Suppose a scientist is working to develop a new waterproof, breathable fabric for hiking boots. This is an example of ______.
Help me plz

Answer:

The displacement by [tex]CH_{3}CO_{2}^{-}[/tex] on bromoethane.

Explanation:

Given that,

The displacement by [tex]CH_{3}CO_{2}^{-}[/tex] on bromoethane or bromocyclohexane.

We know that,

Bromoethane is not stable. It can easily break. But bromocyclohexane is more stable obstruct and very strong to displace.

Bromocyclohexane is a ring and we can not break easily of a ring.

So, bromocyclohexane does not displace by [tex]CH_{3}CO_{2}^{-}[/tex].

Hence, The displacement by [tex]CH_{3}CO_{2}^{-}[/tex] on bromoethane.

Answer:

CHCl_3

Explanation:

An Arrhenius acid produces H^+ in solution. If we look at the options provided, all the other species are acids that contain at least one replaceable hydrogen ion hence they possess H^+ and can act as Arrhenius acids in solution.

However, CHCl_3 does not contain a replaceable hydrogen ion hence it does not function as an Arrhenius acid.

The species that should not be capable of acting as an  Arrhenius acid in an aqueous solution is option A.  CHCl_3.

it is a compound that rised the concentration of hydrogen ion (H +) in an aqueous solution. Here the CHCl_3 should not generate the proton at the time when it should be mixed with water since it creates two immiscible layer. Moreover, the HNO3, H2SO4, H3O+, and HCIO4 should produce proton in aqueous.

Therefore, the option A should be considered.

learn more about acid here: https://brainly.com/question/23706382

Answer:

1.5 × 10⁻¹¹ M

Explanation:

Step 1: Given data

Step 2: Consider the self-ionization of water

H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)

Step 3: Calculate the molar concentration of H⁺

We will use the equilibrium constant for the self-ionization of water (Kw).

Kw = 1.0 × 10⁻¹⁴ = [H⁺] × [OH⁻]

[H⁺] = 1.0 × 10⁻¹⁴ / [OH⁻]

[H⁺] = 1.0 × 10⁻¹⁴ / 6.6 × 10⁻⁴

[H⁺] = 1.5 × 10⁻¹¹ M

Answer:

Dimethylmethane and propane

Explanation:

Answer:

4.3 × 10⁻⁵ M s⁻¹

Explanation:

Step 1: Given data

Step 2: Write the balanced reaction

NO + O₃ ⇒ NO₂ + O₂

Step 3: Calculate the reaction rate

The rate law is:

rate = k × [NO] × [O₃]

rate = 2.20 × 10⁷ M⁻¹s⁻¹ × 3.3 × 10⁻⁶ M × 5.9 × 10⁻⁷ M

rate = 4.3 × 10⁻⁵ M s⁻¹

Answer:

Electrons are transferred in an ionic bond, whereas they are unequally shared in a polar covalent bond, are equally blank in a nonpolar covalent bond.

Explanation:

An ionic bond involved the transfer of electron(s) from one atom to another. For instance, NaCl is formed by a transfer of one electron from sodium to chlorine.

A polar covalent bond is formed by an unequal sharing of electrons between atoms of different electro negativities. This is the case in polar HCl.

Non polar covalent bonds are formed when electrons are equally shared between two or more atoms such as in CH4.

Answer:

Explanation:

Relation between ΔG₀ and K ( equilibrium constant ) is as follows .

lnK =  -  ΔG₀ / RT

[tex]K = e^{-\frac{\triangle G_0}{RT}[/tex]

The value of R and T are same for all reactions .

So higher the value of negative ΔG₀ , higher will be the value of K  .

Mg(s) + N₂0(g) → MgO(s) + N₂(g)

has the ΔG₀ value of -673 kJ which is highest negative value . So this reaction will have highest value of equilibrium constant K .

Answer:

Higher pressure, is the right answer.

Explanation:

The A will have a higher pressure. Since we have given the volume and temperature is same in both containers A and B. Below is the calculation for proof that shows which container has the higher pressure while keeping the volume and temperature the same.  

[tex]So, \ V_A = V_B \\\frac{n_A T_A}{P_A} = \frac{n_B T_B}{P_B} \\Here, \ T_A = T_B \\P_A = \frac{n_A}{n_B} \times P_B \\\frac{n_A}{n_B} > 1 \\\frac{P_A}{P_B} > 1 \\P_A > P_B \\[/tex]

Therefore, the container “A” will have higher pressure.

Container A will have a higher pressure than container B.

According to the approximations of ideal gas conditions, the pressure of a gas is directly proportional to the number of molecules of a gas at constant temperature and volume.

Having this in mind, at constant temperature and volume, container A has more gaseous molecules than B, then container A will have a higher pressure than container B.

Missing parts;

If two separate containers A and B have the same volume and temperature, but container A has more gaseous molecules than B, then container A will have: A) Higher pressure B) Lower pressure C) A greater universal gas constant D) A smaller universal gas constant

Learn more: https://brainly.com/question/11155928

Answer:

The final volume was 41

Explanation:

m = 147 grams

d = 7.00 g/mL

V = x - 20

=========

d = m/V

=========

7 = 147 / (x - 20)

Multiply both sides by x - 20

7*(x - 20) = 147

Divide both sides by 7

x - 20 = 147 / 7

x - 20 = 21  

Add 20 to both sides

x = 21 + 20

x = 41

The final volume was 41

Answer:

a

Explanation:

a

Answer:

Chemical Change

Explanation:

Because it dissolves with the help of saliva , then into stomach and excreted in a different form

Answer:

Yess its a chemical change

:*

Explanation:

Answer:

See attached picture.

Explanation:

Hello,

In this case, on the attached picture you will find the required line structures for the cis and trans configurations of the given compound (2-pentene). Take into account for the cis that the adjacent carbons to those having the double bond remain in the same plane, whereas for the trans one, the adjacent carbons remain in a different plane.

Regards-

Answer: the molarity of the solution in volumetric flask "B' is 0.0100 M

Explanation:

Given that;

the Molarity of stock solution M₁ = 1.25M

The molarity os solution in volumetric flask A (M₂) = M₂

Volume of stock solution pipet out (V₁) = 5.00mL

Volume of solution in volumetric flask A V₂ = 25.00mL

using the dilution formula

M₁V₁ = M₂V₂

M₂ = M₁V₁ / V₂

WE SUBSTITUTE

M₂ =  ( 1.25 × 5.00 ) / 25.00 mL

M₂ = 0.25 M

Now volume of solution pipet out from volumetric flask A V₂ = 2.00 mL

Molarity of solution in volumetric flask B (M₃) = M₃

Volume of solution in volumetric flask B V₃ = 50.00m L

Using dilution formula again

M₂V₂ = M₃V₃

M₃ = M₂V₂ / V₃

WE SUBSTITUTE

M₃ = ( 0.25 × 2.0) / 50.0

M₃ = 0.0100 M

Therefore the molarity of the solution in volumetric flask "B' is 0.0100 M

The concentration of the final solution is 0.01 M.

This is a problem of serial dilution. We have to first obtain the concentration of  the solution in the new flask.

C1V1 = C2 V2

C1 = concentration of stock solution = 1.25 M

V1 = volume of stock solution =  5.00 mL

C2 = concentration of solution in the new flask = ?

V2 = volume of solution in flask B in the new flask = 25.00 mL

C2 = C1V1 /V2

C2 = 1.25 M ×  5.00 mL/ 25.00 mL

C2 = 0.25 M

Again we need to find the concentration when this solution is further diluted;

C1 = 0.25 M

V1 = 2.00 mL

C2 = ?

V2 = 50.00 mL

C2 = C1V1/V2

C2 = 0.25 M ×  2.00 mL/50.00 mL

C2 = 0.01 M

The concentration of the final solution is 0.01 M.

Learn more: https://brainly.com/question/6505878

Answer:

The correct answer is 8.786 g CaCO₃

Explanation:

The balanced reaction is the following:

CaCl₂(ac) + K₂CO₃(ac) → CaCO₃(s) + 2 KCl(ac)

From the stoichiometry, 1 mol of CaCl₂ (111 g) reacts with 1 mol of K₂CO₃ (138 g) to form 1 mol CaCO₃(100 g) and 2 moles of KCl (149 g).

The stoichiometric ratio CaCl₂/K₂CO₃ is: 111 g/138 g= 0.80 g CaCl₂/K₂CO₃.

We have 14.584 g CaCl₂ and 12.125 g K₂CO₃, which gives a ratio of: 14.584g/12.125 g= 1.2 g CaCl₂/K₂CO₃.

0.8 ∠ 1.2 ⇒ K₂CO₃ is the limiting reactant

We use the limiting reactant to calculate the grams of CaCO₃ produced. For this, we know that from 138 g K₂CO₃  100 g of CaCO₃ are produced. So, we multiply the amount of K₂CO₃ by this stoichiometric ratio to obtain the grams of CaCO₃ produced:

12.125 g K₂CO₃ x 100 g CaCO₃/138 g K₂CO₃= 8.786 g CaCO₃

Therefore, the theoretical yield of CaCO₃ is 8.786 g.

1) 4.5 mL

2) 12 mL

3) 82 mL

4) 110 mL

5) 330 mL

Answer:

42.75 grams of SiCl2Br2 must be weighed out

Explanation:

Here is the complete question:

An experiment requires that enough SiCl2Br2 be used to yield 13.2g of bromine . How much SiCl2Br2 must be weighed out?

Explanation:

First, we will determine the Molar mass of SiCl2Br2,

Si = 28.08, Cl = 35.45, Br = 79.90

Molar mass of SiCl2Br2 = 28.08 + 35.45(2) + 79.90(2)

= 258.78

Hence, the molar mass of SiCl2Br2 is 258.78 g/mol

If 79.90 grams of bromine is present in 258.78 grams of SiCl2Br2

Then, 13.2 grams of bromine will be present in [tex]x[/tex] grams of SiCl2Br2

[tex]x[/tex] = (13.2× 258.78) / 79.90

[tex]x[/tex] = 42.75 grams

Hence, 42.75 grams of SiCl2Br2 must be weighed out.

The family of elements that contains elements with a full octet of valence electrons is D. The noble gases. These elements have achieved stability by completely filling their outer electron shells with 8 electrons (except for helium, which has 2).

Noble gases are located in Group 18 of the periodic table and include elements such as helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). These elements have a completely filled outer electron shell, also known as a full octet. A full octet means that the outermost energy level of the atom contains 8 electrons, except for helium which has only 2 electrons.

Having a full octet of valence electrons makes noble gases highly stable and unreactive. This stability is due to the fact that the atoms of noble gases have achieved the same electron configuration as the nearest noble gas element.

For example, helium has a full outer shell with 2 electrons, which is the same electron configuration as the nearest noble gas, neon. Neon and the other noble gases have 8 electrons in their outermost shell, fulfilling the octet rule.

In contrast, the other options mentioned:

A. The actinides: The actinides are a series of elements in the periodic table that have their valence electrons in the 5f orbital. They do not have a full octet of valence electrons.

B. The halogens: The halogens are located in Group 17 of the periodic table and include elements such as fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At). These elements have 7 valence electrons and are highly reactive, seeking to gain one electron to achieve a full octet.

C. The alkali metals: The alkali metals are located in Group 1 of the periodic table and include elements such as lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr). These elements have 1 valence electron and are highly reactive, seeking to lose this electron to achieve a full octet.

To know more about noble gases:

https://brainly.com/question/19024000

#SPJ6

Answer:

Explanation:

volume of heptane= mass / density

volume of heptane = 37. 8 / .684

= 55.26 mL

volume of water  = 34.7  / 1

= 34.7 mL or cc.

If l₁ be the length of heptane layer in the graduated cylinder

volume = cross sectional area x length or height  of layer

π r² x l where r is radius of bore of the cylinder  , l is height of liquid inside cylinder .

for heptane

π r² x l₁ =  55.26

3.14 x 1.54² x l₁ = 55.26

l₁ = 7.42 cm

for water

π r² x l₂ =   34.7

3.14 x 1.54² x l₂ = 34.7

l₂ = 4.65  cm

Combined height = l₁ + l₂

= 7.42 + 4.65

= 12.07 cm .

Answer:

The units of both types of energy are Joule (kg × m² × s⁻²).

Explanation:

Step 1: Show the units of kinetic energy

The equation for kinetic energy is:

K = 1/2 × m × v²

where,

m: mass

v: speed

The units are:

K = 1/2 × m × v²

[K] = kg × (m/s)²

[K] = kg × m² × s⁻² = J

Step 2: Show the units of gravitational potential energy

The equation for gravitational potential energy is:

G = m × g × h

where,

m: mass

g: gravity

h: height

The units are:

G = m × g × h

[G] = kg × m/s² × m

[G] = kg × m² × s⁻² = J

Answer:

As the molecules of a liquid are cooled they slow down. As the molecules slow down they take up less volume. Taking up less room because of the molecules lower energy causes the liquid to contract.

Explanation:

The question is incomplete; the complete question is;

The normal boiling point of acetic acid is 118.1°C. If a sample of the acetic acid is at 125.2°C, predict the

signs of ∆H, ∆S, and ∆G for the boiling process at this temperature.

A. ∆H > 0, ∆S > 0, ∆G < 0

B. ∆H > 0, ∆S > 0, ∆G > 0

C. ∆H > 0, ∆S < 0, ∆G < 0

D. ∆H < 0, ∆S > 0, ∆G > 0

E. ∆H < 0, ∆S < 0, ∆G > 0

Answer:

∆H > 0, ∆S > 0, ∆G < 0

Explanation:

If we look at the question carefully, we will observe that it deals with a phase change from liquid to vapour phase.

Energy is required to break the intermolecular bonds in the liquid as it changes into vapour hence the process is endothermic, ∆H>0.

Also, the entropy of the vapour phase is greater than that of the liquid phase hence there is a positive change in entropy, ∆S>0.

Lastly, the process is spontaneous, hence the change in free energy ∆G is less than zero.

Answer:

help them

Explanation:

Answer:

Roll over the ground as fast as possible and cover the person as soon as possible.

Explanation:

When you run, the body on fire catches oxygen which stimulates a combustion reaction hence causing the fire to grow bigger.

Hope this helps! :)

And if possible, please mark this answer brainliest so I can get to the next rank :)

Answer:

d

Explanation:

when an atom lose an electron its radius reduces

Answer:

The peroxide initiates the free radical reaction

Explanation:

The addition of HBr to alkene in the presence of peroxides occurs via a free radical mechanism.

The organic peroxide acts as the initiator of the free radical reaction. The organic free radical interacts with HBr to produce a bromine free radical which now interacts with the alkene and the propagation steps continue until it is terminated by the coupling of two free radicals.

The peroxide effect leads to anti-Markovnikov addition.

Answer:

No it is not soluble

Explanation:

if you were to look at the solubilibity table its not there

Answer:

where is statements if you give statements then ican answer okk

The branch of science which deals with chemical bonds is called chemistry.

The correct answer to the question is rancidity.

The process of decomposition of the edible items in presence of air which gives a bad odor is called rancidity.

The canned baked items are less prone to rancidity because they have preservation and nitrogen gas in them which prevent them from decomposition.

When the food reacts with the air it starts to decomposition due to oxidation.

Hence, canned baked last longer than the can in the air.

For more information, refer to the link:-https://brainly.com/question/25026730

Answer:

6.37 × 10²³ molecules

Explanation:

The molar mass of NaNO₃ = (23 × 1) + (14 ×1) + (16 × 3) = 23 + 14 + 48 = 85 g/mol

Since the fertilizer contains 17.3% sodium nitrate, The number of sodium nitrate in 0.520 kg of fertilizer = 17.3% × 0.520 kg = 0.173 × 520 g = 89.96 g

Number of moles of NaNO₃ in 0.520 kg of fertilizer =  89.96 g / 85 g/mol = 1.0584 moles

Number of molecules of NaNO₃ in 0.520 kg of fertilizer =  1.0584 moles × 6.02 × 10²³ = 6.37 × 10²³ molecules

Answer:

[tex]V=50mL[/tex]

Explanation:

Hello,

In this case, by knowing that the volume of an object is computed by considering its dimensions, width, length and height, for the given measurements, we obtain:

[tex]V=W*H*L=1.25cm*2.5cm*15.956cm\\\\V=49.86cm^3[/tex]

Moreover, since one cubic centimetre equals one millilitre, the required volume is:

[tex]V=49.86cm^3*\frac{1mL}{1cm^3}\\ \\V=49.86mL[/tex]

Finally, since 2.5 cm has the fewest significant figures (2), the proper result is:

[tex]V=50mL[/tex]

Regards.