Solve for x. Round your answer to the nearest tenth if necessary.

X=

Let daughter be x years old. Then, Shyam is (x + 28) years old.

So,

x(x + 28) = 204

=> x² + 28x = 204

=> x² + 28x - 204 = 0

=> x² - 6x + 34x - 204 = 0

=> x(x-6) + 34(x-6)

=> (x - 6) (x + 34) = 0

=> x - 6 = 0 or x + 34 = 0

=> x = 6 or x = -34

Since any age cannot be negative, daughter's age is 6 years old.

Answer:

2n+2

Step-by-step explanation:

the common difference is 4,6,8

again the common difference of 4,6,8 is 2,2

hence its common difference is 2

now, nth term,=a+(n-1) *d

4+(n-1)*2

4+2n-2

2n+2

Answer:

because of its bark

Step-by-step explanation:

the answers have corresponding letters so answer the questions and put the letter next to the question above the answer

some of the answers are repeated

Step-by-step explanation:

We need to say that [tex]9^{3/4}[/tex] is equivalent to what.

We know that, (3)² = 9

So,

[tex]9^{3/4}=((3)^2)^{3/4}\\\\=3^{3/2}[/tex]

We can write [tex]3^{3/2} =3\times 3^{1/2}[/tex]

And [tex]3^{1/2}=\sqrt{3}[/tex]

So,

[tex]3\times 3^{1/2}=3\sqrt{3}[/tex]

So, [tex]9^{3/4}[/tex] is equivalent to [tex]3\sqrt{3}[/tex].

Hence, this is the required solution.

Answer:

54 inches

Step-by-step explanation:

First, let's convert the measurements into a common measurement.

Since inch is the smallest measurement here, let's use that.

Ella's pet snake is 42 inches long.

Roya's pet snake is 8 feet long. There are 12 inches in one foot. Therefore, 8 feet would mean 12 times 8 or 96 inches.

Therefore, Roya's snake is 96 inches long.

To find out how many inches longer is Roya's snake, subtract:

96 - 42 = 54.

Therefore, Roya's snake is 54 inches longer than Ella's.

Answer:

3x^2-2x-6

Step-by-step explanation:

(f-g)(x) = f(x) - g(x)

=3x^2-2-2x-4=3x^2-2x-6

Answer:

1)  502.65"

2) 367.57 yd

3)  141.37'  

4) 471.24'

Step-by-step explanation:

Formula: volume of a cylinder = πr²h

1) v= πr²h                     2) v= πr²h                      

  v= π x 4² x 10                v= π x 3² x 13

  v=  502.65"                   v= 367.57 yd

3) v= πr²h                       4) v= πr²h

    v=  π x 3² x 5                 v= π x 5² x 6

     v= 141.37'                       v= 471.24'

I hope this helped

Answer:

1. 502.5 [tex]in^{3}[/tex]

2. 367.38 [tex]yd^{3}[/tex]

3. 141.3 [tex]cm^{3}[/tex]

4. 471 [tex]cm^{3}[/tex]

Step-by-step explanation:

The solution to finding the volume of a cylinder is: [tex]\pi r^{2} h[/tex].

They give us a diameter but no radius. So, we just need to divide the diameter, 8, by two. That leaves us with a radius of 4.

We can also see that the height of the first cylinder is 10. That gives us all our information to find the volume!

3.14 · [tex]4^{2}[/tex] · 10 = 502.5

So, the volume of the first cylinder is 502.5[tex]in^{3}[/tex]

This, hopefully explains how to find the volume of the rest of the cylinders!! :)

Hope this helps!! <3

Answer:

Ross = 15 hours

Russel = 40 hours

Step-by-step explanation:

Let Ross have used their sprinklers for x hours

Let Russell  have used their sprinklers for y hours

Together they used 55 hours

x+y = 55 hours

The output of Ross is 35 liters per hour and Russell is 30 liters per hour for a total of 1725

35x + 30y = 1725

Multiply the first equation by -30

-30(x+y=55)

-30x -30y = -1650

Add this to the second equation to eliminate y

-30x -30y = -1650

35x + 30y = 1725

-----------------------------

5x =75

Divide each side by 5

x = 15

Now find y

x+y = 55

y = 55-15

y = 40

Answer: B) different y intercepts; same end behavior

=======================================================

Explanation:

The graph shows the y intercept is 4 as this is where the green curve crosses the vertical y axis.

The y intercept of g(x) is 6 which can be found by plugging x = 0 into the g(x) function

g(x) = 4(1/4)^x + 2

g(0) = 4(1/4)^0 + 2

g(0) = 6

So we can see the y intercepts are different.

----------

However, the end behaviors are the same for each function. The left side of f(x) goes up forever to positive infinity. The same is true for g(x). You could use a graphing calculator or a table to see this. As x heads to negative infinity, y goes to positive infinity.

In terms of symbols, [tex]x \to -\infty, y \to \infty[/tex]

----------

For the right side of f(x), it slowly approaches the horizontal asymptote y = 2. It never actually reaches this y value. The same happens with g(x). The portion 4(1/4)^x gets smaller but never gets to 0 so overall 4(1/4)^x+2 gets closer to 2. We can say that as x approaches infinity, y approaches 2.

In terms of symbols, [tex]x \to \infty, y \to 2[/tex]

Answer:

Answer:

The right option is definitely the first one

Hope this helps

Answer:

if 5 people =1 hour. which is 60 minutes.

so 8people.52 minutes ...it wont take hours .since an hour is 60 min.

Answer:

Step-by-step explanation:

Let's solve:

[tex] \mathsf {people \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: time( \: in \: minutes) }[/tex]

[tex] \mathsf{5 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 1 hour = 60 minutes}[/tex]

[tex] \mathsf{8 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x}[/tex]

Here, Let 8 people take x minutes to complete the work.

Since, the number of people and their working minutes are indirect proportional. So,

Here, the ratio of people = 5 : 8

The ratio of minutes = 60 : x

So,

[tex] \mathsf{ \frac{5}{8} = \frac{x}{60} }[/tex]

Apply cross product property

⇒[tex] \mathsf{8x = 60 \times 5}[/tex]

Multiply the numbers

⇒[tex] \mathsf{8x = 300}[/tex]

Divide both sides of the equation by 8

⇒[tex] \mathsf {\frac{8x}{8} = \frac{300}{8} }[/tex]

Calculate

⇒[tex] \mathsf{x = 37.5 \: minutes}[/tex]

Hope I helped!

Best regards!

Answer:

see below (I hope this makes sense!)

Step-by-step explanation:

Constants, as the name suggest, stay constant, meaning that their value never changes. For example, 2 will always be 2 and 9.4 will always be 9.4. On the other hand, the values of variables can change. Take, for example, the variable 2x. When x = 1, 2x = 2 and when x  =2, 2x = 4 so the value of 2x can change depending on what x is. You can't combine constants and variables because they are not like terms, basically, one can change and the other can't and you cannot combine terms that are not like each other.

Answer:

A = 120

Step-by-step explanation:

Angle A is a vertical angle to 120 and vertical angles are equal

A = 120

[tex]\Large\rm\underbrace{{\green{ \: Angle \: A \: = \: 120 \degree}}}[/tex]

Because vertically opposite angles are always equal.

Answer:

Stick 2: [tex] \frac{1}{2} [/tex]

Stick 3: [tex] \frac{4}{10} [/tex]

Step-by-step explanation:

To determine which of the lengths are less than ⅗ meters, you would compare each given length with ⅗ meters.

Stick 1: Comparing ⁹/10 and ⅗

Find The common denominator of both fractions. 10 is the common denominator. Multiply the numerator and denominator of ⅗ by 2 to create a fraction equivalent to ⁹/10.

Thus,

[tex] \frac{3*2}{5*2} = \frac{6}{10} [/tex]

Compare the numerator of [tex] \frac{9}{10} [/tex] and [tex] \frac{6}{10} [/tex].

9 is greater than 6. This means [tex] \frac{9}{10} [/tex] > [tex] \frac{6}{10} [/tex].

Therefore, [tex] \frac{9}{10} [/tex] > [tex] \frac{3}{5} [/tex]

Stick 2: comparing ½ and ⅗

Common denominator = 10

Make both fractions equivalent to each other as follows,

[tex] \frac{1*5}{2*5} = \frac{5}{10} [/tex]

[tex] \frac{3*2}{5*2} = \frac{6}{10} [/tex]

5 < 6. This means, [tex] \frac{5}{10} [/tex] < [tex] \frac{6}{10} [/tex].

Therefore, [tex] \frac{1}{2} [/tex] < [tex] \frac{3}{5} [/tex]

Stick 3: comparing ⁴/10 and ⅗

Common denominator = 10

Make the fractions equivalent as follows,

[tex] \frac{4*1}{10*1} = \frac{4}{10} [/tex]

[tex] \frac{3*2}{5*2} = \frac{6}{10} [/tex]

4 < 6. This means, [tex] \frac{4}{10} [/tex] < [tex] \frac{6}{10} [/tex].

Therefore, [tex] \frac{4}{10} [/tex] < [tex] \frac{3}{5} [/tex]

Stick 4: comparing ⅘ and ⅗

Common denominator = 5

Since both denominators are already the same, both fractions are equivalent. Comparing their numerator, 4 > 3. Therefore, ⅘ > ⅗.

Answer:

Does the answer help you?

Answer:

y=1 and x=2

Step-by-step explanation:

Add the two linear equation and you will have 2y=2, y=1. Plugging this in any equation, we have x=2

Answer:

The solution is (2,1)

Step-by-step explanation:

Set the two equations equal

y=3x-5 and y=-3x+7

3x-5 = -3x+7

Add 3x to each side

3x-5+3x = -3x+7+3x

6x-5 = 7

Add 5 to each side

6x-5+5 = 7+5

6x = 12

Divide by 6

6x/6 = 12/6

x=2

Now find y

y =3x-5

y=3(2)-5

y = 6-5

y=1

The solution is (2,1)

Answer: Adding integers means adding integers with the same signs, while subtracting integers means adding the integers of opposite signs.

Step-by-step explanation:

Answer:

False

Step-by-step explanation:

If an angle is congruent, it means that the angle is equal to the first angle which is 56 degrees, in theory, it would be false because 56 degrees is an acute angle and not obtuse.

Answer:

C

Step-by-step explanation:

sqrt(a^7) = sqrt(a^6 * a)

Answer:

option 2 with radius of 1.4 in, and height of 1.2 in.

Step-by-step explanation:

If two cylinders are similar, the ratio of one cylinder's radius to its height must be the same as that of the other.

To know which cylinder is similar to the given cylinder with radius 2.8 in and height of 2.4 in, find the ratio, and compare with the ratio of the options provided. The option with the same ratio, is the cylinder that is similar.

This,

The given cylinder => radius : height = [tex] \frac{2.8}{2.4} = \frac{0.7}{0.6} = \frac{7}{6} [/tex]

First option:

Radius : height = [tex] \frac{1.8}{1.4} = \frac{0.9}{0.7} = \frac{9}{7} [/tex]

Second option:

Radius : height = [tex] \frac{1.4}{1.2} = \frac{0.7}{0.6} = \frac{7}{6} [/tex]

Third option:

Radius : height = [tex]\frac{5.6}{4.2} = \frac{0.8}{0.6} = \frac{0.4}{0.3} = \frac{4}{3}[/tex]

Fourth option:

Radius : height = [tex] \frac{2.4}{2.8} = \frac{0.6}{0.7} = \frac{6}{7} [/tex]

The correct option with the cylinder that is similar with the given cylinder is option 2 with radius of 1.4 in, and height of 1.2 in.

Answer:

10x - 15

Step-by-step explanation:

5(2x-3) = 10x - 15

Answer:

$64

Step-by-step explanation:

She should pay the entire amount which is $17 + $36 + $11 = $64

Answer:

64

Step-by-step explanation:

yezzir

Answer:

A 0.6 0.9 1.2 1.5 1.8

B 3/8 5/8 7/8 9/8 11/8

C -7 -5 -3 -2 -1

D 1, 1 1/3, 1 2/3, 2, 2 1/3

E 0.61 0.72 0.83 0.94 1.05

Step-by-step explanation:

Answer:

A.  x  x   1.2  1.5  1.8

B.  3/8   x   x  x  1 2/8

C.  x  x  -3  -2  -1

D.   0  x  x  x  5 1/3

E.   x  x   0.83  0.94  1.05

Step-by-step explanation:

hope it helped

[tex]\\ \sf\longmapsto 2(5m-4)-3(m-5)^2[/tex]

[tex]\\ \sf\longmapsto 10m-8-3(m^2-10m+5^2)[/tex]

[tex]\\ \sf\longmapsto 10m-8-3(m^2-10m+25)[/tex]

[tex]\\ \sf\longmapsto 10m-8-3m^2+30m-75[/tex]

[tex]\\ \sf\longmapsto -3m^2+30m+10m-75-8[/tex]

[tex]\\ \sf\longmapsto -3m^2+40m-83[/tex]

Answer: 2.31

Step-by-step explanation:

Answer:

no solutions

Step-by-step explanation:

|16 + t| = – 3

Absolute values are greater than or equal to zero

They cannot be negative so there are no solutions

Answer:

no solutions

Step-by-step explanation:

|16 + t| = – 3

Absolute values are greater than or equal to zero

They cannot be negative so there are no solutions

the graph will shift 3 units to the right

Answer:

1) La opción correcta es;

c) 0

2) La opción correcta es;

c) x = 2

Step-by-step explanation:

1) La forma general de una ecuación cuadrática se puede escribir en la forma;

a · x² + b · x + c = 0

Dónde;

a, y b son los coeficientes de x², x y c es el término constante

Por tanto, para que exista un polinomio de 2º grado es necesario que el coeficiente a sea diferente de 0

De lo que tenemos;

(0) × x² + b · x + c = 0, lo que da;

(0) × x² + b · x + c = b · x + c = 0 que es una ecuación lineal o un polinomio de primer grado

Por tanto, la opción correcta es c) 0

2)

La ecuación dada se presenta como sigue;

f (x) = x² - 5 · x + 6 = 0

Usando el método de prueba y error, tenemos;

Cuando x = 0

f (0) = 0² - 5 · (0) + 6 = 6 que no es igual a 0 y, por lo tanto, no es una solución

Cuando x = 1

f (1) = (1) ² - 5 · (1) + 6 = 1 que no es igual a 0 y por lo tanto, no es una solución

Cuando x = 2

f (2) = (2) ² - 5 · (2) + 6 = 0 que es igual a 0 y por lo tanto, es una solución

Cuando x = -2

f (1) = (-2) ² - 5 × (-2) + 6 = 20 que no es igual a 0 y por lo tanto, no es una solución

Por tanto, la opción correcta es c) x = 2

The answer is Or + 12