The gas arsine, AsH3, decomposes as follows: In an experiment at a certain temperature, pure AsH3(g) was placed in an empty, rigid, sealed flask at a pressure of 392.0 torr. After 48 hours the pressure in the flask was observed to be constant at 488.0 torr. a. Calculate the equilibrium pressure of H2(g). b. Calculate Kp for this reaction

Answer:

best answer is D

Explanation:

if element has even number then protons and neutrons are same but if element has odd number then we should add 1 number in number of protons to know neutrons. but this rule is not work in 4 element that element are argon, nitrogen, hydrogen and one other

[tex]oxidation \: number \: of \: oxygen = \\ before \: rxn = - 2 \\ after \: rxn = - 2[/tex]

[tex]oxidation \: number \: of \: hydrogen = \\ before \: rxn = + 1 \\ after \: rxn = \\ 2x - 2 = 0 \\ x = + 1[/tex]

[tex]oxidation \: number \: of \: carbon = \\ before \: rxn = \\ x - 6 = - 2 \\ x = 4 \\ after \: rxn = \\ x - 4 = 0 \\ x = 4[/tex]

[tex]oxidation \: numbers \: remain \: constant \\ so \: none \:a re \: undergoing \: oxidation \: \\ nor \: reduction \: [/tex]

Answer:

D

Explanation:

I believe that is the answer

The compound that is formed is calcium hydroxide.

When limestone is decomposed at a high temperature, calcium oxide is formed as the residue.

[tex]CaCO_3 --- > CaO + CO_2[/tex]

When the calcium oxide residue is treated with water, a calcium hydroxide solution is formed.

[tex]CaO + H_2O -- > Ca(OH)_2[/tex]

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If not all of the salt has dissolved then the measurement of the concentration at the time is really inaccurate.

The concentration is the amount of substance that is present in solution. We know that we can not measure the concentration unless all of the solute have been dissolved in the solution.

Thus, if not all of the salt has dissolved then the measurement of the concentration at the time is really inaccurate.

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Answer:

C.) H₂O and K₂SO₄

Explanation:

This appears to be a double-displacement reaction. In these reactions, the cation of one substance is swapped with the cation of another.

So, K⁺ from KOH is swapped with the H⁺ from H₂SO₄. The new compounds should have an overall charge of 0. Therefore, it may be necessary to modify the amount of each ion (not just be 1:1).

K₂SO₄
-----> K⁺ and SO₄²⁻

-----> + 1 + 1 + (-2) = 0

H₂O

-----> H⁺ and OH⁻

-----> + 1 + (-1) = 0

Answer:

electrical conduction

Explanation:

Based on the type of experiment that is being conducted:

This is the term that is used to refer to the variable that is used to arrive at conclusions about the dependent variable.

The experiment is trying to tell us that the temperature of a material is the function of the heat applied to it and the type of material.

This is the term that is used to refer to the variable of interest. It is what is being tested in the experiment.

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The reaction is based on law of conservation of mass.

The balanced chemical equation is

[tex]$4 \mathrm{NaI}+\mathrm{Pb}\left(\mathrm{SO}_{4}\right)_{2} \rightarrow \mathrm{PbI}_{4}+2 \mathrm{Na}_{2} \mathrm{SO}_{4}$[/tex]

Every balanced chemical equation follows the direction of conservation of mass. This law states that mass can neither be completed nor can be destroyed but it can only be transformed from one condition to another form. This law likewise states that the total number of individual atoms on the reactant side must be comparable to the total number of individual atoms on the product side.

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The total atmospheric pressure of the final product in the flask is 18.36atm

Atmospheric pressure can be defined as the force exerted on a surface by the air above it as gravity pulls it to earth.

Furthermore, the standard atmosphere is a unit of pressure which is also defined as:

101,325 Pa =760mmHg

So therefore, the total pressure of the final product in the flask is 18.36atm

Complete question:

Gaseous iodine pentafluoride, IF₅, can be prepared by the reaction of solid iodine and gaseous fluorine:

I₂(s) + 5F₂(g) → 2IF₅(g)

A 10.00 L flask is charged with 19.0 grams of I₂ and 2.00 atm of F₂ at 25°C. The flask is heated to 100°C until one of the reagents is completely consumed. What will be the total pressure (in atm) of the final products in the flask at 100°C? (Assume ideal gas behavior)

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If 30.0 mL of 0.150 M CaCl₂ is added to 38.5 mL of 0.100 M AgNO3. The mass of the AgCl precipitate is 0.552 g.

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

2AgNO₃ + CaCl₂ →  2AgCl + Ca(NO₃)₂

Molecular Weight of CaCl₂ = 110.98 g/mol

Molecular Weight of AgNO₃ = 170.01 g/mol

Molecular Weight of AgCl = 143.45 g/mol

Here,

Volume of CaCl₂ = 30.0 mL = 0.03L

Volume of AgNO₃ = 38.5 mL = 0.0385 L

Now find the number of moles

Number of moles = Volume × Molarity

Number of moles of CaCl₂ = 0.03 L × 0.150

                                             = 0.00456 mol

Number of moles of AgNO₃ = 0.0385 L × 0.100

                                               = 0.00385 mol

The stoichiometric ratio of AgNO₃ to CaCl₂ is 2:1.

= [tex]\frac{0.00385}{2}[/tex]

= 0.001925 mol                      

According to Stoichiometry Mass of AgCl

[tex]= 0.0385 \times \frac{0.1}{1\ \text{mol}} \times \frac{2\ \text{mol} AgCl}{2\ \text{mol} AgNO_3} \times \frac{143.4\ g}{1\ \text{mol}}[/tex]

= 0.552 g AgCl

Thus from the above conclusion we can say that If 30.0 mL of 0.150 M CaCl₂ is added to 38.5 mL of 0.100 M AgNO3. The mass of the AgCl precipitate is 0.552 g.

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Answer:

larger the intermolecular forces in a compound, the slower its evaporation rate

Explanation:

socratic

The pH of buffered solution is:

The two buffered solutions have 'equal' pH values.

Comparison between two buffer solutions:

To compare the pH of two different buffer solutions with different concentrations, Henderson-Hasselbalch equation is used.

pH = pKa + log [tex]\frac{Salt}{Acid}[/tex]

pKa of HOAc = 4.76

In solution 1:

Concentration of salt= 5 M

Concentration of acid= 5 M

Putting the values in the equation,

pH = 4.76 + log [tex]\frac{5}{5}[/tex]

pH = 4.76 + log1

pH = 4.76

In solution 2:

Concentration of salt= 0.050 M

Concentration of acid= 0.050 M

Putting the values in the equation,

pH = 4.76 + log[tex]\frac{0.050}{0.050}[/tex]

pH = 4.76 + log1

pH = 4.76

As the ratio  [tex]log\frac{salt}{acid}[/tex] is the same for the different solutions.

Therefore, the pH of the solution remains the same in both the buffer solutions even if the two solutions have different concentrations.

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answer - Albert Einstein

explanation -

Albert Einstein is arguably the most influential scientist of the 20th century. His … general theory of relativity changed our understanding of space and time, becoming one of the two pillars of modern physics – the other being quantum mechanics.

Answer:

Fe(CH₂CO₂)₂, Fe₂MnO, Pb(CH₂CO₂)₄, PbMnO

Explanation:

Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.

1.) Fe(CH₂CO₂)₂

   ----> Fe²⁺ and 2 CH₂CO₂⁻

   ----> +2 + (-1) + (-1) = 0

2.) Fe₂MnO

   ----> 2 Fe²⁺ and 1 MnO⁴⁻
   ----> 2(+2) + (-4) = 0

3.) Pb(CH₂CO₂)₄
   ----> 1 Pb⁴⁺ and 4 CH₂CO₂⁻
   ----> +4 + (-1) + (-1) + (-1) + (-1) = 0

4.) PbMnO

   ----> 1 Pb⁴⁺ and 1 MnO⁴⁻

   ----> +4 + (-4) = 0

The concentration of the acetic acid before titration is 0.128M

For weak acid and strong base titration-

Moles of acetic acid =  moles of NaOH

Given concentration of NaOH = 0.1067M

Volume of NaOH = 30.07ml = 0.03007L

Using the formula, Concentration = Moles/Volume

Moles of NaOH = concentration X volume = 0.1067 X 0.03007 = 0.0032

Therefore, moles of acetic acid  = 0.0032mole

Using the formula, Concentration = Moles/Volume

Concentration of acetic acid =  0.0032/0.025 = 0.128M

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18.06 ₓ [tex]10^{23}[/tex] molecules in 3 mol of carbon dioxide (CO2).

The proportionality factor that connects the quantity of substance in a sample to the number of constituent particles in that sample is called the Avogadro constant. The reciprocal mole, which is its SI unit, is specified precisely as NA 6.02214076 × [tex]10^{23}[/tex] [tex]mol^{-1}[/tex]. It bears Amedeo Avogadro's name, an Italian scientist.

When dealing with very big quantities, chemistry uses Avogadro's number. It serves as the foundation for the mole, a unit of measurement that makes converting between moles, mass, and the number of molecules simple. The quantity, for instance, can be used to determine how many water molecules make up a single snowflake.

1 Mole is 6.02ₓ [tex]10^{23}[/tex] molecules.

Therefore 3 Moles of Carbon Dioxide ([tex]CO_{2}[/tex]) =3(6.02ₓ [tex]10^{23}[/tex])

3 Moles of Carbon Dioxide ([tex]CO_{2}[/tex]) =18.06 ₓ [tex]10^{23}[/tex]molecules of [tex]CO_{2}[/tex].

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Based on the given scenario, the rate of increase in water pressure in atm/km is known to be 992 atm/km.

Pressure is known to be that kind of force that is known to often pushes water via pipes.

Note that Water pressure is a tool that is often used to know or identify the flow of water from any given tap. The amount of pressure at one's tap is said to be often dependent on how high the service tank or water tower is above one's home.

Therefore since 1 atm/m  = 1000 atm/km

Hence 0.992 atm/m  :

           = 0.992 x 1000

          = 992 atm/km.

Therefore, Based on the given scenario, the rate of increase in water pressure in atm/km is known to be 992 atm/km.

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Answer:

particles in liquids have greater kinetic energy than particles in solids

Answer:

1) a) 1.81  × 10²³ molecules (b) 1.93  × 10²³ molecules (c) 0.66× 10²³ molecules

2) a) 0.45× 10²³ions  (b) 0.84× 10²³ions (c) 3.6 × 10²³ions

Explanation:

1) Number of molecules:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

a) 16g of H₂CO₃

Number of moles = mass/ molar mass

Number of moles = 16 g/ 62.03 g/mol

Number of moles = 0.3 mol

1 mol = 6.022 × 10²³ molecules

0.3 mol ×  6.022 × 10²³ molecules /1 mol

1.81  × 10²³ molecules

b) 20g of HNO₃

Number of moles = mass/ molar mass

Number of moles = 20 g/ 63.01 g/mol

Number of moles = 0.32 mol

1 mol = 6.022 × 10²³ molecules

0.32 mol ×  6.022 × 10²³ molecules /1 mol

1.93  × 10²³ molecules

c) 30g of C₆H₁₂O₆

Number of moles = mass/ molar mass

Number of moles = 20 g/ 180.156 g/mol

Number of moles = 0.11 mol

1 mol = 6.022 × 10²³ molecules

0.11 mol ×  6.022 × 10²³ molecules /1 mol

0.66× 10²³ molecules

2. Calculate the number of ions in the following compounds:

a) 10g of AlCl₃

Number of moles = mass/ molar mass

Number of moles = 10g/ 133.34 g/mol

Number of moles = 0.075 mol

1 mol = 6.022 × 10²³ ions

0.075 mol ×  6.022 × 10²³ ions/1 mol

0.45× 10²³ions

b) 30g of BaCl₂

Number of moles = mass/ molar mass

Number of moles = 30g/ 208.23 g/mol

Number of moles = 0.14 mol

1 mol = 6.022 × 10²³ ions

0.14 mol ×  6.022 × 10²³ ions/1 mol

0.84× 10²³ions

c) 58 g of H2SO4

Number of moles = mass/ molar mass

Number of moles = 58g/ 98.079 g/mol

Number of moles = 0.59 mol

1 mol = 6.022 × 10²³ ions

0.59 mol ×  6.022 × 10²³ ions/1 mol

3.6 × 10²³ions

Explanation:

Answer:

Any base with an ability to dissolve in water are called alkalis. All alkalis are bases, however, not all bases are alkalis.

The statement is False.

Ethanol is one of many toxic substances found in tobacco smoke.

Ethanol is used in the manufacture of drugs, plastics, lacquers, polishes, plasticizers, and cosmetics. Ethanol is utilized in remedy as a topical antiinfective, and as an antidote for ethylene glycol or methanol overdose.

Ethanol is a natural chemical compound. it's far simple alcohol with the chemical formula C₂H₆O. Its system can be additionally written as CH ₃−CH ₂−OH or C ₂H ₅OH and is frequently abbreviated as EtOH. Ethanol is a risky, flammable, colorless liquid with a characteristic wine-like smell and pungent taste.

Within the worst instances, there can also be respiratory problems, low blood strain, incontinence coronary heart troubles, blood troubles, liver damage, and loss of life. Ethanol can also dry out and worsen the skin; there may be aches, redness, and swelling. Eye publicity to ethanol also can purpose tearing, burning, and stinging.

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The freezing point of a solution is -1.16°C

Calculation,

The equation which give relation between freezing point depletion and molality is,

Δ[tex]T_{f} = K_{f} .m[/tex]      ... (i)

Moles of the solute = 22.0 g / 114.23 g/mole = 0.193 mole

Mass of the solvent in g = 148 g

Mass of the solvent in kg = 0.148 kg

Molality = 0.193 mole/ 0.148 kg = 1.3 m

Now, after putting the value of  [tex]K_{f}[/tex] and m in equation (i) we get

Δ[tex]T_{f} = K_{f} .m[/tex]  

Δ[tex]T_{f}[/tex]= 5.12°C/m×1.3 m = 6.66°C

Δ[tex]T_{f}[/tex]=  [tex]T_{f}[/tex] (solvent) - [tex]T_{f}[/tex] (solution)

[tex]T_{f}[/tex] (solution) = [tex]T_{f}[/tex] (solvent)  -Δ[tex]T_{f}[/tex]= 5.5 °C - 6.66°C = -1.16°C

The freezing point of a is -1.16°C

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Pure liquids and solids at the equilibrium stage:

Pure solids and pure liquids are not included in expressions for the equilibrium constant of heterogeneous equilibria since their concentrations are constant across time. Therefore, including it in our equilibrium expression is not significant.

Equilibrium expression:

When a certain chemical reaction is in equilibrium, the rates of the forward and backward reactions are equal, which means that there is no net change in the concentrations of the reactants and products and that the reaction mixture's composition does not change.

The concentration of solid and liquid:

Solid or liquid concentration,

= No. of Moles/ Volume in L

= Mass/(Volume × molar mass)

= Density/ Molar mass

Pure solids and liquids have constant densities and molar masses at a constant temperature.

Because of this, they have constant molar concentrations, which means that they are not considered in the equilibrium constant for a heterogeneous reaction.

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The oxidation number for S in the compound SO3 is +6 (option D). Details about oxidation number can be found below.

Oxidation number of an element is the hypothetical charge of an atom within a molecule.

The oxidation number of elements in a compound adds up to the overall charge of that compound.

According to this question, O has an oxidation number of -2 in SO3, the oxidation number of S can be calculated as follows:

x - 2(3) = 0

x - 6 = 0

x = 6

Therefore, the oxidation number for S in the compound SO3 is +6.

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The answer is D: 6+

Worked for me on EDGE 2023

Answer:

2 FeCl3 → 2 Fe + 3 Cl2

Explanation:

2 Fe and 6 Cl on the reactants side, and 2 Fe and 6 Cl on the products side.

Answer:

B) Gold

A) Number of electrons and protons.

Explanation:

Atomic Masses (from periodic table):

----> Copper (Cu): 63.546 g/mol

----> Gold (Au): 196.97 g/mol

----> Iron (Fe): 55.845 g/mol

----> Platinum (Pt): 195.08 g/mol

The atomic number represents the number of protons. Neutral atoms have the same number of protons as electrons. The mass number represents the number of protons and neutrons.

Answer:

Sucrose to is the substrate of the reaction because is a simple sugar( disaccharide) which produce glucose and fructose in the presence of sucrase or when it is hydrolysed.

Answer:

0.638 M NaOH

Explanation:

To find the molarity of the solution, you need to (1) convert grams NaOH to moles NaOH (via the molar mass of NaOH) and then (2) calculate the molarity (via the molarity formula). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator).

(Step 1)

Molar Mass (NaOH): 22.990 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (NaOH): 39.996 g/mol

25.5 grams NaOH                 1 mole
-----------------------------  x  ----------------------------  =  0.638 moles NaOH
                                           39.996 grams

(Step 2)

Molarity = moles / volume (L)

Molarity = 0.638 moles / 1 L

Molarity = 0.638 M

In the electrolysis of water,  3490 hour will it take to produce 165.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 113.0 mA.

The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.

It is expressed as

PV = nRT

where,

P = Pressure

V = Volume in liters

n = number of moles of gas

R = Ideal gas constant

T = Temperature in kelvin

Here,

P = 1.0 atm

V = 165.0 L

R = 0.0821 atm. L/mol.K (Ideal gas constant)

T = 273 K

n = ?

Now put the value in above expression, we get

PV = nRT

1.0 atm × 165.0 L = n × 0.0821 atm. L/mol.K × 273 K

165.0 atm. L = n × 22.4  atm. L/mol

[tex]n = \frac{165.0\ \text{atm. L}}{22.4\ \text{atm. L/mol}}[/tex]

n = 7.36 mol

The reaction is

2H⁺ + 2e⁻ → H₂

1 mol of electrons is produced from 96500 C

So,

[tex]96500 \frac{C}{\text{mol} \times e} \times 2e \times 7.36\ \text{mol}[/tex]

= 1,420,480 C

Convert milliampere to C/s

1mA = 0.001 C/s

113.0 mA = 113.0 × 0.001

               = 0.113 c/s

The relation between current, charge and time is expressed as:

[tex]I = \frac{Q}{t}[/tex]

where,

I = Current

Q = Charge in Coulomb

t = time

Now put the value in above formula we get

[tex]I = \frac{Q}{t}[/tex]

  [tex]= \frac{1,420,480\ C}{0.113\ C/s}[/tex]

  = 12,570,619.469 s

  = 3490 hour

Thus from the above conclusion we can say that In the electrolysis of water,  3490 hour will it take to produce 165.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 113.0 mA.

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Answer:

A resistor resists extra electric current.