the frequency content of an analog signal to be digitized has a range roughly covering the range of the auditory system of a young child: 200 hz to 20,000 hz. for accurate sampling, what is the minimal sampling rate necessary for an a/d convertor?

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Answer 1

For accurate sampling, -44.1khz is minimum sampling rate for an a/d convertor.

What is sampling rate?

The number of samples per second (or other unit) taken from a continuous signal to form a discrete or digital signal. The sample rate or sample rate specifies the number of samples per second (or other unit). of a continuous signal to form a discrete or digital signal..

The sampling rate can be thought of as the audio version of frames per second. This is the number of "clips" taken from an analogue sound wave to make a digital file. In addition, the sample rate also controls the highest frequency that can be accurately reproduced by a digital file.

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On level ground, how much farther can a person jump on the moon as compared to the earth if the takeoff speed and the angle are the same? The free-fall acceleration on the moon is one-sixth what it is on Earth.

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The person can jump 6 times higher on the moon compared to Earth.

What is the maximum height jumped by an object?

The maximum height an object can Jump is the height vertical displacement of the object during an upward motion.

Mathematically, the maximum height an object can jump is given as;

H = u²sin²θ/2g

where;

u is the initial velocity of the objectθ is the angle of projection of the objectg is acceleration due to gravityh is the maximum height of jump

When a person moves to the moon, the acceleration due to gravity becomes ; ¹/₆

The new height the object can jump is calculated as follows;

H = u²sin²θ/(2 x ¹/₆g)

H = 6( u²sin²θ/2g)

Thus, the person will jump higher on the moon due to lesser acceleration due to gravity.

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For a force to do work on an object, some of the force must act in the________________
as the object moves.

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Answer:

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What is the condition for a force to do work on a body ?

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What is the condition for a force to do work on a body ?

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Solution

The condition of force to do some work is that the force should be along the direction of displacement.

work is done when the object moves through a certain distance in a particular direction after the force had been applied on it.

Work Done = Force x Distance x Cos theta

For work to be done, the force must be applied and must not be zero.

The body on which the force is applied must move in one direction or the other and hence the S must not be zero.

The force must not be applied at 90 degrees angle upon the object as Cos 90 equals zero.

how is the energy that powers radio galaxies, quasars, and other active galactic nuclei thought to be produced?

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The energy that powers radio galaxies, quasars, and other active galactic nuclei is thought to be produced by accreting matter onto a supermassive black hole. This process is called active galactic nucleus (AGN) fueling.

The gas that surrounds the black hole is heated to millions of degrees as it falls into the black hole. Because the gas is so hot, it emits a great deal of radiation in many different wavelengths.

This radiation can be seen across the electromagnetic spectrum, from low-energy gamma rays to high-energy X-rays. In some cases, jets of charged particles are ejected at nearly the speed of light along magnetic field lines; these jets can create shock waves in the surrounding medium that emit radio waves.

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A spherical object has a certain density. If it is compressed under high pressure to half of its original diameter, its density will now be.

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The following formula can be used to determine an object's density if it is spherical.

ρ = 3/4 x π x r³

Here, r denotes the spherical object's radius.

and is a constant in mathematics with the value 22/7.

Assume that the object's initial diameter is d.

As a result, it will have a radius of = d/2 = 0.50d.

Let's enter this value and calculate density as 1.

ρ₁ = 3/4 x π x (r)³

ρ₁ = 1/2 x 22/7 x (0.5d)³

The object is currently being compressed so that its diameter is reduced to a fourth of what it was.

The object's new diameter would be d/2 = 0.50d.

The new radius would be 0.50d/2 = 0.25d as a result.

Find the new density 2 now.

ρ₂ = 1/2 x 22/7 x (0.25d)³

Compare numbers 1 and 2 now.

3/4 x 22/7 x (0.25d)3 divided by 3/4 x 22/7 x (0.5d)3 equals 2/1.

1/2 and 22/7 can be canceled here.

ρ₂/ρ₁ = (0.25d)³ / (0.5d)³

d is terminated.

ρ₂/ρ₁ = 0.125

ρ₂ = 0.125 ρ₁

The original density is 1, and the revised density is 2.

Since its new density would be 0.125 times that of its original, we can conclude that.

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according to karl popper, a discipline that claims to be a science is really a pseudoscience like astrology if it:

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A scientific theory should make testable predictions and if those predictions are found to be incorrect the theory should be dismissed.

He argued that science advances best through the use of deductive reasoning, known as critical rationalism, as its primary emphasis. Popper coined the term critical rationalism to describe his philosophy. Popper rejected the empiricist view that basic statements are infallible.

Karl Popper was a scientific realist against his will. Despite his own limitations regarding the forms of acceptable scientific reasoning and the extent of empirical evidence, he advocated a very real conception of scientific goals and outcomes. A significant contribution stems from his rejection of induction in empirical science.

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the force F acting on a body along a circular path depends on a mass of the body (m),velocity(v) and radius (r) of the circular path.obtain the expression for the force by dimensional analysis method(take constant k to be 1)​

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the required equation for centripetal force is F = k m¹ v¹ r⁻¹.

A particle traveling uniformly in a circle experiences a centripetal force, F, which is dependent on the mass (m), velocity (v), and radius (r) of the circle.

the F formula using the dimensions method is

Suppose F = k mᵃvᵇrⁿ. (i)

Where a, b, and n are the respective powers of m, v, and r and k is the dimensionless constant of proportionality.

Upon putting the measurements of various amounts in (i)

we get

[M¹L¹T‐²] = Mᵃ[LT‐¹]ᵇ Lⁿ

=> [M¹L¹T‐²] = Mᵃ Lᵇ Lⁿ T⁻ᵇ

=> [M¹L¹T-²] = Mᵃ Lᵇ⁺ⁿ T⁻ᵇ

on comparing both sides we get

a = 1

b+n = 1

-b = -2 => b = 2

Then n = -1

Onputting these values in (i),

we get

F = k m¹ v¹ r⁻¹

Or

F=k(mv²)/r

This is the required equation for centripetal force.

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The place kicker on a football team kicks a ball from ground level with an initial speed of 8.40 m/s at an angle of 21.0° above the horizontal. How long is the ball in the air, in seconds, before it lands on the ground again? You may neglect air resistance.

Answers

Answer:

See below

Explanation:

Vertical component of the kick-off velocity is  8.4 sin21° = 3.01 m/s

Find the time-point where vertical velocity = 0   the ball is in the air for twice this long  ( as it still has to fall back down to the ground)

vf = vo + at

0  = 3.01 m/s   - 9.81 t     shows t = .307   twice this is .614 sec  

  ( what a sorry kick !)

A small nail stuck in your car tire moves on a circular path with a radius of 35 cm. when the nail has traveled a linear distance of 5.5 m, through what angle has the tire rotated in both radians and degrees?

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To cover 5.5 meters in a straight line, the tire rotated at an angle of 15.714rad.

What is a circle's simple definition?

To put it simply, a circle is a spherical shape without any corners or line segments. In geometry, it has the shape of a closed curve.

A definition from Euclid

A circle is a plane figure that is bounded by a single curved line and in which all straight lines drawn from any point inside the circle to the boundary are equal. Its center is the point, and its circumference is the bounding line. — Book I of Euclid's Elements.

Given,

circular path with a radius of 35cm,

Circumference of car tire is 2πr = 2×3.14×0.35 = 2.198m

For traveling a distance of  5.5m

5.5 = angle in rads ×radius

angle = 5.5/0.35

angle = 15.714 rad

To cover 5.5 meters in a straight line, the tire rotated at an angle of 15.714rad.

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a mass m is attached to an ideal massless spring. when this system is set in motion with amplitude a, it has a period t. how does the period of the motion change if the amplitude of the motion is increased to 2a? explain.

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System is set in motion with an amplitude of a and a period of T. If the amplitude of the motion is increased to 2a, the period of the motion changes.

A straightforward harmonic oscillator's period is independent of its amplitude. with the graphs of acceleration and velocity produced by the time derivatives. These oscillators also show how kinetic and potential energy can be transferred.

The acceleration of the mass increases proportionally with the increase in force, causing the mass to travel farther in the same amount of time. Therefore, increasing the amplitude has no overall impact on the oscillation's period.

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which of the glass lenses above, when placed in air, will cause rays of light (parallel to the central axis) to converge?

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Convex lenses when placed in the air, will cause rays of light (parallel to the central axis) to converge.

Converging lenses, commonly referred to as convex lenses, have thicker centers and narrower upper and lower margins. The edges are outwardly curled. This lens has the ability to concentrate a beam of parallel light rays coming from the outside onto a spot on the opposite side of the lens.

The image created is referred to be a genuine image when it is inverted relative to the object. On a screen, this kind of image can be recorded. When the object is positioned at a point farther than one focal length from the lens, a converging lens creates a true image.

A virtual image is one that cannot be produced on a screen and is formed when the image is upright in relation to the object. When an item is positioned within one focal length of a converging lens, a virtual image is created. It creates an enlarged image of the object on the same side of the lens as the image. It serves as a magnifier.

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Which has the most kinetic energy from its motion?

Multiple choice question.
cross out

A)
a 1,100-kg car traveling 60 km/h

cross out

B)
a 2,000-kg truck traveling 50 km/h

cross out

C)
a 900-kg car traveling 80 km/h

cross out

D)
a 300-kg motorcycle traveling 100 km/h

Answers

Among the given options the vehicle that has the most kinetic energy is a 900-kg car traveling 80 km/h

KE = 1 / 2 m v²

KE = Kinetic energy

m = Mass

v = Velocity

For A,

m = 1100 kg

v = 60 km / h

KE = 1 / 2 * 1100 * 60²

KE = 1980000 J

KE = 1980 KJ

For B,

m = 2000 kg

v = 50 km / h

KE = 1 / 2 * 2000 * 50²

KE = 2500000 J

KE = 2500 KJ

For C,

m = 900 kg

v = 80 km / h

KE = 1 / 2 * 900 * 80²

KE = 2880000 J

KE = 2880 KJ

For D,

m = 300 kg

v = 100 km / h

KE = 1 / 2 * 300 * 100²

KE = 1500000 J

KE = 1500 KJ

KEc > KEb > KEa > KEd

Therefore, the 900-kg car traveling 80 km/h has the most kinetic energy

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a 0.111 kg hockey puck moving at 55 m/s is caught by a 80 kg goalie at rest. with what speed does the goalie slide on the (frictionless) ice?

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The goalie slides on the frictionless ice at a speed of 0.076 m/s.

collision energy equals collision momentum

What generates momentum?

An object's momentum will vary as a result of a force applied for a specific length of time. In other words, an uneven force an object regardless of whether it is speeding up or slowin accelerates g down. When a force exerted against an object's motion slows it down.

The puck weighs 0.111 kg in terms of mass.

Hockey puck velocity is 55 meters per second.

Goalkeeper weight: 80 kg

Goalkeeper's speed is 0 meters per second.

Following the rule of linear momentum conservation, (0.111 kg 55 m/s) + (80 kg 0 m/s) = (0.111 kg + 80 kg) V V = (6.105 / 80.111) = 0.076 m/s (0.111 kg 55 m/s) + (0.111 kg + 80 kg) V = 0.076 m/s

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A brick is thrown upward from the top of a building at an angle of 25 to the horizontal and with an initial speed of 15 m/s. The brick hits the ground after 3.0s of flight.
(a) Calculate the height of the building.

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The vertical height of the building is determined as 44.1 m.

What is the height of the building?

The height of the building is calculated by applying the following kinematic equation as shown below.

h = vyt + ¹/₂gt²

where;

vy is the initial vertical velocity of the brickt is the time of motion of the brickh is the height of fall of the brickg is acceleration due to gravity

h = (v sinθ)t + ¹/₂gt²

where

θ is the angle of inclination of the velocity

The given parameters include the following;

initial vertical velocity of the brick, vy = 0the time of motion of the brick, t = 3.0 sthe height of fall of the brick, h = ?acceleration due to gravity = 9.8 m/s²

h = (0 x sin25)(3)  +  ¹/₂(9.8)(3²)

h = 44.1 m

Thus, the height of the building is equal to the vertical distance travelled by the brick thrown at the given initial velocity.

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A diver runs horizontally off the end of a 3.0-m-high diving board with an initial speed of 1.8 m/s. Find her y positions at the times t = 0.25 s , t = 0.50 s , and t = 0.75 s .

Answers

(a) At time, t = 0.25 s, the y position of the driver is 0.31 m.

(b) At time, t = 0.50 s, the y position of the driver is 1.2 m

(c) At time, t = 0.75 s, the y position of the driver is 2.76 m

What is the position of the driver?

The position of the driver at the various time is determined by applying the following kinematic equation.

y = vt + ¹/₂gt²

where;

v is the initial vertical velocity of the drivert is the time of motion of the drivery is the vertical position of the driver at various timet is the time of motion

Since the driver runs horizontally, the initial vertical velocity = 0

y = 0 + ¹/₂gt²

y = ¹/₂gt²

at time, t = 0.25 s, the y position of the driver is calculated as;

y = ¹/₂gt²

y = ¹/₂(9.8)(0.25)²

y = 0.31 m

at time, t = 0.5 s, the y position of the driver is calculated as;

y = ¹/₂gt²

y = ¹/₂(9.8)(0.5)²

y = 1.2 m

at time, t = 0.75 s, the y position of the driver is calculated as;

y = ¹/₂gt²

y = ¹/₂(9.8)(0.75)²

y = 2.76 m

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Which of the following is not a density-dependent factor limiting a population growth?

a) intra-specific competition

b) switching behavior of a predator

c) a stress syndrome that alters hormone levels

d) a limited number of available nesting site

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Answer:A.

i know its a, i did quiz

an object is 16.0cm from a concave mirror whose focal length is 10.0cm. (a) how far is the image from the mirror? answer: cm (b) what is the magnification? include any sign answer: (c) is the image real or virtual? answer: (d) is the image upright or inverted? answer:

Answers

The distance of the image is 26.67 cm

The magnification is -1.67

The image is real

The image is inverted

The focal length of the concave mirror = 10 cm

The distance of the object from the concave mirror = 16 cm

The distance of the image can be found using the formula

                 1/p + 1/q = 1/f

where p is the distance of the object

          q is the distance of the image

          f is the focal length

                  1/q = 1/f - 1/p

                  1/q = (p - f)/fp

                    q = fp / (p - f)

                    q = 16 x 10 / ( 16 - 10)

                       = 160 / 6

                       = 26.67 cm

The distance of the image from the concave mirror is 26.67 cm

The magnification of the concave mirror can be found using

                  M = -q/p

where M is the magnification

                 M = -26.67 / 16

                     = -1.67

The distance of the image is positive, so the image is real

The magnification value is negative, so the image is inverted.

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two workers are sliding 260 kg crate across the floor. one worker pushes forward on the crate with a force of 450 n while the other pulls in the same direction with a force of 370 n using a rope connected to the crate. both forces are horizontal, and the crate slides with a constant speed. what is the crate's coefficient of kinetic friction on the floor?

Answers

To find out the kinetic friction, using the coefficient friction formula.

What is kinetic friction?

A force that acts between moving surfaces is called "kinetic friction." A force acting in opposition to the direction of a moving body on the surface is felt. The two materials' kinetic friction coefficients will determine how much force is applied.

What is coefficient friction?

A measure of the degree of friction between two surfaces is the coefficient of friction. A coefficient of friction is determined by calculating the resistance to motion at the intersection of two surfaces made of the same or different materials.

UK

U-coefficient of friction

K-Kinetic friction

Using UK

450+370-f=m*o

f=820=UK*260*9.8

UK=2.548

820/2.548

UK= 321.8210361

Therefore the coefficient of kinetic friction is 321.8210361

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a solenoid of length 1.50 cm and radius 0.550 cm has 37 turns. if the wire of the solenoid has 1.15 amps of current, what is the magnitude of the magnetic field inside the solenoid? magnitude of the magnetic field: t ignoring the weak magnetic field outside the solenoid, find the magnetic energy density inside the solenoid. magnetic energy density: j/m3 what is the total magnetic energy inside the solenoid? total magnetic energy: j

Answers

a) magnitude of the magnetic field = 8.02 X [tex]10^{-3}[/tex] T

b)Energy Density = 5.03 J/[tex]m^{3}[/tex]

c) Total magnetic energy inside the solenoid = 2.01 X [tex]10^{-5}[/tex] J

What is magnetic field?A magnetic field, a vector field in the vicinity of a magnet, an electric current, or a changing electric field in which magnetic forces can be observed. Magnetic fields, such as those found on Earth, cause magnetic compass needles and other permanent magnets to align in the field's direction. Magnetic fields cause electrically charged particles to move in a circular or helical pattern. The operation of electric motors is based on this force, which is exerted on electric currents in wires in a magnetic field. 

Calculation

a) B = uNI/L

B = (4π X [tex]10^{-7}[/tex])(37)(1.15)/(.015)

B = 8.02 X [tex]10^{-3}[/tex] T

b) Energy Density = [tex]B^{2}[/tex]/2u

Energy Density = [tex](8.02 *10^{-3} )^{2}[/tex]/(2)(4π X [tex]10^{-7}[/tex])

Energy Density = 5.03 J/[tex]m^{3}[/tex]

c) Total magnetic energy inside the solenoid

Multiply by volume for total energy.

Total Energy = 5.03(π[tex]r^{2}[/tex])(L)

Total Energy = (5.03)(π)[tex](8.5*10^{-3})^{2}[/tex])(.015)

Total Energy = 2.01 X [tex]10^{-5}[/tex] J

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a)The  magnitude of the magnetic field [tex]$=\mathbf{8 . 0 2} \times 10^{-3} \mathbf{T}$[/tex]

b)The  Energy Density [tex]$=\mathbf{5 . 0 3} \mathrm{J} / \mathrm{m}^3$[/tex]

c) Total magnetic energy inside the solenoid [tex]$=\mathbf{2} . \mathbf{0 1} \mathbf{X} 10^{-5} \mathbf{J}$[/tex]

What is magnetic field?A magnetic field, a vector field in the vicinity of a magnet, an electric current, or a changing electric field in which magnetic forces can be observed.Magnetic fields, such as those found on Earth, cause magnetic compass needles and other permanent magnets to align in the field's direction.Magnetic fields cause electrically charged particles to move in a circular or helical pattern.The operation of electric motors is based on this force, which is exerted on electric currents in wires in a magnetic field.

a) [tex]$B=u N I / L$[/tex]

[tex]&B=\left(4 \pi \times 10^{-7}\right)(37)(1.15) /(.015) \\[/tex]

[tex]&B=8.02 \times 10^{-3} \mathrm{~T}[/tex]

b) Energy Density[tex]$=B^2 / 2 \mathrm{u}$[/tex]

Energy Density[tex]$=\left(8.02 * 10^{-3}\right)^2 /(2)\left(4 \Pi \times 10^{-7}\right)$[/tex]

Energy Density [tex]$=5.03 \mathrm{~J} / \mathrm{m}^3$[/tex]

c) Total magnetic energy inside the solenoid

Multiply by volume for total energy.

Total Energy [tex]$=5.03\left(\pi r^2\right)(\mathrm{L})$[/tex]

Total Energy [tex]$\left.=(5.03)(\pi)\left(8.5 * 10^{-3}\right)^2\right)(.015)$[/tex]

Total Energy [tex]$=2.01 \times 10^{-5} \mathrm{~J}$[/tex]

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What is the total momentum before the collision?

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Answer:

When two objects collide the total momentum before the collision is equal to the total momentum after the collision (in the absence of external forces). This is the law of conservation of momentum. It is true for all collisions.

Explanation:

...

Answer:

When two objects collide the complete momentum before the collision is similar to the complete momentum afterwards the collision (in the absence of outside forces) . This is the law of conservation of momentum . it's accurate for all collisions .

if there is no air resistance, what is the net if there is 10 n of air resistance, what is the net force? what is the acceleration?? what is the acceleration?

Answers

If there is no air resistance, what is the net if there is 10 n of air resistance, what is the net force,the net force of an object is 0N and acceleration is 6N.

When compared to displacement and velocity, acceleration is like the wrathful, flaming dragon of motion variables. People may be terrified of it, it might be harmful, and if it's enormous, it draws your attention. When you're in a fast-turning corner in a car or go-kart or when you're in a plane during takeoff, you can feel your own acceleration.

Since velocity depends on both speed and direction, you can only accelerate by changing either one or the other, if not both. The object will be moving faster if the acceleration is pointing in the same direction as the velocity. Additionally, the item will slow down if the acceleration is pointing in the opposite direction from the direction of the velocity.

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which answer would you choose if the rocks fall out through a hole in the floor of the car, one at a time?

Answers

The car speeds remains constant.

Using the following equation for momentum:

Pi=Pf

(c=car and r=rock)
              McVc + MrVr = McV'c + MrV'r

Initially
                         Vc=Vr=Vi
and since rocks are being dropped directly downward, final momentum of the rocks (being dropped one at a time) should be zero because their falling down, out of the railroad car.
So:
Vi( Mc+Mr) = McV'c V'c = [Vi(Mr+Mc)] / Mc

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two copper wires (in different circuits) carry the same current, but wire a has twice the radius of wire b. if the drift speed of the conducting electrons in wire a is 0.1 mm/s, what is the drift speed of the conduction electrons in wire b? assume the number density of conducting electrons is the same in both wires.

Answers

4 is the drift speed of the conduction electrons in wire b.

I = neA [tex]V_{d}[/tex]

[tex]V_{d}[/tex] = [tex]\frac{I}{neA}[/tex]

    = [tex]\frac{I}{ne\pi r^{2} }[/tex]

[tex]V_{d}[/tex] [tex]\alpha[/tex]   [tex]\frac{1}{r^{2} }[/tex]

r' = 2r

A' = [tex]\pi 2r^{2}[/tex]

   = 4[tex]\pi r^{2}[/tex]

[tex]\frac{Vd'}{Vd}[/tex]= [tex]\frac{r^{2} }{2r^{2} }[/tex] = 1/4

[tex]V_{d}[/tex] = 4

What is drift speed?

Subatomic particles like electrons move in random directions all the time. When electrons are exposed to an electric field, they  move randomly but  slowly drift in one direction,  the direction of the applied electric field. The net speed at which these electrons drift is called the drift speed.  Curvature can be defined as follows:

The average speed of charged particles (eg electrons) in a material under the influence of an electric field. the SI unit of yard speed is m/s. It is also measured in [tex]m^2[/tex]/(V.s).

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How many moles of CaCo2 are in 50g of calcium carbonate

Answers

The answer is 0.32 moles if you round up. You divide 50g and 157.86g to get 0.32 moles.

a nearsighted man has a far point of 300 cm. what kind of corrective lens should be prescribed for him?

Answers

The diverging lens/concave lens is used as a corrective lens is used for a nearsighted person

Nearsightedness is also known as myopia where the person with myopia will be able to see the near object but far objects will look blurry.

Myopia is corrected with lenses called "minus power lenses". They are concave in shape and help the eye to focus light properly. Myopia causes distant objects to appear blurry. Prescription glasses or contact lenses can usually correct this blurry distance vision. Myopic eyes have a stronger ability to focus than normal eyes. Focus in front of the retina, not on the retina. Lenses used to correct nearsightedness work by reducing the eye's ability to focus.

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How does a white dwarf differ from a neutron star? how does each form? what keeps each from collapsing under its own weight?.

Answers

An electron degenerate object is a white dwarf, whereas a neutron star is a neutron degenerate object. A white dwarf is less compact and has a larger radius than a neutron star.

How is a white dwarf transformed into a neutron star?

A white dwarf would collapse into a denser entity known as a neutron star if it reached the Chandrasekhar limit and nuclear reactions were to stop. This would happen if nuclear reactions continued to occur.

How is a white dwarf prevented from exploding into a neutron star?

White dwarf stars are prevented from collapsing by the fact that electrons are fermions, while neutron stars are prevented from collapsing by the fact that electrons are fermions.

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when a star is moving towards us (the earth) due to a planet orbiting it and tugging on it, we see a blue shift in the star's spectrum. this corresponds to what in terms of its radial velocity?

Answers

When the radial velocity is positive, it means the distance between the objects is or was becoming closer; when it is negative, it means the distance between the source and the observer is or was getting closer.

What is radial velocity?

The portion of a particle's velocity that is moving in the direction of its radius vector. or radial motion, which is the speed at which an observer approaches or recedes from a celestial body or other source of radiation in the line that connects the two: speed in the visual field.

This technique is one of the detection methods that enables us to calculate an exoplanet's mass, a crucial factor in the hunt for worlds similar to Earth and other extraterrestrial life.

Radial velocity has been used to locate hundreds of distant planets and was the first effective approach for exoplanet discovery. Because stars do not need to be continuously monitored as they do with transit photometry, it is perfect for ground-based telescopes.

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a 70 kg man is floating at rest near his spaceship. he throws a 1.5 kg wrench away from the ship at a speed of 10 m/s in order to move himself toward it. with what speed does he move toward the ship?

Answers

0.218 m/s speed does he move toward the ship.

use the formula from conservation of Momentum

mu  + MV  =  (m-M)V'

u  =  o

so

MV  =  (m-M)V'

V'  =  (1.5 * 10)/(70-1.5)

V'  =  0.218 m/s

What is speed?

The most crucial scientific notion is measurement. Base or physical fundamental units are used to quantify a wide range of quantifiable quantities. One such measurable metric is speed, which calculates the ratio between the distance an object travels and the time needed to cover that distance. Let's explore speed in-depth in this session.

The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.

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How many g are in a pack containing 10 tablets of 500 mg each? *
5g
50g
100g
500g​

Answers

Answer:

5 g

Explanation:

500 mg x 10 = 5000 mg

5000 x 10^-3 g = 5 g

Hello..!

To solve the problem and calculate the number of pills in the package, we will use the conversion factor.

The conversion factor or unit factor is a conversion method that is based on multiplying by one or more fractions where the numerator and denominator are equal quantities expressed in different units of measure, so that each fraction is equivalent to the unit.

Find out that 1 gram has a total of 1000 mg.

Problem:

How many g are in a carton containing 10 tablets of 500 mg each?

According to the previous text we can say that the conversion factor would be:

[tex] \: \: \: \: \: \qquad \qquad \large \sf\dfrac{1\ g}{1000\ mg}[/tex]

Now we must find out that the box has a total of 10 pills of 500 mg, so to know how many grams the box has we must know how many grams only one pill weighs:

[tex] \sf \qquad\boxed{\boxed{ \sf\large 500\ mg*\dfrac{1\ g}{1000\ mg}= 0.5\ g}}[/tex]

We know that a pill weighs 0.5 grams, now to calculate how many grams the box weighs we must multiply the total pills by the weight of just one pill:

[tex]\qquad \boxed{\boxed{ \sf\large 0.5\ g\times 10= 5\ g}}[/tex]

We conclude that one box contains 5 grams of tablet, option 1.

[tex]\begin{gathered}\rule{7cm}{0.01mm}\\\texttt{Good studies! :D}\\\rule{7cm}{0.01mm}\end{gathered}[/tex]

if the test section is designed to have a velocity of 200 m/s, determine the mach number, temperature and pressure in the test section. is the pressure in the test section greater than or less than the surrounding atmospheric pressure?

Answers

The test section's pressure is lower than the ambient pressure.

What exactly does pressure mean?

In the physical sciences, pressure is defined as the perpendicular force per unit area or the stress at a particular location within a confined fluid.

Given,

Diameter of Test section, d₂ = 0.5m

Area, A₂ = π/4d₂² = π/4×0.5² = 0.19635m²

Now, At Inlet,

Po = 101325Pa

To = 288 k

s = 122 kg/m³

(a) Using Bernoulli Theorem, i'n Test Section,

Po = [tex]P_{t}[/tex] +1/2γ [tex]v_{t^{2} }[/tex]

101325 = [tex]P_{t}[/tex] + ½ (1.22) (200) ²

[tex]P_{t}[/tex] = 76925 Pa

[[tex]v_{t}[/tex] = 200m/s]

Now,

Static Temperature, [tex]T_{t}[/tex]

[tex]T_{0}[/tex] = [tex]T_{t}[/tex] +v²/2[tex]c_{p}[/tex]

288 = [tex]T_{t}[/tex] +200²/2×1005

[tex]T_{t}[/tex] = 268.09k.

Thus,

[tex]M_{t}[/tex] = [tex]v_{t}[/tex]/[tex]\sqrt{\nu RT_{t} }[/tex]

[tex]M_{t}[/tex] = 200/1.4×287×268

[tex]M_{t}[/tex]= 0.609

The test section's pressure is lower than the ambient pressure.

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How long does it take a car to travel 330 m at a speed of 30.0 m/s

Answers

It will take 11 seconds

330/30=11

It will take 11 seconds for a car to travel 330 m at a speed of 30.0 m/s

By going through the formula of calculating the speed of the vehicle

that is, S=D/T

We get the equation T=D/S.........(i)

Where T stands for Time

D stands for Distance

S stands for Speed

Now, as per the given question

Distance(D)= 330 meters

Speed(S)= 30.0 meters per second

Time(T)= ?

Putting the values in equation (i),

                      T=330 meters/30 meters per second

                      T = 11 seconds.

Therefore, A car moving at a speed of 30.0 meters per second will traverse 330 meters in 11 seconds.

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