Solve for 2 in the diagram below.
45°
150
42°
ea
Stuck? Watch a video or use a hint.

Solve For 2 In The Diagram Below.4515042eaStuck? Watch A Video Or Use A Hint.

Answers

Answer 1

Step-by-step explanation:

Hi, there!!!

It's so simple..

Let me clear you, alright.

Here, On the fig line, OE is just a confusing line. If you look it in simple way,

AB and CD are interested at a point O.

so, angle AOD and angle COB are equal.{ because they are vertically opposite angle}

so, angle AOD= angle COB

or, 4x°=45°+15°

or, 4x°= 60°

or, x= 60°/4

Therefore, x= 15°.

Hope it helps....

Solve For 2 In The Diagram Below.4515042eaStuck? Watch A Video Or Use A Hint.

Related Questions

Find the interquartile range of the following data set.
Number of Points Scored at Ten Basketball Games
57 63 44 29 36 62 48 50 42 34
a .21
B.28
C. 6
D. 34

Answers

Answer:

b.28 its ans is no.b

Step-by-step explanation:

no point score in basketball

How many solutions does this system of equations have?

y = -1/3x+7

y = -2x3 + 5x2 + x - 2

O A.

no solution

OB

1 solution

O C.

2 solutions

OD

3 solutions

Answers

Answer:

1 solution

Step-by-step explanation:

the two equations only cross once

The system of equations may have either 2 or 1 solution, but we cannot determine the exact number of solutions without further information or analysis.

We have,

The given system of equations consists of two equations in two variables:

y = (-1/3)x + 7 _______(1)

y = -2x³ + 5x² + x - 2 _______(2)

To find the solutions of the system, we need to find the values of x and y that satisfy both equations simultaneously.

Since both equations are in the form y = ...,

we can set the expressions on the right-hand sides of the equations equal to each other:

(-1/3)x + 7 = -2x³ + 5x² + x - 2

Rearranging and simplifying, we get:

2x³ - 5x² - (2/3)x + 9 = 0

To solve for x, we can use factoring or the rational root theorem.

However, the polynomial on the left-hand side of the equation does not appear to have any rational roots or easily factorable forms.

Therefore, to determine the number of solutions,

we can use Descartes' rule of signs to find the possible number of positive and negative roots of the polynomial:

The number of positive roots is either equal to the number of sign changes in the coefficients or less than it by an even integer.

There are two sign changes in the coefficients, so there can be either 2 or 0 positive roots.

The number of negative roots is either equal to the number of sign changes in the coefficients or less than it by an even integer.

There is one sign change in the coefficients, so there can be either 1 or 0 negative roots.

Since the sum of the possible number of positive and negative roots is either 2 or 1, the total number of solutions is either 2 or 1.

Therefore,

The system of equations may have either 2 or 1 solution, but we cannot determine the exact number of solutions without further information or analysis.

Learn more about solutions of equations here:

https://brainly.com/question/545403

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Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in the variability in service time (in hours) spent by mechanics fixing the same automotive problem. A random sample was taken resulting in a sample of size 20 from a substantial file of reported experience. The summary statistics are as follows: n = 20, sample mean = 13.8 hours, sample standard deviation = 3.9 hours. Assume service time follows a normal distribution. Round to two decimal places.

Answers

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - α)% confidence interval for the population variance is given as follows:

[tex]\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}[/tex]

It is provided that:

n = 20

s = 3.9

Confidence level = 95%

α = 0.05

Compute the critical values of Chi-square:

[tex]\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907[/tex]

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

[tex]\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}[/tex]

[tex]\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45[/tex]

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

I need to know what’s 500+0+12+44+55+500+0+12+44+55+ 500+0+12+44+55+500+0+12+44+55+

Answers

Answer:

Step-by-step explanation:

2,444

Answer:

2,444.

Step-by-step explanation:

500+0+12+44+55+500+0+12+44+55+ 500+0+12+44+55+500+0+12+44+55 = 500 + 12 + 44 + 55 + 500 + 12 + 44 + 55 + 500 + 12 + 44 + 55 + 500 + 12 + 44 + 55 = 4(500 + 12 + 44 + 55) = 4(512 + 99) = 4(611) = 2,444.

Hope this helps!

Найдите наибольшее значение функции y=8ln(x+7)-8x+3 на отрезке [-6,5;0]

Answers

Answer:

Maximum at (-6,51), or value of f(-6) = 51

Step-by-step explanation:

f(x) = 8*log(x+7)-8*x+3

differentiate with respect to x

f'(x) = 8/(x+7) -8

To find maximum, set f'(x) = 0

f'(x) = 8/(x+7) -8 = 0

solver for x

x= -6

evaluate f(x) at x=-6

f(-6) = 8log(-6+7) - 8(-6) + 3

= 0 +48 +3

= 51

Note: next time please post only in English.  This post will soon be deleted.

5.39 jings =15.4 hings
4.9 hings = 2.8 gings

According to the conversion rates above, how
many jings equal 1 ging?
E. 7/40
F. 5/8
G. 49/80
H. 20/7

Answers

Step-by-step explanation:

It is given that,

5.39 jings =15.4 hings  ....(1)

4.9 hings = 2.8 gings ...(2)

From equation (2), the value of 1 ging is :

[tex]1\ \text{ging} = \dfrac{4.9}{2.8}\ \text{hing}\ .....(3)[/tex]

From equation (1), the value of 1 jing is :

[tex]1\ \text{jing} = \dfrac{15.4}{5.39}\ \text{hing}\ .....(4)[/tex]

From equation (3) and (4), we get :

[tex]\dfrac{\text{1 ging}}{\text{1 jing}}=\dfrac{4.9}{2.8}\times \dfrac{5.39}{15.4}\\\\\dfrac{\text{1 ging}}{\text{1 jing}}=\dfrac{49}{80} \\\\1\ \text{ging}=\dfrac{49}{80}\ \text{ jings}[/tex]

Hence, the correct option is (g) "49/80"

The product of a number and 3 is equal to 15 minutes twice the number, find the number.​

Answers

Answer:

The answer is 3

Step-by-step explanation:

Let the number to be found be x

The product of a number and 3 is written as

3 × x = 3x

15 minus twice the number is written as

15 - 2x

Now equate the two statements

That's

3x = 15 - 2x

Group like terms

3x + 2x = 15

5x = 15

Divide both sides by 5

the final answer is

x = 3

Hope this helps you

How should a musician effectively convey emotions or ideas in a performance?

Answers

Answer:

Within the factors hindering expression in music, tempo is the most important number of factors such as your mood.

Step-by-step explanation:

If one wants to convey a message, they should try these:

a) Use real life

b) introduce symbolism

c) convey sensory disruption, e.t.c.

Hope these helps.

What is the answer -13.62-(27.9)

Answers

Answer:

−  1049

Step-by-step explanation:

-13.62-(27.9)

primero haremos los paréntesis y después las demás multiplicaciones de izquierda a derecha.

-13.62-243

-806-243

Finalmente tenemos −  1049

Espero te ayude :)

Answer:

-41.52

Step-by-step explanation:

-13.62 - (27.9) = -13.62 - 27.9

When you subtract from a negative, the answer will be smaller than the starting number:

-13.62 - 27.9 = -41.52

Therefore, the answer is -41.52.

ΔABC is similar to ΔMNO. The scale factor from ΔMNO to ΔABC is 3∕2 . If the area of ΔMNO is 10 square units, what's the area of ΔABC? Question 12 options: A) 45 square units B) 90 square units C) 22.5 square units D) 15 square units

Answers

Answer:

The area of ΔABC= 6.667 square units

Step-by-step explanation:

ΔABC is similar to ΔMNO.

The scale factor from ΔMNO to ΔABC is 3∕2

the area of ΔMNO is 10 square units,

The area of ΔABC/the area of ΔMNO

= 2/3

The area of ΔABC/10= 2/3

The area of ΔABC= 2/3 * 10

The area of ΔABC= 20/3

The area of ΔABC= 6 2/3

The area of ΔABC= 6.667 square units

Answer:

22.5 square units

Step-by-step explanation:

i multiplied 10 by 2 to get 20 and went with the closest answer and got it right.

i dont know how to do math but i guess it worked

The amount of money spent on textbooks per year for students is approximately normal.
A. To estimate the population mean, 19 students are randomly selected the sample mean was $390 and the standard deviation was $120. Find a 95% confidence for the population meam.
B. If the confidence level in part a changed from 95% 1 to 1999%, would the margin of error for the confidence interval:
1. decrease.
2. stay the same.
3. increase not.
C. If the sample size in part a changed from 19% 10 to 22, would the margin of errot for the confidence interval:
1. decrease.
2. stay the same.
3. increase
D. To estimate the proportion of students who purchase their textbookslused, 500 students were sampled. 210 of these students purchased used textbooks. Find a 99% confidence interval for the proportion of students who purchase used text books.

Answers

Answer:

(A) A 95% confidence for the population mean is [$332.16, $447.84] .

(B) If the confidence level in part (a) changed from 95% to 99%, then the margin of error for the confidence interval would increase.

(C) If the sample size in part (a) changed from 19 to 22, then the margin of error for the confidence interval would decrease.

(D) A 99% confidence interval for the proportion of students who purchase used textbooks is [0.363, 0.477]  .

Step-by-step explanation:

We are given that 19 students are randomly selected the sample mean was $390 and the standard deviation was $120.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                             P.Q.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean = $390

            s = sample standard deviation = $120

            n = sample of students = 19

            [tex]\mu[/tex] = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, [tex]\mu[/tex] is ;

P(-2.101 < [tex]t_1_8[/tex] < 2.101) = 0.95  {As the critical value of t at 18 degrees of

                                               freedom are -2.101 & 2.101 with P = 2.5%}  

P(-2.101 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 2.101) = 0.95

P( [tex]-2.101 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}[/tex] < [tex]2.101 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95

P( [tex]\bar X-2.101 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+2.101 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95

95% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-2.101 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X+2.101 \times {\frac{s}{\sqrt{n} } }[/tex] ]

                        = [ [tex]\$390-2.101 \times {\frac{\$120}{\sqrt{19} } }[/tex] , [tex]\$390+2.101 \times {\frac{\$120}{\sqrt{19} } }[/tex] ]

                        = [$332.16, $447.84]

(A)  Therefore, a 95% confidence for the population mean is [$332.16, $447.84] .

(B) If the confidence level in part (a) changed from 95% to 99%, then the margin of error for the confidence interval which is [tex]Z_(_\frac{\alpha}{2}_) \times \frac{s}{\sqrt{n} }[/tex] would increase because of an increase in the z value.

(C) If the sample size in part (a) changed from 19 to 22, then the margin of error for the confidence interval which is [tex]Z_(_\frac{\alpha}{2}_) \times \frac{s}{\sqrt{n} }[/tex]  would decrease because as denominator increases; the whole fraction decreases.

(D) We are given that to estimate the proportion of students who purchase their textbooks used, 500 students were sampled. 210 of these students purchased used textbooks.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

                             P.Q.  =  [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex]  ~ N(0,1)

where, [tex]\hat p[/tex] = sample proportion students who purchase their used textbooks = [tex]\frac{210}{500}[/tex] = 0.42    

            n = sample of students = 500

            p = population proportion

Here for constructing a 99% confidence interval we have used a One-sample z-test statistics for proportions

So, 99% confidence interval for the population proportion, p is ;

P(-2.58 < N(0,1) < 2.58) = 0.99  {As the critical value of z at 0.5%

                                               level of significance are -2.58 & 2.58}  

P(-2.58 < [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < 2.58) = 0.99

P( [tex]-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < [tex]{\hat p-p}[/tex] < [tex]2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.99

P( [tex]\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < p < [tex]\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.99

99% confidence interval for p = [ [tex]\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] , [tex]\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ]

= [ [tex]0.42 -2.58 \times {\sqrt{\frac{0.42(1-0.42)}{500} } }[/tex] , [tex]0.42 +2.58 \times {\sqrt{\frac{0.42(1-0.42)}{500} } }[/tex] ]

= [0.363, 0.477]

Therefore, a 99% confidence interval for the proportion of students who purchase used textbooks is [0.363, 0.477]  .

inverse of f(x)=e^(3x-1)

Answers

Answer:

f(x) = 3ex - e

Step-by-step explanation:

In this equation we have basically the times e by 3x and -1

so first let's do e times 3x

here...

e X 3x = 3ex

so let's rewrite the equation

3ex - 1

now we times e by 1. (Note - Negative sign stays)

3ex - 1e

we don't have to write 1e cause 1e = e, they are the same.

Therefore the answer is 3ex - 1e

Following are the calculation of inverse:

Given:  

[tex]\to f(x)=e^{3x-1}[/tex]

To find:

inverse function=?

Solution:

A function g is the inverse of function F if for [tex]y=f(x), x=g(y)[/tex]

[tex]\to y=e^{3x-1}[/tex]

Replacing the value of x with y  

[tex]\to x=e^{3y-1}[/tex]

Solve for [tex]y, x=e^{3y-1}[/tex]

Therefore, the answer is [tex]\frac{\log(x)+1}{3}[/tex].

Learn more about the inverse function:

brainly.com/question/13671128

Help very confusing to me???!

Answers

Answer:

Heyy mate... here's ur ans ;)

they asked us to apply pythagarus theorem becoz that theorem proves

that it is rectangle so lets get started

( p - perpendicular / b - base / h - hypotenuse )

a) =>

B = 8.1 m

P = 6.3 m

H = 10.15m

Now applying thm => H^2=p^2+b^2

(8.1)^2 + (6.3)^2 = (10.15)^2

65.61 + 39.69 = 103.02

so now LHS = 105.3 and RHS = 103.02 hence

LHS not equal to RHS

so is not rectangle

b) =>

B = 14.4

P = 5.2

H = 15.31

Now applying thm => H^2=p^2+b^2

(5.2)^2 + (14.4)^2 = (15.31)^2

27.04 + 207.36 = 234.39

LHS = 234.4 and RHS = 234.39

just taking approximation rhs is 234.4

hence

LHS = RHS

so it is a rectangle

please mark it brainliest <3

Given the graph, find an equation for the parabola.

Answers

Answer:

[tex]\Large \boxed{\sf \bf \ \ y=\dfrac{1}{16}(a-3)^2-2 \ \ }[/tex]

Step-by-step explanation:

Hello, please consider the following.

When the parabola equation is like

[tex]y=a(x-h)^2+k[/tex]

The vertex is the point (h,k) and the focus is the point (h, k+1/(4a))

As the vertex is (3,-2) we can say that h = 3 and k = -2.

We need to find a.

The focus  is (3,2) so we can say.

[tex]2=-2+\dfrac{1}{4a}\\\\\text{*** We add 2. ***}\\\\\dfrac{1}{4a}=2+2=4\\\\\text{*** We multiply by 4a. ***}\\\\16a=1\\\\\text{*** We divide by 16. ***}\\\\a=\dfrac{1}{16}[/tex]

So an equation for the parabola is.

[tex]\large \boxed{\sf y=\dfrac{1}{16}(a-3)^2-2 }[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Write the equation of the line that passes through (-1,5) and has a slope of 3 in point slope form

Answers

Answer:

y-5=3(x+1)

Step-by-step explanation:

we use the point-slope formula to plug all of our values in.

[tex]y-y_{1}=m(x-x_{1})[/tex]

 evaluate the expression for r=-10 -54-r=

Answers

Answer:

To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.

Step-by-step explanation:

Evaluate Algebraic Expressions. ... To evaluate an algebraic expression means to find the value of the expression when the variable is replaced by a given number. To evaluate an expression, we substitute the given number for the variable in the expression and then simplify the expression using the order of operations.

Which polynomial function has zeros when ? A: B: C: D:

Answers

B BBbBbBBbBbBbBbbBbBbBbbBbBbBBbBbBb

A baking scale measures mass to the tenth of a gram, up to 650 grams. A cup of flour is placed on the scale and results in a measure of 121.8 grams. Which of the following statements is not true?
a.The exact mass of the cup of flour must be between 121.7 and 121.9 grams.
b.The cup of flour has a mass of exactly 121.8 grams.
c.Given the limitations of the scale, the measurement has an appropriate level of accuracy.
d.To the nearest gram, the cup of flour has a mass of 122 grams.

Answers

Answer

Is it C I may have done my math wrong lol

Step-by-step explanation:

a sample from a mummified bull was taken from a certain place. The sample shows that 71% of the carbon-14 still remains. how old is the sample

Answers

Answer:

Step-by-step explanation:

Decay of carbon - 14 is exponential in nature . It decays as follows .

[tex]N=N_0e^{-\lambda t}[/tex]  λ is called decay constant .

λ = .693 / T where T is half life .

Half life of carbon-14 is 5700 years

λ = .693 / T

= .693 / 5700

= 12.158 x 10⁻⁵ year⁻¹

[tex]N=N_0e^{-\lambda t}[/tex]

N = .71 N₀

[tex].71 N_0 =N_0e^{-\lambda t}[/tex]

[tex].71 =e^{-\lambda t}[/tex]

Taking ln on both sides

ln .71 = - λ t

ln .71 = - 12.158 x 10⁻⁵  t

-0.3425 =  - 12.158 x 10⁻⁵  t

t = .3425 / 12.158 x 10⁻⁵

2817  years .

Please help to solve this.
Find sin5x,if sinx+cosx=1,4

Answers

Answer:

Hello,

Step-by-step explanation:

we must first remember that:

[tex]\boxed{sin(5x)=5sin(x)-20*sin^3(x)+16*sin^5(x)}\\\\[/tex]

Let say t=sin(x)

[tex]sin(x)+cos(x)=1.4\\\\t+\sqrt{1-t^2}=1.4\\\sqrt{1-t^2}=1.4-t\ we\ square\\1-t^2=1.4^2+t^2-2.8*t\\2t^2-2.8*t+0.96=0\\\Delta=2.8^2-4*2*0.96=0.16=0.4^2\\\\t=\dfrac{2.8-0.4}{4} =0.6\ or\ t=\dfrac{2.8+0.4}{4}=0.8\\\\t^3=0,216\ or\ t^3=0,512\\\\t^5=0,07776\ or\ t^5=0,32768\\\\\boxed{sin(5x)=5*0.6-20*0.216+16*0.07776=-0,07584}\\\\or\\\\\boxed{sin(5x)=5*0.8-20*0.512+16*0.32768=-0,99712}[/tex]

If path has 56 marbles and he gave Sandra 34 how many marbles will he have left?​

Answers

Answer:

22

Step-by-step explanation:

You just subtract them

56-34

= 22

56-34= 22
Therefore your answer is 22

An economist is interested in studying the income of consumers in a particular region. The population standard deviation is known to be $1,000. A random sample of 50 individuals resulted in an average income of $15,000. What is the width of the 90% confidence interval

Answers

Answer:

The width is  [tex]w = 282.8[/tex]

Step-by-step explanation:

From the question we are told that

  The sample size is n =  50

  The  population standard deviation is  [tex]\sigma = \$ 1000[/tex]

   The sample size is  [tex]\= x = \$ 15,000[/tex]

Given that the confidence level is  90%  then the level of significance can be mathematically represented as

             [tex]\alpha = 100 - 90[/tex]  

             [tex]\alpha = 10 \%[/tex]  

              [tex]\alpha = 0.10[/tex]

Next we obtain the critical value of  [tex]\frac{\alpha }{2}[/tex] from the  normal distribution table, the value is  

             [tex]Z_{\frac{0.10 }{2} } = 1.645[/tex]

Generally the margin of error is mathematically represented as

               [tex]E = Z_{\frac{0.10}{2} } * \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

                 [tex]E = 1.645 * \frac{1000 }{\sqrt{50 }}[/tex]

=>                [tex]E = 141.42[/tex]

  The width of the 90%  confidence level is mathematically represented as

                      [tex]w = 2 * E[/tex]

substituting values

                       [tex]w = 2 * 141.42[/tex]

                       [tex]w = 282.8[/tex]

 

g (1) = ?
Evaluate piecewise functions

Answers

Answer:

g(1) = 1

Step-by-step explanation:

g(1) with x = 1 corresponds to x ≠ - 2, - 1 with g(x) = x³ - x² + 1 , then

g(1) = 1³ - 1² + 1 = 1 - 1 + 1 = 1

Answer:

g ( 1 ) = 1

Step-by-step explanation:

→ Substitute x = 1 into x³ - x² + 1

( 1 ) ³ - ( 1 )² + 1

→ Simplify

1 - 1 + 1 = 1

The deck for a card game contains 30 cards. 10 are red, 10 yellow, 5 blue, and 1 green, and 4 are wild cards. Each player is randomly dealt a five-card hand. a) What is the probability that a hand will contain exactly two wild cards? b) What is the probability that a hand will contain two wild cards, two red cards, and one blue cards?

Answers

Answer: a) 0.1095     b) 0.0095

Step-by-step explanation:

Given : The deck for a card game contains 30 cards.

10 are red, 10 yellow, 5 blue, and 1 green, and 4 are wild cards.

Each player is randomly dealt a five-card hand.

Number of ways to choose 5 cards out of 30 = [tex]C(30,5)=\dfrac{30!}{5!25!}=142506[/tex]

a)  Cards other than wild card = 30-4=26

Number of ways to choose exactly two wild cards = [tex]C(26,3)\timesC(4,2)[/tex]

[tex]=\dfrac{26!}{3!23!}\times\dfrac{4!}{2!2!}\\\\=15600[/tex]

Probability that a hand will contain exactly two wild cards = [tex]\dfrac{15600}{142506}=0.1095[/tex]

b) Number of ways to choose two wild cards, two red cards, and one blue cards = [tex]C(4,2)\times C(10,2)\times C(5,1)[/tex]

[tex]=\dfrac{4!}{2!2!}\times\dfrac{10!}{2!8!}\times5=1350[/tex]

Probability that a hand will contain two wild cards, two red cards, and one blue cards = [tex]\dfrac{1350}{142506}=0.0095[/tex]

Question 3 Rewrite in simplest rational exponent form √x • 4√x. Show each step of your process.

Answers

Answer:

4x

Step-by-step explanation:

Given:

√x • 4√x

Required:

Simplify in rational exponent form

SOLUTION:

Recall => [tex] \sqrt{a} = a^{\frac{1}{2}} [/tex]

Thus,

[tex] \sqrt{x}*4\sqrt{x} [/tex] can be expressed in exponent form as [tex] x^{\frac{1}{2}}*4x^{\frac{1}{2} [/tex]

When multiplying 2 bases having exponents together, their exponents should be added together, while you multiply the bases. I.e. [tex]x^m*x^n = x^{m+n }[/tex]

[tex] = x*4^{\frac{1}{2}+\frac{1}{2} [/tex]

[tex] = 4x^{1} = 4x [/tex]

The answer is 4x

evaluate -7x^2 -5 + y^2- forx = -2, y=4

Answers

Answer:

The (y^2 ) or (y^–2) It is not clear, I solved it in both ways (y^2) and (y^-2) .^_^

[tex] - 7 {x }^{2} - 5 + {y}^{2} \\ - 7( { - 2}^{2} ) - 5 + {4}^{2} \\ - 7( - 4) - 5 + 16 \\ 28 - 5 + 16 \\ = 39[/tex]

_______o_____o_______

[tex] - 7 {x }^{2} - 5 + {y}^{ - 2} \\ - 7( { - 2}^{2} ) - 5 + {4}^{ - 2} \\ - 7( - 4) - 5 + \frac{1}{16} \\ 28 - 5 + \frac{1}{16} \\ = 23.06[/tex]

I hope I helped you^_^

Name one real-world object that suggests A. Points B. Lines and C. Planes

Answers

There are many examples to pick from, one is

point = location on map

line = straight road between two locations (aka two points)

plane = flat ground (the ground cannot have any hills or valleys)

First, let's write some useful definitions:

Point: it is an entity that has a location in a given space or plane, and do not have any surface nor measure.

Line: if we have two points, we can define a line as a straight, infinite ray that connects them. Still does not have a surface

Plane: We can define a plane as a line and a point outside of it, here appears the concept of the surface.

So, the easier one is a plane, a sheet of paper could be a good representation of a plane. And in the same way that a sheet of paper can bend in different ways, also do the planes.

For the line, we could use a really straight wire.

Finally, the point, which is the hardest one to describe (notice that we used points to describe the other two, lines, and planes) so here we could choose something small, that has near to no surface and that also has a location in the space. An example of this could be an electron or any other elemental particle.

If you want to learn more, you can read:

https://brainly.com/question/17213603

Please help——- Geometry problem

Thank you.

Answers

Answer:

b

Step-by-step explanation:

sinA = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{s\sqrt{3} }{2s}[/tex] ( cancel s on numerator/ denominator ), then

sinA = [tex]\frac{\sqrt{3} }{2}[/tex] → b

Cases Prudence has a special (cubic) die. The values on its face are the integers from 1 to 6, but they are not arranged ae in a normal die. When Prudence first tosses the die, the sum of the values on the four side faces is 15. In her second toss, the sum of these values is 12. Find what value appears in the face opposite 6 on Prudence’s special die. (Hint: what are possible values for the top and bottom face when the sum of the side faces is 12).

Answers

Answer: 3

Step-by-step explanation:

first, we know that:

1 + 2 + 3 + 4 +5 +6 = 21

Now, which two numbers we should take out in order to have 15?

we can remove the 2 and the 4, or the 1 and the 5.

so here we have two possibilities, 2 and 4 are opposite, or 1 and 5 are opposite (they are located in opposite faces of the die)

in the other arrange, we have that removing two numbers we should get 12.

in order to reach 12, we should remove two numbers that add 9 together.

those can be 4 and 5, or 6 and 3.

Now, notice that in the first restriction we have that:

Or 2 and 4 are opposite,

or 1 and 5 are opposite.

So 4 and 5 can never be opposite, so we should have that 6 and 3 are opposite.

Then we can affirm that the value that appears in the face opposite to the 6, is the 3.

PLEASE HELP!!!
The following data are the distance from the workplace ( in miles) for the 5 employees of a small business.

10,17,12,14,12

Assuming that these distance constitute an entire population, find the standard deviation of the population. Round your answer to two decimal places.​

Answers

Answer:

stdev= 2.366431913

Step-by-step explanation:

10  stdev= 2.366431913

17  

12  

14  

12  

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