the base of an aluminum block, which is fixed in place, measures 90 x 90 cm. the height of the block is 60cm. a force, applied to the upper force and parallel to it, produces a shear strain of 0.0060. the shear modulus of aluminum is 3.0 x 10^10 pa. what is the displacement

Answer:

A quality of matter that is unrelated to a change in its chemical makeup is called a physical property.

Examples of physical properties of matter:

Physical properties are any qualities of matter that may be felt or seen without changing the sample's chemical composition.

Due to the wide range of features that make up physical attributes, they are further separated into intensive and extensive as well as isotropic and anisotropic categories.

Any characteristic that can be recognized and measured by sight, hearing, touch, smell, or other senses without evoking a chemical reaction is referred to as a physical property. Examples of physical traits are:

Color, Shape, Volume, Density, Calorific value, Boiling point, Viscosity, Pressure, Solubility, electrical current

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Both graphs of energy are attached in the answer.

The ability of a body to do tasks may be referred to as energy. The joule is the SI unit of energy (J). or 1 kJ Equals 1000 J. energy guises: Potential energy, kinetic energy, thermal energy, chemical energy, and light energy are some of the several types.

Potential energy of a man due to gravity can be express as = mass × acceleration due to gravity × height.

Hence, graph, that shows potential energy of a firefighter slides through the vertical pipe with length, will be linearly decreasing type.

As, total energy is conserved, graph, that shows kinetic energy of a firefighter slides through the vertical pipe with length, will be linearly increasing type.

Graphical representation of both linearly increasing and linearly decreasing is attached here.

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The best model according to vespr  model has the best arrangement of a given number of electron domains and is the one with less repulsion among the  electrons

The VESPR model is also known as VSEPR theory or valence shell electron pair repulsion theory. This model provides a three-dimensional structure for the arrangement of electrons within an atom. According to this model, valence shell electrons participate in chemical bonding processes. Molecular geometry shows that only valence shell electrons participate in ionic or molecular bonding.

The theory is based on the premise that repulsion between the pairs of valence electrons in all atoms and the atoms will always tend to arrange  themselves in a manner in which this electron pair repulsion is minimized

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Amplitude does not affect wave speed because amplitude is a measure of the wave energy as it oscillates. This implies that movement of the wave is separate from the movement indicated by the sleep of the wave.

By increasing the tension, the wave speed increases and hence frequency increases. Greater tension implies greater acceleration of particles, which means greater speed of particles and hence greater speed of wave.

As we know, speed = frequency * wavelength. This clearly means that speed is directly proportional to the frequency such that when frequency increases, speed also increases and vice versa.

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Answer:

Therefore the acceleration of the block is 6m/s.

Formula of Coefficient of friction= F/N

Force applied on the block =47N (Provided in the question)

Mass of the body=15kg (Provided in the question)

Normal force applicable on the body(N)=m x g

N= m x g

Where N represents the Normal Force, m the mass of the body and g represents the gravitational force.

N= 15 x 9.8

N=147N

When a force is applied on a body that is less than that of the Limiting force ( the maximum static friction that can be there) then the friction force produced as a reaction to that force is equal and opposite in nature, acting on the same body.

Since a 47N force is applied on the block a static friction force of the same value will pull the body in the opposite direction.

Thus force due to Friction=47 N

Coefficient of Friction= Friction/ Normal Force

Coefficient of friction =47/147

coefficient of friction=0.319

coefficient of friction≈0.32

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To determine the total number of microstates, we need to determine the density of states in one dimension. The density of states function (g(E)) is the number of microstates per unit length per unit energy range.

In one dimension for a particle of mass 'm' in a box of length 'L' we have the energy given
E: hk2 2

From the boundary conditions of the cuboid at x=0 and x=L, we deduce that 'k' can take on discrete values ​​in units of 2π/L. Consequently, the quantum states are in units of L/2π. The number of states 'N' for momentum 'k' will be equal to,

2KL N = TT

And the energy E at any momentum "k" is given by

E: hk2 2

The density of states in 1D is given by

9(E) 1 IN L DE = 1 DN dk L dk de

we know

NP 27 dk 1

AND,

hk DE Ε dk dk dЕ = m hk m

Notation in terms of energy E,

dk DE -m 1/2 E-1/2 -1/2

The density of states will be

9(E) 1 dN 1 dN dk IDE = I dk DE L L dE V2 m1/2E-12 πh

The total number of microstates at energy 'E' is,

2m Z(E) = [” 9(E)E = Z dE = E-1/2 DE 6.* -12dE = 22m VE ић пh

(i) A two-particle system will have the number of microstates will be,

Z(E) = 21(E1Z2E - E1)

where Z1 and Z2 are the microstates due to particle 1 and particle 2 calculated above. E1 is the energy of particle 1, so the energy of particle 2 is E-E1.

(ii) For indistinguishable particles, the number of microstates will be

Z(E) 21(E1)Z2(E – E1) 2!

​​​​where Z1 and Z2 are the microstates caused by particle 1 and particle 2, respectively, calculated as above. E1 is the energy of particle 1 and (E-E1) is the energy of particle 2. 2! it comes as a result of the fact that if we exchange two particles, due to their indistinguishability, the result will be the same.

E is the total energy of the system for both the above cases.

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The third snowman will be placed at a distance of 2.1m from the 15.0 kg mass such that the net gravitational force on it by the other two is zero .

Mass of the snowman 1 = M1 = 15 kg

Mass of the snowman 2 = M2 = 20 kg

Distance between both the masses = r = 4 m

Gravitational force is the force that attracts any two objects of mass.

where G is the gravitational force constant,

M1 and M2 are the masses of the two different bodies respectively,

r is the distance between the masses.

F = [tex]\frac{GM1M2}{r^{2} }[/tex]

Let the mass M3 be the mass which lies between the masses such that the net gravitational force on it by the other two is zero.

F = [tex]\frac{GM1M3}{(r-d)^{2} }[/tex]  = [tex]\frac{GM2M3}{(d)^{2} }[/tex]

here 'd' is the distance at which the mass M3 will be placed such that the net gravitational force on it by the other two is zero.

[tex]\frac{GM1M3}{(r-d)^{2} }[/tex]  = [tex]\frac{GM2M3}{(d)^{2} }[/tex]

[tex]\frac{M1}{(r-d)^{2} }[/tex]  = [tex]\frac{M2}{(d)^{2} }[/tex]

[tex]\frac{15}{(4-d)^{2} }[/tex]  = [tex]\frac{20}{(d)^{2} }[/tex]

3[tex]d^{2}[/tex] = 4[tex](4-d)^{2}[/tex]

3[tex]d^{2}[/tex] = 4 (16 + [tex]d^{2}[/tex] - 2*4*d)

3[tex]d^{2}[/tex] = 64 + 4[tex]d^{2}[/tex] - 32d

[tex]d^{2}[/tex] - 32d + 64 = 0

On solving the above quadratic equation we get the values of d as;

d1 = 29.

d2 = 2.1

Since the d is the distance between the two masses therefore it must be less than 4 m, therefore d2 will be considered as the value of d.

Hence the mass M3 should be placed at a distance of 2.1 m away from the mass M1 to get zero as the net gravitational force

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Answer:

1875 J

Explanation:

kinetic energy= [tex]\frac{1}{2}[/tex]×mass×velocity²

K.E=[tex]\frac{1}{2}[/tex]mv²

K.E=[tex]\frac{1}{2}[/tex]×150×5.0²

K.E= 1875 J

Acceleration: the rate at which the speed and direction of a moving object vary over time.A point or object going straight ahead is accelerated when it accelerates or decelerates.

Three different accelerated motion types exist: average acceleration, non-uniform acceleration, and uniform acceleration.

a = F / m

1 N = 1 kg•m/s²

F = ma; where F = force in newtons (N), m = mass in kg, and a = acceleration in m/s².

Known and Unknown

F = 3000 N = 3000kg•m/s²

m = 1200 kg

a = F/m

a = (3000 kg•m/s²)/(1200 kg)

Kilograms cancel.a =  2.5m/s²

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Answer:

2. The object must have zero average acceleration over the interval.

Explanation:

Notes:

-Velocity can have zero change if it is either at rest or moving at a constant velocity. This also means there is zero acceleration (acceleration is any change in velocity).

-Velocity is also speed and direction, so if it changes direction (for example: moving backward or in a circle) it is not constant even if it has a constant speed. It also means the object is accelerating.

1: Nothing can be determined without additional information.

Incorrect, because it is solvable by the process of elimination.

2: The object must have zero average acceleration over the interval.

Correct, because zero acceleration equals zero change in velocity.

3: The object must be changing position.

Incorrect, because you don't know whether or not the object is accelerating.

4:  The object must have zero average velocity over the interval.

Incorrect, because this implies it is at rest. To have zero change, it can be at rest OR moving at a constant velocity.

5:  The object must have constant velocity over the interval.

Incorrect, because zero change in velocity can mean either be at rest OR moving at a constant velocity.

6: The object must begin and end at the same position.

Incorrect, because to begin and end at the same position implies that it was at rest or it changed direction while moving to end at the same position. (see Notes above for explanation)

7: The object must have constant acceleration over the interval.

Incorrect, because you can't have zero change in velocity if there is acceleration (Acceleration is any change in velocity).

8: The object must be at rest.

Incorrect, because to have zero change, it can be at rest OR moving at a constant velocity.

The load of 1.8 N will give it an extension of 12cm.

Amount of force required to increase unit length of a spring is known as spring constant. Si unit of spring constant is Newton/meter.

Given parameters:

Loads on the spring; F₁ = 7.5 N.

Increase in length of the spring; x₁ = 50 cm = 0.5 m.

So, spring constant of it; k = F₁/x₁ = 7.5/0.5 N/m = 15 N/m.

Hence, to extent it of 12 cm; required load

= spring constant × increase in length

= 15 N/m × 12 cm.

= 15 N/m × 0.12 m.

= 1.8 N.

So, the required load is 1.8 N.

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Answer:Use Bungee Cord Power. Use the tension of bungee cords as opposed to springs to power your catapult.

Shoot From the Best Angle. Create an arm break that stops the arm at a 45-degree angle from the floor.

Explanation:

The magnification of this telescope is 12.

Solution:

F = 1200 mm = 120 cm

f = 32mm, 25mm, 14 mm, 10mm

M = F/f 120/ = 3.75

M = 120/25 =  4.8

M = 120/14 = 8.57

M = 120/10 = 12.

Magnification ratio means that the ratio of subject size on the sensor plane is greater than or equal to the actual size of the subject. This allows macro lenses to capture very sharp close-ups of insects, etc. The magnification produced by a lens is equal to the ratio of image distance to object distance. Total magnification In a compound microscope the total magnification is the product of the objective and ocular lenses.

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The force needed to bring a car to rest from a speed is 2,541 Newton.

The formula in non-uniform motion

v = u + at

v² = u² + 2ad

[tex]d = u \times t + \frac{1}{2} \times a \times t^2[/tex]

Because the final speed is km/h, we must convert it into m/s

v = 85.0 km/h

v = [tex]85.0 \times \frac{1 \: km}{1 \: hour}[/tex]

v = [tex]85.0 \times \frac{1,000 \: m}{3,600 \: s}[/tex]

v = [tex]\frac{850}{36}[/tex]

v = 23.6 m/s

Calculate the acceleration

v² = u² + 2ad

23.6² = 0² + (2×a×15)

556.96 = 230a

[tex]a = \frac{556.96}{230}[/tex]

a = 2.42 m/s

Formula to find the force F=ma

F = ma

F = 1,050×2.42

F = 2541 Newton

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Answer: (C)

Explanation:  (B) is the weight of the box acting downwards

(A) is the frictional force acting on the box because of moving forward against the plane

(D) is the force that moves the box forward

( C) is perpendicular to the box which means it is at 90 degrees with the box. Normal usually means at 90 degrees

Answer:

Light can travel through a glass or through a vacuum

Number of photons emitted per second are 2928.02×10²⁵

Photons, also called light quanta, are small energy packages of electromagnetic radiation. Photon energy depends on the frequency of the radiation. There are photons of all energies, from high-energy gamma rays and x-rays to visible light, low-energy infrared and radio waves. All photons travel at the speed of light. A photon, considered among sub-atomic particles, is a boson with no charge, no rest mass, and no spin unit. They are field particles that are thought to be carriers of the electromagnetic field.

For the given question:

Number of photons = power/energy

n = P/E

Power =  521 KW

Since energy is not given, we need to calculate it,

Using, E = h × f

Where, h = plank's constant (6.62607015×10⁻³⁴ J-Hz⁻¹)

f = frequency (849×10³ Hz)

Substitute the values in the equation for calculation of energy:

E = h × f

E = 6.62×10⁻³⁴ × 849×10³

E = 5620.38×10⁻³¹ J

E = 5.62×10⁻²⁸ J

Now, for number of photon:

n = P/E

n = 521×10³/5.62×10⁻²⁸

n = 2928.02×10²⁵ photons

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The angle of the rope makes with the vertical when the ball's kinetic energy is halved is 14.78°.

Parameter

When the ball is pushed horizontally and moves from point A to point B where the ball's kinetic energy halves, the law of conservation of energy applies.

Mechanical energy at A = Mechanical energy at B

Epa + Eka = Epb + EKb

Eka - Ekb = EPb - Epa

[tex]Ek_A -\frac{1}{2}Ek_A = mgh_B - mgh_A[/tex]

[tex]\frac{1}{2}Ek_A = mg \: (h_B - h_A)[/tex]

[tex]\frac{1}{2} \times \frac{1}{2} m v_A^2 = mgh[/tex]

[tex] \frac{1}{4} v_A^2 = gh[/tex]

[tex]gh = \frac{1}{4} \times 1.3^2[/tex]

gh = 0.4225

[tex]h = \frac{0.4225}{9.8}[/tex]

h = 0.043 m

Look at the picture

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Answer: As soon as it leaves the barrel.

Explanation:

A bullet fired from a rifle begins to fall immediately upon leaving the barrel. Despite its initial forward momentum, the bullet is subject to the force of gravity.

The gravitational force acts vertically downward and causes the bullet to accelerate downward due to its free fall. However, due to its initial high velocity, the bullet's downward acceleration is minimal compared to its forward motion. As a result, the bullet follows a curved trajectory known as a ballistic trajectory.

Over time, the effects of gravity become more significant, causing the bullet to gradually descend and eventually hit the ground, following a parabolic path.

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The base ball would have more acceleration than the bowling ball. Option C.

We know that from the Newton second law of motion, force is the product of the mass and the acceleration of an object. We can write that; F = ma

F = force

m= mass

a= acceleration

It is clear from the equation that we have shown above that the accaleration of the object does not only depend on the force but also on mass of the object. We can now write;

a = F/m

The higher the mass the lesser the acceleration of the object as we saw above.

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We cannot. The precise location of the electron cannot be predicted. The likelihood of where an electron will land can be predicted.

Only the likelihood of an electron being present at different sites can be predicted. The probability distribution can even tell you the average location of several electrons, but quantum theory cannot tell you the precise location of the electron. It can only give you a rough sense of where the one electron will end up.

The wave effectively splits into two new waves as it travels through both holes, each of which spreads out from a different slit. Then, there is interference between these two waves. A peak and a trough may occasionally cross paths where they cancel one another out.

The double-slit experiment, which was conducted to study the characteristics of light in the eighteenth century, has subsequently been found to illustrate the duality of photons as well as the ideas of superposition and quantum interference.

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Leveling the amount of work done at each work station is an example of Value Stream Mapping.

Value stream mapping was developed out of lean manufacturing, which companies use to create a visual guide of all the components required to deliver a product or service for the purpose of analyzing and optimizing the entire process.

The process of creating a value stream map takes all the people, processes, information, and inventory you need and presents them in flowchart form.

Learning core Lean Six Sigma (LSS) tools can help you become more attractive to new employers or increase the value you offer in your current workplace in a number of ways, including:

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A linear track beings at 0 meters and has a total distance of 100 meters, then she will go 55 meters. Hence, option D is correct.

The pace at which the distance a moving item travels changes is measured as speed. Since speed is a scalar, it has quantity but no orientation as a unit of measurement.

Let A represent Juliet's position. O is the starting point with OA = 10, AB = 45, and OP = 100 as its coordinates.

The location of Juliet following running 45 meters will therefore be 55 m, as may be seen from simple math. In the figure, it is OB.

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Your question is not complete, your question probably be :

A linear track begins at 0 meters and has a total distance of 100 meters to the finish line. Juliet starts at the 10-meter mar

while practicing for a race.

After running 45 meters, how far is she from the beginning of the track?

10 meters

35 meters

45 meters

55 meters

Answer:

Work = 196 Joules (1 kg*m^2/sec^2 is 1 Joule)

Explanation:

Work, W, is defined as force. F, times displacement, d.  

  W = Force*displacement

In the worker's case, the force he/she is struggling against is Earth's gravity's acceleration, g, (9.8 m/sec^2) times the mass, m.

Force = mg

Force = (10kg)*(9.8 m/sec^2) = 98 kg*m/sec^2

Use this force in the work calculation.

W = Force*displacement

The displacement is 2 meters.

Work = (98 kg*m/sec^2)*(2 meters) = 196 kg*m^2/sec^2

1 kg*m^2/sec^2 is 1 Joule

Work = 196 Joules

If the effective coefficient of friction was 0.40, the amount of work done required to move a 41.0-kg container 10.4 m of  a surface would be 1671.448 J.

Take into account "Friction" as the applied force on the box and "friction" as the force on by friction.

f = coefficient of friction*M* acceleration due to gravity

where 'M', 'N', and 'g' stand for the mass of the box, the normal force acting onto the block, and the acceleration acts on by gravity, respectively.

Since the people application of force does not cause the block to accelerate, we may write

F=0.4*41kg*9.8 = 160.72N;

the work required to move the box by a distance of s = 10.4 m is

Work done = Force *S

= 160.72*10.4 = 1671.448 J.

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A cosmic catastrophe jolts earth so that its axis is perpendicular to the orbital plane between earth and the sun therefore the largest effect of this change would be the elimination of seasonal variation.

This is referred to as the period of the year that is distinguished by special climate conditions and examples include winter, summer etc.

In a situation where a cosmic catastrophe results in it being perpendicular to the orbital plane between earth and the sun there will be no seasonal variation as a result of it hindering the effect of the sun and other factors.

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Answer: B. Energy

Explanation:

The Energy is the quantity that only depicts the magnitude and not the direction, hence it is a scalar quantity, so option B is correct.

In physics, energy is the capacity to do work. It might be potential, kinetic, thermal, electrical, chemical, radioactive, etc. Heat and work are further examples of energy being transferred from one body to another. Once it has been transmitted, energy is always allotted based on its nature. Thus, heat transmission could result in thermal energy while effort could produce mechanical energy.

The scalar quantity means they have only the magnitude and no direction. The velocity of any object tells the speed at which it is moving and its direction also, and the force applied to an object also tells the magnitude with direction, the momentum of an object is dependent on the force, so it is also a vector quantity

Therefore, Energy is the quantity that only depicts the magnitude and not the direction, hence it is a scalar quantity.

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The wise and economic use of energy sources is the best way of conserving existing energy sources because it ensures that energy sources that are not renewable such as petroleum are effectively managed so that they last for a longer time.

The conservation of resources refers to the various steps ad method employed to ensure that the existing resources are available for a long time and for future generations.

Conservation of energy sources involves effective and efficient use and management of energy sources so that they last longer. One way is the use of renewable energy.

One of the most important ways of the conservation of resources is the process of recycling to ensure that resources are reused.

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☆ Hello ☆

We first apply the data to the problem.

Data:

Then, we apply the formula that is.

Formula:

Finally we develop the problem.

Developing:

The distance traveled is 400 kilometers.

Uniform line movement

Rectilinear uniform motion is one in which an object moves in a straight line, it is a single direction, with a constant speed. When we speak of constant speed we mean that the movement maintains the same speed; that is, the object does not move faster or slower, always at the same speed.

We have that the data is:

Speed (V) = 80 km/h

Distance (d) = ?

Time (t) = 5 h

The formula for uniform motion is:

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V=\frac{d}{t} } \end{gathered}$} }[/tex]

We clear for the distance

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{d=v*t} \end{gathered}$} }[/tex]

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{d=80\ \frac{km}{\not{h}}*5\not{h} } \end{gathered}$}}[/tex]

[tex]\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{d=400 \ km} \end{gathered}$}}}[/tex]