Answer:
The center of the circle:
(2, -1)
The radius of the circle:
r = 4
Step-by-step explanation:
The first step is to complete the square on both x and y:
x^2 + y^2 -4x + 2y - 11 = 0
x^2 -4x +y^2 +2y = 11
We determine c1 to complete the square on x:
c1 = (b/2)^2
c1 = (-4/2)^2 = 4
We then determine c2 to complete the square on y:
c2 = (2/2)^2 = 1
The equation of the circle is then re-written as:
x^2 -4x + 4 +y^2 +2y + 1 = 11 +4 +1
We then factorize the expressions in x and y separately:
(x-2)^2 + (y +1)^2 = 16
The center of the circle is thus:
(2, -1)
The radius is the square root of 16:
r = 4
Answer:
center : (2, -1)
radius : r = 4
Step-by-step explanation:
Help! Solve equation: xe^2x=0
Answer: x=0
Step-by-step explanation:
For this problem, there are no calculations needed. You just have to know your algebraic properties. Since we are looking for x, we know that x must be 0. The answer is 0. Figuring out e²ˣ can be tricky, but since there is an x multiplying it in front, we know that x must be 0 to make the equation equal to 0.
Multiple-Choice Questions
1. In 1995, Diana read 10 English books and 7 French books. In 1996, she read twice as many French books as English books. If 60% of the books that she read during the 2 years were French, how many English and French books did she read in 1996?
(A) 16
(B) 26
(0) 32
(D) 48
Answer:
(D) 48
Step-by-step explanation:
Let English book = x
Let french book = y
In 1995 x= 10
Y= 7
In 1996
Y = 2x
Total book read in the two years
0.6(Total) = y
0.4(total) = x
We don't know the exact amount of books read in 1996.
Total = 10 + 7 +x +2x
Total = 17+3x
0.6(total) = 7+2x
0.6(17+3x) = 7+2x
10.2 +1.8x= 7+2x
10.2-7= 2x-1.8x
3.2= 0.2x
3.2/0.2= x
16= x
So she read 16 English book
And 16*2 = 32 french book Making it a total of 16+32= 48 books in 1996
Which property of equality was used to solve this equation? x − 5 = -14 x − 5 + 5 = -14 + 5 x = -9 A. addition property of equality B. subtraction property of equality C. multiplication property of equality D. division property of equality
Answer:
A
Step-by-step explanation:
In the second step, they added 5 to both sides to get rid of the -5 on the left side. Since the same thing was done to both sides (addition), the answer is the addition property of equality.
Answer:
Addition property of equality
Step-by-step explanation:
The equation is like:
=> x - 5 = -14
=> x - 5 + 5 = -14 + 5
=> x = -9
Since, we add 5 to both sides to solve for "x", the answer is "Addition Property of Equality".
Hope this helps.
Lydia has 955 in her account.she withdrew 245 and later 447.How many is left in her account.
Answer:
263
Step-by-step explanation:
with 955 in the account, you subtract all the amount withdrawed from the main money in the account.
955-245-447
=263
Divide write the quotient in lowest term 1 1/3 divided by 1 3/4
Answer:
7/3 or 2 1/3
Step-by-step explanation:
1 1/3 ÷ 1 3/4
Change to improper fractions
(3*1+1)/3 ÷ (4*1+3)/4
4/3 ÷ 7/4
Copy dot flip
4/3 * 7/4
Rewriting
4/4 * 7/3
7/3
As a mixed number
2 1/3
Answer:
11/3÷13/4
11/3×4/13
44/39=
1.1282
Graph the function f(x) = 18(0.8)
[tex]f(x)=18(0.8)=14.4[/tex]
is a constant function, so it will be a straight line parallel to x axis and passing through y axis at $14.4$
Hey can anyone help me solve this
Answer:
24
Step-by-step explanation:
Answer and Step-by-step explanation:
I think the answer is 48.
We should add the 12 and 4, then multiply by 3. The 16 times 3 is to get the original amount of candies. To check, we go through the process using the number 48.
48 times 1/3 is 16. 4 of them are given to the brother, which leaves us with 12 remaining candies.
#teamtrees #PAW (Plant And Water)
The higher the bowling score the better. The lower the golf score the better. Assume both are normally distributed. a. Suppose we have a sample of the Santa Ana Strikers' bowling scores. Q1 = 125 and Q3 = 156. Would it be usual or unusual to have a score of 200?b. Suppose the mean bowling score is 155 with a standard deviation of 16 points. What is the probability that in a sample of 40 bowling scores, the mean will be smaller than 150?c. Suppose the mean golf score is 77 with a standard deviation of 3 strokes We will give a trophy for the best 5% of scores. What score must you get to receive a trophy? d. Suppose the mean golf score is 77 with a standard deviation of 3 strokes. Would a golf score of 70 be ordinary, a mild outlier, or an extreme outlier?
Answer:
Explained below.
Step-by-step explanation:
(a)
The first and third quartiles of bowling scores are as follows:
Q₁ = 125 and Q₃ = 156
Then the inter quartile range will be:
IQR = Q₁ - Q₃
= 156 - 125
= 31
Any value lying outside the range (Q₁ - 1.5×IQR, Q₃ + 1.5×IQR) are considered as unusual.
The range is:
(Q₁ - 1.5×IQR, Q₃ + 1.5×IQR) = (125 - 1.5×31, 156 + 1.5×31)
= (78.5, 202.5)
The bowling score of 200 lies in this range.
Thus, the bowling score of 200 is usual.
(b)
Compute the probability that the mean bowling score will be smaller than 150 as follows:
[tex]P(\bar X<150)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}<\frac{150-155}{16/\sqrt{40}})[/tex]
[tex]=P(Z<-1.98)\\=1-P(Z<1.98)\\=1-0.97615\\=0.02385\\\approx 0.024[/tex]
Thus, the probability that in a sample of 40 bowling scores, the mean will be smaller than 150 is 0.024.
(c)
It is provided that, the lower the golf score the better.
So, the best 5% of scores would be the bottom 5%.
That is, P (X > x) = 0.05.
⇒ P (Z > z) = 0.05
⇒ P (Z < z) = 0.95
⇒ z = 1.645
Compute the value of x as follows:
[tex]z=\frac{x-\mu}{\sigma}\\\\1.645=\frac{x-77}{3}\\\\x=77+(3\times 1.645)\\\\x=81.935\\\\x\approx 82[/tex]
Thus, the score is 82.
(d)
A z-scores outside the range (-2, +2) are considered as mild outlier and the z-scores outside the range (-3, +3) are considered as extreme outlier.
Compute the z-score for the golf score of 70 as follows:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
[tex]=\farc{70-77}{3}\\\\=\frac{-7}{3}\\\\=-2.33[/tex]
As the z-score for the golf score of 70 is less than -2, it is considered as a mild outlier.
find inverse of f(x)=- 1/2 x+11
Answer:
-2x + 22
Step-by-step explanation:
We have the function f(x) = -1/2x + 11 and are asked to find the inverse of it.
To find the inverse, we will follow the according steps :
Replacing x with ySolving for yLet's do as followed:
Replacing x with y :
Since f(x) can be also written as y, we can do y = -1/2x + 11, thus making the switch alot easier.
y = -1/2x + 11
x = -1/2y + 11
Solve for y :
We have to get y alone to find the inverse, to do so, get rid of the outlier by subtracting 11 from both sides :
x - 11 = -1/2y
Now divide both sides by -1/2 to get y alone and retrieve our inverse :
-2(x - 11)
Distribute to get the inverse :
-2x + 22
if the sin 30 = 1/2, then which statement is true?
Answer:
cos 60° = 1/2 because the angles are complements.
Step-by-step explanation:
What is the x-intercept?
Compute (3/4)*(8/9)*(15/16)*(24/25)*(35/36)*(48/49)*(63/64)*(80/81)*(99/100) Express your answer in the simplest way possible. (Suggestion: First, try computing 3/4*8/9 then 3/4*8/9*15/16 and so on. Look for patterns.
Answer:
[tex](\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16})*(\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49})*(\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}) = \frac{11}{20}[/tex]
Step-by-step explanation:
Given
[tex](\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16})*(\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49})*(\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100})[/tex]
Required
Simplify
For clarity, group the expression in threes
[tex]((\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
Evaluate the first group [Divide 8 by 4]
[tex]((\frac{3}{1})*(\frac{2}{9})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[Divide 9 by 3]
[tex]((\frac{1}{1})*(\frac{2}{3})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[tex]((\frac{2}{3})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[Divide 15 by 3]
[tex]((\frac{2}{1})*(\frac{5}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[Divide 16 by 2]
[tex]((\frac{1}{1})*(\frac{5}{8}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[tex](\frac{5}{8})*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
Evaluate the second group [Divide 35 and 25 by 5]
[tex](\frac{5}{8})*((\frac{24}{5})*(\frac{7}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[Divide 49 by 7]
[tex](\frac{5}{8})*((\frac{24}{5})*(\frac{1}{3})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[Divide 24 by 3]
[tex](\frac{5}{8})*((\frac{8}{5})*(\frac{1}{1})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[tex](\frac{5}{8})*((\frac{8}{5})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
Merge the first and second group
[tex]((\frac{5}{8})*(\frac{8}{5})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[tex](1*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[tex](\frac{4}{7})*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
Evaluate the last group [Divide 99 by 9]
[tex](\frac{4}{7})*((\frac{63}{64})*(\frac{80}{9})*(\frac{11}{100}))[/tex]
[Divide 63 by 9]
[tex](\frac{4}{7})*((\frac{7}{64})*(\frac{80}{1})*(\frac{11}{100}))[/tex]
[Divide 64 and 80 by 8]
[tex](\frac{4}{7})*((\frac{7}{8})*(\frac{10}{1})*(\frac{11}{100}))[/tex]
[Divide 10 and 4 by 2]
[tex](\frac{4}{7})*((\frac{7}{4})*(\frac{5}{1})*(\frac{11}{100}))[/tex]
[Divide 100 by 5]
[tex](\frac{4}{7})*((\frac{7}{4})*(\frac{1}{1})*(\frac{11}{20}))[/tex]
[tex](\frac{4}{7})*((\frac{7}{4})*(\frac{11}{20}))[/tex]
[tex](\frac{4}{7})*(\frac{7}{4})*(\frac{11}{20})[/tex]
[tex]1*(\frac{11}{20})[/tex]
[tex]\frac{11}{20}[/tex]
Hence;
[tex](\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16})*(\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49})*(\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}) = \frac{11}{20}[/tex]
HELP! What is the probability of randomly picking a green marble from a bag of 10 green marbles, 10 yellow marbles, and 5 red marbles?
Answer:
2/5
Step-by-step explanation:
For probability, it's the
number of the type you want
_______________________
the total number of items
So the equation for this would be
10/10+10+5
= 10/25
= 2/5
The final answer is 2/5. Keep in mind that probability is a ratio of likeliness between things, so you CANNOT write it as a decimal!
I hope this helped! :D
A population has a standard deviation of 16. If a sample of size 64 is selected from this population, what is the probability that the sample mean will be within 2 of the population mean?
a. Since the mean is not given, there is no answer to this question.
b. -0.6826
c. 0.3413
d. 0.6826
e. -0.3413
Answer:
The correct option is D
Step-by-step explanation:
From the question we are told that
The standard deviation is [tex]\sigma = 16[/tex]
The sample size is n = 64
The standard error of mean is mathematically evaluated as
[tex]\sigma _{\= x } = \frac{\sigma }{\sqrt{n} }[/tex]
substituting values
[tex]\sigma _{\= x } = \frac{16 }{\sqrt{64} }[/tex]
[tex]\sigma _{\= x } = 2[/tex]
Generally the probability that the sample mean will be within 2 of the population mean is mathematically represented as
[tex]P( \mu - 2 < \= x < \mu + 2) = P(\frac{( \mu - 2 ) - \mu }{\sigma_{\= x }} < \frac{ \= x - \mu }{\sigma_{\= x }} < \frac{( \mu +2 ) - \mu }{\sigma_{\= x }} )[/tex]
Generally [tex]\frac{ \= x - \mu }{\sigma_{\= x }} = Z (The \ standardized \ value \ of \ \= x )[/tex]
So
[tex]P( \mu - 2 < \= x < \mu + 2) = P(\frac{( \mu - 2 ) - \mu }{\sigma_{\= x }} < Z< \frac{( \mu +2 ) - \mu }{\sigma_{\= x }} )[/tex]
[tex]P( \mu - 2 < \= x < \mu + 2) = P(\frac{( -2 }{\sigma_{\= x }} < Z< \frac{ 2 }{\sigma_{\= x }} )[/tex]
substituting values
[tex]P( \mu - 2 < \= x < \mu + 2) = P(\frac{-2 }{2} < Z< \frac{ 2 }{2} )[/tex]
[tex]P( \mu - 2 < \= x < \mu + 2) = P(-1< Z< 1 )[/tex]
=> [tex]P( \mu - 2 < \= x < \mu + 2) = P(Z < 1) - P(Z < -1)[/tex]
From the normal distribution table [tex]P(Z < 1 ) = 0.84134[/tex]
[tex]P(Z < - 1) = 0.15866[/tex]
=> [tex]P( \mu - 2 < \= x < \mu + 2) = 0.84134 - 0.15866[/tex]
=> [tex]P( \mu - 2 < \= x < \mu + 2) = 0.6826[/tex]
how do I write 1/2 in a from of a decimal?
Answer:
0.5
1 divide by 2 = 0.5
Trisha bought a carton of orange juice. She drank 1/3 of the carton on Monday and 5/12 of the carton on Tuesday. What fraction of the carton did Trisha drink?
Answer:
9/12 or 2/3
Step-by-step explanation:
Make both fractions have the same denominator by finding their least common multiple
1x12 = 12 1x3 = 3
2x6 = 12 3x1 = 3
3x4 = 12
4x3 = 12
6x2 = 12
12x1 = 12
In which case it would be 12.
1/3 would be 4/12
5/12 + 4/12 = 9/12
which is also 2/3 if your teacher wants the simplest answer
illustrate the distributive property to solve 144/8
Answer:
8 (19) or 8 (18 +1)
Step-by-step explanation:
Distributive property means to distribute.
HCF of 144 and 8.
=> 8 is the HCF of 144 and 8
8 (18 + 1)
=> 8 (19)
Instructions: Find the missing side. Round your answer to the
nearest tenth
Answer:
49
Step-by-step explanation:
sin(theta) = P/H
sin(28)=23/x, x=23/sin(28)=49
Find the value of x
pls with all solution
Answer:
the value of x is 85
Step-by-step explanation:
x+x+40+2x-20=360
4x=360-20
4x=340
x=340÷4
x=85
Answer:
X+X+40+2x-20=360(being complete angle)
2x+40+2x -20= 360
4x+20=360
4x=360 - 20
4x= 340
X=340÷4
X= 85
now putting the value of X
X+40
85+ 40
125
2x-20
2×85-20
170- 20
150
hope this answer will help you if it did then make me brainliest.
Varia is studying abroad in Europe. She is required pay $3,500 (in US dollars) per year to the university; however, she must pay in euros. How many euros can Varia expect to pay per month to the university?
Answer: 247.92 euros
Step-by-step explanation:
Given: Varia is required pay $3,500 (in US dollars) per year to the university.
So, [tex]$3500\div 12 \approx\$291.67[/tex]
i.e. She will pay $ 291.67 per month.
Recent currency value: 1 US dollar = 0.85 euro
∴ $291.67 = ( 0.85 ×291.67) euros
= 247.92 euros [Round to the nearest cent]
∴ She can expect 247.92 euros to pay per month to the university.
Which of the following is an example of closure? (1 point)
The equation 5 - 5 = 0 is an example of the natural numbers being closed under subtraction
The equation 1.5 +1.6 = 3.1 is an example of the rational numbers being closed under addition
The equation 4 - 6 = -2 is an example of the whole numbers being closed under subtraction
The equation 1+0= 1 is an example of the natural numbers being closed under addition
Answer:
The equation 1+0=1
Step-by-step explanation:
Other options are not eligible because
1 option -Natural numbers cannot be closed under subtraction
2 option-The equation is not having proper rational numbers, they are decimals
3 option-Whole numbers cannot be closed under subtraction
Thank you!
A shirt is on sale for 20% off. Sandy paid $8 for the shirt. What was the shirt's regular price?
Answer:16
Step-by-step explanation:
Will mark Brainliest! Which point is a vertex of the hyperbola?
A. (1,−15)
B. (1,−2)
C. (1,3)
D. (1,11)
Answer:
So (1,3) is a vertex (out of two) of the hyperbola.
Step-by-step explanation:
The vertices are marked by the dot on the hyperbola.
They are (1,3) and (1,-7).
However, (1,-7) is not on the list of answer choices, but (1,3) is.
So (1,3) is a vertex (out of two) of the hyperbola.
So (1,3) is a vertex (out of two) of the hyperbola.
What is hyperbola?a plane curve generated by a point so moving that the difference of the distances from two fixed points is a constant : a curve formed by the intersection of a double right circular cone with a plane that cuts both halves of the cone.
According to the question
The vertices are marked by the dot on the hyperbola.
They are (1,3) and (1,-7).
However, (1,-7) is not on the list of answer choices, but (1,3) is.
Hence , (1,3) is a vertex (out of two) of the hyperbola.
To learn more about hyperbola from here
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Simplify the following expression. 3x(4x − 3) A. 12x2 + 13x B. 12x2 + 5x C. 12x2 − 5x D. 12x2 − 9x
Answer:
Multiply using the distributive property.
D is the best answer.
Step-by-step explanation:
The simplified form of expression 3x (4x - 3) is 12x² - 9x.
What is an algebraic expression?An algebraic expression is consists of variables, numbers with various mathematical operations,
The given expression is,
3x (4x - 3).
Simplify the expression by solving bracket term,
3x × (4x) - 3 x (3x)
12x² - 9x
The given expression can be simplified as 12x² - 9x.
Hence, option (D) is correct.
To know more about Algebraic expression on:
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Instructions: Determine whether the following polygons are
similar. If yes, type in the similarity statement and scale factor. If
no, type 'None' in the blanks.
Answer:
No they aren't similar different measurements but same angle so they can't be said to be similar
can someone help me please
Answer:
[tex] {x}^{4} = 2880[/tex]
Step-by-step explanation:
[tex] {y}^{2} = 20 \: (eq . \: 1)[/tex]
[tex] {x}^{2} = {(2 \sqrt{3y)} }^{2} = 12y [/tex]
Putting value of eq. 1 in the following:
[tex] {x}^{4 } = {(12y)}^{2} = 144{y}^{2} = 144 \times 20 = 2880[/tex]
Find the indicated complement. A certain group of women has a 0.12% rate of red/green color blindness. If a woman is randomly selected, what is the probability that she does not have red/green color blindness?
Answer:
the probability will be 0.
Step-by-step explanation:
0.12%= 0.0012= 3/2500.
Helppppp, i dont know how to do this problem
Answer:
(3, -5) (4, -5) (2, -7)
Step-by-step explanation:
An integer is any whole number that is not a fraction, they include -10204, -3, 0, 5, and 8592. (random numbers)
A coordinate with integers can be anything such as (0, 4582) and (547, 42)
However, it can not be (0.45846, 4579) or (54.42, 58).
To determine which points have coordinates that look like they are integers, you just have to select 3 points that lie at the intersection of the y and x value tic marks
You can see that (3, -5) is at the intersection of the x value 3 tic mark and the y value -5 tic mark, while also being on the parabola.
A wheel with radius 1 m is rolled in a straight line through one complete revolution on a flat horizontal surface. How many metres did the centre of the wheel travel horizontally from its starting location?
Answer:
6.28 m
Step-by-step explanation:
If a wheel travels with one full revolution, it would have travelled the circumference's distance from it's starting point.
The circumference of a circle is [tex]2\pi r[/tex]
Let's assume [tex]\pi[/tex] is 3.14 and solve for the equation.
[tex]2\cdot3.14\cdot1\\6.28[/tex]
Hope this helped!
pls help! I need the answer quickly! thank you!
The perimeter of a triangle is the summation of the three sides of the triangle. Base on the assumed values, the length of side BD is 2.
For [tex]\triangle ACD[/tex], the sides are: AC, AD and CD
So, the perimeter is:
[tex]P_{\triangle ACD} = AC + AD + CD[/tex]
For [tex]\triangle ABD[/tex], the sides are: AB, AD and BD
So, the perimeter is:
[tex]P_{\triangle ABD} = AB + AD + BD[/tex]
The difference in the perimeters is:
[tex]P_{\triangle ACD} - P_{\triangle ABD} =1 + \sqrt 3[/tex]
So, we have:
[tex](AC + AD + CD) - ( AB + AD + BD) =1 + \sqrt 3[/tex]
Open brackets
[tex]AC + AD + CD - AB - AD - BD =1 + \sqrt 3[/tex]
Evaluate like terms
[tex]AC + CD - AB - BD =1 + \sqrt 3[/tex]
Make BD the subject
[tex]BD = AC + CD - AB - (1 + \sqrt 3)[/tex]
The solution cannot be completed because the side lengths of [tex]\triangle ACD[/tex] and [tex]\triangle ABD[/tex] are not given; so, I will assume the following values.
[tex]AC =2; CD = 1; AB = \sqrt 3[/tex]
[tex]BD = AC + CD - AB - (1 + \sqrt 3)[/tex] becomes
[tex]BD = 2 + 1 + \sqrt 3 - (1 + \sqrt 3)[/tex]
Open bracket
[tex]BD = 2 + 1 + \sqrt 3 - 1 - \sqrt 3[/tex]
Evaluate like terms
[tex]BD = 2[/tex]
Base on the assumed values, the length of side BD is 2.
Read more about perimeters at:
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