Side1 : 3x^2 − 4x − 1 (^to the second power)
Side2: 4x − x^2 + 5 (^to the second power)
Perimeter of the triangle is: 5x^3 -2x^2+3x-8 (^to the second power)

Please Explain:
Part A: What is the total lenge of sides 1 and 2 of the triangle?
Part B: What is the length of the 3rd side of traingle?
Part C: Is Part A and Part B identify the polynomials are closed under addition and subtraction-please show math

Answers

Answer 1

9514 1404 393

Answer:

  A. 2x^2 +4

  B. 5x^3 -4x^2 +3x -12

  C. addition and subtraction of polynomials result in polynomials (closed)

Step-by-step explanation:

A. The total of the two side lengths is ...

  (3x^2 -4x -1) +(-x^2 +4x +5) = (3 -1)x^2 +(-4+4)x +(-1+5) = 2x^2 +4

__

B. The length of the third side is the difference between the total for all three sides and the total for the given two sides:

  (5x^3 -2x^2 +3x -8) - (2x^2 +4) = 5x^3 +(-2-2)x^2 +3x +(-8-4)

  = 5x^3 -4x^2 +3x -12

__

C. Addition of the two polynomials results in a polynomial. Subtraction of the two polynomials results in a polynomial. There is nothing here to indicate the set of polynomials is not closed under addition and subtraction.


Related Questions

Given: 8(y + 2) = 48
Solve for “y.”

16
-6
20
4

Answers

To equal 48 y should equal 4

Since (y+2) is in parenthesis it always goes first

Substitute 4 for y so added to 2 it equals 6

6x8=48

The value of y will be equal to 4. The correct option is D.

What is an expression?

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

The given expression 8(y + 2) = 48 will be solved for y as below:-

8(y + 2) = 48

Divide both sides by 8 and solve.

[ 8 (y + 2) ] / 8 = 48 / 8

y + 2 = 6

Substract 2 from both the sides to get the value of y.

y + 2 - 2 = 6 -2

y = 4

Therefore, the value of y will be equal to 4. The correct option is D.

To know more about Expression follow

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Geometry pls help !!! Find the value of AB.
AB = [?]

Answers

Answer:

AB = 16 Units

Step-by-step explanation:

In the given figure, CD is the diameter and AB is the chord of the circle.

Since, diameter of the circle bisects the chord at right angle.

Therefore, AE = 1/2 AB

Or AB = 2AE...(1)

Let the center of the circle be given by O. Join OA.

OA = OD = 10 (Radii of same circle)

Triangle OAE is right triangle.

Now, by Pythagoras theorem:

[tex] OA^2 = AE^2 + OE^2 \\

10^2 = AE^2 + 6^2 \\

100= AE^2 + 36\\

100-36 = AE^2 \\

64= AE^2 \\

AE = \sqrt{64}\\

AE = 8 \\

\because AB = 2AE..[From \: equation\: (1)] \\

\therefore AB = 2\times 8\\

\huge \purple {\boxed {AB = 16 \: Units}} [/tex]

A car dealership is advertising a car for $16,299.99. If the sales tax rate is 6.5 percent, what
is the total tax paid for the car?
A. S993 34
B. $1.000.00
CS1.059 50
DS1.359.19

Answers

Answer:

C. 1059.50

Step-by-step explanation:

Sales price x sales tax rate = sales tax

16299.99 x .065 (6.5%) = 1059.50

In a study of 100 new cars, 29 are white. Find and g, where
is the proportion of new cars that are white.​

Answers

Question

In a study of 100 new cars, 29 are white. Find p and q , where p is the proportion of new cars that are white.

Answer:

p = 0.29  and q = 0.71

Step-by-step explanation:

Given

Total new cars =  100

White new cars = 29

Required

Determine p and q

From the question;

p represents white new cars

Hence;

[tex]p = 29[/tex]

Note that;

[tex]p + q = 100[/tex]

Substitute 29 for p

[tex]29 + q = 100[/tex]

[tex]29 - 29 + q = 100 - 29[/tex]

[tex]q = 100 - 29[/tex]

[tex]q = 71[/tex]

The proportion of p is calculate by dividing p by the total number of new cars (Same process is done for q)

For proportion of p

[tex]Proportion,\ p = \frac{p}{new\ cars}[/tex]

[tex]Proportion,\ p = \frac{29}{100}[/tex]

[tex]Proportion,\ p = 0.29[/tex]

For proportion of q

[tex]Proportion,\ q = \frac{q}{new\ cars}[/tex]

[tex]Proportion,\ q = \frac{71}{100}[/tex]

[tex]Proportion,\ q = 0.71[/tex]

Use Newton's method to find all solutions of the equation correct to six decimal places. (Enter your answers as a comma-separated list.) ln(x) = 1 /x − 3

Answers

Answer:

  x ≈ {0.653059729092, 3.75570086464}

Step-by-step explanation:

A graphing calculator can tell you the roots of ...

  f(x) = ln(x) -1/(x -3)

are near 0.653 and 3.756. These values are sufficiently close that Newton's method iteration can find solutions to full calculator precision in a few iterations.

In the attachment, we use g(x) as the iteration function. Since its value is shown even as its argument is being typed, we can start typing with the graphical solution value, then simply copy the digits of the iterated value as they appear. After about 6 or 8 input digits, the output stops changing, so that is our solution.

Rounded to 6 decimal places, the solutions are {0.653060, 3.755701}.

_____

A similar method can be used on a calculator such as the TI-84. One function can be defined a.s f(x) is above. Another can be defined as g(x) is in the attachment, by making use of the calculator's derivative function. After the first g(0.653) value is found, for example, remaining iterations can be g(Ans) until the result stops changing,

PLEASE HELP!!!!!!! FIRST CORRECT ANSWER WILL BE THE BRAINLIEST....PLEASE HELP
Lunch Choices of Students
The bar graph shows the percent of students that chose each food in the school
cafeteria. Which statement about the graph is true?

Answers

Answer:

(2) If 300 lunches were sold, then 120 chose tacos.

Step-by-step explanation:

We can evaluate each option and see if it makes it true.

For 1: If 200 lunches were served, 10 more students chose pizza over hotdogs.

We can find how many pizzas/hotdogs were given if 200 lunches were served by relating it to 100.

20% chose hotdog, which is [tex]\frac{20}{100}[/tex]. Multiply both the numerator and denominator by two: [tex]\frac{40}{200}[/tex] - so 40 students chose hotdogs.

Same logic for pizza: 30% chose pizza - [tex]\frac{30}{100} = \frac{60}{200}[/tex] so 60.

60 - 40 = 20, not 10, so 1 doesn't work.

2: If 300 lunches were sold, then 120 chose tacos.

Let's set up a proportion again. 40% of 100 is 40.

[tex]\frac{40}{100} = \frac{40\cdot3}{300} = \frac{120}{300}[/tex]

So 120 tacos were chosen - yes this works!

Hope this helped!

help asap!!
Find the length of AB
A. 2.89
B. 33.13
C. 378.63
D. 377.19

Answers

Answer:

C

Step-by-step explanation:

[tex] \sin( 5 ^{o} ) = \frac{33}{ab} \\ ab = 378.63[/tex]

The answer is C……………….

somebody please help

Answers

Answer: 3

Explanation:

x^2 + 6x + 9
= (x + 3)^2

The cost in dollars y of producing x computer
desks is given by y = 20x + 3000
х
100
200
300
a. Complete the table
y
b. Find the number of computer desks that can be produced for $4300. (HintFind x when y = 4300)
a. Complete the table.
х
100
200
300
y
b. For $4300, computer desks can be produced.

Answers

Answer:

Step-by-step explanation:

a. table

x = 100,y = 20*100+3000 = 2000+3000 = 5000

x = 200,y = 20*200+3000 = 4000+3000 = 7000

x = 300,y = 20*300+3000 = 6000+3000 = 9000

b:

y = 4300

4300 = 20x+3000

20x = 4300-3000

20x = 1300

x = 1300/20

x  = 65

so 65 computer desks can be produced.

What is the approximate area of the unshaded region under the standard normal curve below? Use the portion of the standard normal table given to help answer the question.

A normal curve with a peak at 0 is shown. The area under the curve shaded is 1 to 2.

z
Probability
0.00
0.5000
1.00
0.8413
2.00
0.9772
3.00
0.9987
0.14
0.16
0.86
0.98

Answers

Answer:

0.14

Step-by-step explanation:

The z score is a score used in statistics to determine by how many standard deviations ti the raw score above or below the mean. If the raw score is above the mean then the z score is positive while If the raw score is below the mean then the z score is negative, It is given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

From the normal distribution table, The area under the curve shaded is 1 to 2 = P(1 < z < 2) = P(z < 2) - P(z < 1) = 0.9772 - 0.8413 = 0.1359 ≈ 0.14

The area under the curve shaded is 1 to 2 is 0.14

What are probabilities?

Probabilities are used to determine the chances of an event

The shaded region represents the probability of the z-scores

The shaded region 1 to 2 is represented as:

P(1 < z < 2) =

Using the probability of z-score, we have the formula

P(1 < z < 2) = P(z < 2) - P(z < 1)

From the given standard normal table:

P(z < 2) = 0.9772

P(z < 1) = 0.8413

So, we have:

P(1 < z < 2) = 0.9772 - 0.8413

P(1 < z < 2) = 0.1359

Approximate

P(1 < z < 2) = 0.14

Hence, the area under the curve shaded is 1 to 2 is 0.14

Read more about normal distribution at:

https://brainly.com/question/4079902

a sample of 25 workers with employer provided health insurance paid an average premium of $6600 eith a sample standard deviation of $800. Construct a 95% confidence interval for the mean premium amount paid by all workers who have employer provided health insurance g

Answers

Answer:

$6284.4≤μ≤$6313.6

Step-by-step explanation:

Using the formula for calculating confidence interval as shown:

CI = xbar ± Z×S/√n

xbar is the average premium

Z is the z-score at 95% confidence

S is the standard deviation

n is the sample size

Given parameters

xbar = $6600

Z score at 95% CI = 1.96

S = $800

n = 25

Substituting this parameters in the formula we have;

CI = 6600±1.96×800/√25

CI = 6600±(1.96×800/5)

CI = 6600±(1.96×160)

CI = 6600±313.6

CI = (6600-313.6, 6600+313.6)

CI = (6284.4, 6913.6)

Hence the 95% confidence interval for the mean premium amount paid by all workers who have employer provided health insurance is $6284.4≤μ≤$6313.6

Determine whether Rolle's Theorem can be applied to f on the closed interval
[a, b].
f(x) = −x2 + 3x, [0, 3]
Yes, Rolle's Theorem can be applied.No, because f is not continuous on the closed interval [a, b].No, because f is not differentiable in the open interval (a, b).No, because f(a) ≠ f(b).
If Rolle's Theorem can be applied, find all values of c in the open interval
(a, b)
such that
f '(c) = 0.
(Enter your answers as a comma-separated list. If Rolle's Theorem cannot be applied, enter NA.)
c =

Answers

Answer:

Yes, Rolle's theorem can be applied

There is only one value of c such that f'(c) = 0, and this is c = 1.5 (or 3/2 in fraction form)

Step-by-step explanation:

Yes, Rolle's theorem can be applied on this function because the function is continuous in the closed interval (it is a polynomial function) and differentiable  in the open interval, and f(a) = f(b) given that:

[tex]f(0)=-0^2+3\,(0)=0\\f(3)=-3^2+3\,(3)=-9+9=0[/tex]

Then there must be a c in the open interval for which f'(c) =0

In order to find "c", we derive the function and evaluate it at "c", making the derivative equal zero, to solve for c:

[tex]f(x)=-x^2+3\,x\\f'(x)=-2\,x+3\\f'(c)=-2\,c+3\\0=-2\,c+3\\2\,c=3\\c=\frac{3}{2} =1.5[/tex]

There is a unique answer for c, and that is c = 1.5

Rolle's theorem is applicable if [tex]f(a)=f(b)[/tex] and $f$ is differentiable in $(a,b)$

since it's polynomial function, it's always continuous and differentiable..

and you can easily check that $f(0)=f(-3)=0$

so it is applicable.

now, $f'(x)=-2x+3=0 \implies x=\frac32$

there is only once value (as you can imagine, the graph will be downward parabola)

An athletic club charges a monthly membership
fee of $65. Members can also take classes for an
additional $15 per class. For this month only, the
club has a special that includes two free classes for
all new members. Which of the following functions
expresses the cost for the month for new members
who take x classes this month, where x > 2?
(A) C(x) = 2x + 65
(B) C(x) = 15x + 65
(C) C(x) = 2(x - 15) + 65
(D) C(x) = 15(x - 2) + 65

Answers

Answer: D

Explanation:

Special case:

New membership cost 65 but also free 2 class. However, the cost of a new member who takes x class where x > 2 which mean 2 or more class.

C(x) = 65$ + 15(x - 2)$

Find the midpoint of the segment between the points (8,−10) and (−10,−8) A. (−1,−9) B. (0,−6) C. (0,0) D. (−1,2)

Answers

Answer:

Hey there!

We can use the midpoint formula to find that the midpoint is (-1, -9).

Let me know if this helps :)

The midpoint of the segment between the points (8,−10) and (−10,−8) will be (−1, −9). Then the correct option is A.

What is the midpoint of line segment AB?

Let C be the mid-point of the line segment AB.

A = (x₁, y₁)

B = (x₂, y₂)

C = (x, y)

Then the midpoint will be

x = (x₁ + x₂) / 2

y = (y₁ + y₂) / 2

The midpoint of the segment between the points (8,−10) and (−10,−8)

x = (8 – 10) / 2

x = –1

y = (– 10 – 8) / 2

y = –9

Then the correct option is A.

More about the midpoint of line segment AB link is given below.

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Expand (2+x)^-3







....

Answers

Answer:

1/(x^3 + 6x^2 + 12x + 8)

Step-by-step explanation:

The first thing we do is rationalize this expression. (2+x)^-3 is written as

1/(2+x)^3

Then from there we can foil out the denominator. It is easiest to foil (2+x)(2+x) first and then multiply that product by (2+x).

(2+x)(2+x) = 4 + 4x + x^2

(4+4x+x^2)(2+x) = 8+8x+2x^2+4x+4x^2+x^3.

Then we combine like terms and put them in order to get:

x^3 + 6x^2 + 12x + 8

And of course we can't forget that this was raised to the negative third power, so our answer is 1/(x^3 + 6x^2 + 12x + 8)

Answer:

Hello,

Step-by-step explanation:

[tex](a+x)^n=a^n+\left(\begin{array}{c}n\\ 1\end{array}\right)*a^{n-1}*x+\left(\begin{array}{c}n\\ 2\end{array}\right)*a^{n-2}*x^2+\left(\begin{array}{c}n\\ 3\end{array}\right)*a^{n-3}*x^3+\left(\begin{array}{c}n\\ 4\end{array}\right)*a^{n-4}*x^4+...+\left(\begin{array}{c}n\\ n\end{array}\right)*a^{n-n}*x^n[/tex]

[tex]with \\\\\left(\begin{array}{c}n\\ 1\end{array}\right)=n\\\\\left(\begin{array}{c}n\\ 2\end{array}\right)=\dfrac{n(n-1)}{2!} \\\\\left(\begin{array}{c}n\\3 \end{array}\right)=\dfrac{n(n-1)(n-2)}{3!} \\\\...\\[/tex]

[tex]\dfrac{1}{(2+x)^3} =\dfrac{1}{8} +3*\dfrac{x}{4}+3\dfrac{x^2}{2}+x^3\\\\[/tex]

A helicopter is at a cruising height of 1,200 feet. Suppose the angle of depression to the landing pad is 15°, which is located on top of a building that is 64 feet high. If the helicopter continues at the current cruising height, how far does the helicopter need to travel to be directly above the landing pad? Include a sketch that shows all known information and clearly shows what you need to find. Show all work and give the answer rounded to the nearest foot.

Answers

Answer:

we have a right triangle and to get the internal angle of the right triangle formed at the helicopter we subtract 62 degrees from 90 which equals 28 degrees

we now use the cosine to find the distance (d) from the helicopter

cosine 28 = 85/d

d = 85 / cosine 28 = 85 / 0.8829 = 96.2736 = 96 feet

What is the true solution to the equation below? 2 in e in2×-in e in 10×= in 30 A x=30 B x=75 C x=150 D x=300

Answers

Answer:

Option B.

Step-by-step explanation:

Let as consider the given equation:

[tex]2\ln e^{\ln 2x}-\ln e^{\ln 10x}=\ln 30[/tex]

It can be written as

[tex]2(\ln 2x)-(\ln 10x)=\ln 30[/tex]         [tex][\because \ln e^a=a][/tex]

[tex]\ln (2x)^2-(\ln 10x)=\ln 30[/tex]        [tex][\because \ln a^b=b\ln a][/tex]

[tex]\ln \dfrac{4x^2}{10x}=\ln 30[/tex]        [tex][\because \ln \dfrac{a}{b}=\ln a-\ln b][/tex]

[tex]\ln \dfrac{2x}{5}=\ln 30[/tex]

On comparing both sides, we get

[tex]\dfrac{2x}{5}=30[/tex]

Multiply both sides by 5.

[tex]2x=150[/tex]

Divide both sides by 2.

[tex]x=75[/tex]

Therefore, the correct option is B.

Answer:

b x=75

Step-by-step explanation:

The research group asked the following question of individuals who earned in excess of​ $100,000 per year and those who earned less than​ $100,000 per​ year: "Do you believe that it is morally wrong for unwed women to have​ children?" Of the individuals who earned in excess of​ $100,000 per​ year, said​ yes; of the individuals who earned less than​ $100,000 per​ year, said yes. Construct a​ 95% confidence interval to determine if there is a difference in the proportion of individuals who believe it is morally wrong for unwed women to have children.

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  lower bound is  [tex]0.0234[/tex]

The  upper bound is  [tex]0.100[/tex]

So from the value obtained the solution to the question are

  1  Does not include

  2 sufficient

 3  not different  

Step-by-step explanation:

From the question we are told that

The  sample size of  individuals who earned in excess of​ $100,000 per​ year is   [tex]n_ 1 = 1205[/tex]

The  number of  individuals who earned in excess of​ $100,000 per​ year  that said yes is

    [tex]w = 712[/tex]

The  sample size  individuals who earned less than​ $100,000 per​ year is [tex]n_2 = 1310[/tex]

The  number of  individuals who earned less than​ $100,000 per​ year that said yes is

       [tex]v= 693[/tex]

The sample proportion of  individuals who earned in excess of​ $100,000 per​ year  that said yes is

           [tex]\r p _ 1 = \frac{w}{n_1 }[/tex]

substituting values

          [tex]\r p _ 1 = \frac{712}{1205}[/tex]

          [tex]\r p _ 1 =0.5909[/tex]

The sample proportion of  individuals who earned less than​ $100,000 per​ year that said yes is

          [tex]\r p _ 1 = \frac{v}{n_2 }[/tex]

substituting values

         [tex]\r p _ 1 = \frac{693 }{1310}[/tex]

        [tex]\r p _ 1 = 0.529[/tex]

Given that the confidence level is  95% then the level of significance is mathematically represented as

           [tex]\alpha = 1 -0.95[/tex]

           [tex]\alpha = 0.05[/tex]

 Next we obtain the critical value of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table the value is  [tex]Z_{\frac{\alpha }{2} } = 1.96[/tex]

    Generally the margin of error is  

   [tex]E = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{ \r p _1 (1- \r p_1 )}{n_1} + \frac{ \r p _2 (1- \r p_2 )}{n_2} } }[/tex]

substituting values

   [tex]E = 1.96 * \sqrt{ \frac{ 0.5909 (1- 0.5909 )}{1205} + \frac{ 0.592 (1- 0.6592 )}{1310} } }[/tex]

    [tex]E =0.03846[/tex]

Generally the 95% confidence interval is  

        [tex](\r p_1 - \r p_2) - E < p_1 - p_2 <( \r p_1 - \r p_2 ) + E[/tex]

substituting values

        [tex](0.5909 - 0.529 ) - 0.03846 < p_1 - p_2 < (0.5909 - 0.529 ) + 0.03846[/tex]

         [tex]0.02344 < p_1 - p_2 < 0.10036[/tex]

The  lower bound is  [tex]0.0234[/tex]

The  upper bound is  [tex]0.100[/tex]

So from the value obtained the solution to the question are

  1  Does not include

  2 sufficient

 3  not different  

The lower bound is 0.0234 and the upper bound is 0.100. Then the 95% confidence interval is (0.0234, 0.100)

What is the margin of error?

The probability or the chances of error while choosing or calculating a sample in a survey is called the margin of error.

The research group asked the following question of individuals who earned in excess of​ $100,000 per year and those who earned less than​ $100,000 per​ year.

The sample size of individuals who earned in excess of $100,000 per year will be

[tex]\rm n_1 =1205[/tex]

The sample size of individuals who earned less than $100,000 per year will be

[tex]\rm n_1 =1205[/tex]

The number of individuals who earn an excess of $100,000 per year that said yes will be

[tex]\rm w = 712[/tex]

The number of individuals who earn less than $100,000 per year that said yes will be

[tex]\rm v= 693[/tex]

Then the sample proportion of individuals who earned in excess of $100,000 per year that said yes will be

[tex]\rm \hat{p}_1=\dfrac{w}{n_1}\\\\\hat{p}_1=\dfrac{712}{1205}\\\\\hat{p}_1= 0.5909[/tex]

Then the sample proportion of individuals who earned less than $100,000 per year that said yes will be

[tex]\rm \hat{p}_2=\dfrac{v}{n_2}\\\\\hat{p}_2=\dfrac{693}{1310}\\\\\hat{p}_2= 0.529[/tex]

The confidence level is 95% then the level of significance is mathematically represented as

[tex]\alpha =1-0.95\\\\\alpha =0.05[/tex]

Then the critical value of α/2 from the normal distribution table. Then the value of z is 1.96, then the error of margin will be

[tex]E = z_{\alpha /2} \times \sqrt{\dfrac{\hat{p}_1(1-\hat{p}_1)}{n_1} + \dfrac{\hat{p}_2(1-\hat{p}_2)}{n_2}}\\\\E = 1.96 \times \sqrt{\dfrac{05909(1-0.5909)}{1205} + \dfrac{0.529(1-0529)}{1310}}\\\\E = 0.03846[/tex]

The 95% confidence interval will be

[tex]\begin{aligned} (\hat{p}_1-\hat{p}_2)-E & < p_1-p_2 < (\hat{p}_1-\hat{p}_2) + E\\\\(0.5909 - 0.529) - 0.03846 & < p_1-p_2 < (0.5909 - 0.529) + 0.03846\\\\0.02344 & < p_1-p_2 < 0.10036 \end{aligned}[/tex]

More about the margin of error link is given below.

https://brainly.com/question/6979326

If you draw one card at random, what is the probability that card is a (n) Heart?

Answers

Answer:

1/13

Step-by-step explanation:

There are 52 cards in a deck of cards and 13 of them are hears

P(heart) = hearts / total

              = 13/52 = 1/13

Write six hundred twelve thousand, three hundred in the place-value chart. Then write the number in expanded

Answers

Answer:

612,300

600,000

10,000

2,000

300

00

0

In a mathematics class, half of the students scored 86 on an achievement test. With the exception of a few students who scored 46, the remaining students scored 77. Which of the following statements is true about the distribution of scores

Answers

Answer:

B. The mean is less than the median.

Step-by-step explanation:

Say there was 20 kids: 10 kids(half) scored 86's, 3 kids(a few) scored 45's, and 7 kids(the remaining) scored 77's.

The median would be- 81.5 (chronological order, find the middle number)

The mean would be- 76.85 (sum of all the scores divided by the number of scores)

The mode would be- 86 (most frequent number)

The mean(76.85) is less than(<) the median(81.5)


Amira starts an exercise programme on the 3rd of March. She decides she will swim every
3 days and cycle every 4 days. On which dates in March will she swim and cycle on the
same day?

Answers

Answer:

12 days

Step-by-step explanation:

The answer of the problem is the LCM of 3 and 4=12. Hence the answer is 12 days

On 12 March she will swim and cycle on the same day if Amira starts an exercise program on the 3rd of March.

What is LCM?

It is defined as the common number of two integers, which is the lowest number that is a multiple of two or more numbers. The full name of LCM is the least common multiple.

We have:

Amira starts an exercise program on the 3rd of March.

She will swim every 3 days and cycle every 4 days.

Total days =3 + 4 = 7 days = 1 week

The day she swims and cycles on the same day = LCM of 3 and 4

= 3, 6, 9, 12, 15

= 4, 8, 12, 16

= 12

Thus, on 12 March she will swim and cycle on the same day if Amira starts an exercise program on the 3rd of March.

Learn more about the LCM here:

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Which of the following expressions represents a function? (5 points) a {(1, 2), (4, −2), (8, 3), (9, −3)} b y2 = 16 − x2 c 2x2 + y2 = 5 d x = 7

Answers

Answer: Option "a" is the only expression that represents a function.

Step-by-step explanation:

A function f(x) = y is a "operator" that takes an input element, x, and assigns it to only one output element, y.

So, if we have that for a given value of x.

f(x) = y and f(x) = h

where y and h are different values, then this is not a function, because is assigning the input value x to two different output values.

Let's see the different options:

a) {(1, 2), (4, −2), (8, 3), (9, −3)}

This points are of the form (x, y)

We can see that each value of x is assigned to only one value of y, so this can represent a function.

b)  y^2 = 16 − x^2

Ok, suppose that x = 0, then:

y^2 = 16 - 0 = 16

then we have that y*y = 16.

So y can take two different values:

y = 4 ---> 4*4 = 16

y = -4 ---> -4*-4 = 16.

So this is not a function.

c) 2x^2 + y^2 = 5

First, we want to isolate y in one side:

y^2 = 5 - 2*x^2

Here we have a similar case to the option b, and we can use a similar argument to prove that this is not a function, so we can discard this.

d) x = 7.

Ok, this is not a relation between two variables, so this is not a function, as if x is the input value, we have only one value of x that solves the equation.

You are an urban planner assessing the growth of a city. Ten years ago, the city's population was 250,823. Its current population is 325,823. By about what percentage has the city grown over the past ten years? Round to the nearest percent.

Answers

Answer:

Here is the answer i got-

Step-by-step explanation:

325823-250823=75000

325823’s 244367250percent is 75000

In triangle ABC, ∠ABC=70° and ∠ACB=50°. Points M and N lie on sides AB and AC respectively such that ∠MCB=40° and ∠NBC=50°. Find m∠NMC.

Answers

Answer:

∠NMC  = 50°

Step-by-step explanation:

The interpretation of the information given in the question can be seen in the attached images below.

In ΔABC;

∠ A + ∠ B + ∠ C = 180°    (sum of angles in a triangle)

∠ A + 70°  + 50°  = 180°

∠ A = 180° - 70° - 50°

∠ A =  180° - 120°

∠ A =  60°

In ΔAMN ; the base angle are equal , let the base angles be x and y

So; x = y   (base angle of an equilateral  triangle)

Then;

x + x + 60° = 180°

2x +  60° = 180°

2x = 180° - 60°

2x = 120°

x = 120°/2

x = 60°

∴ x = 60° , y = 60°

In ΔBQC

∠a + ∠e + ∠b = 180°

50° + ∠e + 40° = 180°

∠e = 180° - 50° - 40°

∠e = 180° - 90°

∠e = 90°

At point Q , ∠e = ∠f = ∠g = ∠h = 90°  (angles at a point)

∠i  = 50° - 40° = 10°

In ΔNQC

∠f + ∠i   + ∠j = 180°

90° + 10° + ∠j = 180°

∠j  = 180° - 90°-10°

∠j  = 180° - 100°

∠j  = 80°

From  line AC , at point N , ∠y + ∠c + ∠j = 180°   (sum of angles on a straight line)

60° + ∠c + ∠80° = 180°

∠c  = 180° - 60°-80°

∠c  = 180° - 140°

∠c  = 40°

Recall that :

At point Q , ∠e = ∠f = ∠g = ∠h = 90°  (angles at a point)

Then In Δ NMC ;

∠d + ∠h + ∠c = 180°   (sum of angles in a triangle)

∠d + 90° + 40° = 180°

∠d  = 180° - 90° -40°

∠d  = 180° - 130°

∠d  = 50°

Therefore, ∠NMC = ∠d  = 50°

A report states that the mean yearly salary offer for students graduating with a degree in accounting is $48,722. Suppose that a random sample of 50 accounting graduates at a large university who received job offers resulted in a mean offer of $49,870 and a standard deviation of $3900. Do the sample data provide strong support for the claim that the mean salary offer for accounting graduates of this university is higher than the national average of $48,722? Test the relevant hypotheses using α = 0.05. State your conclusion.A. Reject H0. We do not have convincing evidence that the mean salary offer for accounting graduates of this university is higher than the national average of $48,722.B. Do not reject H0. We do not have convincing evidence that the mean salary offer for accounting graduates of this university is higher than the national average of $48,722.C. Reject H0. We have convincing evidence that the mean salary offer for accounting graduates of this university is higher than the national average of $48,722.D. Do not reject H0. We have convincing evidence that the mean salary offer for accounting graduates of this university is higher than the national average of $48,722.

Answers

Answer:

Option C - Reject H0. We have convincing evidence that the mean salary offer for accounting graduates of this university is higher than the national average of $48,722.

Step-by-step explanation:

First of all let's define the hypothesis;

Null hypothesis;H0; μ = $48,722

Alternative hypothesis;Ha; μ > $48,722

Now, let's find the test statistic for the z-score. Formula is;

z = (x' - μ)/(σ/√n)

We are given;

x' = 48,722

μ = 49,870

σ = 3900

n = 50

Thus;

z = (49870- 48722)/(3900/√50)

z = 2.08

So from online p-value calculator as attached, using z = 2.08 and α = 0.05 ,we have p = 0.037526

This p-value of 0.037526 is less than the significance value of 0.05,thus, we reject the claim that that the mean salary offer for accounting graduates of this university is higher than the national average of $48,722

Assume the triangular prism has a base area of 49cm^2 and a volume of 588cm^3. What side length does the rectangular prism need to have the same volume?

Answers

Answer:

Length = Width = 7 cm

Step-by-step explanation:

Volume of a triangular prism is represented by the formula,

Volume = (Area of the triangular base) × height

588 = 49 × h

h = [tex]\frac{588}{49}[/tex]

h = 12 cm

We have to find the side length of a rectangular prism having same volume.

Volume = Area of the rectangular base × height

588 = (l × b) × h [l = length and b = width ]

588 = (l × b) × 12

l × b = 49 = 7 × 7

Therefore, length = width = 7 cm may be the side lengths of the rectangular prism to have the same volume.              

Solve 5x + 3 = -7x + 21

Answers

Answer:

x = 3/2

Step-by-step explanation:

5x + 3 = -7x + 21

5x - -7x = 21 - 3

12x = 18

x = 18/12

x = 3/2

Which of the fractions below are less than 2/5? Select two.

Answers

Answer:

1/8 is less than

Step-by-step explanation:

i dont see any fractions below gona have to edit your answer

A graphics designer is designing an advertising brochure for an art show. Each page of the brochure is rectangular with an area of 52 in^2 and a perimeter of 30in. Find the dimensions of the brochure. The longer side is _____in. The shorter side is ______ in.

Answers

9514 1404 393

Answer:

9.562 in5.438 in

Step-by-step explanation:

The sum of side lengths of a rectangle is half the perimeter, so is 15 inches for this brochure. If x is one of the side lengths, then (15 -x) is the other one, and the area is ...

  x(15 -x) = 52

  x^2 -15x = -52 . . . . multiply by -1 and expand

  (x -7.5)^2 = -52 +56.25 = 4.25 . . .  complete the square

  x = 7.5 ±√4.25 ≈ {5.438, 9.562} . . . inches

The longer side is 7+√4.25 ≈ 9.562 inches; the shorter side is 7-√4.25 ≈ 5.438 inches.

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