex]sample \: space = 52 \: cards \\ spades = 13 \: cards \\ number \: 4s = 4 \: cards \\ diamonds = 13 \: cards \\ note \: that = \\ there \: is \: replacement \\ order \: does \: matter[/tex]

[tex]P( \gamma ) = \frac{13}{52} \times \frac{4}{52} \times \frac{13}{52} = \frac{1}{208} [/tex]

Answer:

b

Step-by-step explanation:

We have proven that ΔACO ≅ ΔBDO using the SAS (Side-angle-side) theorem

From the question, we are to prove that ΔACO ≅ ΔBDO

From one of the congruent triangles theorem, we have that

If two sides and the included angle of one triangle are equal to two sides and the included angle of another triangle, the triangles are congruent.

This is the SAS (Side-angle-side) theorem.

From the given information,

AB and CD intersect at point O

Thus, AO = BO

Also,

∠ACO ≅ ∠BDO

In the diagram, we can as well observe that CO ≅ DO

Thus, we can conclude that AC ≅ BD

Since sides AC, CO and the included angle ACO are congruent to sides BD, DO and the included angle BDO, we can conclude that ΔACO ≅ ΔBDO using the SAS theorem.

Hence, we have proven that ΔACO ≅ ΔBDO

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1. Start the search among 2-digit numbers. A dropdown number (DDN) with 2 digits is a number [tex]ab[/tex] such that

[tex]\dfrac{a+b}2 = a \implies a + b = 2a \implies b = a[/tex]

or

[tex]\dfrac{a+b}2 = b \implies a+b = 2b \implies a=b[/tex]

but both of these solutions violate the requirement that the digits are distinct, so there are no 2-digit DDNs.

A 3-digit DDN [tex]abc[/tex] is such that

[tex]\dfrac{a+b+c}3 = a \implies a+b+c = 3a \implies b+c = 2a[/tex]

or [tex]a+c=2b[/tex] if the average is [tex]b[/tex], or [tex]a+b=2c[/tex] if the average is [tex]c[/tex]. The smallest possible value for [tex]a[/tex] is 1 since we require 3 digits. Then [tex]b+c=2[/tex], and we can pick [tex]b=0[/tex] and [tex]c=2[/tex] to get the smallest DDN, 102.

2. In a 4-digit DDN [tex]abcd[/tex], we have

[tex]\dfrac{a+b+c+d}4 = a \implies a + b + c + d = 4a \implies b+c+d=3a[/tex]

or [tex]a+c+d=3b[/tex] or [tex]a+b+d=3c[/tex] or [tex]a+b+c=3d[/tex].

We're free to fix [tex]a=1[/tex] and [tex]b=0[/tex] to try to get the smallest DDN. This leaves us with [tex]c+d=3[/tex] or [tex]c+d=-1[/tex] or [tex]1+d=3c[/tex] or [tex]c=3d[/tex].

The first two cases are impossible - the only choices for [tex]c,d[/tex] such that [tex]c+d=3[/tex] are 1 and 2, and the sum of two positive integers must be positive. The smallest possible value of [tex]c[/tex] is 2; this leaves us with [tex]1+d=6[/tex] or [tex]2=3d[/tex], but the latter case is impossible because 3 does not divide 2. So [tex]d=5[/tex], and the smallest 4-digit DDN is 1025.

To find the largest DDN, start with the largest possible values for [tex]a[/tex] and [tex]b[/tex]. Let [tex]a=9[/tex] and [tex]b=8[/tex]. Then [tex]c+d=19[/tex] or [tex]c+d=15[/tex] or [tex]17+d=3c[/tex] or [tex]17+c=3d[/tex]. At most, we can have [tex]c+d=13[/tex] with 7 and 6, so the first two cases are impossible. If we maximize [tex]c=7[/tex], then either [tex]17+d=21\implies d=4[/tex] or [tex]24=3d\implies d=8[/tex] (which we don't want). So the largest 3-digit DDN is 9874.

3. I don't have an analytical solution to this, but using brute force (program) the total count is 112.

4. It is possible; consider 1249 and 1250, with digital averages

[tex]\dfrac{1+2+4+9}4=4 \text{ and } \dfrac{1+2+5+0}4=2[/tex]

which happens to be the smallest pair. (Also found with brute force.)

Answer:

B is the answer of that question

I HOPE IT HELP YOU

Answer:

I am going to answer the ones you haven't answered yet...

Bullet point 2: The Y-intercept is where the graph crosses the y-axis in this case that would be y=0 or (0,0)

Bullet Point 5: the question basically says that for the values of x when they are between 0 and 6 the y values are ___. the answer for this one would be y ≥ 0.

To start solving the exercise, we obtain as data:

We apply as a formula:

We apply the formula and solve:

Therefore, the area of the circle is 27 ft².

Answer: 27ft²

Step-by-step explanation: Soln:

Given that,

π=3

Radius(r)=3ft.

We have,

A = π r²

A = 3* (3)²

A=3*9

A=27ft²

Answer:

[tex]\sf a. \quad \dfrac{21}{10+x}+\dfrac{21}{10-x}=5[/tex]

Step-by-step explanation:

Formula for calculating speed:

[tex]\boxed{\sf Speed=\dfrac{Distance}{Time}}[/tex]

Therefore:

[tex]\boxed{\sf Time=\dfrac{Distance}{Speed}}[/tex]

Given values:

If the boat is traveling downstream, the current (x mph) will be pushing the boat faster, and so the boat's speed will increase by x mph.

Therefore, the expression for the time it takes for the boat to travel downstream is:

[tex]\sf Time\:(downstream)=\dfrac{21}{10+x}[/tex]

If the boat is traveling upstream, the current (x mph) will be pushing against the boat and so the boat's speed will decrease by x mph.

Therefore, the expression for the time it takes for the boat to travel upstream is:

[tex]\sf Time\:(upstream)=\dfrac{21}{10-x}[/tex]

Therefore, if the total time it takes to travel downstream and upstream is 5 hours:

[tex]\implies \sf \dfrac{21}{10+x}+\dfrac{21}{10-x}=5[/tex]

To solve for x:

[tex]\implies \sf \dfrac{21}{10+x}+\dfrac{21}{10-x}=5[/tex]

[tex]\implies \sf \dfrac{21(10-x)}{(10+x)(10-x)}+\dfrac{21(10+x)}{(10-x)(10+x)}=5[/tex]

[tex]\implies \sf \dfrac{21(10-x)+21(10+x)}{(10+x)(10-x)}=5[/tex]

[tex]\implies \sf21(10-x)+21(10+x)=5(10+x)(10-x)[/tex]

[tex]\implies \sf 210-21x+210+21x=5(100-10x+10x-x^2)[/tex]

[tex]\implies \sf 420=500-5x^2[/tex]

[tex]\implies \sf 5x^2=80[/tex]

[tex]\implies \sf x^2=16[/tex]

[tex]\implies \sf x=\pm4[/tex]

Therefore, the rate of the current is 4 mph.

Answer:

i got 2808 in3 which wasn't on the list and i was extremely confused, i redid the problem multiple times and got the same answer, i used a calculator AND searched of the web, it still gave me the same answer, if those are the only options something might be wrong, the answer should be 2808 in3.

Answer:

Option C; 26cm by 14 cm

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

Answer:

5 students

Step-by-step explanation:

35-20=15

15/3=5

Answer:

35 kids 20 students pass the test 35 -20 = 15 divided by 3 =5 students per teacher.

Step-by-step explanation: hope this helps can I be brainlyest. This is a bunny /\__/\

          | *  .  * |

The domain of the notation [tex]s(x) = \sum\limits^{\infty}_{n=1} n^{-x}[/tex] is the set of all real values

The sum notation is given as:

[tex]s(x) = \sum\limits^{\infty}_{n=1} n^{-x}[/tex]

From the above notation, the smallest value of n is 1.

This means that the variable x can take any real value as it value

Hence, the domain of the notation [tex]s(x) = \sum\limits^{\infty}_{n=1} n^{-x}[/tex] is the set of all real values

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To figure out the average of Michael and Melissa we must add up all their test scores and divide the by 7; which is the number of tests they took.

Michael:

(80+76+73+70+40+25+10)/7

Melissa:

(88+83+75+70+60+65+62)/7

Michael's average is 53.4

Melissa's average is 71.9

So Melissa is earning a C in Latin.