The effective spring constant describing the potential energy of the HBr molecule is 410 N/m and that for the NO molecule is 1530 N/m.A) Calculate the minimum amplitude of vibration for the NO molecule.
B) Calculate the minimum amplitude of vibration for the HCl molecule.

Answers

Answer 1

Answer:

a. the minimum amplitude of vibration for the NO molecule A [tex]\simeq[/tex] 4.9378 pm

b. the minimum amplitude of vibration for the HCl molecule A [tex]\simeq[/tex] 10.9336 pm

Explanation:

Given that:

The effective spring constant describing the potential energy of the HBr molecule is 410 N/m

The effective spring constant describing the potential energy of the NO molecule is 1530 N/m

To calculate the minimum amplitude of vibration for the NO molecule, we use the formula:

[tex]\dfrac{1}{2}kA^2= \dfrac{1}{2}hf[/tex]

[tex]kA^2= hf[/tex]

[tex]A^2= \dfrac{hf}{k}[/tex]

[tex]A = \sqrt{\dfrac{hf}{k}}[/tex]

[tex]A = \sqrt{\dfrac{(6.626 \times 10^{-34} \ J. s ) ( 5.63 \times 10^{13} \ s^{-1})}{1530 \ N/m}}[/tex]

[tex]A = \sqrt{\dfrac{3.730438 \times 10^{-20} \ m}{1530 }[/tex]

[tex]A = \sqrt{2.43819477 \times 10^{-23}\ m[/tex]

[tex]A =4.93780799 \times 10^{-12} \ m[/tex]

A [tex]\simeq[/tex] 4.9378 pm

The effective spring constant describing the potential energy of the HCl molecule is 480 N/m

To calculate the minimum amplitude using the  same formula above, we have:

[tex]A = \sqrt{\dfrac{hf}{k}}[/tex]

[tex]A = \sqrt{\dfrac{(6.626 \times 10^{-34} \ J. s ) ( 8.66 \times 10^{13} \ s^{-1})}{480 \ N/m}}[/tex]

[tex]A = \sqrt{\dfrac{5.738116\times 10^{-20} \ m}{480 }[/tex]

[tex]A = \sqrt{1.19544083\times 10^{-22}\ m[/tex]

[tex]A = 1.09336217 \times 10^{-11} \ m[/tex]

[tex]A = 10.9336217 \times 10^{-12} \ m[/tex]

A [tex]\simeq[/tex] 10.9336 pm


Related Questions

Which observation is the most objective? a My frog died after 3 days in the aquarium. I will miss him. b My frog died after three days in the aquarium. We will test the temperature and water conditions to find out why. c Frogs tend to die in captivity. Ours did after three days.

Answers

Answer:

b

Explanation:

a looks so silly

A farmer lifts his hay bales into the top loft of his barn by walking his horse forward with a constant velocity of 8 ft/s. Determine the velocity and acceleration of the hay bale when the horse is 10 ft away from the barn.

Answers

Answer:

Velocity = 8 ft/s

Acceleration = 0 m/s²

Explanation:

Since, the horse is moving with a constant velocity, whose magnitude is given as equal to 8 ft/s. Therefore, it will have the same velocity when it is 10 ft away from the barn. And the velocity of hay bale will be same as the velocity of horse, as the horse is carrying the bales. Therefore:

Velocity = 8 ft/s

Coming to the second part of the question, which relates to the acceleration of the hay bale, when horse is 10 ft away from the barn. The formula for acceleration is given as:

Acceleration = Change in Velocity/ Time

But, the velocity of the horse in constant, which means there is no change in velocity. Hence,

Change in Velocity = 0

Therefore,

Acceleration = 0/Time

Acceleration 0 m/s²

What is the average power output (in W) of a heart defibrillator that dissipates 435 J of energy in 10.5 ms?

Answers

Answer:

The  power is   [tex]P  =  41429 \  W[/tex]

Explanation:

From the question we are told that

   The  energy is  [tex]E =  435  \  J[/tex]

    The time taken is  [tex]t =  10.5 \  ms  =  10.5 *10^{-3} \  s[/tex]

Generally the the average power is  mathematically represented as

       [tex]P  =  \frac{E}{t}[/tex]

=>    [tex]P  =  \frac{ 435}{ 10.5*10^{-3}}[/tex]

=>     [tex]P  =  41429 \  W[/tex]

(a) A narrow beam of light containing yellow (580 nm) and green (550 nm) wavelengths goes from polystyrene to air, striking the surface at a 30.0°30.0° incident angle. What is the angle between the colors when they emerge?

Answers

Answer:

0.043°

Explanation:

Snell's law States that the ratio of the angle of incidence to angle of refraction is a constant for a given pair of media.

n = sin(i)/sin(r)

n1/n2 = sin(i)/sin(r)

For the green polystyrene

n2 = refractive index of green polystyrene = 1.493

n1 = refractive index of air = 1

1/1.493= sin30°/sin(r1)

sin(r1) = sin30°×1.493

sin(r1) = 0.5×1.493

sin(r1) = 0.7465

r1 = sin^-1(0.7465)

r1 = 48.288°

For the yellow polystyrene

n2 = refractive index of yellow polystyrene = 1.492

n1 = refractive index of air = 1

1.492/1= sin30°/sin(r2)

sin(r2) = sin30°×1.492

sin(r2) = 0.5×1.492

sin(r2) = 0.746

r2 = sin^-1(0.746)

r2 = 48.245°

The angle between the colors when they emerge = r1-r2

angle between the colors when they emerge = 48.288°-48.245°

angle between the colors when they emerge = 0.043°

Density is calculated by dividing

Answers

Answer:

Density is the mass of an object divided by its volume. Density often has units of grams per cubic centimeter (g/cm3). Remember, grams is a mass and cubic centimeters is a volume (the same volume as 1 milliliter).

Explanation:

Hey, there!

Density is defined as mass per unit volume. so, when we keep is as a formula we get like,

[tex]density = \frac{mass}{volume} [/tex]

So, you can state that density is calculated by dividing mass by its unit volume.

Hope it helps...

What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 203 km above Earth's surface

Answers

Answer:

7,790.38 m/s

Explanation:

Given the following :

What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 203 km above Earth's surface

Altitude = 203 km

Using the formula :

V = √GM/r

Where G = gravitational constant =6.67×10^-11

Kindly check attached picture for detailed explanation.

an Alpha particle moving in north direction give reasons​

Answers

Your question has been heard loud and clear.

An alpha particle , can move in any direction randomly. But with a magnetic field , we can deflect the alpha particle in any direction we want.

So , the magnetic field must be placed to the west of the alpha particle , so that the particle gets deflected and moves towards the north direction.

Thank you.

Like AL2006 said reasons for what

You drop a ball from a height of 1.7 m, and it bounces back to a height of 1.2 m.
Part A) What fraction of its initial energy is lost during the bounce? Express your answer using two significant figures.
Part B) What is the ball's speed just before the bounce? Express your answer to two significant figures and include the appropriate units.
Part C) What is the ball's speed just after the bounce? Express your answer to two significant figures and include the appropriate units.
Part D) Where did the energy go?
1. The energy "lost" was changed primarily into chemical energy.
2. The energy "lost" was changed primarily into acoustic energy.
3. The energy "lost" was changed primarily into thermal energy due to friction.
4. The energy "lost" was changed primarily into heat energy.

Answers

Answer:

A)       ΔEm = 0.29,  B)   v₁ = 5.8 m/s, c)   v₂=  4.9 m / s    D) the correct answer from 4

Explanation:

For this exercise we will use conservation of energy, taking care of how to choose our system

A) For this case we take two instants

starting point. When the ball goes out

        Em₀ = U = m g y₁

Final point. When the ball reaches its maximum height

         [tex]Em_{f}[/tex] = U = m g y₂

In this case we see that there is a loss of mechanical energy at the moment of rebound, therefore the fraction of energy lost is

          ΔEm = Em_{f} / Em₀

          ΔEm = mg y₂ / mg y₁

          ΔEm = y₂ / y₁

          ΔEm = 1.2 / 1.7

the lost part of energy  

          ΔEm = 1 -0.706

          ΔEm = 0.29

B) the velocity just before the bounce

starting point. When the ball is released

          Em₀ = U = m g y₁

final punot. Just wide of the bounce

           Em_{f} = K = ½ m v₁²

As it has not yet rebounded, it has no energy loss, therefore the mechanical energy is conserved

            Em₀ = Em_{f}

            m g y₁ = ½ m v₁²

             v₁ = √ 2 g y₁

let's calculate

            v₁ =√ (2 9.8 1.7)

             v₁ = 5.77 m / s

            v₁ = 5.8 m/s

C) the velocity just after the bounce

   starting point, after bounce

               Em₀ = K = ½ m v₂²

   final point. Maximum height after bounce

               Em_{f} = U = m g y₂

as it already bounced, the energy is conserved in this interval

               Em₀ = Em_{f}

               ½ m v₂² = m g y₂

               v₂ = √ (2 g y₂)

               v₂ = √ (2 9.8 1.2)

               v₂ = 4.85 m / s

               v₂=  4.9 m / s

D) during the time that the bounce lasts, there is a strong change in energy, part of it is transformed into thermal energy, due to several processes: friction, change in the potential energy of the molecules of the ball, change in the internal energy of the balls. molecules.

Therefore we cannot specify a single process, consequently the correct answer from 4

while working out a man performed 375J of work in 11 seconds what was his power

Answers

Answer:

power=work done /time taken

therefore..375/11

=34.09

there he used 34.1

Industrial espionage is the use of spying techniques to find out key information that is of economic value.
a) true
b) false

Answers

Answer:

The given statement is "True".

Explanation:

Industrial spying or espionage seems to be the surreptitious but sometimes unconstitutional method of trying to investigate competition in the market to gain a competitive advantage throughout the commercial enterprise. The investigation's goal may be a closely guarded secret including a patented product design or formulation, or growth strategy details.

Which of the following are subjects of scientific laws?a. gravityb. motionc. thermodynamics

Answers

can u only pick one answer? if not then i’d be weird because it’s a and b

ame
2. A train moving at 15 m/s slows down, and eventually stops after 5
seconds. What is the acceleration of the train?
G: Vi =
Vf=
U:
E: Formula
S: Substitute
S: Solve

Answers

Answer:

Acceleration, a = -3 m/s²

Explanation:

Given that,

Initial speed, u = 15 m/s

Final speed, v = 0

Time, t = 5 s

We need to find the acceleration of the train. It is equal to the change in velocity divided by time taken. So,

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{0-15\ m/s}{5\ s}\\\\a=-3\ m/s^2[/tex]

So, the acceleration of the train is 3 m/s² and it is deaccelerating.

What do civic heroes contribute to their society?

Answers

the quest for civic virtue

Explanation:

improving schools, the society....to help educators like yourself, the bill of rights institute has written a New classroom-friendly curriculum called Heroes and Villains....

15. Two like charges: A. Attract each other B. Repel each other C. Must be neutrons D. Neutralize each other

Answers

Answer:

B. Repel each other

Explanation:

Two like charges have the same sign. Example an electron with a negative charge (-e) and another electron with same charge(-e). Or a proton with a positive charge (+e) and another proton with same charge (+e). Since each of  these pair charges have the same sign, they will repel each other.

On the other hand, if the charges are opposite, ie  negative charge and positive charge, they will attract each other.

B. Repel each other

You drive your car in a straight line at 15 m/s for 10 kilometers, then at 25 m/s for another 10 kilometers.
a. What is your average speed?
b. Choose the best explanation from among the following:
1) More time is spent at 15 m/s than at 25 m/s.
2) The average of 15 m/s and 25 m/s is 20 m/s.
3) Less time is spent at 15 m/s than at 25 m/s.

Answers

Answer:

A) Average speed = 18.75 m/s

B) More time is spent at 15 m/s than at 25 m/s.

Explanation:

Let the first distance be d1 and the second distance be d2.

We are given;

d1 = 10 km = 10000 m

d2 = 10 km = 10000 m

Speed; v1 = 15 m/s

Speed; v2 = 25 m/s

Now, the formula for distance is; Distance = speed x time

Thus:

d1 = v1 x t1

t1 = d1/v1 = 10000/15 = 666.67 seconds

Also,

d2 = v2 x t2

t2 = d2/v2 = 10000/25 = 400 seconds

Average speed = total distance/total time = (10000 + 10000)/(666.67 + 400) = 18.75 m/s

From earlier, since t1 = 666.67 seconds and t2 = 400 seconds, then;

More time at 15 m/s than at 25 m/s.

Anyone able to also give me the working to how they figured it out?​

Answers

Answer:

Lamp 1:  4 Volts,  and 0.2 Amps

Lamp 2 : 4 Volts, and 0.2 Amps

Explanation:

Considering that the three lamps are equal (they have the same resistance R), we can find the actual resistance of the lamps with the information they provide that the potential difference measured across lamp 3 is 8 volts, using Ohm's Law:

[tex]V = I\,*\,R\\R = \frac{V}{I}\\R= \frac{8}{0.4} \\R = 20\,\,\Omega[/tex]

We can also estimate the potential difference across the lamps 1 and 2 (which are connected in parallel) using Kirchhoff's loop law, which tells us that the 12 volts provided by the battery should equal the addition of voltage drops in lamp 3 plus the drop in the parallel combination of lamps 1 and 2 (call that X):

12 V = 8 V + X

X = 12 - 8 = 4 V

Now, the current circulating through lamp 1 should be given by Ohm's Law:

[tex]V = I\,*\,R\\I = \frac{V}{R} \\I = \frac{4}{20}\\I = 0.2 \,\,Amps[/tex]

Notice that lamp 2 is equal to lamp 1 so the current value should be the same: 0.2 Amps

Why do scientists need creativity? What is gravity? Why are two objects with mass drawn to each other? List the two things that affect gravitational force. How are mass and weight different? Why does weight change depending on location? Explain in your own words the law of universal gravitation. Why does gravitational force vary between objects? How do we know how much gravitational force objects have? How does distance affect gravity? answer them all

Answers

Answer:

The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other.

the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force.

mass and distance.

The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass.

A person can weigh differently at various place on Earth because of the fluctuations in Earth's gravity.

We call the gravitational force attractive because it always tries to pull masses together, it never pushes them apart. In fact, every object, including you, is pulling on every other object in the entire universe!

Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force

Its weight is determined by the degree to which gravitational force acts on it.

the force of gravity the masses exert on each other. increases, the force of gravity decreases

The mass of the objects and their separation from one another determine the gravitational force's strength. The gravitational pull of masses on one another.

What affect gravitational force?

Mass is a measure of the quantity of substance in a material, whereas weight measures how the force of gravity acts upon a mass.

Because of variations in Earth's gravity, a person's weight might vary depending on where they are on the planet.

The gravitational force is referred to as attractive because it continually tries to pull masses together rather than push them apart. In truth, you and everything else in the universe are being pulled in different directions.

Therefore, Greater gravitational forces will pull more massive objects toward one another because gravitational force is directly proportional to the mass of both interacting objects.

Learn more about gravitational force here:

https://brainly.com/question/12528243

#SPJ2

Two cars, C and D, travel in the same direction on a long, straight section of highway. During a particular time interval Ato, car D is ahead of car C and is speeding up while car C is slowing down. During the interval At, it is observed that car C gains on car D (i.e., the distance between the cars decreases). Explain how this is possible, and give a specific example of such a case.

Answers

Answer:

possibly because the car is running out of gas

Explanation:

1st block
Worksheet: Metric Prefixes
A. Circle the larger unit:
1.millimeter, centimeter
2. kilogram, megagram
3. microsecond, millisecond
4.dL, mL
5.mg, kg

Answers

Answer:

2

Explanation:

kilogram and megagram is the larger unit

Which term describes a quantity that has both magnitude and direction?

Answers

Vector  explanation is apex and I got 100 on the test and it’s the definition

1. A particle is moving along the x-axis. Its position as a function of time is given as x = bt − ct 2 . a) What must be the units of the constants b and c, if x is in meters and t in seconds?

Answers

Answer:

Given x = bt-c²

We know that t= time (s)

x= distance (m)

So

bxt= meters

m/s x s= m

And then c= m/s²

And b= m/s

A 50 kg child is riding on a carousel (merry-go-round) at a constant speed of 5 m/s. What is the magnitude of the change in the child's momentum ∣Δp⃗ ∣∣ in going all the way around (360∘)?In going halfway around (180∘)? It is very helpful to draw a diagram, and to do the vector subtraction graphically.

Answers

Answer:

a) [tex]\mathbf{|\Delta p^{\to}_{11}| = 0 \ kg.m/s}[/tex]

b) [tex]\mathbf{|\Delta p^{\to}_{12}| = 500 \ kg.m/s}[/tex]

Explanation:

From the image attached below.

Suppose the child goes all the way around, i.e., 360, the child will execute a movement of 1 complete revolution and be at his starting point. At that point, the velocity vector is towards the y-direction.

Thus, the velocity of the child is:

[tex]v_1^{\to} = v \hat _v_1} \\ \\ v_1^{\to} = (5)(0,1,0)\\ \\ v_1^{\to} = (0,5,0) \ m/s[/tex]

the momentum will be:

[tex]p_1^{\to} = m v_1^{\to} \\ \\ p_1^{\to} = (50)(0,5,0) \\ \\ p_1^{\to} = (0,250,0) \ kg.m/s[/tex]

the  change in momentum now is [tex]\Delta p = p_1^{\to} -p_1^{\to}[/tex] since that is the child's momentum initially.

∴ [tex]\Delta p =(0,250,0) - (0,250,0)[/tex]

[tex]\mathbf{\Delta p =(0,0,0) \ kg.m/s}[/tex]

By subtracting the two vector graphically as being asked in the question, we have :

[tex]|\Delta p^{\to}_{11}| = \sqrt{(0)^2+(0)^2 +(0)^2 }[/tex]

[tex]\mathbf{|\Delta p^{\to}_{11}| = 0 \ kg.m/s}[/tex]

b) In going halfway around (180°), the child will be opposite with respect to the starting point. Hence, the velocity vector will be in the negative y-direction.

Thus, the velocity of the child is:

[tex]v_2^{\to} = v \hat _v_2} \\ \\ v_2^{\to} = (5)(0,-1,0)\\ \\ v_2^{\to} = (0,-5,0) \ m/s[/tex]

the momentum will be:

[tex]p_2^{\to} = m v_2^{\to} \\ \\ p_2^{\to} = (50)(0,-5,0) \\ \\ p_2^{\to} = (0,-250,0) \ kg.m/s[/tex]

the  change in momentum now is [tex]\Delta p = p_2^{\to} -p_1^{\to}[/tex] since that is the child's momentum initially.

∴ [tex]\Delta p =(0,-250,0) - (0,250,0)[/tex]

[tex]{\Delta p =(0,-500,0) \ kg.m/s[/tex]

By subtracting the two vector graphically as being asked in the question, we have :

[tex]|\Delta p^{\to}_{12}| = \sqrt{(0)^2+(-500)^2 +(0)^2 }[/tex]

[tex]|\Delta p^{\to}_{12}| = \sqrt{250000}[/tex]

[tex]\mathbf{|\Delta p^{\to}_{12}| = 500 \ kg.m/s}[/tex]

A large magnetic flux change through a coil must induce a greater emf in the coil than a small flux change. A) True B) False

Answers

Answer:

False

Explanation:

Faraday's law gives the relationship between the induced emf and the rate of change of magnetic flux i.e.

[tex]\epsilon=\dfrac{-d\phi}{dt}[/tex]

The given statement "A large magnetic flux change through a coil must induce a greater emf in the coil than a small flux change" is false. The reason is that if the rate of change of magnetic flux is greater, then its will induce more emf. It would mean it does not say about emf.

Hence, it is false.

43 Points For Answering & +22 for Brainliest

Question 1

A student conducts an experiment to test how the temperature of a ball affects its bounce height. The same ball is used for each test, and the ball is dropped from the same height each time. What is the dependent variable?
A.The type of ball
B.The temperature of the ball
C.The drop height of the ball
D.The bounce height of the ball

Question 2

A student conducts an experiment to test how the temperature affects the amount of sugar that can dissolve in water. In the experiment, she uses 100 millilitres of water in each trial and stirs for five minutes each time. What is the independent variable?
A.The amount of water
B.The temperature of the water
C.The amount of sugar
D The time stirred

Question 3

Which of the following is a way for scientists to limit the amount of errors in their experimentation?
A.Using controls
B.Only completing an experiment once
C.Using equipment to measure the experiment that has been damaged
D.There is no need to record data from an experiment

Answers

Answer:

Question 1: D because the height the ball bounces depends on all the other factors in the experiment.

Question 2: B because the the temperature of the water is not affected by the other variables.

Question 3: A because the more that they can control in the experiment, the more accurate the results will be.

Hopefully this helps :)

1:D 2:B 3:A

just took the test

A beam of helium-3 atoms (m = 3.016 u) is incident on a target of nitrogen-14 atoms (m = 14.003 u) at rest. During the collision, a proton from the helium-3 nucleus passes to the nitrogen nucleus, so that following the collision there are two atoms: an atom of "heavy hydrogen" (deuterium, m = 2.014 u) and an atom of oxygen-15 (m = 15.003 u). The incident helium atoms are moving at a velocity of 6.346 x 10° m/s. After the collision, the deuterium atoms are observed to be moving forward (in the same direction as the initial helium atoms) with a velocity of 1.531 x 107 m/s.A) What is the final velocity of the oxygen-15 atoms? B) Compare the total kinetic energies before and after the collision.

Answers

Answer:

Explanation:

We shall apply law of conservation of momentum to solve the problem .

Helium-3 collides with nitrogen-14 at rest . After the collision the newly formed deuterium atom and oxygen-15  atom moves .

momentum before the collision

= 3.016 x 6.346 x 10⁶ + 14.003 x 0 = 19.14 x 10⁶ unit

momentum after collision

2.014 x 1.531 x 10⁷ + 15.003 V

3.083 x 10⁷ +  15.003 V units

Applying the law of conservation of momentum ,

19.14 x 10⁶ = 3.083 x 10⁷ +  15.003 V

1.914 x 10⁷ = 3.083 x 10⁷ +  15.003 V

15.003 V = - 1.169 x 10⁷

V = .077917 x 10⁷

= 7.79 x 10⁵  m /s

= .0779 x 10⁷ m /s

mass of helium atom = 3.016 u = 3.016 x 1.67 x 10⁻²⁷ kg

velocity = 6.346 x 10⁶ m /s

kinetic energy = 1 /2 x  3.016 x 1.67 x 10⁻²⁷ x (6.346 x 10⁶ )²

= 101.42 x 10⁻¹⁵ J  

kinetic energy of nitrogen atoms = 0

Total energy before collision =  101.42 x 10⁻¹⁵ J  

Similarly kinetic energy after collision

= 1 /2 x [ 2.014 x 1.531² + 15.003 x .0779² ] x 1.67 x 10⁻²⁷ x 10¹⁴

= .835 x [ 4.72  + .09 ] x 10⁻¹³ J

=  4.016 x 10⁻¹³ J

= 401.6 x 10⁻¹⁵  J  

value of kinetic energy is increased .

give me an example of orderliness In nature​

Answers

Answer:

Here are some examples of orderliness In nature​

1. The proposal that the order of nature showed evidence of having its own human-like "intelligence" goes back to the origins of Greek natural philosophy and science, and its attention to the orderliness of nature, often with special reference to the revolving of the heavens.

2. For Stillman, the orderliness of Astaire-like dance is an actual cure for destructive emotions.

3. Tells about the orderliness of the crowds, and of the dispatch with which the trains were being filled and emptied.

The siren of a fire engine that is driving northward at 31.0 m/s emits a sound of frequency 2020 Hz. A truck in front of this fire engine is moving northward at 19.0 m/s.
a) What is the frequency of the siren's sound that the fire engine's driver hears reflected from the back of the truck?
b) What wavelength would this driver measure for these reflected sound waves?

Answers

Answer:

A. Using

Fl= ( v+vl/v+vz)fz

= (340+19/340+31) x 2020

= 1954.7Hz

Then to find the frequency of sound when reflected from the truck such that the driver becomes the listener

we use

F"= ( v+vz/v+vl) fz

= 340+31/340+19 x 2020

2087.5Hz

B to find the wavelength of sound we use

Wavelength= V+vl/ F"

= 340+31/2087.5= 0.18m

Martin is conducting an experiment. His first test gives him a yield of 5.2 grams. His second test gives him a yield of 1.3 grams. His third test gives him a yield of 8.5 grams. On average, his yield is 5.0 grams, which is close to the known yield of 5.1 grams of substance. Which of the following are true?

Answers

Complete Question

Martin is conducting an experiment. His first test gives him a yield of 5.2 grams. His second test gives him a yield of 1.3 grams. His third test gives him a yield of 8.5 grams. On average, his yield is 5.0 grams, which is close to the known yield of 5.1 grams of substance. Which of the following are true?

A His results are accurate but not precise.

B His results are neither accurate nor precise.

C His results are both accurate and precise

D His results are precise but not accurate.

Answer:

Correct option is A

Explanation:

From the question we are told that  

   The  yield of the first test [tex]k  =  5.2 \  g[/tex]

   The  yield of the second  is  [tex]u =  1.3 \  g[/tex]

   The  third yield is  [tex]p =  8.5 \  g[/tex]

   The  average yield  [tex]A = 5.0 \ g[/tex]

    The  know yield is  [tex]A_S =  5.1 \  g[/tex]

From the data given we see that

        [tex]A_S \ne A[/tex]

Since his average yield is closer to the known yield then the answer is accurate

But since the yield for each test are not repeated the answer is not precise

So the answer is accurate but not precise  

His results are accurate but not precise.

Your question is not complete, it seems to be missing the following information;

"A His results are accurate but not precise.

B His results are neither accurate nor precise.

C His results are both accurate and precise.

D His results are precise but not accurate."

The given parameters;

first measurement = 5.2 gsecond measurement = 1.3 gthird measurement = 8.5 gaverage measurement = 5.0known substance average yield = 5.1 g

Each of the measurement is far from each other. That is 5.2 grams, 1.3 grams and 8.5 grams are all far apart. So this measurement is not precise.

The known average (5.1 g) and the measured average (5.0 g) are close to each other, so the measurement is accurate.

Thus, we can conclude that his results are accurate but not precise.

Learn more here: https://brainly.com/question/13377944

A jet makes a landing traveling due east with a speed of 115 m/s. If the jet comes to rest in 13.0 s, what is the magnitude of its average acceleration

Answers

Answer:

8.846 m/s²

Explanation:

From the question,

The magnitude of the average acceleration is given as,

a = (v-u)/t.................. Equation 1

Where a = acceleration of the jet, v = final velocity of the jet, u = initial velocity of the jet, t = time taken for the jet to come to rest.

Given: v = 115 m/s, u = 0 m/s( from rest), t = 13.0 s

Substitute these values into equation 1

a = (115-0)/13.0

a = 115/13

a = 8.846 m/s²

Hence the magnitude of the average acceleration of the jet is 8.846 m/s²

Answer:

The  value is  [tex]a = 8.85 \ m/s^2[/tex]

Explanation:

From the question we are told that

   The speed is  [tex]v = 115\ m/s[/tex]

   The  time taken is  t =  13.0

   The initial speed is  [tex]u = 0 \ m/s[/tex]

Generally the magnitude of the average acceleration is mathematically represented as

      [tex]a = \frac{v-u}{ t}[/tex]

=>  [tex]a = \frac{ 115 -0}{ 13}[/tex]

=>    [tex]a = 8.85 \ m/s^2[/tex]

The presence of dwarf galaxies around the Milky Way supports what picture of our galaxy’s formation?

Answers

Answer:

The presence of dwarf galaxies around the Milky Way supports what picture that our galaxy was formed by a coming together or combination of smaller systems

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