Solve the following three equations.
Equation #1 60 = 6(6 – 2n)
Equation #2 5x + 7 + 3x = -8 + 3x
Equation #3 3(1 + 4v) – 2(5v- 3) = 25

Answers

Answer 1

Answer:

#1 N=2

#2 X= -3

#3 V=1, 1 1/2


Related Questions

If segment AB is 4 units, segment AD is 23 units, and segment CD is 12 units, what is the length of segment BC?
23
A
9 units
B.
6 units
C
7 units
D
8 units

Answers

Answer:

C . 7 units

Step-by-step explanation:

The question is lacking appropriate diagram. Find the diagram to the question attached.

From the diagram, it can be seen that AD = AB+BC+CD

Given the following

AD = 23units

AB = 4units

CD = 12units

To get C=BC, we will substitute the given segments into the expression above as shown;

23 = 4+BC+12

23 = BC + 4 + 12

23 = BC+16

Subtract 16 from both sides

23-16 = BC+16-16

7 = BC

Hence the length of segment BC is 7units.

9/5 - 4/3 =

A. 1/3

B. 8/15

C. 7/15

D. 1 1/15

Answers

Answer:

[tex] \frac{7}{15} [/tex]

Step-by-step explanation:

[tex] \frac{9}{5} - \frac{4}{3} = \frac{27 - 20}{15} = \frac{7}{15} [/tex]

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{ \frac{7}{15} }}}}}[/tex]

Option C is the correct option

Step-by-step explanation:

[tex] \sf{ \frac{9}{5} - \frac{4}{3} }[/tex]

Take the L.C.M ( Lowest Common Multiple ) of 5 and 3.

L.C.M of 5 and 3 = 15

⇒[tex] \sf{ \frac{9 \times 3 - 4 \times 5}{15} }[/tex]

Multiply the numbers

⇒[tex] \sf{ \frac{27 - 20}{15} }[/tex]

Subtract 20 from 27

⇒[tex] \sf{ \frac{7}{15} }[/tex]

Hope I helped!

Best regards! :D

Please someone help me, youvmust find the value of: ​

Answers

Answer:

1

Step-by-step explanation:

Using the sum to product formulae and the exact values

sin x + sin y = 2sin([tex]\frac{x+y}{2}[/tex] )cos([tex]\frac{x-y}{2}[/tex] )

cos x + cos y = 2cos([tex]\frac{x+y}{2}[/tex] )cos([tex]\frac{x-y}{2}[/tex] )

sin45° = cos45° = [tex]\frac{1}{\sqrt{2} }[/tex] , cos30° = [tex]\frac{\sqrt{3} }{2}[/tex]

Given

[tex]\frac{sin75+sin15}{cos75+cos15}[/tex]

= [tex]\frac{2sin(\frac{75+15}{2})cos(\frac{75-15}{2}) }{2cos(\frac{75+15}{2})cos(\frac{75-15}{2}) }[/tex]

= [tex]\frac{2si45cos30}{2cos45cos30}[/tex]

= (2 × [tex]\frac{1}{\sqrt{2} }[/tex] × [tex]\frac{\sqrt{3} }{2}[/tex] ) ÷ (2 × [tex]\frac{1}{\sqrt{2} }[/tex] × [tex]\frac{\sqrt{3} }{2}[/tex] )

= 1

Answer:  1

Step-by-step explanation:

sin 75 = sin(30 + 45) = sin30 · cos45  + cos30 · sin45

                                 [tex]=\dfrac{1}{2}\cdot \dfrac{\sqrt2}{2}+\dfrac{\sqrt3}{2}\cdot\dfrac{\sqrt2}{2}\qquad =\dfrac{\sqrt2+\sqrt6}{4}[/tex]

sin 15 = sin(45 - 30) = sin45 · cos30  - cos45 · sin30

                                  [tex]=\dfrac{\sqrt2}{2}\cdot \dfrac{\sqrt3}{2}-\dfrac{\sqrt2}{2}\cdot\dfrac{1}{2}\qquad =\dfrac{\sqrt6+\sqrt2}{4}[/tex]

cos 75 = cos(30 + 45) = cos30 · cos45  - sin30 · sin45

                                   [tex]=\dfrac{\sqrt3}{2}\cdot \dfrac{\sqrt2}{2}-\dfrac{1}{2}\cdot\dfrac{\sqrt2}{2}\qquad =\dfrac{\sqrt6-\sqrt2}{4}[/tex]

cos 15 = cos(45 - 30) = cos45 · cos30  + sin45 · sin30

                                   [tex]=\dfrac{\sqrt2}{2}\cdot \dfrac{\sqrt3}{2}+\dfrac{\sqrt2}{2}\cdot\dfrac{1}{2}\qquad =\dfrac{\sqrt6+\sqrt2}{4}[/tex]

       [tex]\dfrac{\sin 75+\sin 15}{\cos 75+\cos 15}[/tex]

   [tex]=\dfrac{\frac{\sqrt2+\sqrt6}{4}+\frac{\sqrt6-\sqrt2}{4}}{\frac{\sqrt6-\sqrt2}{4}+\frac{\sqrt6+\sqrt2}{4}}\\\\\\=\dfrac{\frac{\sqrt6}{2}}{\frac{\sqrt6}{2}}\\\\\\=1[/tex]

Find the difference. 15 5/12 - 11 1/8

Answers

Answer:

4 7/24

Step-by-step explanation:

Answer:

103/24 or 4.29 or 4 7/24

Step-by-step explanation:

15 5/12 - 11 1/8

185/12 - 89/8

370/24 - 267/24 = 103/24

or

15 10/24 - 11 3/24 = 4 7/24

what is 4 1/2 * 2 1/7 as a mixed number in simplest form?

Answers

It would be 9 9/14 :)

Answer:

9 9/14

Step-by-step explanation:

[tex]4\frac{1}{2}\times\:2\frac{1}{7}\\\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 4\frac{1}{2}=\frac{9}{2}\\\\\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 2\frac{1}{7}=\frac{15}{7}\\\frac{9}{2}\times\frac{15}{7}\\\\\mathrm{Multiply\:fractions}:\\\quad \frac{a}{b}\times\frac{c}{d}=\frac{a\:\times\:c}{b\:\times\:d}\\\\=\frac{9\times\:15}{2\times\:7}\\\\=\frac{135}{14}\\\\[/tex]

[tex]\mathrm{Convert\:improper\:fractions\:to\:mixed\:numbers}:\quad \frac{135}{14}\\=9\frac{9}{14}[/tex]

HELP PLEASE
Will give brainliest

Answers

Answer:

[tex]=7x^2+8x-2[/tex]

Step-by-step explanation:

So, on Monday, Tuesday, and Wednesday, he mowed:

[tex](4x^2+3x-4),(5x-8),(3x^2+10)[/tex]

yards, respectively.

To determine how many yards he mowed in the three days, simply add the three expressions. Thus:

[tex](4x^2+3x-4)+(5x-8)+(3x^2+10)[/tex]

Combine like terms:

[tex]=(4x^2+3x^2)+(3x+5x)+(-4-8+10)[/tex]

Add or subtract:

[tex]=7x^2+8x-2[/tex]

And it cannot be simplified further :)

A square has an area of 112 cm squared what is the approximate perimeter of the square

Answers

Answer:

approximate perimeter is 42.32

Step-by-step explanation:

each side of a square is equal to each other

1. Find the square root of 112

[tex]10.58^2 = 112[/tex]

2. Multiply 10.58 by 4(number of sides)

[tex]10.58(4) = 42.32[/tex]

find the value. 2⅔×2¹/7​

Answers

Answer: 40/7, if you need, the mixed fraction is 5 5/7

Step-by-step explanation:

First of all, convert all the mixed fraction into improper fraction.

2 2/3=8/3

2 1/7=15/7

Then do the multiplication.

8/3 × 15/7=120/21=40/7 (You can directly simplify it to 40/7 since you can use 15 divided by 3 to get 5 left in the numerator)

Hope this helps!! :)

Please let me know if you have any question

Answer:

5.71

Step-by-step explanation:

two two by three × two one by seven

=8/3×15/7

=8×5/7 as 15 and three will divide and 15 will change to 5

=40/7

=5.71

perimeter help please quick !

Answers

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{x = 4.4}}}}}[/tex]

Step-by-step explanation:

Given,

Length of the rectangle ( l ) = 3x + 5

Breadth of the rectangle ( b ) = 2x - 1

Perimeter of the rectangle ( P ) = 52

Finding the value of x

[tex] \boxed{ \sf{perimeter \: of \: rectangle = 2(l + b)}}[/tex]

⇒[tex] \sf{52 = 2(3x + 5 + 2x - 1)}[/tex]

⇒[tex] \sf{52 = 2(5x + 4)}[/tex]

⇒[tex] \sf{52 = 10x + 8}[/tex]

⇒[tex] \sf{10x + 8 = 52}[/tex]

⇒[tex] \sf{10x = 52 - 8}[/tex]

⇒[tex] \sf{10x = 44}[/tex]

⇒[tex] \sf{ \frac{10x}{10} = \frac{44}{10} }[/tex]

⇒[tex] \sf{x = 4.4 \: }[/tex]

Hope I helped!

Best regards!! :D

Find the other endpoint of the line segment with the given endpoint and midpoint.

Endpoint: ( -1, -7) Midpoint: ( -4, 10)

Answers

Don’t listen to other person above me who said you sell your self for s*x, just bc you need help on a question doesn’t make you stupid and doesn’t not mean you should drop out.

Here is the answer:

Endpoint 1 - (-1, -7)
Endpoint 2 - (-7, 27)
Midpoint - (-4, 10)

Can somebody help me with this ?? :)

Answers

The answer is C. If the verticle line intersects with the graph more than once, it is NOT a function.

Please help me with math.​

Answers

Answer:

Step-by-step explanation:

1=

option b= 4

2.

option b=60miles per hour

Hope it helps

The chart shows the cost of tuition at a certain state university. Model the data in the chart with a linear function, using the points (1,9941) and (3,11242). Predict the cost of college tuition in 2007-2008.

What is the linear model for the data?
Y=?

Answers

Answer:

The cost in 2007 - 2008  =  $15,795.5

The linear model for the data is y = $650.5·x + $9290.5

Step-by-step explanation:

The given data can be presented as follows;

College year,                         x,                 Estimated tuition, y

1997-1998,                             0,                 $9412

1998-1999,                             1,                  $9941

1999-2000,                            2,                 $10561

2000-2001,                            3,                 $11242

2001-2002,                            4,                  $11965

2002-2003,                            5,                  

2003-2004,                            6,                  

2004-2005,                            7,                

2005-2006,                            8,                

2006-2007,                            9,                  

2007-2008,                            10,                  

With points (1, 9941) and (3, 11242), we have the slope given by the equation;

[tex]m = \dfrac{y_2 - y_1}{x_2 - x_1}[/tex]

Which gives;

[tex]m = \dfrac{11242 - 9941}{3 - 1}= 650.5[/tex]

Therefore;

y - 11242 = 650.5 × (x - 3)

y= 650.5·x - 650.5 ×3 + 11242

y = 650.5·x + 9290.5

Therefore from the above table at 2007 - 2008, the value of x should be 10, we therefore have;

y = 650.5×10 + 9290.5 = $15,795.5

The cost (estimated tuition) in 2007 - 2008  =  $15,795.5

The linear model for the data is y = 650.5·x + 9290.5.

The linear model for the data is y = 650.5x + 9290.5 and The cost of college tuition in 2007-2008 is $15795.5

Linear equation

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

Let y represent the cost of tuition of battery after x years.

From the table using the points (1, 9941) and (3, 11242):

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\ \\ y-9941=\frac{11242-9941}{3-1}(x-1)\\ \\ y=650.5x+9290.5[/tex]

The linear model for the data is y = 650.5x + 9290.5

At 2007-2008 (x = 10:

y = 650.5(10) + 9290.5 = 15795.5

The cost of college tuition in 2007-2008 is $15795.5

Find out more on linear equation at: https://brainly.com/question/14323743

3-12=
please help i do not understand this

Answers

Unfortunately, I do not go to Harvard Business School so I am unable to solve this complex equation.

Answer: -9

Step-by-step explanation: you want to take away 12 from 3, which will leave you in the negatives

Is two to the fourth power equal to 2×4

Answers

Answer:

No

Step-by-step explanation:

2 to the fourth power is equal to 16.

On the other hand, 2 times 4 is equal to 8.

So, they are not equivalent because 16 [tex]\neq[/tex] 8

4² is the same as the question 4 x 4 which is 16

How can you prove that a conjecture if false?

Answers

Answer:

To show that a conjecture is false, you have to find only one example in which the conjecture is not true. So an example could be a drawing, a statement, or a number.

Please help me!! I can't do this...

Answers

Answer:

focus and belive on your self

Step-by-step explanation:

Which statement best describes the graph of 2x−5y=−25 and the graph of y=5/2x+5?

Answers

Answer:

Explanation:
2x - 5y = -25
-5y = -2x - 25
y = (-2/-5)x - 25/-5
y = (2/5)x + 5

y = 5/2x + 5

We can see that their slope is different but have the same y-intercept.

On a coordinate plane, point M is plotted (-3,-1) and point N is plotted (4,5). What is the distance between points M and N? square root of 117 square root of 85 5 square root of 17 85

Answers

Answer:

The square root of 85

Step-by-step explanation:

The formula to find out the distance between the points is shown below:

The Distance is

[tex]= \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]

where,

x_1 = -3

y_1 = -1

x_2 = 4

And, the y_2 = 5

Now place these values to the above formula

So, the distance is

[tex]= \sqrt{(4+3)^2 + (5+1)^2} \\\\= \sqrt{49 + 36} \\\\= \sqrt{85}[/tex]

= 9.22 units

Hence, the distance between points M and N is 9.22 units or the square root of 85

Hence, the second option is correct

Rationalize the denominator of $\frac{\sqrt{32}}{\sqrt{16}-\sqrt{2}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$, and $D$ are integers, $D$ is positive, and $B$ is not divisible by the square of any prime. Find the minimum possible value of $A+B+C+D$.

Answers

Rationalizing the denominator involves exploiting the well-known difference of squares formula,

[tex]a^2-b^2=(a-b)(a+b)[/tex]

We have

[tex](\sqrt{16}-\sqrt2)(\sqrt{16}+\sqrt2)=(\sqrt{16})^2-(\sqrt2)^2=16-2=14[/tex]

so that

[tex]\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{\sqrt{32}(\sqrt{16}+\sqrt2)}{14}[/tex]

Rewrite 16 and 32 as powers of 2, then simplify:

[tex]\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{\sqrt{2^5}(\sqrt{2^4}+\sqrt2)}{14}[/tex]

[tex]\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{2^2\sqrt2(2^2+\sqrt2)}{14}[/tex]

[tex]\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{4\sqrt2(4+\sqrt2)}{14}[/tex]

[tex]\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{16\sqrt2+4(\sqrt2)^2}{14}[/tex]

[tex]\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{16\sqrt2+8}{14}[/tex]

[tex]\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{8\sqrt2+4}7[/tex]

So we have A = 8, B = 2, C = 4, and D = 7, and thus A + B + C + D = 21.

The rationalized form of the given surd is [tex]\frac{8\sqrt{2}+4}{7}[/tex], and the minimum possible value of A + B + C + D = 8 + 2 + 4 + 7 = 21

Rationalizing Surds

From the question, we are to rationalize the denominator of the given surd.

We are to write the answer in the form

[tex]\frac{A\sqrt{B}+C}{D}[/tex]

and find the minimum possible value of A + B + C + D

The given surd is

[tex]\frac{\sqrt{32}}{\sqrt{16}-\sqrt{2}}[/tex]

To rationalize the surd, we will multiply the numerator and denominator by the conjugate of the denominator

The conjugate of the denominator is [tex]\sqrt{16}+\sqrt{2}[/tex]

Therefore,

[tex]\frac{\sqrt{32}}{\sqrt{16}-\sqrt{2}} \times \frac{\sqrt{16}+\sqrt{2}}{\sqrt{16}+\sqrt{2}}[/tex]

[tex]= \frac{\sqrt{32}(\sqrt{16}+\sqrt{2})}{(\sqrt{16}-\sqrt{2})(\sqrt{16}+\sqrt{2})}[/tex]

[tex]= \frac{\sqrt{512}+\sqrt{64})}{(\sqrt{16})^{2} -(\sqrt{2})^{2} }[/tex]

[tex]= \frac{16\sqrt{2}+8}{16-2}[/tex]

[tex]= \frac{16\sqrt{2}+8}{14}[/tex]

[tex]= \frac{2(8\sqrt{2}+4)}{2(7)}[/tex]

By comparing with, [tex]\frac{A\sqrt{B}+C}{D}[/tex]

A = 8, B = 2, C = 4, and D = 7

Then, the minimum possible value of A + B + C + D = 8 + 2 + 4 + 7 = 21

Hence, the rationalized form of the given surd is [tex]\frac{8\sqrt{2}+4}{7}[/tex], and the minimum possible value of A + B + C + D = 8 + 2 + 4 + 7 = 21

Learn more on Rationalizing surds here: https://brainly.com/question/9547165

what is the differnece in meaning between f and f(x)

Answers

Answer:f(x) indicates applying the function to the value x and can also represent the actual value obtained by applying the function to x

Step-by-step explanation:

Answer:

f(x) means y

Step-by-step explanation:

You use f(x) when it is representing y in a function

Does 21, 10, and 9 be the measures of the sides of a triangle

Answers

Answer:

no

Step-by-step explanation:

The sum of the lengths of any two sides of a triangle is greater than the length of the third side.

9+10 > 21

19 >21

This is not true so it cannot make a triangle

The Yellow Cab Company charges just $0.25 a mile, but it costs $5 to get in the cab. Express
Cab charges no fee to get in the cab, but $1.50 a mile for the ride.
a) If you are going 7 miles, which cab company should you call?
b)
If you are going 3 miles, which cab company should you call?
c)
For what length of drive is the cost equal?

Answers

Yellow Cab : y = 0.25x + 5
Express Cab: y = 1.5x
a) Yellow Cab: 1.75 + 5 = 6.75
Express Cab: 1.5 * 7 = 10.5
YELLOW CAB
b) Yellow Cab: 0.75 + 5 = 5.75
Express Cab: 1.5 * 3 = 4.5
EXPRESS CAB
c) 0.25x + 5 = 1.5x
1.25x = 5
x = 4
4 MILES

Answer:

For 7 miles call they Yellow Cab and for 3 miles call Express Cab

In 4 miles it cost $6.00 for both

Step-by-step explanation:

Express Cab= $4.50 for 3 miles, and for 7 miles it cost $10.50

Yellow Cab = $5.75 for 3 miles, and for 7 miles it cost $6.75

add 1.50 to 4.50 and is 6 dollars in 4 miles and add 0.25 to 5.75 and it also makes it 4 miles

Find the solutions to the equation below.
Check all that apply.
6x2 + 5x - 4 = 0
A. X=
-IN
B. X=
C. x =
1 D. x = -2
E. x=-5
F. X= 4

Answers

Answer:

X=1/2. X=4/3

Step-by-step explanation:

6x2+5X-4=0

6X2+8X-3X-4=0

2x(3x+4) - 1(3x+4)=0

2x-1) (3X-4)

X=1/2. X=4/3

The Solution of Equation is x = -4/3 or x= 2.

What is Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

We have the Equation:

6x² + 5x - 4 = 0

Solving the Quadratic equation

6x² + 5x - 4 = 0

6x² -3x + 8x - 4 = 0

3x( x- 2) +4 (x-2)= 0

(3x + 4) (x-2) = 0

3x +4 = 0 or x-2 = 0

x = -4/3 or x= 2

Learn more about Equation here:

https://brainly.com/question/29657983

#SPJ7

Give an example of a function with both a removable and a non-removable discontinuity.

Answers

Answer:

(x+5) (x=3)

(X+5) (x+1)

Step-by-step explanation:

A removeable discontinuity is always found in the denominator of a rational function and is one that can be reduced away with an identical term in the numerator. It is still, however, a problem because it causes the denominator to equal 0 if filled in with the necessary value of x. In my function above, the terms (x + 5) in the numerator and denominator can cancel each other out, leaving a hole in your graph at -5 since x doesn't exist at -5, but the x + 1 doesn't have anything to cancel out with, so this will present as a vertical asymptote in your graph at x = -1, a nonremoveable discontinuity.

Apply each transformation described to Figure A. If you get stuck, try using tracing paper. A figure A with a point P, a line l and a point P prime on a triangular grid. A translation which takes LaTeX: PP to LaTeX: P'P ′ A counterclockwise rotation of A, using center LaTeX: PP, of 60 degrees A reflection of A across line LaTeX: \ellℓ HTML EditorKeyboard Shortcuts

Answers

Answer:

p

Step-by-step explanation:

14, the difference of 4 times a and b

Answers

7.5 should be the answer

find the inverse of the function f(x)=6x^2+3

Answers

Answer:

The answer is

[tex]{f}^{ - 1} (x) = \sqrt{ \frac{x - 3}{6} } [/tex]

Step-by-step explanation:

f(x) = 6x² + 3

To find the inverse of the function above equate it to y

That's

f(x) = y

So we have

y = 6x² + 3

Next interchange the variables that's x becomes y and y becomes x.

x = 6y² + 3

Next make y the subject

Subtract 3 from both sides

That's

6y² + 3 - 3 = x - 3

6y² = x - 3

Divide both sides by 6

That's

[tex] {y}^{2} = \frac{x - 3}{6} [/tex]

Next find the square root of both sides

[tex]y = \sqrt{ \frac{x - 3}{6} } [/tex]

We have the final answer as

[tex] {f}^{ - 1} (x) = \sqrt{ \frac{x - 3}{6} } [/tex]

Hope this helps you

Plz help ASAP!!!! WILL MARK YOU BRAINLIST IF YOUR ANSWER IS CORRECT!! Question # 7 last question

Answers

Answer:

the last one

Step-by-step explanation:

i took the test

Answer: Choice A

If you plug x = 3 into choice A, then you dont have any division by zero errors or square roots of negative values.

Choice B in contrast has x-9 = 3-9 = -6 under the square root, so this leads to an imaginary/complex result. Choice D is similar.

Choice C will have zero in the denominator after plugging in x = 3 since x^2-9 = 3^2-9 = 9-9 = 0.

PLZ HELP!!!
At the band’s peak of popularity, a signed Black Diamond poster sold for $500. Three years later, the band was almost forgotten, and the poster was worth only $10. Write a function that will allow you to calculate how much the poster is worth after x years. State the meaning of each part of the equation in the context of the problem.

The annual depreciation rate is 72.86%

Answers

Answer:

The annual depreciation rate is 72.86%.

Step-by-step explanation:

The information provided are:

At the band’s peak of popularity, a signed Black Diamond poster sold for $500.Three years later, the band was almost forgotten, and the poster was worth only $10.

From the above data we know that the band's popularity depreciated.

The initial cost of a signed Black Diamond poster was, a = $500.

After three years the cost of a signed Black Diamond poster was, y = $10.

It can be seen that the value of a signed Black Diamond poster is decreasing exponentially over the years.

The formula for exponential decay or depreciation is:

[tex]y=a(1-r)^{x}[/tex]

Here,

y = final value

a = initial value

r = rate of depreciation

x = time

Compute the annual depreciation rate as follows:

         [tex]y=a(1-r)^{x}[/tex]

        [tex]10=500\times (1 -r)^{3}[/tex]

[tex](1-r)^{3}=\frac{10}{500}[/tex]

 [tex](1-r)=\sqrt[3]{\frac{1}{50}}[/tex]

    [tex]1-r=0.2714[/tex]

          [tex]r=1-0.2714\\\\r=0.7286[/tex]

Thus, the annual depreciation rate is 72.86%.

Other Questions
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