Solve for x. Please look at the picture and answer it. Thank you.

Answer:

Yes

Step-by-step explanation:

Answer:

The answer is Yes. Hope this helps :)

Step-by-step explanation:

Answer:

see explanation

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the gradient and c the y- intercept )

given

x + 2y + 6 = 0 ( subtract x + 6 from both sides )

2y = - x - 6 ( divide terms by 2 )

y = - [tex]\frac{1}{2}[/tex] x - 3 ← in slope- intercept form

with gradient m = - [tex]\frac{1}{2}[/tex] and y- intercept c = - 3

Answer: Win $0.33

Step-by-step explanation:

Answers win 0.33

Step-by-step explanation:

I got you

Answer:

Nothing further can be done to this equation.

Step-by-step explanation:

Since the variables dont match you can add, subtract, divide, or multiply the number.

Hope this helps : )

Answer:

The expression is simplified.

Step-by-step explanation:

Nothing can be done to it.

Answer:

37in.^2

Step-by-step explanation:

So if the triangles at the top have a hypotenuse of 5, and a length of 4, then doing reverse Pythagorean theorem, you find out that the width is 3.[tex]a^{2} +b^{2} =c^{2}[/tex]. so reverse of that for this problem would be [tex]c^{2} -b^{2} =a^{2}[/tex] and if we plug it in, we get 25 -16=9 and the square root of 9 is 3. so if we find the are of the triangle, 3*4*1/2=6 and there are 2 triangles so 12 for both triangles. The square is 5*4=20. and the smaller triangles on the side are 1*5*1/2=2.5, and there are 2 traingles so 2.5*2= 5. So 5+20+12=37. You can do this on most calculators, and please put my answer as the brainliest.✌

When the rectangle is dilated, the new and the old rectangles will have a different area

The area of the image of the rectangle is 12k^2

The area of the rectangle is given as:

A = 12

The scale of dilation is given as k.

So, the area of the image of the dilation is:

[tex]A_2 = A * k^2[/tex]

This gives

[tex]A_2 = 12 * k^2[/tex]

Evaluate the product

[tex]A_2 = 12k^2[/tex]

Hence, the area of the image of the rectangle is 12k^2

Read more about dilation at:

https://brainly.com/question/10253650

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

To write this in interval notation, we can say [tex](-\infty, 0) \cup (0, \infty)[/tex] which is the result of poking a hole at 0 on the real number line.

--------------

The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

In interval notation, we would say [tex](-\infty, \infty)[/tex] which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

=======================================================

Part (b)

We can compact that to the notation [tex]x = \pm 4[/tex]

These are the locations where the blue hyperbolic curve crosses the x axis.

=======================================================

Part (c)

Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.

=======================================================

Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

=======================================================

Part (e)

The oblique or slant asymptote is the diagonal dashed line.

It goes through (0,0) and (2,6)

The equation of the line through those points is y = 3x

If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.

Answer:

(Bro you gotta give me brainliest for this lol, I'm answering 6, 7, and 8. Tell me in comments if you need all of them.)

6. [tex]\frac{66}{5}[/tex] = 13 [tex]\frac{1}{5}[/tex]

7. [tex]\frac{1117}{60}[/tex] = 18 [tex]\frac{37}{60}[/tex]

8. [tex]\frac{1849}{180}[/tex] = 10 49/180

Note: This is not an estimated sum, this is the exact answer calculated from the questions you provided.

Answer:

1 Is In The Thousands Place

Step-by-step explanation:

Uhm You Should Know This But Heres The Answer

900,000

80,000

1,000

400

40

3

Answer: they are uneven

Step-by-step explanation: the 30 has to be 15 on each side and the 16 stays the same

4w-4y-2

hope this helps

Answer:

64.62

Step-by-step explanation:

[tex]cos(x)^{-1} = \frac{3}{7}[/tex]

Part A: what tool can help Jada find possible dimensions for the base of the block? Explain.

     I am not sure what a "tool" is by their wording, but we can use the formula for volume to solve for the base.

-> B is the base, length times width, and H is the height

V = B * H

350 in³ = B * 5 in

70 in² = B

  Answer: The base will be 70 in²

Part B: Give one pair of possible whole-number dimensions for the base.

     Since we know the base will be 70 in², we can find a possible pair of whole-number dimensions for the base.

B = L * W

70 in² = L * W

     Now we just need to find pairs of whole numbers that multiply to 70:

70 / 2 = 35

  Answer: A possible pair of whole-number dimensions for the base is 2 and 35.

Answer:

[tex]8\frac{4}{7}[/tex]

Step-by-step explanation:

Answer: SAS

Step-by-step explanation:

It is given that DN is congruent to ML.

It is also given that angle DNL is congruent to angle MLN

We can figure out that NL is congruent to LN by the reflexive property.

Therefore, these triangles are congruent by Side-Angle-Side

Answer:

The answer for this question is 3.2 minus 365 minus 102

(a) The claim is made for all positive integers n, so we start at n = 1. We have

[tex]\displaystyle \sin(x) \sum_{k=1}^1 \sin(2kx) = \sin(x) \sin(2x) = \sin(1x) \sin((1+1)x)[/tex]

so the claim is true for the base case.

Suppose the claim is true for n = m, so that

[tex]\displaystyle \sin(x) \sum_{k=1}^m \sin(2kx) = \sin(mx) \sin((m+1)x)[/tex]

We want to use this to establish the identity for n = m + 1. That is, we want to prove that

[tex]\displaystyle \sin(x) \sum_{k=1}^{m+1} \sin(2kx) = \sin((m+1)x) \sin((m+2)x)[/tex]

Working with the left side, we remove the last term from the sum and we have

[tex]\displaystyle \sin(x) \sum_{k=1}^{m+1} \sin(2kx) = \sin(x) \sum_{k=1}^m \sin(2kx) + \sin(x) \sin(2(m+1)x) \\\\\\ = \sin(mx) \sin((m+1)x) + \sin(x) \sin(2(m+1))x[/tex]

Recall the angle sum identities:

[tex]\sin(x + y) = \sin(x) \cos(y) + \cos(x) \sin(y)[/tex]

[tex]\sin(x - y) = \sin(x) \cos(y) - \cos(x) \sin(y)[/tex]

[tex]\cos(x + y) = \cos(x) \cos(y) - \sin(x) \sin(y)[/tex]

[tex]\cos(x - y) = \cos(x) \cos(y) + \sin(x) \sin(y)[/tex]

Then

[tex]\sin(2(m+1)x) = 2 \sin((m+1)x) \cos((m+1)x)[/tex]

so we can remove a factor of sin((m + 1) x) :

[tex]\displaystyle \sin(x) \sum_{k=1}^{m+1} \sin(2kx) = \sin((m+1)x) \bigg(\sin(mx) + 2 \sin(x) \cos((m+1)x)\bigg)[/tex]

and we also have

[tex]2 \sin(x) \cos((m+1)x) = \sin(x+(m+1)x) + \sin(x - (m+1)x) \\\\ = \sin((m+2)x) + \sin(-mx) \\\\ = \sin((m+2)x) - \sin(mx)[/tex]

Then the sin(mx) terms cancel, and we're left with what we wanted:

[tex]\displaystyle \sin(x) \sum_{k=1}^{m+1} \sin(2kx) = \sin((m+1)x) \sin((m+2)x)[/tex]

and the induction proof is complete.

(b) From the identities mentioned earlier, one has

[tex]\sin\left(x - \dfrac\pi4\right) = \sin(x) \cos\left(\dfrac\pi4\right) - \cos(x) \sin\left(\dfrac\pi4\right) \\\\ = \dfrac{\sin(x) - \cos(x)}{\sqrt2}[/tex]

Then

[tex]\sin^2\left(x - \dfrac\pi4\right) = \dfrac{(\sin(x) - \cos(x))^2}2 \\\\ = \dfrac{\sin^2(x) - 2 \sin(x) \cos(x) + \cos^2(x)}2 \\\\ = \dfrac{1 - \sin(2x)}2[/tex]

We can then rewrite the sum as

[tex]\displaystyle \sum_{k=1}^{369} \sin^2\left(\dfrac{k\pi}5 - \dfrac\pi4\right) = \frac12 \sum_{k=1}^{369} \left(1 - \sin\left(\frac{2k\pi}5\right)\right) \\\\ = \frac12 \sum_{k=1}^{369} 1 - \frac12 \sum_{k=1}^{369} \sin\left(\frac{2k\pi}5\right)[/tex]

Recall that

[tex]\displaystyle \sum_{k=1}^n 1 = 1 + 1 + \cdots + 1 = n[/tex]

For the sum involving sine, let x = π/5. Then using the result from part (a),

[tex]\displaystyle \sin\left(\frac\pi5\right) \sum_{k=1}^{369} \sin\left(\dfrac{2k\pi}5\right) = \sin\left(\dfrac{369\pi}5\right) \sin\left(\dfrac{370\pi}5\right)[/tex]

and this sum vanishes, since sin(370π/5) = sin(74π) = 0.

It follows that

[tex]\displaystyle \sum_{k=1}^{369} \sin^2\left(\dfrac{k\pi}5 - \dfrac\pi4\right) = \frac12 \sum_{k=1}^{369} 1 = \boxed{\frac{369}2}[/tex]

Answer:

+act of kindness and its We are given with the expression sin 52° cos 13° - cos 52° sin 13° The expression can be patterned from the trigonometric identity sin (a - b) = sin a cos B - cos A sin B. In this case, the expression is equal to sin (52-13) or equal to a simplified term sin 39

Step-by-step explanation:

Answer:$1.5

$30*5/100=15/10=3/2=$1.5

Step-by-step explanation:

Answer: P is independent and 2b is dependent

Step-by-step explanation:

If P=2b is the answer. Then the Independent Value is P and the Dependent Value is 2b.

Carbon, hydrogen, nitrogen, oxygen, phosphorus, and sulfur are the strengths of the cell. The first four are the most significant since they are utilized to build the molecules required to create live cells.

The models draw attention to characteristics that are less obvious in actual cells. Color is used by the models to highlight various components. example of a weakness The models are static, but real cells feature moving elements. While the models depict cross-sections in two dimensions, real cells are three dimensional.

The inadequacy of cellular models to accurately represent the function of complicated decision-making by human beings is one of their shortcomings. Although transition rules are handled probabilistically in Markov models and may be affected by temporal lags in cell response, cellular frameworks can be coupled with these models.

Carbon, hydrogen, nitrogen, oxygen, phosphorus, and sulfur are the strengths of the cell. The first four are the most significant since they are utilized to build the molecules required to create live cells.

The complete question is:

What are the strengths and weaknesses of the cell model?

To learn more about the cell model refer to:

brainly.com/question/19450928

#SPJ7

Answer:

[tex]60[/tex]

Step-by-step explanation:

Evaluate 7p + 6(p ÷ q)^2 - 2q (if p = 6 and q = 3)

[tex]7p + 6(p \div q)^2 - 2q\\\\7(6) + 6(6 \div 3)^2 - 2(3)\\\\7(6) + 6(2)^2 - 2(3)\\\\7(6) + 6(4) - 2(3)\\\\42 + 24 - 6\\\\66-6\\\\60[/tex]

Hope this helps!

Answer:

-2

Step-by-step explanation:

make 'n' subject of formula

n= 5 -7

n= -2

Answer:

n = -2

Step-by-step explanation:

7 + n = 5

prove that the value of n is -2

proven

The given dimensions of 9.5, 6, 7, and 6.5 cm gives the following

perimeter and area of the trapezium.

The perimeter of a trapezoid is given as follows;

Perimeter = The sum of the lengths of the sides

Which gives;

Perimeter = 6 + 7 + 6.5 + 9.5 = 29

The perimeter of the trapezoid = 29 cm

The area of the trapezoid is given as follows;

[tex]Area = \mathbf{ \dfrac{Sum \ of \ the \ parallel \ sides }{2} \times Height}[/tex]

Which gives;

[tex]Area = \dfrac{7 + 9.5 }{2} \times 6 = 49.5[/tex]

The area of the trapezoid = 49.5 cm²

Learn more about the area and perimeter of geometric shapes here:

https://brainly.com/question/359059

https://brainly.com/question/11461461

Answer:

g(9) = 48

Step-by-step explanation:

g(x)= – x2–5x + 12

I'll assume this is

g(x)= – x^2–5x + 12

find g(9)

find g(9)

g(9)= – 9^2–5(9) + 12

g(9)= 81–45 + 12

g(9) = 48

Answer: -6i

Step-by-step explanation:

A line of symmetry is a figure that can be divided in 2 equal parts.

I have drawn and attached the image!!~

[tex]\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}[/tex]

Answer:

x=15

y=25

Step-by-step explanation:

first number x

second number y

x+y=40

y=2x-5

x+(2x-5)=40

x+2x-5=40

3x=45

x=45/3=15

y=(2*15)-5=25

Answer:

Solving steps:

Explanation:

The first bit of information is about amount, and the second part is about cost. We will make an equation for each one. Just so you know, I'm going to abbreviate "children" to c and "adults" to a .

The first equation is about amount. So since the total amount of people that came was

283

, this is the equation:

c + a = 283

The second is about cost. Children cost

$5.50 and adults cost $15.00, so we can make this equation:

=> 5.50c + 15.00a = 2,649.00

Now rearrange the first equation so that we can solve for one of the variables:

c + a = 283 → c = 283 − a

Substitute it into the second equation:

5.5c +15a = 2,649

5.5(283 − a) + 15a = 2,649

1,556.5 − 5.5a + 15a = 2,649

1,556.5 + 9.5a = 2,649

9.5a = 1,092.5

a = 115

115 adults came.

Now substitute the value of into this equation and solve for c

.c = 283 - a

c = 283 - 115

c = 168

168 children came.