The area of Asia is approximately 4.46 × 107 square kilometers. Its population is approximately 3.70 × 109 people. What is the approximate population density (people per square kilometer) of Asia? Write your answer in standard form. If necessary, round your answer to the nearest hundredth.

- 120.54 people/km2
- 82.96 people/km2
- 8.30 x 10 (15th power) people/km2
- 8.30 x 10 (1st power) people/km2

Answers

Answer 1

Step-by-step explanation:

you have to be careful what you are typing.

the way you wrote the numbers Asia would be a tiny place with very few people.

but I think you meant to say :

area is 4.46 × 10⁷ km²

with 3.70 × 10⁹ people.

people / km² = 3.70/4.46 × 10⁹/10⁷ =

= 0.829596413... × 10² = 82.9596413... =

= 82.96 people/km²

Answer 2

The population density will be equal to 82.96 people/km2. The correct option is B.

What is an expression?

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that the area is 4.46 × 10⁷ km² with 3.70 × 10⁹ people. The population density will be calculated as below:-

Density = people / km² = ( 3.70 × 10⁹ ) / ( 4.46 x 10⁷ )

Density = 0.829596413... × 10² = 82.9596413

Density = 82.96 people/km²

Therefore, the population density will be equal to 82.96 people/km2. The correct option is B.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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The lengths of the sides of quadrilateral EFGH are as follows: EF = 12 cm, FG = 6 cm, GH = 9 cm, and EH
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Answers

The true statement about the side lengths of quadrilateral MNOP is (d) MP = OP = 11.25 cm because the scale factor for dilating quadrilateral EFGH is 1.25.

The side lengths of EFGH are given as:

[tex]EF = 12\ cm[/tex]

[tex]FG = 6\ cm[/tex]

[tex]GH = 9\ cm[/tex]

[tex]EH = 9\ cm[/tex]

Length NO is also given as:

[tex]NO = 7.5\ cm[/tex]

Because both quadrilaterals are similar, then side NO corresponds to side FG.

The scale factor (k) from EFGH to MNOP is then calculated as:

[tex]k = \frac{NO}{FG}[/tex]

[tex]k = \frac{7.5}{6}[/tex]

[tex]k = 1.25[/tex]

The side lengths of MNOP are then calculated using:

[tex]MN = 12cm \times 1.25[/tex]

[tex]MN = 15\ cm[/tex]

[tex]OP = 9cm \times 1.25[/tex]

[tex]O P = 11. 25 cm[/tex]

Also,

[tex]MP = 11. 25 cm[/tex]

So, the true statement is (d)

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Answer:

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Step-by-step explanation:

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B 4,8 new 2,4

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Answer:

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B = (2,4)

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D = (3,3)

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Filler and more filler

The area of  the square is 9 [tex]cm^{2}[/tex].

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Answers

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

Step-by-step explanation:

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------------------------------

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------------------------------

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Lastly, you need to find x on it's own so you have to divide by - 2.

Therefore, the answer would be x < -1.

Hope this helps :)

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Answers

The answer is

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