The driver of a car traveling at 38.7 m/s applies the brakes and undergoes a constant
deceleration of 2.41 m/s. How many revolutions does each tire make
before the car comes to a stop, assuming that
the car does not skid and the tires have
radii of 0.18 m?
Answer in units of rev.

Answers

Answer 1

Each tire makes 274.9 revolutions before the car comes to a stop.

How to calculate?

We will calculate the distance covered for by the car after the brakes are applied. We will apply the following equation of motion:

V^2=U² +2as where V is the final velocity, U is the initial velocity, a is the acceleration and s is the distance covered during that acceleration.

0=(38.7)² -2* 2.41 *S (This negative because it is decelerating).

0 = 1497.69 - 4.82* S

S = 310.72

Circumference of the tire = 2πr where r is the radius.

Circumference = 1.13

Distance / circumference = Number of revolutions.

Number of revolutions. =310.72 / 1.13

Number of revolutions = 274.9

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Related Questions

draw a block diagram of the components for an elevator-position control. indicate how you would measure the position of the elevator car. consider a combined coarse and fine measurement system. what accuracies do you suggest for each sensor?

Answers

In feedback control, the variable being controlled is measured and compared with a target value.

what accuracies do you suggest for each sensor?

The accuracy of the sensor is the maximum difference that will exist between the actual value (which must be measured by a primary or good secondary standard) and the indicated value at the output of the sensor. Again, the accuracy can be expressed either as a percentage of full scale or in absolute terms.For example, if a pressure sensor with a full scale range of 100 psi reports a pressure of 76 psi – and the actual pressure is 75 psi, then the error is 1 psi, and when we divide this by the full scale and express it as a percentage, we say that accuracy (or error) of the sensor is 1%.For the classification of a force sensor in accuracy class 0.5, the temperature-induced drift of the zero signal over a temperture range of 10 ° C should be less than 0.5% of the characteristic value of the sensor. With a characteristic value of 1 mV/V (FS, "Full Scale"), this means a maximum drift of 0.005 mV/V/10°C.

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Does kinetic energy increases or decreases?

Answers

kinetic energy can increase, decrease or stay constant depending on the motion of the object and the forces acting upon it.

Kinetic energy can increase or decrease depending on the motion of an object and the forces acting upon it. If an object is moving and is acted upon by a force that increases its velocity, such as an external force or the force of gravity, the kinetic energy of the object will increase. For example, if a car is pushed from a standstill, its kinetic energy will increase as it moves faster. On the other hand, if an object is moving and is acted upon by an opposing force, such as friction or air resistance, the kinetic energy of the object will decrease as it slows down. For example, if a car is driving on a road with friction and it needs to stop, the kinetic energy of the car will decrease as it slows down. In addition, if an object is moving at a constant velocity, the kinetic energy of the object will also be constant.

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017 (part 2 of 2) 10.0 points
Leaving the distance between the 313 kg and
the 536 kg masses fixed, at what distance from
the 536 kg mass (other than infinitely remote
ones) does the 39.3 kg mass experience a net
force of zero?
Answer in units of m.

Answers

The distance of 39.3 kg mass from 536 kg mass will be .0567d to have zero force of attraction.

What is Gravitational Force ?

The force of attraction between any two bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.

If the cannon is fired after being filled with gunpowder, the following situations could occur.

The gun will fall to Earth in a projectile motion if its speed is low.The cannonball will continue to circle the Earth in a constant orbit if, at that precise height, its speed is equal to the orbital speed.The cannonball maintains an elliptical orbit around the Earth if its speed is more than the orbital velocity but insufficient to escape from it, that is, lower than the Earth's escape velocity.The projectile departs the Earth on a parabolic or hyperbolic trajectory if the speed is equal to escape velocity or greater.

The masses are

m₁ = 313 kg

m₂ = 536 kg

m = 39.3 kg

So as per sum if the distance between m₁ and m₂ is d and distance between m and m₂ is s then

The gravitational force between m₁ and m is equal to gravitational force between m and m₂.

[tex]\frac{G*m\x_{1} *m }{(d-s)\x^{2} } =\frac{G*m\x_{2} *m }{s\x^{2} }[/tex]

⇒ m₁* s² = m₂ * (d-s)²

⇒313s² = 536d² - 1072ds + 536s²

⇒223s² + 536d² - 1072ds = 0

⇒ s = 0.567d

The distance of 39.3 kg mass from 536 kg mass will be .0567d to have zero force of attraction.

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Please help me.... ASAP

Answers

Answer:

True

Explanation:

what are three reasonable ways the experimenter could improve upon these measurements using the same apparatus, in order to reduce the uncertainty in the resulting period values?

Answers

Test and Collect Data, Select a Better Calibration Laboratory, Remove Bias and Characterize could be three reasonable measures

For any experiment, a need to keep in mind that the data that you collected must be tested or verified which means for the best answer one needs to get the best or clear input that is input in the case of experiments. And collect relevant data only for the output to preside.

The second way could be the workplace or laboratory need to be a calibration Laboratory so the experiments could be conducted without ant external disturbance along with the required equipment to make the work easy and faster.

last but not least one need to select unbiased and characterized types of equipment which reduce the margin of error from the output we are providing

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What is the kinetic energy at the lowest point?

Answers

Potential energy is zero and maximum at the lowest point, whereas kinetic energy is zero and maximum. The amount of energy is influenced by mass or not.

It is possible to observe kinetic energy, sometimes referred to as the energy of motion, in the motion of objects and subatomic particles. All moving objects and particles contain kinetic energy. A human walking, a baseball soaring through the air, food tumbling off a table, and a charged particle in an electric field are all examples of kinetic energy in operation. One way to compute kinetic energy is as follows: K.E. is defined as the ratio of m/v2, or the square of an object's mass and velocity. If the mass is measured in kilogrammes and the velocity is measured in metres per second, the kinetic energy is expressed as kilogram-meter squared per second squared.

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Which of the following statements about independent and dependent variables is accurate? (Choose all that apply)

a. The independent variable is manipulated by the scientist.

b. Both the independent and dependent variables are mentioned in the hypothesis.

c. Experiments test for a relationship between the independent and dependent variable.

d. The independent variables are held constant during an experiment.

e. The dependent variable will never change during the experiment.

Answers

The independent variables are held constant during an experiment. Hence, option (d) is correct.

What are  independent and dependent variables ?

In mathematical modelling, statistical modelling, and experimental sciences, there are dependent and independent variables.

Dependent variables get their name because, during an experiment, their values are examined under the assumption or requirement that they are dependent on the values of other variables due to some law or rule (for example, a mathematical function).

In the context of the experiment under consideration, independent variables are those that are not perceived as dependent on any other factors.

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a 325 kg satellite is in circular orbit around earth. if the orbital altitude of the satellite is 575 km, what is the speed of the satellite

Answers

To calculate the speed of the satellite, we can use the formula for centripetal force:

F = (mv^2) / r

Where:

F = centripetal force (Newtons)

m = mass of the satellite (kg)

v = velocity of the satellite (m/s)

r = radius of the orbit (m)

We know that the centripetal force is provided by the gravitational force between the satellite and the Earth, and the gravitational force can be calculated using the formula:

F = G(m1m2)/r^2

Where:

G = gravitational constant (6.674 x 10^-11 N*m^2/kg^2)

m1 = mass of the satellite (kg)

m2 = mass of the earth (5.972 x 10^24 kg)

r = distance from the centre of the Earth to the satellite (m)

So we can combine the two equations above to get:

mv^2/r = G(m1m2)/r^2

Now we know that the radius of the orbit is the distance from the centre of the Earth to the satellite, which is (6371 + 575) km = 6946 km, so we can convert it to meters:

r = 6946 x 10^3 m

We also know that the mass of the satellite is 325 kg.

So we can substitute the known values into the equation and solve for v:

v^2 = G(m1m2)/r

v = (G(m1m2)/r)^0.5

v = (6.674 x 10^-11 x (325 x 5.972 x 10^24))^0.5 / (6946 x 10^3)

v = 7.711 x 10^3 m/s

Therefore, the speed of the satellite is 7.711 x 10^3 m/s (rounded to the nearest whole number).

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Schools can ensure certain rights, accommodations and supportive measures only for victims who report the incident to law enforcement.

Answers

The given statement is false. Schools should ensure rights, accomodation and supportive measures for all the victims whether they have reported the incident or not.

Colleges are required to safeguard the rights of sexual assault victims and make specific concessions. Campus SaVE mandates that establishments offer survivors fair accommodations and safety precautions whether or not they choose to contact law police. Sexual assault and harassment are vices that frequently occur in educational settings. Every school needs to have a process or department in place to handle complaints from those who have been the victims of sexual offenses.

All of a school's activities or programs for teaching fall under this category. This means that regardless of whether the programs are held on school property or elsewhere, Title IX safeguards students in connection with all academic, instructional, extracurricular, sports, and other activities.

In response to the query, schools are required to guarantee specific rights, accommodations, and protective measures for sexual assault victims—and not just in cases when they decide to notify law enforcement.

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The complete question is

Schools must ensure certain rights, accommodations

and protective measures for sexual assault victims

only if they choose to report to law enforcement.

True

False

New traits usually occur due to an organism adapting, random genetic mutations, effects from the environment.

Answers

New traits usually occur in an organism or a population due to random genetic variations or mutations. Thus, the correct option is B.

What are Mutations?

A mutation is a change in the genetic material that occurs in the DNA  (deoxyribonucleic acid) sequence, either due to the mistakes when the DNA is being copied or as the result of the environmental factors such as UV (Ultraviolet) light and cigarette smoke.

Genetic variations in an organism can arise from the gene variants also called as mutations or from a normal process in which the genetic material is rearranged as a cell is getting ready to undergo division known as genetic recombination. Genetic variations which alter gene activity or the protein function can introduce different traits in an organism or a complete species.

Therefore, the correct option is B.

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a second magnitude star in ursa major is brighter than a fourth magnitude star in orion. TRUE OR FALSE

Answers

It is true that a second-magnitude star in Ursa Major is brighter than a fourth-magnitude star in Orion. Hence, the given statement is true.

The star, Sirius is the star with the brightest apparent magnitude as measured on the modern magnitude scale. The star has been assigned a magnitude of −1.5. There are many other objects in the sky that can appear even brighter than the Sirius star.

So the angle between the northern horizon and the northern celestial pole is the same as the angle of latitude. Hence the angle between the northern horizon and the northern celestial pole will be 40 degrees.

The brightest star in the sky according to the ancient magnitude scale is the first-magnitude star. The dimmest star that is visible to the eye is categorized as the sixth magnitude star. Therefore a second-degree star is bright but less bright than a first-magnitude star.

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What is on the Physics module 4 DBA?

Answers

I was asked to describe my house by my teacher (how many bedrooms & bathrooms stuff like that).

Describe physics.

Physics is the study of the interaction between the fundamental components of the universe and the composition of matter. General relativity is applied to examine everything in the universe, while quantum mechanics is utilized to study incredibly small objects.

Physics applications.

Engineering frequently utilizes physics. For instance, the construction of bridges as well as other static structures uses statics, a branch of mechanics. Better music halls and sound control are produced by an understanding of and application of acoustics, just as improved optical systems are produced by an application of optics.

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you measured the mass of three different volumes of water. what was the total mass of the graduated cylinder and the water for the three measurements? choose the masses that are closest to the observed values.

Answers

The total mass of the graduated cylinder and the water for the three measurements would be 120g.

What is mass?

Mass is the physical property of a body which determines its resistance to acceleration when a net force is applied. It is measured in kilograms (kg) or pounds (lbs) and is proportional to the amount of matter the body contains. Mass is an intrinsic property of matter, meaning it cannot be altered by changing the shape, size or temperature of a body. Mass is often confused with weight, which is the measure of the gravitational force on an object, and should not be used interchangeably.

The total mass of the graduated cylinder and the water for the three measurements would depend on the individual masses of each measurement. For example, if the measurements were 10mL, 20mL, and 30mL of water respectively, the total mass of the graduated cylinder and the water would be the sum of the individual masses. Assuming the density of the water is 1g/mL, the total mass of the graduated cylinder and the water for the three measurements would be 40g. If the measurements were 20mL, 40mL, and 60mL of water respectively, the total mass of the graduated cylinder and the water for the three measurements would be 120g.

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Why the speed of pendulum is highest at mean point?

Answers

The speed of a pendulum is highest at the mean point because at this point the pendulum has the greatest potential energy. As the pendulum swings back and forth, potential energy is converted to kinetic energy at the mean point, leading to the highest speed.

The pendulum is at its highest point in its swing and has the most potential energy at the mean position. This potential energy is transformed into kinetic energy, the energy of motion, when it starts to swing downward. The kinetic energy increases with potential energy, increasing speed as a result. Because of this, the mean point is where the pendulum swings at its fastest. In addition, air resistance and friction have a greater impact as the pendulum approaches the extremities of its arc, slowing it down. The pendulum's maximum speed is reached at the mean point in part because of this.

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Help ASAP!
Which statement is true because of Newton's second law?

a.
When the net force on an object increases, the object's acceleration decreases.


b.
When the net force on an object decreases, the acceleration doesn't change.

c.
When the net force on an object decreases, the object's acceleration increases.


d.
When the net force on an object decreases, the object's acceleration decreases.

Answers

Answer:

When the net force on an object decreases, the object's acceleration decreases.

Explanation:

i know

which property is unique to electromagnetic waves?

Answers

The frequency is a fundamental property of electromagnetic waves. According to Maxwell, a magnetic field develops when the electric field changes.

A time-varying magnetic field is created by an accelerated charge, which then creates a time-varying electric field.

They can move across the water's surface. The gravitational force over them can control them. Structures on Earth can be shook by them. They are capable of travelling in a hoover. Any electromagnetic wave moves at the same constant speed of light. Other characteristics, like frequency, energy, and wavelength, depend on the kind of wave and the source that is creating it. But the speed doesn't change. It is made up of perpendicular time-varying electric and magnetic fields that are both perpendicular to the direction and to each other.

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what is the maximum speed for a car rounding a 125 m curve on a highway under very icy (no friction) conditions if the banking angle is 20.0o.

Answers

the maximum speed for a car rounding a 125 m curve on a highway under very icy (no friction) conditions if the banking angle is 20.0 is  70.3 km/h.

If a car is driving on a highway with a banking angle of 20.0o and icy (no friction) conditions, the maximum speed it can reach while rounding a 125 m curve is determined by the following calculations:

The maximum centripetal acceleration (a) is equal to the gravitational acceleration (g) multiplied by the sine of the banking angle (θ). In this case, a = g * sin(20.0o) = 9.8 m/s2 * 0.3420201433 = 3.36 m/s2.

The maximum speed (v) is then equal to the square root of the maximum centripetal acceleration (a) multiplied by the radius of the curve (r). In this case, v = √(3.36 m/s2 * 125 m) = 19.6 m/s = 70.3 km/h.

Therefore, the maximum speed a car can reach while rounding a 125 m curve on a highway under very icy (no friction) conditions if the banking angle is 20.0o is 70.3 km/h.

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The coordinates of a bird flying in the xy-plane are given by x(t) = αt and y(t) = 3. 0 m - βt2, where α = 2. 4 m/s and β = 1. 2 m/s2. (a) Sketch the path of the bird between t = 0 and t = 2. 0 s. (b) Calculate the velocity and acceleration vectors of the bird as functions of time. (c) Calculate the magnitude and direction of the bird’s velocity and acceleration at t = 2. 0 s. (d) Sketch the velocity and acceleration vectors at t = 2. 0 s. At this instant, is the bird’s speed increasing, decreasing, or not changing? Is the bird turning? If so, in what direction?

Answers

The velocity vector of the bird as a function of time 2.4√1+ t².  The velocity and acceleration vectors of the bird as functions of time v = 5.367 m\s

Evaluating the velocity vector :

x (t) =[tex]\alpha[/tex] t

dx /dt = [tex]\alpha[/tex]

The x-component is, dx/dt = [tex]\alpha[/tex]

y(t) = 3. 0 m - βt²

dy/dt = - 2βt

The y-component is , dy/dt = -2βt

Now we must compute the bird's velocity vector as a function of time.

vector V = √x² + y²

When we now incorporate the values of the x- and y-components into this equation, we obtain,

Vector V = √x² + y²

                  = √[tex]\alpha[/tex]² +( -2βt )²

                  = √(2.4)² + ( -2 × 1.2 × t)²

                = 2.4 √1 + t²

B.             x'' (t) = 0

                 y''(t) = - 2.4

α =  x'' (t) , y''(t)

        = ( 0 , 2.4 )

C.                 t = 2 sec.

        |v| = √2.4² + ( -2.4 × 2)²

                 v = 5.367 m\s

D. Taking from a

tan θ = - t = -2

t = 2

θ = 360 ° - 63.43

= 297°

2. at this instant , the bird speed is increasing , the bird is turning in vertical axis .

Vector velocity :

The rate of an object's position change is represented by a velocity vector. A velocity vector's magnitude indicates an object's speed, while the vector's direction indicates its direction. The principles of vector addition can be used to add or subtract velocity vectors. magnitude of a vector's velocity.

Exactly why is velocity a vector?

Because velocity has magnitude as well as direction, it is a vector quantity. Speed, on the other hand, is a scalar quantity because it only has a magnitude and no direction.

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Note: Take East as the positive direction. A(n) 89 kg fisherman jumps from a dock into a 135 kg rowboat at rest on the West side of the dock. If the velocity of the fisherman is 5.2 m/s to the West as he leaves the dock, what is the final velocity of the fisherman and the boat? Answer in units of m/s. Answer in units of m/s.

Answers

The final velocity of the fisherman and the boat is 2.06 m/sec.

What is meant by velocity?The directional speed of an item in motion, as measured by a specific unit of time and viewed from a certain point of reference, is what is referred to as velocity.The displacement that an object or particle experiences with respect to time is expressed vectorially as velocity. The metre per second (m/s) is the accepted unit of velocity magnitude (also known as speed).The vector quantity velocity (v), denoted by the equation v = s/t, quantifies displacement (or change in position, s), over change in time (t).Velocity is the pace and direction of an item's movement, whereas speed is the time rate at which an object is travelling along a route. In other words, velocity is a vector, whereas speed is a scalar number.

Given data :

We have given mass of the fisherman [tex]m_{1}[/tex] = 89 kg

Velocity of fisherman v = - 5.2 m/sec ( As east direction is positive direction )

Mass of the rowboat [tex]m_{2}[/tex] = 135 kg

As the rowboat is at rest so [tex]v_{2}[/tex] = 0 m/sec

Now according to conservation of momentum

[tex]m_{1}[/tex] [tex]v_{1}[/tex] + [tex]m_{2}[/tex][tex]v_{2}[/tex]  = ( [tex]m_{1}[/tex] + [tex]m_{2}[/tex] ) v

89 x 5.2 + 135 x 0 = ( 89 + 135 ) x v

462.8 + 0 = 224 x v

v = 462.8/ 224 = 2.06 m/sec

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what does the electronic stability control system designed to do?

Answers

Electronic stability control system designed to prevent lose control of the vehicle in the high speed and skidding when cornering at high speed.

What is  the electronic stability control system?

electronic stability control system or ESC system also called as dynamic stability control or electronic stability program is a computerized technology which increases a vehicle's stability by reducing and detecting loss of traction. ESC is proven to be effective in decreasing roll over crashes and the accident of single vehicle. Vehicles equipped with ESC are   told has 32% lower single-vehicle crashes and 58% lower roll-over crashes that cause in driver injury.

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A flask containing 125 mL of hexanes is boiled at about 342 K. What happens during this process? The boiling point of hexanes is 68.73 °C. A. All IMFs break and the solvent vaporizes. B. IMFs are formed and the solvent condenses. C. MFs are formed and the solvent vaporizes. D. All IMFs break and the solvent condenses.

Answers

During the process all IMFs break and the solvent vaporizes.

During the boiling process, the solvent (hexanes) reaches its boiling point (68.73 °C) and vaporizes, meaning it changes from a liquid to a gas. The boiling point of a liquid is the temperature at which its vapor pressure is equal to the atmospheric pressure. The solvent molecules need to gain enough energy to overcome the intermolecular forces (IMFs) between them to change phase from liquid to gas. The process of vaporization requires an input of energy, which is supplied by heat. The heat energy provided causes the solvent molecules to absorb enough energy to overcome the IMFs, and the solvent vaporizes.

IMFs are the forces that hold the molecules of a substance together, and these forces are weaker in gases than in liquids. When the solvent vaporizes, the IMFs between the solvent molecules are broken, and the solvent molecules move freely in the gaseous state. So, in this case, during the boiling process, all IMFs break and the solvent vaporizes.

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microscope objectives stay relatively in focus when magnification is changed. ?
a. parfocal
b. field of view
c. resolution
d. lowest

Answers

Answer: Parfocal will be the answer.

Explanation:

What happens to velocity when air resistance is ignored?

Answers

When air resistance is ignored, the velocity of an object remains constant in the absence of any other forces. This is known as free fall motion and is described by the equation of motion v = v0 + at, where v0 is the initial velocity, a is the acceleration due to gravity (g = 9.8 m/s^2), and t is time.

When air resistance is ignored, the velocity of an object remains constant in the absence of any other forces. This is known as free fall motion and is described by the equation of motion v = v0 + at, where v0 is the initial velocity, a is the acceleration due to gravity (g = 9.8 m/s^2), and t is time. If an object is dropped from a height, its velocity will increase with time until it reaches its maximum velocity at the point of impact with the ground. The velocity will remain constant in the absence of air resistance and other forces, such as friction, which can cause the velocity to decrease. In real-world scenarios, air resistance is a significant force that must be taken into account when calculating the motion of an object, especially at high speeds.

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Discovering outer space had been an ancient goal of humanity. The first rocket launched ever was by the
American college professor and scientist Robert Goddard who built and flew the world's first liquid propellant
rocket on March 16, 1926. Its flight, though unimpressive (it climbed only 12.5 meters), was the forerunner of
the Saturn V Moon rocket 43 years later. Answer the following question using your math and science skills.
While launching a rocket into space, the rocket thrust (force) is calculated to be 20,000 N.
OOD
a) The mass of the rocket is approximately 3,000 kg, what would be the acceleration of the launched rocket?
b) The rocket starts from rest, what would be the final speed after 5 min?

Answers

The earliest known observations of the night sky date back to ancient civilizations such as the Babylonians, Egyptians, and Chinese, who recorded the positions of stars, planets, and other celestial bodies.

Explain about goal of humanity:Discovering outer space has been a goal of humanity for centuries. Throughout history, people have looked to the stars with a sense of wonder and curiosity, trying to understand the nature of the universe. a) To calculate the acceleration of the launched rocket, you can use the formula:However, it wasn't until the 20th century that humans were able to physically explore space. With the development of rocket technology, scientists were able to launch spacecrafts beyond Earth's atmosphere, allowing for the study of celestial bodies and the exploration of the Solar System and beyond.

a = F / m

where F is the force (thrust) acting on the rocket and m is the mass of the rocket.

In this case, F = 20,000 N and m = 3,000 kg

So, a = 20,000 N / 3,000 kg = 6.67 m/s²

b) To calculate the final speed of the rocket after 5 minutes, you can use the formula:

v = a * t

where v is the final speed, a is the acceleration and t is the time.

In this case, a = 6.67 m/s² and t = 5 minutes = 300 seconds.

So, v = 6.67 m/s² * 300 seconds = 2,001 m/s

It's worth noting that the acceleration and final speed calculations are assuming that the rocket thrust is constant during the entire flight, which is not the case in reality, thrust changes during different stages of the rocket's flight.

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the earth completes a circular orbit around the sun in one year. the orbit has a radius of 93,000,000 miles. what is the speed of the earth around the sun in m/s? Report your result using scientific notation.

Answers

Answer:

29,800.85 m/s or 2.98 x 10^4

Explanation:

1 mile is 1609.34 Meters

1 year is 31,536,000 seconds

1609.34 x 93,000,000 = radius in meters= 149,668,620,000

2 x pi x r = circumference and or distance traveled

2 x pi x 149,668,620,000

distance traveled / time it takes to travel the distance = speed or velocity

940,395,674,129.84 / 31,556,000 = 29,800.85 m/s or 2.98 x 10^4

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(Only If You Answer Properly)


An enormous amount of electricity is created at power-generating stations and sent across the country through wires that carry high voltages. Appliances, power lines, airport and military radars, substations, transformers, computers, and other equipment that carries or uses electricity all generate electromagnetic fields. Many questions have been raised about how electromagnetic fields affect our bodies. Do they pose a public health risk? Perform an Internet search to find information about the effects of electromagnetic fields on public health. Then, discuss the pros and cons of using equipment that produces an electromagnetic field

Answers

The human person and electromagnetic fields both have their benefits and drawbacks. They do present a threat to public health. Power plants produce a tremendous amount of electricity.

How do magnetic fields work?

When an electrically charged object moves through space, it receives a magnetic force in the magnetic field. The coil becomes magnetised when current passes through the circuit. A straight wire's magnetic field in an electrical circuit is weaker than a coiled wire's magnetic field.

Power plants produce a tremendous amount of electricity, which is then sent across the nation on high-voltage cables. Electromagnetic fields are produced by appliances, power lines, radars used by the military and airports, substations, transformers, computers, and other electrically powered machinery. Scientists have shown that our well-being is actually influenced by the earth's electromagnetic climate. Since there are so many objects in our daily lives that produce electromagnetic fields, it is challenging to avoid them.

Learn more about the Electromagnetic field.

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A uniform meter rule of Mass 150 gram is balanced on a knife edge at x meter From a Mass OF 50 gram Suspended at the 0.1m mark Find the position X of the Knife edge​

Answers

If the mass of meter rule is given then the ans is  50cm automatically cuz thats the point when the mass of the meter rule adds up.

Find the position X of the Knife edge​?

Given:

x - the mark on the ruler where the knife edge is

M - mass of the ruler

m - mass of the object attached to the ruler

a - the point where the mass m is attached

L - length of the ruler

Solution

The torque created by the hanging mass and the piece of ruler that is on the side where the mass is attached:

           τ1=X/L M x/2+am

The torque created by the ruler mass on the other side:

            τ2=L-x/L m L-x/2

Equilibrium means that

               τ1=τ2

           x²/2L M+am=(L-X)²/2L M

         x=0.467m

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an ant runs forward at 4 cm/s. the ant is on a tray being carried backward at 0.75 m/s by a person. the person is on a boat that is steaming forward at 20 m/s. the boat is in an ocean that has a current flowing at 36 km/h backward. how fast is the ant moving relative to the surface of the earth?

Answers

The ant is moving at a velocity of 0.1325 m/s relative to the surface of the earth.

To find the speed of the ant relative to the surface of the earth, you need to add or subtract the velocities of the various reference frames.

The ant is moving forward at 4 cm/s.

The tray is moving backward at 0.75 m/s.

The boat is moving forward at 20 m/s.

The ocean current is moving backward at 36 km/h.

To convert km/h to m/s, divide by 3.6.

So, the ocean current is moving backward at 10 m/s.

Then, you can use the following vector addition to calculate the final velocity of the ant relative to the surface of the earth:

V_ant = V_ant + V_tray + V_boat + V_current = 4 cm/s - 0.75 m/s + 20 m/s - 10 m/s = 13.25 cm/s (0.1325 m/s)

So the ant is moving at a velocity of 0.1325 m/s relative to the surface of the earth.

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a 2.0 kg ball is thrown at 2 m/s strikes a 20.0 kg person sitting at rest on a bench. the ball gets stuck in the person's hair. what is the velocity of the person and the ball?

Answers

Answer:

0.18 m/s

Explanation:

Conservation of Momentum Law:  total P before the collision must equal total momentum after the collision.  P = mv

(2.0 kg)(2 m/s) + (20.0 kg)(0 m/s) = (2.0 kg + 20 kg)v

                     before                                  after

4 kg·m/s = (22.0 kg)v

v = (4 kg·m/s) / (22.0 kg)  = 0.18 m/s

certain latitudes have a surplus of energy that accumulates over an entire year, because more radiation is absorbed from the sun than is emitted by the earth. where are these latitudes?

Answers

The latitudes that have a surplus of energy that accumulates over an entire year, because more radiation is absorbed from the sun than is emitted by the earth, are the tropical regions. These regions are located near the equator, between the Tropic of Cancer (23.5 degrees North) and the Tropic of Capricorn (23.5 degrees South).

In these latitudes, the sun is directly overhead at least once a year, resulting in high levels of solar radiation being absorbed. The high temperatures and high humidity in these regions also contribute to the Earth's energy balance by increasing the rate at which energy is emitted back into the atmosphere.

The tropical regions also receive more radiation from the sun throughout the year than do regions closer to the poles because the sun's rays are less inclined there, meaning they hit the surface at a more perpendicular angle, increasing the amount of energy absorbed.

This surplus of energy in the tropical regions is the main reason why they are characterized by lush vegetation, high temperatures, and heavy precipitation.

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