Someone help me with this question!

Someone Help Me With This Question!

Answers

Answer 1

Answer: [tex]160^{\circ}[/tex]

Step-by-step explanation:

By the exterior angle theorem,

[tex]4x-14+5x-182=5x-100\\\\9x-196=5x-100\\\\4x=96\\\\x=24\\\\\implies m\angle BCD=20^{\circ}\\\\\implies m\angle BCA=160^{\circ}[/tex]

Answer 2

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

Angle BCA = 160°

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

By Exterior angle property :

[tex]\qquad❖ \: \sf \:4x - 114 + 5x - 182 = 5x - 100[/tex]

[tex]\qquad❖ \: \sf \:9x -29 6 = 5x - 100[/tex]

[tex]\qquad❖ \: \sf \:9x - 5x = - 100 + 296[/tex]

[tex]\qquad❖ \: \sf \:4x = 96[/tex]

[tex]\qquad❖ \: \sf \:x = 24 \degree[/tex]

Next, Angle BCA = 180° - Angle BCD

( linear pair )

[ let angle BCA = y ]

[tex]\qquad❖ \: \sf \:y = 180 - (5x- 100)[/tex]

[tex]\qquad❖ \: \sf \:y = 180 - (5(24) - 100)[/tex]

[tex]\qquad❖ \: \sf \:y = 180 - (120 - 100)[/tex]

[tex]\qquad❖ \: \sf \:y = 180 - 20[/tex]

[tex]\qquad❖ \: \sf \:y = 160 \degree[/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

Angle BCA = 160°

Related Questions

Need help with this one

Answers

Answer:

The answer is a.2x/9

Step-by-step explanation:

[tex] \frac{x {}^{2} }{3y} \div \frac{3x}{2y} \\ \frac{x {}^{2} }{3y} \times \frac{2y}{3x} \\ \frac{x {}^{2} }{3} \times \frac{2}{3x} \\ \frac{x}{3} \times \frac{2}{3} = \frac{2x}{9} [/tex]

5.5(x+6 1/2)-(x+9 1/3) - (19-x)

Answers

The simplest form of the expression given in the task content is; 5.5x +7.42.

What is the simplest form of the expression?

The expression given in the task content is;

5.5(x+6 1/2)-(x+9 1/3) - (19-x)

Hence, the expression can be written in its simplest form as follows;

5.5x + 35.75 -x -9.33 -19 +x

= 5.5x +7.42.

Remarks: The complete task requires that the expression be written in its simplest form.

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I need help with my work

Answers

The area of the interior above the polar axis is -0.858 square units

The area bounded by a polar curve

The area bounded by a polar curve between θ = θ₁ and θ = θ₂ is given by

[tex]A = \int\limits^{\theta_{2} }_{\theta_{1} } {\frac{1}{2}r^{2} } \, d\theta[/tex]

Now, since we have the curve r = 1 - sinθ and we want to find the area of the interior above the polar axis, we integrate from θ = 0 to θ = π, since this is the region above the polar axis.

So, [tex]A = \int\limits^{\theta_{2} }_{\theta_{1} } {\frac{1}{2}r^{2} } \, d\theta\\= \int\limits^{\pi}_{0} {\frac{1}{2}(1 - sin\theta)^{2} } \, d\theta\\= \int\limits^{\pi}_{0} {\frac{1}{2}[1 - 2sin\theta + (sin\theta)^{2}] } \, d\theta\\= \int\limits^{\pi}_{0} {\frac{1}{2}\, d\theta - \int\limits^{\pi}_{0} 2sin\theta \, d\theta+ \int\limits^{\pi}_{0} (sin\theta)^{2} } \, d\theta\\[/tex]

[tex]A = \int\limits^{\pi}_{0} {\frac{1}{2}\, d\theta - 2\int\limits^{\pi}_{0} sin\theta \, d\theta+ \int\limits^{\pi}_{0} \frac{(1 - cos2\theta)}{2} } \, d\theta\\= \int\limits^{\pi}_{0} {\frac{1}{2}\, d\theta - 2\int\limits^{\pi}_{0} sin\theta \, d\theta+ \int\limits^{\pi}_{0} \frac{1}{2} } \, d\theta -\int\limits^{\pi}_{0} \frac{cos2\theta}{2} } \, d\theta\\[/tex]

[tex]A = \int\limits^{\pi}_{0} \, d\theta - 2\int\limits^{\pi}_{0} sin\theta \, d\theta -\int\limits^{\pi}_{0} \frac{cos2\theta}{2} } \, d\theta\\= [\theta]_{0}^{\pi} - 2[-cos\theta]^{\pi} _{0} - [\frac{sin2\theta}{4}]_{0}^{\pi} \\= [\theta]_{0}^{\pi} + 2[cos\theta]^{\pi} _{0} - [\frac{sin2\theta}{4}]_{0}^{\pi}\\= [\pi - 0] + 2[cos\pi - cos0] - \frac{ [sin2\pi - sin0]}{4}\\= \pi + 2[-1 - 1] - \frac{ [0 - 0]}{4}\\= \pi + 2[-2] - \frac{ [0]}{4}\\= \pi - 4 - 0\\= \pi - 4\\= 3.142 - 4\\= -0.858[/tex]

So, the area of the interior above the polar axis is -0.858 square units

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what is the inverse of the following function? 50 points

Answers

The inverse of the given function [tex]f(x)=\sqrt[5]{x^3}[/tex] is [tex]f^{-1}(x)=x^{\frac{5}{3}}[/tex]

Inverse of a function

The given function is:

[tex]f(x)=\sqrt[5]{x^3}[/tex]

This function can be written in exponent form as:

[tex]f(x)=x^\frac{3}{5}[/tex]

Make x the subject of the formula:

[tex]x=[f(x)]^\frac{5}{3}[/tex]

Let x be replaced by [tex]f^{-1}(x)[/tex] and f(x) be replaced by x

The inverse function therefore becomes:

[tex]f^{-1}(x)=x^{\frac{5}{3}}\\\\ f^{-1}(x)=\sqrt[3]{5}[/tex]

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Which expression is equivalent to √2+4?
OA. (2+4)²
OB. (2+4)²
OC. 6
D. 62

Answers

Option A, root(2+4) = root 6. Can be written as (2+4)^1/2

How do you solve for m?

m= −(4+m)+2

Answers

Answer:

[tex]\bf m = - 1[/tex]

Step-by-step explanation:

[tex]\bf m= −(4+m)+2[/tex]

First of all, let's Rearrange the given terms :-

[tex]\bf m = - ( m +4) + 2[/tex]

Now, let's distribute:-

[tex]\bf m = - m - 4 + 2[/tex]

Add numbers -4 + 2 = -2

[tex]\bf m = - m - 2[/tex]

Add m to both sides, and combine like terms :-

[tex]\bf 2m = - 2[/tex]

Divide both sides by 2 :-

[tex]\bf m = - 1[/tex]

m= -(4+m)+2
m= -4-m+2
2m= -2
m= -1

Hope it helps : )

Find the limit
lim x->0 (4x/tan2x)

Answers

Answer:

Step-by-step explanation:

hello : here is a solution

Jackson invested $4,200 in an account paying an interest rate of 9 1/2 compounded continuously. Julia invested $4,200 in an account paying an interest rate of 8 7/8 compounded quarterly. To the nearest hundredth of a year, how much longer would it take for Julia's money to double than for Jackson's money to double?

Answers

It would Julia 0.60 years more to double the initial investment.

What is future value?

Future value means the initial investment multiplied by 2 since the future value is meant to double.

The formula for future value of a continuously interest rate is provided below:

FV=PV*e^(rt)

FV=future value=$4,200*2=$8,400

PV=initial investment=$4,200

e=exponential constant=2.7182818

r=interest rate=9.5%

t=number of years it takes for the investment to double=unknown

$8,400=$4,200*2.7182818^(9.5%*t)

$8,400/$4,200=2.7182818^(0.095t)

2=2.7182818^0.095t

take log of both sides

ln(2)=0.095t* ln(2.7182818)

0.095t=ln(2)/ln(2.7182818)

0.095t=0.69314718781684800

t=0.69314718781684800/0.095

t=7.30 years

The future value when interest is compounded quarterly is shown thus:

FV=PV*(1+r/4)^(N*4)

FV=$8,400

PV=$4,200

r=8 7/8%

r=8.875%

N=the number of years it would take for the initial investment to double=unknown

$8,400=$4,200*(1+8.875%/4)^(N4)

$8,400=$4,200*(1+0.0221875)^(N4)

$8,400/$4,200=(1+0.0221875)^(N4)

2=(1+0.0221875)^(N4)

2=(1.0221875)^(N4)

take log of both sides

ln(2)=N4*ln(1.0221875)

N4=ln(2)/ln(1.0221875)

N4=31.5857423180125

N=31.5857423180125/4

N=7.90

Difference in years=7.90-7.30

difference in years=0.60 years

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I need help ASAP please

Answers

Answer:

8.1

Step-by-step explanation:

[tex]\sqrt{(-1-0)^2 + (5-(-3))^2}=\sqrt{65} \approx 8.1[/tex]

Find the missing coordinate.
x = cos t
y = sin t

(-1, [?])

Answers

Answer:

0

Step-by-step explanation:

sin²t + cos²t = 1, so since cos²t = 1, sin²t = 0, and thus sint = y = 0.

39 kg Rice of taken out of a bag of rice. If 8/22 of the rice is left in the beg then find the quantity of rice the bag contained in the beginning

Answers

Answer:

429/7 kg or 61 2/7 kg

Step-by-step explanation:

I'll answer according to how I understand this problem, but I'm not sure this is correct.

"39 kg of rice is taken out of bag of rice. If 8/22 of the rice is left, what was the original weight of the rice in the bag?"

8/22 is a strange number to work with because it could have been given as 4/11. This is another reason I'm not too sure about this problem.

8/22 = 4/11

If 4/11 is left, then since 11/11 - 4/11 = 7/11, 7/11 of the rice remains.

7/11 x = 39

x = 39 × 11/7

x = 429/7

x = 61 2/7

help guys please. I ​

Answers

Step-by-step explanation:

you need to use the ruler to measure the lengths of it, like place the ruler from A to B and look at the measurement of it

1. In a class of 60 students, a survey was conducted, 30 students had applied for Addis Ababa University, 25 students applied for Bahir Dar University and 24 students applied for Wachemo University. 11 students applied for both Addis Ababa and Bahir Dar Universities, 6 applied for both Addis Ababa and Wachemo Universities, 9 applied for both Wachemo and Bahir Dar Universities while 4 applied neither of the aforementioned universities. Find 1.. number of students that applied for all the universities. 2 number of students that applied for at least two of the universities. 3 number of students that applied at most two universities. 4 number of students that applied for Addis Ababa but not Bahir Dar University? Please I need your help?​

Answers

1. Consult the linked question. [tex]n(A\cap B\cap W) = \boxed{3}[/tex].

2. We have

[tex]n(A\cap B) = n(A\cap B \cap W) + n(A\cap B \cap W') \\\\ \implies 11 = 3 + n(A\cap B \cap W') \\\\ \implies n(A\cap B\cap W') = 8[/tex]

Similarly we can find

[tex]n(A\cap B' \cap W) = 3[/tex]

[tex]n(A'\cap B\cap W) = 6[/tex]

[tex]n(A\cap B'\cap W') = 16[/tex]

[tex]n(A'\cap B\cap W') = 8[/tex]

[tex]n(A'\cap B'\cap W) = 12[/tex]

Then the total number of students that applied to at least two of the universities is

[tex]\underbrace{n(A\cap B\cap W') + n(A\cap B'\cap W) + n(A'\cap B\cap W)}_{\text{only 2}} + \underbrace{n(A\cap B\cap W)}_{\text{all 3}} = \boxed{20}[/tex]

3. There's a small ambiguity here. Are we interested in students that applied to zero universities? If so, there are

[tex]\underbrace{n(U\setminus(A\cup B\cup W))}_{\text{none}} + \underbrace{n(A\cap B'\cap W') + n(A'\cap B\cap W') + n(A'\cap B'\cap W)}_{\text{only 1}} = \boxed{40}[/tex]

If we want students that applied to at least 1 school, we omit the first term and get a total of 36.

4. Split this set of students into those that also applied to Wachemo and those that did not.

[tex]n(A \cap B') = n(A\cap B' \cap W) + n(A\cap B'\cap W') = \boxed{19}[/tex]

please open the attached image

Answers

The function that will have a horizontal asymptotes are function B, C and D

Horizontal asymptotes of a function

A function is said to have a horizontal asymptotes of the degree of the numerator is less or equal to that of the denominator.

From the rational expression given, the function A and E wil have no horizontal asymptotes since the power of the numerator is greater abd equal to the denominator,

The function that will have a horizontal asymptotes are function B, C and D

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Solve for v. -8=-2/v

Answers

Answer is 1/4
Step by step
-8 = -2/v
First we want to isolate “v”
-2 is divided by “v”, so we will multiply both sides by “v”
-8v = -2
Now we can solve for v
Divide both sides by -8
v = 2/8, simplified to 1/4
(Remember when you multiply or divide two negatives it becomes a positive)

If you want to check your work, substitute your answer of 1/4 into the original equation.

-8= (-2) divided by (1/4)
-8 = -8
Problem solved!!

Question 10 (2.5 points) ✓ Saved
Write the comparison below as a ratio in simplest form using a fraction, a colon (:), and the word to.
15 dollars to 27 dollars

Answers

15/27 15:27 15 to 27

Which person is vulnerable to identity theft

Answers

The person which is more vulnerable to identity theft include:

The elderlyCollege studentsChildren

What is Identity theft?

This involves using someone's personal information to commit fraud and other forms of crime.

The set of people mentioned above are usually naive and innocent thereby making them more vulnerable to identity theft.

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The soil samples for the next field indicate that fertilizer

Answers

In order to have a greater fertilizer coverage, you need to increase flow rate and: A. increase speed to approximately 7.1 mph so that you cover the field more quickly.

What is a flow rate?

A flow rate is an average rate and it can be defined as the number of flow units that are created per unit time such as fertilizer coverage on a farm.

In this context, we can infer and logically deduce that you have to increase flow rate and your increase speed to approximately 7.1 mph, so that you can cover the field more quickly and have a greater fertilizer coverage.

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Complete Question:

The soil samples for the next field indicate that fertilizer coverage needs to be greater. To achieve this, you need to increase flow rate. How would you achieve this?

A. Increase speed to approximately 7.1 mph so that you cover the field more quickly

B. Increase the engine speed to approximately 2,000 rpm

C. Decrease speed to approximately 6.0 mph so that you cover the field more slowly

D. Shift to second gear so that the engine speed slows

Graph the image of the polygon after a reflection in the line y = t.

Answers

Answer:

  see the attached

Step-by-step explanation:

Reflection over a line moves each point so that the segment between it and its image has the reflection line as its perpendicular bisector.

Reflection over y=x

The line of reflection y=x has the effect of swapping the x- and y-coordinates:

  (x, y) ⇒ (y, x) . . . . . reflection in y=x

For example, point C(2, 3) moves to point C'(3, 2).

The attachment shows the reflected figure.

At full price, Melvin would pay 1.679 dollars per liter of gasoline. Using his loyalty card, Melvin only pays 1.439 dollars per liter

Answers

He pays $0.24 less when using his loyalty card.

How much less does Melvin pay per liter when using his credit card?

We know that, without the card, he would pay $1.679 dollars per liter of gasoline.

With his card, he would pay $1.439

To find the relation between the two prices, we just need to take the difference between the two values (a difference is a subtraction).

d = $1.679 - $1.439 = $0.24

He pays $0.24 less when using his loyalty card.

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In exercises 21 and 22, point B is between A and C on Line AC. Use the information to write an equation in terms of x. Then solve the equation and find AB, BC, and AC. AB= 13+ 2x BC= 12 AC= x+2

Answers

The value of x is -23 and the values of AB, BC, and AC are -33, 12 and -21

How to solve the equation and find AB, BC, and AC?

The equations are given as

AB = 13 + 2x

BC = 12

AC = x + 2

Point B is between A and C on Line AC.

So, we have

AC = AB + BC

This gives

x + 2 = 13 + 2x + 12

Evaluate the like terms

x - 2x = 13 + 12 - 2

This gives

-x = 23

Divide by -1

x =-23

Substitute x =-23 in AB = 13 + 2x and AC = x + 2

AB = 13 - 2 * 23 = -33

AC = -23 + 2 = -21

Hence, the value of x is -23 and the values of AB, BC, and AC are -33, 12 and -21

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sandy uses 41 round beads to make some triangles. how many triangles did she make.​

Answers

Answer:

3

Step-by-step explanation:

Numbers of beads used in making triangles:

3, 6, 10, 15, 21, 28, 36, ...

We need to pick a few numbers from those above that add to 41.

3 + 10 + 28 = 41

Answer: 3 triangles

Rafael earns $35 more per week than Andrew. If their weekly salaries total $715, what amount does each earn?

Answers

Answer:

Rafael earns $375

Andrew earns $340

Step-by-step explanation:

Here, we will set up a system of equations where r represents Rafael and a represents andrew.

r = a + 35

r + a = 715

Next, we substitute a + 35 for r in the second equation.

(a + 35) + a = 715 (combine like terms)

2a + 35 = 715 (subtract 35 from both sides)

2a = 680 (divide both sides by 2)

a = 340

To solve for r, we can plug 340 for a into either equation.

r = (340) + 35

r = 375

We can double check by plugging both values into the other equation.

375 + 340 = 715 (yes, it works!)

Brainliest, please :)

which of the following functions is graphed below?

Answers

The graphed piecewise function is the one in option B.

Which of the given functions is the graphed one?

On the graph, we can see that on the lowest part we have a closed dot at x = 1

And the above part has a open dot at x = 1.

Then the piecewise function is of the form:

y = f(x)  for x ≤ 1y = g(x) for x > 1

Such that the above part seems to be quadratic, and the part below seems to have a larger degree.

With that, we can conclude that the correct option is:

y = x^2 + 4,   for x > 1y = x^3 - 2,   for  x ≤ 1

Which is option b.

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Melissa is driving at a constant speed. She catches up to a minivan half a mile ahead of her that is
moving at 50 miles per hour in 50 seconds. How many miles per hour is the speed of the sports
car?

Answers

The speed of the sports car is 53.6 miles per hour

The key concept for solving such questions is the relationship between speed, distance and time.

The relationship between them is Distance = Speed x Time

Distance covered by Melissa = 0.5 miles + Distance covered by minivan

Let speed of Melissa be x miles per second

x. 50 = 0.5 + 50x50/3600

x .50 = 0.5 + 25/36

x = 1/100 + 1/72

x = 0.001 + 0.013

x = 0.014 miles per second

x = 3600 x 0.014 = 53.6 miles per hour

Thus the speed of the sports car is 53.6 miles per hour

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Please help ASAP!
What is the measure of arcXY shown in the diagram below?

Answers

Applying the angles of intersecting secants theorem, the measure of arc XY is: 32°.

How to Apply the Angles of Intersecting Secants Theorem?

According to the angles of intersecting secants theorem, m∠XZY = 1/2(arc VW - arc XY).

Plug in the values:

39 = 1/2(110 - arc XY)

2(39) = 110 - arc XY

78 = 110 - arc XY

78 - 110 = - arc XY

-32 = - arc XY

Arc XY = 32°

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Two trees are 120 m apart. From the point halfway between them, the angle of elevation to the top of the trees is 36 and 52. How much taller is one tree than the other.

Answers

One tree is 31.044 m taller than the other one in height.

Given Information and Formula Used:

The distance between the trees, BC (from the figure) = 120 m

Elevation of angles to the top of the trees,

∠AMB = 52°

∠DMC = 36°

In a right angled triangle,

tan x = Perpendicular/Height

Here, x is the angle opposite to the Perpendicular.

Calculating the Height Difference:

Let's compute the height of the taller tree first.

In ΔAMB,

tan 52° = AB / BM

Now, since M is the point halfway between the trees,

BM = CM = BC/2

BM = CM = 60 m

⇒ 1.2799 = AB / 60

AB = 1.2799 × 60

Thus, the height of the taller tree, AB =  76.794 m

Now, we will compute the height of the smaller tree.

In ΔDCM,

tan 36° = DC / CM

⇒ 0.7625 = DC / 60

DC = 0.7625 × 60

Thus, the height of the smaller tree, DC = 45.75 m

The difference in the heights of the trees, AP = AB - DC

AP = (76.794 - 45.75)m

AP = 31.044m

Hence one tree is 31.044m taller in height than the other.

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PLEASE FAST!!! Explain why, given a large unit A and a small unit B, it is wise to leave the conversion factor in fractional form if the decimal form goes on forever.

Answers

Numbers whose decimals form goes on forever are best represented as fractions because they are non-terminating decimals

How to determine the reasons?

The decimal numbers are represented as:

A and B

Where

A > B

Numbers whose decimals form goes on forever are non-terminating numbers, and the complete form cannot be represented using decimals except with the sign .......

Because non-terminating decimals have no end, it is best to represent them as fractions

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Length of the lot is 7 5/8 inches 1/2in=16ft
A.) 234ft
B.) 245 ft
C.) 244 ft
D.) 254 ft

Answers

Answer:

244 ft

Step-by-step explanation:

Scale: 1/2 in = 16 ft

Scale length = 7 5/8 inches

Real length = ?

We can use a proportion.

1/2 in : 16 ft = 7 5/8 in. : x

(1/2)/16 = (7 5/8)/x

(1/2)x = 16 × 7 5/8

(1/2)x = 122

x = 244

Answer: C. 244 ft  


Question 3
Show work and solve 3 = 5*+1 using change of base formula.

Answers

Answer: [tex]x=\frac{\log (3/5)}{\log 5}[/tex]

Step-by-step explanation:

[tex]3=5^{x+1}\\\\\log_{5} 3=x+1\\\\x=\log_{5} 3-1\\\\x=\log_{5} 3-\log_{5} 5\\\\x=\log_{5} \left(\frac{3}{5} \right)\\\\x=\frac{\log (3/5)}{\log 5}[/tex]

Other Questions
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