The dosage for a certain drug calls for 20mg per kg per day and is divided into two doses(1every 12 hours) if a person weighs 197 pounds how much of the drug should be given each dose

Answers

Answer 1

Answer:

893.42

Step-by-step explanation:

1kg=2.205pounds

so 20mg is for 2.205pounds

therefore for 197pounds will be 1784.84mg

but the dose is once every 12hrs meaning twice a day so divide 1784.84/2 to get the pounds


Related Questions

[tex]\sqrt{x^{2} +5x+3} +2x^{2} +10x-15=0[/tex]

Answers

Factor√x²+5x+3+2x²+10x-15=0√x²+2x²+5x+10x+3-15=0√3x²+15x-12=0√3x²+(3(5x)+3×-4=0√3(x²+5x)+3×-4=0√3(x²+5x-4)=0

please mark this answer as brainlist

please answer the following question(math question)
don't spam​

Answers

Answer:

well hlo again ( ˘ ³˘)♥ (◍•ᴗ•◍)❤

find the common difference

Answers

9514 1404 393

Answer:

  (a)  1/12

Step-by-step explanation:

The difference of adjacent terms is ...

  1/4 -1/6 = 3/12 -2/12 = 1/12

The answer is 1/12!!!

Divide. Write your answer as a fraction in simplest form. −2 4/5÷(−7)=

Answers

the answer is in the photo

Answer:

2/5

Step-by-step explanation:

[tex] - 2\frac{4}{5} \div ( - 7)[/tex]

[tex] = \frac{2 \times 5 + 4}{5} [/tex]

[tex] = \frac{10 + 4}{5} [/tex]

[tex] = \frac{14}{5} [/tex]

[tex] = - \frac{14}{5} \times 7[/tex]

[tex] = \frac{14}{5} \div 7[/tex]

[tex] = \frac{2}{5} [/tex]

50 points and brainliest, please show your work :D (trying to learn so an explanation would be appreciated)

Answers

( a ) Well we know that the limit for the range is 400 dollars, as ( 1 ) her greatest balance was 400 dollars, and ( 2 ) the balance is dependent on the days, and hence represents the range. Respectively the limit for the domain would be 3 weeks.

( b ) Remember that B(0) models the balance over the course of 0 days. As you can see that starting mark is about half of the greatest balance on the graph, 400 dollars. Therefore you can estimate B(0) to be $200.

( c ) B(12) models the balance over the course of 12 days. It mentions that at B(12) the balance reaches $0, so in function notation that would be :

B(12) = 0

( d ) Segment 4 would represent that information. As you can see on the graph, the only time period with which the balance became 0 is represented by the fourth segment.

Combine the radicals. 2√24+5√54 A) 53√6 B) 5√6 C) 19√6 D) 93√6

Answers

Answer:

The answer is option C

Step-by-step explanation:

2√24 + 5√54

To combine the radicals first make sure the radicals have the same square root

That's

For 2√24

[tex]2 \sqrt{24} = 2 \sqrt{4 \times 6} = 2 \times 2 \sqrt{6} [/tex][tex] = 4 \sqrt{6} [/tex]For 9√54

[tex]5 \sqrt{54} = 5 \sqrt{9 \times 6} = 5 \times \sqrt{9} \times \sqrt{6} [/tex][tex] = 5 \times 3 \times \sqrt{6} [/tex][tex] = 15 \sqrt{6} [/tex]

Since they have the same square root we can combine them

That's

[tex]4 \sqrt{6} + 15 \sqrt{6} = (4 + 15) \sqrt{6} [/tex]

We have the final answer as

[tex]19 \sqrt{6} [/tex]

Hope this helps you

Will give Brainly
Find the probability that a
randomly
selected point within the circle falls
in the red shaded area.
60°
60°
r= 4 cm
[? ]%
Round to the nearest tenth of a percent.

Answers

Answer:

mate....where is red shaded region....

probably this will help ..... ;)

find the probability that a randomly selected point within the circle falls in the red shaded area

https://brainly.com/question/14113463?utm_source=android&utm_medium=share&utm_campaign=question

23^3 (-12)^3 +(-11)^3 without actually calculating cubes

Answers

Answer:

9108

Step-by-step explanation:

23^3+(-12)^3+(-11)^3                              remove parentheses

= 23^3-12^3-11^3                                  group difference of two cubes

= (23-12)(23^2+23*12+12^2) + 11^3      factor difference of two cubes

= 11 (23^2+23*12+12^2-11^2)                factor ou 11

= 11(23(23+12) + (12+11)(12-11))              apply difference of two squares

= 11 (23*35+23*1)                                  factor out 23

= 11(23*(35+1))                                       simplify

= 11*23*36                                             convert 11*23 into difference of 2 squares                                                                    

= (17^2-6^2)*6^2                                   expand parentheses

= 102^2-36^2                                       evaluate squares

= 10404 - 1296                                     subtraction

= 9108

(no calculator required)

Find the lateral surface area of the
following prism:
5 cm
5 cm
-apothem = 3.44 cm
5 cm
5 cm
10 cm
5 cm

Answers

Answer:

250 cm²

Step-by-step explanation:

Lateral area of the prism is,

5×10×5

= 250 cm²

Lateral surface area of the given prism is equals to [tex]250cm^{2}[/tex].

What is lateral surface area?

" Lateral surface area is defined as the sum of  area of the all the surfaces except top and bottom of the given geometrical shape."

Formula used

Lateral surface area of pentagonal prism [tex]=5ah[/tex]

[tex]a=[/tex] edge length of the base

[tex]h=[/tex] height of the prism

According to the question,

For the given pentagonal prism,

Edge length of the base [tex]'a' = 5cm[/tex]

Height of the prism [tex]'h' = 10cm[/tex]

Substitute the value in the formula of lateral surface area we get,

Lateral surface area of pentagonal prism [tex]= 5 \times 5\times 10[/tex]

                                                                      [tex]= 250cm^{2}[/tex]

Hence, lateral surface area of the given prism is equals to [tex]250cm^{2}[/tex].

Learn more about  lateral surface area here

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have two one-quart jars; the first is filled with water, and the second is empty. I pour half of the water in the first jar into the second, then a third of the water in the second jar into the first, then a fourth of the water in the first jar into the second, then a fifth of the water in the second jar into the first, and so on. How much water in quarts is in the first jar after the $10^{\textrm{th}}$ pour? Express your answer as a common fraction.

Answers

Answer:

water in quarts is in the first jar after 10th pour = 12/11

Step-by-step explanation:

Let X represent first jar and Y represents second jar.

have two one-quart jars; the first is filled with water, and the second is empty

Lets give the initial value of 2 to the first jar which is filled with water. Lets say there are two liters of water in first jar.

Lets give the initial value of 0 to the second as it is empty.

So before any pour, the values are:

X: 2

Y: 0

pour half of the water in the first jar into the second

After first pour the value of jar X becomes:

Previously it was 2.

Now half of water is taken i.e. half of 2

2 - 1 = 1

So X = 1

The value of jar Y becomes:

The half from jar X is added to second jar Y which was 0:

After first pour the value of jar Y becomes:

0 + 1 = 1

Y = 1

a third of the water in the second jar into the first

After second pour the value of jar X becomes:

Previously it was 1.

Now third of the water in second jar Y is added to jar X

1 + 1/3

=  (3 + 1)/3

= 4/3

X = 4/3

After second pour the value of jar Y becomes:

Previously it was 1.

Now third of the water in Y jar is taken and added to jar X so,

1 - 1/3

=  (3 - 1)/3

= 2/3

Y = 2/3

a fourth of the water in the first jar into the second

After third pour the value of jar X becomes:

Previously it was 4/3.

Now fourth of the water in the first jar X is taken and is added to jar Y

= 3/4 * (4/3)

= 1

X = 1

After third pour the value of jar Y becomes:

Previously it was 2/3

Now fourth of the water in the second jar X is added to jar Y

= 2/3 + 1/4*(4/3)

= 2/3 + 4/12

= 1

Y = 1

a fifth of the water in the second jar into the first

After fourth pour the value of jar X becomes:

Previously it was 1

Now fifth of the water in second jar Y is added to jar X

= 1 + 1/5*(1)

= 1 + 1/5

=  (5+1) / 5

= 6/5

X = 6/5

After fourth pour the value of jar Y becomes:

Previously it was 1.

Now fifth of the water in Y jar is taken and added to jar X so,

= 1 - 1/5

= (5 - 1)  / 5

= 4/5

Y = 4/5

a sixth of the water in the first jar into the second

After fifth pour the value of jar X becomes:

Previously it was 6/5

Now sixth of the water in the first jar X is taken and is added to jar Y

5/6 * (6/5)

= 1

X = 1

After fifth pour the value of jar Y becomes:

Previously it was 4/5

Now sixth of the water in the first jar X is taken and is added to jar Y

= 4/5 + 1/6 (6/5)

= 4/5 + 1/5

= (4+1) /5

= 5/5

= 1

Y = 1

a seventh of the water in the second jar into the first

After sixth pour the value of jar X becomes:

Previously it was 1

Now seventh of the water in second jar Y is added to jar X

= 1 + 1/7*(1)

= 1 + 1/7

=  (7+1) / 7

= 8/7

X = 8/7

After sixth pour the value of jar Y becomes:

Previously it was 1.

Now seventh of the water in Y jar is taken and added to jar X so,

= 1 - 1/7

=  (7-1) / 7

= 6/7

Y = 6/7

a eighth of the water in the first jar into the second

After seventh pour the value of jar X becomes:

Previously it was 8/7

Now eighth of the water in the first jar X is taken and is added to jar Y

7/8* (8/7)

= 1

X = 1

After seventh pour the value of jar Y becomes:

Previously it was 6/7

Now eighth of the water in the first jar X is taken and is added to jar Y

= 6/7 + 1/8 (8/7)

= 6/7 + 1/7

= 7/7

= 1

Y = 1

a ninth of the water in the second jar into the first

After eighth pour the value of jar X becomes:

Previously it was 1

Now ninth of the water in second jar Y is added to jar X

= 1 + 1/9*(1)

= 1 + 1/9

=  (9+1) / 9

= 10/9

X = 10/9

After eighth pour the value of jar Y becomes:

Previously it was 1.

Now ninth of the water in Y jar is taken and added to jar X so,

= 1 - 1/9

=  (9-1) / 9

= 8/9

Y = 8/9

a tenth of the water in the first jar into the second

After ninth pour the value of jar X becomes:

Previously it was 10/9

Now tenth of the water in the first jar X is taken and is added to jar Y

9/10* (10/9)

= 1

X = 1

After ninth pour the value of jar Y becomes:

Previously it was 8/9

Now tenth of the water in the first jar X is taken and is added to jar Y

= 8/9 + 1/10 (10/9)

= 8/9 + 1/9

= 9/9

= 1

Y = 1

a eleventh of the water in the second jar into the first

After tenth pour the value of jar X becomes:

Previously it was 1

Now eleventh of the water in second jar Y is added to jar X

= 1 + 1/11*(1)

= 1 + 1/11

= (11 + 1) / 11

= 12/11

X = 12/11

After tenth pour the value of jar Y becomes:

Previously it was 1.

Now eleventh of the water in Y jar is taken and added to jar X so,

= 1 - 1/11

=  (11-1) / 11

= 10/11

Y = 10/11

Answer:

6/11

Step-by-step explanation:

1/2 + (1/2)(2/11) = 6/11

sus

Can someone please help me with these 3 questions?

Answers

25) First, find the amount of minutes in 2 hours. Note that there are 60 minutes in one hour:

2 x 60 = 120 minutes per 2 hours.

Next, the bacteria doubles every 20 minutes. 120/20 = 6, which means that the bacteria will double 6 times:

1 x 2 = 2

2 x 2 = 4

4 x 2 = 8

8 x 2 = 16

16 x 2 = 32

32 x 2 = 64

64 bacteria will be your answer.

~

26) The Area of a circle = πr²

Set the equation:

400π = π(r + 2)²

First, divide common factors from both sides, or π.

(400π)/π = (π(r + 2)²)/π

400 = (r + 2)²

√400 = √(r + 2)²

r + 2 = √400

r + 2 = √(20 x 20)

r + 2 = 20

r + 2 (-2) = 20 (-2)

r = 20 - 2

r = 18

18 is your final answer.

~

27)

The volume of a box can be found by multiplying length x width x height:

[tex]V (box) = l * w * h[/tex]

The volume given is 90, the height 3, and the width is 1 foot less then length:

First solve what you know:

[tex]V(box) = 90\\h = 3\\l = l\\w = l - 1[/tex]

Plug in the corresponding terms with the corresponding variable. Isolate the variable, l. Divide 3 from both sides of the equation:

[tex]90 = 3 * l (l - 1)\\\frac{90}{3} = \frac{3 * l(l -1)}{3}\\30 = l(l - 1)\\[/tex]

Distribute l to both terms in the parenthesis:

[tex]30 = l(l - 1)\\30 = l^2 - l[/tex]

Solve:

[tex]30 = (6)^{2} -6\\30 = 36 - 6\\30 = 30[/tex]

∴ [tex]l = 6[/tex]

Solve for width. Width is 1 less foot then length:

[tex]l - 1 = w\\l = 6\\[/tex]

∴ [tex]6 - 1 = w\\w = 5[/tex]

Equation: [tex]V (box) = l * w * h[/tex]

or

[tex]l = \frac{V(box)}{w * h}[/tex]

[tex]V(box) = 90\\h = 3\\l = 6\\w = 5[/tex]

Find the standard deviation for the set of data.
{5,4, 18, 14, 22, 20, 6, 16, 12}

Answers

The Answer is 6.3245553203368.

Also if you can please answer my recent question.
That will Mean so much.

for the answer: The florist needs at least 1/3 gallons of nutrient rich water for each bushel of flowers he buys. If w is the gallons of water and f is the bushels of flowers, then:

w≥1/3f

I don't understand how you derive this equation.

Answers

Answer:

see below

Step-by-step explanation:

The phrase "at least" indicates that you use the symbol ≥, so that's where they got the ≥ from. The amount of water needed for each bushel is 1/3 * f or 1/3f because you need 1/3 gallons of water per one bushel. We know that the amount of water needed is at least 1/3 gallons per bushel. Since the amount of water is w, "at least" is ≥ and 1/3 gallons per bushel is 1/3f, the inequality is w ≥ 1/3f. I hope this makes sense.

Apply the distributive property to create an equivalent expression. ( 1 -2g +4h)\cdot 5 =(1−2g+4h)⋅5=left parenthesis, 1, minus, 2, g, plus, 4, h, right parenthesis, dot, 5, equals

Answers

Answer:

5 - 10g + 20h

Step-by-step explanation:

Given three elements A, B and C related together according to the expression A(B+C), according to distributive property, the element A will be distributed to the rest of the element as shown;

A(B+C) = A(B)+A(C)

A(B+C) = AB + AC (Law of distributivity)

Given the expression according to the question (1−2g+4h)⋅5, in order to use the distributive law to find the equivalent expression, we will use the concept above as shown;

= (1−2g+4h)⋅5

= 5.(1−2g+4h)

= 5(1)-5(2g)+5(4h)

= 5 - 10g + 20h

Hence the equivalent expression using the distributive property is 5 - 10g + 20h

Answer:

5 - 10g + 20h

Triangle A' B' C' is a dilation of a triangle ABC. The scale factor is [tex]\frac{3}{4}[/tex]. Point B is 11 inches away from the center of dilation is point B'?

Answers

Answer:

None of the options are correct

Step-by-step explanation:

Let us assume point B is at (x, y) and the center of dilation is at (a, b). Therefore the distance between the two points is:

[tex]Distance =\sqrt{(b-y)^2+(a-x)^2}=11 \\\\\sqrt{(b-y)^2+(a-x)^2}=11[/tex]

If Triangle ABC is then dilated by 3/4, the new coordinate is B'(3/4 (x-a) + a, 3/4 (y - b) + b). The distance between B' and the center of dilation would be:

[tex]Distance =\sqrt{(b-[\frac{3}{4}( y-b)+b])^2+(a-[\frac{3}{4} (x-a)+a])^2}[/tex]

Therefore the distance cannot be gotten until the center of dilation is given

Moly completes 3/10 of her science project in 4/5 hour

Answers

Answer:

1.5 per hour

Step-by-step explanation:

3/8 is the answer !!!!

If a+b+c = 0 then a3 + b3 + c3 is equal to
a.abc
b.0
c.3abc
d.9abc​

Answers

actually these question is lack of information. but for me i’ll go with b

please help me with these equations and please show the steps​

Answers

Answer:

I have explained the answer in detailed steps for you. If you do not understand any steps, please comment below, and I will help you out.

Which set is of whole numbers but not natural numbers?

Answers

Step-by-step explanation:

The set of Natural numbers: {1, 2, 3, 4, 5, ...}

The set of Whole numbers: {0, 1, 2, 3, 4, 5, ...} ← it has the number 0

Please help me with this trigonometry math question ASAP! Thanks so much!

Answers

Answer:

[tex]cos\alpha =\frac{7}{25}; \ tan\alpha =-\frac{7}{24}.[/tex]

Step-by-step explanation:

if π<α<2π and cotα<0, then 1.5π<α<2π. It means, that cosα>0 and tanα<0.

1) tanα=1/cotα; ⇒tanα= -7/24;

2) [tex]cos\alpha =\frac{1}{\sqrt{1+cot^2\alpha }}}; \ cos\alpha =\frac{7}{25}.[/tex]

Jorge walked 25 steps north. then he walked 75 steps south what is Jorges final position ​

Answers

Answer:

If Jorge goes up 25 (positive) and then goes 75 steps south (negative). Then you have to calculate 25-75. This equals -50. We know negative distance is south so he's final position will be 50 steps south.

Step-by-step explanation:

The square root of the product of two positive numbers is called their geometric mean. What is the geometric mean of 16 and 64?

Answers

Answer:

Geometric mean of a and b: Square root of axb.

16x64 = 1024

Square root of 1024: 32.

So, the geometric mean is 32.

Hope this helps!

Please answer this question now

Answers

Answer:

V = 60 m³

Step-by-step explanation:

Volume of Triangular Pyramid: V = 1/3bh

Area of Triangle: A = 1/2bh

b = area of bottom triangle (base)

h = height of triangular pyramid

Step 1: Find area of base triangle

A = 1/2(8)(5)

A = 4(5)

A = 20

Step 2: Plug in known variables into volume formula

V = 1/3(20)(9)

V = 1/3(180)

V = 60

6 less than twice a number

Answers

Answer:

6-2x

Step-by-step explanation:

six less than (subtraction) twice a number. 2 times a number x

A grocery store bought some mangoes at a rate of 5 for a dollar. They were separated into two stacks, one of which was sold at a rate of 3 for a dollar and the other at a rate of 6 for a dollar. What was the ratio of the number of mangoes in the two stacks if the store broke even after having sold all of its mangoes?

Answers

Answer:

The ratio of the number of mangoes in the $3 stack to those in the $6 stack is 1 : 2

Step-by-step explanation:

Let the number of mangoes bought by the grocery store be n. Also let the number of mango sold for $3 in one stack be x and the number of mango sold for $6 in the second stack be y.

Therefore:

x + y = z                                  (1)

Also, the mangoes was sold at break even price, that is the cost of the mango and the price it was sold for was the same. Therefore:

Cost of buying = Price it was sold for

The cost of the mango = 5z and the price it was sold for = 3x + 6y

3x + 6y = 5z                            (2)

Substituting z = x + y in equation 1

3x + 6y = 5(x + y)

3x + 6y = 5x + 5y

6y - 5y = 5x - 3x

y = 2x

x / y = 1/ 2 = 1 : 2

The ratio of the number of mangoes in the $3 stack to those in the $6 stack is 1 : 2

evaluate the following expressions if a = 2, b = 3, x = 4, y = 5

Answers

Answer:

18

Step-by-step explanation:

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

         ✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

                                        PEACE!

I WILL GIVE BRAINLEST PLEASE HELP
Which of the following is an example of the difference of two​ squares?
A x2−9
B x3−9
C (x+9)2
D (x−9)2
I know the answer is either A or B i might be wrong tho pls help im not sure.

Answers

Answer:

A

Step-by-step explanation:

In this question, we are concerned with selecting which of the options best represents the difference of two squares.

Let’s have an exposition below as follows;

Consider two numbers, which are perfect squares and can be expressed as a square of their square roots;

a^2 and b^2

where a and b represents the square roots of the numbers respectively.

Inserting a difference between the two, we have;

a^2 - b^2

Now by applying the difference of two squares, these numbers will become;

a^2 - b^2 = (a + b)(a-b)

So our answer out of the options will be that option that could be expressed as above.

The correct answer to this is option A

Kindly note that;

x^2 -9 can be expressed as x^2 - 3^2 and consequently, this can be written as;

(x-3)(x + 3)

I need help I need help

Answers

Answer:

[tex]{ \boxed{ \bf{c}}} \: \: \frac{3.8}{4} = s[/tex]

Step-by-step explanation:

[tex]{ \tt{4 \: pies \: = \: 3.8 \: ounces}} \\ { \tt{1 \: pie \: = \: ( \frac{1}{4} \times 3.8) \: ounces}} \\ { \tt{ = 0.95 \: ounces}}[/tex]

[tex]{ \underline{ \sf{ \blue{christ \: † \: alone}}}}[/tex]

the probability of getting an ace or a King from a pack of 52 cards is :
1/4
2/13
5/13
6/13​

Answers

Answer:

2/13

Step-by-step explanation:

Cdgfsggdehfetgfrhfer

Answer: 2/13

Explanation:

As there are 4 aces and 4 kings in a pack of cards:

(4 + 4)/52 = 8/52 = 2/13

A car is traveling on a highway. The distance (in miles) from its destination and the time (in hours) is given by the equation d = 420 minus 65 t. What is the practical meaning of the d-intercept? a. Initially the car is 355 miles from its destination. b. Initially the car is 420 miles from its destination. c. Initially the car is 65 miles from its destination. d. Initially the car is 485 miles from its destination.

Answers

Answer:

the correct answer is b. Initially the car is 420 miles from its destination.

Step-by-step explanation:

Other Questions
someone please help me with this question Geometry - Triangle d) In the given figure, BE = EC and CE is the bisector of ZACB. Prove that ZBEC = ZACD. E B D look at the image below 12 2x= -2(y x)-2x = -2(y x) 12x= (y - x) + 6 Which point is located at (5, 2)? In this module, you learned about the risks or costs associated with financial goals. What are the risks or costs associated with your goal, and how can you overcome these challenges compare the values of the 7s in the number 4,877,034 A wave has a frequency of 5 Hz and a wavelength of 0.5 m, what is the speed of this wave? Imagine that you plan to write a procedural document. What question shouldyou ask yourself to ensure that you address your audience correctly?A. Which topic interests me most?B. What type of media should I use to illustrate my topic?C. How much are my readers likely to know about my topic?D. What kinds of sources should I use to research my topic? what is the change in each term of the sequence? 0.8, 1, 1.2, 1.4, 1.6 The frequency table categorizes winners of a prestigious award from.1990-2012 by their age at the time they received the award. Gii h mnh vi ,mnh cm n Jorges monthly bill from his Internet service provider was $25. The service provider charges a base rate of $15 per month plus $1 for each hour that the service is used. Find the number of hours that Jorge was charged for that month. I really need help with this apples are on sale for $3 and 12 per kilogram is the total cost of the apples proportional to the total yes or no I copied the problem Assignment: Quote Analysis Essay to kill a mockingbird Brainliest if you can help me!! Academic sources should be from a primary source be from a secondary source have references to both primary and secondary sources have references to neither primary nor secondary sources A piece of unknown metal weighs 500 g. When the piece of metal absorbs 6.64 kJ of heat, its temperature increases from 25C to 78C. What's the specific heat capacityof this metal?A. 13 J/gCB. 0.25 J/gCC. 25 J/gCD.2.5 J/g C