The 240 kg boat moves at a speed of 2 m/s. The 60 kg person on it jumps into the water at a speed of 8 m/s. What will be the speed of the boat after the jump?

The person can go high up to 685.71 m. The principle of energy conservation is applied in this question. First , use the term of efficiency to estimate the available energy. Finally, use energy conservation to calculate the person's height.

The following formula can be used to calculate an object's potential energy.

            PE = mgh

Here, m denotes mass, g denotes gravitational acceleration, and h denotes body height.

Step 1:

The average efficiency of energy utilised by the body is 25%. As a result, climbing the stairs consumes 25% of the person's entire energy. The following formula is used to determine available energy:

           E' = E(25/100)

In the above equation, replace E with 480 Cal.

           E' = (480 Cal) (25/100) ((4.2 * 10^3 J)/1 Cal)

               = 504 * 10^3 J

Step 2:

The body's initial energy is the energy needed to execute the task. The following is the initial energy:

            TE = E'

Substitute 504 * 10^3 J in the above equation.

            TE = 504 * 10^3 J

The available energy is used to complete the task of climbing the steps. As a result, the starting energy equals the end energy.

Replace mgh with TE in the above expression and find the height h.

           mgh = 504 * 10^3 J

            h = (504 * 10^3 J)/mg

Substitute 75 kg for m and 9.8 m/s^2 for g in the above expression.

            h = (504 * 10^3 J)/(75 kg)*(9.8m/s^2)

               = 685.71 m.

Thus, the height covered by the person is 685.71 m.

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They are not correct. The correct volume of the gas at 2.44 atm and 100 °C is 0.95 L

To know if your classmates are correct or not, we shall determine volume.

We can calculate the volume of the gas by using the combined gas equation as shown below:

P₁V₁ / T₁ = P₂V₂ / T₂

(1.22 × 1.64) / 323 = (2.44 × V₂) / 373

Cross multiply

323 × 2.44 × V₂ = 1.22 × 1.64 × 373

Divide both side by (323 × 2.44)

V₂ = (1.22 × 1.64 × 373) / (323 × 2.44)

V₂ = 0.95 L

We can see from the above calculation that the volume of gas at 2.44 atm and 100 °C is 0.95 L.

Thus, your classmates are not correct.

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Coherent scattering and compton scattering may result in the production of small-angle scatter.

Compton scattering is a type of scattering that occurs when a photon interacts with an atom or molecule and loses some of its energy to an electron. This results in the photon being scattered at a smaller angle and the electron being excited to a higher energy level.

Coherent scattering, also known as Rayleigh scattering, occurs when a photon interacts with an atom or molecule and is scattered in the forward direction. This type of scattering is characterized by a very small angle of scattering and is responsible for the blue color of the sky. Both Compton scattering and coherent scattering can result in small-angle scatter of x-radiation.

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Your question seems incomplete, but I assume the question was:

"which two interactions between x-radiation and matter may result in the production of small-angle scatter?

(group of answer choices)

photoelectric absorption and compton scattering

coherent scattering and compton scattering

photoelectric absorption and pair production

coherent scattering and pair production."

Answer:

The answer is 294 J

Answer:

294 j

Explanation:

The electric potential energy change is described by the equation U = U2 - U1, and the quantity of work performed by the electric force is -2.68 x 10-17 J.

U1 = kqQ / r

Where U1 is the change in electrical potential energy and k is a constant,

• Charge = Q

• r = separation from the charge point

V = kQ / r, therefore U1 = V1 q.

U₁ = 23q

U2 = V2q is the electrical potential energy at position P2.

U2 = 185 x q

The following equation represents the change in electric potential energy:

ΔU = U₂- U1

(b)

Solving the equation, we have:

ΔU = 185 - 23

ΔU = 162 eV

Since the charge in the change in potential difference is positive, the work produced by the electric force when the proton is in motion is negative.

i.e.

ΔUE = q(162)

ΔUE (-e) (162) V

ΔUE = -162 eV

where;

• ΔUE denotes the work done by the electric force.

Recall that:

• 1 electron volt = 1.66 x 10-19 Joules

ΔUE = -162 x 1.66 x 10-19 J

ΔUE = -2.68 x 10-17 J

This leads us to the conclusion that the electric potential energy change is described by the equation U = U2 - U1, and the quantity of work performed by the electric force is -2.68 x 10-17 J.

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For an object placed before a concave mirror:

a) u and v value = -60 cm and -40 cm respectively.

b) -24 cm

c) 2/3.

a) According to the New Cartesian sign convention, the object distance (u) is -60 cm and the image distance (v) is -40 cm.

b) To find the focal length of the mirror, we can use the lens equation: 1/f = 1/u + 1/v. Substituting the values for u and v, we get: 1/f = 1/-60 + 1/-40 = -1/60 + 3/120 = -1/60 + 1/40 = -1/24 cm. Therefore, the focal length of the mirror is -24 cm.

c) To find the magnification, we use the formula: Magnification (M) = -v/u. Substituting the values for u and v, we get: M = -(-40)/(-60) = 2/3. Therefore, the magnification of the image is 2/3.

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Answer:

С.Coiling the wire around a permanent magnet.

The following vectors are calculated by multiplying the vector's magnitude by the relevant unit vector:

The vector [tex]$\vec{A}$[/tex] would be [tex]$- < \mathbf{0 . 7 0 8}, \mathbf{0}, \mathbf{- 0 . 7 0 8} > * 4.66 * 10^{-3}$[/tex]

The vector, [tex]$\vec{B}=\left\langle 0,-1,0 > ^* 676\right.$[/tex]

The vector, [tex]\vec{C}=\left\langle 0.707,0,-0.707 > * 4.47 * 10^2\right.[/tex]

As per the data provided in the above question are a bellow,

The basic vector looks like this:

[tex]$$\vec{A}=(\mathrm{a}, \mathrm{b}, \mathrm{c}) \ldots . .1$$[/tex]

the magnitude [tex]$|\vec{A}|$[/tex] can be obtained as :

[tex]$$|\vec{A}|=\sqrt{a^2+b^2+c^2} \ldots . .2$$[/tex]

This could be the unit vector:

[tex]$$\hat{u}_A=\frac{\vec{A}}{|\vec{A}|_{\ldots \ldots .3}}$$[/tex]

a) (0.00330, 0 , -0.00330)

Thus,

=(0.00330, 0 , -0.00330)

Using equation two to calculate this magnitude:

[tex]$$|\vec{A}|=\sqrt{0.00330^2+0^2+(-0.00330)^2}=4.66 * 10^{-3}$$[/tex]

This could be the unit vector:

[tex]\hat{u}_A & =\frac{\vec{A}}{|\vec{A}|} \\\hat{u}_A & =\left\langle\frac{0.00330}{4.66 * 10^{-3}}, \frac{0}{4.66 * 10^{-3}}, \frac{-0.00330}{4.66 * 10^{-3}} > \right. \\\hat{u}_A & = < 708,0,-708 >[/tex]

Thus, the vector [tex]$\vec{A}$[/tex] would be [tex]$- < \mathbf{0 . 7 0 8}, \mathbf{0}, \mathbf{- 0 . 7 0 8} > * 4.66 * 10^{-3}$[/tex]

B)(0 , -676, 0)

Solving similar problems to A),

The vector,

[tex]$|\vec{B}|=\sqrt{0^2+-676^2+0^2}=676$[/tex]

This could be the unit vector:

[tex]& \hat{u}_B=\frac{\vec{B}}{|\vec{B}|} \\& \hat{u}_B=\left\langle\frac{0}{676}, \frac{-676}{676}, \frac{0}{676}\right\rangle[/tex]

And the vector,

[tex]$\vec{B}=\left\langle 0,-1,0 > ^* 676\right.$[/tex]

C) (0.00316 , 0 , -0.00316)

When we attempt the third vector, we will obtain magnitude:

[tex]$$|\vec{C}|=\sqrt{0.00316^2+0^2+(-0.00316)^2}=* 4.47 * 10^{-3}$$[/tex]

Then,

[tex]& \hat{u}_C=\frac{\vec{C}}{|\vec{C}|} \\& \hat{u}_C=\left\langle\frac{0.00316}{4.47 * 10^2}, \frac{0}{4.47 * 10^2}, \frac{0.00316}{4.47 * 10^2}\right\rangle[/tex]

And the vector,

[tex]\vec{C}=\left\langle 0.707,0,-0.707 > * 4.47 * 10^2\right.[/tex]

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The speed of the water inside a garden hose is 12.6 m.

If the nozzle has an opening of diameter 1.0 cm and the water is leaving the nozzle at a speed of 14 m/s, then the speed of the water inside the hose can be calculated.

To find the speed of the water inside the hose, the Bernoulli equation can be used. The Bernoulli equation states that for an ideal, inviscid flow:

P1/ρ + (V1^2)/2 + gz1 = P2/ρ + (V2^2)/2 + gz2

The speed of the water inside the hose is Where P1 and P2 are the pressures at 1 and 2, V1 and V2 are the velocities at 1 and 2, g is the acceleration due to gravity, and z1 and z2 are the heights at 1 and 2.

The pressure inside the hose will remain constant, so the Bernoulli equation can be simplified to:

(V1^2)/2 = (V2^2)/2

The velocity of the water inside the hose can then be calculated by rearranging the equation:

V2 = √(V1^2 - 2g (z1 - z2))

Therefore, the speed of the water inside the hose can be calculated by substituting in the known values for V1, g, z1, and z2.

Using the given values, the speed of the water inside the hose is calculated to be 12.6 m/s.

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"The most applicable term to a discussion of angular momentum in the context of black holes is Spin."

Angular Momentum is defined as the property of any rotating object which is given by the product of the moment of inertia of an object and the angular velocity of the rotating object. Angular momentum is a vector quantity and it has both the magnitude and direction. The Earth's rotation and revolution are two instances of angular momentum.

When astronomers claim to have calculated a black hole's spin, they actually mean to have calculated its angular momentum. This is the total angular momentum of all the materials on the Universe that ever crossed the event horizon and got trapped inside it.

The given question is incomplete. The complete question contains options. they are 'A: Photon B: Curvature C: Spin D: Time'

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Absolute zero is the temperature at which the atoms in an object stop moving and thus cannot get any colder.

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Answer:

coal

petroleum

and natural gas

When the ball reaches its maximum height, velocity will becomes zero. The velocity of an object can be positive, negative, or zero.

The ball is at the highest point of its trajectory and has momentarily stopped moving upward, but has not yet begun moving downward. The ball is momentarily at rest, thus it has zero velocity at that instant. Velocity is a vector quantity and it represents the rate of change of displacement. At the maximum height, the displacement changes from upward to downward direction. Therefore, the velocity of the ball becomes zero at the maximum height. The velocity of the object at maximum height is zero because the object is at rest at that point. At this point, the net force acting on the object is zero, and the object is not moving in any direction. The object is momentarily at rest, thus it has zero velocity at that instant.

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The magnitude of the impulse acting on the rubber ball is 1.5 kg m/s.

Magnitude is a measure of the size of a physical quantity, usually expressed as a numerical value and often used to compare the relative sizes of different objects or phenomena. It is typically used to measure the intensity, size, or strength of something. Magnitude is a concept applicable to many different physical quantities, such as light, sound, energy, speed, and force.

This is calculated by taking the difference between the initial and final momentum of the ball, which is (0.5 kg × 11 m/s) - (0.5 kg × 9.0 m/s) = 1.5 kg m/s.

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When you swing the pendulum, there will be an exchange of kinetic and potential energy.

A pendulum is an object attached to a string and can swing freely and periodically. When the pendulum is swinging, there will be a constant exchange of energy. The exchange of kinetic energy and gravitational potential energy occurs in every vibration. The mechanical energy involved in this action helps maintain the pendulum's constant period. The time it takes for the pendulum to swing back to its original position is called the pendulum's period. The period of the pendulum depends on the force of gravity and the length of the pendulum.

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Answer:

Explanation:

Seatbelts are essential in a car because they serve to hold the vehicle's passengers firmly in their seats during a collision. This reduces the danger of serious injury or death by protecting people from being flung from the vehicle or colliding with hard objects inside the vehicle.

In addition to wearing seatbelts, the following steps can be done to lessen the severity of an accident:

1. Airbags: In modern automobiles, airbags release following a collision to absorb the impact and prevent the occupants from hitting hard objects within the vehicle.

2. Kid safety seats: Children should be properly strapped in a child safety seat that is age and size appropriate.

3. Headrests: Properly positioned headrests can help lessen the risk of whiplash injuries in the event of an accident.

4. Avoiding distractions: One of the primary causes of accidents is distracted driving. Avoiding distractions while driving, such as using a mobile phone, eating, or applying make-up, can assist to lower the chance of an accident.

5. Regular car maintenance, such as regular servicing, tyre pressure checks, and brake checks, may assist to ensure that the vehicle is in excellent condition and lower the danger of an accident.

6. Avoiding aggressive driving: Speeding, tailgating, and making rapid lane changes all raise the chance of an accident.

7. Following traffic rules, such as respecting speed limits, traffic signs, and signals, as well as maintaining a safe distance from other cars, can assist to lessen the likelihood of an accident.

If a 30N net force is applied to an object with a mass of 60 kg, the net acceleration will be 0.5 m/s².

In mechanics, acceleration is the rate of change of the velocity of an object with respect to time.

F = m x a

30N = 60kg x a

a = [tex]\frac{30N}{60Kg}[/tex]

a = 0.5 m/s²

Accelerations are vector quantities (in that they have magnitude and direction). The orientation of an object's acceleration is given by the orientation of the net force acting on that object. the acceleration is when the velocity of object and car increases time by time. acceleration can be positive and negative depending on the application. The magnitude of an object's acceleration, as described by Newton's Second Law, is the combined effect of two causes. by this information and the given data, we can calculate that if a 30N net force is applied to an object with a mass of 60 kg, the net acceleration will be 0.5 m/s².

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The direction of the acceleration from t = 10 s to t = 15 s is opposite to the direction of velocity.

Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Both effects contribute to the acceleration for all other motions.

Acceleration is a vector quantity since it has both a magnitude and a direction.

As velocity linearly decreases, the direction of the acceleration from t = 10 s to t = 15 s is opposite to the direction of velocity.

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Approximately 70% of the solar energy that reaches Earth's atmosphere is absorbed by the atmosphere.

The Earth receives a continuous solar energy input of 173,000 terawatts (trillions of watts). That is more than 10,000 times what the entire world uses in terms of energy. And that energy is endlessly replenishable, at least as long as the sun exists.

Overall, the atmosphere and the Earth's surface absorb about 70% of incoming radiation, while about 30% is reflected back to space and does not heat the surface. Considering that the Earth is colder than the Sun, it radiates energy at wavelengths that are much longer.

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The crate will not slide down the ramp since the force of friction is greater than parallel force.

The force of friction resisting the motion of the container is calculated by applying the following formula.

Ff = μmg cosθ

where;

Ff = 0.47 x 84 kg  x 9.8 m/s² x cos (22)

Ff = 358.7 N

The parallel force on the container is calculated as follows;

Fp = mg sinθ

Fp = 84 x 9.8 x sin (22)

Fp = 308.38 N

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The velocity of the 5kg particle immediately after collision is -1m/s, the total kinetic energy of the system of the two particles change by -40 joules and the additional kinetic energy can be gained by using some external material.

Kinetic energy is the energy stored in the object by virtue of its motion and its unit is Joule. Momentum is defined as the product of mass and velocity of the particle. To calculate the velocity of the particle after collision, we first equate the values in the formula of conservation of momentum which is given as:

[tex]m1v1 + m2v2 = M1V1 +M2V2[/tex] ...(1)

m1, v1 = mass and velocity of object of mass 5kg (before collision)

m2, v2 = mass and velocity of object of mass 10kg (before collision)

M1, V1 = mass and velocity of object of mass 5kg (after collision)

M2, V2 = mass and velocity of object of mass 10kg (after collision)

Putting values in equation 1, we get:

5(3) + 10(2) = 5(V1) + 10(4)

5V1 = -5, ∴ V1 = -1 m/s

To calculate change in kinetic energy, we equate as follows:

[tex]Ki - Kf = 1/2(m1v1^2) + 1/2(m2v2^2) - 1/2(M1V1^2) - 1/2(M2V2^2)[/tex] ...(2)

Putting values in equation (2), we get:

Ki -Kf =  1/2(5×3^2) + 1/2(10×2^2)  1/2(5×1^2) + 1/2(10×4^2)

Change in K.E. = -40Joules

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The horizontal distance is R = 8100 m.

What are Newton's first, second, and third laws of motion?

According to the first law, a force must be applied to an object before it may affect its motion. According to the second law, an object experiences a force equal to its mass times its acceleration. According to the third law, when two things interact, they exert forces on one another that are both equal in strength and directed in the opposite direction.

To find the height of the plane from ground :

H = ut + (1/2)gt²

Where

initial velocity ,u = 0 m/s,

t = time = 27 s,

acceleration due to gravity ,g = 10 m/s²

H = 0*(27) + (1/2)*(10)*(27)²

H = 3645 m = 3.6 km

The horizontal distance (R) :

R = ut

R = 300*(27)

R = 8100 m

If d represent the distance from the engine to the air plane at the ground, hence:

d² = 8100² + 3645²

d = 7233 m

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The tension in the string at the top is calculated to be 71 N and at the bottom of the string is calculated to be 1.1 × 10⁻² N.

F cent = F g + F t

where, F cent is centripetal force

F g is the gravitational force

The tension force is denoted by F t

F t = F cent - F g = (4π² R m)/T² - m g

where,

R is the radius

m is the mass

T is the time taken for one revolution

g is the acceleration due to gravity

On substituting the values,

F t = (4 × 3.14²×1)/0.97² - 2.2× 9.8 = 70.7259 N ≈ 71 N

At the bottom of the string is,

F cent = -F g + F t

F t = F cent + F g = (4 π² R m)/T² + m g = (4 × 3.14²×1)/0.97² + (2.2× 9.8) =  113.8899 N = 1.1 × 10⁻² N

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Through sound waves, the meatball's kinetic energy is dissipated into the environment.

Lengthwise waves are what sound waves are. Any given medium will experience compressions and rarefactions as longitudinal waves pass through it. When particles move closely together during compression, high pressure zones are created.

A vibrating object or medium causes its constituent particles to begin to move. Sound waves are the name given to this particle movement. This kind of mechanical wave exists.

The meatball's kinetic energy causes vibrations in the wall and the surrounding air when it strikes the wall. The kinetic energy is converted to sound energy through these vibrations until the energy runs out.

As a result, sound waves dissipate the meatball's kinetic energy into the environment.

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(a) The time spent in the air by the ball is 4.02 s.

(b) The horizontal distance travelled by the ball is 140.7 m

The time of motion of the ball is calculated by applying the following equation.

t = √ ( 2h / g )

where;

t = √ ( 2 x 79 / 9.8 )

t = 4.02 s

The horizontal distance travelled by the ball is calculated as follows;

d = vt

where;

d = 35 m/s x 4.02 s

d = 140.7 m

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Coulomb's law, states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them, can be used to compute the electric force.

The equation is: F = k * (q1 * q2) / r^2

where F is the electric force, k is Coulomb's constant (9 x 10^9 N * m^2 / C^2), q1 and q2 are the charges, and r is the distance between them. So, in this case, the electric force between the two charges of +4 x 10^-5 C would be:

F = (9 x 10^9 N * m^2 / C^2) * ((+4 x 10^-5 C) * (+4 x 10^-5 C)) / (0.5 m)^2

F = (9 x 10^9 N * m^2 / C^2) * (16 x 10^-10 C^2) / (0.5 m)^2

F = (9 x 10^9 N * m^2 / C^2) * (16 x 10^-10 C^2) / (0.25 m^2)

F = 36 x 10^9 N. So the force between the two charges is 36 x 10^9 N.

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The cable that should be connected to a multimeter in order to measure the electric potential different are two banana cables, the black probe should be plugged into the COM and the red probe into the port marked VΩmA.

The black end of the probe is connected into the COM socket. All meters use this as standard. The red probe lead is plugged into a socket labeled VΩmA, which can be used to measure voltage, resistance, or microamperes. If the socket doesn't say "mA" as described above, there will be one or more separate sockets where the red probe lead can be connected to measure current. The maximum current range for these sockets will be indicated with a "A" or "mA" marking.

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The bicyclist's acceleration is 2.7 m/s². Thus, Option C is the answer

Acceleration is defined as rate of change of velocity with time. Its formula is

a= [tex]\frac{vf - vi}{t}[/tex]

acceleration = (final velocity - initial velocity) / time

The bicyclist's acceleration can be found using this equation:

In this case,

final velocity = 12.15 m/s

initial velocity is 0 m/s (since the bicyclist starts from rest)

time = 4.5 s

Plugging these values into the equation, we get:

a =[tex]\frac{12.5 - 0}{4.5}[/tex]

a = 2.7 ms⁻²

Therefore, The correct answer is c. 2.7 m/s²

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The acceleration of the frog when it started from rest is 61.67 m/s^2.

The frog starts from rest. So, the initial speed is

U=0m/s

And the final velocity is

V= 3.7m/s

And the time taken by the frog to do this is

t=60ms

So, the acceleration of the frog is

a=v-u/t

a= 61.67 m/s^2

Although the ability to plot a graph accurately is important, it is absolutely essential to be able to interpret graphs and to visualise the shape of a graph for a given motion.

For an object that is stationary, the displacement–time, velocity–time and acceleration–time graphs

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